Which expession is equivalent to -3(6c + 2) + 5c

[tex]answer \\ 9 \\ please \: see \: the \: attached \: picture \: for \: full \: solution \\ hope \: it \: helps[/tex]

Answer:

9

Step-by-step explanation:

The ratio of 5 to 5+3 is equivalent to the ratio of 15 to 15+x. This is because when you have a triangle inside of a triangle and both of them share two of the same sides and the third sides are parallel to each other, the side ratios of the triangles are always proportionate.

[tex]\frac{5}{5+3} =\frac{15}{15+x}[/tex]   Starting equation

[tex]\frac{5}{8} =\frac{15}{15+x}[/tex]   Simplify

[tex]5(15+x)=8*(15)[/tex]   Cross multiply

[tex]75+5x=120[/tex]   Distributive Property on left and simplify on right

[tex]5x=45[/tex]   Isolate the variable

[tex]x=9[/tex]   Divide both sides by 5 (Division Property of Equality)

Answer:

Step-by-step explanation:

The measure of an arc is twice the measure of the inscribed angle that subtends that arc. A tangent is a special case where the chord that is one leg of the inscribed angle has a length of zero.

1. Short arc LJ is 2a°. Short arc LK is 2b°. Then arc JLK is 2(a+b)°, and short arc JK is ...

  arc JK = 360° -2(a +b)° . . . . . matches choice B

__

2. Long arc WY is twice the measure of "inscribed" angle WYZ, so is ...

  long ard WY = 2(104°) = 208°

Then short arc WY is ...

  arc WXY = 360° -208° = 152°

__

3. The arc measures are double those of the corresponding inscribed angles. We can add up the arcs around the circle:

  (arc AB +arc BC) = 2×70° = 140° . . . inscribed angle relation

  (arc BC +arc CD) = 2×98° = 196° . . . inscribed angle relation

  arc AB + arc BC +arc CD +arc DA = 360° . . . . sum around the circle

Adding the first two equations with arc DA, we have ...

  (arc AB + arc BC) +(arc BC +arc CD) +arc DA = 360° +arc BC

  140° +196° +80° = 360° +arc BC

  416° -360° = arc BC = 56° . . . . . matches choice B

__

4. Angle C and angle A are supplementary in this inscribed quadrilateral.

  angle C = 180° -98° = 82° . . . . . matches choice A

Answer:

$932.92

Step-by-step explanation:

6.5% = 0.065

(875.98) + (875.98)(0065)

(875.98) + (56.9387)

932.9187

$932.92

Answer:

$[tex]932.92[/tex]

Step-by-step explanation:

[tex]6.5/100=0.65[/tex]

Next, multiply the price by the sales tax.

[tex]875.98*0.65=56.94[/tex]

Then, add.

[tex]875.98+ 56.94=932.92[/tex]

$[tex]932.92[/tex] is the total cost of the laptop.

Answer:

D.

Step-by-step explanation:

Since a quadrilateral inscribed in a circle has its opposite angles adding up to 180°

So,

<MNO + <OLM = 180

82 + <OLM = 180

<OLM = 180-82

<OLM = 98°

Answer:

/-37/, /-24/, /-6/, /2/, /18/, /23/

Answer:

Which earns more interest = Account B

How much more = $1,306.60

Step-by-step explanation:

Given;

Principal P = $2,000

Interest rate r = 5% = 0.05

Time t = 20 years

For account A;

Simple interest = P×r×t

Substituting the values;

Simple interest = 2,000 × 0.05 × 20 = $2000

Interest on account A = $2,000

For account B;

Compound interest

Final amount = P(1 + r)^t

Since it's compounded annually

Substituting the values;

Final amount = 2000(1+0.05)^20

Final amount = $5306.60

Interest = final amount - principal = $5306.60 -$2000

Interest = $3,306.60

Therefore, account B earns more interest.

Difference = account B interest - account A interest

Difference = $3,306.60 - $2,000

Difference = $1,306.60

Answer:

its b I belive

Step-by-step explanation:

Answer:

The answer is B.

Step-by-step explanation:

In order to find (f-g)(x), you have to subtract g(x) from f(x) :

[tex]f(x) = {3}^{x} + 10[/tex]

[tex]g(x) = 2x - 4[/tex]

[tex](f - g)(x) = {3}^{x} + 10 - 2x - ( - 4)[/tex]

[tex](f - g)(x) = {3}^{x} + 10 - 2x + 4[/tex]

[tex](f - g)(x) = {3}^{x} - 2x + 14[/tex]

Answer:

see explanation

Step-by-step explanation:

The n th term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

(a)

Given a₁ = - 2 and a₄ = 16, then

a₁ + 3d = 16 , that is

- 2 + 3d = 16 ( add 2 to both sides )

3d = 18 ( divide both sides by 3 )

d = 6

--------------

(b)

Given

[tex]a_{n}[/tex] = 11998 , then

a₁ + (n - 1)d = 11998 , that is

- 2 + 6(n - 1) = 11998 ( add 2 to both sides )

6(n - 1) = 12000 ( divide both sides by 6 )

n - 1 = 2000 ( add 1 to both sides )

n = 2001

------------------

Answer:

10

-5

Step-by-step explanation:

5 - -5

Subtracting a negative is like adding

5+5 = 10

-9 - -4

-9+4

-5

Answer:

Step-by-step explanation:

5+5 = 10

-9+4 = -5

Answer:

your answer is 127596 because you would take (45+2) first then you would take (55^2+10s+3) then you multiply them

Step-by-step explanation:

Answer:

10% probability that both the bus and train will be more than 5 minutes late

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, we have that:

[tex]P(A \cap B) = P(A)*P(B)[/tex]

What is the probability that both the bus and train will be more than 5 minutes late?

The bus being more than 5 minutes late is independent of the train, and vice versa. So

Event A: Bus more than 5 minutes late

Event B: Train more than 5 minutes late

The train is more than 5 minutes late 1/6 of the times they use it

This means that [tex]P(B) = \frac{1}{6}[/tex]

The bus is more than 5 minutes late 3/5 of the times they use it.

This means that [tex]P(A) = \frac{3}{5}[/tex]

Then

[tex]P(A \cap B) = \frac{3}{5}*\frac{1}{6} = \frac{3}{30} = 0.1[/tex]

10% probability that both the bus and train will be more than 5 minutes late

Answer:

Hey mate , here is your answer. Hope it helps you

Step-by-step explanation:

Given Zareen has 24min to work on her math homework, and each problem is taking her 2/3 of a minute

As give one problem takes

24*(2/3) minutes = 16

Hence

2/3 divided by 24

Answer:

144

Step-by-step explanation:

Answer:

116

Step-by-step explanation:

3x4=12

12x4=48

8x4=32

32-3=29

29x4=116

Hope it's clear

Answer:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Step-by-step explanation:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Answer:

your number should be 8

Step-by-step explanation:

5x+(-3)=37

5x-3=37

+3       +3

5x=40

÷5  ÷5

x=8

hope this helps

Answer:

The answer is 8.

5x-3=37

5x=37+3

5x=40

x=40/5

x=8

HOPE IT HELPS!!

Answer:

[tex]9\dfrac{5}{6}[/tex]

Step-by-step explanation:

[tex]5\dfrac{1}{6}+4\dfrac{2}{3}=\\\\5\dfrac{1}{6}+4\dfrac{4}{6}=\\\\9\dfrac{5}{6}[/tex]

Hope this helps!

Answer:

I made is clear for you, now you may match each one

Step-by-step explanation:

f(1)= 11, f(n)= 3*f(n-1)

⊕ middle

f(1)= -18, f(n)= f(n-1)+21

f(1)= -18, f(n)= f(n-1) + 22

f(1)= -18, f(n)= 2*f(n-1)

⊕ bottom

f(1)= -18, f(n)= 6*f(n-1)

⊕ top

f(1)= 11, f(n)= f(n-1) + 22

Answer:

Probability that one of the giftcards will go to a student athlete and one will go to a freshman = 26.4%

Step-by-step explanation:

At Central High School, 55% of students play a school sport. Also, 24% of the student population is in ninth grade. No ninth graders are allowed to play school sports. If two students are selected at random to receive a gift card, what is the probability that one will go to a student athlete and one will go to a freshman? Write the answer as a percent rounded to the nearest tenth of a percent.

Solution

Probability that a student plays a school sport, that is, probability that a student is a student athlete = P(S) = 55% = 0.55

Probability that a student is in the ninth grade, that is, probability that a student is a freshman = P(F) = 24% = 0.24

It was given that no freshman is allowed to play sports, hence, it translates that the event that a student is a student athlete and the event that a student is a freshman are mutually exclusive.

P(S n F) = 0

If two students are then picked at random to receive a gift card, we require the probability that one will go to a student athlete and one will go to a freshman.

Probability that the first one goes to a student athlete = P(S) = 0.55

Probability that the second one goes to a freshman ≈ 0.24

Probability that the first one goes to a freshman = P(F) = 0.24

Probability that the second one goes to a student athlete ≈ 0.55

Probability that one will go to a student athlete and one will go to a freshman

= (0.55 × 24) + (0.24 × 0.55)

= 0.132 + 0.132

= 0.264

= 26.4% in percent to the nearest tenth.

Hope this Helps!!

Answer: 5 (estimate)

Step-by-step explanation:

x - 17 4/5 = -13 1/5

Estimate:  x - 18 = -13

x - 18 + 18 = -13 + 18

x = 5

actual answer without estimating using exact numbers is 4 3/5 (so estimate is reasonable)

Answer:

  84°

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary:

  ∠A = 180° -96°

  ∠A = 84°

Answer:

19.2

Step-by-step explanation:

It's right on Acellus.

The required value of x nearest to tenth is 19.17

The longest side of the right angled triangle is called hypotenuse

By the Pythagoras theorem in the right angled triangle

h^2 = b^2 + p^2

where h = hypotenuse, b = base, p = perpendicular

Here we have given perpendicular p = 9

and an angle = 28°

Using sin for the given angle we have

sin 28° = [tex]\frac{perpendicular}{hypotenuse}[/tex]

0.46947 = [tex]\frac{9}{x}[/tex]

x = [tex]\frac{9}{0.46947}[/tex]

x =  19.17

Hence the required length of the side hypotenuse = x = 19.17

This is the conclusion to the answer.

Learn more about hypotenuse here-

https://brainly.com/question/2217700

#SPJ2

Answer:

27/(4x^6y^8)

Step-by-step explanation:

Target the variables first. (x^a)^b is the same as x^(a x b).

In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.

Same principle on the bottom. the denominator is x^12 and y^20.

In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

[tex]\frac{dV}{dt}=15ft^3/min[/tex]

We have to find the increasing rate of change of height of pile  when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r=[tex]\frac{d}{2}=\frac{h}{2}[/tex]

Volume of pile=[tex]\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3[/tex]

[tex]\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}[/tex]

h=12 ft

Substitute the values

[tex]15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}[/tex]

[tex]\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}[/tex]

[tex]\frac{dh}{dt}=0.13ft/min[/tex]

Answer:

10-19 ⇒ 3

50-59 ⇒ 4

Answer:

# of ties    # of racks

 10-19               3

50-59              4

Step-by-step explanation:

Using the Stem and Leaf plot, our data is:

11, 12, 16

21

32, 34, 36, 37, 39

41, 45

51, 52, 53, 56

# of ties    # of racks

 10-19               3 (11, 12, 16)

50-59              4 (51, 52, 53, 56)

Answer:

a) From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data so then that would be the answer for this case.

b) [tex] z=\frac{96.97-98.19}{0.61}=-2[/tex]

[tex] z=\frac{99.41-98.19}{0.61}=2[/tex]

And within 2 deviations from the mean we have 95% of the values.

Step-by-step explanation:

For this case we know that the distribution of the temperatures have the following parameters:

[tex] \mu = 98.19, \sigma =0.61[/tex]

Part a

From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data so then that would be the answer for this case.

Part b

We can calculate the number of deviations from the mean with the z score with this formula:

[tex]z=\frac{X -\mu}{\sigma}[/tex]

And using this formula we got:

[tex] z=\frac{96.97-98.19}{0.61}=-2[/tex]

[tex] z=\frac{99.41-98.19}{0.61}=2[/tex]

And within 2 deviations from the mean we have 95% of the values.

Answer

g(x) moves 4 spaces to the left compared to f(x),  

when g(4)=0  when f(0)=0

when g(3)=1   when f(-1)=1

...

and so on

Answer:

The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States

Step-by-step explanation:

We want to see if the majority of Niagara Falls visitors are from the United States.

Looking at the confidence interval

We have to see if the lower end of the interval is higher than 0.5.

In this question:

The 95% confidence interval to estimate the true proportion of visitors to Niagara Falls that are from the United States was (0.5216, 0.6784).

The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States

Answer:

P = 4878

Step-by-step explanation:

So we'll use the formula

A = p(1+r/n)^ (nt)

A = 1000000

P is the unknown

R = 4.2

N = 13

T = 13

1000000= p ( 1+ 0.42/13)^ 169

1000000 = p (1.032)^169

1000000= p 205

P = 4878

Answer:

The answer is D.

Step-by-step explanation:

You have to apply Indices Law,

[tex] { ({a}^{m}) }^{n} \: ⇒ \: {a}^{mn} [/tex]

So for this question :

[tex] { ({6}^{7}) }^{3} [/tex]

[tex] = {6}^{7 \times 3} [/tex]

[tex] = {6}^{21} [/tex]

Answer:

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time

Step-by-step explanation:

Given;

function​ s(t) represents the position of an object at time t moving along a line.

s(1) = 62 at t1 = 1

s(5) = 102 at t5 = 5

Velocity v = distance/time

Average velocity v over time t is;

v = ∆s/∆t

v = [s(5) - s(1)]/[t5 - t1]

Substituting the given values;

v = (102 - 62)/(5 - 1)

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time