The answer would be -3 13/81 (simplified)
All of the following are examples of quantitative data EXCEPT ________.
a. the amount of sleep normally gotten by the students in a class
b. the number of siblings that students have
c. the cholesterol levels of the students in a class
d. the exam scores for the students in a class
d. the gender of the students in a class
Answer:
e. the gender of the students in a class
Step-by-step explanation:
Quantitative data is measured is numbers. For example 1, 2, 3.5,...
Qualitative data are labels, that is, tall, short, male, female, Brazilian, Colombian,...
In this question:
The only data that is not measured in numbers is the gender of the studens in class, which can be male or female, they do not assume any numeric value. So the answer is e.
The quantitive data example does not include option e. the gender of the students in a class.
Data:Quantitative data is measured in numbers. like 1, 2, 3.5,..While on the other hand, Qualitative data are labels i.e. tall, short, male, female, etc. Based on this, the last option is correct.learn more about the data here: https://brainly.com/question/20296761
What is the slope of a line that is perpendicular to the line y = -1/2x + 5?
the answer choices are
-2
-1/2
1/2
2
Answer:
2
Step-by-step explanation:
as you can see the slope of the line y = -1/2x + 5 is -1/2
the slope m of any line perpendicular to it should verify : -1/2×m = -1
-1/2×m = -1
→ multiply both sides by -2
m = 2
In a sample of 800 adults, 214 think that most celebrities are good role models. Two us adults are selected from this sample without replacement. find the probability that both adults think most celebrities are good role models
Answer:
11449/160000
Step-by-step explanation:
The probability of selecting a single adult that thinks most celebrities are good role models is 214/800 = 107/400
The probability that both do is
(107/400)^2 =. 11449/160000
Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won:
20-24
25-29
30-34
35-39
40-44
45-49
50-54
Frequency:
29
36
15
3
6
2
2
Answer:
Lower class Limit: 20,25,30,35,40,45,50
Upper class limit: 24,29,34,39,44,49,54
Class width: 4
Class Midpoints : 22,27,32,37,42,47,52
Class Boundries : 19.5,24.5,29.5,34,5,39.5,44.5,49.5,54.5
Total Individuals: 93
Step-by-step explanation:
Lower class limit is the lowest value of a class e.g in the first class, the lowest value is 20. Similarly find lower class limit of othere classes.
Upper class limit is the highest value of a class e.g in the first class, the highest value is 24. Similarly find upper class limit of othere classes.
Class width is the difference between highest and lowest value of a class e.g 24-20=4
Class Midpoints can be found by adding lowest and highest value of a class and dividing it by 2 e.g (20+24)/2 = 22
Class boundaries are the halfway point which seperates the classes e.g for first classes, clasee boundry is (19.5,24.5)
Total individuals are founf by adding all the frequencies.
Simplify 1 ∙ x -x/1 .
Answer:
0
Step-by-step explanation:
1x=x
-x/1=-x
x-x=0
Answer:
Brainleist !
Step-by-step explanation:
x - x /1
x - x = nothing or 0
Please show how the following equasion Square root of 64+6/-2*-2 I cannot arrive at the answer of 9.5
Answer:
[tex]9.5[/tex]
Step-by-step explanation:
[tex]\sqrt{64}+\frac{6}{-2\left(-2\right)}[/tex]
[tex]\sqrt{64}+\frac{6}{2 \times 2}[/tex]
[tex]8+\frac{6}{4}[/tex]
[tex]\frac{19}{2}[/tex]
[tex]=9.5[/tex]
Answer:
Hello!
I hope that this is the answer you are looking for
=8.09320
That is the rounded answer.
I hope that helped you!
Step-by-step explanation:
Graph g(x), where f(x) = 2x − 5 and g(x) = f(x + 1).
A.) a line labeled g(x) that passes through points 0, negative 4 and 2, 0
B.) a line labeled g(x) that passes through points 0, negative 3 and 4, 5
C.) a line labeled g(x) that passes through points negative 5, negative 3 and 0, 7
D.) a line labeled g(x) that passes through points 0, negative 7 and 5, 3
Answer:
B.) a line labeled g(x) that passes through points 0, negative 3 and 4, 5
Step-by-step explanation:
I graphed both equation on the graph below to find the description of the graph of g(x).
Answer:
b for brakes?
Step-by-step explanation:
Andrew invests 79500 for 2 years akd earns 10017 of simple interest. Calculate the interest rate.
Answer:use mathematic pathway to calualte
Step-by-step explanation:
What’s the correct answer for this?
Answer:
B.
Step-by-step explanation:
In the attached file
CAN SOMEONE HELP ME IN THIS INTEGRAND QUESTION PLS PLS PLS PLS
''Find the surface area between the z = 1 and z = 4 planes of z = x ^ 2 + y ^ 2 paraboloid.''
Answer:
Step-by-step explanation:
Answer:
S = ⅙ π (65^³/₂ − 5^³/₂)
Step-by-step explanation:
z = x² + y², 1 < z < 4
Surface area is:
S = ∫∫√(1 + (fₓ)² + (fᵧ)²) dA
where fₓ and fᵧ are the partial derivatives of f(x,y) with respect to x and y, respectively.
fₓ = 2x, fᵧ = 2y
S = ∫∫√(1 + (2x)² + (2y)²) dA
S = ∫∫√(1 + 4x² + 4y²) dA
For ease, convert to polar coordinates.
S = ∫∫√(1 + 4r²) dA
S = ∫∫√(1 + 4r²) r dr dθ
At z = 1, r = 1. At z = 4, r = 4.
So 1 < r < 4, and 0 < θ < 2π. These are the limits of the integral.
S = ∫₀²ᵖⁱ∫₁⁴√(1 + 4r²) r dr dθ
To integrate, use u-substitution.
u = 1 + 4r²
du = 8r dr
⅛ du = r dr
When r = 1, u = 5. When r = 4, u = 65.
S = ∫₀²ᵖⁱ∫₅⁶⁵√u (⅛ du) dθ
S = ∫₀²ᵖⁱ (⅛ ∫₅⁶⁵√u du) dθ
S = ∫₀²ᵖⁱ (¹/₁₂ u^³/₂ |₅⁶⁵) dθ
S = ∫₀²ᵖⁱ (¹/₁₂ (65^³/₂ − 5^³/₂)) dθ
S = (¹/₁₂ (65^³/₂ − 5^³/₂)) θ |₀²ᵖⁱ
S = (¹/₁₂ (65^³/₂ − 5^³/₂)) (2π)
S = ⅙ π (65^³/₂ − 5^³/₂)
HELP! Look at the figure, PQRS. Find the values of x and y. a) x = 5, y = 7 b)x = 6, y = 8 c)x = 6, y = 9 d)x = 7, y = 10
Answer:
c) x = 6, y = 9
Step-by-step explanation:
The figure is a parallelogram. The diagonals of a parallelogram bisect each other, so each part of a given diagonal is equal to the other part.
3x = 2y
2x = y+3
__
Solving the second equation for y, we have ...
y = 2x -3
Substituting into the first equation gives ...
3x = 2(2x -3)
3x = 4x -6 . . . . simplify
6 = x . . . . . . . . .add 6 -3x
y = 2(6) -3 = 9 . . . . use the above expression for y
The values of x and y are (x, y) = (6, 9).
A study published in 2010 showed that city dwellers have a higher risk of developing anxiety disorders and a higher risk of developing mood disorders than those who live in the country. A follow-up study published in 2011 used brain scans of city dwellers and country dwellers as they took a difficult math test.1 To increase the stress of the participants, those conducting the study tried to humiliate the participants by telling them how poorly they were doing on the test. The brain scans showed very different levels of activity in stress centers of the brain, with the urban dwellers having greater brain activity than rural dwellers in areas that react to stress.
Required:
a. Is the 2010 study an experiment or an observational study?
i. Experiment
ii. Observational study
b. Can we conclude from the 2010 study that living in a city increases a person's likelihood of developing an anxiety disorder or mood disorder?
i. Yes
ii. No
c. Is the 2011 study an experiment or an observational study?
i. Experiment
ii. Observational study
d. Can we conclude from the 2011 study that living in a city increases activity in stress centers of the brain when a person is under stress?
i. Yes
ii. No
Step-by-step explanation:
a.It is a controlled experiment because it is clearly seen that an established hypothesis or study is being verified through an experiment, now in this case the hypothesis is tested through an experiment where excessive stress is placed on the Participants during their math exam to effectively verify that people in urban or city areas live with more stress than people in rural areas.
2..As now that the previously established hypothesis has been verified, it is concluded that people who live in the city live with more anxiety and stress than people who live in rural areas.
Dixie Showtime Movie Theaters, Inc., owns and operates a chain of cinemas in several markets in the southern U.S. The owners would like to estimate weekly gross revenue as a function of advertising expenditures. Data for a sample of eight markets for a recent week follow.
Market
Weekly Gross Revenue
($100s)
Television Advertising
($100s)
Newspaper Advertising
($100s)
Mobile
101.3
5
1.5
Shreveport
51.9
3
3
Jackson
74.8
4
1.5
Birmingham
126.2
4.3
4.3
Little Rock
137.8
3.6
4
Biloxi
101.4
3.5
2.3
New Orleans
237.8
5
8.4
Baton Rouge
219.6
6.9
5.8
(a) Use the data to develop an estimated regression with the amount of television advertising as the independent variable.
Let x represent the amount of television advertising.
If required, round your answers to four decimal places. For subtractive or negative numbers use a minus sign even if there is a + sign before the blank. (Example: -300)
= + x
Test for a significant relationship between television advertising and weekly gross revenue at the 0.05 level of significance. What is the interpretation of this relationship?
The input in the box below will not be graded, but may be reviewed and considered by your instructor.
(b) How much of the variation in the sample values of weekly gross revenue does the model in part (a) explain?
If required, round your answer to two decimal places.
%
(c) Use the data to develop an estimated regression equation with both television advertising and newspaper advertising as the independent variables.
Let x1 represent the amount of television advertising.
Let x2 represent the amount of newspaper advertising.
If required, round your answers to four decimal places. For subtractive or negative numbers use a minus sign even if there is a + sign before the blank. (Example: -300)
= + x1 + x2
Is the overall regression statistically significant at the 0.05 level of significance? If so, then test whether each of the regression parameters β0, β1, and β2 is equal to zero at a 0.05 level of significance. What are the correct interpretations of the estimated regression parameters? Are these interpretations reasonable?
The input in the box below will not be graded, but may be reviewed and considered by your instructor.
(d) How much of the variation in the sample values of weekly gross revenue does the model in part (c) explain?
If required, round your answer to two decimal places.
%
(e) Given the results in part (a) and part (c), what should your next step be? Explain.
The input in the box below will not be graded, but may be reviewed and considered by your instructor.
(f) What are the managerial implications of these results?
The input in the box below will not be graded, but may be reviewed and considered by your instructor.
Determine whether the given value is a statistic or a parameter.A homeowner measured the voltage supplied to his home on 42 random days, and the average (mean) value is 127.1 volts.A) The given value is a statistic for the year because the data collected represented a population.
B) The given value is a parameter for the year because the data collected represent a sample.
C) The given value is a parameter for the year because the data collected represent a population.
D) The given value is a statistic for the year because the data collected represent a sample.
Answer:
[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]
And for this case the sample mean is
[tex]\bar X = 127.1[/tex]
And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:
D) The given value is a statistic for the year because the data collected represent a sample.
Step-by-step explanation:
For this case we know that a homeowner take a random sample of 42 voltage values ina year and he calculate the sample mean with this formula:
[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]
And for this case the sample mean is
[tex]\bar X = 127.1[/tex]
And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:
D) The given value is a statistic for the year because the data collected represent a sample.
CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS
''Find the surface area between the z = 1 and z = 4 planes of z = x ^ 2 + y ^ 2 paraboloid.''
Due to the symmetry of the paraboloid about the z-axis, you can treat this is a surface of revolution. Consider the curve [tex]y=x^2[/tex], with [tex]1\le x\le2[/tex], and revolve it about the y-axis. The area of the resulting surface is then
[tex]\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6[/tex]
But perhaps you'd like the surface integral treatment. Parameterize the surface by
[tex]\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k[/tex]
with [tex]1\le u\le2[/tex] and [tex]0\le v\le2\pi[/tex], where the third component follows from
[tex]z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2[/tex]
Take the normal vector to the surface to be
[tex]\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k[/tex]
The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:
[tex]\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}[/tex]
Then the area of the surface is
[tex]\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv[/tex]
which reduces to the integral used in the surface-of-revolution setup.
8,36 : 1,6
pleaseeeeeeeeee
Answer:
209 : 40 or 5.225 : 1
Step-by-step explanation:
Your calculator can tell you the ratio 8.36/1.60 is 5.225. Writing that decimal as a fraction, you can factor out 25 to get ...
8.36 : 1.6 = 5.225 : 1 = 5225 : 1000 = (25)(209) : (25)(40) = 209 : 40
You need to haul a load of patio bricks to a job site. Each brick weighs 4 pounds 14 ounces. Truck can carry a 3/4 - ton load. How many bricks can the truck carry in a full load?
Answer:
339 bricks.
Step-by-step explanation:
We have the weight of each brick and what the truck can support. Therefore what we must do is pass all to the same unit of measurement to calculate the quantity of bricks.
In this case we will pass everything to pounds.
We have that a 1 pound is 16 ounces, therefore 14 would be:
14 ounces * 1 pound / 16 ounces = 0.875 pounds
In addition we have that 1 ton is 2204.62 pounds, therefore 3/4 would be:
3/4 ton * 2204.62 pounds / 1 ton = 1653.467 pounds
Therefore, in total the brick weighs 4,875 pounds (4 + 0.875) and the truck can support 1653,467 pounds, the number of bricks would be:
1653.467 / 4.875 = 339.17
In other words, it can support about 339 bricks.
Find the number of ways of arranging the numbers 1,2,3,4,5,6,7, if no two even numbers can be adjacent, and no two odd numbers can be adjacent.
Answer:
24 ways
Step-by-step explanation:
1) In Combinatorics when we arrange a number and the order matter, we call it arrange the possibilities. For this exercise let's not use formulas but reasoning.
2) For this case we need a two figure number. Since we have seven numbers.
Since there is no repetition, all the possibilities are:
[tex]7*6=42[/tex]
3) But there is a restriction it's forbidden adjacent even and odd numbers: These numbers we don't want them:
13 15 17
24 26
31 35 37
42 46
51 53 57
62 66
71 73 75
18 non desirable results
The total arrangements minus the not possible combinations, will match the possible results:
[tex]42-18=24[/tex]
3) Just for checking, we have here the allowed combinations:
12 14 16
21 23 25 27
32 34 36
41 43 45 47
52 54 56
61 63 65 67
72 74 76
A total of 24 possible ways.
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1082 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.53 hours with a standard deviation of 0.71 hour.
a. Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day
b. The nutritionist is 95% confident that the amount of time spent eating or drinking per day for any individual is between_________and_________hours.
c. There is a 95% probability that the mean amount of time spent eating or drinking per day is between and hours.
d. The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day is between_______and_____________
Answer:
a) The 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day is (1.49, 1.57).
d) The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day for any individual is between 1.49 and 1.57 hours.
(c and b can not be concluded from the confidence interval)
Step-by-step explanation:
We have to calculate a 95% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=1.53.
The sample size is N=1082.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.71}{\sqrt{1082}}=\dfrac{0.71}{32.89}=0.022[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=1082-1=1081[/tex]
The t-value for a 95% confidence interval and 1081 degrees of freedom is t=1.962.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.962 \cdot 0.022=0.042[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex][tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex]
The 95% confidence interval for the mean is (1.49, 1.57).
What is the inverse of the function f(x) = 2x + 1?
1
Oh(x) =
Ex-
2
2
O h(x)
1
2
1
2
h(x) =
Ex-
- 3x + 2
h(x) =
X
+
Save and Exit
Next
Mark this and return
Answer:
The inverse function is [tex]f^{-1}(x) = \frac{x-1}{2}[/tex]
Step-by-step explanation:
We have the following function:
y = 2x + 1
Finding the inverse:
Exchange y and x, and then isolate y again. So
y = 2x + 1
Exchange y and x
x = 2y + 1
2y = x - 1
[tex]y = \frac{x-1}{2}[/tex]
So
The inverse function is [tex]f^{-1}(x) = \frac{x-1}{2}[/tex]
The people at the party ate 16 chocolate chip cookies and 26 sugar cookies. What percent of the cookies were sugar cookies?
Answer:
61%
Step-by-step explanation:
16/26 x 100 = 61.538461
You have to round it up if the question tells you to round it up.
hope it helps! :)
Answer:
62%
Step-by-step explanation:
42 x 62% = 26.04
I am sorry if you get this wrong. I really hope this helps.
what is X:
|4x−1|=3
|x|=−4
Answer:
1
Step-by-step explanation:
A sports shop sells tennis rackets in 4 different weights, 2 types of string, and 3 grip sizes. How many different rackets
could they sell?
O 32
O 18
0 24
0 9
Answer: C) 24
Step-by-step explanation:
first we take down the information given to us
sports shop sells rackets in
4 different weights
2 types of strings
3 grip sizes
Now to get the number of different rackets they could sell, you simply take the multiplication of the number of racket gripe sizes, the types of strings and different weights they sell
so
4 * 2 * 3 = 24
therefore the sport shop could sell up to 24 different rackets .
Answer:
24
Step-by-step explanation: got it right on my test
The sum of two consecutive integers is −19. Find the integers.
Answer:
-9 and -10
Step-by-step explanation:
x + x+1=-19
2x+1=-19
2x=-19-1
2x=-20
x=-10
x+1
-10+1=-9
Answer:
[tex]-9[/tex]
[tex]-10[/tex]
Step-by-step explanation:
[tex]x+x+1=-19[/tex]
[tex]2x+1=-19[/tex]
[tex]2x=-19-1[/tex]
[tex]2x=-20[/tex]
[tex]x=-20 \div 2[/tex]
[tex]x=-10[/tex]
[tex]x+x+1=-19[/tex]
[tex]x+1=-19-x[/tex]
[tex]-10+1=-19-(-10)[/tex]
[tex]-9=-19+10[/tex]
[tex]-9=-9[/tex]
Data on return-to-pay ratios was collected from CEOs of companies within both the low-tech industry and the consumer products industry.
Low-Tech Consumer Products
Sample size 14 12
Sample mean 157 218
Sample Variance 1563 1602
Assume population variances are unequal.
(a) The point estimate of the difference between the means of the two populations is
(b) The standard error for the difference between the two means is
(c) The correct distribution to use is :
t-distribution with 26 degrees of freedom
t-distribution with 23 degrees of freedom
normal distribution
t-distribution with 24 degrees of freedom
Answer:
Step-by-step explanation:
The confidence interval for the difference of two population means is expressed as
Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)
Where
x1 = sample mean of low-tech industry
x2 = sample mean of consumer products industry
s1 = sample standard deviation low-tech industry
s2 = sample standard deviation for consumer products industry
n1 = number of samples of low-tech industry
n2 = number of samples of consumer products industry
a) x1 - x2 is the point estimate of the difference between the means of the two populations
Therefore,
Point estimate = 157 - 218 = - 61
b) the formula for standard error is expressed as
√(s1²/n1 + s2²/n2)
Variance = standard deviation²(s²)
s1² = 1563
s2² = 1602
Standard error = √(1563²/14 + 1602²/12) = 623.2
c) Degree of freedom =
(n1 - 1) + (n2 - 1) = (14 - 1) + (12 - 1) = 24
t-distribution with 24 degrees of freedom
According to the data given, we have that:
a) 61
b) 15.65
c) t-distribution with 24 degrees of freedom
Item a:
The point estimate is the difference between the two sample means, hence:
218 - 157 = 61.
Item b:
For each sample, the standard errors are:
[tex]s_l = \sqrt{\frac{1563}{14}} = 10.57[/tex]
[tex]s_h = \sqrt{\frac{1602}{12}} = 11.54[/tex]
For the difference of the two means, it is:
[tex]s = \sqrt{s_l^2 + s_h^2} = \sqrt{10.57^2 + 11.54^2} = 15.65[/tex]
Item c:
Samples of 14 and 12, hence 14 + 12 - 2 = 24 df.
A similar problem is given at https://brainly.com/question/12490448
Please help me with this question!!
Answer:
IV
Step-by-step explanation:
Cosine is positive in quadrants I and IV.
Cosecant (also sine) is negative in quadrants III and IV.
The quadrant where cos > 0 and csc < 0 is quadrant IV.
Square A"B"C"D" is the final image after the rule was applied to square ABCD. On a coordinate plane, a square A double-prime B double-prime C double-prime D double-prime has points (negative 5, negative 3), (negative 3, negative 1), (negative 1, negative 3), (negative 3, negative 5). What are the coordinates of vertex A of square ABCD? (–1, –6) (–1, –2) (–1, 6) (–2, 1)
Answer:
The answer is (-2 , 1 ) or D on Edge
Step-by-step explanation:
The coordinates of vertex A of square ABCD is (-1, -2).
What are coordinates?Coordinates are two numbers (Cartesian coordinates), or sometimes a letter and a number, that locate a specific point on a grid, known as a coordinate plane.
Given:
A(-5, -3), B(-3, -1), C(-1, -3) and D(-3, -5)
By using the rule
T(-4, -1)
So, the coordinate of Vertex A will be
A( -5 + 4, -3 + 1)
=A(-1, -2)
Learn more about coordinates here:
https://brainly.com/question/7869125
#SPJ2
Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that involves mailing discount coupons to all their credit card customers. This promotion will be considered a success if more than of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of credit card customers. Click on the datafile logo to reference the data.
a. Develop hypotheses that can be used to test whether the population proportion of those who will use the coupons is sufficient to go national.b. The file Eagle contains the sample data. Develop a point estimate of the population proportion.c. Use αα= .05 to conduct your hypothesis test. Should Eagle go national with the promotion?
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. It is considering a promotion that involves mailing discount coupons to all its credit card customers. This promotion will be considered a success if more than 10% of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of 100 credit card customers. Out of the 100 customers, 13 customers said that they used the discount coupons to make a purchase at a Eagle Outfitters store. Use a 0.05 level of significance. (a) Develop the null and alternative hypotheses that can be used to test whether the population proportion of those who will use the coupons is sufficient to go national. (b) Compute the sample proportion. (c) Compute the test statistic. (d) Compute the critical value. (e) Based on the critical value, do we reject H0 or do we not reject H0? (f) Based on the result of the hypothesis test, should Eagle Outfitter go national with the promotion?
Solution:
a) We would set up the hypothesis test.
For the null hypothesis,
H0: p ≥ 0.1
For the alternative hypothesis,
Ha: p < 0.1
This is a left tailed test
Considering the population proportion, probability of success, p = 0.1
q = probability of failure = 1 - p
q = 1 - 0.1 = 0.9
b) Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 13
n = number of samples = 100
p = 13/100 = 0.13
c) We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.13 - 0.1)/√(0.1 × 0.9)/100 = 1
The calculated test statistic is 1 for the right tail and - 1 for the left tail.
d) Since α = 0.05, the critical value is determined from the normal distribution table.
For the left, α/2 = 0.51/2 = 0.025
The z score for an area to the left of 0.025 is - 1.96
For the right, α/2 = 1 - 0.025 = 0.975
The z score for an area to the right of 0.975 is 1.96
e) In order to reject the null hypothesis, the test statistic must be smaller than - 1.96 or greater than 1.96
Since - 1 > - 1.96 and 1 < 1.96, we would fail to reject the null hypothesis.
Therefore, based on the result of the hypothesis test, the Eagle Outfitter should go national with the promotion
1. Is (6,7) a solution to the inequality y> 2x - 5?
2. Mathematically prove that it is or isn't below.
Answer:
[tex]\fbox{\begin{minipage}{8em}Not a solution\end{minipage}}[/tex]
Step-by-step explanation:
Step 1: Consider the assumption:
Generally, [tex](6, 7)[/tex]) is supposed to be the pair of 2 components, in which, the first component is x-component (domain), the second component is y-component (range).
Hence, [tex]x = 6, y = 7[/tex]
Step 2: Substitute [tex]x[/tex] and [tex]y[/tex] into the inequality
[tex]y > 2x - 5[/tex]
<=> [tex]7 > 2*6 - 5[/tex]
Step 3: Simplify
<=> [tex]7> 12 - 5[/tex]
<=> [tex]7 > 7[/tex]
Step 4: Evaluate
Invalid
Reason: [tex]7 = 7[/tex]
Step 5: Conclude
[tex](6, 7)[/tex] is not a solution to the inequality [tex]y > 2x - 5[/tex]
Hope this helps!
:)
Find the measure of a positive angle and a negative angles that are coterminal with each given angle 400°
Answer: see below
Step-by-step explanation:
To find a coterminal angle, add or subtract 360° to the given angle as many times as needed to get a positive or negative angle.
I should mention that there are an infinite number of answers!
4) 400°
I can subtract 360° to get a positive angle of 40°
I can subtract another 360° to get a negative angle of -320°
5) -360°
I can subtract 360° to get a negative angle of -720°
I can add 360° twice to get a positive angle of 360°
6) -1010°
I can add 360° to get a negative angle of -650°
I can add 360° another 3 times to get a positive angle of 720°
7) 567°
I can subtract 360° to get a positive angle of 207°
I can subtract another 360° to get a negative angle of -153°
8) -164°
I can subtract 360° to get a negative angle of -524°
I can add 360° to get a positive angle of 194°
9) 358°
I can subtract 360° to get a negative angle of -2°
I can add 360° to get a positive angle of 718°
