What is the solution to this system of equations y=3x-4 4y=12x-4 a no solution b (0,4) C Infinite solutions

The equation of Q(n) is [tex]Q(n) = \frac89 * (88n + 23)[/tex]

The functions are given as:

[tex]R(d) = \frac89 d[/tex]

[tex]P(n) = 88n + 23[/tex]

From the question, we understand that:

d = P(n)

This means that:

d = 88n + 23

Substitute d = 88n + 23 in R(d)

[tex]R(n) = \frac89 * (88n + 23)[/tex]

Also, from the question

Q(n) = R(n)

So, we have:

[tex]Q(n) = \frac89 * (88n + 23)[/tex]

Hence, the equation of Q(n) is [tex]Q(n) = \frac89 * (88n + 23)[/tex]

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It looks like you're talking about the indefinite integral

[tex]\displaystyle \int t^2 e^{-10t} \, dt[/tex]

Integrate by parts:

[tex]\displaystyle u\,dv = uv - \int v\,du[/tex]

Let

[tex]u = t^2 \implies du = 2t \, dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

Integrate by parts again, this time with

[tex]u = t \implies du = dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t e^{-10t} \, dt = -\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt[/tex]

Putting everything together, we get

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \left(-\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt\right)[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \int e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \left(-\frac1{10} e^{-10t}\right) + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} - \frac1{500} e^{-10t} + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = \boxed{-\frac{e^{-10t}}{500} \left(50t^2 + 10t + 1\right) + C}[/tex]

Answer:

[tex]\text{length of \textit{CA}} \ = \ 12.0 \ \ \ (\text{nearest tenth})[/tex]

Step-by-step explanation:

Radian measure is the ratio of the length of a circular arc to its radius.

A radian is the measurement of the central angle which subtends an arc whose length is equal to the length of the radius of the circle.

In the case of the unit circle, as shown in the figure below, one radian is the angle of the sector with a radius of 1 and circular arclength of 1.

Following this definition, the magnitude, in radians, of one complete revolution of a unit circle is the circumference of the unit circle divided by its radius, [tex]\displaystyle\frac{2\pi}{1}[/tex] or [tex]2\pi[/tex]. Thus, [tex]2\pi[/tex] radians is equal to [tex]360^{\circ}[/tex] degrees. Alternatively, one radian is equal to [tex]\displaystyle\frac{180^{\circ}}{\pi} \ \approx \ 57.296^{\circ} \ \ \ (3 \ d.p.)[/tex].

Since radian measure is defined as the ratio of the arc length of a sector to its radius, hence

                                                        [tex]\displaystyle\frac{s}{r} \ = \ \theta \\\\ s \ = \ r\theta[/tex]

where [tex]s[/tex] is the arclength, [tex]r[/tex] is the radius, and [tex]\theta[/tex] is the central angle, in radians.

Therefore, the length of CA is

                                           [tex]\displaystyle\frac{s}{\theta} \ = \ r \\ \\ r \ = \ \displaystyle\frac{26}{124^{\circ} \ \times \ \displaystyle\frac{\pi}{180^{\circ}} \ \text{rad}} \\ \\ r = \displaystyle\frac{26 \ \times \ 45}{31 \ \times \ 3.14} \\ \\ r\ = \ 12.0 \ \ \ \ \left(\text{nearest tenth}\right)[/tex]

Answer:

3041.06

Step-by-step explanation:

The formula of a cone is [tex]\pi r^{2} \frac{h}{3}[/tex] , so plugging both the height and radius will result in the answer!

Answer: 6x+12

Step-by-step explanation: Both denominators can be multiplied to create 6x + 12.

2x + 4

2x(3) + 4(3)

6x+12

3x + 6

3x(2) + 6(2)

6x+12

I hope this helps!

The histogram of the distribution plotted on the y - axis and the interval for the length of time on the x - axis is attached below.

The first bar denotes the length of time between 0 and 10 having a frequency of 8. The second bar denoted the interval between 10 and 15 with a frequency of 15

The third bar denoted the interval between 15 and 20 with a frequency of 10. The fourth bar denoted the interval between 20 and 30 with a frequency of 11

Therefore, the histogram of the distribution is attached below.

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Answer: 83

Step-by-step explanation:

The equation of the line in point-slope form is

[tex]y-3=4(x-2)[/tex]

Substituting in x = 22,

Answer:

$27,500.00

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year.

Solving our equation:

A = 11000(1 + (0.06 × 25)) = 27500

A = $27,500.00

The total amount accrued, principal plus interest, from simple interest on a principal of $11,000.00 at a rate of 6% per year for 25 years is $27,500.00.

Answer:

Step-by-step explanation:

I can give you the meaning of Y

Y is the vertical value in a pair of coordinates. In other words how far up or down the point is. The Y coordinate is always written second in an ordered pair of coordinates (x,y) when used. A example from the internet is:

Answer:

[tex]\cos \theta =\dfrac{\sqrt{21}}{5}[/tex]

Step-by-step explanation:

Given:

Substitute the given value of sin θ into the given identity and solve for cos θ:

[tex]\begin{aligned}(\sin x)^2+(\cos x)^2 & =1\\\implies (\sin \theta)^2+(\cos \theta)^2 & =1\\\left(\dfrac{2}{5}\right)^2+(\cos \theta)^2 & =1\\\left(\dfrac{2^2}{5^2}\right)+(\cos \theta)^2 & =1\\\dfrac{4}{25}+(\cos \theta)^2 & =1\\(\cos \theta)^2 & =1-\dfrac{4}{25}\\(\cos \theta)^2 & =\dfrac{21}{25}\\\cos \theta & =\sqrt{\dfrac{21}{25}}\\\cos \theta & =\dfrac{\sqrt{21}}{\sqrt{25}}\\\cos \theta & =\dfrac{\sqrt{21}}{5}\end{aligned}[/tex]

Step-by-step explanation:

please mark me as brainlest

Answer:

6x > 3+4(2x -1)

6x > 3+ 8x - 4

6x > (-1) + 8x

6x - 6x > (-1) + 8x - 6x

subtracting 6x from both sides

0 > 2x - 1

adding +1 on both sides

1 > 2x

1/2 > x

x < 1/2

The correct representations of the inequality 6x ≥ 3 + 4(2x - 1) is,

⇒ x ≤ 1/2

A relation by which we can compare two or more mathematical expression is called an inequality.

We have to given that;

The inequality is,

⇒ 6x ≥ 3 + 4(2x - 1)

Now, We can simplify as;

⇒ 6x ≥ 3 + 4(2x - 1)

⇒ 6x ≥ 3 + 8x - 4

⇒ 6x ≥ 8x - 1

⇒ 1 ≥ 8x - 6x

⇒ 1 ≥ 2x

⇒ x ≤ 1/2

Thus, The correct representations of the inequality 6x ≥ 3 + 4(2x - 1) is,

⇒ x ≤ 1/2

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Answer:

jenejebdjdndnr

r

r

r

r

r

r

Answer:

Step-by-step explanation:

Comment

Multiply through by x - 3

Then factor the result

4*(x - 3) / (x - 3) = x*(x - 3)

4 = x * (x - 3 )                          Remove the brackets

4 = x^2 - 3x                            Subtract 4 from both sides

4-4 = x^2 - 3x - 4                    Simplify

0 = x^2 - 3x- 4

This factors

0=(x - 4)(x + 1)

Answer

x - 4 = 0

x = 4

x+ 1 = 0

x = - 1

Answer:

Im pretty sure its B,  1.75. Not exactly sure though

Step-by-step explanation:

Answer:

$21.25

Step-by-step explanation:

The cost of the 2 adult tickets before the discount is $8 * 2 = $16

The cost of the 2 child tickets before the discount is $5 * 2 = $10

The total cost before the discount is $16 + $10 = $26

The total cost after the discount is

$26 * (1 - 0.15) =

$26 * 0.85 =

$21.25

Answer:

[tex](4-¹)(2³-4-2) 4 - ¹ ) ( 2³ - 4-2 )[/tex]

[tex]4 {}^{ - 2} (2 {}^{3 } - 4 - 2)(2 {}^{3} - 4 - 2)[/tex]

[tex]4 {}^{ - 2} (2 {}^{3} - 4 - 2) {}^{2} [/tex]

[tex] \frac{1}{16} (8 - 4 - 2) {}^{2} [/tex]

[tex] \frac{1}{16} (4 - 2) {}^{2} [/tex]

[tex] \frac{1}{16} \times 4[/tex]

[tex] \frac{1}{4} [/tex]

Answer:

9=0

Step-by-step explanation:

9=0

The roots of x in the equation -10x² + 12x - 9 = 0 are:

x = (3/5) + (3/5)√(6)i

x = (3/5) - (3/5)√(6)i

For variable x : ax² + bx + c = 0, where a≠0 is a standard quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution since it is a second-order polynomial equation, which is guaranteed by the algebraic basic theorem.

To find the roots of x in the equation -10x² + 12x - 9 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation in standard form (ax² + bx + c).

In this case, a = -10, b = 12, and c = -9. Substituting these values into the quadratic formula, we get:

x = (-12 ± √(12² - 4(-10)(-9))) / 2(-10)

x = (-12 ± √(144 - 360)) / (-20)

x = (-12 ± √(-216)) / (-20)

Substituting this into the expression for x, we get:

x = (-12 ± 6√(6)i) / (-20)

Simplifying the expression further, we get:

x = (3/5) ± (3/5)√(6)i

Therefore, the roots of x in the equation -10x² + 12x - 9 = 0 are:

x = (3/5) + (3/5)√(6)i

x = (3/5) - (3/5)√(6)i

These roots are complex conjugates of each other.

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The trigonometric expression that can be used to find the height of the tree where the top guy wire attaches is tan(45 + 30)

The height of the tree can be found using trigonometric ratios.

Therefore,

tan ∅ = opposite / adjacent

Hence,

for the higher wire

tan 75 = h / 4

4 tan 75 = h

This can be express as follows:

tan 75 = tan(45 + 30)

Hence,

4 × 3.73205080757 = 14.9282032303 ft = 14.9ft

Hence, the trigonometric expression that can be used to find the height of the tree where the top guy wire attaches is tan(45 + 30)

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Finding the percent increase, it is found that the correct option is given by:

C. The Master Program and the Excel Program are both effective, but Math is more effective because of the greater percent increase.

The percent increase is given by the difference between the final and the initial score, divided by the initial score and multiplied by 100%.

Researching the problem on the internet, we have that:

The percent increases are given as follows:

Hence the correct option is given by:

C. The Master Program and the Excel Program are both effective, but Math is more effective because of the greater percent increase.

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Answer: 72

Step-by-step explanation:

[tex]\sum^{3}_{t=0} (6t^{2}-3)=(6(0)^{2}-3)+(6(1)^{2}-3)+(6(2)^{2}-3)+(6(3)^{2}-3)=\boxed{72}[/tex]

Answer:

We know that

The costs of repair for each of the four crashes were

$2529, $1889, $2610, $1073

Here we have to compute the mean, median, and mode cost of repair.

Mean = total cost

the no of crashes

Mean = $2529 + $1889 +$2610 +$1073

4

Mean = $2025.25

Therefore the mean = 2025.25

Then we have to find median.

Now first we have to arrange the data in ascending order (smallest to highest).

$1073,$1889,$2529,$2610

Add the two middle numbers and then divide by two, to get the average:

$1889+$2529 = $4418

Median = $4418/2 = $2209

Therefore the median = $2209

Here there is no mode cost.

Substituting into the formula [tex]d=\frac{m}{v}[/tex],

[tex]19.32=\frac{m}{0.5}\\\\m=\boxed{9.66 \text{ grams}}[/tex]

Answer:

y - 5 = -2(x + 3)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

Given:

point: (-3, 5)

slope (m): -2

The standard point-slope equation is

y - y₁ = m(x - x₁)

Plug in what you know.

y - (5) = -2(x - (-3))

Simplify.

y - 5 = -2(x + 3)

This is your equation.

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Answer:

6.25 litres

Step-by-step explanation:

ratio 1:4

25/4 = 6.25

4 * 6.25 = 25

1 * 6.25 = 6.25

= 6.25 litres of concentrate

Answer:

6.25 litres of juice concentrate

Answer: 18, 24, 30

Step-by-step explanation:

For the segments to create a right triangle, they must satisfy the Pythagorean theorem.

The only set which satisfies the Pythagorean theorem, is 18, 24, 30, since [tex]18^{2}+24^{2}=30^{2}[/tex]

The value of x is 38 degree.

A triangle is a polygon with three sides , three angles and three sides .

The sum of all angles in a triangle is equal to 180 degree

The angles of the triangle given are

83 degree and 59  degree and x degree

83 + 59 + x = 180

x = 38 degree

Therefore the value of x is 38 degree.

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The triangle ABC and triangle CDA are congruent by AAS [Angle - Angle-Side] property.

If two triangles are congruent, this means they are the same shape and the same size. By definition, all corresponding angles of two congruent triangles are congruent. Additionally, all corresponding sides of two congruent triangles are congruent.

In the given triangles we can see that:-

Therefore we can see that the triangle ABC and triangle CDA are congruent by AAS [Angle - Angle-Side] property.

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Answer:

[tex] - 5.4z {}^{2} + 6.6z[/tex]

Step-by-step explanation:

Given:

[tex]-3z(1.8z-2.2)[/tex]

Solution:

Applying Distributive property,we obtain

Simplifying using PEMDAS:

Done!

Answer:A

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

you are multiplying so it is the product of the three

2 ( ...  )    ( ... )

and you must solve the brackets first so C and not D