when an object is immersed in liquid at rest,why is the net force on the object is the horizontal direction equal to zero?​

this is where the sun and moon line up where you asleep only a tiny bit of the sun it's pretty cool to see

Explanation:

a solar eclipse means when the moon goes infront of the sun and the earth turns dark

Answer:

25.0 cm3

Explanation:

The volume is 25.0 cm3 .

This question involves the concepts of density, volume, and mass.

(a) The volume occupied by this amount of water is "90 m³".

(b) The length of an edge of each small cube is "83 μm".

(c) The length of the edge of each small cube is "equal" to the diameter of a molecule.

(a)

The volume can be found using the following formula:

[tex]V = \frac{nM}{\rho}[/tex]

where,

V = volume occoupied = ?

n = no. of moles = 5 mol

M = molar mass = 18 g/mol

[tex]\rho[/tex] = density of water = 1 g/m³

Therefore,

[tex]V=\frac{(5\ mol)(18\ g/mol)}{1\ g/m^3}\\\\[/tex]

V = 90 m³

(b)

First, we will find the volume of an individual molecule:

[tex]V_i =\frac{V}{nN_A}[/tex]

where,

[tex]N_A[/tex] = Avogadro's number = 6.02 x 10²³ molecules/mol

Therefore,

[tex]V_i=\frac{90\ m^3}{5\ mol(6.02\ x\ 10^{23}\ molecules/mol)}[/tex]

Vi = 3 x 10⁻²³ m³

This volume can be given as a volume of the sphere:

[tex]V_i=\frac{4}{3}\pi r^3\\\\r=\sqrt[3]{\frac{3(3\ x\ 10^{-23}\ m^3)}{4\pi}}[/tex]

r = 4.15 x 10⁻⁷ m

Diameter = d = 2r = 2(4.15 x 10⁻⁷ m)

d = 8.3 x 10⁻⁷ m = 83 μm

since the cubes are adjacent to each other. Therefore, the diameter will be equal to the edge length.

Edge Length = L = d

L = 8.3 x 10⁻⁷ m = 83 μm

(c)

The edge length is equal to the diameter of the molecule.

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The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.

The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.

At standard conditions;

We know that:

Therefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.  

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Answer:

Our atmosphere has five different layers. They are:

1. Troposphere: This is the most important layer of the atmosphere with an average height of 13 km from the earth. It is in this layer that we find the air that we breathe. Almost all the weather phenomena such as rainfall, fog and hailstorm occur here.

2. Stratosphere: This layer extends up to a height of 50 km. It presents the most ideal condition for flying airplanes. It contains a layer of ozone gas which protects us from the harmful effect of the sun rays.

3. Mesosphere: This layer extends up to a height of 80 km. Meteorites bum up in this layer on entering from the space.

4. Thermosphere: In this layer, the temperature rises very rapidly with increasing height. The ionosphere is a part of this layer. It extends between 80-400 km. This layer helps in radio transmission. Radio waves transmitted from the earth the reflected back to the earth by this layer.

5. Exosphere: It is the uppermost layer where there is very thin air. Light gases such as helium and hydrogen float into space from here.

Answer:

C. crests

don't trust me though

Answer:

The less dense areas created as a sound wave propagates are called rarefactions.

Explanation:

Hoped this helped.

Answer:

bathing and wear clean clothes 2 pollute 3throwing waste in land air water pollution

Answer:

i think the correct answer is B. cancel out

Answer:

a) 1 m/s²

b) -1 m/s²

c) 0 m/s² (constant speed, not accelerating)

Explanation:

A

delta speed = 10 - 0

delta time = 10 - 0

delta speed / delta time = 10/10

delta speed / delta time = 1

B

ds = 5 - 10

dt = 15 - 10

ds / dt = -5 / 5

ds / dt = -1

C

ds = 5 - 5

dt = 25 - 15

ds / dt = 0 / 10

ds / dt = 0

The average acceleration of A, B, and C will be 1 m/s², -1 m/s², and 0 m/s².

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

There are different types of acceleration :

Average acceleration is defined as the average change in velocity with respect to the average change in time.

SI unit is m/s² and it is vector quantity.

According to the question,

For A, Acceleration= (v₁-v₀)/(t₁-t₀)

⇒10-0/10-0

= 1 m/s².

For B, Acceleration= (v₃-v₂)/(t₃-t₂)

⇒5-10/15-10

= -1 m/s²

For C, Acceleration will be constant because change in velocity is constant, this is the case of uniform motion, so its acceleration is also going to be constant (as per the definition of acceleration change in velocity ratio change in time).

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Answer:

a1 = -w^2 A sin w t        where w is the angular frequency

a2 =  - (2 w)^2 A sin 2 w t       where w2 = 2 w1

a2 / a1 = 4 sin 2 w t / sin  w t

Since sin 2 w t / sin w t = 2     sin w t will change twice as fast

a2 / a1 = 8      the max acceleration must change 8 tims as fast

Answer:

No

Explanation:

Acceleration is not a "Force"

The only things added on a force diagrams are forces that are acting on the object. Force causes acceleration to change but it is not a force itself and is not included on a force diagram.

Hi there!

We can begin by using a summation of torques, with the fulcrum being at the rope farthest from the person (the other end).

Thus:

F1 = weight of person

R1 = distance of person to fulcrum (farther end)

F2 = Tension of rope closest to person

R2 = distance of rope to fulcrum

∑τ = 0 = R2F2 - R1F1

R2F2 = R1F1

Plug in values:

2F2 = 1.5(700N)

2F2 = 1050 N

F2 = 525 N = Tension of closest rope

Answer:

Explanation:

v² = u² + 2as

s = (v² - u²)/2a

s = (0² - 75²) / (2(-14))

s = 200.8928

s = 200 m

Answer:

Identification

Explanation:

:-;..........

Answer:

  1.5 m/s

Explanation:

Conservation of momentum means the momentum of the system before the collision is the same as after.

The before, after momentum of each ball is ...

  5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)

  10 kg ball: (10 kg)(0 m/s), (10 kg)(v)

The sum of the "before" products is the same as the sum of the "after" products:

  (5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v

  (10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides

  v = (15 kg·m/s)/(10 kg) = 1.5 m/s

The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

          n₁sinθ₁ = n₂sinθ₂

          1 sin52 = 1.33sinθ₂

                  θ₂ = arcsin(sin52 / 1.33)

                  θ₂ = 36°

as measured from the perpendicular to the surface

Answer:

Con el cielo del agua

Explanation:

espero que te ayude

The increase in the temperature of the soil when bag fall from the given height is 0.065 ⁰C.

The given parameters:

Apply the principle of conservation of energy as follows;

[tex]mgh = mC \Delta T\\\\gh = C \Delta T\\\\\Delta T= \frac{gh}{C}[/tex]

Convert the value of C in kcal/kg ⁰C  to  J/kg ⁰C

1 kcal = 4180 J

[tex]0.200 \ kcal/kg ^0 C= 0.2 \times 4180 (J/kg ^0C) = 836 \ J/kg^0 C[/tex]

The increase in the temperature of the soil is calculated as follows;

[tex]\Delta T= \frac{gh}{C}\\\\\Delta T= \frac{9.8 \times 5.5}{836} \\\\\Delta T= 0.065 \ ^0C[/tex]

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Answer:

False..

Explanation:

An electoMagnets attract iron due to the influence of their magnetic field upon the iron. ...

Answer:

op

Explanation:

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

How to find g (acceleration due to gravity)

We know,

Acceleration due to gravity (g)

[tex] = \frac{GM}{ {R}^{2} } [/tex]

where, G = Gravitational constant

[tex] = 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\ [/tex]

M = Mass of the earth

[tex] = 6 \times {10}^{24} \: kg[/tex]

R = Radius of the earth

[tex] = 6.4 \times {10}^{6} m[/tex]

Putting these values of G, M and R in the above formula, we get

[tex]g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2} [/tex]

So, the value of acceleration due to gravity is

[tex]9.8m/s ^{2} [/tex]

Hope it helps.

Do comment if you have any query.

Answer:

B.-80.35 J

i dont know the calculation

The speed of the chord wave allows finding a new speed when the mass is increased and the chord length is:

A wave is a periodic movement of the particles that carries energy, but not matter, the speed of the waves is related to the properties of the medium by the relationship.

           [tex]v = \sqrt{\frac{T}{\mu } }[/tex]  

Where v is the speed of the wave, T the force and μ is the linear density.

Indicates that the applied mass increases by a factor of 18.0 and the length of the head is increased to twice the original.

The linear density of the cable is

          [tex]\mu = \frac{m}{l}[/tex]

Where m is the mass of the cable and l is the length.

Let's use the subscript "o" for the initial conditions.

          M = 18.0 m₀

          l = 2 l₀

We look for the density.

         [tex]\mu = \frac{18.0 m_o}{2.0 l_o}[/tex]mu = 18.0 mo / 2 lo

         [tex]\mu = 9.0 \mu_o[/tex]  

We substitute in the expression for the velocity assuming that the tension is kept constant.

        [tex]v= \sqrt{\frac{T}{9.0 \mu} }[/tex]  

        [tex]v= \frac{v_o}{3}[/tex]  

In conclusion, using the speed of the chord wave we can find a new speed when the mass is increased and the chord length is:

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Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.

Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.

The force that draws molecules of the same substance together is called the cohesive force. The force that holds molecules of various substances together is known as the adhesive force.

Between molecules of the same substance, there are cohesive forces. There is a natural tendency to resist separation due to these intermolecular forces between like elements. Conversely, adhesive forces draw disparate molecules together.

In physics, cohesion refers to the intermolecular attraction that exists between two adjacent parts of a substance, especially one that is solid or liquid. A piece of matter is held together by this force. Adhesion is a term for the intermolecular forces that act when two dissimilar substances come into contact.

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Answer:

c

Explanation:

Answer:

Explanation:

350 cm / 25 cm = 14 radians

14 rad / 2π rad/rev = 2.23 revolutions

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

Answer:

Explanation:

I'm not 10% sure but i think that if you were to do:

603 + 277 = 880

1000 - 880 = 120

So to keep it from moving, i think you would need to pull with a force of 120N

The force with which it should be pulled to keep the knot from moving is 663.58 N.

Newton's third law states that, for every action, there is an equal and opposite reaction.

Here,

Force exerted by Roberta, F₁ = 277 N

Force exerted by Michael, F₂ = 603 N

Since, Roberta is pulling to the west and Michael is pulling towards the south, the angle between the forces applied by them is 90°.

The force needed to keep the knot from moving is the resultant force of these two forces.

Therefore, the resultant force,

Fₙ = √F₁² + F₂²

Fₙ = √(277)² + (603)²

Fₙ = 663.58 N

Hence,

The force with which it should be pulled to keep the knot from moving is 663.58 N.

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