When a person sits in a chair they apply a force to the chair the chair?; When you sit in a chair your body exerts a downward force on the chair What is the reaction force?; What would happen if a person sat on a chair and the chair did not exert an equal force back?; Why is it that if you sit on a chair you do not fall to the ground?

Answer: When the light hits the water, it causes the light to slow down, and when it does this, the light changes directions.

Explanation:

More massive stars emit more energy and run out of hydrogen fuel in their cores faster.

In order to create helium and energy, hydrogen nuclei must fuse. The procedure uses hydrogen as its fuel. As the hydrogen is depleted, the star's core condenses and warms up further. As a result, all the elements up to iron are formed through the fusing of heavier and heavier elements.

Nuclear fusion is how stars generate their energy. This process, known as the "proton-proton chain," which involves a series of events that turns four hydrogen atoms into one helium atom, dominates for the majority of stars.

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Answer:

B: 2 kg.

Explanation:

To find the mass of an object given its momentum and velocity, you can use the following formula:

mass = momentum / velocity

In this case, the momentum of the ball is 18 kg*m/s and its velocity is 9 1 m/s, so the mass of the ball is:

mass = 18 kg*m/s / 9 1 m/s

= 2 kg

Therefore, the correct answer is B: 2 kg.

The volume of the right circular cone is given by the formula πR²H/3.

A right circular cone is a kind of cone in which the centre of the circular base of the cone is perpendicular to the vertical height of the cone.

The volume of any right circular cone is generally given by the formula,

V = πR²H/3

Where,

V is the volume of the right circular cone,

R is the radius of the circular base of the right circular cone.

H is the vertical height of The right circular cone.

π is a constant that has a valued 22/7.

In any general case when we are given the value of the radius of the circular base of the right circular cone and the height of the right circular cone, then we can just simply put the values in the above mentioned formula and we get the volume of the right circular cone.

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The magnitude and direction of its momentum are 23259.5 kg*m/s. and eastward direction respectively.

Its velocity is 10.66 m/s

To find the magnitude and direction of the momentum of the compact car, we can use the formula for momentum, which is defined as the product of an object's mass and velocity:

momentum = mass * velocity

In this case, the mass of the compact car is 725 kg and its velocity is 115 km/h. Converting the velocity to meters per second (m/s) by dividing by 3.6 gives us a velocity of 31.94 m/s.

Plugging these values into the formula above gives us a momentum of 23259.5 kg*m/s.

The direction of the momentum is the same as the direction of the velocity, which in this case is toward the east. Therefore, we can represent the momentum of the compact car as an arrow pointing eastward.

To find the velocity of the second car, we can use the formula for momentum and solve for velocity:

velocity = momentum / mass

In this case, the mass of the second car is 2175 kg and its momentum is the same as that of the compact car, which we calculated to be 23259.5 kg*m/s. Plugging these values into the formula above gives us a velocity of 10.66 m/s.

Note that the velocity of the second car is much lower than that of the compact car, despite having the same momentum. This is because the second car has a much larger mass, so it takes a larger force to change its momentum by a given amount.

Therefore, the correct answer is as given above

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The light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.

The speed of light in a medium is given by the formula,

n = c/v

Where,

c is the speed with which the light travels in the medium,

v is the frequency of the light and n us the refractive index of the medium.

Now, here in this case, the refractive index of the block of glass is 1.59 and the frequency of the light is 5.9 x 10¹⁴ Hz.

Now, putting values,

1.59 = c/5.9 x 10¹⁴

c = 9.38 x 10¹⁴ m/s.

So, the light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.

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The velocity with which the jumper leaves the floor is 5.1 m/s.

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

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The Mountain range will have a mountain deep that extends deep into the mantle.

A mantle is a layered interior of a planetary frame bounded underneath through a core and above by using a crust. Mantles are made of rock or ice and are commonly the largest and most massive layer of the planetary body.

It's far more frequently solid rock, but less viscous at tectonic plate obstacles and mantle plumes. Mantle rocks there are smooth and able to pass plastically at great depth and stress. The transfer of heat and material in the mantle helps decide the panorama of Earth.

The basic styles of mantle substances consist of stone, vintage, timber, and forged stone.

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The angle between the two vectors is 59 degrees.

The angle between the two vectors is calculated by applying the following equation as shown below.

Mathematically, the formula for angle between two vectors is given as;

tan θ = Vy / Vx

where;

The resultant vertical vector is calculated as follows;

∑ Vy = ( 1 + 4 ) = 5 y

The resultant horizontal vector is calculated as follows;

∑ Vx = ( -4 + 1 ) = -3x

The angle between the two vectors is calculated as follows;

tan θ = Vy / Vx

tan θ = 5 / 3

tan θ = 1.667

θ = arc tan ( 1.667 )

θ = 59 degrees

Thus, the angle between the two vectors is a function of the resultant vertical and horizontal vector.

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The mass flow rate can be given as [tex]V=S[\frac{u_y}{2}-\frac{H^3}{12m}\frac{\delta p}{\delta x}][/tex] and when H=0 then net flow rate will be zero.

Given,

upper plate velocity = [tex]u_{s1}[/tex]

opposite plate velocity = [tex]u_{s2}[/tex]

The total velocity between the plates will be

[tex]u_y=u_{s1}+u_{s2}[/tex]

Flow rate is the velocity integrated over an area,

[tex]Q=\int \overline u \hat n \ dA[/tex]

The equation above is only valid for a flat, plane area. In general, including curved areas, the equation becomes a surface integral.

The areas would be cross-sectional.The area of a liquid passing through a pipe is the cross-section of the pipe at the section under consideration. The magnitude of the area through which the mass passes, A, and a unit vector normal to the area combine to form the vector area.

The mass flow rate ,

[tex]V=SQ=S\int\limits^H_0 \int\limits^L_0 u(y)dzdy\\\\=SL\int\limits^H_0u(y)dy\\\\\frac{V}{L}=S\int\limits^H_0[\frac{1}{2m}\frac{\delta p}{\delta x}(y^2-Hy)+\frac{u_y}{H}]dy\\\\=\frac{S}{2M}\frac{\delta p}{\delta x}(\frac{H^3}{3}-\frac{H^3}{2})+\frac{u_y}{2}[/tex]

The mass flow rate for unit width is

[tex]V=S[\frac{u_y}{2}-\frac{H^3}{12m}\frac{\delta p}{\delta x}][/tex]

if H=0 then net flow rate will be zero.

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1. Galileo.

2. Newton.

3. Kepler.

4. Brahe.

5. Refracting telescope.

6. Reflecting telescope.

7. Astrolabe

8. Camera.

9. Radio telescope.

1. Galileo, who uncovered information about the lunar surface.

2. The first reflecting telescope was created by Newton.

3. Kepler discovered elliptical orbits for planets.

4. Brahe: He meticulously mapped the sky.

5. A large glass lens is used in a refractive telescope.

6. A reflecting telescope concentrates light using a mirror.

7. Astrolabe: a device used to pinpoint a star's location.

8. Camera: a device that gathers light from an item to display greater detail.

9. The sound of stars is captured by radio telescopes.

Complete question:

The complete questions is (see in attachments).

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Momentum of any system is constant in all over elastic collisions, but momentum for the system doesn't lost during inelastic collisions. so it's False.

An elastic collision is a collision wherein there's no internet loss in kinetic power withinside the gadget because of the collision. Both momentum and kinetic power are conserved portions in elastic collisions. Suppose comparable trolleys are journeying closer to every different with identical speed. They collide, bouncing off every different without a loss in speed. This collision is flawlessly elastic due to the fact no power has been misplaced.

In reality, examples of flawlessly elastic collisions aren't a part of our ordinary experience. Some collisions among atoms in gases are examples of flawlessly elastic collisions. However, there are a few examples of collisions in mechanics wherein the power misplaced may be negligible. These collisions may be considered elastic, despite the fact that they may be now no longer flawlessly elastic. Collisions of inflexible billiard balls or the balls in a Newton's cradle are such examples.

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(a) If the cornea were simply thin lens then power will be 43 diopters.

(b) This is a concave lens

The cornea is the transparent front part of the eye that covers the iris, pupil, and anterior chamber. Despite injury or disease, the cornea can still repair itself quickly. However, there are situations where damage is too severe for the cornea to heal on its own – such as with a deep injury to the cornea. The following symptoms may indicate that the cornea has sustained a substantial infection, injury or disease: Blurred vision Pain Redness.

Along with the anterior chamber and lens, the cornea refracts light, accounting for approximately two-thirds of the eye's total optical power. In humans, the refractive power of the cornea is approximately 43 diopters.

There are two types of lenses: converging and diverging and here if the cornea was simply thin then the diverging or concave lens is used in the eyes which is thin in the center than their edges.

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Answer:

(a) 3.14

(b) 3.1416

(c) 3.141593

Explanation:

The first several digits of n are known to be x = 3.14159265358979.

(a) To three significant figures, x is 3.14.

(b) To five significant figures, x is 3.1416.

(c) To seven significant figures, x is 3.141593.

The graph that best represents the relationship between the gravitational potential energy of a freely falling object and the object's height above the ground is the last graph.

What is Gravitational potential energy ?

Gravitational potential energy is the energy possessed by a body by virtue of its position. The formula is expressed as:

E = mgh

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object

Note that the formula shows that the gravitational potential energy is directly proportional to the height of the object

This direct proportionality shows that the required graph will have a positive slope.

This shows that the graph that best represents the relationship between the gravitational potential energy of a freely falling object and the object's height above the ground is the last graph.

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The false option about a real image is that  It appears behind the mirror. Last option.

Rays merely appear to diverge in a virtual image, whereas they actually converge in a real image. Only when the item is placed farther away from the mirror/lens than the focal point and this real picture is reversed can concave mirrors and converging lenses produce genuine images.

Using a converging lens or a concave mirror, actual images can be captured. The positioning of the object affects the size of the actual image.

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The tension in the string is 15 N.

String is a data type used in programming that refers to a sequence of characters. It is typically used to store text-based data, such as words or sentences, and is often used to represent strings of text that the user has input. String data types are used in many programming languages, including Java, C++, Python, and JavaScript. String data types are also used to store information such as file paths, website URLs, and database names. In some programming languages, a string is also referred to as a character array.

F = 1 kg * 1 m/s2 = 1 N
The tension in the string is the sum of the forces acting on each object.
For Object A, the forces are F (1 N) and the friction force (5 N).
For Object B, the forces are the friction force (10 N) and the tension in the string.
Therefore, the tension in the string is 10 N + 5 N = 15 N.

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The quantity of radioactivity is stated in Becquerel (Bq), that's the worldwide unit, or the Curie (Ci), that's the unit used withinside the United States. 

Geiger counters are generally used to degree the quantity of radioactivity, however there are different forms of detectors that can be used.

The decay fee is expressed as a percentage. We convert it to a decimal through really lowering the percentage and dividing it through 100. Then calculate the decay aspect b = 1-r. For instance, if the fee of degradation is 25%, the exponential function's decay fee is 0.25 and the decay aspect b = 1- 0.25 = 0.75.

Atoms of a determine radioactive isotope randomly decay right into a daughter isotope. Over time the range of determine atoms decreases and the range of daughter atoms increases. Rutherford and Soddy (1902) observed that the fee of degradation of a radioactive isotope relies upon on the quantity of the determine isotope remaining.

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The wave is traveling in the negative x direction.The wave speed is 12.0m/s.The frequency is 5HzThe wavelength is 2.4m.The displacement is 0.029m.

The general wave equation is given by;

y(x, t) = y cos (2(x/λ) - 2ft)    --------------------------------(i)

y(x, t) is the displacement of the wave at position x and a given time t

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]   ------------------(ii)

Which can be re-written as;

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m)) + 2π(t/(0.20 s))]  -------------(iii)

Comparing equations (i) and (iii) we have that;

=> 2π(x/(2.4 m) = 2π(x/λ)

=> λ = 2.4m

Therefore the wavelength of the wave is 2.4m

Also, still comparing the two equations;

=> 2π(t/(0.20 s) = 2πft

=> f = 1 / 0.20

=> f = 5Hz

Therefore the frequency of the wave is 5Hz

To get the wave speed (v), it is given by;

v = f x λ

Where f = 5Hz and λ = 2.4m

=> v = 5 x 2.4

=> v = 12.0m/s

Therefore, the speed of the wave is 12.0m/s

At t = 0.50s and x = 0.20m;

The displacement, y(x,t) of the string wave is given by

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]

Convert the amplitude of 3.0cm to m

=> 3.0cm = 0.03m

Carefully solve the equation

=> y(x, t) = (0.03m) × cos[2π((0.20)/(2.4 m)) + 2π(0.50/(0.20 s))]

=> y(x, t) = (0.03m) × -0.9684

=> y(x, t) = 0.029m

Therefore the displacement at those points is -0.029m

Also, the sign of the displacement shows that the direction of the wave is in the negative x direction.

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The wave bounces off an item when there is a reflection kind of wave interaction.

When waves strike a surface and rebound, reflection occurs. When a wave encounters a surface, it might reflect in all directions. For instance, visible light bounces off the surfaces it encounters. Your eyes receive the reflected light, which makes it possible for you to see the objects.

When two or more waves collide, interaction occurs. Wave interference is the term used to describe how waves interact with one another. Wave interference may occur when two waves that are traveling in opposite directions meet. The two waves pass through each other, and this affects their amplitude.

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The answer is e-10³⁰.

Solution:

The expression for find transmission co-efficient is

[tex]T = e^{-2CL}[/tex]

Substitute values in the above equation

T = e -2(2.5-10³²)(2×10⁻³)

= e -10×10²⁹

≈ e-10³⁰

Magnitude estimation is a psychophysical method by which participants judge the perceived strength of a stimulus and assign a numerical estimate. Magnitude is an exponential change of plus or minus one in the value of a quantity or unit. The term is commonly used in relation to the 10th power scientific notation.

Magnitude is used to make the size of numbers and the scale of things more intuitive and understandable. A rough estimate of size helps the project manager estimate a rough figure for the total cost of the project. The approximate financial impact of future projects. Change the precision as needed.

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a)  The acceleration of the proton is  6.4×10¹⁰  m/s².

b)  Time taken is 1.875×10⁻⁵ second .

c)  It moved in this time is 11.25 meter.

d)  its kinetic energy is  1.15×10⁻¹⁵ Joule.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

uniform electric field: E = 640 N/C.

its speed is: v= 1.20 x 10⁶ m/s

a)  the acceleration of the proton = qE/m

= (1.6×10⁻¹⁹×641)/(1.6×10⁻²⁷) m/s²

= 6.4×10¹⁰  m/s²

b) Time taken = (1.20 x 10⁶ / 6.4×10¹⁰)second = 1.875×10⁻⁵ second .

c)   it moved in this time = ( 1.20 x 10⁶×1.875×10⁻⁵ )/2 meter = 11.25 meter.

d)  its kinetic energy = mv²/2 =  (1.6×10⁻²⁷)(1.20 x 10⁶)²/2 joule = 1.15×10⁻¹⁵ Joule.

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Energy is transferred through matter by both conduction and convection. Only radiation can convey energy without the need for substance. The transfer of energy through waves is known as radiation

The definition of radiation is radiation that emanates from a source and moves at the speed of light through space. This energy has wave-like characteristics and is surrounded by an electric and magnetic field. Electromagnetic waves are another name for radiation.

The definition of radiation was energy that emanates from a source and moves through a substance or through space. Radiation includes heat and light. Ionizing radiation, the type of radiation covered on this website, is so-named because it has sufficient energy to knock an electron out of an atom, converting it into an ion.

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An express magnitude is a positive number and angle between. ±180∘.  v1 = ∠ ∘ V.

Nodal stress analysis complements the previous mesh analysis in that it is equally powerful and based on the same concepts as matrix analysis. As the name suggests, node voltage analysis uses Kirchhoff's first law node equation to find the voltage potential around a circuit.

When we use the term node voltage, we are referring to the potential difference between two nodes in a circuit. Select one of the nodes in your circuit as the reference node. All other node voltages are measured with respect to this one reference node.

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The velocity of the cart (with cannon) after the ball is fired is u₂ = Mv - mVb / ( M - m(ball) ).

option A is the correct answer.

The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.

Mathematically, the law of conservation of linear momentum is given as;

Pi = Pf

where;

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

Mass of the cannon ball  +  cart = M

mass of the cart only, m₂ = M - m(ball)

The final velocity of the cart  is calculated as follows;

mVb + m₂u₂ =  Mv

m₂u₂ = Mv - mVb

u₂ = Mv - mVb / m₂

u₂ =  ( Mv - mVb ) / ( M - m(ball) )

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The metal rod's moment of inertia, Ml²/12, has a midway that is equal to 3k/M.

A line that cuts through the intersection of two adjacent line segments at a right angle is known as a perpendicular bisector. In other words, a perpendicular bisector always splits a line segment through its middle. The word "bisect" itself refers to an even or uniform division.

A line that is perpendicular to a triangle's side and travels through the middle of that side is said to be the perpendicular bisector of that side. The circumcenter of a triangle is where the triangle's three perpendicular bisectors meet (the center of the circle through the three vertices). A line segment is a perpendicular bisector when it encounters another line segment at a straight angle and divides it into two equal halves at its halfway.

When the rod is twisted at an angle, the spring is squeezed by a tiny distance.

springs, which add force

= k x

torque moment about an axis

= k x l /2

= k θ( l /2 )² ( x / .5 l = θ )

Angular acceleration times the rod's moment of inertia equals the moment of torque.

M l2 / 12 d2 / dt2 = k (l /2)2

d²θ/dt² = 3 k/M θ

acceleration equals two.

ω² = 3 k/M

ω = √ 3 k / M

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The angular acceleration is 0.19 and the number of turns is 41.07 revolutions.

m = 87 kg be the mass of the grindstone,

r = 0.35 m be the radius of the grindstone,

I = mr²/2 be the grindstone's moment of inertia,

ω = 95 revolution/min = 95 2π/60s = 9.9 s-1 be initial angular velocity,

F = 15 N be the force pressing radially,

f = 0.2 be the coefficient of friction,

α (unknown) be the grindstones angular acceleration.

a)The tangential force slowing the grindstone is

fF

Its torque is

rfF

By Newton's Second Law

rfF = Iα

Therefore

α = rfF/I = 2rfF/mr² = 2fF/mr

Substituting actual numbers

α = 2×0.2×15/(87×0.35) = 0.19 s-2

Note that the above is the absolute value of the acceleration.

Depending on which direction is considered positive or negative,

the answer may need to be negated.

b)

Let

t be the time it takes the grindstone to come to rest,

θ be the total angle by which the grindstone will turn before coming to rest.We have the following identities, which follow from the definition of acceleration:

ω = αt

θ = αt²/2

From the first

t = ω/α

Plug into the second

θ = α(ω/α)²/2 = ω²/2α

Substitute actual numbers

θ = 9.9²/2×0.19 = 257.92

The above result is in radians.

Since the result is supposed to be given in revolutions,

we need to divide by the number of radians per revolutions:

257.92/2π = 41.07 revolutions

Therefore, the angular acceleration is 0.19 and the number of turns is 41.07 revolutions.

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The metals on the basis of the maximum kinetic energy of the emitted electrons is Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum.

From Einstein photo electic effect equation

E = 3.1 eV

E = Wo+ Kmax

Kmax = E - Wo

For Be:  E< Wo, Kmax =  0

There is no emission of photo electron

For K : Kmax = 3.1 -2.3 = 0.8 eV

For Al : E< Wo, Kmax =  0

There is no emission of photo electron

For  Mg: E< Wo, Kmax =  0

There is no emission of photo electron

For Cs: Kmax = 3.1 -2.1 = 1.0 eV

For Pt : E< Wo, Kmax =  0

There is no emission of photo electron

Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum

Einstein photo electic effect:

Einstein said that energy is a beam of particles related to frequency according to Planck's formula. When this beam is directed at a metal, photons collide with atoms. If the photon frequency is high enough to knock off an electron, the collision will produce the photoelectric effect.

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The value of F CA = 4500 NC. The fundamental difference between compression and tension is that compression represents forces meant to shorten a body, whereas tension describes forces designed to prolong a body.

A rope bridge may support both the load it carries and itself by using tension forces that pull and stretch material in opposing directions. A rock arch bridge carries a load by pressing its rocks against one another due to compression forces that squeeze and push material inward.

One that pulls materials apart is a tension force. When material is compressed, it gets squeezed together. Some materials are more resilient to compression, some to tension, and some are suitable for usage when both compression and tension are present.

Efforts to distort an object are called tension and compression forces. The basic distinction between tension and compression is that tension describes forces intended to lengthen a body, whereas compression describes forces intended to shorten the body.

Support Reactions: Entire truss:

[tex]+\Sigma F_x=0: \quad B_x=0 \\[/tex]

[tex]+{ }_{+} \Sigma M_C=0: \quad-B_y(400 \mathrm{~mm})-(1200 \mathrm{~N})(500 \mathrm{~mm})=0 \\[/tex]

[tex]B_y=-1500 \mathrm{~N} \quad \mathbf{B}_y=1500 \mathrm{~N} \\[/tex]

[tex]+\left\lceil\Sigma F_y=0: \quad-1500 \mathrm{~N}-1200 \mathrm{~N}+C=0\right. \\[/tex]

C = 2700 N

Free body: Joint B:

[tex]$\frac{F_{B A}}{13}=\frac{F_{B C}}{12}=\frac{1500 \mathrm{~N}}{5} .[/tex]

[tex]$\begin{array}{r}F_{B A}=3900 \mathrm{~N} \\ \\ F_{B C}=3600 \mathrm{~N} C\end{array}$[/tex]

simplifying the above equation, we get

[tex]$\frac{F_{C A}}{5}=\frac{2700 \mathrm{~N}}{3}$[/tex]

Therefore, the value of [tex]$F_{C A}=4500 \mathrm{~N} C$[/tex]

The complete question is:

Using the method of joints, determine the force in each member of the truss shown. State whether each member is in tension or compression.

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