What qualities does a regular polygon have select all that apply?

Answer:

Step-by-step explanation:

33.3%

Standard error of the  of the standard deviation of 2 years with the mean  and the sample size of n will be 3

The parameter list is abbreviated (lower value, upper value, μ,

, α / √n

normal cdf: (85,92,90, 15 / √25

= 0.6997

To find the value that is two standard deviations above the expected value 90, use the formula:

value = ux + ( # of STDEVs ( αx / √n )

value = 90 + 2 (15 / √25 )= 96

The value that is two standard deviations above the expected value is 96. The standard error of the mean is

σ / √n = 15√25

= 3.

standard error of the mean is a description of how far that the sample mean will be from the population mean in repeated simple random samples of size n.

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Answer: The answer is B and D

Step-by-step explanation: The answer is B and D because B is -2 and D is 2, so when we combine them(combine means add) we get -2 + 2 which equals 0.

a)Preliminary estimate for p = 0.27

 [tex]n = \frac{0.27 (1 -0.27)}{(\frac{0.1}{1.96})^2 }[/tex] = 78.84  

And rounded up we have that n = 79

b)  No preliminary estimate for p

[tex]n = \frac{0.5(1 - 0.5)}{(\frac{0.1}{1.96} )^2}[/tex] = 96.04

And rounded up we have that n=97

The population proportion have the following distribution

p ~ [tex]N ( p , \sqrt{\frac{p(1 -p)}{n} }[/tex]

Solution to the problem

Part a) preliminary estimate for p :

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by α = 1 - 0.95 and α/2 = 0.025. And the critical value would be given by:

[tex]z_{\alpha /2} = - 1.96 , z_{1 - \alpha /2} = 1.96[/tex]

The margin of error for the proportion interval is given by this formula:  

   (a)  [tex]ME = z_{\alpha /2} \sqrt{\frac{p (1-p)}{n} }[/tex]              ----------------- (1)

And on this case we have that  and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

  (b)  [tex]n = \frac{p(1 -p)}{(\frac{ME}{2} )^2}[/tex]                             ---------------------- (2)

And replacing into equation (2) the values from part a we got:

[tex]n = \frac{0.27 (1 -0.27)}{(\frac{0.1}{1.96})^2 }[/tex] = 78.84

 And rounded up we have that n = 79

Part b) no preliminary estimate

Since we don't have a prior estimation for p we can use . And on this case we have that  and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

  (b)  [tex]n = \frac{p(1 -p)}{(\frac{ME}{2} )^2}[/tex]

And replacing into equation (b) the values from part a we got:

[tex]n = \frac{0.5(1 -0.5)}{(\frac{0.1}{1.96})^2 }[/tex] = 96.04

 And rounded up we have that n=97

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Answer:

somone in my class is literally a new York rat

Step-by-step explanation:

The value of the required probabilities are:

(a) E[X] = 6

(b) E[X|Y=1] = 1/36

(c) E[X|Y=5] = 5/36.

To find the values of P{X=x, Y=1} and P{X=x, Y=5}, we need to understand the concept of conditional probability and the properties of geometric distributions.

First, let's recall some properties of geometric distributions:

The probability of success (rolling a specific number on a fair die) in a single trial is denoted by p, and for a fair die, p = 1/6.

The probability of failure (not rolling the specific number) in a single trial is denoted by q, and for a fair die, q = 1 - p = 5/6.

The geometric distribution is the number of trials required to achieve the first success (rolling the specific number) in a sequence of independent trials.

For the random variable X (number of rolls necessary to obtain a 6), X follows a geometric distribution with parameter p = 1/6.

Now, let's find the values of P{X=x, Y=1} and P{X=x, Y=5}.

(a) E[X]:

The expected value of X (denoted as E[X]) for a geometric distribution is given by E[X] = 1/p. For a fair die, p = 1/6, so E[X] = 1 / (1/6) = 6.

(b) E[X|Y=1]:

This represents the expected number of rolls necessary to obtain a 6 given that the first roll resulted in a 5.

To find E[X|Y=1], we need to consider the conditional probability.

The event "Y=1" represents that the first roll resulted in a 5.

The probability of rolling a 6 in the next roll (X=1) given that Y=1 is P{X=1, Y=1}.

Since the rolls are independent, P{X=1, Y=1} = P{X=1} * P{Y=1}.

The probability of rolling a 6 in a single roll (P{X=1}) is 1/6, and the probability of rolling a 5 in a single roll (P{Y=1}) is also 1/6 (since we want the first roll to be a 5).

So, P{X=1, Y=1} = (1/6) * (1/6) = 1/36.

Now, to find E[X|Y=1], we need to sum the products of the number of rolls (x) and the corresponding probabilities for all possible values of x, given that Y=1:

E[X|Y=1] = ∑(x * P{X=x, Y=1})

Since the geometric distribution is defined over all non-negative integers, we need to consider all possible values of x (0, 1, 2, 3, ...).

E[X|Y=1] = (0 * P{X=0, Y=1}) + (1 * P{X=1, Y=1}) + (2 * P{X=2, Y=1}) + ...

Now, we already know that P{X=1, Y=1} = 1/36. For all other values of x, P{X=x, Y=1} = 0 because we cannot have any rolls beyond the first roll when Y=1 (since Y=1 means the first roll was a 5).

So, E[X|Y=1] = (1 * 1/36) + (0 * 0) + (0 * 0) + ... = 1/36.

(c) E[X|Y=5]:

This represents the expected number of rolls necessary to obtain a 6 given that the first roll resulted in a 5 followed by four rolls that resulted in other numbers (not 6).

Similarly to part (b), we need to consider the conditional probability.

The event "Y=5" represents that the first five rolls resulted in numbers other than 6.

The probability of rolling a 6 in the next roll (X=1) given that Y=5 is P{X=1, Y=5}.

Again, since the rolls are independent, P{X=1, Y=5} = P{X=1} * P{Y=5}.

The probability of rolling a 6 in a single roll (P{X=1}) is 1/6, and the probability of rolling a number other than 6 in a single roll (P{Y=5}) is 5/6 (since we want the first five rolls to be numbers other than 6).

So, P{X=1, Y=5} = (1/6) * (5/6) = 5/36.

To find E[X|Y=5], we need to sum the products of the number of rolls (x) and the corresponding probabilities for all possible values of x, given that Y=5:

E[X|Y=5] = ∑(x * P{X=x, Y=5})

Similarly to part (b), for all values of x other than 1, P{X=x, Y=5} = 0 because we cannot have any rolls beyond the first roll when Y=5 (since Y=5 means the first five rolls were other numbers).

So, E[X|Y=5] = (1 * 5/36) + (0 * 0) + (0 * 0) + ... = 5/36.

Hence, The value of the required probabilities are:

(a) E[X] = 6

(b) E[X|Y=1] = 1/36

(c) E[X|Y=5] = 5/36.

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(a)let A=event that first k-1 draws will get r-1 red balls

let B=event that last (kth) draw will get rth red ball

P(kth draw is the rth red ball)= P(A AND B) = P(A)xP(B)

(b)P(A)=  # of  ways to draw r-1 red balls in k-1 trail

         # of ways to draw k-1 balls

RBBB *R is one way to achieve P(A AND B)

BBBR *R is another way.

(c)There are n−(r−1) red left, and a total of (m+n)−(k−1) balls left, so the (conditional) probability of drawing a red on the kth trial is n−r+1/m+n−k+1 Thus our required probability is

So,  P(A)= nC(r-1) x mC(n-r) x 1/(n+m)C(k-1)

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Answer:

You can split the 36 into base 10 blocks and tell them 3 means three 10 blocks.

True , The adjusted R^2: is used primarily to monitor whether extra explanatory variables really belong in a multiple regression model .

Given :

The adjusted R^2: is used primarily to monitor whether extra explanatory variables really belong in a multiple regression model .

If the regression equation includes anything other than a constant plus the sum of products of constants and variables, the model will not be linear.

Adjusted R^2 is a corrected goodness - of - fit  ( model accuracy ) measure for linear models. It identifies the percentage of variance in the target field that is explained by the input or inputs.

So the above statement is true.

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The interest rate required to accumulate a simple interest of $ 1,711.11 in 220 days is approximately 20%.

The simple interest formula is expressed as;

I = P × r × t

Where I is interest, P is principal, r is interest rate and t is time.

Given the data in the question;

Plug the given values into the above formula and solve for interest rate r.

I = P × r × t

$1711.11 = $14000  × r × 220/365yr

1711.11  = 616000/73 × r

r = 1711.11 ÷ 616000/73

r = 0.20227776

Rate R = r × 100%

Rate R = 0.20227776 × 100%

Rate R = 20%

Therefore, rate of the investment is 20%

Option A is the correct answer.

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Let A be a diagonalizable matrix. If c₁ and c₂ are solution to system

x⃗' (t) = A x⃗ ( t )

the possible values of c₁ is 1 and c₂ is 2 .

So, the correct option is option(a) and (e).

We have given that A is 2 × 2 diagonalizable matrix and x⃗ (t) = ( 3eᵗ + eᶜ₁t , 3e²ᵗ + eᶜ₂ᵗ) is a solution of system, x⃗ '(t) = A x⃗(ᵗ) .

A Solution of system always satisfied the equation of system.

Now, Differenating x⃗ (t) wih respect to t we get, x⃗' (t)=( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ)

So, ( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ)= A ( 3eᵗ + eᶜ₁t , 3e²ᵗ + eᶜ₂ᵗ) where A is diagonalizable and A = [a 0 0 b].

Then, ( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ) = ( 3aeᵗ + aeᶜ₁t , 3be²ᵗ + b eᶜ₂ᵗ)

equating the coefficients on both sides we get, 3eᵗ + c₁ eᶜ₁t = 3aeᵗ + aeᶜ₁t 6e²ᵗ + c₂ eᶜ₂ᵗ = 3be²ᵗ + b eᶜ₂ᵗ

after equating the corresponding equations , 3 = 3a and c₁ = a and 6 = 3b and c₂ = b after solving all we get a = 1 and b = 2 which implies c₁ = 1 and c₂ = 2. Hence, the possible values are c₁ = 1 and c₂ = 2.

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Complete question:

Let A be a diagonalizable matrix. If c₁ and c₂ are solution to system x⃗ (t) = A x⃗

then check all the possible values of c₁ and c₂ and below.

(a) c₁ = 1

(b) c₁ = 3

(c) c₁ = 2

d) c₂ = 1

(e)c₂ =2

(f) c₂ = 3

The integer minus four to vector input integers:

# Python program to count positive and negative numbers in a List
# list of numbers
list1 = [10, -21, 4, -45, 66, -93, 1]
pos_count, neg_count = 0, 0
# iterating each number in list
for num in list1:
  # checking condition
  if num >= 0:
      pos_count += 1
  else:
      neg_count += 1
print("Positive numbers in the list: ", pos_count)
print("Negative numbers in the list: ", neg_count)

What is loop in python?

A for loop is used for iterating over a sequence (that is either a list, a tuple, a dictionary, a set, or a string). This is less like the for keyword in other programming languages, and works more like an iterator method as found in other object-orientated programming languages.
Using a for loop, count both positive and negative numbers from a specified list. Use a for loop to iterate each member in the list, then check to see if the positive number test is true by seeing if num >= 0.
Increase the positive count if the condition is true; else, increase the negative count.

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The difference in the mean of the two major automobile manufactures is equal to option c. 2.0.

As given in the questions,

Number of samples selected for each manufactures = 8

For manufacturers A :

Mean of manufacturer A

=(Sum of all the eight data) / ( Number of data)

= ( 32+ 27 + 26 + 26 + 25 + 29 + 31 + 25 ) / 8

= 221 / 8

= 27.625

Mean of manufacturer B

=(Sum of all the eight data) / ( Number of data)

= ( 28 + 22 + 27 + 24 + 24 + 25 + 28 + 27 ) / 8

= 205 / 8

= 25.625

Difference in the mean of manufacturer A and B

= 27.625 - 25.625

= 2.0

Therefore, the difference in the mean of both manufacturer is given by Option C. 2.0.

The complete question is :

Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining whether or not there is a significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles. A random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance. The following data (in miles per gallon) show the results of the test. Assume the population of differences is normally distributed.

Driver              Manufacturer A                 Manufacturer B

1                             32                                    28

2                            27                                    22

3                            26                                    27

4                            26                                    24

5                            25                                    24

6                            29                                    25

7                             31                                    28

8                             25                                   27

A) The mean for the differences is __________

a. 0.50               b. 1.5                 c. 2.0              d. 2.5

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Answer:

somone in my class is literaly a new York rat

Step-by-step explanation:

You did not copy the image with the question. Sometimes you have to screenshot or use the Snip-it app to get the image.

Answer:

angle congruence just watch some videos about it explaining that

the correct expression for the rate of this reaction would be A[B] 3At or A[G] 2Ît, but not -A[A] At.

A rate expression is a mathematical expression that describes the rate at which a chemical reaction proceeds. It is typically written in the form of a differential equation, with the reactants on the left-hand side and the products on the right-hand side. The coefficients of the reactants and products represent the stoichiometric coefficients of the reaction. In the expression 2A +3B -> F+ 2G, the reactants are A and B, and the products are F and G. Therefore, the correct expression for the rate of this reaction would be A[B] 3At or A[G] 2Ît, but not -A[A] At.

A rate expression is an equation that describes the rate at which a chemical reaction occurs. It is usually written in the form of a differential equation, with the reactants on the left-hand side and the products on the right-hand side. The coefficients of the reactants and products represent the stoichiometric coefficients of the reaction. In the expression 2A +3B -> F+ 2G, the reactants are A and B, and the products are F and G. Therefore, the correct expression for the rate of this reaction would be A[B] 3At or A[G] 2Ît, but not -A[A] At, which does not represent a proper rate expression for this reaction.

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Therefore, the equation having solution x=5 are option b) x+2=7 ,Option c) 3x=15 and Option e)x-5=0

equation, a declaration of equivalence between two expressions with variable- and/or number-filled expressions. In essence, equations are questions, and efforts to discover a method for answering them have fueled the growth of mathematics.

Here,

A.)20 - x = 5

B) x + 2 = 7

C) 3x = 15

D) 5x = 15

E) x- 5 = 0

So, the equation which has solution as x=5 are:

Option b) x+2=7

=>x+2=7

=>x=7-2

=>x=5

Option c) 3x=15

=> 3x=15

=> x=15/3

=> x=5

Option e)x-5=0

=>x-5=0

=>x=5

Therefore, the equation having solution x=5 are option b) x+2=7 ,Option c) 3x=15 and Option e)x-5=0

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The error in computing the area of triangle is 10.75 and the percentage error in computing the area of triangle is 1.194%.

Given that, base of the triangle is 36 cm (a)

Altitude of the triangle is 50 cm (b)

Error in each measurement is 0.25 cm

We know that, area of the triangle (s) = 1/2 * base * altitude

Let us consider base as ' a ' and altitude as ' b '

So, the maximum error of ' s ' can be calculated as

⇒ ds/da * da + ds/db * db

⇒ 1/2* b * da + 1/2 *a * db

⇒ 1/2* 36 * 0.25 + 1/2* 50* 0.25

⇒ 4.5 + 6.25 = 10.75

Now, let us calculate the percentage error in computing the area of the triangle.

dA/A * 100 = [(1/2* b* da + 1/2* a * db)/ 1/2* b *h] * 100

⇒ [(1/2* 36 * 0.25 + 1/2* 50 * 0.25)/ 1/2* 36 * 50] * 100

⇒ [ 21.5/ 1800 ] * 100

⇒ 1.194%

Thus, the error in computing the area of the triangle is 10.75 and the percentage error in computing the area of the triangle is 1.194%.

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The difference between the normal low temperature and the record low temperature is 31°F.

The physical concept of temperature indicates in numerical form how hot or cold the weather is. A thermometer is used to determine temperature.

When the temperature is hot the measure of temparature will be in positive when the temperature is cold the measure of temparature will be negative.  

The formula for the difference between the normal low temperature and the record low temperature is given by

Here we have

The coldest temperature ever recorded in Mathville was - 16° F

This happened on January 30th, 1984. The normal low for that day is 15°F.

Here we need to find the difference between the normal low temperature and the record low temperature.

The formula for the difference is given by

Difference = (record low temperature) - (normal low temperature)  

From the given data,

Difference will be = - 16°F - (15°F) = -16°F - 15°F = - 31°F  

Therefore,

The difference between the normal low temperature and the record low temperature is 31°F.

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Answer:

4 cupcakes

Step-by-step explanation:

Answer:

4

cupcakes

Step-by-step explanation:

This is because it says the cupcakes are 3$ each. if you buy 7 items for 15$

3x4=12.

Using simple percentage rule, the answer is 25%,52% and 16.67%.

A percentage is a figure or ratio stated as a fraction of 100 in mathematics. The percent symbol, %, or the abbreviation "pct" are frequently used to indicate percentages. The term "percent" derives from "percent," a shortened form of "per centum," which meaning per hundred.

The required formula is:

percentage (%) = Change/total * 100

Percentage Decrease = [tex]\frac {80-60}{80} * 100[/tex]

=25%

Percentage Decrease=[tex]\frac {500-240}{500} * 100[/tex]

=52%

Percentage Decrease = [tex]\frac {144-120}{144} * 100[/tex]

=16.67%

We calculated the percentage decrease using the above-mentioned formula.

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Answer:

C. 20

Step-by-step explanation:

60 = 2x + 20  ==> solve for x

60 - 20 = 2x + 20 - 20  ==> subtract 20 on both sides to isolate x

40 = 2x  ==> simplify

x = 40/2  ==> divide both sides by 2 to isolate x

x = 20 degrees

Answer: C. 20

Answer:

Step-by-step explanation:

You and a friend race each other. you give your friend a 50-foot head start. the distance y (in feet) your friend runs after x seconds is represented by the linear function y=14x+50 . the table shows the distances you run. time (seconds) x :  2, 4, 6, 8 distinct (feet) y :  38, 7...

well, we know the TV cost 200 bucks, now if we just bump it up by 45%, that'd do it.

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{45\% of 200}}{\left( \cfrac{45}{100} \right)200}\implies 90~\hfill \underset{retail~price}{\stackrel{200~~ + ~~90}{\text{\LARGE 290}}}[/tex]

Answer: .29

Step-by-step explanation:

The probability that 75% or more of the women in the sample have been on a diet is 0.0371 or 3.71 %.

Here, n = 267, p = 0.7, 1 = 0.3

Mean, [tex]m_p = p[/tex]

⇒ [tex]m_p = 0.7[/tex]

Standard deviation, [tex]\sigma_p = \sqrt(\frac{pq}{n})[/tex]

⇒ [tex]\sigma_p[/tex] = 0.028

The conditions for a sampling distribution to be normal distribution, it must satisfy

1. Randomization condition(SRS)

2. logo condition

3. success/failure condition

Hence, the given sampling distribution in the problem statement is approximately normal distribution.

n×p = 267×0.7 = 186.9 ≥ 10

n×q = 267×0.3 = 80.1 ≥ 10

Norm cdf = (0.75, 999, 0.7, 0.028) ≈ 0.0371 ≈ 3.71%

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The option that is not true about the given radical function is; d. f'(x) exists for all x

We are given the function;

f(x) = 1 + x^(2/3)

a) All odd radical functions are continuous for all numbers, this is,  exists for every x ∈ ℝ. A set of real numbers.

b) From the graph attached, the function f(x) has an absolute minimum at x = 0.

c) f(x) increases for x > 0 and x < 0.

d)  First derivative does not exists for x = 0

e) The first and second derivatives of the function are f'(x) = ²/₃x^(-1/3) and  f"(x) = -²/₉x^(-4/3)

Thus, the first derivative f"(x) does not exist for x = 0

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(c) is correct option as it is forming an arithmetic sequence with a common difference of -2.

There are two definitions for an arithmetic sequence. It is a "series where the differences between every two succeeding terms are the same" or "each term in an arithmetic sequence is formed by adding a fixed number (positive, negative, or zero) to its preceding term." The following is an arithmetic sequence where each term is created by adding 4 to the one before it.

An arithmetic sequence's first term is 'a', its common difference is 'd', and n is the total number of terms. The AP has the following general forms: a, a+d, a+2d, a+3d, etc., up to n words.

(a) 1,2,3,5,7,9 is not an arithmetic sequence as 2-1=1 and 5-3=2. That shows common difference is not constant.

(b) 1,10,20,30 is not an arithmetic sequence as 10-1=9 and 20-10=10. That shows common difference is not constant.

(c) 1,-1,-3,-5 is an arithmetic sequence as (-1)-1=-2 and -3-(-1)=-2. That shows common difference is constant.

(d) 7,-7,7,-7 is not forming an arithmetic sequence because common difference is not constant.

Option (c) is correct option.

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