Which are elements involved in modeling a solution? Choose all that apply. A) often includes a visual graphic B) shows the flow of information from task to task C) assigns demands D) breaks the solution into tasks E) includes pseudocode

Answers

Answer 1
Need to know how to read Circuit diagramed
Answer 2

Often includes a visual graphic, shows the flow of information from task to task, breaks the solution into tasks and includes pseudocode are elements involved in modeling a solution. Hence, options A, B, D and E are correct.

What is pseudocode?

Pseudocode is a made-up, informal language that aids in the creation of algorithms by programmers. A "text-based" detail design tool is pseudocode. The Pseudocode rules are not too complicated. Statements that demonstrate "dependence" must all be indented. Some of these are while, do, for, if, and switch.

Pseudo code: It's just a plain text document with annotations and informative text that implements an algorithm. It has no grammar like any other programming language, making it impossible for a computer to compile or interpret.

A simplified version of an algorithm that expresses coding logic in English is known as pseudocode. It enables programmers to plan the architecture of any algorithm using straightforward commands. Pseudocode describes numerous coding actions and their proper order mostly in plain English.

Thus, options A, B, D and E are correct.

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Related Questions

Read the following program requirements prior to completing the Hands-on. A retail company must file a monthly sales tax report listing the total sales for the month and the amount of state and county sales tax collected. The state sales tax rate is 4 percent and the county sales tax rate is 2 percent. Write a program that asks the user to enter the total sales for the month. The application should calculate and display the following: • The amount of county sales tax • The amount of state sales tax • The total sales tax (county plus state) Step 1: Write the steps the algorithm:

Answers

Answer:

state_sales_tax_rate = 0.04

county_sales_tax_rate = 0.02

sales = float(input("Enter the total sales for the month: "))

county_sales_tax = sales * county_sales_tax_rate

state_sales_tax = sales * state_sales_tax_rate

total_sales_tax = county_sales_tax + state_sales_tax

print("The amount of county sales tax is " + str(county_sales_tax))

print("The amount of state sales tax is " + str(state_sales_tax))

print("The total sales tax is " + str(total_sales_tax))

Explanation:

*The code is in Python.

Set the  state_sales_tax_rate and county_sales_tax_rate

Ask the user to enter the sales

Calculate the county_sales_tax, multiply sales by county_sales_tax_rate

Calculate the state_sales_tax, multiply sales by state_sales_tax_rate

Calculate the total_sales_tax, sum county_sales_tax and state_sales_tax

Print the results

After analyzing the following code, which statement is not True:
import sqlite3
connection = sqlite3.connect("aquarium.db")
a. import sqlite3 gives our Python program access to the sqlite3 module.
b. The sqlite3.connect() function returns a Connection object
c. The aquarium.db file is created automatically by sqlite3.connect() if aquarium.db does not already exist on our computer.
d. A syntax error, if aquarium.db does not already exist on our computer.

Answers

Answer:

d. A syntax error, if aquarium.db does not already exist on our computer.

Explanation:

The SQLite database is a relational database used readily in python backend web frameworks to store and retrieve data. The python packages like the sqlite3 are extensions of python proving its flexibility and power as a multi-purpose programming language.

The sqlite3 package is first installed and imported in the python file and a sqlite connection is made to the database which is automatically saved in the aquarium.db file ( created if it doesn't already exist ).

A(n) _____ website gathers, organizes, and then distributes web content.

Answers

Answer:

content aggregator

Explanation:

:)

Write a script which: Uses the input function to get any number and store it in a variable named my_number Create a new variable named calculation which equals my_number plus 9 Multiply calculation by 2 Subtract 4 from calculation Divide calculation by 2 Subtract my_number from calculation Print calculation

Answers

Answer:

# Using the input function

# Prompt the user to input some number

# Convert the input to a float - this will cater for both floating

# numbers and integers

# Store the result in a variable called my_number

my_number = float(input('Please enter some number '))

#Create a variable named calculation which equals my_number plus 9

calculation = my_number + 9

#Multiply calculation by 2

calculation *= 2

#Subtract 4 from calculation

calculation -= 4

#Divide calculation by 2

calculation /= 2

#Subtract my_number from calculation

calculation -= my_number

#Print calculation

print('calculation = ' + str(calculation))

Sample Output

>> Please enter some number 8

calculation = 7.0

Explanation:

The above program has been written in Python and it contains comments explaining each line of the code. Please go through the comments. A sample output has also been provided.

Create a cell reference in a format by typing in the cell name or

Answers

Answer:

D. Create a cell reference in a formula by typing in the cell name or clicking the cell.

Further Explanation:

To create a cell reference in a formula the following procedure is used:

First, click on the cell where you want to add formula.

After that, in the formula bar assign the equal (=) sign.

Now, you have two options to reference one or more cells. Select a cell or range of cells that you want to reference. You can color code the cell references and borders to make it easier to work with it. Here, you can expand the cell selection or corner of the border.

Again, now define the name by typing in the cell and press F3 key to select the paste name box.

Finally, create a reference in any formula by pressing Ctrl+Shift+Enter.

When visiting a museum Lian takes a photo of a painting with a smartphone which stores the photo as an image file. Which of the following best describes the differences between the painting itself and the photo of the painting stored on the smartphone? A. Both the painting and the photo are analog B. The photo is a digital representation of the analog painting C. Sampling can be used to determine whether the analog image is an accurate representation of the painting D. The phone can represent the photo in either digital or analog formats depending on the sampling technique that is used

Answers

Digital copy of the original

The best statement that best describes the differences between the painting itself and the photo of the painting stored on the smartphone is that the photo is a digital representation of the analog painting.

For better Understanding, we have to know about analog and digital terms means

Analog simply means a way of giving out information by a regular but different signal. Digital simply means a way of storing or giving out information by discrete, non regular ways.

The painting is the analog while the photo is the digital copy. the photo is a copy of the original and when you look at it, the photo is not giving continous signals like an analog.

From the above, we can therefore say that the answer that the photo is a digital representation of the analog painting is true.

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Horizontal scaling of a client/server architecture means _____.
a. migrating the network to decentralized servers.
b. migrating the network to a faster communication media.
c. adding more proxy servers.
d. adding more workstations.

Answers

Answer:

D. I think

Explanation:

Horizontal scaling of a client/server architecture means adding more workstations. Thus the correct option is D.

What is client/server architecture?

A computing model which  places the majority of the services and features that the client requests on the server, which also hosts, delivers, and manages them are known as client-server architecture 

Most applications that call for a division of labor between the client and the server benefit from the client-server architecture. The accessibility performance of applications is improved.

Both horizontal and vertical scaling is possible for client/server architectures. If a network is scaled vertically, more powerful, faster servers are added to the network, whereas horizontal scaling involves adding additional workstations (clients).

Therefore, option D is appropriate.

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Describe what each of the following functions in R do.1. t2. matplot3. c4. seq5. legend6. matrix7. rownames8. colnames9. type of

Answers

Answer:

1. t is a function used to transpose a matrix object. The object is passed as an argument to the function.

2. matplot is a graphical function in R used for data visualization.

3. The c function is used to combine arguments.

4. seq is an R function used to derive a range of numbers, optionally specifying a start, stop and step argument or simply a single numeric argument.

5. legends are used in data visualization to list and define items in the graphical presentation.

6. matrix is a function in R used to create and work with matrix and data frame objects.

7. rownames and colnames are functions used to label the row and columns of a data frame in R.

8. The typeof function return the data type of an object.

Explanation:

The R programming language is a dedicated programming language for data analysis and visualization.

Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real number representing a lower bound The second input will be a single real number representing an upper bound The return value must be a list of 200 numbers evenly spaced between the lower bound and the upper bound.

Answers

Explanation:

==================  

lin_spaced_vector.m  

==================  

function out=lin_spaced_vector(in1,in2)%defining function

out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2

end​

===================  

Executable File

===================

clear all%clears history

clc%clears screen

lin_spaced_vector(1,10)%calling function​

clear all

clc

lin_spaced_vector(1,10)

Name three actions you should take if you believe you’ve been victimized by crimeware or online fraud

Answers

Try restating system software and delete anything that may have caused the online fraud then remove all credit cards and info on the device. Tell the authorities and get a new device and email with a software protector. When doing this DO NOT DO WHAT YOU ORIGINALLY DID TO GET VICTIMIZED AND (DON'T TRY TO SIGN INTO YOUR PREVIOUS EMAIL ON A NEW DEVICE)  

Consider three different processors P1, P2, and P3 executing the same instruction set. P1 has a 3GHz clock rate and a CPI of 1.5. P2 has a 2.5GHz clock rate and a CPI of 1.0. P3 has a 4.0GHz clock rate and has a CPI of 2.2. a. Which processor has the highest performance expressed in instructions per second? b. If the processors each execute a program in 10 seconds, find the number of cycles and the number of instructions. c. We are trying to reduce the execution time by 30%, but this leads to an increase of 20% in the CPI. What clock rate should we have to get this time reduction?

Answers

Answer:

   See explanation

Explanation:

Given:

Processors:

P1  

P2

P3

Clock Rate of Processors:

Clock rate of P1 = 3 GHz

Clock rate of P2 = 2.5 GHz  

Clock rate of P3 = 4.0 GHz  

CPI of Processors:

Cycles per instruction = CPI of P1 = 1.5  

Cycles per instruction = CPI of P2 = 1.0

Cycles per instruction = CPI of P3 = 2.2

To find:

a) Which processor has the highest performance expressed in instructions per second

Solution:

Performance = clock rate / CPI  

The performance of processor depends on instructions count and CPU time.  

As we know that  

CPU time = Instructions * Cycles Per Instruction / clock rate  

CPU time = Instructions * CPI / clock rate

Instructions per second = Instruction count / CPU time  

As:    

CPU time = Instructions * CPI/ clock rate  

Instructions/CPU time = clock rate/CPI  

Instructions per second = clock rate / CPI

IPS = clock rate/ CPI  

Hence

Performance = Clock rate / CPI = clock rate/ CPI

Compute Performance of P1:

Performance for P1 = IPS of P1 = clock rate of P1 / CPI of P1 = 3 GHz / 1.5 = 2

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is  2 x 10⁹

Compute Performance of P2:

Performance for P2 = IPS of P2= clock rate of P2 / CPI of P2 = 2.5 GHz / 1.0 = 2 .5

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is  2.5 x 10⁹

Compute Performance of P3:

Performance for P3 = IPS of P3= clock rate of P3 / CPI of P3 = 4.0 GHz / 2.2 = 1.82

As we know that 1 GHz = 10⁹ Hz. So:  

Performance of P1  expressed in instructions per second is 1.82 x 10⁹

From the above computed performances of each processor it can be seen that Processor 2 (P2) has the highest performance expressed in instructions per second i.e. 2.5 x 10⁹

b) find the number of cycles and the number of instructions.

Given:

processors each execute a program in 10 seconds, So,

CPU time = 10 sec

Solution:

Compute number of cycles:

As we know that:

CPU time = cycles count / clock rate   = clock cycles/clock rate

So

clock cycles = CPU time x clock rate

Compute number of cycles of P1:

clock cycles  = 10 x 3 GHz

                     = 30

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P1 = 3 x 10¹⁰

Compute number of cycles of P2:

clock cycles  = 10 x 2.5 GHz

                     = 25

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P2 = 2.5 x 10¹⁰

Compute number of cycles of P3:

clock cycles  = 10 x 4.0 GHz

                     = 40

As we know that 1 GHz = 10⁹ Hz. So:  

clock cycles of P3 = 4 x 10¹⁰

Now as we know that:

Instructions per second = Instruction count / CPU time  

IPS = IC + CPU time

So to find number of instructions:

instruction count = Instructions per second x CPU time

Compute number of instructions of P1:

instructions of P1 = Instructions per second of P1 x CPU time

                            = 2 x 10⁹  x 10

                            = 2 x 10¹⁰

Compute number of instructions of P2:

instructions of P2 = Instructions per second of P2 x CPU time

                            = 2.5 x 10⁹  x 10

                            = 2.5 x 10¹⁰

Compute number of instructions of P3:

instructions of P3 = Instructions per second of P3 x CPU time

                            = 1.82 x 10⁹  x 10

                            = 1.82 x 10¹⁰

c) What clock rate should we have to reduce the execution time by 30%

As we know

CPU time = Execution time = instructions x CPI / clock rate

We have to find new clock rate to reduce execution time by 30%

This means we have to find:

New Execution Time = 70% of Old Execution Time

According to formula of Execution time:

instructions(new) x CPI(new) / clock rate(new) = 0.7 [instructions(old) x CPI(old) / clock rate(old)]

As the instructions(new)  = instructions(old)

So,

CPI(new) / clock rate(new) = 0.7 [CPI(old) / clock rate(old)]

When trying to reduce the execution time by 30%, this leads to an increase of 20% in the CPI.

CPI(new) = 1.2 CPI(old)

New CPI of P1:

CPI(new P1) = 1.2 CPI(old P1)

                    = 1.2 x 1.5

CPI(new P1) = 1.8

New CPI of P2:

CPI(new P2) = 1.2 CPI(old P2)

                    = 1.2 x 1.0

CPI(new P2) = 1.2

New CPI of P3:

CPI(new P3) = 1.2 CPI(old P3)

                    = 1.2 x 2.2

CPI(new P3) = 2.6

1.2 / clock rate (new) = 0.7 / clock rate(old)

So new clock rate is computed as:

clock rate (new)  = (1.2 / 0.7 ) x clock rate(old)

clock rate (new)  = 1.71 x clock rate(old)

clock rate (new)  = 1.71 x clock rate(old)

Hence the clock rate should be increased by 71% approx.

Now new clock rate for each processor is:

clock rate (new) for P1 = 3 GHz x 1.71     = 5.13 GHz

clock rate (new) for P2 = 2.5 GHz x 1.71 = 4.27 GHz

clock rate (new) for P3 = 4.0 GHz x 1.71 = 6.84 GHz  

In this exercise we have to use CPU and processor knowledge, so we can say that:

A)Processador 2

B) Processador 3

C) Processador 3

From the information given in the text we have:

Clock rate of P1 = 3 GHz Clock rate of P2 = 2.5 GHz   Clock rate of P3 = 4.0 GHz   CPI of P1 = 1.5   CPI of P2 = 1.0 CPI of P3 = 2.2

a) With the formula bellow, we find:

[tex]Performance = clock \ rate / CPI[/tex]

The performance of processor depends on instructions count and CPU time.  

Compute Performance of P1:

[tex]P= 3 GHz / 1.5 = 2*10^9[/tex]

Compute Performance of P2:

[tex]P = 2.5 GHz / 1.0 = 2 .5*10^9[/tex]

Compute Performance of P3:

[tex]P = 4.0 GHz / 2.2 = 1.82 *10^9[/tex]

b) Processors each execute a program in 10 seconds, So:

P1:

[tex]10 * 3 GHz = 30*10^{10}[/tex]

P2:

[tex]10 * 2.5 GHz= 25*10^{10[/tex]

P3:

[tex]10 * 4.0 GHz = 40*10^{10[/tex]

c) So for reduce we have:

New CPI of P1:

[tex]CPI = 1.2 CPI = 1.2 * 1.5CPI = 1.8[/tex]

New CPI of P2:

[tex]CPI= 1.2 CPI = 1.2 * 1.0\\CPI= 1.2[/tex]

New CPI of P3:

[tex]CPI= 1.2 CPI = 1.2 *2.2\\CPI = 2.6[/tex]

Now new clock rate for each processor is:

[tex]clock rate (new) for P1 = 3 GHz x 1.71 = 5.13 GHz\\clock rate (new) for P2 = 2.5 GHz x 1.71 = 4.27 GHz\\clock rate (new) for P3 = 4.0 GHz x 1.71 = 6.84 GHz[/tex]

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what is the function of control unit? in computer.

Answers

regulates and integrates the operations of the computer. It selects and retrieves instructions from the main memory in proper sequence and interprets them

What is hardware?
O All elements of a computer
O The parts of a computer that you can touch
O Wooden planks sold in a hardware store
The parts of software that you can't see​

Answers

The answer would be the first option, all elements of a computer

2. Which of the following is a
Web 2.0 programming
methodology you could use to
create Web pages that are
dynamic and interactive without
the need to refresh or
reload the page?
a. Wiki
b. RSS
c. Blog
d. Ajax

Answers

The correct answer would be ajax

Answer:ajax

Explanation:

Are scripted languages easier or more difficult to port than programming languages? Why?

Answers

Answer:

Scripting languages are easier to port to various platforms due to the compiling and interpreting tools it uses to read the source code.

Explanation:

Programming languages are used to create source codes for various applications from web programming to mobile application implementation.

A programming language can be a scripting language, only with the required tools like a compiler or an interpreter. For example, C source codes are compiled to executable scripting file with the GCC compiler and python codes are interpreted with the cpython interpreter.

How many different values can be stored in a byte?

Answers

Answer:

255

Explanation:

1 byte has 8 bits, that is, 8 combinations of binary inputs, which can result in calculations up to the number 2 ^ 8-1 = 255 (-1 because 0 will always be the first number), a computer nowadays has 64 bits (8bytes ), thus being able to calculate numbers up to 2 ^ 64-1, an integer file has 4 bytes, being able to calculate up to 2 ^ 32-1, and so on.

Which WPA mode allows users to provide authentication via a pre-shared key or password?

Answers

Answer:

WPA2 allows users to provide authentication via a pre-shared network key / password

Explanation:

The WPA mode that allows users to provide authentication via a pre-shared key or password is the personal mode. The correct option is a.

What is WPA mode?

The most recent and secure Wi-Fi protocol at the moment is WPA3 Personal. A pre-shared key is used by Personal WPA to verify users' first login information.

Wi-Fi security access All users on 2 pre-shared key (WPA-PSK) networks use the same passphrase. A security standard for computing devices using wireless internet connections is called Wi-Fi Protected Access (WPA).

It was created by the Wi-Fi Alliance to provide stronger user authentication and data encryption than the original Wi-Fi security standard, Wired Equivalent Privacy (WEP).

Therefore, the correct option is a. Personal mode.

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The question is incomplete. Your most probably complete question is given below:

a. Personal mode

b. Enterprise mode

c. Extensible Authentication Protocol mode

d. Wired Equivalent Privacy mode

Write a program that converts a time in 12-hour format to 24-hour format. The program will prompt the user to enter a time in HH:MM:SS AM/PM form. (The time must be entered exactly in this format all on one line.) It will then convert the time to 24 hour form. You may use a string type to read in the entire time at once, including the space before AM/PM, or you may choose to use separate variables for the hours, minutes, seconds and AM/PM.

Answers

Answer:

This program is written in Python

inputtime = input("HH:MM:SS AM/PM: ")

splittime = inputtime.split(":")

secondAM = splittime[2].split()

if secondAM[1] == "AM":

   print(splittime[0]+":"+splittime[1]+":"+secondAM[0])

elif secondAM[1] == "PM":

   HH = int(splittime[0])

   HH = HH + 12

   print(str(HH)+":"+splittime[1]+":"+secondAM[0])

   

Explanation:

This line prompts user for input

inputtime = input("HH:MM:SS AM/PM: ")

This line splits the input string to HH, MM and "SS AM/PM"

splittime = inputtime.split(":")

This line splits "SS AM/PM" to SS and AM/PM

secondAM = splittime[2].split()

This line checks if time is AM

if secondAM[1] == "AM":

This line prints the equivalent time

   print(splittime[0]+":"+splittime[1]+":"+secondAM[0])

Else;

elif secondAM[1] == "PM":

The equivalent 24 hour is calculated

   HH = int(splittime[0]) + 12

This line prints the equivalent time

   print(str(HH)+":"+splittime[1]+":"+secondAM[0])

A WHILE loop can be constructed with a CMP instruction at the bottom of the loop, followed by a conditional jump instruction.

a) true

b) false

Answers

Answer:

false

Explanation:

If the condition is false at the start, the contents of the loop should never be executed. If the CMP is at the end, you cannot prevent the code to run at least once. So this approach will work for a DO { ... } WHILE() loop, but not for a regular WHILE() { ... }

Where does the CPU store its computations?
A. Registers
B. External Data Bus
C. Binary
D. Processor

Answers

Answer: A. Registers

Explanation:

Option A is correct. The CPU stores its computations in the Registers

The CPU is known as the Central Processing Unit.

The CPU is useful in reading data and instructions from memory and then stores the results of what was computed in its main memory.

This computation in the main memory is usually stored in the Register.

Hence we can conclude that the CPU store its computations in the Register.

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_____ is the operation of setting a variable to a value.

Answers

Answer:

Assignment is the operation of a variable to a value

Consider the definition in OCaml
let fabcd = a.(if b then c else d)
Which of the following must hold (zero, one or more answers can be correct)?
A. The type of a is int array.
B. The type of b is bool.
C. The type of c is int.
D. The type of d is int.
E. The return type of f is int.

Answers

Answer:

The type of b is bool ( B )

The type of c is int ( C )

The type of d is int ( D )

Explanation:

The options that must hold zero are: The type of b is bool,The type of d is int and The type of c is int.

If b is true then c or d is true because c and d are int. this is because b been a true/false means that d and c are boolean int. because d and c are assigned to integers  

The statements that must hold are:

b. The type of b is bool c. The type of c is int d. The type of d is int

The definition is given as:

let fabcd = a.(if b then c else d)

From the above definition, we have the following if condition

if b then c else d

This means that:

Variable b can only take either true or false, as its value.

So, b is of Boolean type

Variables c and d can take any numerical data type such as int, floats, and any character type such as char and string.

This means that:

Options (c) and (d) can also hold.

Hence, the true options are: (b), (c) and (d)

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Which does a traditional camera need in order to capture images?
A. secure digital (SD) card B. printer C. scanner D. film

Answers

Answer:

I think secure digital is needed

Answer:

Film

Explanation:

I chose Film and got it correct

Consider the following algorithm: ```c++ Algorithm Mystery(n) { // Input:A nonnegative integer n S = 0; for i = 1 to n do { S = S + i * i; } return S } ``` 1. What does this algorithm compute? 2. What is its basic operation? 3. How many times is the basic operation executed? 4. What is the efficiency class of this algorithm? 5. Suggest an improvement, or a better algorithm altogether, and indicate its efficiency class. If you cannot do it, try to prove that, in fact, it cannot be done.

Answers

Answer:

See explanation

Explanation:

First let us find what this algorithm compute:

Algorithm Mystery(n) {

        S = 0;

        for i = 1 to n do

             { S = S + i * i; }

         return S }

1)

Let suppose n = 3

S = 0

The algorithm has a for loop that has a loop variable i initialized to 1

At first iteration:

i = 1

S = S + i * i;

   = 0 + 1 * 1

S = 1

At second iteration:

i = 2

S = 1

S = S + 2 * 2;

   = 1 + 2 * 2

   = 1 + 4

S = 5

At third iteration:

i = 3

S = 5

S = S + 3 * 3;

   = 5 + 3 * 3

   = 5 + 9

S = 14

Now the loop breaks at i=4 because loop iterates up to n and n =3

So from above example it is clear that the algorithm computes the sum of squares of numbers from 1 to n. Or you can say it compute the sum of first n squares.  Let us represent this statement in mathematical form:

∑[tex]\left \ {{n} \atop {i=1}} \right.[/tex] i²

2)

From above example we can see that the basic operation is multiplication. At every iteration loop variable i is multiplied by itself from 1 to n or till n times. However we can also say that addition is the basic operation because at each iteration the value of S is added to the square of i. So it takes the same amount of time.

3)

In the for loop, the basic operation executes once. We can say that at each iteration of the loop, multiplication is performed once. Suppose A(n) represents the number of times basic operation executes then,

A(n) = ∑[tex]\left \ {{n} \atop {i=1}} \right.[/tex] 1 = n

4)

Since for loop executes once for each of the numbers from 1 to n, so this shows that for loop executes for n times. The basic operation in best, worst or average case runs n times. Hence the running time of Θ(n) . We can say that A(n) = n ∈ Θ(n)  

If b is the number of bits needed to  represent n then

b = log₂n + 1

b = log₂n

So

n ≈ [tex]2^{b}[/tex]

A(n) ≈ [tex]2^{b}[/tex] ≈ Θ( [tex]2^{b}[/tex] )  

5)

One solution is to calculate sum of squares without using Θ(n) algorithm.  So the efficient algorithm that takes less time than the previous algorithm is:

Algorithm Mystery(n) {

        S = 0;

        S = (n * ( n + 1 ) (2n + 1) ) / 6 ;

        return S}

Now the sum can be calculated in Θ(1)  times. This is because regardless of the size and number of operands/operations, the time of arithmetic operation stays the same. Now lets find out how this algorithm works for

n = 3

S = (n * ( n + 1 ) (2n + 1) ) / 6 ;

 = (3 * ( 3 + 1 ) * (2(3) + 1) ) / 6

 = (3 * (4) * (6+1)) / 6

= (3 * (4) * (7)) / 6

= (3 * 4 * 7) / 6

= 84 / 6

S = 14

Write a Java program to count the characters in each word in a given sentence?Examples:Input : geeks for geeksOutput :geeks->5for->3geeks->5

Answers

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    Scanner in = new Scanner(System.in);

   

    System.out.print("Enter a sentence: ");

    String sentence = in.nextLine();

   

    String[] words = sentence.split("\\s");

   

    for(String s : words)

     System.out.println(s + " -> " + s.length());

}

}

Explanation:

Ask the user to enter a sentence

Get each word in the sentence using split method and put them in words array

Loop through the words. Print each word and number of characters they have  using the length method in required format

Explain the basic method for implementing paging.

Answers

Answer:

The answer is below

Explanation:

In order to carry out the basic method for implementing paging, the following processes are involved:

1. Both physical and logical memories are broken into predetermined sizes of blocks otherwise known as FRAMES and PAGES respectively

2. During processing, Pages are loaded into the accessible free memory frames from the backing store. The backing store is however compartmentalized into predetermined sizes of blocks whose size is equal to the size of the memory frames

What is the range of possible values for the variable x?

int x = (int)(Math.random() * 10);

Answers

Answer:

int number = (int)(Math. random() * 10); By multiplying the value by 10, the range of possible values becomes 0.0 <= number < 10.0

please mark me as the brainliest answer and please follow me for more answers.

Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B travels south at an average speed of y miles per hour. Write a program that prompts the user to enter: The average speed of both the cars The elapsed time (in hours and minutes, separated by a space) Ex: For two hours and 30 minutes, 2 30 would be entered

Answers

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

Write code to assign the number of characters in the string rv to a variable num_chars.

Answers

Answer:

rv = "hello"

num_chars = len(rv)

print(num_chars)

Explanation:

*The code is in Python.

Initialize the string rv, in this example I set it to "hello"

Use the len() method to get the number of characters in the rv and set it to the num_chars

Print the num_chars

Note that the result will be 5 in this case, because hello consists of five characters

Scenario2: Now suppose the LAN must support both voice and data and you must choose one of these multiple access strategies in order to support both applications on the same network, with the understanding that voice calls are more important than data. Which would you choose and why? How would voice and data be sent in this scenario? That is, which access protocol would you use, or adapt/modify, and why?

Answers

Answer:

The RTP (real time protocol) which uses the UDP ( user datagram protocol) and Real-time control protocol.

Explanation:

The RTP of a voice over IP protocol (VoIP) which is used to prioritise the transfer of video and audio data over text data. It is used for video conferencing and telephony services in an enterprise.

It uses the user-datagram protocol to transfer or access videos and audio data for its real time effect and the real-time control protocol for quality of service analysis and maintenance.

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