What would be the cost for 5 of the gift cards?

Answer:

Yes

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

4 + -x ==> 4 - x

Example

x = 3; 4 + (-3) = 4-3 =1

Answer:

A

Step-by-step explanation:

I assume that the whole expression a⁸a³ is under the square root.

then remember 2 things :

1. when multiplying the same base variable (or constant) the result is that single base variable (or constant) to the power of the sum of the exponents.

e.g. x³x² = x⁵ because

x×x×x × x×x = x×x×x×x×x = x⁵

2. a square root as exponent is 1/2.

a cubic root is 1/3 and so on.

therefore

sqrt(a⁸a³) = sqrt(a¹¹) = a^11/2

The solution for the given equation will be x=7.8873 and x=0.112699.

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

Find the Solution for

9x²−72x+8=0

using the Quadratic Formula where

a = 9, b = -72, and c = 8

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\dfrac{(-72)\pm\sqrt{(-72)^2-4(9)(8)}}{2(9)}[/tex]

x=   [tex]\dfrac{72\pm4896}{\sqrt{18}}[/tex]

The discriminant b2−4ac>0

so, there are two real roots. After solving for plus and then minus we will get two values as follows.

x=7.8873

x=0.112699

Therefore the solution for the given equation will be x=7.8873 and x=0.112699.

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Answer:

No. There should be 210 small triangles

Step-by-step explanation:

The number of small triangles in these figures forms a sequence

Fig         No Small Triangles
1             1
2            3  (1+2)
3            6  (1+2+3)

So the nth figure should have 1+2+3+.....+(n-1)+ n

1+2+3+.....+(n-1)+ n = [tex]\frac{n (n-1)}{2}[/tex]
So for 20th figure, n = 20 and number of small triangles = 20 x 21 /2 = 420/2 = 210

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Answer:  [tex]\textsf{Option A, (-2, 4)}[/tex]

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Given:  [tex]\textsf{f(x) = x + 6}[/tex]

Find:  [tex]\textsf{f(-2)}[/tex]

Solution:  We need to plug in the value -2 into every variable x that we have in the expression and simplify to get the solution.

Plug in the values

Simplify

Therefore, the ordered pair that would match would have a x-coordinate of -2 and a y-coordinate of 4 producing (-2, 4) which matches option A.

Answer:

There are 240 students in the school

Step-by-step explanation:

Givens

55% of the total number of students in a school are girls.

Equation

55/100 * x = 132

Solution

Multiply both sides of the equation  by 100

55/100x * 100  = 132 * 100

55x = 13200                          Divide by 55

55x/55  = 13200/55

x = 240

Answer:

cos65 = sin25 = p

tan205 = tan25 = p/√(1-√p)

Step-by-step explanation:

trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (cosec)

some Trigonometric identities used in the question:

in the question it is given,

sin25 = p

using above mentioned identity:-

cos 65 = cos(90-25) = sin25 = p

hence value of cos65 is p.

for, tan205 we have to first find the cos25

so to find cos25 we use above mentioned identity,

cos²25 + sin²25 = 1

cos²25 + √p      = 1

cos²25               = 1-√p

cos25               = √(1-√p)  

now to find out tan205 use third identity mentioned above,

tan205 = tan(π+25) = tan25

tan25 = sin25/cos25

tan25 = p/√(1-√p)  

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Answer:

x = 10

Step-by-step explanation:

5(2x - 12) + 21 = 2x + 41 ← distribute parenthesis and simplify left side

10x - 60 + 21 = 2x + 41

10x - 39 = 2x + 41 ( subtract 2x from both sides )

8x - 39 = 41 ( add 39 to both sides )

8x = 80 ( divide both sides by 8 )

x = 10

Step-by-step explanation:

[tex] = 4x - 8y + 6 {x}^{2} + 3x - 5y[/tex]

[tex] = 6 {x}^{2} + (4x + 3x) + ( - 8y - 5y)[/tex]

[tex] = 6 {x}^{2} + 7x - 13y[/tex]

The answer is B.

Answer:

b.) 6x² + 7x - 13y

Explanation:

Given Expression

= 4x - 8y + 6x² + 3x - 5y

collect like terms

= 6x² + 4x + 3x -8y - 5y

combine similar terms

= 6x² + 7x - 13y

Answer:

The choice D.

[tex]f(x) = 3 {(0.2)}^{x} [/tex]

Answer:

D

Step-by-step explanation:

Order of elimination:

1. the graph is going down exponentially. This means that the base is less than 1.

A and C are eliminated.

2. When x is equal to 0, f(x) = 3.

Substitute x for 0, and you'll find out that the only one possible is D.

It is to be noted that the Graph of the indicated inequalities is herewith attached.

As indicated above, this is a graph of a system of inequalities, where:

Y > -4x-1 and

y <3/2x-1

No. the point (-1, 1) is not included in the solution area for the system.

Step 1 - Plug in (-1, 1) in to the first equation. where y = -1 and x = 1.

Hence,

-1 > -4(1) -1

4 +1 < -1

4 < 0 (This is False)

Step 2  - Plug in (-1, 1) in to the second equation. where y = -1 and x = 1.

-1 < (3/2)(1) - 1

-1 < 1/2 (This is true).

Thus (-1, 1) is only partially included in the solution area.)

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Answer:

A fraction equivalent to [tex]\frac{1}{2}[/tex] on the number line is [tex]\frac{3}{6}[/tex].

Drag the dot to [tex]\frac{3}{6}[/tex] on the number line.

Step-by-step explanation:

3 is half of 6. To check if this is correct multiply [tex]\frac{1}{2}[/tex] and 3.

[tex]\frac{1}{2}*3=\frac{3}{6}[/tex]

Hope this helps!

If not, I am sorry.

The values of k and r are given by 5 and 3 respectively.

Here in this problem it is given that,

General formula for the sequence is given by,

[tex]U_{n+1}=kU_n+r[/tex]

First term of the sequence, [tex]U_1=37[/tex]

Second term,

[tex]U_2=188[/tex]

[tex]U_{1+1}=188[/tex], rearranging

[tex]kU_1+r=188[/tex], applying general formula

[tex]37k+r=188[/tex]..........(1)

Third term,

[tex]U_3=943[/tex]

[tex]U_{2+1}=943[/tex], rearranging

[tex]kU_2+r=943[/tex], applying general formula

[tex]188k+r=943[/tex]..........(2)

Now (2) - (1) we get,

188k+r-37k-r = 943-188

151k = 755

k = 755/151 = 5

Hence the value of k is 5.

Substituting the value of k in (1) we get,

37*5+r = 188

185+r = 188

r = 188-185 = 3

Thus the value of r is 3.

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Answer:

[tex]12z^{2} -10z -12[/tex]

Step-by-step explanation:

Let the number be z

2 more than 3 times z ==> 3z + 2

6 less than 4 times z ==> 4z - 6

Product of the above two is
[tex](3z + 2) (4z - 6) \\= (3z)(4z) + (3z)(-6) + (4z)(2) + (2)(-6)\\= 12z^{2} -18z + 8z - 12\\= 12z^{2} -10z -12[/tex]

Answer:

x = 3

y = 2

Step-by-step explanation:

3x + 2y = 12

-2x + 3y = 5 to find the solution we will use elimination method and for that, multiply second equation with 3 and the first equation with 2

2 * 3x + 2y = 12

6x + 4y = 24

3 * -2x + 3y = 5

-6x + 9y = 15  now find the sum of both equation:

6x + 4y  -6x + 9y = 24 + 15 add like terms

13y = 39 divide both sides by 13

y = 3 now that we found the value of y we can use this to calculate the value of x

3x + 2y = 12 replace y with 3

3x + 2*2 = 12

3x + 4 = 12 subtract 4 from both sides

3x = 9 divide both sides by 3

x = 3

Answer:

240

Step-by-step explanation:

Using the straight line formula; y=mx+c, take two points, for example, (4, 80) and (5, 100)

m=change in y/change in x, so;

m=(100-80)/(5-4)= 20

Take point (4, 80)

80=20×4 + c

80-80=c=0

so y=20x

y=20×12=240

Answer: A

Step-by-step explanation:

[tex]\frac{dy}{dx}=\frac{1+x}{xy} \\ \\ y \text{ } dy=\frac{1+x}{x} \text{ } dx \\ \\ y \text{ } dy= \left(\frac{1}{x}+1 \right) \text{ } dx \\ \\ \int y \text{ } dy=\int \left(\frac{1}{x}+1 \right) \text{ } dx \\ \\ \frac{y^{2}}{2}=\ln \left| x \right|+x+C[/tex]

Substituting in the initial condition,

[tex]\frac{(-2)^{2}}{2}=\ln \left|1 \right|+1+C\\\\2=1+C\\\\C=1[/tex]

So,

[tex]\boxed{\frac{1}{2}y^{2}=\ln \left|x \right|+x+1}[/tex]

Answer:

[tex]\textsf{A.} \quad \dfrac{1}{2}y^2=\ln|x|+x+1[/tex]

Step-by-step explanation:

To solve the differential equation:

Rearrange the given equation to get all the terms containing y on the left side, and all the terms containing x on the right side:

         [tex]\dfrac{dy}{dx}=\dfrac{1+x}{xy}[/tex]

[tex]\implies y\dfrac{dy}{dx}=\dfrac{1+x}{x}[/tex]

[tex]\implies y\:dy=\dfrac{1+x}{x}\:dx[/tex]

[tex]\implies y\:dy=\dfrac{1}{x}+\dfrac{x}{x}\:dx[/tex]

[tex]\implies y\:dy=\left(\dfrac{1}{x}+1\right)\:dx[/tex]

Integrate both sides:

[tex]\displaystyle \implies \int y\:dy=\int \left(\dfrac{1}{x}+1\right)\:dx[/tex]

[tex]\implies \dfrac{1}{2}y^2=\ln|x|+x+C[/tex]

Find the value of C using the given values of x and y:

when x = 1, y = -2

[tex]\implies \dfrac{1}{2}(-2)^2=\ln|1|+1+C[/tex]

[tex]\implies 2=0+1+C[/tex]

[tex]\implies C=1[/tex]

Substitute the found value of C:

[tex]\implies \dfrac{1}{2}y^2=\ln|x|+x+1[/tex]

Answer #1:

The total cost with 6 snacks is $78.

Answer #2:

The total cost with x snacks is represented by the expression 60 + 3x.

Step-by-step explanation for answer #1:

Starting off with what we know:

To answer the question of how much money Genesis would have to pay for her family if she bought 6 snacks for everybody, first consider the total cost of the movie tickets.

Multiply the total number of people by the cost of each movie ticket:

[tex]4* 15=60[/tex]

Genesis will be paying $60 total only to see the movie with her 3 kids. To find the total cost of both seeing the movie and buying 6 snacks, simply multiply the number of snacks by the cost of each snack:

[tex]6 * 3=18[/tex]

Then, add the total cost of the movie tickets by the total cost of the snacks to achieve your first answer:

[tex]60+18=78[/tex]

The total cost with 6 snacks is $78.

Step-by-step explanation for answer #2:

To find the total cost of "x" snacks (x is being used as a variable term to represent a quantity subject to change), we can create an algebraic expression.

Let "t" represent the total cost.

Since we've established that finding the total cost is just a matter of adding the total cost of movie tickets (60) and the total cost of snacks (3 multiplied by the number of snacks), let "x" represent the number of snacks in the equation to find the total cost with x snacks:

[tex]60+3x=t[/tex]

The total cost with x snacks is represented by the expression 60 + 3x.

Based on the given data, the total cost of 6 snacks: $78. total cost with x snacks: $60 + (3x).

Use the concept of multiplication defined as:

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that,

Genesis is going to see a movie with her 3 kids.

Each movie ticket costs $15.

There are snacks available for purchase at $3 each.

Genesis wants to buy 6 snacks for everybody to share.

To calculate the total cost for Genesis and her 3 kids,

Consider the movie tickets and the snacks.

The cost of the movie tickets can be calculated by multiplying the number of people (4 in this case) by the cost of each ticket ($15).

So, Genesis would have to pay 4 x $15 = $60 for the movie tickets.

Now, let's calculate the total cost if Genesis were to buy 6 snacks for everybody to share.

Each snack costs $3, so 6 snacks would cost 6 x $3 = $18.

Therefore, the total cost for Genesis would be,

$60 (movie tickets) + $18 (snacks) = $78.

If we consider x snacks for everybody to share,

The total cost for snacks would be x $3.

So, the final cost would be $60 (movie tickets) + (3x) (snacks).

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Answer:

9. 15b + 4

10. 4y + 6

11. 15r+72

12. 130n + 20

Step-by-step explanation:

9. Combine Like terms

10. Combine Like terms

11. Distribute the 8 into (r + 9) then combine like terms

12. Distribute 10 into (3n + 2 + 10n) then combine like terms

Answer:

[tex]\mathsf {9) 15b + 4}\\\mathsf {10) 4y + 6}\\\mathsf {11) 15r + 72}\\\mathsf {12) 130n + 20}[/tex]

Step-by-step explanation:

[tex]\textsf {Question 9}[/tex]

[tex]\mathsf {3 + 8b + 4 + 7b - 3}[/tex]

[tex]\mathsf {8b + 7b + 4 + 3 - 3}[/tex]

[tex]\mathsf {15b + 4}[/tex]

[tex]\textsf {Question 10}[/tex]

[tex]\mathsf {8 + 7y - 3y + 2 - 4}[/tex]

[tex]\mathsf {7y - 3y + 8 + 2 - 4}[/tex]

[tex]\mathsf {4y + 6}[/tex]

[tex]\textsf {Question 11}[/tex]

[tex]\mathsf {8(r + 9) + 7r}[/tex]

[tex]\mathsf {8r + 8(9) + 7r}[/tex]

[tex]\mathsf {8r + 7r + 72}[/tex]

[tex]\mathsf {15r + 72}[/tex]

[tex]\textsf {Question 12}[/tex]

[tex]\mathsf {10(3n + 2 + 10n)}[/tex]

[tex]\mathsf {10(13n + 2)}[/tex]

[tex]\mathsf {10(13n) + 10(2)}[/tex]

[tex]\mathsf {130n + 20}[/tex]

Answer: Quadrant III

Step-by-step explanation:

The slope is negative and the y-intercept is positive.

This means that it is impossible for both x and y to be negative, and thus it does not pass through Quadrant III

i. Cube of any odd number is even. False

ii.  A perfect cube does not end with two zeros. True

iii.  If square of a number ends with 5, then its cube ends with 25. False

iv. There is no perfect cube which ends with 8. False

v. The cube of a two digit number may be a three digit number. False

vi.  The cube of a two digit number may have seven or more digits. False

vii. The cube of a single digit number may be a single digit number. True

i.  Cube of any odd number is even. This statement is false because the cube of odd numbers are also odd

ii.  A perfect cube does not end with two zeros. This statement is True because the cube of a two digit number cannot be a 3 digit number and therefore cannot end with two zeros.

iii.  If square of a number ends with 5, then its cube ends with 25. This statement is False

Using the illustration

35^2 = 35 x 35= 1225 , its square ends with 5

35^3= 35 x 35 x 35= 42875 which ends with 75

iv.  There is no perfect cube which ends with 8. This statement is False.

Using the illustration, the cube of 2 is given thus

2 * 2 * 2 = 8

The cube of 2 ends with 8

v. The cube of a two digit number may be a three digit number. This statement is False.

Using the illustration, 10 is a two digit number

10 * 10 * 10 = 1000

The cube of 10 which is a two digit number is not a three digit number and same applies to all two digit numbers

vi  The cube of a two digit number may have seven or more digits. This statement is False because the cube of a two digit number can only be a four digit number.

vii. The cube of a single digit number may be a single digit number. This statement is True because the cube of a single digit number can be a single, two or three digit number.

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[tex] \frac{ - n}{5} + 7 = 2 \\ \\ \frac{ - n + 35}{5} = 2 \\ \\ - n + 35 = 10 \\ \\ - n = 10 - 35 \\ \\ - n = - 25[/tex]

cancel (-) sign both sides ,

[tex]n = 25.[/tex]

Step-by-step explanation:

please mark me as brainlest

Answer:

n = 250

See solution and check blow.

Step-by-step explanation:

Solution:

-17 + n/5 = 33

Add 17 to both sides.

-17 + 17 + n/5 = 33 + 17

n/5 = 50

Multiply both sides by 5.

n/5 × 5 = 50 × 5

n = 250

Check:

-17 + n/5 = 33

Since we found out that n = 250, substitute 250 for n in the equation.

-17 + 250/5 = 33

Simplify the left side. Divide 250 by 5.

-17 + 50 = 33

Add on the left side.

33 = 33

Since 33 = 33 is a true statement, the solution n = 250 is correct.

Answer:

Step-by-step explanation:

30 is an opposite angle (2 angles of 30°)

sum of all angles = 360°

360 - 90 -30 - 150 - 30 = 60°

check

60 + 30 + 150 + 30 + 90 = 360°

the answer is good

Answer:

b = 60

Step-by-step explanation:

A straight line is 180 degrees

30+90+b = 180

Combine like terms

120 +b = 180

b =180-120

b = 60

£36

20+25=45          Take away 13 and it's 32.   32+4 (the shipping charge) is 36. So Ruth pays 36 pounds.

Answer:

(f+g)(x)

= |3x+5| + 13

Step-by-step explanation:

(f+g)(x) means

f(x) + g(x)

so you add the functions together.

|3x+5| + 6 + 7

And simplify.

|3x+5| + 13

Using an exponential function, it is found that the half-life of the substance is of 5.23 units of time.

The function is given by:

[tex]A(t) = A(0)e^{-kt}[/tex]

In which:

The parameters are given by:

A(0) = 48,  k = 0.1325.

Hence the equation is:

[tex]A(t) = 48e^{-0.1325t}[/tex]

The half-life is the amount of time for which A(t) = 0.5A(0) = 24, hence:

[tex]A(t) = 48e^{-0.1325t}[/tex]

[tex]24 = 48e^{-0.1325t}[/tex]

[tex]e^{-0.1325t} = 0.5[/tex]

[tex]\ln{e^{-0.1325t}} = \ln{0.5}[/tex]

[tex]0.1325t = -\ln{0.5}[/tex]

[tex]t = -\frac{\ln{0.5}}{0.1325}[/tex]

t = 5.23.

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The line is drawn at point A and Point C is a line of symmetry because lines of symmetry make exactly two halves with similar shapes and sizes.

It is defined as the line which will make exactly two halves with similar shape and size in geometry. For a two-dimensional shape, there is a line of symmetry, and for three-dimensional shapes, there is a plane of symmetry. In other words, if we make a mirror image of the shape around the line of symmetry, we will get exactly the same half portion.

We have given a figure in the picture.

The figure is a quadrilateral(a kite)

As we know, lines of symmetry make exactly two halves with similar shapes and sizes.

IF we draw a line from Point A to Point C we will get two similar and figures in size and shape.

Thus, the line is drawn point A and Point C is a line of symmetry because lines of symmetry make exactly two halves with similar shapes and sizes.

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Answer:

point C

Here is a step-by-step explanation of the statement:

1. Draw a point B and a point C on a piece of paper or a computer screen.

2. Draw a straight line that goes through both point B and point C.

3. Fold the paper along the line you just drew, so that the line is the fold line.

4. Notice that if you were to fold the paper exactly in half along the line, point B would match up with its reflection on the other side of the line, and point C would match up with its reflection on the other side of the line.

5. This means that the line you drew is a line of symmetry, because it divides the paper into two identical halves that can be folded together.

6. Therefore, the statement "A line drawn through point B and point C is a line of symmetry" is true.