When looking for the domain of a graph, which values are you looking for?


x-values


y-values

The Polynomial 4 will be 3x^2 - 2. The solution is obtained using arithmetic operations.

What are arithmetic operations?

There are four basic operations which are listed as follows:

⇒Polynomial 1 = x^2 - x^2 + x + x + x + x - 1 + 1 - 1

⇒Polynomial 1 = 4x - 1

⇒Polynomial 2 = x + x + x - x - x^2 - x^2 - 1 + 1 - 1

⇒Polynomial 2 = 2x - 2x^2 - 1

⇒Polynomial 2 = -2x^2 + 2x  - 1

⇒Polynomial 3 = 1 + 1 + 1 + 1 - x - x + x - x^2 + x^2 - x^2

⇒Polynomial 3 = 4 - x - x^2

⇒Polynomial 3 = -x^2 - x + 4

We are given sum of all four expressions = 5x

So,

4x - 1 + (-2x^2 + 2x  - 1) + (-x^2 - x + 4) + Polynomial 4 = 5x

On simplifying the equation,

⇒4x - 1 - 2x^2 + 2x  - 1 - x^2 - x + 4 + Polynomial 4 = 5x

⇒5x - 3x^2 + 2 + Polynomial 4 = 5x

⇒Polynomial 4 = 5x - (5x - 3x^2 + 2)

⇒Polynomial 4 = 5x - 5x + 3x^2 - 2

⇒Polynomial 4 = 3x^2 - 2

Hence, polynomial 4 is 3x^2 - 2 which will be 3 big black squares and 2 small white squares.

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The required quadratic polynomial is  [tex]x^{2} - 8x + 12 =0[/tex] and roots of this quadratic polynomial are 2 and 6.

Let the roots of the quadratic equation be  [tex]\alpha[/tex] and [tex]\beta[/tex] .

Given,  

          Sum of zeroes,  [tex]\alpha +\beta = 8[/tex]

           Product of Zeroes, [tex]\alpha *\beta = 12[/tex]

we know that,

      Quadratic Equation can be written as :

                     [tex]x^{2} - (\alpha + \beta )x + \alpha \beta =0[/tex]

     Substituting the values in the above Equation,

                    [tex]x^{2} - (8)x + (12) =0[/tex]

                    [tex]x^{2} - 8x + 12 =0[/tex]

Hence, The required quadratic equation is [tex]x^{2} - 8x + 12 =0[/tex] .

Now, let's factorize the equation to find its root:

                    [tex]x^{2} - 8x + 12 =0[/tex]

                    [tex]x^{2} - 6x -2x+ 12 =0[/tex]

                    [tex]x(x-6) -2(x-6)=0[/tex]

                     [tex](x-6)(x-2)=0[/tex]

                    ⇒ [tex]x= 2,6[/tex]

Therefore roots of the quadratic equation [tex]\alpha ,\beta[/tex] are [tex]2,6[/tex] .

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Let's use v1(t) and v2(t) to represent the speed of the first and second runners, respectively, at time t. The functions v1 and v2 must both be continuous in the time variable t, hence this assumption must be made.

So, their difference, a(t), is similarly a continuous function in the variable t, with the formula a(t) = v1(t)-v2(t).  

Now, using the principle of contradiction, one may demonstrate that t1, t2, such that a(t1) is less than or equal to 0 and a(t2) is higher than or equal to 0, exist because the overall average speed of both runners is identical.

Now, we may utilize the continuous function a's Intermediate Value Property to locate a t0 between t1 and t2, where a(to)=0 and the runners are moving at the same speed at this point.

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trignometry of  secx * cscx= 1/ cosx*sinx  = sin^2 x+ cos ^ 2 x/ cos x * sin x   = cotx + tan x

What is the formula of sin?

The sine of an angle of a right-angled triangle is the ratio of its perpendicular (that is opposite to the angle) to the hypotenuse. The sin formula is given as: sin θ = Perpendicular / Hypotenuse.

secx = 1/cosx

and cscx= 1/sin x

then secx * cscx= 1/ cosx*sinx

                         = sin^2 x+ cos ^ 2 x/ cos x * sin x

                          = cotx + tan x

Hence trignometry of  secx * cscx= 1/ cosx*sinx  = sin^2 x+ cos ^ 2 x/ cos x * sin x   = cotx + tan x

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Answer:

6 cm

Step-by-step explanation:

a = 1/2bh

42 = 1/2(14)h

42 = 7h  Divide both sides by 7

6 = h

Answer:

Solve the formula firnthebspecified variable

I= Prt

P=

The graph that represents the situation is added as an attachment

From the question, we have the following parameters that can be used in our computation:

This means that the graph would be represented using a distance/time graph

Such that the distance would be on the y-axis and the time would be on the x-axis

See attachment for the graph

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The value of the third quartile was then found to be 4.0, which is the 12th entry in the ordered data.

below is a stem and leaf plot of the magnitude of earthquakes on sept. 4th, 2012 in the philippine islands region. this data was collected by the general social survey. find the third quartile.

Stem|Leaf

2 | 0 2 3 6 8 9

3 | 0 1 3 4 6 7 8

4 | 0 1 2 4 5

Third Quartile = 4.0

Step 1: Order the data from least to greatest:

2.0, 2.3, 2.6, 2.8, 2.9, 3.0, 3.1, 3.3, 3.4, 3.6, 3.7, 3.8, 4.0, 4.1, 4.2, 4.4, 4.5

Step 2: Count the data points:

There are 16 data points.

Step 3: Calculate the index of the third quartile:

Index of third quartile = (3/4) x (16) = 12

Step 4: Find the value of the third quartile:

The value of the third quartile is the 12th entry in the ordered data, which is 4.0.

The third quartile of the magnitude of earthquakes in the Philippine Islands region on September 4th, 2012 is 4.0. This data was collected by the General Social Survey. To calculate the third quartile, the data points were ordered from least to greatest and the index of the third quartile was calculated. The value of the third quartile was then found to be 4.0, which is the 12th entry in the ordered data.

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The expression 12 *3/4 is 9.

Explanation:

12 * 3/4 = 91 = 9.

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The expression 12 *3/4 is 9.

By multiplying both sides of the equation by the least common denominator (LCD) of each term, a fractional equation can be solved by first eliminating the fractions. This is possible because an equation cannot become unbalanced when both sides are multiplied by the same number, in this case, the LCD.

Using mathematical operations like subtraction, addition, multiplication, and division, terms are joined to form an expression. Mathematical expressions contain the following terms: Constant: An absolute number is a constant.

12 * 3/4 = 91 = 9.

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The angular size of the minor arc AB can be calculated using the formula: Angular size = Arc length/Radius. Therefore, the angular size of the minor arc AB is 16 cm/12 cm = 1.333 radians.

The angular size of the minor arc AB can be calculated using the formula: Angular size = Arc length/Radius. To calculate the angular size of the minor arc AB, we need to know the length of the chord AB and the radius of the circle. In this case, the chord AB is 16 cm long and the radius of the circle is 12 cm. Therefore, we can calculate the angular size of the minor arc AB by dividing the length of the chord AB by the radius of the circle, which is 16 cm/12 cm = 1.333 radians. The angular size of the minor arc AB is 1.333 radians.

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The following statements are true:

BC║B'C'

AC ⊥ line C'D'

D' and C have the same coordinates

C' lies on line OC

What is dilation?

In mathematics, dilation refers to the process of scaling a geometric figure by a certain factor. This factor is called the scale factor or dilation factor, and it can be either greater than or less than 1. A dilation that enlarges an object is called a magnifying dilation and a dilation that reduces an object is called a shrinking dilation.

Dilation does not change angles or directions. Every image point X' lies on the line containing the center of dilation and the pre-image point X. If the scale factor is other than 1, no image segment will be congruent to its pre-image segment.

Hence, the following statements are true:

BC║B'C'

AC ⊥ line C'D'

D' and C have the same coordinates

C' lies on line OC

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The length of the trail is given as follows:

32 km.

The length of the trail is obtained applying the proportions in the context of this problem.

The fractions hiked each day are given as follows:

The total fraction after the second day is given as follows:

1/8 + 4/7 x 7/8 = 5/8.

On the third day, one third of the remaining was hiked, hence:

5/8 + 1/3 x 3/8 = 6/8.

Meaning that the remaining distance of 8 km is 2/8 = 1/4 of the total distance, hence:

x/4 = 8

x = 32 km.

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The domain of the function is all real numbers[tex]$\{x|x\in \mathbb{R}\}$[/tex] greater or equal to 0, because the number of players $n$ can not be negative.

The graph of the function is a line with a slope of 1.5 and a y-intercept of 2.5. This can be seen by considering the equation c(n) = 1.5n + 2.5. As the number of new players n increases, the cost c increases by 1.5 for each new player added. For example, if you add 3 new players, the total cost c is 1.5(3) + 2.5 = 6.5. Similarly, if you add 5 new players, the total cost is 1.5(5) + 2.5 = 8.5.

For example, if you want to add 10 new players, the cost will be $c=1.50\times10+2.50=17.50$. Substituting $n=10$ into the function gives $c=17.50$. The graph of this function is a straight line that passes through the origin and has a positive slope of 1.50.

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Answer:

3

Step-by-step explanation:

Let x represent the missing value.

(-3) = x + (-6)

6 + (-3) = x + 6 + (-6)

3 = x

Answer:A

Step-by-step explanation:

1440:15=96

Answer:

24

Step-by-step explanation:

Because of similar triangles,

UV/UG = UW/UH

132/24 = 132/UH

UH = 24

Answer:

24

Step-by-step explanation:

GU.U.V=HU. UW

24×132=HU×132

3168=132HU

HU=24

Answer:

[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Bank & \sf Basic\;Fee\times 12 & \sf Bill\;Paying\;Fee\times 12 & \sf Checks\;Written-Limit\\\cline{1-4}\vphantom{\dfrac12}\sf A&\$18&\$27&20\\\cline{1-4}\vphantom{\dfrac12}\sf B&\$30&\$27&10\\\cline{1-4}\vphantom{\dfrac12}\sf C&\$18&\$21&10\\\cline{1-4}\vphantom{\dfrac12}\sf D&\$30&\$21&20\\\cline{1-4}\end{array}[/tex]

[tex]\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12}\sf Bank & \sf Column\;4\times Cost\;per\;bill\times 12 & \sf Annual\;Total\\\cline{1-3}\vphantom{\dfrac12}\sf A&\$24&\$69\\\cline{1-3}\vphantom{\dfrac12}\sf B&\$18&\$75\\\cline{1-3}\vphantom{\dfrac12}\sf C&\$24&\$63\\\cline{1-3}\vphantom{\dfrac12}\sf D&\$48&\$99\\\cline{1-3}\end{array}[/tex]

Step-by-step explanation:

Jane wants to compare the cost of online banking across 4 different banks. We are told that she writes an average of 40 checks each month.

Given monthly charges for four different banks:

[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5}\vphantom{\dfrac12}\sf Bank & \sf Basic\;Monthly\;Fee& \sf Bill\;Paying\;Monthly\;Fee & \sf Limit& \sf Cost\;per\;bill\;beyond\;limit\\\cline{1-5}\vphantom{\dfrac12}\sf A&\$1.50&\$2.25&20&\$0.10\\\cline{1-5}\vphantom{\dfrac12}\sf B&\$2.50&\$2.25&30&\$0.15\\\cline{1-5}\vphantom{\dfrac12}\sf C&\$1.50&\$1.75&30&\$0.20\\\cline{1-5}\vphantom{\dfrac12}\sf D&\$2.50&\$1.75&20&\$0.20\\\cline{1-5}\end{array}[/tex]

The "limit" is the number of checks Jane is not charged a fee to write per month.  For each check Jane writes above this monthly limit, she will be charged a fee (fifth column).

To complete the first table:

[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Bank&\sf Basic\;Fee\times12&\sf Bill\;Paying\;Fee\times12&\sf Checks\;Written-Limit\\\cline{1-4}\vphantom{\dfrac12}\sf A&\$1.50\times12=\$18&\$2.25\times12=\$27&40-20=20\\\cline{1-4}\vphantom{\dfrac12}\sf B&\$2.50\times12=\$30&\$2.25\times12=\$27&40-30=10\\\cline{1-4}\vphantom{\dfrac12}\sf C&\$1.50\times12=\$18&\$1.75\times12=\$21&40-30=10\\\cline{1-4}\vphantom{\dfrac12}\sf D&\$2.50\times12=\$30&\$1.75\times12=\$21&40-20=20\\\cline{1-4}\end{array}[/tex]

To complete the second table:

[tex]\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12}\sf Bank & \sf Column\;4\times Cost\;per\;bill\times 12 & \sf Annual\;Total\\\cline{1-3}\vphantom{\dfrac12}\sf A&20\times\$0.10\times12=\$24&\$18+\$27+\$24=\$69\\\cline{1-3}\vphantom{\dfrac12}\sf B&10\times\$0.15\times12=\$18&\$30+\$27+\$18=\$75\\\cline{1-3}\vphantom{\dfrac12}\sf C&10\times\$0.20\times12=\$24&\$18+\$21+\$24=\$63\\\cline{1-3}\vphantom{\dfrac12}\sf D&20\times\$0.20\times12=\$48&\$30+\$21+\$48=\$99\\\cline{1-3}\end{array}[/tex]

The percentage of the variation in height that is explained by a regression on age is 0.64, which is the right answer.

from the aforementioned case, The relationship between children's age and height is strongly correlated, as evidenced by the correlation coefficient R of 0.8. Given the correlation coefficient value, we can calculate the coefficient of determination (R2), which indicates the proportion of variation that the regression model can account for.

Therefore, R2 = 0.82 = 0.64, which is the coefficient of determination. Therefore, the proportion of the variation in children's height that can be attributed to age is 0.64 and the remaining 0.36 can be attributed to other factors.

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This is a system of equations problem. Let x be the number of dimes and y be the number of nickels.

From the problem, we know the following:

x + y = n (where n is the total number of coins)

y = 3x - 9 (because the number of nickels is three times the number of dimes minus nine)

We also know that the total value of the coins is $2.55 and that a dime is worth $0.10 and a nickel is worth $0.05. So we can create an equation using the total value of the coins:

0.10x + 0.05y = 2.55

Now we have a system of three equations and three variables. To solve for x, y and n, we can use substitution or elimination method.

First equation and second equation:

x+3x-9 = n

4x-9=n

4x = n+9

x = (n+9)/4

By substituting the value of x in equation 3

0.10*(n+9)/4 + 0.05*(3*(n+9)/4-9) = 2.55

Solving this equation we get n = 63

Thus, x = (63+9)/4 = 18 dimes

y = 3x - 9 = 3*18 - 9 = 45 nickels

So, Carolyn has 18 dimes and 45 nickels.

The average rate of growth between each pair of years was calculated in part (a). The instantaneous rate of growth for 2006 was estimated in part (b) and (c), and the instantaneous rate of growth for 2007 was estimated in part (d). Comparing the growth rates from parts (c) and (d), it can be concluded that the rate of growth is constant.

In part (a), the average rate of growth between each pair of years was calculated by dividing the difference between the number of locations in two consecutive years by the number of years between them. For example, to find the average rate of growth between 2005 and 2006, the difference in the number of locations (12441-10236) was divided by the number of years (1). The result was 22.05 locations/year. In part (b), the instantaneous rate of growth in 2006 was estimated by taking the average of the last two rates of change from part (a). This was done by adding the rates of growth from 2005 to 2006 (22.05 locations/year) and 2006 to 2007 (27.64 locations/year) and then dividing by two. The result was 24.85 locations/year. In part (c), the instantaneous rate of growth in 2006 was estimated by measuring the slope of the tangent line through (2005, 10236) and (2007, 15005). This was done by finding the difference in the number of locations (15005-10236) and dividing by the number of years (2). The result was 22.85 locations/year. In part (d), the instantaneous rate of growth in 2007 was estimated by measuring the slope of the tangent line through (2006, 12441) and (2008, 16683). This was done by finding the difference in the number of locations (16683-12441) and dividing by the number of years (2). The result was 22.21 locations/year. Comparing the growth rates from parts (c) and (d), it can be concluded that the rate of growth is constant.

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The slope of the line is given by the equation m = -3

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

Let the first point be represented as P ( 2 , -1 )

Let the second point be represented as Q ( 1 , 2 )

Now , the slope of the line between the points is

Slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values in the equation , we get

Slope m = ( 2 - ( -1 ) ) / 1 - 2

Slope m = 3 / -1

Slope m = -3

Hence , the slope of the line is decreasing as m = -3 and has a negative value

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The volume of the cube with side of (4m⁸n⁴) unit is (64m²⁴n¹²) unit³

An equation is an expression showing two or more numbers and variables linked together by a mathematical operation. Types of equations are linear, quadratic, cubic and so on depending on the degree of the variable.

Volume is the amount of space that a three dimensional object occupies. For a cube, all the sides are equal, that is length = width = height

The volume of the cube is:

Volume = length³

Given that length = 4m⁸n⁴

Hence:

Volume = length³ = (4m⁸n⁴)³ = 64m²⁴n¹²

The volume of the cube is (64m²⁴n¹²) unit³

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The values of the variance and expected value expressions are

From the question, we have the following parameters that can be used in our computation:

E(Y1) = 10

E(Y2) = 2

The above parameters are calculated as follows:

a. Expected value

E(4Y1 – 2Y2 + 6) = 4E(Y1) – 2E(Y2) + 6

= 4(10) – 2(2) + 6

= 40 - 4 + 6

= 42

So E(4Y1 – 2Y2 + 6) = 42

b. Variance

V(4Y1 – 2Y2 + 6) = 4^2 * V(Y1) + (-2)^2 * V(Y2)

= 16 * V(Y1) + 4 * V(Y2)

The variances of Y1 and Y2 are not given

This means that the value of the expression cannot be calculated

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The proportional relationship between time spent skateboarding and the number of calories burned will be y = 10x.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

Let 'x' be the number of minutes and 'y' be the number of calories burned. And at x = 0, the value of y is also zero. Then we have

0 = m(0) + c

c = 0

Then the equation is given as,

y = mx

At x = 5, the value of y is 50. Then we have

50 = m(5)

5m = 50

m = 50 / 5

m = 10 calories per minute

The proportional relationship between time spent skateboarding and the number of calories burned will be y = 10x.

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The missing graph is attached below.

Answer: she will receive a grade of zero if she gets one more question incorrect.

Step-by-step explanation: She gets 2 questions correct which equals 4 points and 3 questions wrong which is minus 3 points

4-3=1 so if she were to get one more incorrect she would receive a zero

Yes, there is an association between food ordered and drink ordered because the distributive property of drinks ordered differs among the food groups.

Yes, there is an association between food ordered and drink ordered, as evidenced by the graph. The graph shows the distribution of drinks ordered among the various food groups, and it can be seen that the distribution differs among the food groups. For example, beer is the most popular drink ordered when burgers are the food ordered, while soda is the most popular drink when salads are the food ordered. This indicates that customers are more likely to order certain drinks depending on the type of food they are ordering, showing an association between food ordered and drink ordered.

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The numeric value of f(x) = x - 3 at x = 7 is given as follows:

f(7) = 4.

To find the numeric value of a function or of an expression, we replace each instance of the variable in the function or in the expression by the value at which we want to find the numeric value.

The function for this problem is defined as follows:

f(x) = x - 3.

To obtain the numeric value of the function at x = 7, we replace the lone instance of x by 7, hence:

f(7) = 7 - 3 = 4.

The function for this problem is defined as follows:

f(x) = x - 3.

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Many times referred to as "story issues," word problems can range in the amount of technical terminology utilized and typically incorporate some form of narrative.

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Data Retention Settings. This feature allows you to specify how long user-level and event-level data is stored by analytics before being automatically deleted. You can set up data retention periods for different types of data, such as individual user data, event data, and session data.

Data Retention Settings is a feature available in many analytics platforms that allows you to control how long user-level and event-level data is stored. This helps ensure that the data stored is only relevant to your project. You can set up different data retention periods for different types of data, such as individual user data, event data, and session data. This allows you to specify how long the data should be stored before being automatically deleted. Data retention settings are important as they help protect user privacy and ensure that only the data necessary for your project is stored. They also help you manage your storage costs by allowing you to set a maximum amount of data that can be stored for a certain period of time. Data Retention Settings is a valuable tool for managing the data collected by your analytics platform.

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The complete question is

which of these features lets you control how long user-level and event-level data is stored by analytics Data Retention Policies.

The equation be (x - 10)(x + 10) then x² - 100.

In addition to the monomial, binomial, and polynomial types of expressions, there are two further categories into which an algebraic expression can be placed: Expression in numbers. adjustable expression.

Using the operations + , – , × or ÷ a group of numbers or variables can be combined to form an expression. Expressions in algebra that include variables, numbers, and mathematical operators differ from expressions in arithmetic that simply contain numbers and mathematical operators.

Let the equation be (x - 10)(x + 10)

(x - 10)(x + 10)

simplifying the above equation, we get

= x² - 100

The equation be (x - 10)(x + 10) then x² - 100.

The complete question is:

How do you simplify (x - 10)(x + 10) ?

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