When you hold your cardboard square between the lights source and the wall what do you observe

Galileo’s astronomical observations  that were best explained by a heliocentric model is "The phases of Venus can only occur the way they do if Venus is orbiting the Sun".

What about the heliocentric model was accurate?

Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric concept puts the Sun at the core of the solar system. Our increased grasp of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.

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The big o notation of the worst-case scenario of pushing back an

element into a queue implemented using a list is Array or a Linked list.

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The time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

The time taken for the object to fall the same distance on planet X is calculated as follows;

t = √2h/g

where;

t² = 2h/g

gt² = 2h

g₁t₁² = g₂t₂²

t₂² = g₁t₁²/g₂

t₂² = (g₁ x 3.8²) / (0.2g₁)

not e one-fifth = 1/5 = 0.2

t₂² = 72.2

t₂ = √72.2

t₂ = 8.5 seconds

Thus, time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

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150 will be: stratified sample.

The partitioning of a population into smaller subgroups known as strata is a key component of the sampling technique known as stratified random sampling. In stratified random sampling, also known as stratification, the strata are created based on the shared traits or features of the members, such as wealth or level of education. Numerous uses and advantages of stratified random sampling include examining life expectancy and population demography.

Proportional or quota random sampling are other names for stratified random sampling. Researchers can produce a sample population that most accurately represents the whole population under study using stratified random sampling. Sampling is the process of drawing conclusions about a population using a small sample.

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The name of the temperature zone that includes the equator is Zone C and is referred to as the tropical zone.

This is referred to as the type of zone which is characterized by areas or regions around the equator. The name tropical was coined from its distinct climate which is usually warm all year round as a result of its very high sun exposure.

The degrees of latitude which this zone covers is 23.5 degrees and is south of the Equator which is therefore the reason why it was chosen as the most appropriate choice.

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Since motion under gravity only act on the vertical component of the velocity, the answer for both vertical and horizontal variables are;

a.) 9.8 m/s², 0

b.) 0, 18 m/s

c.) 21.2 m/s, 0

d.) 23 m, 39 m

e.) 2.2 s

Motion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

From the question, the following parameters are given.

a.) The vertical acceleration will be equal to acceleration due to gravity which is equal to 9.8 m/s². While the horizontal acceleration will be equal to zero.

b.) The vertical initial velocity is zero. Vertically, it will be assumed that the stone is dropped. While the given initial velocity is the horizontal initial velocity which is 18 m/s

c.) The vertical final velocity V can be calculated by using the formula

V² = U² + 2gH

V² = 0 + 2 × 9.8 × 23

V² = 450.8

V = √450.8

V = 21.23 m/s

Motion under gravity only act on the vertical component of the velocity. so, horizontal final velocity is equal to zero.

d.) Vertical distance = 23 m

While the horizontal distance = Range = ut

e.) Both the vertical and horizontal time will be the same. We can calculate the time by using the formula

h = ut + 1/2gt²

Vertically, u = 0

23 = 0 + 1/2 × 9.8 × t²

23 = 4.9t²

t² = 23/4.9

t² = 4.694

t = √4.69

t = 2.166 s

t = 2.2 s

so, the range = 18 × 2.166 = 38.997 m

Therefore, the time taken is 2.2 and the range is approximately 39 m.

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Charge,Q = 6.48 × [tex]10^-^9[/tex] C

It is given that,

Electric field strength, E = 180000 N/C

Distance from a small object, r = 1.8 cm = 0.018 m

Electric field at a point is given by :

[tex]E=\frac{KQ}{r^2}[/tex]

Q is the charge on an object

[tex]Q=\frac{Er^2}{k}[/tex]

Q = [180000 × [tex](0.018)^2[/tex]] ÷ 9 × [tex]10^9[/tex]

Q = 6.48 × [tex]10^-^9[/tex] C

So, the charge on the object is Q = 6.48 × [tex]10^-^9[/tex] C . Hence, this is the required solution.

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0.125 kg

Explanation:

The distance between the second-order fringes for these two wavelengths is 0.3 × 10—³ m.

The wavelength of first light is,

[tex]λ _{1} = 720 \: nm = 720 \times 10 ^{ - 9} \: m[/tex]

The wavelength of the second light is,

[tex]λ _{1} = 660 \: nm = 660 \times 10 ^{ - 9} \: m[/tex]

The separation is d.

d = 0.61 mm

[tex]d = 0.61 \times 10 ^{ - 9} \: m[/tex]

The distance of the screen is D.

D = 1 m

For wavelength 1 the distance of the second fringe is,

The number of fringes is 2.

[tex]x _{n} = \frac{nλD}{d} [/tex]

[tex]x _{2} = \frac{2 \times 720 \times 10 ^{ - 9} \times 1.5}{0.61 \times 10 ^{ - 3} } [/tex]

[tex] = 3.5 \times 10 ^{ - 3} [/tex]

For wavelength 2 the distance of the second fringe is,

[tex]x ^{'} _{n} = \frac{nλD}{d} [/tex]

[tex]x ^{'} _{2} = \frac{2 \times 660 \times 10 ^{ - 9} \times 1.5}{0.61 \times 10 ^{ - 3} } [/tex]

[tex]x ^{'} _{2} = 3.2\times 10 ^{ - 3} [/tex]

The distance between the second-order fringes for these two wavelengths on a screen 1.5 m away is,

[tex]∆x = x _{2} - x ^{'} _{2} [/tex]

[tex] = (3.5 \times 10 ^{ - 3} - 3.2 \times 10 ^{ - 3} )[/tex]

[tex] = 0.3 \times 10 ^{ - 3} \: m[/tex]

Therefore, the distance between the second-order fringes for these two wavelengths is 0.3 × 10—³ m.

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The weight of the combined system = 1,996.3 N

Given,

Mass of the Plastic tank = 3.5 kg

Volume of the liquid water in the tank = 0.2 m³

Density of water = 1000 kg/m³  

Now,

We know

Density = Mass ÷ Volume

Thus,

Mass = Density × Volume

therefore,

Mass of the water in the tank = 1000 × 0.2

= 200 kg

Thus,

The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg

Also,

Weight in N = Mass × Acceleration due to gravity (g)

and,

g = 9.81 m/s²

Therefore,

The weight of the combined system = 203.5 kg × 9.81 m/s²

= 1,996.3 N

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2.2cm^3

As per the statement the given measurement of different volumes

Let consider

V1 = 2.1cm^3

V2 = 2.1cm^3

V3 = 2.4cm^3

Now, we are supposed to find the mean value

mean value = submission of total number observation÷ sum of no. of observation

mean value = 2.1+2.1+2.4÷ 3

mean value = 6.6÷3

mean value= 2.2cm^3

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C. The launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

The angle of projection is calculated as follows;

R = u²sin(2θ) / g

where;

θ = 15⁰

sin 2θ = sin 2(15) = sin (30) = 0.5

θ = 90⁰ - 15⁰ = 75⁰

sin(2θ) = sin (2 x 75⁰) = sin (150⁰) = 0.5

Thus, the launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

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Answer:

Independent variable is the variable that causes the changes in the experiment. Dependent variable is the variable that is affected by the changes.

Explanation:

Explanation:

interesting let's see it is very confusing

Answer:

See below

Explanation:

Motion as the change of position of an object with respect to time.

Uniform motion covers equal distance at an equal time interval. The velocity is constant. For example, a car traveling at 55 mph constant speed for 2 hours has uniform motion

Non-uniform motion covers unequal distance at equal time intervals. For example, in heavy traffic, a car may travel at 20mph for the first 10 minutes, then 10mph for the next 10 minutes etc. Thus velocity changes over equal time periods

A boolean variable with the value "true" or "false" is what is referred to as a "flag" variable. You can either use an integer value with zero for "false" and semi for "true" or the boolean type with true or false.

CY is the carry flag's symbol. If a carry is produced during the procedure, it will be set to 1.

The procedure's outcome would be:

54 + C4 = 01010100 + 11000100

= 100011000

however because it cannot fit into the 8-bit destination register, the top bit is lost, and the actual result is 0x000110.

As a result, we can see that a carry is produced. CY will therefore equal 1.

The registers will be updated with the hexadecimal integers.

As a result, we can observe that no carry is produced. CY will therefore equal 0.

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Answer:

6 Newton.

Explanation:

Force (F) = Mass (M) x Acceleration (A).

Force = 2kg x 3 m/s^2

F = 6kg m/s^2 = 6 Newton. = 6N

Therefore, Force required to accelerate the body is 6N

The final pressure of ammonia if there is no change in temperature is 1.575atm.

A given mass of gas has a pressure that is inversely proportional to its volume at constant temperature. The gas rules of Boyle are followed in this query.

The mathematical notation is as follows:

[tex]P_{1} V_{1} = P_{2} V_{2}[/tex]

Rearranging the formula so that pressure [tex]P_{2}[/tex] is the formula's subject;

[tex]P_{2} = \frac{P_{1}V_{1} }{V_{2} }[/tex]

Plugging in the values we get:

[tex]P_{2} = \frac{(0.920)(80.3)}{(46.9)}[/tex]

[tex]P_{2} = 1.575atm[/tex]

Therefore,  the final pressure of ammonia if there is no change in temperature is 1.575atm.

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Acceleration of a ball rolling down hill, a = 3.5 m/s².

Given in details,

Initial velocity of ball,

u = 3 m/s

Final velocity of ball,

v = 34.5 m/s

Time taken for changing velocity,

t = 9 s

To find acceleration of ball,

a =?

Using formula,

First equation of motion

 v = u + a t

where,

v is final velocity,

u is initial velocity,

t is time taken

a is acceleration

Using this first equation of motion,

v = u + a t

34.5 = 3 + a × 9

34.5 - 3 = 9 a

31.5 = 9 a

a = 31.5 / 9

a = 3.5 m/s²

Newton's first law: the law of inertia

According to Newton's first law, if a body is at rest or moving in a straight line at a constant speed, it will continue to move at that speed or remain at rest until acted upon by a force.

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86.925 km

1=runner v1= 4.1km/h = 1.13m/s, here v1 and v2 is velocity

2=bird v2=12.3km/h = 3.41 m/s

bird covers 7100 m in t=7100/3.41=2082 s

at same time runner has traveled x=1.13  * 2082=2352.6

the remaining distance of 7100-2352=6865 m is traveled by runner an bird

6865=v1t+v2t

then t=6865/(1.13+3.41)=23410 s

the distance traveled by bird is

x2=7100+v2t

=7100+3.41*23410

x2=86928m = 86.925 km

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The energy absorbed outdoor copper sculpture heats up during the day q = 1.79 x 10⁵ J.

To find energy using formula,

q = mcΔT

where,

q is energy

m is mass

c is specific heat

ΔT is change in temperature

Given,

m = 7.8 kg

c = 390 J/kg

T₁ =  28°C

T₂ = 87°C

To find ΔT,

ΔT = T₂ - T₁

ΔT = 87° - 28°

ΔT = 59°C

Now, putting values,

q = mcΔT

q = 7.8 kg x 390 J/kg x 59

q = 1.79 x 10⁵ J

The best materials for sculpture are copper and copper alloys for a variety of reasons. They offer countless artistic possibilities because they can be molded into any desired shape. Copper components can be mechanically joined or assembled by bolting or bonded by welding, enabling works of enormous size.

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By using uniform motion, in 0.04 second the player will spend in the top 13.7cm .

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

hmax = 74.8 cm = 0.748 m

h = 13.7 cm = 0.137 m

g = 9.8 m/s²

Find the initial speed by using hmax (vt = 0 m/s)

vt² = vo² + 2a . s

0² = vo² - 2g . hmax

2 . 9.8 . 0.748 = vo²

vo² = 14.6608

vo = 3.83 m/s

Find the vt when h is 13.7 cm

vt² = vo² + 2a . s

vt² = 3.83² - 2g . h

vt² = 3.83² - 2. 9.8 . 0.137

vt² = 11.98

vt = 3.46 m/s

Find the time taken

vt = vo + a . t

3.46 = 3.83 - g . t

9.8t = 0.37

t = 0.04 second

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It is a physical field occupied by a charged particle on another particle in its surrounding .The magnitude of electric field will be -0.0241 MN/C.

What is electric field?

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles. Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.

The electric force in an electric field is given by the equation,

 [tex]E = \frac{F}{Q}[/tex]

Since electric field is balanced by the weight of the plastic sphere, the electric force is equal to weight of the sphere.

[tex]F = mg[/tex]

So the equation becomes

[tex]E = \frac{mg}{Q}[/tex]

Putting the value from the question,

m = 0.0074 kg

Q = (-3.0) Nc

g (gravitational acceleration) = 9.8 m/s^2

So, we get

[tex]E = \frac{(9.8)(0.0074)}{(-3.0)}[/tex]

[tex]E = -0.0241 MN/C[/tex]

Hence, the electric field is -0.0241 MN/C.

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The average velocity of the ball is - 14 m / s if it rolls from x = 10 to x = - 25 in 2.5 seconds.

We know that,

v = Δd / t

where,

v = Average velocity

Δd = Displacement

t = Time taken

Given that,

t = 2.5 sec

Δd = - 25 - 10

Δd = - 35 m

v = - 35 / 2.5

v = - 14 m / s

Average velocity is the average value of velocity from the starting point to ending point in a given amount of time.

Therefore, the average velocity of the ball is - 14 m / s

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The Law of Universal Gravitation,  states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Newton's law of gravitation, states that any particle of matter in the universe draws another with pressure varying at once as the manufactured from the loads and inversely as the rectangular.

Newton, the pressure of gravity appearing between the earth and another item is at once proportional to the mass of the earth, directly proportional to the mass of the item, and inversely proportional to the square of the distance that separates the centers of the earth and the item. Gravitational steady, G is unbiased of the nature of the particle, medium among the debris, and time. Its cost is constant anywhere within the Universe.

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The square of the distance has an adverse relationship with the electrical force.

The square of the distance has an adverse relationship with the gravitational force.

The fundamental distinction between electrostatic and gravitational forces is that gravitational force is the force that draws objects to the earth based on mass. This force is conservative. While an object's electrostatic force is its force as a result of charge. Moreover, it is a conservative force.

Electric force is the attractive or repulsive interaction between any two charged bodies. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.

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The wavelength released in transition energy is 4.23 x 10¯⁶ m.

We need to know about transition energy to solve this problem. Electrons in a hydrogen atom can move to another level of energy. It is also called a transition. In this process, electrons will absorb or release their energy to move. The transition energy can be determined as

ΔE = E2 - E1

where ΔE is transition energy, E2 is the final state of energy and E1 is the initial state of energy.

The state energy of a hydrogen atom can be calculated by

E = -(13.6) / n² eV

E = h.c / λ

where n is the number of energy states, h is Planck constant (4.136 x 10¯¹⁵ eV/Hz), c is speed of light (3 x 10⁸ m/s) and λ is wavelength.

From the question above, we know that

n1 = 5

n2 = 2

By substituting the following parameter, we get

ΔE = E2 - E1

ΔE = -(13.6) / n2² - (-(13.6) / n1²)

ΔE = -(13.6) / 2² - (-(13.6) / 5²)

ΔE = 0.544 - 0.85

ΔE = -0.306 eV

the energy is minus because it got released.

Calculate the wavelength released

ΔE = 0.306 eV

h.c / λ = 0.306 eV

4.136 x 10¯¹⁵ . 3 x 10⁸ / λ = 0.306

λ = 4.23 x 10¯⁶ m

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Dawkins says selection acts on the variations in the populations which are responsible for increasing or decreasing the fitness of the individuals carrying them.

Variation is distributed population following Mendelian genetics. Like the law of independent assortment where variations are transferred independently of each other. When blending inheritance was discarded where traits were thought to be average of that of parents of progeny , which was not the case in many cases.

One example of unconscious selection is the loss of various traits like  loss of natural dispersal mechanisms, even  and rapid seed germination, larger propagules, simultaneous ripening, and loss of mechanical protection as well as changes in the breeding system. This loss or selection on these traits while selecting for other traits like more yield and water efficiency , resistance to diseases etc. This unconscious selection associated with other selection by humans is unconscious.

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