The name of the compound is calcium chloride and the chemical formula of the compound is CaCl₂.
What is chemical formula?Chemical formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols of elements. It also makes use of brackets and subscripts.
Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form is called empirical formula.
It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.
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For the reaction 2HNO3 + Mg(OH)2 → Mg(NO3)2 + 2H₂O, how many grams of magnesium nitrate are produced from 9 grams of nitric acid, HNO3 ?
Read the information in the table below:
Which type of reaction is represented by B? (5 points)
Endothermic reaction
Exothermic reaction
Reaction between liquids
Reaction between solids
Answer:
it's exothermic reaction, becasue it have negative energy and the temperature increases
For the following reactions, calculate the ionization constant of each reaction. CH3COOH (aq) + H2O (l) equation H3O+ (aq) + CH3COO-(aq); [CH3COOH] = 0.8M, [H3O+] = 7.6M, [CH3COO-] = 16.4MKa =
Ionization constant of a reaction is the ratio of the molar concentration of product to that of reactants. For the given reaction, the ionization constant is 155.8 .
What is ionization constant ?A compound or element gets ionized to form its anion or cation by the gain or lose of electrons.
Here, acetic acid, CH₃COOH ionizes to form hydronium ion and acetate ion. The ratio of product of molar concentrations of products to the product of molar concentrations of the reactants is called the reaction constant.
The ionization constant of the given reaction is written as:
K = [H₃O]⁺ [CH₃COO-]/[CH₃COOH]
Given, [CH₃COOH] = 0.8 M
[CH₃COO-] = 16.4 M
and [H₃O]⁺ = 7.6 M.
then, K = 7.6 M × 16.4 M/ 0.8 M = 155.8
Therefore, the ionization constant of the reaction is 155.8.
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a solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g of water has a freezing point of -3.33 *C. Calculate the molar mass of the unknown liquid in g/mol.
The depression in freezing point of water here is 3.33 °C. Then the molality of the solution is 1.79. From number of moles of solute is calculated as 0.0161. Then , the molar mass of the solute is 62.11 g.
What is depression in freezing point ?The addition of a non-volatile salt into a solvent will decrease the freezing point of the solution than the pure solvent. The change in freezing point is proportional to the molality of the solution.
ΔTf = Kf m
Kf is called molal depression constant.
Kf for water = 1.86 °C Kg/mol
given ΔTf = 3.33 (0 - (-3.33))
then m = ΔTf /Kf = 3.33/ 1.86 °C Kg/mol = 1.79
Now, mass of water= 9 g = 0.009 kg
then number of moles = molality × mass of solvent
n = 0.009 kg × 1.79 = 0.0161.
mass of solute taken = 1 g
then, molar mass = 1/0.0161 = 62.11 g.
Therefore, the molar mass of the solute is 62.11 g.
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