What is the results of
4-³ × (¼)²

Answer:

4x+1

Step-by-step explanation:

3x+x+1=4x+1

The slope and the y-intercept of the linear function represented by the graph is given as follows:

The slope is two-thirds, and the y-intercept is –2.

A linear function is modeled by:

y = mx + b

In which:

Looking at the graph, when x = 0, y = -2, hence the y-intercept is of -2. The slope is given by change in y divided by change in x, hence considering that the graph also goes through (3,0), it is given by:

[tex]m = \frac{0 - (-2)}{3 - 0} = \frac{2}{3}[/tex]

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Answer:

50°

Step-by-step explanation:

because there opposite to each other.

The slant height of the pyramid will be 5 inches.

Given Information and Formula Used

Volume of the clay = 48 cubic inches

Edge of the square base of the pyramid, a= 6 inches

Volume of the pyramid = (1/3) × Base Area × Height

Pythagoras Theorem, l² = x² + h²

Here, l is the hypotenuse, x is the base and [tex]h[/tex] is the height in a right angle triangle.

Calculating the Height, h of the Pyramid

Volume of the pyramid = Volume of the clay

Volume of the pyramid, V= 48 cubic inches

Base Area of the pyramid, B = a²

⇒ B = 6² square inches

⇒ B = 36 square inches

∵ V = (1/3)×B×H

[tex]\frac{1}{3}*36*h = 48[/tex]

∴ [tex]h = \frac{48*3}{36}[/tex]

⇒ h = 4 inches

Calculating the Slant Height, l of the Pyramid

Applying Pythagoras Theorem to determine the slant height,

l² = x² + h²

Here, we have x=a/2

[tex]l^{2} = \frac{a^{2} }{4} + b^{2}[/tex]      

[tex]l^{2} = \frac{6^{2} }{4} + 4^{2}[/tex]

[tex]l = \sqrt{9+16}[/tex]

[tex]l=\sqrt{25}[/tex]

l =5 inches

Thus, the slant height of the solid right pyramid with a square base made by Helen is 5 inches.

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Two possible solutions are: (4.5, 8.5) and (8, 6.3)

Let x represents hours dog walking and y represents hours washing cars.

So, we have:

Earnings = Rate of dog walk * x + Rate of car wash * y

This gives

Earnings = 7x + 11y

He wants to earn at least $125.

This means that:

7x + 11y ≥ 125

See attachment for the graph of the inequality

From the attached graph, two possible solutions are: (4.5, 8.5) and (8, 6.3)

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Step-by-step explanation:

LINE B.I is parallel to LINE O.D

therefore :Ô = Î ( alternate angles )

: Ď = B ( alternate angles )

In ️ B. I. G and ️ D O G

️ BIG is similar to ️ DOG

Answer:

Least, Median and Greatest height of boys are all higher then Least, Median and Greatest of girls height

Step-by-step explanation:

Least height of boys: 158cm > 150cm Least height of girls

Median height of boys: 168cm > 165cm Median height of girls

Greatest height of boys: 182cm > 170cm Greatest height of girls

Answer:

(-1,3)

y=5x+8 , y=-4x-1y=5x+8,y=−4x−1

Both sides have y on the left hand side so make the right hand side equal and solve for x

5x+8= -4x-15x+8=−4x−1

To solve for x , add 4x on both sides

9x+8=-19x+8=−1

Subtract 8 on both sides

9x=-99x=−9

Divide by 9 on both sides

x=-1x=−1

Now plug in -1 for x in the first equation and find out y

y=5x+8y=5x+8

y=5(-1)+8y=5(−1)+8

y=-5+8y=−5+8

y=3y=3

Ordered pair is (x,y) that is (-1,3)

Step-by-step explanation:

Mark me as brainliest plsss

The equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Given, that a hyperbola centred at the origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0)

In mathematics, a hyperbola is a type of smooth curve lying in a plane, defined by its geometric properties or by equations for which it is the solution set. A hyperbola has two pieces, called connected components or branches, that are mirror images of each other and resemble two infinite bows.

The formula for a hyperbola centred at the origin is [tex]\frac{x^2}{a^2} -\frac{y^2}{b^2 } =1[/tex]

The vertices are located at (±a, 0), so we have that the value of a is [tex]\sqrt{61}[/tex].

The foci are located at (±c, 0), where [tex]c^2 = a^2 + b^2[/tex].

So if we have that [tex]c = \sqrt{98}[/tex], we can find the value of b:

[tex]98 = 61 + b^2[/tex]

⇒ [tex]b^2 = 37[/tex]

⇒ [tex]b = \sqrt{37}[/tex]

So, the formula for this hyperbola is [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Therefore, the equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

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Answer:34

Step-by-step explanation:

Giving away all that is not new or fav so 12 fav + 18 new + 4 which are new an favorite = 34

Answer:

22

Step-by-step explanation:

63 is the total

14 are new

8 are fav

14+8=22

Answer:

1

Step-by-step explanation:

listing the factors of both numbers

factors of 10 are 1, 2, ,5, 10

factors of 3 are 1, 3

the only common factor to both is 1

the greatest common factor is 1

Answer: 2:3

Step-by-step explanation:

common factor of 42 and 63: 21

42/21= 2

63/21= 3

find the common factor to find the ratio!

therefore the ratio is 2:3

Answer:

yes it is I'm sure of it ok.

Answer:

[0, ∞)

(all real numbers greater than or equal to 0)

Explanation:

the domain of a function is all possible x-values (and the range is all possible y-values)

We know that you cannot have a negative square root, so all negative x-values are not possible--only values 0 to infinity.

So the domain of this function is [0, ∞).

{ [brackets] in math mean the number is included, (parentheses) in math means the number is not included.}

All [real] numbers ≥ 0

is the domain of y=√x

(written as: all real numbers greater than or equal to 0)

3(x-4) ≥ 5x +2

3*x - 3*4 ≥ 5x +2

3x - 12≥ 5x - 2

-12 + 2 ≥ 5x- 3x

-10 ≥ 2x

2x ≤ -10

x ≤ -5

Answer:

0

y = 2

Step-by-step explanation:

Since it's a flat line, the slope is 0.

Since all of the points have a y-value of 2, the equation is y = 2.

Answer:

Slope = 0

Equation: y = 2

Step-by-step explanation:

PQ is parallel  to x-axis. Slope of the line parallel to x-axis = 0.

Slope of diagonal PQ = 0

Equation of line parallel to x-axis : y = a

Equation of diagonal PQ: y = 2  or y -2 = 0

Two angles whose sum is 180° are called supplementary angles. If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line.

Two angles whose sum is 180° are called supplementary angles. If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line. Those two-two angles are two pairs of supplementary angles. That means, that if supplementary angles are aligned adjacent to each other, their exterior sides will make a straight line.

When two lines cross at a single point, a linear pair of angles is generated. If the angles are next to each other after the two lines intersect, they are considered to be linear pairs. The total of the angles of a linear pair is always 180°. These angles are also referred to as supplementary angles.

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Answer:

7(2a+6) = 4

and the answer is:

19/7

Step-by-step explanation:

7(2a+6) = 4

7*2a + 7*6 = 4

14a + 42 = 4

14a = 4 - 42

14a = -38

a = -38/14

a = -19/7

Answer:

no solutions

Step-by-step explanation:

-7 does not equal 7, so there are no solutions.

Infinite solutions would be if it was two equal values, for example, 7 = 7.

Answer:

-10

Step-by-step explanation:

y2- y1 -7 -3

---------- ----------

x2 - x1 -6 6

2. 3 is not a function

3. 4 is a function

To be a function it has to pass the vertical line test, meaning the x value can not repeat. So for this problem, you need to look at the ordered pair (x,y). For problem 2, answer 3 is not a function because the x value of 1 appears twice. For problem 3, answer 4 is a function because there aren't any x values being repeated.

Answer: C

Step-by-step explanation:

Given the following inequality:

[tex]W& > \dfrac{Y + H}{P}[/tex]

Solve for H.

To solve for H we will start by multiplying both sides of the equation by P

[tex]PW& > \dfrac{Y + H}{P}\times P\\[0.3cm] PW& > Y + H\\[0.3cm][/tex]

Next, we will subtract Y from both sides of the inequality

[tex]\boxed{{WP - Y > H}}[/tex]

Therefore, the correct answer is C

Answer:

2

Step-by-step explanation:

[tex]\text{First I'd recommend using this little equation:}\\\text{m}=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{Substitute the values::}\\\text{m}=\dfrac{5-1}{3-1} \\\text{m}=\dfrac{4}{3}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\text{The gradient is:: }\dfrac{4}{3}[/tex]

Answer:

[tex] {x}^{2} + {y}^{2} = 100[/tex]

The equation of the circle is x² + y² = 100.

Option A is the correct answer.

A circle is a two-dimensional figure with a radius and circumference of 2pir.

The area of a circle is πr².

We have,

The circle's equation is:

x² + y² = r²

where r is the length of the radius.

In this case, r = 10, so the equation becomes:

x² + y² = 10²

Simplifying:

x² + y² = 100

Therefore,

The equation of the circle is x² + y² = 100.

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Answer:

x = 6

Step-by-step explanation:

CT is a median, which means it divided AB into two equal parts so we can write the following equation:

7x + 9 = 5x + 21 transfer like terms to the same side of the equation

7x - 5x = 21 - 9 do the extraction

2x = 12 divide both sides by 2

x = 6

Answer:

Number of Days he can feed Pickles from a 15-cup bag of Hungry Hound  =  5 Days

Step-by-step explanation:

this is question based on simple algebraic equations

Simple Algebraic equations -  An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other. The algebraic equation usually consists of a variable, coefficients and constants. we can apply many operations on algebraic equations like addition, subtraction, multiplication, division and raising to a power, and extraction of a root.

so in the question algebraic operation used to solve is simple division.

therefore, according to the question -

Total cups of Hungry Hound dog food pickles eats each day are - 3 cups

Total number of cups of Hungry Hound Terrence have = 15 cups

Number of days Terrence can feed pickles from these cups are =    

15/3 =  5 days

so the correct answer is = 5 Days

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Answer:

Only the equation is the function

An expression is defined as a set of numbers, variables, and mathematical operations. There are a total of 10 benches in the class.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Let the total number of benches be represented by x. If students sit 3 per bench, we are short 3 benches. Therefore, the total number of students can be written as,

Total number of students = 3x + 9

If they sit 5 per bench, 2 benches are left empty, and one bench only has 4 students.

Total number of students = 5(x-1) - 10 +4

Now, the total number of students can be written as,

3x + 9 = 5(x-1) - 10 +4

3x + 9 = 5x - 11

20 = 2x

x = 10

Hence, there are a total of 10 benches in the class.

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Hey there!

[tex] \sf{ \purple{ \boxed{\bold{m = - \dfrac{7}{3} }}}} [/tex]

[tex] \\ [/tex]

We are given the points [tex] \sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })} [/tex] . To find the slope [tex] \sf{\purple{m}} [/tex] of such a line, we use the slope formula which is the following:

[tex] \sf{ \purple{m} }= \dfrac{\Delta y}{\Delta x} = \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}} [/tex]

[tex] \\ [/tex]

⇢Now, by plugging in our values, we get :

[tex] \sf{ \purple{m}} = \dfrac{ \red{ - 1} - \orange{( - 8)}}{ \green{5} \: - \: \blue{8}} = \dfrac{ \: \: 7 \: }{ - 3 \: } \\ \\ \implies \sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}}[/tex]

Therefore, the slope of the line is [tex] \sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}} [/tex]

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

What is the slope of a linear function that goes through (8,-8) and (5,-1)?

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

Formula utilised, here [tex]\bf{\dfrac{y2-y1}{x2-x1}}[/tex].

We utilise that formula because we have two points as our given information.

So, we

put in the values

[tex]\bf{\dfrac{-1-(-8)}{5-8}}[/tex] | subtract on top and bottom

[tex]\bf{\dfrac{-1+8}{-3}}[/tex] | simplify

[tex]\bf{\dfrac{7}{-3}[/tex]

[tex]\cline{1-2}[/tex]

[tex]\bf{Result:}[/tex]

                [tex]\bf{=Slope=-\dfrac{7}{3}}[/tex]

[tex]\LARGE\boxed{\bf{aesthetic\not1\theta l}}[/tex]