what should be the concentration of thc in cbd oil? ans. there should be no more than 0.3% thc in cbd oil. this is necessary for it to be legal at the federal level.

Boyle's Law, Charles' Law, and Avogadro's Law can be derived from the ideal gas law, which is expressed as:

PV = nRT , where:

P = pressure

V = volume

n = number of moles of gas

R = ideal gas constant

T = temperature

Let's see how each law can be derived:

Boyle's Law:

Boyle's Law states that at constant temperature, the pressure of a given amount of gas is inversely proportional to its volume. Mathematically, it can be written as:

P₁V₁ = P₂V₂

Assuming the amount of gas (n) and temperature (T) remain constant, we can rewrite Boyle's Law using the ideal gas law:

(P₁/nT) × V₁ = (P₂/nT) × V₂

By canceling out the constant factors (n and T) on both sides, we obtain:

P₁V₁ = P₂V₂

This equation represents Boyle's Law, which demonstrates the inverse relationship between pressure and volume at constant temperature.

Charles' Law:

Charles' Law states that at constant pressure, the volume of a given amount of gas is directly proportional to its temperature. It can be expressed as:

V₁/T₁ = V₂/T₂

Assuming the amount of gas (n) and pressure (P) remain constant, we can rearrange the ideal gas law to obtain:

(V₁/nP) × T₁ = (V₂/nP) × T₂

By canceling out the constant factors (n and P) on both sides, we get:

V₁/T₁ = V₂/T₂

This equation represents Charles' Law, showing the direct relationship between volume and temperature at constant pressure.

Avogadro's Law:

Avogadro's Law states that at constant temperature and pressure, equal volumes of different gases contain an equal number of molecules (or moles). It can be written as:

V₁/n₁ = V₂/n₂

Using the ideal gas law, we can rearrange it as:

(V₁/P₁) × (T/P₁) × n₁ = (V₂/P₂) × (T/P₂) × n₂

Canceling out the constant factors (P₁/P₁, T/T) and rearranging the equation, we have:

V₁/n₁ = V₂/n₂

This equation represents Avogadro's Law, demonstrating that equal volumes of gases contain an equal number of moles at constant temperature and pressure.

In summary, Boyle's Law, Charles' Law, and Avogadro's Law can all be derived from the ideal gas law by manipulating the equation while holding certain variables constant.

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On a cold day, a person with a lung capacity of 2.2 L must breathe in 1.97 L of air at 276 K to fill their lungs. The correct option is B) 1.97 L.

To solve this problem, we will use the combined gas law formula, which is P1V1/T1 = P2V2/T2.

In this case, the pressure (P) remains constant, so we can simplify the formula to V1/T1 = V2/T2.

We know the lung capacity (V2) is 2.2 L, the body temperature (T1) is 309 K, and the outside air temperature (T2) is 276 K. Our goal is to find the volume of air required (V1).

Plugging the values into the formula, we get V1/309 = 2.2/276.

Solving for V1, we find that V1 = 1.97 L.

Thus, a person must breathe in 1.97 L of air at 276 K to fill their lungs.

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The ideal gas law is an important equation that describes the behavior of gases, and for solving ideal gas problems.

To help remember the ideal gas law, one strategy is to use the acronym PV = nRT

Where;

This acronym can help you remember the variables involved in the equation and their relationships.

So if you're not sure how to figure out the relationship between properties of an enclosed gas, one strategy you can use is to apply the ideal gas law. You can rearrange the equation to solve for the variable you're interested in.

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The adoption of carbon sequestration technology among coal-fired power plants can vary over time due to factors such as regulations, technological advancements, and economic considerations.

However, it's worth noting that carbon capture and storage (CCS) technologies, including carbon sequestration, have been developed and implemented in some coal-fired power plants around the world.

These technologies aim to capture CO2 emissions and store them underground to mitigate the environmental impact of greenhouse gas emissions.

To obtain the current percentage of coal-fired power plants in the USA using carbon sequestration technology.

It would be best to refer to the latest reports and studies from relevant organizations and government agencies specializing in energy and environmental research, such as the U.S. Energy Information Administration (EIA) or the Environmental Protection Agency (EPA).

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The amount of 1.20 m NaOH that will be needed to neutralize 225 ml of battery acid is 1125 ml.

The balanced chemical reaction is given as,

H₂SO₄ (aq) + 2 NaOh (aq) → 2 H₂O + Na₂SO₄ (aq)

Generally molarity is defined as one of the most widely used unit of concentration and it is denoted by M.

By formula of molarity,

V1M1 n2 =  V2M2n1

V=  volume

M =  concentration  in  mole  per   liter

n =  number  of  moles

V1 =?

V2 =  225  ml  

M1 = 1.2  M

M2 =  3 m  

n1 =2  moles

V1   is  therefore  =  ( 225  x3  x2 )  /1.2  =  1125  ml

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After the lab tech pours some of the solutions from beakers A and B into beakers C and D, there are 600 milliliters of solution remaining in beaker B.

To solve this problem, we can use the following equations:

Amount of salt in beaker A = 0.2 * 500 = 100 milliliters

Amount of salt in beaker B = 0.5 * 800 = 400 milliliters

Amount of salt in beaker C = 0.3 * 100 = 30 milliliters

Amount of salt in beaker D = 0.45 * 200 = 90 milliliters

We know that the total amount of salt in the four beakers is constant, so we can set up the following equation:

100 + 400 = 30 + 90 + x

where x is the amount of salt in beaker B after the lab tech pours some of the solutions into beakers C and D.

Solving for x, we get:

x = 400 - 30 - 90 = 280

Therefore, there are 600 milliliters of solution remaining in beaker B.

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The molarity of CH₃OH in the solution with a density of 0.97 g/ml cannot be determined without additional information.

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. However, in this question, we are not provided with the volume or mass of the solution. We only know the density of the solution, which is the mass of the solution per unit volume. Therefore, we cannot calculate the volume of the solution without knowing the mass.

Furthermore, we are not given the molar mass of CH₃OH, so we cannot convert the mass of CH₃OH to moles. Without additional information, it is impossible to calculate the molarity of CH₃OH in the solution.

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The mass of KF in the solution is 59.3 g. The correct answer is 59.3 g which is in option A as  the formula for calculating the mass of solute in a solution is: mass of solute = molarity × volume × molar mass.

mass of solute = molarity × volume × molar mass

First, one needs to calculate the number of moles of KF in the solution:

molarity = number of moles / volume

Rearranging this equation gives :

number of moles = molarity × volume

number of moles = 2.00 M × 0.510 L

number of moles = 1.02 mol

The molar mass of KF is 58.10 g/mol. Now the mass of KF in the solution is calculated:

mass of KF = 1.02 mol × 58.10 g/mol

mass of KF = 59.3 g

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The quantity of energy released or absorbed when a material is dissolved in a solvent is known as the heat of solution, also known as enthalpy of solution.

In this instance, the lattice energy and the heat of hydration are subtracted from one another to get the heat of solution for MX. MX's heat of hydration is -395 kJ/mol, and its lattice energy is -475 kJ/mol. As a result, MX's heat of solution is -80 kJ/mol. An essential thermodynamic characteristic that may be used to estimate a substance's solubility in a solvent is the heat of solution.

When the solute particles are distributed in the solvent, energy is either released or absorbed. The temperature of the MX solution in this instance is only soluble in water.

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The pressure of oxygen gas in a mixture of nitrogen and helium is to be determined.

The three gases are present in a 2.00 liter container, and their individual pressures are known. The total pressure exerted by the three gases in the container is also given.

In order to determine the pressure of the oxygen gas, we will need to apply Dalton's law of partial pressures. According to this law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases. Mathematically, we can express this as:

P_total = P_1 + P_2 + P_3

where P_total is the total pressure, and P_1, P_2, and P_3 are the partial pressures of the gases.

In the given problem, we know the partial pressures of nitrogen and helium, and the total pressure of the mixture. Therefore, we can write:

P_total = P_N2 + P_He + P_O2

Substituting the values given in the problem, we get:

1173.99 torr = 215.91 torr + 53.46 torr + P_O2

Solving for P_O2, we get:

P_O2 = P_total - P_N2 - P_He

P_O2 = 1173.99 torr - 215.91 torr - 53.46 torr

P_O2 = 904.62 torr

Therefore, the pressure of the oxygen gas in the mixture is 904.62 torr.

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Answer:

The answer is it is spontaneous at 25°C.

The second law of thermodynamics states that the entropy of the universe is always increasing. This means that any process that increases the entropy of the universe is spontaneous. A process with ΔSuniv > 0 at 25°C is increasing the entropy of the universe, so it is spontaneous at 25°C.

The other choices are not correct. A process with ΔSuniv > 0 at 25°C could be exothermic or endothermic. It will not necessarily move rapidly toward equilibrium.

Explanation:

Therefore, the answer is D) 3.1 × 10^20. This means that 3.1 × 10^20 electrons flow through the device in 10 seconds.

To calculate the number of electrons that flow through the device in 10 seconds, we need to use the formula:
number of electrons = (current × time) / charge of one electron
We are given the current, which is 5.0 A, and the time, which is 10 seconds. The charge of one electron is e = 1.60 × 10-19 C. Plugging these values into the formula, we get:
number of electrons = (5.0 A × 10 s) / (1.60 × 10-19 C)
Simplifying this expression, we get:
number of electrons = (5.0 × 10) / (1.60 × 10-19)
number of electrons = 3.125 × 10^20
It is important to note that this is a very large number of electrons, which highlights the fact that even small currents can involve a large number of electrons.

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A chloride ion, Cl-, has the same electron configuration as a neutral atom of the element argon (Ar). Both have a complete outer electron shell with 8 electrons.

This is because a chloride ion is formed by the gain of one electron by a neutral chlorine atom (Cl), which has 7 electrons in its outermost shell. When it gains one electron, it completes its outer shell and becomes a chloride ion with the same electron configuration as argon. This electron configuration is stable and unreactive, which is why both argon and chloride ions do not readily form chemical bonds with other atoms or molecules. Overall, the electron configuration of a chloride ion is a result of its chemical properties and interactions with other atoms.

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The chemical reaction CO2 + H2O = HCO3- + H+ is an important reaction in the regulation of the pH of blood and other bodily fluids.

This reaction occurs in the red blood cells and involves the conversion of carbon dioxide (CO2) and water (H2O) into bicarbonate ion (HCO3-) and hydrogen ion (H+).

An increase in CO2 will lead to an increase in the concentration of H+ ions and HCO3- ions in the blood.

This is because CO2 is an acidic gas, and when it dissolves in water, it forms carbonic acid (H2CO3). Carbonic acid then dissociates into H+ ions and HCO3- ions, increasing the concentration of both ions in the blood.

This increase in H+ ions will cause a decrease in the pH of the blood, making it more acidic.

This increase in acidity can have negative effects on the body, such as interfering with enzyme activity and altering protein structure.

The body has mechanisms in place to regulate the pH of the blood and other bodily fluids, such as the respiratory and renal systems, which can help to compensate for changes in CO2 levels and maintain a stable pH.

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The original element, bismuth-213 (Bi-213), undergoes a nuclear transformation, reducing its atomic number by two units and its atomic mass by four units, leading to the formation of thallium-209.

The isotope bismuth-213 (Bi-213) undergoes alpha decay, a type of radioactive decay, by emitting an alpha particle from its atomic nucleus. An alpha particle is composed of two protons and two neutrons, which is equivalent to a helium-4 nucleus. During alpha decay, the bismuth-213 nucleus loses the alpha particle, reducing its atomic number by two units and its atomic mass by four units. The atomic number represents the number of protons in the nucleus, determining the element's identity. Bismuth has an atomic number of 83, so when it emits an alpha particle, the resulting element will have an atomic number of 81. This new element is thallium (Tl). Therefore, the isotope bismuth-213 transforms into thallium-209 (Tl-209) as a result of the emission of an alpha particle. The decay process can be represented as follows:

Bismuth-213 (Bi-213) -> Thallium-209 (Tl-209) + Alpha particle

Overall, when bismuth-213 undergoes alpha decay, it leads to the formation of thallium-209 as the new element, with the emission of an alpha particle.

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A balanced equation obeys the law of conservation of mass. According to the law, the mass can neither be created nor be destroyed but can be converted from one form to another.

A chemical equation in which number of atoms of reactants and products are equal on both sides of the equation are defined as the balanced chemical equation. The numbers which are used to balance the chemical equation are called the coefficients.

Here the given equations are balanced as follows:

1. 2C₃H₆ + 9O₂ → 6CO₂ + 6H₂O

2. 3 LiOH + Al(NO₃)₃ → 3Li (NO₃) + Al(OH)₃

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Answer: 6.65*10^-3

Explanation:

The reaction below has the products and reactants reversed, so the Kp will be inversed (Kp^-1). The coefficients are also halved, so the Kp^-1 will be to the power of 1/2. This means that the Kp for the reaction below is [tex](K_p^{-1})^{1/2}[/tex] = [tex]K_p^{-\frac{1}{2} }[/tex] = [tex]\frac{1}{\sqrt{K_p}}[/tex] = [tex]\frac{1}{\sqrt{2.26*10^4}}[/tex] = 6.65*10^-3

The atomic theory proposed by Dalton in the early 19th century was a significant milestone in the field of chemistry. It suggested that atoms were the fundamental building blocks of matter and that they combined in fixed ratios to form compounds.

Over time, the theory has undergone several modifications and expansions as new scientific discoveries have been made. However, it has not been entirely discarded or found to be plagiarized. Today, the basic principles of Dalton's atomic theory are still widely accepted and taught in chemistry classrooms around the world, although they have been refined and updated with modern scientific advancements.

The atomic theory proposed by John Dalton has not been totally discarded, accepted unchanged, or found to be plagiarized. Instead, it has been expanded and modified over time. Dalton's original theory laid the foundation for our understanding of atomic structure, but further scientific discoveries have led to more comprehensive atomic models. These modifications include the discovery of subatomic particles, such as electrons, protons, and neutrons, as well as the development of quantum mechanics to explain their behavior. Despite these updates, Dalton's theory remains a crucial part of the history of atomic science.

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To determine the value for ΔHrxn in kJ/mol, we will use Hess's Law. we get:ΔHrxn = (-467.8 kJ/mol) + (-285.8 kJ/mol) - [(-943.4 kJ/mol) + 2(-365.5 kJ/mol)]ΔHrxn = -733.6 kJ/mole Therefore, the value for ΔHrxn in kJ/mol is -733.6.

Magnesium oxide is MgO, while nitric acid is HNO3. Thus, the balanced chemical equation for the reaction between magnesium oxide and nitric acid is:MgO + 2HNO3 → Mg(NO3)2 + H2OWe must determine the enthalpy change of this reaction (ΔHrxn), which can be accomplished using Hess's Law and the following information:ΔH1 = -943.4 kJ/mol (the heat of formation of MgO)ΔH2 = -365.5 kJ/mol (the heat of formation of HNO3)ΔH3 = -467.8 kJ/mol (the heat of formation of Mg(NO3)2)ΔH4 = -285.8 kJ/mol (the heat of formation of H2O)

We can use these values along with the chemical equation to derive an expression for the enthalpy change of the reaction as follows:ΔHrxn = ΔH3 + ΔH4 - (ΔH1 + 2ΔH2)Plugging in the values, we get:ΔHrxn = (-467.8 kJ/mol) + (-285.8 kJ/mol) - [(-943.4 kJ/mol) + 2(-365.5 kJ/mol)]ΔHrxn = -733.6 kJ/molTherefore, the value for ΔHrxn in kJ/mol is -733.6.

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It can be estimated that in the one-dimensional elastic collision, almost all of the electron's initial kinetic energy is transferred to the kinetic energy of the hydrogen atom.

What is the transfer of kinetic energy?

Kinetic energy transfer is the procedure through which energy related to an object's motion is transferred from one object to another. Kinetic energy, which is determined by an object's mass and velocity, is the energy that an object has as a result of its motion.

Kinetic energy can be exchanged between two things when they come into contact with one another, such as when they collide or are subjected to forces. Different techniques, such as physical contact, electromagnetic forces, or gravitational forces, can be used to transfer kinetic energy.

Momentum and kinetic energy are both conserved in an elastic collision. The total kinetic energy of an electron, before it collides with a stationary hydrogen atom, is the same as the total kinetic energy after it collides.

The hydrogen atom has no initial kinetic energy because it is initially at rest. Any kinetic energy that is measured following the impact must thus have come from the electron.

We can infer that the hydrogen atom gains the majority of the kinetic energy transmitted during the collision because its mass is significantly more (1840 times) than the mass of the electron. This is due to the fact that the change in velocity for the electron is far larger than the change in velocity for the much heavier hydrogen atom.

Therefore, it can be estimated that in the one-dimensional elastic collision, almost all of the electron's initial kinetic energy is transferred to the kinetic energy of the hydrogen atom.

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If a compound is impure, containing traces of starting material or byproduct, the melting point is expected to be lower than the melting point of a pure compound.

This is because impurities in a compound disrupt the crystal lattice structure, which causes the melting point to decrease. In a pure compound, the molecules are arranged in a uniform and regular pattern, allowing for efficient packing and strong intermolecular forces. Impurities introduce disorder and randomness into the crystal lattice, creating voids or vacancies that weaken the intermolecular bonds. As a result, less energy is required to overcome the intermolecular forces and the compound melts at a lower temperature. Therefore, the melting point of an impure compound can be used as an indication of its purity. The more impurities a compound has, the lower its melting point will be.

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The false statement for NH3 and NF3 is option G - the bond angles in NF3 are smaller than those in NH3. In NH3, the nitrogen atom is sp3 hybridized, which means that it utilizes four hybrid orbitals for bonding.

Three of these orbitals overlap with the 1s orbitals of the three hydrogen atoms, forming three sigma bonds, while the fourth hybrid orbital contains a lone pair of electrons. This results in a trigonal pyramidal geometry with bond angles of approximately 107 degrees.
Similarly, in NF3, the nitrogen atom is also sp3 hybridized and utilizes four hybrid orbitals for bonding. However, in this case, three of the hybrid orbitals overlap with the 2p orbitals of the three fluorine atoms, forming three sigma bonds, while the fourth hybrid orbital contains a lone pair of electrons. The bond dipoles in NF3 are directed towards fluorine atoms, which are more electronegative than nitrogen, making the molecule polar. The unshared pair of electrons also has a greater influence on the molecular shape, causing the bond angles to be slightly larger than those in NH3, at approximately 102 degrees. Therefore, option G is false.

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To determine the time required to plate out each substance, The approximate time required for each case is: a) 1.11 × 10⁶ seconds b) 3.29 × 10⁻⁴ seconds c) 4.82 × 10² seconds

The equation for Faraday's law is:

a) Plating out 1.0 kg of Al from aqueous Al³⁺:

molar mass of Al = 26.98 g/mol

moles of Al = mass / molar mass = 1000 g / 26.98 g/mol = 37.06 mol

So, moles of substance = 37.06 mol

time ≈ 1.11 ×10⁶ seconds

b) Plating out 1.0 g of Ni from aqueous Ni²⁺:

molar mass of Ni = 58.69 g/mol

moles of Ni = mass / molar mass = 1.0 g / 58.69 g/mol ≈ 0.017 mol

So, moles of substance = 0.017 mol

time = (0.017 mol ×2 ×96485 C/mol) / 100 A

time ≈ 3.29 × 10⁻⁴ seconds

c) Plating out 5.0 mol of Ag from aqueous Ag⁺:

So, moles of substance = 5.0 mol

time = (5.0 mol × 1 ×96485 C/mol) / 100 A

time ≈ 4.82 × 10² seconds

Therefore, the approximate time required for each case is:

a) 1.11 × 10⁶ seconds

b) 3.29 × 10⁻⁴ seconds

c) 4.82 × 10² seconds

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Separation involves dividing a mixture into its components, while purification removes impurities to obtain a pure substance. Purity can be determined through analytical techniques. Additional purification techniques may be employed if needed.

In liquid-liquid extraction, separation occurs by exploiting differences in solubility between the components in two immiscible solvents. Separation focuses on dividing a mixture into its individual components, while purification aims to remove impurities to obtain a single, pure substance.

To determine if the separated compounds are pure, you can use analytical techniques such as chromatography, melting point analysis, or spectroscopy. If the compounds are found to be impure, additional purification techniques can be applied, such as recrystallization, distillation, or chromatography, depending on the nature of the impurities and the physical and chemical properties of the compounds in question.

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The final volume of the solution would be 1200 mL when a 500.0 mL solution of 2.40 M KCl is diluted to 1.00 M as dilution involves adjusting the concentration by adding a solvent (usually water) while keeping the number of moles constant.

M₁V₁ = M₂V₂

Where: M₁ = initial concentration, V₁ = initial volume ,M₂ = final concentration, V₂ = final volume

In this case, 

M₁ = 2.40 M (initial concentration), V₁ = 500.0 mL (initial volume) ,M₂ = 1.00 M (final concentration) ,V₂ = ? (final volume)

M₁V₁ = M₂V₂

(2.40 M)(500.0 mL) = (1.00 M)(V₂)

Now, for V₂:

V₂ = (2.40 M)(500.0 mL) / (1.00 M)

V₂ = 1200 mL

The final volume of the solution would be 1200 mL 

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The reaction between nitrogen and oxygen gas to form dinitrogen monoxide has a positive entropy change in the surroundings.

This is because the reaction results in an increase in the number of gas molecules, which increases the disorder or randomness of the system. According to the second law of thermodynamics, the entropy change in the surroundings is given by the negative of the heat absorbed by the surroundings divided by the temperature at which the heat is absorbed. The exact value of the entropy change in the surroundings for this reaction depends on the specific conditions under which it occurs, such as temperature, pressure, and initial concentrations of the reactants.

The reaction between nitrogen and oxygen gas to form dinitrogen monoxide is given by:

N2(g) + O2(g) → 2NO(g)

To calculate the entropy change in the surroundings (ΔS_surroundings) associated with this reaction occurring at a specific temperature, you can use the formula:

ΔS_surroundings = -ΔH_system / T

ΔH_system is the enthalpy change of the system and T is the temperature in Kelvin. To obtain the value of ΔH_system, you can use the standard enthalpies of formation for the reactants and products. Once you have the values for ΔH_system and T, you can plug them into the formula to calculate ΔS_surroundings.

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The electron affinity of an element refers to the energy released when an electron is added to an atom of that element.

The 7A group of the periodic table is also known as the halogens and these elements have a higher electron affinity compared to the 4A group because they have one less electron in their outermost energy level or valence shell. As a result, they are more likely to attract an additional electron to complete their valence shell and achieve a more stable electron configuration. On the other hand, the 4A group or the carbon family already has a complete valence shell, which makes it more difficult for them to attract an additional electron.

Therefore, the halogens in the 7A group have a greater electron affinity than the elements in the 4A group.

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The fair test that he could do to answer the question is C. Try to scratch the marble with each of the minerals, and group the minerals that do scratch the marble together.

When he try to scratch the marble with each of the minerals in her group he can observe the results for a fair test. however One that scratches the other is harder than one that has been scratched.

Hence, Given that marble is a well-known mineral, any mineral that scratches it is harder, while those that do not are less so. and the hardness of minerals can be determined using  with the Moh's scale, with diamond being the hardest mineral and talc being the least hard.

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complete question;

Lewis has the collection of minerals shown in the picture below.He knows that a harder mineral will scratch a softer mineral. He wants to design an experiment that will answer the following question:

Which of the minerals in the collection have a greater hardness than a rock made of marble?

Which of these is a fair test that he could do to answer the question?

A.

Separate the minerals into light and dark colors, and then try to scratch the marble with the light colored minerals.

B.

Separate the minerals into ones that feel heavier and lighter, and then try to scratch the marble with the heavy minerals.

C.

Try to scratch the marble with each of the minerals, and group the minerals that do scratch the marble together.

D.

Try to scratch the pink quartz with each of the minerals, and group the minerals that do not scratch the pink quartz together.