When water vapor cools, it condenses.
Which number represents this process on the hydrologic cycle
diagram?
O 1
02
O 3
04

Answer:

9.519e^-2

Explanation:

To accurately show the number in scientific notation, you need to move the decimal place to the left 2 spaces. Because you are moving the decimal place to the left, the exponent will be a negative number. Because the decimal place moves 2 units to the left, the exponent will be a -2.

Therefore, the answer in correct scientific notation is:

951.9 ----------> 9.519e^-2

Reduction involves the either the addition of hydrogen and removal of oxygen.

Reduction involves the removal of oxygen.

This implies there is a loss of oxygen in reduction.

This can be represented in the extraction of iron from it ores.

Fe₂O₃ + 3CO →  2Fe + 3CO₂

Reduction is also the addition of hydrogen. This implies it is the gain of hydrogen.

For example

CH₃CHO → CH₃CH₂OH

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That would be...*drumroll* the structure of DNA!

Answer:

they help becuz they dont use any extra power and the are reneable

Answer:

i think the answer is Continental polar air masses

Explanation:

Answer:

49 moles of atoms

Explanation:

There are 7 individual atoms in each molecule of H2SO4:  (2 hydrogens + 1 sulfur + 4 oxygens).

Therefore, if 7 moles are decomposed, there would be 7 times that amount of individual atoms:

7 x 7 = 49 moles of atoms

the mr-vp tests are part of a battery of tests called imvic tests. these tests are useful in identifying and differentiating  Gram-positive cocci.

mr-vp tests can be regarded as a test that is used in the determination of fermentation pathway that is required in glucose.

It is used in mixed acid fermentation pathway and can be used in  identifying and differentiating  Gram-positive cocci.

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Answer:

Approximately 11460 Years Old

Explanation:

i looked this up :/

way to much maths for me

The age of the bone given that it contains C-14 and N-14 in ratio of 1:3 is 11460 years

C-14 is usually used for radioactive dating (i.e to determine the aga of substance)

From the question, C-14 and N-14 exist in ratio of 1:3.

thus, the amount of C-14 remaining can be obtained as follow:

Percentage of C-14 remaining = 1/4 × 100

Percentage of C-14 remaining = 25%

2ⁿ = N₀ / N

2ⁿ = 100 / 25

2ⁿ = 4

2ⁿ = 2²

n = 2

t = n × t½

t = 2 × 5730

t = 11460 years

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Answer:

the answer is c

Explanation:

A carboxylic acid is an organic compound that contains the carboxyl functional group.

Answer:

See Below

Explanation:

'an aerobic ' means it does not use oxygen

Answer:

anaerobic

Explanation:

The formula of hydrated copper(II) sulfate is CuSO4.10H2O

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

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Answer:

Cryogenic distillation is the commercially viable separation; however, it consumes over 20 Gigajoules of energy for every ton of ethylene produced. This energy consumption is associated with significant greenhouse gas emission and depletion of non-renewable energy resources

Explanation:

hope it's helpful to you

The work of John Lawrence scientist was most essential to the use of radioactive isotopes in medicine.

John Lawrence was the first scientist that use a radioactive isotope in the treatment of a human disease. He became known as the father of nuclear medicine and his laboratory is considered the birthplace of this field.

So we can conclude that the work of John Lawrence scientist was most essential to the use of radioactive isotopes in medicine.

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Answer: 0 K

Explanation:

This is a fact - absolute zero is defined as 0 degrees Kelvin.

Red algae and euglena evolved from a symbiotic relationship of organisms, which resulted in eukaryotic organisms containing chloroplasts

Theory of endosymbiosis:

Early eukaryotes developed by the symbiotic connection of prokaryotes, in accordance with the endosymbiosis idea. Which two protists underwent symbiotic evolution, leading to the development of eukaryotic creatures with chloroplasts.

-Symbiotic relationships between two or more prokaryotic cells led to the evolution of the first eukaryotic cells. Greater prokaryotic cells invaded or devoured smaller prokaryotic cells. The connection provided a secure home and nourishment for the tiny cells. By absorbing part of the organic molecules or energy generated by the endosymbionts, the bigger cells (now referred to as hosts) profited.

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Answer:

yellow

Explanation:

The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of a direct current through it.

The ions present in the system are[tex]H^+[/tex], [tex]OH^-[/tex] and [tex]NO_3^-[/tex] ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half-reaction equation of the reduction is;

[tex]2H^+(aq) + e[/tex] → [tex]H_2(g)[/tex]

The oxidation half-reaction equation is;

[tex]4OH^- (aq)[/tex] → [tex]2H_2O(l) + 4e[/tex]

The overall equation is;

[tex]4H^+(aq) + 4OH^- (aq)[/tex] → [tex]4H_2(g) + 2H_2O(l) + 4e[/tex]

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Answer: 29.2

Explanation:

From the coefficients of the equation, we know that for every 3 moles of hydrogen consumed, 1 mole of nitrogen is consumed.

This means we would need 6.25/3 = 2.0833333333333 mol of nitrogen.

Nitrogen has an atomic mass of 14.007 g/mol, so 2.0833333333333 moles of nitrogen have a mass of (14.007)(2.0833333333333) = 29.2 g (to 3 sf)

Answer:

answer will be b

Explanation:

mole is given 0.20

you have to find mass so just convert it into mass

remember if you move away from mole you multiply and if you move towards mole you divide so

just multiply mole with molar mass of glucose

so

0.20×180 = 36 grams

simple keep learning.......

Answer:

102 g Al₂O₃

Explanation:

To find the mass of Al₂O₃, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Al₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given values.

Molar Mass (Al): 26.98 g/mol

Molar Mass (Al₂O₃): 101.96 g/mol

4 Al + 3 O₂ ---> 2 Al₂O₃

54.0 g Al          1 mole             2 moles Al₂O₃         101.96 g
--------------  x  -----------------  x  -----------------------  x  ----------------  =  102 g Al₂O₃
                        26.98 g               4 moles Al            1 mole

Answer: 102 for 54.0 and 136 for 64.0

Explanation:

The alkaline earth metals are also referred to as Group 2A. elements are comparable to one another in terms of their electron configurations and thus, their properties.

From beryllium (Be) through radium, the alkaline-earth metals comprise Group 2 of the periodic table (Ra). The alkaline earth metals are so reactive because each of these elements has two electrons in its lowest energy level that they are rarely encountered alone in nature. However, they don't react as quickly as alkali metals do. Compared to the alkali metals, their chemical reactions normally proceed more slowly and generate less heat.

Be :- [He]2S2

Mg:-[Ne]3S2

Ca :-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Group 2A is another name for the alkaline earth metals, which are similar to one another in terms of their electron configurations and thus, their properties.

Group 2 of the periodic table is made up of alkaline-earth metals, starting with beryllium (Be) and ending with radium (Ra). The fact that each of these elements possesses two electrons at its lowest energy level makes the alkaline earth metals extremely reactive, which is why they are rarely found by themselves in nature. They don't respond as quickly, though, as alkali metals do. Their chemical reactions often take longer and produce less heat than those of the alkali metals.

Be:- [He]2S2

Mg:-[Ne]3S2

Ca:-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Answer:

C

Explanation:

The higher the period the higher the activity of an element, therefore, since iodine is in period 6 and bromine is in period 5, the described reaction is not possible due to the fact that bromine is less active

M₁V₁=M₂V₂

20 x V₁ = 3.5 x 755

V₁ = 132.125 ml

The statement that is correct about the emission spectrum of hydrogen in the visible region is that the line corresponding to the greatest emission of energy is in the ultraviolet region.

Hydrogen spectrum is defined as the dissociation of hydrogen atom upon action of electric current into spectral lines that can be seen in that visible light.

These lines falls under the electromagnetic wave of ultraviolet and infrared regions. But the lines of greatest emission is found in the ultraviolet region.

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