The correct answer is that proton is the subatomic particle that gives the nucleus an overall positive charge.
A proton is a stable subatomic particle with the designations p, H+, or 1H+ with an electric charge of +1 e. (elementary charge). Its mass is just somewhat less than a neutron and 1,836 times more than that of an electron (the proton–electron mass ratio). Protons and neutrons, which have masses of around one atomic mass unit each, are together referred to as "nucleons" (particles present in atomic nuclei).
One or more protons can be found in the nucleus of every atom. They provide the main electrical attraction and holding power for the atomic electrons. An element may be identified by its atomic number, which is the quantity of protons in its nucleus (represented by the symbol Z).
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what piece of lab equipment would you use to estimate the volume of a drop of water?
To estimate the volume of a drop of water, you can use a piece of lab equipment called a micropipette.
A micropipette is a precision instrument that is used to measure and transfer small volumes of liquid. It works by suctioning up a known volume of liquid and then dispensing it into a test tube or other vessel. The micropipette is accurate to within 0.1-1% of the total volume, making it ideal for measuring small volumes such as drops of water.
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an unknown compound contains only c , h , and o . combustion of 5.90 g of this compound produced 13.4 g co2 and 5.49 g h2o . what is the empirical formula of the unknown compound? insert subscripts as needed.
The unidentified compound's empirical formula is C9.45H5.13O1 (rounded to the nearest whole number). The simplest whole number ratio of the atoms in a compound is the empirical formula.
We must ascertain the relative proportions of each element in the combination in order to get the empirical formula. the volume of CO2 generated: 13.4 g of CO2 are created per mass of C. mass of H = (mass of H2O created) (2 mol H2O / 1 mol H2) (1 g/mol) = 5.49 g 2 / 18.015 g/mol = 0.610 g. the compound's overall bulk 5.90 g, 13.4 g, 0.610 g, and 1.89 g are the mass of O, total mass, mass of C, and mass of H, respectively. figuring out the empirical formula Create moles out of the masses: 13.4 g divided by 12.011 g/mol yields 1.117 mol of carbon. 0.606 mol is equal to 0.610 g/1.008 g/mol, or moles of H. Omoles are calculated as 1.89 g / 15.999 g/mol, or 0.118 mol. the most basic ratio of entire numbers: moles of C, moles of H, and moles of O are equal to 1.117, 0.606, and 0.118 mol/moles, respectively. The abbreviation is: C9.45H5.13O1. Hence, C9.45H5.13O1 is the empirical formula for the unidentified molecule.
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Select the term that correctly describes a chemical reaction that favors one possible structural isomer over one or more other structural isomers.
A. Stereogeneic
B. Stereoselective
C. Regioselective
D. Regiogenic
A chemical reaction that prefers one potential structural isomer over one or more other structural isomers is accurately referred to as stereoselective.
One stereoisomer from a variety of stereoisomers interacts in a stereoselective reaction. Additionally, a reaction that, although it has the potential to yield two or more stereoisomers, only ever yields one stereoisomer.
The overall reaction is referred to as stereoselective if more than one reaction between a group of reactants may take place under the same circumstances, producing products that are stereoisomers, and if one product forms in larger proportions than the others.
Occasionally, the phrase "stereospecific" is used to denote "100% stereoselective" (cf. regiospecific). It is advised to avoid using the phrase stereospecific to signify 100% stereoselective because the term's original definition is different.
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Observation when separating iron filings, sand and salt
true or false. all liquid and precipitate waste will be placed in a glass bottle waste container in the fume hood. however, cu and mg waste will be placed in the solid waste container.
The statement "all liquid and precipitate waste will be placed in a glass bottle waste container in the fume hood. However, Cu and Mg waste will be placed in the solid waste container" is generally true and reflects standard practices in laboratory waste disposal.
In the laboratory, it is important to properly dispose of any waste generated during experiments in order to minimize environmental impact and ensure safety. Liquid and precipitate waste is typically collected in glass bottles, which are more suitable for containing such materials and can be more easily recycled. Glass is also more chemically resistant and less likely to react with the waste materials compared to plastic containers. Furthermore, waste containers should be placed in the fume hood to prevent exposure to any harmful fumes and to minimize any risk of explosion or fire.
On the other hand, solid waste containers are typically used for the disposal of any solid waste materials generated during experiments, such as Cu and Mg waste. Copper (Cu) and magnesium (Mg) are metals that are often used in laboratory experiments and can produce solid waste materials. These solid waste materials can be safely disposed of in a solid waste container, which can be emptied and disposed of as general waste.
It is important to note that laboratory waste disposal practices may vary depending on the specific institution or laboratory. Some laboratories may have their own specific guidelines for waste disposal that should be followed. Additionally, some materials may require special handling or disposal procedures, such as hazardous or radioactive waste. In such cases, additional precautions may be necessary to ensure proper disposal and minimize potential risks to health and the environment.
In conclusion, proper disposal of laboratory waste is essential to maintain a safe and sustainable working environment. Collecting liquid and precipitate waste in glass bottles in the fume hood and solid waste in a designated container, such as Cu and Mg waste, are standard practices in laboratory waste disposal. Laboratories should establish clear guidelines for waste disposal and ensure that all personnel are trained and follow proper waste disposal procedures to ensure safety and environmental responsibility.
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the free-base form of cocaine has a solubility of 1.00 g in 6.70 ml ethanol (ch3ch2oh) . calculate the molarity of a saturated solution of the free-base form of cocaine in ethanol. express your answer to three significant figures and include the appropriate units.
The molarity of a saturated solution of the free-base form of cocaine in ethanol is 0.49M if it has a solubility of 1.00 g in 6.70 ml ethanol.
Given the mass of free-base form of cocaine = 1g
The volume of ethanol = 6.70mL
Molarity is calculated as moles of solute divided by the volume of solution
We know that Volume of solute + Volume of solvent gives Volume of solution.
Moles of solute cocaine ([tex]C17H21NO4[/tex]) = mass of cocaine/molar mass
moles = 1/303.353 = 0.00330 mol [tex]C17H21NO4[/tex]
Volume of solution = 6.7/1000 = 0.0067 L
Then the molarity = 0.00330/0.0067 = 0.49 mol/L or 0.49 M
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Why do ionic compounds need to reach stability in their charges?
Answer:
Ionic compounds need to reach stability in their charges because they are composed of ions, which are atoms or molecules that have gained or lost electrons. The positive and negative charges within an ionic compound must balance out in order to achieve stability. If the charges are not balanced, the compound will be unstable and will tend to react with other ions or molecules in an attempt to reach a state of stability. This is why ionic compounds form crystal lattices, with each ion arranged in a specific position in the lattice so that the positive and negative charges are evenly balanced.
Explanation:
Tell me if you still confuse
ALLEN
convert 24g of NaCk to formula units
Answer:
Explanation:
In the case of NaCl
Formula units, also known as formula mass, are the simplest repeating unit in a chemical compound. For a salt like sodium chloride (NaCl), one formula unit would be one Na+ ion and one Cl- ion.
For sodium chloride, the formula mass is the sum of the atomic masses of the individual atoms in the formula unit, which is approximately 58.44 g/mol.
In the case of NaCl, 24 g would be equivalent to approximately 0.41 moles. Since one formula unit of NaCl weighs 58.44 g, then 0.41 moles of NaCl would be equal to approximately 0.41 moles * 6.022 x 10^23 formula units = 2.47 x 10^23 formula units.
Therefore, 24 g of NaCl would be equal to approximately 2.47 x 10^23 formula units.
in a trial, a .300 m solution of no had a new molarity of 0.156 after 500 seconds. what is the rate of formation of n2 (in mol/l*s)?
In a trial, a 0.300 m solution of N[tex]_2[/tex] had a new molarity of 0.156 after 500 seconds. Therefore, 0.0003mol /l× s is the rate of formation of N[tex]_2[/tex].
What is rate of reaction?The reaction rate or rate of reaction is the rate at which a chemical reaction occurs, defined as proportional to the rise in product concentration per unit time and the reduction in reactant concentration per unit time.
The speeds of reaction might vary greatly.
rate of formation of N[tex]_2[/tex] = change in concentration/ change in time
=0 .300 - 0.156 /0- 500
=0.15/500
=0.0003mol /l× s
Therefore, 0.0003mol /l× s is the rate of formation of N[tex]_2[/tex].
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Why does it take a lot of energy for water to boil?
Water has weak bonds inside of the molecule.
Water has strong intermolecular forces (Hydrogen bonding)
Water has weak intermolecular forces (Dispersion forces)
Water has strong bonds inside of the molecule
The reason is because, water has strong intermolecular forces (Hydrogen bonding)
What is Hydrogen bonding?A hydrogen bond is an attraction that is mostly electrostatic between an electronegative atom with a lone pair of electrons and an electronegative atom that is covalently attached to a more electronegative "donor" atom or group.
Intermolecular hydrogen bonding and intramolecular hydrogen bonding are the two main types of hydrogen bonds. Most often, distinct molecules with either the same or different substances form intermolecular hydrogen bonds.
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what will be the most likely change in ph when the h ions in the solution is increased to twice its original concentration
The most likely change in pH when the H+ ions in the solution is increased to twice its original concentration is from 9.5 to 6.5.
This is because the pH of a solution is a measure of the concentration of H+ ions in the solution, and if the concentration is doubled, the pH will decrease. This can be shown mathematically using the equation pH = -log[H+]. For example, if the original concentration of H+ ions is 10^-9.5 moles/liter, then the pH will be 9.5. If the concentration of H+ ions is doubled to 10^-9 moles/liter, then the pH will become 6.5 (-log[10^-9]).
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complete question:What will be the most likely change in pH when the H+ ions in the solution is increased to twice its original concentration?
5.0 to 2.5
4.0 to 2.0
1.6 to 1.3
9.5 to 6.5
A student measures the mass of a solution before and after a chemical reaction takes place. in both cases the students measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. the student realizes that the ranges of uncertainty for each measurement overlap exactly. which claim can the student make?
The student can claim that the mass of the solution before and after the chemical reaction is the same.
This can be supported by the fact that the ranges of uncertainty for each measurement overlap exactly, indicating that the mass of the solution was the same before and after the reaction. This is because the ranges of uncertainty for the two measurements overlap exactly, meaning that the two values are statistically indistinguishable. Mathematically, this means that the absolute difference between the two measurements
[tex](50.25 g - 50.25 g)[/tex] is within the combined uncertainty of the two measurements[tex](0.05 g + 0.05 g).[/tex]
Therefore, the student can conclude that the mass of the solution has not changed.
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Is the disaccharide made from a glucose linked to a fructose?
Sucrose is the carbohydrates that disaccharide made from a glucose which is linked to a glucose named fructose.
Carbohydrates are one of the macro minerals, along with protein and fat, that give the energy necessary for the body to perform all it's diurnal functions. There are two general types of carbohydrates called simple carbohydrates and complex carbohydrates.
Simple carbohydrates are broken down by the body veritably snappily into glucose for energy, and complex carbohydrates have longer chains of glucose motes and thus take longer to digest.
Polysaccharide comes from word “ poly ” which means numerous. Polysaccharides formed of long chains or numerous motes of monosaccharides. It includes bounce, cellulose, glycogen.Two motes of a simple sugar that are linked each other form a disaccharide. One of the most common disaccharides is sucrose( known as table sugar), which is composed of one glucose and one fructose patch. Maltose is composed of two glucose motes, while lactose( milk sugar) is synthesized by glucose and galactose.Monosaccharides or simplest sugar is a structure blocks of carbohydrates. They're glucose, galactose and fructose.Learn more about Types of carbohydrates:
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how many co2 molecules would be formed by complete reaction in each case? (assume 100% actual yield.)
The pcr reaction that yields the most products would result in formation of two CO2 molecules. Two molecules of CO2 and four molecules of H2O will result from two molecule of CH3OH and three molecules of oxygen.
a material's smallest unit that has not only its physical and chemical characteristics. Molecules are made up of one maybe more atoms. Either these are of the same elements or another, a molecule is a group of atoms that are chemically different and linked together.
For instance, the combination of two hydrogen and oxygen atoms yields one molar of a material. The smallest unit of a substance that retains its composition and characteristics is a cell. It is constructed of atomic nuclei connected by chemical bonds. Moles are the foundation of chemistry.
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suppose a student starts with 2.3621 g of a sand mixture and separates the components into 1.3012 g of n a c l , 0.5560 g of s i o 2 , and 0.4503 g of c a c o 3 . based on the amount of recovered s i o 2 , what is the percent of s i o 2 in the starting mixture?
Starting with 2.3621 g of sand, a student divides the mixture into 1.3012 g of naCL, 0.5560 g of siO2, and 0.4503 g of cAcO3. The quantity of recoverable sio 2 So the beginning combination had 21.2066% of silicon dioxide in it.
A residue weighing 1.46g is produced after heating a 1.5 g mixture of SiO2 and Fe2O3 to a high temperature. 3Fe2O32Fe3O4+21O2 is the reaction that causes weight loss. Two double bonds join the two oxygen atoms to the silicon, giving SiO2 its linear structure. On the Si, there aren't any lone pairings. This would represent an instance of sp hybridization. SiO2 is tetrahedral when it is a polymer. SiO2 insulation layers are frequently applied using plasma-enhanced chemical vapor deposition (PECVD), but this method normally needs a relatively high deposition temperature of about 300 C.
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A 20.0 mL sample of 0.150 M KOH is titrated with 0.125 M HClO4 solution. Calculate the pH after the following volumes of acid have been added.a) 20.0mLb) 21.5mLc) 24.0mLd) 26.5mLe) 29.0 mL
The pH values after the given volumes of acid have been added are: a) 12.18, b) 12.39, c) 11.78, d) 11.25, and e) 10.79.
To solve the problem, we need to use the balanced chemical equation for the reaction between KOH and HClO4:
KOH + HClO4 -> KClO4 + H2O
At the start of the titration, before any HClO4 has been added, we have a solution of KOH with a concentration of 0.150 M. We can use this concentration to calculate the initial concentration of hydroxide ions in the solution:
[OH-] = 0.150 M
a) Before any HClO4 has been added, the volume of the solution is 20.0 mL. At this point, no HClO4 has reacted with the KOH, so the concentration of OH- ions is still 0.150 M. To calculate the pH, we can use the formula for the dissociation constant of water:
Kw = [H+][OH-] = 1.0 x 10^-14
pH = -log[H+]
[H+] = Kw/[OH-] = 6.67 x 10^-13 M
pH = -log(6.67 x 10^-13) = 12.18
b) After 1.5 mL of HClO4 has been added, the volume of the solution is 21.5 mL. The moles of HClO4 added is:
0.125 mol/L x 0.0015 L = 1.875 x 10^-5 mol
The moles of KOH initially in the solution is:
0.150 mol/L x 0.020 L = 0.003 mol
Thus, the moles of KOH remaining after reaction with HClO4 is:
0.003 mol - 1.875 x 10^-5 mol = 0.00298125 mol
The total volume of the solution is 21.5 mL, so the new concentration of KOH is:
0.00298125 mol / 0.0215 L = 0.1387 M
Using this concentration, we can calculate the concentration of OH- ions:[OH-] = 0.1387 M
Using the same formula for Kw and pH as before, we find that:
[H+] = 4.06 x 10^-13 M
pH = -log(4.06 x 10^-13) = 12.39
c) Repeating the above process for a volume of 24.0 mL gives:
[H+] = 1.64 x 10^-12 M
pH = -log(1.64 x 10^-12) = 11.78
d) For a volume of 26.5 mL:
[H+] = 5.67 x 10^-12 M
pH = -log(5.67 x 10^-12) = 11.25
e) For a volume of 29.0 mL:
[H+] = 1.63 x 10^-11 M
pH = -log(1.63 x 10^-11) = 10.79
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Matter is anything that has mass and………
O energy
O volume
O gravity
O plasma
Transcribed image text: A pipet is used to measure out 10 mL of water. If the mass of this volume of water is 9.990 g and the density of water is given as 0.9978 g/mL, what is the actual volume of water measured out? O 10.000 mL 9.990 mL O The actual volume measured out is impossible to tell 10.012 mL
10.012 mL is the actual volume of water measured out.
We can use the given information to determine the actual volume of water measured out using the formula:
The density of water is equal to the Mass of water divided by the Volume of water.
Rearranging this formula, we get:
Volume = Mass / Density
As per the given information,
Mass of water = 9.990 mL
Density of water = 0.9978 g/mL
Volume = 9.990 g / 0.9978 g/mL
Volume = 10.012 mL (rounded to three significant figures)
One milliliter of water has a volume of 1 cubic centimeter.
Therefore, the actual volume of water measured out is 10.012 mL. The closest option given in the transcribed image is 10.012 mL.
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What is the longest exothermic reaction?
Answer:intermetallic and thermite reactions.
Explanation:
.
a 9.35 g sample of a compound contains 5.97 g of iron, fe, 1.10 g of phosphorus, p, and oxygen, o. calculate the empirical formula for the compound.
The empirical formula for the compound with 9.35 g sample of a compound contains 5.97 g of iron, fe, 1.10 g of phosphorus, p, and oxygen, o is Fe₃PO₄ .
The empirical formula of a emulsion gives the simplest rate of the number of different tittles present, whereas the molecular formula gives the factual number of each different snippet present in a patch. If the formula is simplified also it's an empirical formula. The molecular formula is generally used and is a multiple of the empirical formula.
Converting grams to mole:
5.97 g Fe x 1 mol Fe / 55.8 g
= 0.106 moles Fe
1.10 g P x 1 mol P / 30.97 g
= 0.0355 moles P
O = 9.35 g - 5.97 g - 1.10 g
= 2.28 g O x 1 mol O / 16 g
= 0.142 moles.
Divide all by 0.0507 to try to get whole numbers:
0.106 / 0.0355 = 3 moles Fe
0.035 / 0.0355 = 1 moles P
0.142 / 0.0355 = 4 moles O
Empirical formula = Fe₃PO₄
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What is the difference between adhesion and cohesion properties?
Cohesion is the force that holds the same substance together, while adhesion is the force that holds different substances together.
Cohesion refers to the force of attraction between the same type of molecules within a substance. It is the bond between molecules of the same substance, such as the hydrogen bonds between water molecules. This property determines the internal strength of a substance and is responsible for the ability of a liquid to maintain its shape and not flow easily. For example, water is said to have high cohesion because its molecules are strongly attracted to each other, giving it its characteristic cohesive behavior.
Adhesion, on the other hand, refers to the force of attraction between two different substances. It is the bond between molecules of different substances, such as the attraction between water and a glass surface. This property determines the ability of a substance to stick to other substances, such as when a droplet of water adheres to a window. For example, gecko lizards can climb smooth surfaces because of the strong adhesion between their feet and the surface.
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an employment situation that pays bills but os largley unfluffing is?
Are you the significance of the value that comes from economic uses of forests, including at least two examples of the different types of economic, foresee us, and explain how the forest economic value relates to its ecological value
The economic value of forests is significant because forests provide a wide range of goods and services that are vital to human well-being and the economy. Some examples of the economic uses of forests are:
-Timber and wood products: Forests provide a source of wood for the construction of homes, furniture, and paper products. The forest industry is a major employer in many parts of the world.
-Non-timber forest products: Many forest products have important cultural and economic value, such as wild berries, mushrooms, medicinal plants, and non-timber forest products like resins and latex.
The economic value of forests is closely linked to their ecological value. Forests play a critical role in maintaining ecosystem services that are essential for human well-being, such as carbon sequestration, water purification, soil conservation, and biodiversity conservation. A well-managed forest that is sustainably harvested can maintain its ecological functions while providing economic benefits. In contrast, unsustainable forest practices can result in deforestation, soil degradation, and loss of biodiversity, which can have negative economic and ecological impacts.
In summary, forests are important for both their economic and ecological values. Sustainable forest management practices that balance economic benefits with ecological conservation are essential for ensuring the long-term health and vitality of forests and the ecosystems they support.
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3. Write a configuration for the following: 0
a. 2, 1, 0, -12
b. 4, 2, 0, -12
c. 5, 3, 2, -12
The electronic configuration can be used to know the details of atom.
What is electronic configuration?
The question is incomplete so I will educate you generally about electronic configuration.
The electronic configuration of an atom refers to the arrangement of electrons in its energy levels or orbitals.
The electrons in an atom occupy specific energy levels, with the innermost energy level having the lowest energy and being occupied by the most electrons. Each energy level can contain a certain number of electrons, and electrons occupy the lowest energy level available to them.
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What is the wavelength of a photon with frequency 5.7 x 10¹4 Hz? What color is it?
The number of oscillations made by the wave in one second is defined as the frequency. The wavelength of a photon with frequency 5.7 x 10¹⁴ Hz is 5.263 × 10⁻⁷.
What is wavelength?The wavelength of light is defined as the distance between the two successive crests or troughs of the light wave is defined as the wavelength. It is denoted by the letter λ (lambda).
The equation connecting the wavelength of light with frequency and speed of light is:
λ = c / ν
c - speed of light = 3.00 × 10⁸ m/s
ν - frequency of light = 5.7 x 10¹⁴ Hz
λ = 3.00 × 10⁸ m/s / 5.7 x 10¹⁴ Hz = 5.26 × 10⁻⁷
Thus the wavelength of light is 5.263 × 10⁻⁷ .
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the rate of decay of a radioactive substance is proportional to the amount of substance present. what is the half-life of a radioactive substance if it takes 3 years for one-third of the substance to decay?
A radioactive substance's rate of decay is inversely correlated with its concentration. The half-life of the radioactive substance is 2.08 years.
If the rate of decay of a radioactive substance is proportional to the amount of substance present, we can use the formula for exponential decay to model its behavior:
N = N0 * e^(-kt)
N0/2 = N0 * e^(-k * t1/2)
where t1/2 is the half-life.
1/2 = e^(-k * t1/2)
Taking the natural logarithm of both sides, we get:
ln(1/2) = -k * t1/2
Solving for t1/2, we get:
t1/2 = ln(2) / k
N/N0 = 1/3
1/3 = e^(-k * 3)
ln(1/3) = -k * 3
k = ln(3) / 3
Now we can substitute this value of k into the equation for t1/2 to find the half-life:
t1/2 = ln(2) / k
t1/2 = ln(2) / (ln(3) / 3)
t1/2 = 2.08 years
Therefore, the half-life of the radioactive substance is 2.08 years.
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butyl alcohol, c4h10o, is highly flammable. when the reaction for the combustion of butyl alcohol is properly balanced, what is the coefficient in front of o2?
When reaction for the combustion of butyl alcohol is properly balanced the coefficient in front of oxygen is 6.
Butyl alcohol is a hydrocarbon containing the which group as its primary group.
When butyl alcohol reacts with oxygen it gives carbon dioxide and water as a result the balanced chemical reaction equation for the combustion of butyl alcohol is given as,
C₄H₉OH + 6O₂ → 4CO₂ + 5H₂O
As we can see from the above stated chemical equation the efficient of butanol or butyl alcohol is 1, the coefficient of oxygen is 6, the coefficient of carbon dioxide is 4 and the coefficient of water is 5.
So, the answer to our question is 6.
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the electron configruration of an atom in the ground state is 2-4 the total number if occupied principal energey levels im this atom is
Answer:
2 energy levels
Explanation:
2 KCIO3 = 2 KCI + 3 O2
If 12.0 grams of potassium chlorate decompose, how many grams of potassium chloride will be
produced? Round your answer to the nearest hundredths.
Answer:
7.30g Potassium Chloride (KCl)
Explanation:
You are given 12.0 grams of KClO3, so start with that!
12g KClO3[tex]\frac{12g KClO3}{ } \frac{1 mol KClO3}{122.55g} \frac{2 mol KCl}{2 mol KClO3} \frac{74.55g KCl}{1 mol KCl} = 7.299877601[/tex]≈7.30
explian why the reactivity of the halogens decreases going down the group
The reactivities of the halogens(17th group) decrease down the group ( At < I < Br < Cl < F). This is due to the fact that atomic radius increases in size with an increase of electronic energy levels. This lessens the attraction for valence electrons of other atoms, decreasing reactivity.