when sample observations can be paired (or we have dependent samples) treating these as independent samples will multiple choice question. reduce the power of the test. decrease the chance of a type ii error. increase the power of the test. always result in rejecting the null hypothesis.

The height of the cylinder is approximately 7.94 meters when rounded to the nearest tenth.

How did this do?

The surface area of a cylinder can be calculated using the formula:

SA = 2πr^2 + 2πrh

where r is the radius of the base and h is the height of the cylinder.

We are given the diameter of the cylinder's base, which is 8 m. The radius is half the diameter, so:

r = 8 m / 2 = 4 m

Substituting this value for r, and the given value for SA into the formula, we get:

256.224 m² = 2π(4 m)^2 + 2π(4 m)h

Simplifying this equation:

256.224 m² = 32π + 8πh

256.224 m² - 32π = 8πh

h = (256.224 m² - 32π) / (8π)

h ≈ 7.94 m (rounded to the nearest tenth)

The solution of the expression is,

⇒ 0 + (7/11)√5

We have to given that;

Expression is,

⇒ (7 + √5) / (7 - √5) - (7 - √5) / (7 + √5)

Take LCM we get;

⇒ (7 + √5)² - (7 - √5)² / (7 - √5) (7 + √5)

⇒ (49 + 5 + 14√5) - (49 + 5 - 14√5) / (7² - √5²)

⇒ (28√5) / (49 - 5)

⇒ 28√5 / 44

⇒ 7√5 / 11

⇒ 0 + (7/11)√5

Thus, The solution of the expression is,

⇒ 0 + (7/11)√5

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The values of r where the area of the shaded region be greater are values at least 8

From the question, we have the following parameters that can be used in our computation:

The area of the larger rectangle is

Area = 12 * 8

Area = 96

The area of the shaded region is

Area = r * 6

Area = 6r

When the shaded region is greater than or equal to half of the area of the larger rectangle, we have

6r ≥ 1/2 * 96

This gives

r ≥ 1/12 * 96

Evaluate

r ≥ 8

Hence, the values of r are r ≥ 8

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The level of accounts receivable will be $479,452.05.

If Harley-Davidson Inc. reduces its DSO to 35 days by pressuring more of its customers to pay their bills on time, the company’s average sales will fall by 15%. To calculate the level of accounts receivable following this change, we need to use the formula for DSO:

DSO = (Accounts Receivable / Average Daily Sales) x Number of Days in Period

We know that the current DSO is 55 days, and the company wants to reduce it to 35 days. Therefore, we can assume that the current average daily sales are:

Average Daily Sales = Annual Sales / 365
DSO = (Accounts Receivable / Average Daily Sales) x Number of Days in Period
55 = ($750,000 / (Annual Sales / 365)) x 365

Solving for Annual Sales, we get:

Annual Sales = $1,095,890.41

If the company’s average sales will fall by 15%, then the new Annual Sales will be:

New Annual Sales = $931,507.85 ($1,095,890.41 - 15%)

Using this new Annual Sales figure, we can now calculate the new level of accounts receivable following the change:

35 = (New Accounts Receivable / (New Annual Sales / 365)) x 365
New Accounts Receivable = $479,452.05

Therefore, if Harley-Davidson Inc. reduces its DSO to 35 days by pressuring more of its customers to pay their bills on time and its average sales fall by 15%, the level of accounts receivable will be $479,452.05.

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Answer:

p=$16.5

Step-by-step explanation:

By using the distributive Property, you can say:

5p-15=63

Then add 15 on both sides to make the equation balanced:

5p=78

Then divide by 5:

p=78/5=$16.5

Answer:

Step-by-step explanation:

it is 83/49 because I searched it up.

The value of x for the same angle based on the information is 13.

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle

Since angles 5 and 10 are the same, we can set them equal to each other:

91 - 2x = 5x

Simplifying this equation, we can add 2x to both sides:

91 = 7x

Then, we can divide both sides by 7 to solve for x:

x = 13

Therefore, the value of x for the same angle is 13.

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Answer:

C. (x+2)2=3

Step-by-step explanation:

Take the root of both sides and solve.

Both x2+4x-5=0 and (x+2)2=3 have the solution of x=1,-5

have a great day and thx for your inquiry :)

The small submarine must travel 1,140 feet and maintain a speed of 19 feet per minute in order to reach a depth of 180 feet below sea level within 60 minutes.

To determine the distance that the small submarine must travel to reach 180 feet below sea level, we need to use some basic math.
First, we need to determine the distance between the current position of the submarine (-1,320 feet) and its target depth (-180 feet below sea level). To do this, we subtract the target depth from the current depth:
-1,320 ft - (-180 ft) = -1,140 ft
This means that the submarine needs to travel 1,140 feet down in order to reach its target depth.
Next, we need to figure out how long it will take the submarine to travel that distance. We know that it has 60 minutes to do so, so we can use the formula:
distance = rate x time
We know the distance (1,140 feet), so we need to solve for rate. Rearranging the formula, we get:
rate = distance / time
Plugging in the values we know, we get:
rate = 1,140 ft / 60 min = 19 ft/min
So the small submarine needs to travel at a rate of 19 feet per minute in order to reach its target depth of 180 feet below sea level in 60 minutes.
In summary, the small submarine must travel 1,140 feet and maintain a speed of 19 feet per minute in order to reach a depth of 180 feet below sea level within 60 minutes.

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When comparing the two means of independent samples, we are allowed to pool the variances when the population variances are unknown, but assumed equal.

Pooling the variances is a statistical technique used when comparing means from independent samples. It involves combining the sample variances from both groups to estimate a common variance. This assumption of equal variances allows for a more accurate estimation of the standard error in the case of equal population variances.

When the population variances are unknown, we can conduct a statistical test, such as the t-test, assuming equal variances. This test uses the pooled variance estimate to calculate the standard error and determine the statistical significance of the mean difference between the two groups.

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Answer:

Step-by-step explanation:

let the present age of mother and daughter be x and y

[tex]\frac{1}{2} * (x + y) = x - y\\x + y = 2x - 2y\\x = 3y --- (1)\\[/tex]

[tex]x+4 = 2(y+4)\\3y+4 = 2y + 8\\y = 4\\x = 3y = 12[/tex]

Age of mother = 12 yrs

Age of daughter = 4 yrs

The maximum number of gift packages that Rodarius can make is 30. Each gift package will contain 4 mini footballs and 1 signed autograph from the Titans.

To determine the maximum number of gift packages Rodarius can make so that each recipient gets an equal number of footballs and autographs, we need to find the greatest common factor (GCF) of the two numbers, 120 and 30.

The prime factorization of 120 is:

120 = 2³ x 3 x 5

The prime factorization of 30 is:

30 = 2 x 3 x 5

To calculate the GCF, multiply the product of the common factors by the lowest exponent:

GCF = 2 x 3 x 5 = 30

So the maximum number of gift packages that Rodarius can make is 30. Each gift package will contain 4 mini footballs and 1 signed autograph from the Titans.

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the series ex2 converges for all real values of x.

The general term of the series ex2 = 1 + x^2 + x^4/2! + x^6/3! + x^8/4! + ... is given by:

an = xn/(n!) for n ≥ 0, where n is an even integer.

Here, xn represents the term with exponent n in the series.

Therefore, the range of values for the index n is all even non-negative integers starting from 0.

Note that n! (n factorial) in the denominator of the general term ensures that each term after the first term (which is 1) is smaller than the preceding term, as n increases.

what is integer?

An integer is a whole number that can be positive, negative, or zero. It does not include fractions or decimals. Examples of integers include -3, -2, -1, 0, 1, 2, 3, and so on. The set of integers is denoted by the symbol Z.

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Answer: It meets at 90, and it passes through the midpoint.

Step-by-step explanation:

It isn't the first option because there is no distance between the line and it's bisector

It meets at AB because at a 90 degree angle because it perpendicular

Because of that, it can't also meet at a 180 degree angle

because its a bisector, it would not pass through A or B

It must meet line AB to bisect it

And because it bisects the line, it would also pass through the midpoint.

To find the points where the height of the Gateway Arch is 100 meters, we need to solve the equation y = 100 for x.

Substituting y = 100 into the equation for the central curve of the arch, we get:

100 = 211.49 - 20.96 cosh (0.03291765x)

Rearranging the equation, we get:

cosh (0.03291765x) = (211.49 - 100) / 20.96

cosh (0.03291765x) = 5.21

Taking the inverse hyperbolic cosine of both sides, we get:

0.03291765x = acosh(5.21)

x = (1/0.03291765) acosh(5.21)

Solving for x using a calculator, we get:

x = ± 64.975

Therefore, the height of the Gateway Arch is 100 meters at the points (64.975, 100) and (-64.975, 100).

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Mike has under 1/4 of a tank of gas, and he decides to fill up his gas tank. his gas tank holds 16 gallons. the gas cost $3.59 per gallon. It will cost Mike $43.08 to fill up his car.

To help you with your question, we first need to determine the amount of gas Mike needs to fill up his car. Since he has less than 1/4 of a tank, let's assume he has exactly 1/4 of a tank for simplicity.
Mike's car has a 16-gallon gas tank, so:
1/4 * 16 gallons = 4 gallons already in the tank.
To fill up the tank, Mike needs to add:
16 gallons - 4 gallons = 12 gallons.
The gas costs $3.59 per gallon, so to find the total cost:
12 gallons * $3.59 = $43.08.
Approximately, it will cost Mike $43.08 to fill up his car.

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Answer:

S=2t

or

T=1/2 S

Answer:

20

Step-by-step explanation:

16 / 20 = 0.80

0.80 = 80%

Step-by-step explanation:

(3j - 5k^3) ( 3j + 5k^3)  =  9j^2 - 25k^6

1.429

This is the answer to your problem

Answer: b

Step-by-step explanation: b

To express the radius of a circle, denoted by r, in terms of the length of the chord (l) and the distance of the chord from the center of the circle (h), we can use the following approach:

In a circle, the perpendicular distance from the center to a chord bisects the chord. This means that the distance from the center to the midpoint of the chord is equal to h/2. Now, consider the right triangle formed by the radius (r), the distance from the center to the midpoint of the chord (h/2), and half of the chord length (l/2). According to the Pythagorean theorem, the square of the radius is equal to the sum of the squares of the other two sides of the triangle.

Using this information, we can write the equation:

r^2 = (h/2)^2 + (l/2)^2

Simplifying the equation:

r^2 = h^2/4 + l^2/4

Taking the square root of both sides to solve for r:

r = √(h^2/4 + l^2/4)

Therefore, the expression for the radius (r) in terms of the length of the chord (l) and the distance of the chord from the center (h) is r = √(h^2/4 + l^2/4).

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The approximate number of customers (waiting and being served) at the carwash is 3.

To determine the number of customers (waiting and being served) at the carwash, we can use Little's Law, which states that the average number of customers in a system is equal to the average arrival rate multiplied by the average time spent in the system.

In this case, the average arrival rate is 9 customers per hour, and the average waiting time is given as 23 minutes (which is equivalent to 23/60 = 0.3833 hours).

Using Little's Law, we can calculate the average number of customers in the system:

Average number of customers = Average arrival rate * Average time spent in the system

Average number of customers = 9 customers/hour * 0.3833 hours

Average number of customers = 3.4497 customers

Since we can't have fractional customers, we round the value to the nearest whole number.

Therefore, the approximate number of customers (waiting and being served) at the carwash is 3.

It's important to note that this calculation assumes steady-state conditions and that the arrival and service distributions are not known.

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[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=6\\ \theta =\frac{\pi }{6} \end{cases}\implies A=\cfrac{(\frac{\pi }{6})(6)^2}{2} \\\\\\ A=3\pi \implies A\approx 9.42~m^2[/tex]

Answer:

----------------------------

Use the formula:

We know that John drives a distance of 16 miles to work at a rate of m miles per hour.

So, the time it takes him to travel the full distance is:

On a certain day, the car stops after only v miles. So, the distance John still needs to travel is:

We also know that he will be traveling at the same rate, so we can use the formula again:

To find the time left, we can rearrange the formula:

Therefore, the probability that the first card is a diamond or the second card is a face card is approximately 0.3039.

We can solve this problem by using the addition rule of probability.

The probability of the first card being a diamond is 13/52 (since there are 13 diamonds in a standard deck of 52 cards). The probability of the second card being a face card is 12/51 (since there are 12 face cards left in the deck after the first card is drawn).

To find the probability that either event occurs, we add the probabilities and subtract the probability of both events happening together (since we only want to count that once):

P(diamond or face card) = P(diamond) + P(face card) - P(diamond and face card)

P(diamond or face card) = 13/52 + 12/51 - (3/51) [since there are 3 face cards that are also diamonds]

Simplifying the expression, we get:

P(diamond or face card) = 0.3039

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a) The radius of convergence is also 1, since it is the same as the radius of convergence of ln(1+x).

a) We can find a power series representation for f(x) = ln(1+x) by using the formula:

ln(1 + x) = ∑(-1)^(n-1) * x^n / n for |x| < 1

So, the power series representation for ln(1+x) is:

ln(1 + x) = x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...

The radius of convergence is 1, since the series converges for |x| < 1 and diverges for |x| > 1.

b) To find a power series for f(x) = xln(1+x), we can use the product rule of power series:

xln(1 + x) = x * [x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...]

= x^2 - x^3/2 + x^4/3 - x^5/4 + x^6/5 - ...

So, the power series representation for f(x) = xln(1+x) is:

f(x) = xln(1+x) = ∑(-1)^(n-1) * x^(n+1) / n for |x| < 1

c) To find a power series for f(x)ln(x^2 + 1), we can use the product rule of power series again:

f(x)ln(x^2 + 1) = [x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...] * ln(x^2 + 1)

= [xln(x^2 + 1)] - [x^2 ln(x^2 + 1)]/2 + [x^3 ln(x^2 + 1)]/3 - [x^4 ln(x^2 + 1)]/4 + [x^5 ln(x^2 + 1)]/5 - ...

We already have a power series for xln(1+x), which is the same as xln(x^2+1) for |x| < 1. So, we can substitute it in the above series:

f(x)ln(x^2 + 1) = ∑(-1)^(n-1) * x^(2n+1) / (2n+1) * [1 - 1/2 + 1/3 - 1/4 + 1/5 - ...]

= ∑(-1)^(n-1) * x^(2n+1) / (2n+1) * ln(x^2 + 1)

The radius of convergence of this power series is also 1, since it is the same as the radius of convergence of ln(1+x) and xln(1+x).

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The number of zeroes or x-intercepts of a polynomial function is related to its highest power, which is determined by the degree of the polynomial. Let's consider a polynomial of degree "n" where "n" is a positive integer.

The minimum number of zeroes or x-intercepts a polynomial can have is zero. This occurs when all the terms of the polynomial have non-zero coefficients and there are no factors that would cause the polynomial to equal zero. For example, a polynomial of degree 2, such as f(x) = x^2 + 1, has no zeroes.

The maximum number of zeroes or x-intercepts a polynomial of degree "n" can have is "n". This is known as the Fundamental Theorem of Algebra, which states that a polynomial of degree "n" can have at most "n" distinct zeroes.

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The 75th percentile of the wait time in a restaurant, assuming it follows an exponential distribution with a mean of 10 minutes, can be found using the inverse of the exponential cumulative distribution function.

In an exponential distribution, the probability density function (PDF) is given by f(x) = λe^(-λx), where λ is the rate parameter. The mean of the exponential distribution is equal to 1/λ. In this case, we are given that the mean is 10 minutes, so λ = 1/10.

To find the 75th percentile, we need to find the value x for which P(X ≤ x) = 0.75. In other words, we want to find the value of x such that 75% of the wait times are less than or equal to x.

Using the exponential cumulative distribution function (CDF), we can solve for x by setting P(X ≤ x) = 0.75 and solving for x. The formula for the exponential CDF is F(x) = 1 - e^(-λx).

Setting 1 - e^(-λx) = 0.75, we can solve for x to find the 75th percentile of the wait time.

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The final result of the expression is -12,173/10,083. First, let's find the sum of 2/9 and -3/7. To add fractions, we need a common denominator. The least common multiple of 9 and 7 is 63.

To simplify the given expression, let's break it down step by step:

The sum of 2/9 and -3/7 is:

(2/9) + (-3/7)

To add these fractions, we need a common denominator, which is the least common multiple (LCM) of 9 and 7, which is 63.

(2/9) + (-3/7) = (2 * 7)/(9 * 7) + (-3 * 9)/(7 * 9)

= 14/63 - 27/63

= (14 - 27)/63

= -13/63

The difference of 3/7 and -13/23 is:

(3/7) - (-13/23)

Again, we need a common denominator, which is the LCM of 7 and 23, which is 161.

(3/7) - (-13/23) = (3 * 23)/(7 * 23) - (-13 * 7)/(23 * 7)

= 69/161 + 91/161

= (69 + 91)/161

= 160/161

Now, we subtract the second result from the first result:

(-13/63) - (160/161)

To subtract fractions, we need a common denominator, which is the LCM of 63 and 161, which is 10,083.

(-13/63) - (160/161) = (-13 * 161)/(63 * 161) - (160 * 63)/(161 * 63)

= -2,093/10,083 - 10,080/10,083

= (-2,093 - 10,080)/10,083

= -12,173/10,083.

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