What’s the correct answer for this question?

Answer:

175

Step-by-step explanation:

+ × - = -

thus 199+(-24)

199-24

175

Answer: 199 + -24 = 175

Step-by-step explanation: 199 is a positive number and -24 is a negative number. If the positive number is bigger than the negative number you subtract. So forget that the - sign is there and subtract it.  

Answer:

[tex](\frac{3}{8}\,in )^2=\frac{9}{64} \,in^2=0.140625\,\,i^2[/tex]

Step-by-step explanation:

Recall that the formula for the area of a square of side L is: [tex]Area=L^2[/tex]

Therefore, for this case:

[tex]Area=L^2\\Area = (\frac{3}{8} \,in)^2\\Area=\frac{9}{64} \,\,in^2\\Area=0.140625\,\,in^2[/tex]

Answer:

4cos=2X

X=3-4COS

X=-1

Answer:

D. (2, 3, 4)

Step-by-step explanation:

The range is the y values. The y values, in numerical order, range from 2 to 4. The 2s do not need to be repeated.

Answer:

-1, 1

13, 15

Step-by-step explanation:

x and x+2 are the integers

Roots of the quadratic equation are: -1 and 13.

So the integers pairs are: -1, 1 and 13, 15

Answer:

15-6x= -12-4x

15-2x= -12

-2x= -27

x= -13.5

Step-by-step explanation:

Answer:

40°

Step-by-step explanation:

2x = 3x - 20 add like terms

x = 20 and angle l is equal to 3x minus 20 so 3 × 20 - 20 = 40°

Answer:

bh

6, 17

102

51

Step-by-step explanation:

Answer:

1/2 (bh)

1/2(17)(6)

51

Answer:

Option (B)

Step-by-step explanation:

Coordinates of the vertices of the rectangle were A(0, 0), B(a, 0), C(a, b) and D(0, b)

Formula to determine the distance between two points with the vertices (x, y) and (x', y') is,

d = [tex]\sqrt{(x-x')^2+(y-y')^2}[/tex]

For the length of AD,

AD = [tex]\sqrt{(0-0)^2+(b-0)^2}[/tex]

     = [tex]\sqrt{b^2}[/tex]

     = b

Therefore, Option (B) will be the answer.

Answer:

Step-by-step explanation:

The original equation is [tex]121y''+110y'-24y=0[/tex]. We propose that the solution of this equations is of the form [tex] y = Ae^{rt}[/tex]. Then, by replacing the derivatives we get the following

[tex]121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)[/tex]

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

[tex]121r^2+110r-24=0[/tex]

Recall that the roots of a polynomial of the form [tex]ax^2+bx+c[/tex] are given by the formula

[tex] x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}[/tex]

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

[tex]r_1 = -\frac{12}{11}[/tex]

[tex]r_2 = \frac{2}{11}[/tex]

So, in this case, the general solution is [tex]y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}[/tex]

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

[tex]c_1 + c_2 = 1[/tex]

[tex]c_1\frac{-12}{11} + c_2\frac{2}{11} = 0[/tex](or equivalently [tex]c_2 = 6c_1[/tex]

By replacing the second equation in the first one, we get [tex]7c_1 = 1 [/tex] which implies that [tex] c_1 = \frac{1}{7}, c_2 = \frac{6}{7}[/tex].

So [tex]y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}[/tex]

b) By using y(0) =0 and y'(0)=1 we get the equations

[tex] c_1+c_2 =0[/tex]

[tex]c_1\frac{-12}{11} + c_2\frac{2}{11} = 1[/tex](or equivalently [tex]-12c_1+2c_2 = 11[/tex]

By solving this system, the solution is [tex]c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}[/tex]

Then [tex]y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}[/tex]

c)

The Wronskian of the solutions is calculated as the determinant of the following matrix

[tex]\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2[/tex]

By plugging the values of [tex]y_1[/tex] and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

[tex]e^{\int -p(x) dx}[/tex]

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

[tex]e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}[/tex]

Note that this function is always positive, and thus, never zero. So [tex]y_1, y_2[/tex] is a fundamental set of solutions.

Answer:

Step-by-step explanation:

a) The probability of a Type I error in a lie detection test would be the probability that the lie detection machine incorrectly detected lie for the truth tellers. This is already given in the problem as 0.07.

Therefore,

[tex]P(Type-I) = 0.07[/tex]

Therefore 0.07 is the required probability here.

b) The probability of a Type II error in a lie detection test would be the probability that the lie detection machine incorrectly detected truth for the the people who are actually liars. This is thus 1 - reliability.

[tex]P(Type-II) = 1 - Reliability = 1- 0.86 = 0.14[/tex]

Therefore 0.14 is the required probability here.

Answer:

a) 0.070

b) 0.14

Step-by-step explanation:

Given that the tests are 86% reliable, i.e a probability of 0.86 a lie would be detected.

Probability of error = 0.070

a) For type I error, we have:

The probability of a type I error in this lie detector is the probability that the test erroneously detects a lie even when the individual is actually telling the truth, i.e

P(type I error) = P(rejecting true null)

= 0.070

b) The probability of a Type II error this lie detectot is the probability that the test erroneously detected truth insteax of lie.

i.e = 1 - reliability

P (Type II error) = P(Failing to reject false Null)

= P(Not detecting a lie)

= 1-0.86

= 0.14

Answer:

Set the height up to 4

Step-by-step explanation:

Since there are 4 numbers between 1-5, set the height up to 4

Answer:

4 temperature recordings.

Step-by-step explanation:

2, 2, 4, 5

There are 4 recordings in the range of 1-5°C.

Answer:

f(2) = f(3) = 102 ft

Step-by-step explanation:

The height f at t = 2 seconds is given by:

[tex]f(t) = -16t^2 + 80t + 6\\f(2) = -16*2^2 + 80*2 + 6\\f(2)=-64+160+6\\f(2)=102\ ft[/tex]

The height f at t = 3 seconds is given by:

[tex]f(t) = -16t^2 + 80t + 6\\f(3) = -16*3^2 + 80*3 + 6\\f(3)=-144+240+6\\f(3)=102\ ft[/tex]

For both t =2 and t =3, the expression results in a height of 102 ft, therefore f(2) = f(3) = 102 ft.

Answer:

662

Step-by-step explanation:

l x w

10x41

6x22

8x15

662

Answer:

2 & 8

-4 & -4

Step-by-step explanation:

x and y are the numbers, as per question:

x= 4+2y and xy= 16

Answer:

Peter gets 18£

Gordon and Gavin each get 9£

Answer:

peter = 18 Gordon = 9 Gavin = 9

Step-by-step explanation:

2+1+1 = 4

36 div 4 = 9

2 times 9 = 18

1 times 9 = 9

Answer:

5/6

Step-by-step explanation:

Find the factor that divides both numbers...

25/5=5

30/5=6

5/6 is the simplified ratio

P.S. Please give me brainliest, i have only have two!

Answer:

1/3:1/4

Step-by-step explanation:

203/259

write in simplest form

2 hours to 45 seconds

Express ratio

15:1

simplest form

1/3:1/4

Answer:

Brainelist?

Step-by-step explanation:

7-4i

just use a online calculator

Answer:

7-4i

Step-by-step explanation:

(2 - 3i)(2 + i)​

FOIL

first 2*2 = 4

Outer: 2i

Inner: -3i*2 = -6i

Last: -3i*i = -3i^2 = -3(-1) = 3

Add them together

4+2i-6i+3

7-4i

Answer:

D

Step-by-step explanation:

Step-by-step explanation:

in mathematics, a basic algebra corporation is there any one of the traditional operation of arithmetic, which are addition, subtraction, multiply, division, rising to an integer power, and taking root (fractional power ).

Answer:

  G(x) = x^2 -10x +25

Step-by-step explanation:

To translate F(x) 5 units to the right, replace x with (x-5).

  G(x) = F(x-5) = (x -5)^2

  G(x) = x^2 -10x +25

Answer:

Class width = 20

Approximate lower class limit of the first class = 110

Approximate Upper class limit of the first class = 119

Step-by-step Explanation:

The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.

Thus, class width = 130 - 110 = 20

The approximate lower class limit of the first class is the lowest score we have in the first class = 110

The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129

Answer:

The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.

Step-by-step explanation:

For each bag, there are only two possible outcomes. Either it arrives on time to it's intended destination, or it does not. The probability of a bag arriving on time is independent of other bags. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Luggage checked-in at Airline A arrives on time to its intended destination with a probability of 0.63.

This means that [tex]p = 0.63[/tex]

In a random sample of 2000 bags

This means that [tex]n = 2000[/tex]

Mean and standard deviation of the number of bags that arrive on time to its intended destination:

[tex]E(X) = np = 2000*0.63 = 1260[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{2000*0.63*0.37} = 21.59[/tex]

The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.

Answer:

66%

Step-by-step explanation:

15% of homes have both features.

The percentage of homes that have a pool and no garage is:

Pool only = 19% - 15% = 4%

The percentage of homes that have a garage and no pool is:

Garage only = 62% - 15% = 47%

Therefore, the percentage of homes that have a pool, a garage or both is:

[tex]P = 4\%+47\%+15\%\\P=66\%[/tex]

Answer:

B and G

Step-by-step explanation:

Square and rectangle

Answer:

-4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello!

The statistical model predicts the appraised value of houses in a section of the county East Meadow (Y) in relationship with the number of rooms of the house (X)

For a sample of n=64 houses the simple linear regression was estimated:

^Y= 74.80 + 24.93X

Range of X: 5 - 11

Range of Y: 160 - 300 ($ thousands of dollars)

Interpretation of the estimates of the y-intercept and the slope

y-intercept:

74.80 thousand dollars is the estimated average value of a house in a section of the county East Meadow when the house has zero rooms.

Slope:

24.93 [tex]\frac{thousand dollars}{rooms}[/tex] is the modification of the estimated average value of a house in a section of the county East Meadow when the number of rooms increases on one.

I hope this helps!

The answer would be -3 13/81 (simplified)

Answer:

B

Step-by-step explanation: