When should a line graph be used?
A. When the independent variable is continuous and shows a causal link to the dependent variable.
B. When the independent variable is composed of categories and does not show a relationship.
C. When there is no independent variable.
D. When the independent variable is continuous and does not show a relationship to the dependent variable.
Answer:
A. When the independent variable is continuous and shows a causal link to the dependent variable.
Explanation:
A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.
In an experiment , the variable being manipulated by an experimenter is known as an independent variable while the dependent variable is the event expected to change when the independent variable is manipulated
Generally, a line graph should be used when the independent variable is continuous and shows a causal link to the dependent variable.
This ultimately implies that, a line graph should be used when the data changes continuously over time and as such there exist a linear relationship between the data (variables).
a ball was changed vertically upwards with kinetic energy 200 joule what will be the total energy and Midway
Answer:
Part 1; The total energy = Constant = 200 J
Part 2; Midway, the potential energy = The kinetic energy = 100 J
Explanation:
Part 1
According to the first law of thermodynamics, energy is neither created nor destroyed but changed from one form to another
The total (mechanical) energy = Potential energy + Kinetic energy = Constant
The kinetic energy given to the ball changed vertically up = 200 J
Potential energy = Mass, m × Gravity, g × Height, h
Given that the mass m of the ball and the acceleration due to gravity, g, remain the same, we have;
Potential energy ∝ The height of the ball
The potential energy at ground level = 0 J (Height , h = 0)
∴ The total (mechanical) energy = 0 J + 200 J = 200 J
At the maximum height, the ball momentarily stops, and the kinetic energy = 0 J
Therefore;
The potential energy of the ball at the maximum height, [tex]h_{max}[/tex], [tex]P.E._{max}[/tex] = 200 J
∴ [tex]P.E._{max}[/tex] = m·g·[tex]h_{max}[/tex] = 200 J
Part 2
At midway we have, the height, h = ([tex]h_{max}[/tex])/2
Therefore, [tex]P.E._{Midway}[/tex] = (m·g·([tex]h_{max}[/tex]))/2 = ([tex]P.E._{max}[/tex])/2 = (200 J)/2 = 100 J
The potential energy midway = 100 J
The remaining 200 J - 100 J = 100 J is the kinetic energy remaining in the ball
The kinetic energy midway = 100 J
Therefore, the total energy midway = 100 J + 100 J = 200 J
15millas a km alguien pliss para ahorita porfa lo sigo
Answer:
X = 24.135 kilometres
Explanation:
Given the following data;
Distance = 15 miles
To convert the value in miles to kilometers;
Conversion:
1 mile = 1.609 kilometres
15 miles = X kilometres
Cross-multiplying, we have;
X = 1.609 * 15
X = 24.135 kilometres
Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(1 point)
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.
According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.
Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.
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What would be the difference in your welght if you were four times farther from the center of Earth than you are now?
you would die.
the core of the earth is as hot as the sun surface so you would be dead
There are four charges, each with a magnitude of 4.25 C. Two are positive and two are negative. The charges are fixed to the corners of a 0.440-m square, one to a corner, in such a way that the net force on any charge is directed toward the center of the square. Find the magnitude of the net electrostatic force experienced by any charge.
Answer:
F = 7.68 10¹¹ N, θ = 45º
Explanation:
In this exercise we ask for the net electric force. Let's start by writing the configuration of the charges, the charges of the same sign must be on the diagonal of the cube so that the net force is directed towards the interior of the cube, see in the attached numbering and sign of the charges
The net force is
F_ {net} = F₂₁ + F₂₃ + F₂₄
bold letters indicate vectors. The easiest method to solve this exercise is by using the components of each force.
let's use trigonometry
cos 45 = F₂₄ₓ / F₂₄
sin 45 = F_{24y) / F₂₄
F₂₄ₓ = F₂₄ cos 45
F_{24y} = F₂₄ sin 45
let's do the sum on each axis
X axis
Fₓ = -F₂₁ + F₂₄ₓ
Fₓ = -F₂₁₁ + F₂₄ cos 45
Y axis
F_y = - F₂₃ + F_{24y}
F_y = -F₂₃ + F₂₄ sin 45
They indicate that the magnitude of all charges is the same, therefore
F₂₁ = F₂₃
Let's use Coulomb's law
F₂₁ = k q₁ q₂ / r₁₂²
the distance between the two charges is
r = a
F₂₁ = k q² / a²
we calculate F₂₄
F₂₄ = k q₂ q₄ / r₂₄²
the distance is
r² = a² + a²
r² = 2 a²
we substitute
F₂₄ = k q² / 2 a²
we substitute in the components of the forces
Fx = [tex]- k \frac{q^2}{a^2} + k \frac{q^2}{2 a^2} \ cos 45[/tex]
Fx = [tex]k \frac{q^2}{a^2}[/tex] ( -1 + ½ cos 45)
F_y = k \frac{q^2}{a^2} ( -1 + ½ sin 45)
We calculate
F₀ = 9 10⁹ 4.25² / 0.440²
F₀ = 8.40 10¹¹ N
Fₓ = 8.40 10¹¹ (½ 0.707 - 1)
Fₓ = -5.43 10¹¹ N
remember cos 45 = sin 45
F_y = - 5.43 10¹¹ N
We can give the resultant force in two ways
a) F = Fₓ î + F_y ^j
F = -5.43 10¹¹ (i + j) N
b) In the form of module and angle.
For the module we use the Pythagorean theorem
F = [tex]\sqrt{F_x^2 + F_y^2}[/tex]
F = 5.43 10¹¹ √2
F = 7.68 10¹¹ N
in angle is
θ = 45º
"Measurement is essential in our life. Justify the statement.
Explanation:
Measurement plays an important role in our daily lives because they are useful to do basic tasks, such as taking the temperature of a child with the help of a thermometer,making time estimations,measure out medicines and find out weights, areas and volumes of different substances
Discuss the role of globalization in the development of sI unit
Answer:
It was created during the French Revolution in 1799 and has enabled for the international exchange of scientific and technical information. Calculating with SI units is also a lot easier than using the English system.
Explanation:
It was first developed during the French Revolution in 1799 and has allowed for the sharing of scientific and technical information on an international level. Performing computations using SI units is also much easier to use than the English system. Thanks
A 2-kg object is pulled to the left with a force of 30 N and to the right with a force of 9 N. What is the acceleration of the object?
An object that weighs 75 N is pulled horizontally to the right with a force of 50 N. The force of friction on this object is 30 N to the left. What is the acceleration of the object?
The force on the object is 50 N to the right and 30 N to the left.
⇒ The net force on the object is, =50−30=20 N to the right.
The weight of the object is, =75 N.
⇒ The mass of the object is ==759.8 kg.
⇒ The acceleration of the object is ==20759.8=2.613 m/s 2.
The acceleration of the object is 10 [tex]m/s^2[/tex].
What is Acceleration?Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
It can be expressed as:
a= v/t
where, a is the acceleration
v is the velocity
t is the time taken
It can also be expressed as F=ma
where, F= force applied
m= mass of the object
So, for above given information
The force on the object is 9N to the right and 30N to the left. The net force on the object is 21N to the left
The mass of the object is 2kg
So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]
Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].
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A sound frequency 100Hz and wavelength 3.34m is travelling through air, calculate the Velocity of sound in air.
Answer:
334m/s
Explanation:
If you take the data you gave and insert it into the equation f=v/λ the frequency would come out to be 3.34m
334 m/s is the Velocity of sound in air.
What is the velocity of a wave?Wave velocity in common usage refers to speed, although, properly, velocity implies both speed and direction.
The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.
Mathematically , v=fλ
According to the question,
Sound frequency (f) = 100Hz
Wavelength (λ)= 3.34m
Computing the values in the formula,
v=fλ
v = 100Hz x 3.34m
v= 334m/s
Therefore,
Velocity of sound in air is 334 m/s.
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Two solid cubes have the same Mass but their edges are in the ratio of 4:1. What isthe ratio of their densities?
Let m be the mass of both cubes. If the smaller cube has side length x, then its volume is x ³. The side lengths of the larger cube have length 4x, so the larger cube's volume is (4x)³ = 64x ³, or 64 times as large as the smaller cube.
The first cube has a density of m/x ³, while the larger one has a density of m/(64x ³) = 1/64 m/x ³, so the ratio of densities is (1/64):1, or 1:64 (larger cube to smaller cube).
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Compare the amount of kinetic energy of particles in each state of matter- solid, liquid, gas
Answer:
gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)
How can a simulation study be used to learn about a planet we have never visited?
In a simulation study you imitate some conditions and characteristics of the real planet. The simulation can be used as a substitute for real data collected on the planet.
Simulation studies can be used for planets we have already visited.
In a simulation study you imitate as many conditions and characteristics as possible of the real thing, in this case the planet you have not visited. By simulating as many conditions as possible you can visualize what the planet might be like and learn things about it without actually visiting it.
Simulation studies cannot be used to learn about a planet we have never visited because we do not know anything about the planet.
A simulation study that is used to learn about a planet by simulating as many conditions as possible, you can visualize what the planet might be like and learn things about it without actually visiting it. The correct option is c.
What is simulation?A simulation is a method of simulating a process or change in the actual world to forecast future events or to explain past events and their causes. These days, simulations are frequently carried out using computers. Scientists use simulations to find answers and to test complicated systems.
A fire drill is used in this instance to get everyone ready for an impending event. In fire drills, the fire alarm is sounded even when there isn't actually a fire.
Therefore, the correct option is c.
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Ignore friction. A 20. Lb. Object was lifted to a height of 10 feet by a force of 30. Lb. (a) How much work (ft.Lb) is done by the force? (b) Find the change in potential energy (ft.Lb) of the object
(a) The work done by force in lb-ft is 300 lb-ft.
(b) The change in potential energy of the object is 200 lb-ft.
Work done by forceThe work done by force in lb-ft is calculated as follows;
W = Fd
W = 30 x 10
W = 300 lb-ft
Change in potential energyThe change in potential energy of the object is calculated as follows;
ΔP.E = P.Ef - P.Ei
ΔP.E = 20 x 10 - 0 = 200 lb-ft
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how far away is a train if you see the steam from is nozzle 4.5 seconds
before you hear its sound?(take speed of sound as 331 m/sec)
Answer:
Distance = 1489.5 meters
Explanation:
Given the following data;
Time = 4.5 secondsSpeed of sound = 331 m/sTo find how far away is the train;
Mathematically, the distance of an object is calculated using the formula;
Distance = speed * time
Distance = 331 * 4.5
Distance = 1489.5 meters
A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *
A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car
The force on the truck is the same in magnitude as the force on the car.
The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.
J = Ft
where;
J is the impulse experienced by the objectt is the timeThe increase in the force applied to an object causes an increase in the impulse experienced by the object.
Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.
Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.
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During the collision of a big truck with a small passenger carGroup of answer choicesthe force from the truck on the car is always much bigger than the force from the car on the truck.the force from the truck on the car may be smaller than, greater than, or equal to the force from the car on the truck.the force from the truck on the car is always much smaller than the force from the car on the truck.the force from the truck on the car is always equal to the force from the car on the truc
Answer:
The force from the truck on the car is always equal to the force from the car on the truck.
Explanation:
According to Newton's third law; action and reaction are equal and opposite. Hence, when the big truck and small passenger car are involved in a collision, we expect that the force from the truck on the car is always equal to the force from the car on the truck. The forces on the car and the truck are equal in magnitude but opposite in direction.
This follows directly from Newton's third law of motion hence the answer above.
Make a super villain out of these resources
Answer:the super villain would have the ability to control electricity and could take any Metal object or weapons that anyone points at him because he is magnetic
Explanation:
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Write a summary of how the eye works:
Answer:
Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.
Explanation:
A monatomic gas is measured to have an average speed of 1477 m/s. If the
total amount of the gas is 2 mol (which equates to a mass of 0.008 kg), what
is the approximate temperature of the gas? (Recall that the equation for
kinetic energy due to translation in a gas is KEtranslational = 1 mv2 = 3 nRT,
2
and R = 8.31 J/(mol-K).)
2
Answer:
The temperature of the gas is 350.02 K.
Explanation:
The average speed is related to the temperature as follows:
[tex] \bar v = \sqrt{\frac{3RT}{M}} [/tex] (1)
Where:
[tex] \bar v [/tex]: is the average speed = 1477 m/s
R: is the gas constant = 8.31 J/(K*mol)
T. is the temperature =?
M: is the molar mass
First, let's find the molar mass:
[tex] M = \frac{m}{n} [/tex]
Where:
m: is the mass of the gas = 0.008 kg
n: is the number of moles = 2 mol
[tex] M = \frac{m}{n} = \frac{0.008 kg}{2 mol} = 0.004 kg/mol [/tex]
Hence, by solving equation (1) fot T we have:
[tex] T = \frac{\bar v^{2}*M}{3R} = \frac{(1477 m/s)^{2}*0.004 kg/mol}{3*8.31 J/(K*mol)} = 350.02 K [/tex]
Therefore, the temperature of the gas is 350.02 K.
I hope it helps you!
Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply.
Answer:
ch3sh + 4O2 are the products
A and B are 0.200m apart in an electric field. If 800J of work are reuqired to move a 2.00 Columb charge from A to B, what is the electric field stregth?
Answer:
hello
Explanation:
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22. In an experiment to determine the density of a soil using a density bottle, the following measuren were recorded. Mass of empty density bottle = 42.9g Mass of density bottle full of water = 66.1g Mass of density bottle with some soil = 67.2g Mass of density bottle with soil filled up with water = 82.0g Use the above data to determine the a) Mass of water that completely filled the bottle (2 b) Volume of water that completely filled the bottle
Answer:1
Explanation:1
A car moving at 41.35 m/s hits a brick wall and stops in 0.140 s. What is the
acceleration of the car?
Answer:
Acceleration, a = 295.36 m/s²
Explanation:
Given the following data;
Final velocity = 41.35 m/s
Initial velocity = 0 m/s
Time = 0.140 seconds
To find the acceleration, we would use the first equation of motion;
V = U + at
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
41.35 = 0 + a*0.140
41.35 - 0 = 0.140a
41.35 = 0.140a
Acceleration, a = 41.35/0.140
Acceleration, a = 295.36 m/s²
. Four bars of metal A, B, C and Dare tested for magnetism. B attracts both A and C but not D. D does not attract A, B or C. A and C sometime attract one another and sometimes repel one another. What conclusion can you draw about? (a) Bar A (b) Bar B (c) Bar D
Answer:
a. Bar A is a magnet
b. Bar B is a metal or magnetic material
c. Bar D is a non-magnetic material
Explanation:
a. Bar A
Since B attracts both A and C, it shows that A and C are both magnetic. So, it is either B and A are magnets or B and C are magnets or A and C are magnets. Also, since A and C sometime attract one another and sometimes repel one another, it means that they attract when their poles are opposite and repel when their poles are negative. This show that both A and C are magnets. Thus, A is a magnet.
b. Bar B
Since B is attracted to both A and C and we know that both A and C are magnets, it implies that B is a magnetic material. Since it does not repel either A or C.
c. Bar D
Since D does not attract A, B or C, D is a non-magnetic material. Since, only a magnetic material can be attracted to magnets and we have established that both A and C are magnets and that B is magnetic. Since D is not also attracted to B, it implies that D is thus non-magnetic.
An engineer wants to design an oval racetrack such that 3.20×103 lb racecars can round the exactly 1000 ft radius turns at 99 mi/h without the aid of friction. She estimates that the cars will round the turns at a maximum of 175 mi/h. Find the banking angle θ necessary for the race cars to navigate the turns at 99 mi/h without the aid of friction.
Answer:
the angle of banking is 33.3 degree.
Explanation:
speed, v = 99 mi/h = 44.26 m/s
radius, r = 1000 ft = 304.8 m
g = 9.8 m/s^2
Let the angle of banking is A.
[tex]tan A = \frac{v ^2}{r g}\\\\tan A = \frac{44.26^2}{304.8\times 9.8}\\\\tan A = 0.66\\\\A = 33.3^0[/tex]
Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of output 5 v and 2.5 A. If the LED is 75% efficient, what would be power dissipated? Also find work done by LED when it is connected to power supply and left for 1 hr 15 minutes?
Answer:
Power = I * V = 2.5 C/s * 5 J/C = 12.5 J/s = 12.5 watts
Regardless of the efficiency the power consumed is that used by the converter.
E = P * t = 12.5 J/s * 4500 s = 4500 J
An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above, what is the length of its image?
Given,
length of object, [tex]h_o = 3 cm[/tex]
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is = [tex]-1[/tex]
length of the image,
[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]
Here, negative sign means inverted image.
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If the force on a spring is 2 N and it stretched 0.5 m, what is the spring constant?
O A. 2 N/m
OB. 0.2 N/m
OC. 0.4 N/m
OD. 4 N/m
answer is
0.4n/m