Which combination of characteristics produces the LEAST energetic waves?
.
A. short wavelength, low frequency
B. short wavelength, high frequency
C. long wavelength, low frequency
D. long wavelength, high frequency

Answer:

[tex]V_0[/tex]

Explanation:

Given that, the range covered by the sphere, [tex]M[/tex], when released by the robot from the height, [tex]H[/tex], with the horizontal speed [tex]V_0[/tex] is [tex]D[/tex] as shown in the figure.

The initial velocity in the vertical direction is [tex]0[/tex].

Let [tex]g[/tex] be the acceleration due to gravity, which always acts vertically downwards, so, it will not change the horizontal direction of the speed, i.e. [tex]V_0[/tex] will remain constant throughout the projectile motion.

So, if the time of flight is [tex]t[/tex], then

[tex]D=V_0t\; \cdots (i)[/tex]

Now, from the equation of motion

[tex]s=ut+\frac 1 2 at^2\;\cdots (ii)[/tex]

Where [tex]s[/tex] is the displacement is the direction of force, [tex]u[/tex] is the initial velocity, [tex]a[/tex] is the constant acceleration and [tex]t[/tex] is time.

Here, [tex]s= -H, u=0,[/tex] and [tex]a=-g[/tex] (negative sign is for taking the sigh convention positive in [tex]+y[/tex] direction as shown in the figure.)

So, from equation (ii),

[tex]-H=0\times t +\frac 1 2 (-g)t^2[/tex]

[tex]\Rightarrow H=\frac 1 2 gt^2[/tex]

[tex]\Rightarrow t=\sqrt {\frac {2H}{g}}\;\cdots (iii)[/tex]

Similarly, for the launched height [tex]2H[/tex], the new time of flight, [tex]t'[/tex], is

[tex]t'=\sqrt {\frac {4H}{g}}[/tex]

From equation (iii), we have

[tex]\Rightarrow t'=\sqrt 2 t\;\cdots (iv)[/tex]

Now, the spheres may be launched at speed [tex]V_0[/tex] or [tex]2V_0[/tex].

Let, the distance covered in the [tex]x-[/tex]direction be [tex]D_1[/tex] for [tex]V_0[/tex] and [tex]D_2[/tex] for [tex]2V_0[/tex], we have

[tex]D_1=V_0t'[/tex]

[tex]D_1=V_0\times \sqrt 2 t[/tex] [from equation (iv)]

[tex]\Rightarrow D_1=\sqrt 2 D[/tex] [from equation (i)]

[tex]\Rightarrow D_1=1.41 D[/tex] (approximately)

This is in the [tex]3[/tex] points range as given in the figure.

Similarly, [tex]D_2=2V_0t'[/tex]

[tex]D_2=2V_0\times \sqrt 2 t[/tex] [from equation (iv)]

[tex]\Rightarrow D_2=2\sqrt 2 D[/tex] [from equation (i)]

[tex]\Rightarrow D_2=2.82 D[/tex] (approximately)

This is out of range, so there is no point for [tex]2V_0[/tex].

Hence, students must choose the speed [tex]V_0[/tex] to launch the sphere to get the maximum number of points.

Free fall motion is motion in which the only force acting on the body is gravity

The student should launch the sphere at 2·v₀, for the sphere will land at approximately 1.41·D, which is in the 3 point zone

The given parameter are;

The distance covered by the sphere when launched at height, H = D

The velocity with which the ball reaches D = v₀

The current available height of launcher= H/2

The available velocities = v₀, and 2·v₀

Solution:

From H = u·t + (1/2)·g·t², where, initial velocity of the vertical motion of the ball, u = 0 we have;

H = (1/2)·g·t²

∴ The time it takes the ball to drop from H, t = √(2·H/g)

The distance, D = v₀ × √(2·H/g)

When the height is H/2, we get;

t = √(2·H/(2·g)) = √(H/g)

The distance covered, D₁ = v₀ × √(H/g)

Therefore, D = (√2) × v₀ × √(H/g) = (√(2))·D₁

D₁ = D/(√2) ≈ 0.71·D

D₁ ≈ 0.71·D

At speed 2·v₀, we have;

D₂ = 2·v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2·H/g) = √2·D₁ ≈ 1.41·D

D₂ ≈ 1.41·D

The 2 point zone = D/2 < x < D = 0.5·D < x < D (Position D₁ ≈ 0.71·D is located here)

The 3 Point Zone =  D < x < 3·D/2 = D < x < 1.5·D (Position D₂ ≈ 1.41·D is located here)

Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2·v₀, so that the ball will land at D₂ ≈ 1.41·D,  which is in the 3 Point Zone

Learn more about free fall motion here:

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Answer:

d. tropical

Explanation:

Tropical climates are characterized by constant high temperatures

Answer: 7.27 m/s

Explanation:

Answer:

Explanation:

Composite volcanoes, also called stratovolcanoes, are cone-shaped volcanoes built from many layers of lava, pumice, ash, and tephra. A lava dome is a circular mound-shaped protrusion resulting from the slow extrusion of viscous lava from a volcano. A shield volcano is a type of volcano usually composed almost entirely of fluid lava flows. It is named for its low profile, resembling a warrior's shield lying on the ground. A cinder cone is a steep conical hill of loose pyroclastic fragments, such as either volcanic clinkers, volcanic ash, or cinder that has been built around a volcanic vent.

Explanation:

solution ,

[tex]a = 9.8m \div {s}^{2} [/tex]

[tex]f = 22 \: newton[/tex]

[tex] M= \: ?[/tex]

Now,

f=Ma

or,

f/a=M

or,

22/9.8=M

or,

2•24=M

or,

M=2.24kg

Answer:

Sound energy (that is, mechanical vibrational waves passing through an elastic medium) is a combination of kinetic and potential energies. As the wave compresses the medium (storing elastic potential energy) the medium comes to rest (no motion so no kinetic energy).

Explanation:

Hope this helps :D

Answer:

the answer is 234 cm is 2.34 meters

Answer:

metallic movement when u heat up metal it get bigger

Explanation:

let's say u had metal ball with a metal ring u heat the metal ball up it won't fit in the ring

Answer:

1 high electrical conductivity and high melting point

Answer:

b. Rollerblading.

Explanation:

Rollerblading involves balances.

Answer:

I would love to be a gardener :)

Explanation:

Plants are kool!!!

Answer:

Explanation:

There are three compositional layers into which the earth is divided into, these are

The core.

The mantle.

The crust.

There are five physical layers into which the earth is divided, these are

The Lithosphere, 40 - 140 km into the earth

The Mesosphere, 50 - 100 km above the earth.

The Asthenosphere, below the lithosphere, 80 - 200 km into the earth.

The Inner Core.

The Outer Core, 2890 km below the earth

Answer:

920 kg

Explanation:

[tex]kinetic \: energy = 222640j \\ \frac{1}{2} mv {}^{2} = 222640 \\ \frac{1}{2} m(22) {}^{2} = 222640 \\ m = 920kg[/tex]

Answer:

A hypothesis is a testable statement, and a theory is well-supported explanation.

Answer:

1.86 m

Explanation:

First, find the time it takes to travel the horizontal distance.  Given:

Δx = 52 m

v₀ = 26 m/s cos 31.5° ≈ 22.2 m/s

a = 0 m/s²

Find: t

Δx = v₀ t + ½ at²

52 m = (22.2 m/s) t + ½ (0 m/s²) t²

t = 2.35 s

Next, find the vertical displacement.  Given:

v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s

a = -9.8 m/s²

t = 2.35 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13.6 m/s) (2.35 s) + ½ (-9.8 m/s²) (2.35 s)²

Δy = 4.91 m

The distance between the ball and the crossbar is:

4.91 m − 3.05 m = 1.86 m

Explanation:

the speed of sound depends on the particles of the medium of the sound wave is moving through because the particles in the solid and tightly packed together South Wales weekly transfers energy from particle to particle in a solid

=======================================================

Work Shown:

r = radius = 1.045 cm

h = height = 30.48 cm

pi = 3.141 approximately

V = volume of cylinder

V = pi*r^2*h

V = 3.141*(1.045)^2*30.48

V = 104.547940002

V = 104.5 cubic cm

Explanation:

Answer:

A. The paper airplane’s motion is due to horizontal inertia and the vertical pull of gravity.

Explanation:

Got it right on edge.

Energy transfer, and transformation.

It is when energy changes from one form to another.

Hope This Helps, Good Luck!

Answer:

Where are the measurements?

Explanation:

We can measure the length of the swimming pool by using the SI unit meter, as the length of the swimming pool comes under the fundamental measurement of the dimension which is measured by the standardized international unit of length.

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

There are three additional units and 7 SI basic units in this system of SI units, the base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole.

As given in the problem we have to find how can we measure the length of the swimming pool,

Due to the fact that the length of the swimming pool falls under the category of a dimension that is fundamentally measured using a standardized international unit of length.

Thus, we can measure the length of the swimming pool by using the SI unit meter,

Learn more about the unit of measurement from here,

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Your question seems incomplete the complete question is,

Which SI units would you use for the following measurements?

the length of a swimming pool

see this picture please mark brainlist

Answer:

7 m

Explanation:

They began walking 6 meters to the right, so +6.

Then 3 meters left so -3,

And then 4 meters to the right again so +4.

4+6-3=7 meters

Answer:

e and b

Explanation:

Answer:

D,E

Explanation:

thats what I would say because PE is the energy stored in an object

Answer: 1,562.5 Km

Explanation: If it takes one hour to travel 625 kilometers, then, in two and a half hours, you should travel 1,562.5 Kilometers because of 625x2.5=1562.5 kilometers

Answer:

meters, yards or feet

Explanation:

Answer:

5m/s

Explanation:

If you do 90-40 (the two distances the problem gave) which will give you 50 meters, and then 15-5 (the two times given) which will give you 10. All you do after that is divide your new found distance with your new time 50/10 and boom chicken soup you got your final answer of 5 m/s :)

We have that The cars displacement is

d=50m

The magnitude of the average velocity is

Avg V=2.5m/s

From the question we are told

A car travels 90 meters due North in 15 seconds. The car turns around and travels 40 meters due south in 5 seconds. What is the magnitude of the average velocity of the car during this 20-second interval

Generally the equation for the Total displacement  is mathematically given as

d=initial displacement -final displacement

Therefore

d=90-40

d=50m

Generally the equation for the average velocity  is mathematically given as

[tex]Avg V=\frac{m}{s}\\\\Avg V=\frac{50}{20}[/tex]

Avg V=2.5m/s

Therefore

The cars displacement is

d=50m

The magnitude of the average velocity

Avg V=2.5m/s

For more information on this visit

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Answer:

1.5 m

Explanation:

a = v/t

a = 2/1,5 = 4/3

x = 1/2 a t² + vt + x

x = 1/2 × 4/3 × 9/4 = 3/2 = 1.5 m