Answer: It’s 2
Step-by-step explanation:
look at picture
In a group of 50 patrons, 14 patrons like lattes and espressos, 11 patrons like
espressos and cappuccinos, 7 patrons like lattes and cappuccinos, and 3
patrons like all 3 coffee drinks. Altogether, 22 patrons like lattes, 30 patrons
like espressos, and 23 patrons like cappuccinos. How many patrons don't like
any of these coffee drinks?
Answer:the answer would be 4. Hope this helps.
Step-by-step explanation:
Using the formula of union of three events, the number of patrons who didn't like any of given coffee drinks = 4.
What is union of three events?Union of three events : P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C).
n (latte ∩ espressos) = 14
n (espressos ∩ cappuccinos) = 11
n (lattes ∩ cappuccinos) = 7
n (latte ∩ espressos ∩ cappuccinos) = 3
n (lattes) = 22
n (espressos) = 30
n (cappuccinos) = 23
n(latte ∪ espressos ∪ cappuccinos) =
= n (lattes) + n (espressos) + n (cappuccinos) - n (latte ∩ espressos) - n (espressos ∩ cappuccinos) - n (lattes ∩ cappuccinos) + n (latte ∩ espressos ∩ cappuccinos)
= 22 + 30 + 23 - 14 - 11 - 7 + 3
= 46
n (universe) = 50
Number of patrons who didn't like any of these drinks =
= n (universe) - n (latte ∪ espressos ∪ cappuccinos) = 50 - 46 = 4
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A typical classroom is a rectangle with dimensions of 20 feet wide by 25 feet long, and the area needed for each person in the room is approximately 28 square feet, what fraction of the total area in a classroom is needed for each person? What is the largest number of people that would fit in an average sized classroom while practicing good social distancing?
Answer:
A fraction of 0.056 of the classroom is needed for each student.
A typical classroom can acomodate up to 17 persons while practicing good social distancing.
Step-by-step explanation:
We have a classroom that is a recatngle with dimensions of 20 feet wide by 25 feet long.
The total area of the classroom is:
[tex]A=w\cdot l=20\cdot25=500[/tex]
As the area of the classromm is 500 square feet and we need 28 square feet for each student, the fraction that is needed for each student is:
[tex]f=\dfrac{A_{\text{student}}}{A_{\text{classroom}}}=\dfrac{28}{500}=0.056[/tex]
A fraction of 0.056 of the classroom is needed for each student.
The largest number of students that would fit in an average sized classroom while practicing good social distancing can be calculated dividing the area of the classroom by the area needed for each student. This is equal to the inverse of the fraction calculated previously:
[tex]n=\dfrac{1}{f}=\dfrac{1}{0.056}\approx17.86[/tex]
A typical classroom can acomodate up to 17 persons while practicing good social distancing.
Account A and Account B both have a principal of $2,000 and an annual interest rate of 5%. No additional deposits or withdrawals are made. Account A earns simple interest. Account B earns interest compounded annually. Compare the amounts in the two accounts after 20 years. Which earns more interest? How much more?
Answer:
Which earns more interest = Account B
How much more = $1,306.60
Step-by-step explanation:
Given;
Principal P = $2,000
Interest rate r = 5% = 0.05
Time t = 20 years
For account A;
Simple interest = P×r×t
Substituting the values;
Simple interest = 2,000 × 0.05 × 20 = $2000
Interest on account A = $2,000
For account B;
Compound interest
Final amount = P(1 + r)^t
Since it's compounded annually
Substituting the values;
Final amount = 2000(1+0.05)^20
Final amount = $5306.60
Interest = final amount - principal = $5306.60 -$2000
Interest = $3,306.60
Therefore, account B earns more interest.
Difference = account B interest - account A interest
Difference = $3,306.60 - $2,000
Difference = $1,306.60
What is the product?
(45+2)(5s2+ 10s+3)
Answer:
your answer is 127596 because you would take (45+2) first then you would take (55^2+10s+3) then you multiply them
Step-by-step explanation:
The probability that a member of a certain class of homeowners with liability and property coverage will file a liability claim is 0.04, and the probability that a member of this class will file a property claim is 0.10. The probability that a member of this class will file a liability claim but not a property claim is 0.01. Calculate the probability that a randomly selected member of this class of homeowners will not file a claim of either type.
Answer:
The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
Step-by-step explanation:
Denote the events as follows:
X = liability claim will be filled
Y = property claim will be filled
The information provided is:
P (X) = 0.04
P (Y) = 0.10
P (X ∩ Y') = 0.01
The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:
[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]
According to the law of total probability:
[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]
Use the law of total probability to determine the value of P (X ∩ Y) as follows:
[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]
The value of P (X ∩ Y) is 0.03.
Compute the value of P (X ∪ Y) as follows:
[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]
[tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]
Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
What’s the correct answer for this?
Answer:
D.
Step-by-step explanation:
Since a quadrilateral inscribed in a circle has its opposite angles adding up to 180°
So,
<MNO + <OLM = 180
82 + <OLM = 180
<OLM = 180-82
<OLM = 98°
How can sums and differences of cubes be identified for factoring?
Answer:
Step-by-step explanation:
The sum of two perfect cubes breaks down into two factors, the first is the sum of their cube roots, and the second is made up of the square of the first root minus the product of both roots plus the square of the second root.
The difference of two perfect cubes is decomposed into two factors, the first is the difference of their cube roots, and the second is made up of the square of the first root plus the product of both roots plus the square of the second root.
Find the value of the logarithm.
log 110
Round your answer to the nearest thousandth.
Answer:
Log 110 = 2.041
Step-by-step explanation:
Log 110 can be simplified and reduced to
Log 110 = log (10*11)
Log 110 = log10 + log11
But log10 = 1
Log 11= unknown = x
10^x= 11
X= 1.0413926
Log 110 = 1+1.0413926
Log110 = 2.0413926
Log 110 = 2.041
The sum is type answer as integer proper fraction or mixed number simplify answer
Answer:
[tex]9\dfrac{5}{6}[/tex]
Step-by-step explanation:
[tex]5\dfrac{1}{6}+4\dfrac{2}{3}=\\\\5\dfrac{1}{6}+4\dfrac{4}{6}=\\\\9\dfrac{5}{6}[/tex]
Hope this helps!
Estimate and then solve the equation. X - 17 4/5=-13 1/5
Answer: 5 (estimate)
Step-by-step explanation:
x - 17 4/5 = -13 1/5
Estimate: x - 18 = -13
x - 18 + 18 = -13 + 18
x = 5
actual answer without estimating using exact numbers is 4 3/5 (so estimate is reasonable)
What is the value of y at the point where the graph of an equation crosses the x-axis?
Answer:
0
Step-by-step explanation:
The x-axis corresponds to the line y = 0. All points on the x-axis have a y-value of zero.
Mitch opened a retirement account that has an annual yield of 4.2% compounding annually. He is planning on retiring in 13 years. How much must he deposit into that account each year so that he can have a total of $1,000,000 by the time he retires?
Answer:
P = 4878
Step-by-step explanation:
So we'll use the formula
A = p(1+r/n)^ (nt)
A = 1000000
P is the unknown
R = 4.2
N = 13
T = 13
1000000= p ( 1+ 0.42/13)^ 169
1000000 = p (1.032)^169
1000000= p 205
P = 4878
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.
Answer:
its b I belive
Step-by-step explanation:
Answer:
The answer is B.
Step-by-step explanation:
In order to find (f-g)(x), you have to subtract g(x) from f(x) :
[tex]f(x) = {3}^{x} + 10[/tex]
[tex]g(x) = 2x - 4[/tex]
[tex](f - g)(x) = {3}^{x} + 10 - 2x - ( - 4)[/tex]
[tex](f - g)(x) = {3}^{x} + 10 - 2x + 4[/tex]
[tex](f - g)(x) = {3}^{x} - 2x + 14[/tex]
Very confused, need help quick! (see attachment) Simplify and show your work.
Answer:
27/(4x^6y^8)
Step-by-step explanation:
Target the variables first. (x^a)^b is the same as x^(a x b).
In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.
Same principle on the bottom. the denominator is x^12 and y^20.
In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)
simplify (6^7)^3
will give brainlist
Answer:
The answer is D.
Step-by-step explanation:
You have to apply Indices Law,
[tex] { ({a}^{m}) }^{n} \: ⇒ \: {a}^{mn} [/tex]
So for this question :
[tex] { ({6}^{7}) }^{3} [/tex]
[tex] = {6}^{7 \times 3} [/tex]
[tex] = {6}^{21} [/tex]
If you found that the 95% confidence interval to estimate the true proportion of visitors to Niagara Falls that are from the United States was (0.5216, 0.6784), does this provide evidence that a majority of visitors to Niagara Falls are from the United States
Answer:
The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States
Step-by-step explanation:
We want to see if the majority of Niagara Falls visitors are from the United States.
Looking at the confidence interval
We have to see if the lower end of the interval is higher than 0.5.
In this question:
The 95% confidence interval to estimate the true proportion of visitors to Niagara Falls that are from the United States was (0.5216, 0.6784).
The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States
Solve for x. 6−x3=3 x=9 x=−9 x=27 x=−27
A researcher conducts two studies. Study 1 uses a one-way between-subjects ANOVA. and Study 2 uses a within-subjects ANOVA. If the number of groups and participants per group are the same in each study, then in which study was the total number of participants larger? Explain.
Answer:
One way between subjects ANOVA
Step-by-step explanation:
In the between groups ANOVA, different people tests each conditions corresponding to the variables in the study while for the within groups ANOVA, the same person tests for all conditions corresponding to the variables. This way the total number of participants will be larger in the between subjects ANOVA group.
Please answer this correctly
Answer:
10-19 ⇒ 3
50-59 ⇒ 4
Answer:
# of ties # of racks
10-19 3
50-59 4
Step-by-step explanation:
Using the Stem and Leaf plot, our data is:
11, 12, 16
21
32, 34, 36, 37, 39
41, 45
51, 52, 53, 56
# of ties # of racks
10-19 3 (11, 12, 16)
50-59 4 (51, 52, 53, 56)
My son and I are stuck on this one. Can anyone give some insight to this problem? Thank you.
Answer:
I made is clear for you, now you may match each one
Step-by-step explanation:
f(1)= 11, f(n)= 3*f(n-1)
11*3= 33, 33*3= 99, 99*3= 297, ...11, 33, 99, 297...⊕ middle
f(1)= -18, f(n)= f(n-1)+21
-18+21= 3, 3+21= 24, 24+21= 45, ...-18, 3, 24, 45, ...f(1)= -18, f(n)= f(n-1) + 22
-18+22= 4, 4+22= 26, 26+22= 48, ...-18, 4, 26, 48, ...f(1)= -18, f(n)= 2*f(n-1)
-18*2= -36, -36*2= -72, -72*2= -144, ...- 18, -36, -72, -144...⊕ bottom
f(1)= -18, f(n)= 6*f(n-1)
-18*6= -108, -108*6= -648, -648*6= -3888, ...- 18, - 108, - 648, -3888, ...⊕ top
f(1)= 11, f(n)= f(n-1) + 22
11+22= 33, 33+22= 55, 55+22= 77, ...11, 33, 55, 77, ...
A candidate scored 32 marks out of 80,
find his percentage score.
A. 20% B.32% 0.40% D. 48% E80%
Answer:
40%
Step-by-step explanation:
you need to divide 80 by 8 to get 10 and then divide 32 by 8 aswell. this gives you 4/10 which is equivalent to 40/100 or 40%
Candidate percent scored is, 40%.
What is mean by Percentage?A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
Given that;
A candidate scored 32 marks out of 80.
Now, Total marks = 80
And, A candidate score = 32
Hence, The percent score is,
⇒ 32 / 80 × 100
⇒ 3200 / 80
⇒ 40%
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At Central High School, 55% of students play a school sport. Also, 24% of the student population is in ninth grade. To ninth graders are allowed to play school sports. If two students are selected at random to receive a gift card, what is the probability that one will go to a student athlete and one will go to a freshman? Write the answer as a percent rounded to the nearest tenth of a percent.
Answer:
Probability that one of the giftcards will go to a student athlete and one will go to a freshman = 26.4%
Step-by-step explanation:
At Central High School, 55% of students play a school sport. Also, 24% of the student population is in ninth grade. No ninth graders are allowed to play school sports. If two students are selected at random to receive a gift card, what is the probability that one will go to a student athlete and one will go to a freshman? Write the answer as a percent rounded to the nearest tenth of a percent.
Solution
Probability that a student plays a school sport, that is, probability that a student is a student athlete = P(S) = 55% = 0.55
Probability that a student is in the ninth grade, that is, probability that a student is a freshman = P(F) = 24% = 0.24
It was given that no freshman is allowed to play sports, hence, it translates that the event that a student is a student athlete and the event that a student is a freshman are mutually exclusive.
P(S n F) = 0
If two students are then picked at random to receive a gift card, we require the probability that one will go to a student athlete and one will go to a freshman.
Probability that the first one goes to a student athlete = P(S) = 0.55
Probability that the second one goes to a freshman ≈ 0.24
Probability that the first one goes to a freshman = P(F) = 0.24
Probability that the second one goes to a student athlete ≈ 0.55
Probability that one will go to a student athlete and one will go to a freshman
= (0.55 × 24) + (0.24 × 0.55)
= 0.132 + 0.132
= 0.264
= 26.4% in percent to the nearest tenth.
Hope this Helps!!
Examine the details of the chi‑square test and conclude in context. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence in the study among those drinking cranberry juice daily. The conditions for inference are not met. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those abstaining from both drinks. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those drinking Lactobacillus drink. There is good evidence (cite P-value) that, in the population of women just treated for a UTI, women drinking cranberry juice daily have fewer UTI recurrences, on average. Question Source: Baldi 4e - The Practice Of Statistics
Answer:
Step-by-step explanation:
We will examine and outline the details of this chi-square test and then conclude in context.
(A) A population of women have just been treated for a urinary tract infection.
(B) Since the chi-square test is done for categorical variables, we will pick out the variable involved here.
That variable is: "UTI Recurrence"
Hence, we are looking at the recurrence of a urinary tract infection, among samples of the population of women who have recently been treated of it.
(C) There are three samples from this population and they are distinguished thus:
SAMPLE 1: Those drinking cranberry juice daily
SAMPLE 2: Those taking lactobacillus drink
SAMPLE 3: Those abstaining from both drinks (the placebo sample)
(D) The result of the test gave good evidence that SAMPLE 1 has the lowest value of the categorical variable involved; as compared to the values from SAMPLE 2 and SAMPLE 3.
In other words, on the average (average here is equal to mode or frequency of occurrence of the variable), the lowest number of UTI recurrences stems from Sample 1, as compared to the numbers of UTI recurrences in the other two samples
Zareen has 24 minutes to work on her math homework in each problem is taking her 2/3 of a minute on average to complete which expression can be used to determine the number of my problem she will be able to complete in the time she has
Answer:
Hey mate , here is your answer. Hope it helps you
Step-by-step explanation:
Given Zareen has 24min to work on her math homework, and each problem is taking her 2/3 of a minute
As give one problem takes
24*(2/3) minutes = 16
Hence
2/3 divided by 24
Find an Equation of a line with the given slope that passes through the point. Write the equation in the form Ax + By=C
M=3/2, (7,-2) -problem
Bridge math sails
Module 4B2
Answer:
c = 24 can i get brainliest
Step-by-step explanation:
What is the next number in the sequence: 3, 8, 12, 48, 29, __
Answer:
144
Step-by-step explanation:
Answer:
116
Step-by-step explanation:
3x4=12
12x4=48
8x4=32
32-3=29
29x4=116
Hope it's clear
A laptop has a listed price of $875.98 before tax. If the sales tax rate is 6.5%, find the total cost of the laptop with sales tax included.
Round your answer to the nearest cent, as necessary.
please!
Answer:
$932.92
Step-by-step explanation:
6.5% = 0.065
(875.98) + (875.98)(0065)
(875.98) + (56.9387)
932.9187
$932.92
Answer:
$[tex]932.92[/tex]
Step-by-step explanation:
[tex]6.5/100=0.65[/tex]
Next, multiply the price by the sales tax.
[tex]875.98*0.65=56.94[/tex]
Then, add.
[tex]875.98+ 56.94=932.92[/tex]
$[tex]932.92[/tex] is the total cost of the laptop.
Can a Math expert please solve this and explain their answers. Thanks
Answer:
B152°BAStep-by-step explanation:
The measure of an arc is twice the measure of the inscribed angle that subtends that arc. A tangent is a special case where the chord that is one leg of the inscribed angle has a length of zero.
1. Short arc LJ is 2a°. Short arc LK is 2b°. Then arc JLK is 2(a+b)°, and short arc JK is ...
arc JK = 360° -2(a +b)° . . . . . matches choice B
__
2. Long arc WY is twice the measure of "inscribed" angle WYZ, so is ...
long ard WY = 2(104°) = 208°
Then short arc WY is ...
arc WXY = 360° -208° = 152°
__
3. The arc measures are double those of the corresponding inscribed angles. We can add up the arcs around the circle:
(arc AB +arc BC) = 2×70° = 140° . . . inscribed angle relation
(arc BC +arc CD) = 2×98° = 196° . . . inscribed angle relation
arc AB + arc BC +arc CD +arc DA = 360° . . . . sum around the circle
Adding the first two equations with arc DA, we have ...
(arc AB + arc BC) +(arc BC +arc CD) +arc DA = 360° +arc BC
140° +196° +80° = 360° +arc BC
416° -360° = arc BC = 56° . . . . . matches choice B
__
4. Angle C and angle A are supplementary in this inscribed quadrilateral.
angle C = 180° -98° = 82° . . . . . matches choice A
Please help me extra points for 1 math question. Please help before my time is up. Five times a number, added to -3, is 37. Find that number.
Answer:
your number should be 8
Step-by-step explanation:
5x+(-3)=37
5x-3=37
+3 +3
5x=40
÷5 ÷5
x=8
hope this helps
Answer:
The answer is 8.
5x-3=37
5x=37+3
5x=40
x=40/5
x=8
HOPE IT HELPS!!
A commuter uses a bus and a train to get to work. The train is more than 5 minutes late 1/6 of the times they use it The bus is more than 5 minutes late 3/5 of the times they use it. What is the probability that both the bus and train will be more than 5 minutes late?
Answer:
10% probability that both the bus and train will be more than 5 minutes late
Step-by-step explanation:
Independent events:
If two events, A and B, are independent, we have that:
[tex]P(A \cap B) = P(A)*P(B)[/tex]
What is the probability that both the bus and train will be more than 5 minutes late?
The bus being more than 5 minutes late is independent of the train, and vice versa. So
Event A: Bus more than 5 minutes late
Event B: Train more than 5 minutes late
The train is more than 5 minutes late 1/6 of the times they use it
This means that [tex]P(B) = \frac{1}{6}[/tex]
The bus is more than 5 minutes late 3/5 of the times they use it.
This means that [tex]P(A) = \frac{3}{5}[/tex]
Then
[tex]P(A \cap B) = \frac{3}{5}*\frac{1}{6} = \frac{3}{30} = 0.1[/tex]
10% probability that both the bus and train will be more than 5 minutes late