What tool do you use to measure mass?

Answer:

Explanation: Mendeleev arranged the elements on the basis of their atomic mass. Melting and boiling point were used as the physical characteristics in deciding the position of elements. He arranged the elements and wrote the formula of their oxides and hydrides which seemed to possess same chemical formula.

Explanation:

Answer:

B. False

Explanation:

The correct fluid is intracellular. (inside cells)

Extracellular contains 1/3 of the body's water. (outside cells)

If we assume the total body contains 60% water, then roughly 2/3 of that which is 40% is the intracellular fluid and the other 1/3 or 20% is extracellular fluid. So the given statement is False. The correct option is B.

The body fluids which are not contained in the cells and they are found in the blood, lymph, etc. are defined as the extracellular fluids. The three types of extracellular fluids are interstitial compartment, intravascular compartment and transcellular compartment.

Interstitial fluids are present in the interstitial compartment, Lymphatic and blood vessels in intravascular compartment, transcellular fluids like ocular and cerebrospinal fluids in transcellular compartment.

So the extracellular fluid make up about one-third of the body fluid, the remaining two-thirds is intracellular.

Thus the correct option is B.

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#SPJ2

Answer:

6.2 g

Explanation:

The mass of oxygen gas produced from 8.5 g CO2 would be 6.2 g.

First, let us look at the equation of the reaction:

[tex]6CO_2 + 6H_2O --> C_6H_1_2O_6 + 6O_2[/tex]

From the equation, 6 moles of CO2 are required to produce 6 moles of O2.

Recall that: mole = mass/molar mass

8.5 g of CO2 = 8.5/44.01 = 0.1931 mole of CO2

Since the ratio of CO2 to O2 is 1:1, 0.1931 moles of CO2 will produce 0.1931 moles of O2.

Hence, mass of oxygen produced = mole x molar mass

                                                         = 0.1931 x 32

                                                               = 6.2 g to 2 significant digits.

The answer is 30.

Explanation:

The total number of protons and neutrons in a nucleus is called mass number. So 14 proton plus 16 neutron is = 30 mass number.

Answer:

obtain something from (a specified source).

Explanation:

Answer:

It is like the orgins of something

≈ 0,27 g/cm³

36.5 l = 36.5 dm³ = 36500 cm³

10 kg = 10000 g

d = m/V

= 10000g/36500cm³

≈ 0,27 g/cm³

Given :

2.5 mole of Sulfuric acid [tex]( H_2SO_4 )[/tex] .

To Find :

Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid

Solution :

Let us assume volume of water be 1 L .

Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .

So , for 2.5 mole sulfuric acid required 5 mole of NaOH .

Moles of NaOH ,

[tex]n=M\times Volume \\\\n=5\times 1=5\ moles[/tex]  

Molecular mass of NaOH , M.M = 58.44 g/mol .

Mass of 5 moles of NaOH :

[tex]m=5\times 58.44\ g\\\\m=292.2\ g[/tex]

Hence , this is the required solution .

Answer:

2 mL

Explanation:

Step 1: Given data

Step 2: Calculate the volume of the 10 M solution

We want to prepare a diluted solution from a concentrated one. we can calculate the volume of the initial solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.1 M × 200 mL/10 M

V₁ = 2 mL

Answer:

7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?

me to

Explanation:

Answer:

HEPES.

Explanation:

Hello,

In this case, considering the given options, and the pH requirement of 7.5, considering the Henderson-Hasselbach equation:

[tex]pH=pKa+log(\frac{[base]}{[acid]})[/tex]

The best buffer is that having the closest pKa to the required pH, thus, for the given Ka, we obtain:

[tex]pKa_{MES}=-log(Ka_{MES})=-log(7.9x10^{-7})=6.10\\\\pKa_{HEPES}=-log(Ka_{HEPES})=-log(3.2x10^{-8})=7.49\\\\pKa_{Formic \ acid}=-log(Ka_{Formic \ acid})=-log(1.8x10^{-4})=3.74\\\\pKa_{Acetic\ acid}=-log(Ka_{Acetic\ acid})=-log(1.8x10^{-5})=4.74\\\\pKa_{Tris}=-log(Ka_{Tris})=-log(6.3x10^{-9})=8.2[/tex]

Therefore, the best buffer is the HEPES since its pKa is almost the required pH.

Regards-

Answer:

All of these are true.

Explanation:

Copper lies below iron in the activity series, this implies that copper is more easily reduced than iron as its electrode potential is positive.

Also, copper is extracted easily from its sulphide ore by oxidation with oxygen. Similarly, the reduction of iron in a blast furnace requires toxic CO, hence the answer above.

Answer: Some examples are color, density, volume and mass

Explanation:

Physical properties are anything you can smell, touch, or hear. They can be observed without changing.

Answer:

CH3CH2CH2CH2CH2I > CH3CH2CH2CH2I > CH3CH2CH2I > CH3CH2I

Explanation:

The magnitude of London dispersion forces increases with increasing molecular mass and chain length. This is as a result of increase in the surface area of the molecule.

Hence, boiling points of molecules increase with increase in magnitude of London dispersion forces. This is the reason behind the ordering of molecules in the answer above.

CH₃CH₂CH₂CH₂CH₂I > CH₃CH₂CH₂CH₂I > CH₃CH₂CH₂I > CH₃CH₂I

The magnitude of London dispersion forces increases with increasing molecular mass and chain length. If there is an increase in chain length, there will be an increase in the strength of electrostatic attractions between molecules. This is as a result of increase in the surface area of the molecule.

Thus, boiling points of molecules increase with increase in magnitude of London dispersion forces.

Therefore, the order for boiling point will be as follows:

CH₃CH₂CH₂CH₂CH₂I > CH₃CH₂CH₂CH₂I > CH₃CH₂CH₂I > CH₃CH₂I

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Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

[tex]C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)[/tex]

Generally [tex]\Delta H = \Delta U + \Delta N* RT[/tex]

Here [tex]\Delta H[/tex] is the change in enthalpy

[tex]\Delta U [/tex] is the change in the internal energy

              [tex] \Delta N[/tex]  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is [tex] O_2[/tex] and  [tex]CO_2[/tex] and this are both gases so the change would occur in the number of moles

So  

[tex]\Delta H = \Delta U + [16 -23]* RT[/tex]

[tex]\Delta H = \Delta U -7RT[/tex]

The  negative sign in the equation tell us that the enthalpy[tex]\Delta_r H[/tex] would be less than the Internal energy [tex]\Delta_r U[/tex]

Answer:

See explanation

Explanation:

The slope of a graph in which mass was plotted against volume is the density of the object. Density of objects have been measured and recorded in standard handbooks for the purpose of reference. If the density of an unknown substance is measured, it can now be compared with the density of known substances recorded in standard handbooks such as the handbook of physics and chemistry. By so doing, the unknown substance can be identified.

According to standard handbooks, the density of copper is 8.96 g/ml while that of nickel is 8.908 g/ml. If the average slope obtained is around 8.96 g/ml, then the metal is copper and not nickel.

An alternative to this method is to measure the refractive index of the piece of metal and compare the average values observed with the contents of standard handbooks in order to identify the unknown metal.

Explanation:

A number can be written in the form of scientific notation as follows :

[tex]N=x\times 10^y[/tex]

x is any real number and y is integer

(a) The distance between Pluto and the Sun is 5,913,000 km.

There are 6 digits after 5. In scientific form is given by :

[tex]N=5.91\times 10^6\ km[/tex]

(b) The density of nitrogen gas is 0.0012506 g/cm³.

There are 2 digits before 1. In scientific notation,

[tex]d=1.25\times 10^{-3}\ g/cm^3[/tex]

Answer:

THE HEAT NEEDED TO CHANGE 3KG OF WATER FROM 10 C TO 80 C IS 877.8kJ OR 877,800 J.

Explanation:

Mass = 3.0 kg = 3 * 1000 = 3000 g

Initial temperature = 10 C

Final temperature = 80 C

Change in temperature = 80 - 10 = 70 C

Specific heat of water = 4.18 J/g C

Heat needed = unknown

Heat is the amount of energy in joules needed to change a gram of water by 1 C.

Heat = mass * specific heat * change in temperature

Heat = 3000 g * 4.18 J/g C * 70 C

Heat = 877 800 Joules

Heat = 877.8 kJ.

The heat needed to change 3 kg mass of water from 10 C to 80 C is 877,800 J or 877.8 kJ.

Answer:

it’s electron configuration is 1s^2 2s^2 2p^4. To determine valence electrons, add the outermost s and p orbitals. In an oxygen atom, 8 electrons are present. Electron present in the first shell (n=1) 2n^2=2 (1)^2=2 (1)=2.

Answer:

The concentration of dye in solution C is 3.02 M.

Explanation:

To find the concentration of dye in solution C we need to use the following equation:

[tex] V_{1}C_{1} = V_{2}C_{2} [/tex]

Where V is for volume and C is for concentration

In the first dilution we have:

[tex] V_{A}C_{A} = V_{T}C_{B} [/tex]

[tex] 2 mL*23.5 M = (2 mL + 12 mL)*C_{B} [/tex]                              

[tex] C_{B} = 3.36 M [/tex]

Now, in the second dilution:

[tex] V_{B}C_{B} = V_{T}C_{C} [/tex]

[tex] 9 mL*3.36 M = (9 mL + 1 mL)*C_{C} [/tex]  

[tex] C_{C} = 3.02 M [/tex]                        

Therefore, the concentration of dye in solution C is 3.02 M.

I hope it helps you!                                        

Answer:

Ksp=5.5x10^46

Explanation:

Calculate the solubility of Au(OH)3 in water

The correct answer is From different social and ethnic backgrounds.

Explanation:

The purpose of science studies is to gain an understanding of specific phenomena and use this in the benefit of the world or humanity. Moreover, science is guided by objective methods and these are applied all around the world. This feature allows scientists from all kinds of social and ethnic backgrounds to study the same phenomena and obtain similar results, which is essential for the progress of scientific knowledge. This is exemplified by two different labs in two different countries studying drug absorption because the results of these two studies can be analyzed together to understand drug absorption.

In this context, one factor that contributes to the progress of scientific knowledge is the effort of scientists "from different social and ethnic backgrounds".

Answer:

The correct answer is From different social and ethnic backgrounds.

Explanation:

right on EDGE 2021

Answer:

The answer is

Explanation:

To find the number of moles in a substance when given the molar mass and mass we use the formula

[tex]n = \frac{m}{M } [/tex]

where

n is the number of moles

M is the molar mass

m is the mass of the substance

Mr( Na) = 23 , Mr( CL ) = 35.5

Molar mass ( NaCl ) = 23 + 35.5

= 58.5 g/mol

Mass = 1.005 kg

It's equivalent in grams is

1.005 × 1000 = 1005 g NaCl

So the number of moles in NaCl is

[tex]n = \frac{1005}{58.5} \\ = 17.179487...[/tex]

We have the final answer as

17.2 mol to the nearest tenth

Hope this helps you

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

Answer:

1a. 6.70 ml of stock dye solution is required

1b. 10.0 ml of stock dye solution is required

1c. 4.00 ml of stock dye solution is required

Explanation:

1a. Using m₁v₁ = m₂v

6.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁵

v₁ = 4 * 10⁻⁴/6.00 * 10⁻⁵

v₁ = 6.70 mL of stock solution

Therefore, 6.70 ml of stock dye solution is required

b. Using m₁v₁ = m₂v

2.00 * 10⁻⁵ * v₁ = 20.0 * 1.00 * 10⁻⁵

v₁ = 2 * 10⁻⁴/2.00 * 10⁻⁵

v₁ = 10.0 mL of stock solution

Therefore, 10.0 ml of stock dye solution is required

c. Using m₁v₁ = m₂v

1.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁶

v₁ = 4 * 10⁻⁵/1.00 * 10⁻⁵

v₁ = 4.00 mL of stock solution

Therefore, 4.00 ml of stock dye solution is required

The procedure is then followed as in steps 2 to 4.

To perform the calculations in order to determine the amount of 6.00x10.5 M stocks solution of 20.00 ml is need to be made in order to calculate the amount of dye solution.

Learn more about the perform the calculations.

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Answer:

142 ft² (Approx)

Given:

Use feet as measurement device( Approx a foot long)

10.5’ × 13.5’ = 141.75 ft²

Find:

Best area for room

Explanation:

We know that Philip uses his feet to measures the area of the room which is not a proper unit of measurement, so we will take Philip's measurement to the maximum absolute unit

So,

Area of the room = 142 ft² (Approx)

Answer:

The quantity of heat necessary to change the temperature of 3.00 mol of the substance from 27°C to 227°C is 19.668 KJ

Explanation:

From the question, The empirical equation is

C=29.5J/(mol⋅K)+(8.20×10−3J/(mol⋅K2))T

[tex]C=29.5J/(mol.K)+(8.20\times 10^{-3} J/(mol.K^{2} ))T[/tex]

Now, to determine the heat necessary to change the temperature of 3.00 mol of this substance from 27∘C to 227∘C, that is ΔQ

From, dQ=nCdT

Integrating both sides, we get

[tex]\int\limits^ {Q_{2}} _{Q_{1}} {dQ} \, = \int\limits^ {T_{2} }_{T_{1} } nC \, dT[/tex]

[tex]{Q_{2}} -{Q_{1}} = \int\limits^ {T_{2} }_{T_{1} } n[ {29.5J/(mol.K)+(8.20\times 10^{-3} J/(mol.K^{2} ))T} \, ]dT[/tex]

[tex]\Delta Q = \int\limits^ {T_{2} }_{T_{1} } 3.00mol[ {29.5J/(mol.K)+(8.20\times 10^{-3} J/(mol.K^{2} ))T} \, ]dT[/tex]

[tex]\Delta Q = \int\limits^ {T_{2} }_{T_{1} } [ {88.5J/K+ (24.6\times 10^{-3} J/K^{2} )T} \, ]dT[/tex]

[tex]\Delta Q = \int\limits^ {T_{2} }_{T_{1} } {88.5J/KdT + \int\limits^ {T_{2} }_{T_{1} } 24.6\times 10^{-3} J/K^{2} T} dT[/tex]

[tex]\Delta Q =(88.5J/K )\int\limits^ {T_{2} }_{T_{1} } dT + (24.6\times 10^{-3} J/K^{2})\int\limits^ {T_{2} }_{T_{1} } T} dT[/tex]

(NOTE: [tex]\int {dx} = x[/tex] and [tex]\int\ {x} \, dx = \frac{x^{2} }{2}[/tex] )

Hence, we get

[tex]\Delta Q =(88.5J/K )({T_{2} }-{T_{1} )+ (24.6\times 10^{-3} J/K^{2}) (\frac{T_{2}^{2} }{2} - \frac{T_{1}^{2} }{2} )[/tex]

From the question, [tex]T_{1}[/tex] = 27 °C = (27+273) K = 300K

Also, [tex]T_{2}[/tex] = 227 °C = (227+273) K = 500K

Then,

[tex]\Delta Q =(88.5J/K )(500K - 300K )+ (24.6\times 10^{-3} J/K^{2}) (\frac{(500K)^{2} }{2} - \frac{(300K)^{2} }{2} )[/tex]

[tex]\Delta Q =(88.5J/K )(200K )+ (24.6\times 10^{-3} J/K^{2}) (80\times 10^{3} K^{2} )[/tex]

[tex]\Delta Q =17700J +1968J \\[/tex]

[tex]\Delta Q =19668J[/tex]

[tex]\Delta Q =19.668KJ[/tex]

Hence, the quantity of heat necessary to change the temperature of 3.00 mol of the substance from 27°C to 227°C is 19.668 KJ

(NOTE: KJ means Kilo Joules)