Explanation:
Given that,
Current, I = 0.015 A
Voltage, V = 240 volts
We need to find the resistance. Using Ohm's law we can find it as follows :
[tex]V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega[/tex]
So, When a current of 0.015 A passes through human body at 240 volts p.d it causes 16000 ohms of resistance.
Which statement is TRUE?
A) Energy can be created or destroyed.
B) Electrical energy is created from other forms of energy.
C) Energy in a battery makes new energy called electrical energy.
D) Stored energy in a battery can be transformed into electrical energy.
A hot air balloon is descending with a velocity of 2.0 m/s straight down. At a height of 6m, a champagne bottle is opened to celebrate a successful flight, expelling the cork horizontally with a velocity of 5.0 m/s. a. What is the initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground? b. What are the horizontal and vertical components of the initial velocity? c. How long is the cork in the air? d. How far away from the balloon does it land?
Answer:
a
[tex]v = 5.39 \ m/s[/tex]
b
Horizontal component
[tex]v_x = 5.00 \ m/s[/tex]
vertical component
[tex]v_y = - 2.0 \ m/s[/tex]
c
[tex]t = 0.921 \ s[/tex]
d
[tex]d = 4.605 \ m [/tex]
Explanation:
Generally from the question we can deduce that he initial velocity of the cork, as seen by an observer on the ground in terms of the x unit vector is
[tex]v_x = 5.00 \ m/s[/tex] due to the fact that the cork is moving horizontally
Generally from the question we can deduce that the vertical and horizontal components of the initial velocity is
[tex]v_y = - 2.0 \ m/s[/tex] due to the fact that the balloon is moving downward which is the negative which will also cause the cork to move vertically with the balloon speed
Generally the initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground is mathematically represented as
[tex]v = \sqrt{ v^2 _x + v^2 _y }[/tex]
[tex]v = \sqrt{ 5^2 + (-2)^2 _y }[/tex]
[tex]v = 5.39 \ m/s[/tex]
Generally the initial direction of motion as seen by the same observer is mathematically represented as
[tex]\theta = tan^{-1}[\frac{2}{5} ][/tex]
[tex]\theta = 21.80^o[/tex]
Generally the time taken by the cork in the air before landing is mathematically represented as
[tex]D = ut + \frac{1}{2} g t^2[/tex]
So D = 6 \ m from the question
g = 9.8 \ m/s^2
u = [tex]v_y[/tex] = 2 m/s this because we are considering the vertical motion
So
[tex]6 = 2 t + \frac{1}{2} * 9.8* t^2[/tex]
[tex]6 = 2 t + 4.9 t^2[/tex]
Solving using quadratic formula w have that
[tex]t = 0.921 \ s[/tex]
Generally the distance of the cork from the balloon is mathematically represented as
[tex]d = v_x * t[/tex]
[tex]d = 5 * 0.921 [/tex]
[tex]d = 4.605 \ m [/tex]
During a relay race, runner A runs a certain distance due north and then hands off the baton to runner B, who runs for the same distance in a direction south of east. The two displacement vectors A and B can be added together to give a resultant vector R. Which drawing correctly shows the resultant vector?
Answer:
d) 4
Explanation:
The image attached shows the options.
The resultant vector is the resultant of two or more vectors. The resultant vector is gotten by adding the sum of the displacement of the vectors together (that is the sum of all the individual vectors).
From the question, since runner A runs north and runner B runs east the resultant vector would be the sum of the displacement of vectors A and B. Also, the direction of the vector would be the north east starting from the beginning of vector A to end of vector B. The correct option is d) 4
Suppose that a particle accelerator is used to move two beams of particles in opposite directions. In a particular region, electrons move to the right at 7130 m/sand protons move to the left at 2583 m/s. The particles are evenly spaced with 0.0288 m between electrons and 0.0747 m between protons. Assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region?
Answer:
Total current, [tex]I=4.51\times 10^{-14}\ A[/tex]
Explanation:
Velocity of electrons is 7130 m/s and particles are evenly spaced with 0.0288 m between electrons. We can find no of electrons passing per second as follows :
[tex]n_e=\dfrac{7130\ m/s}{0.0288\ m}\\\\n_e=247569.44[/tex]
Velocity of protons is 2583 m/s and particles are evenly spaced with 0.0747 m between electrons. We can find no of protons passing per second as follows :
[tex]n_p=\dfrac{2583 \ m/s}{0.0747 \ m}\\\\n_p=34578.31[/tex]
Total current in this region is equal to sum of current due to electrons and current due to protons.
[tex]I=n_e\times e+n_p\times e\\\\I=e(n_e+n_p)\\\\I=1.6\times 10^{-19}\times (247569.44+34578.31)\\\\I=4.51\times 10^{-14}\ A[/tex]
Hence, this is the required solution.
A 30-microfarad capacitor is charged to 90 v and then connected across an initially un charged capacitor of unknown capacitanc c .if the final potintial difference across the 30- microfarad capacitor is 20 v sitemin c
Answer:
The value is [tex] C_u = 5 *10^{-6} F[/tex]
Explanation:
From the question we are told that
The voltage of the capacitor is [tex]V = 90 \ V[/tex]
The capacitance of the capacitor is [tex]C = 30 \ \mu F = 30 *10^{-6} \ F[/tex]
The final voltage is [tex]V_a = 20 \ V[/tex]
Since the capacitors are connected in parallel we have that
[tex]Q_u = Q'_u + Q[/tex]
Where [tex]Q_u[/tex] is the charge of the known capacitor before it is connected to the known capacitor
[tex]Q_u' [/tex] is the charge of the known capacitor after it is connected
[tex]Q [/tex] is the charge of the unknown capacitor
Also the potential across the two capacitors will be the same (except for a loss due heat (it been converted to heat ))
So
[tex]CV = CV_a + C_u * V_a[/tex]
=> [tex] C_u * V_a = CV - CV_a [/tex]
=> [tex] C_u = \frac{CV - CV_a }{ V_a } [/tex]
=> [tex] C_u = \frac{ [30*10^{-6} *90] - [30*10^{-6} * 20] }{ 20 } [/tex]
=> [tex] C_u = 5 *10^{-6} F[/tex]
EXPLAINING ISSUES How did Rome’s status as a site of encounter change the lives of Roman citizen
Answer:
Below, the definition including its position of Roman people is clarified.
Explanation:
Conflicts began to rise in most of the other societies surrounding Rome, as Rome gained property mostly in the peninsula. They were requesting an improvement or change in one's position from these recently subjugated people. Though without the election, they might intermarry among Romans, negotiate agreements and also have freedom of movement brooking sine suffrage as well as citizenship, individuals also requested more.A car starts 20 miles north of town then travel for 40 minutes until it is 100 miles north of town. What is the cars velocity over this time frame?
Can non-coding genes modify proteins?
Answer:
Only about 1 percent of DNA is made up of protein-coding genes; the other 99 percent is noncoding. Noncoding DNA does not provide instructions for making proteins.Aug 17, 2020
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A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which to reduce its speed to 11.3 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive).
Answer:
The value is [tex]a = -3.7 \ m/s^2 [/tex]
Explanation:
From the question we are told that
The landing speed is [tex]u = 71.9 \ m/s[/tex]
The distance traveled is [tex]d = 675 \ m[/tex]
The velocity it is reduced to is [tex]v = 11.3 \ m/s[/tex]
Generally the average acceleration is mathematically represented as
[tex]a = \frac{ v^2 - u^2 }{ 2 * d }[/tex]
=> [tex]a = \frac{ 11.3^2 - 71.9^2 }{ 2 * 675 }[/tex]
=> [tex]a = -3.7 \ m/s^2 [/tex]
Suppose a boat moves at 14.2 m/s relative to the water. If the boat is in a river with the current directed east at 2.70 m/s, what is the boat's speed relative to the ground when it is heading east, with the current, and west, against the current? (Enter your answers in m/s.)
Answer:
3.72 m/s
Explanation:
6. A car is traveling at 50m/s when it begins to slow down to
20m/s. This took the car 5s to slow down. Calculate the
acceleration. *
Answer:
-6 m/s²
Explanation:
Given:
v₀ = 50 m/s
v = 20 m/s
t = 5 s
Find: a
v = at + v₀
20 m/s = a (5 s) + 50 m/s
a = -6 m/s²
Answer:
-5
Explanation:
It takes a car traveling at 18 m/s, 240 seconds to reach Chick-Fil-A from the school. Determine how far Chick-Fil-A is from the school.
Answer:
The requested distance is 4320 meters
Explanation:
We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:
[tex]v=\frac{distance}{time}[/tex]
Since we know the velocity and the time, we can solve for the distance:
[tex]\neq v=\frac{distance}{time} \\18\,\frac{m}{s} = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m[/tex]
Two mechanical waves intersect and produce the straight line seen here. What is the result of this intersection called?
Answer:constructive interfrence
Explanation:
Is there a single linear sequence to the scientific method?
Answer:
no
Explanation:
i did it and got it right.
Driving along in your car, you take your foot off the gas, and your speedometer shows a reduction in speed. Describe an inertial frame in which your car was speeding up during that same period of time. Remember, an inertial frame is one whose speed and direction are not changing.
Answer:
v ’= v + v₀
a system can be another vehicle moving in the opposite direction.
Explanation:
In an inertial reference frame the speed of the vehicle is given by the Galileo transformational
v ’= v - v₀
where v 'is the speed with respect to the mobile system, which moves with constant speed, v is the speed with respect to the fixed system and vo is the speed of the mobile system.
The vehicle's speedometer measures the harvest of a fixed system on earth, in this system v decreases, for a system where v 'increases it has to be a system in which the mobile system moves in the negative direction of the x axis, whereby the transformation ratio is
v ’= v + v₀
Such a system can be another vehicle moving in the opposite direction.
A boy on a roof throws one ball downward and an identical ball upward. The ball thrown downward hits the ground with 100 J of kinetic energy. If both balls are thrown at the same speed and there is no air friction, what is the kinetic energy of the second just before it hits the ground
Answer:
It will be Less than 100J
Explanation:
Because the second ball has both kinetic and potential energy so just before it hits the ground the kinetic energy will be total energy-potential energywhich will be less than 100J
ery large accelerations can injure the body, especially if they last for a considerable length of time. One model used to gauge the likelihood of injury is the severity index ( S????SI ), defined as S????=a5/2tSI=a5/2t . In the expression, tt is the duration of the accleration, but aa is not equal to the acceleration. Rather, aa is a dimensionless constant that equals the number of multiples of gg that the acceleration is equal to. In one set of studies of rear-end collisions, a person's velocity increases by 16.4 km/h16.4 km/h with an acceleration of 34.0 m/s234.0 m/s2 . Let the +x+x direction point in the direction the car is traveling. What is the severity index for the collision?
Answer:
2.98 second
Explanation:
The severity index is defined by :
[tex]S=a^{5/2}t[/tex]
a is dimensionless constant that equals the number of multiples of g
Conditions are given as :
Initial velocity, u = 0
Acceleration, a = 34 m/s²
Final velocity, v = 16.4 km/h = 4.56 m/s
We can find t from the above data as follows :
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{4.56-0}{34}\\\\t=0.134\ s[/tex]
As a is the acceleration that is multiple of g.
So,
[tex]a=\dfrac{34}{9.8}=3.46[/tex]
So,
Severity index,
[tex]S=a^{5/2}t\\\\S=(3.46)^{5/2}\times 0.134\\\\S=2.98\ s[/tex]
Hence, the severity index for the collision is 2.98 seconds.
A massive block is being pulled along a horizontal frictionless surface by a constant horizontal force. The block must be __________. View Available Hint(s) A massive block is being pulled along a horizontal frictionless surface by a constant horizontal force. The block must be __________. continuously changing direction moving at constant velocity moving with a constant nonzero acceleration moving with continuously increasing acceleration
Answer:
The body must be moving with a constant non zero acceleration.
Explanation:
Force produces acceleration on any mass it is applied on. The acceleration produced depends on the magnitude and direction of the force. For this block being dragged by a constant horizontal force, The body will undergo a constant non-zero acceleration that will steadily increase its velocity along the direction of the force.
what does 760mmHg represents??
Explanation:
760 mmHg (millimeters of mercury) is a measure of atmospheric pressure. It represents the height of a column of mercury at which the static pressure at the bottom is equal to the atmospheric pressure.
1 atm = 760 mmHg = 101,325 Pa = 14.7 psi
g Two tiny identical spheres of mass m = 66.7 g carry identical positive charge q. The charges hang from identical massless threads of length L = 84.8 cm attached to a ceiling at the same point. The spheres repel, and the angle between the threads is θ = 33o. Find q, the charge on each sphere, in μC.
Answer:
Explanation:
a
The angle each thread is making with the vertex = 16.5 degree
weight acting downwards = 66.7 x 10⁻³ x 9.8 N .
distance between two charges = 2 x 84.8 x 10⁻² sin 33/2
= .48 m
repulsive force between the two charges
= 9 x 10⁹ x q² / .48²
F = 39 x 10⁹ q²
Now, the tension in the thread be T
T cos 16.5 = mg
T sin 16.5 = F
dividing
tan 16.5 = F / mg = 39 x 10⁹ x q² / 66.7 x 10⁻³ x 9.8
.296 x 66.7 x 10⁻³ x 9.8 = 39 x 10⁹ x q²
q² = 4.96 x 10⁻¹²
q = 2.23 x 10⁻⁶ C
= 2.23 μC
difference between boiling point and freezing point
A nonconducting sphere of mass 18.5 kg and diameter 25.0 cm has 8.10 × 1015 electrons removed from it. The points of removal are spread uniformly throughout the volume of this sphere. A tiny neutral plastic ball of mass 0.120 g is placed just outside the surface of the large sphere and is then released. How many electrons must be removed from the plastic ball so that its initial acceleration just after being released will be 1525 m/s2? You can neglect gravity.
Answer:
The value is [tex]n = 1.527 *10^{14} \ electrons [/tex]
Explanation:
From the question we are told that
The mass of the sphere is m = 18.5 kg
The diameter is [tex]d= 25.0 \ cm = 0.25 \ m[/tex]
The number of electrons is [tex]N = 8.10 *10^{15} \ electrons[/tex]
The mass of the plastic ball is [tex]m_b = 0.120 g[/tex]
The initial acceleration of the ball is [tex]u = 1525\ m/s^2[/tex]
Generally the radius of the sphere is mathematically evaluated as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.25}{2}[/tex]
=> [tex]r = 0.125 \ m [/tex]
Generally the force between the ball and the sphere is
[tex]F = \frac{k * q_1 * q_2 }{r^2}[/tex]
Generally this force can also be mathematically represented as
[tex]F = m_b * a[/tex]
So
[tex] m_b * a = \frac{k * q_1 * q_2 }{r^2}[/tex]
Here [tex]q_1[/tex] is the charge removed from the sphere whicn is evaluated as
[tex]q_1 = N * e[/tex]
substituting [tex]1.60*10^{-19} \ C[/tex] for e
[tex]q_1 = 8.10 *10^{15} * 1.60*10^{-19}[/tex]
[tex]q_1 = 0.0013 \ C [/tex]
and [tex]q_2[/tex] is the charge to be removed from the ball
So
[tex] 0.120 * 1525 = \frac{9*10^9 * 0.0013* q_2 }{0.125^2}[/tex]
[tex]q_2 = 2.44 *10^{-7} \ C [/tex]
Generally the number of electron to be removed from the ball is mathematically represented as
[tex]n = \frac{q_2}{e}[/tex]
=> [tex]n = \frac{ 2.44 *10^{-7}}{1.60*10^{-19}}[/tex]
=> [tex]n = 1.527 *10^{14} \ electrons [/tex]
The symbol equation below is used to calculate distance travelled. Rearrange this symbol equation so you could use it to calculate the speed instead. s = v t
Answer:
Below
Explanation:
s = Distance
v = Velocity ( speed)
t = time
[tex]s = vt[/tex]
Divide both sides of the equation by t
[tex] \frac{s}{t} = \frac{vt}{t} \\ \frac{s}{t} = v[/tex]
A small submarine has a volume of 30 m3 and has a mass of 40,000 kg. It needs external tanks that can be filled with air for buoyancy. Assume the compressed air has a density of 37kg/m3 and the seawater has a density of 1030 kg/m3. If the external air tanks have a mass of 2000 kg, what is the minimum volume of the air tanks to provide enough buoyancy to lift the submarine in sea water?
Answer:
11.2m³
Explanation:
Applying Archimedes principle we have it that
Weight of submarine+ weight of tank+ weight of compound air =uptrust
So
(40000+2000+37V) x9.8= (30+V) 1030 x 9.8
38910= 993V
V= 11.2m³
which of the following temparature is approximately equal to room temperature
A)0k
B)o°c
C)293k
D)100°c
E)100k
Hello there! :)
[tex]\huge\boxed{\text{C. 293K}}[/tex]
Room temperature is approximately 20°C.
We can automatically eliminate choices B and D since they are not equal to 20°C.
Since some choices use the Kelvin scale, we can convert from Celsius to Kelvin using a simple formula:
K = C° + 273
Find room temperature in degrees Kelvin:
K = 20° + 273
K = 293°
Thus, the correct choice would be C. 293K.
Children are told to avoid standing too close to a rapidly moving train because they might get sucked under it. Is this possible? Explain.
Answer:
no its not like the undertow in the ocean
Explanation:
Answer:
Yes
Explanation:
This is possible due to Bernoulli's principle.
What trend does the reactivity of nonmetals show in a periodic table? random changes without any trends on the periodic table changes according to trends on the periodic table increases from left to right across the periodic table decreases from left to right across the periodic table
Answer:
C) increases from left to right across the periodic table
Explanation:
if you're reading this, you better smile cause you aren't the only one stressed out about school :))) have a great day love
The trend of the reactivity of non metals in the periodic table is that it increases from left to right across the periodic table.
The periodic table is composed of metals on the left hand side and nonmetals on the right hand side.
As such, nonmetallic property increases from left to right across a period and so does the reactivity of nonmetals.
This implies that as we move from left to right across a period, nonmetallic elements become more reactive.
Learn more: https://brainly.com/question/23040395
Calculate the potential difference of a wire of 10 ohm , through which 5 A of current is flowing .
2 V
50 V
0.2 V
0.5 V
the machine which turns in a power station
Answer:
generators
Explanation:
the machine which turns in a power station
the machine which turns in a power station are called generators.
Any two objects that have mass will also have which type of force between them?
(5 points) +Brainiest
a
Magnetic
b
Gravitational
c
Nuclear
d
Chemical
Answer:
I think the answer for this question is number b. gravitational
