Answer:
8 + 2 n (second expression listed)
Explanation:
Since we don't know the number, we represent it with a letter (n).
Twice a number (two times that number) will therefore be: 2 n.
and the addition (sum) of 8 to such will lead to 8 + 2 n
The sum of 8 and twice a number is : 8 + 2 n
Law of conservation of energy states that
a
Energy cannot be created or destroyed
b
Momentum is not lost, it is transferred
c
The sum of the kinetic energy and potential energy
How does the water cycle contribute to clean water?
why is science important for our understanding of the natural world?
Philip drives his car at a velocity of 28 m/s he applies the break which slows the vehicle down at a rate of six. 4 m/s2 and it causes it’s to slow to stop how long does it take for the car to stop answer to the nearest 10th?
Which of these statements matches what we saw? Select all that apply: The amount of electric force depends on the amount of charge. Adding more charge to either balloon caused a greater repulsive force. If the one balloon has more electric charge, that causes a greater electric force on only on the other balloon. If the one balloon has more electric charge, that causes a greater electric force on only on itself, causing that balloon to move farther away than the other balloon. If the one balloon has more electric charge, that causes a greater electric force on both balloons, causing them to deflect equally.
Answer:
-The amount of electric force depends on the amount of charge
-Adding more charge to either balloon caused a greater repulsive force.
-If the one balloon has more electric charge, that causes a greater electric force on both balloons, causing them to deflect equally.
Explanation:
According to Coulomb's law of electrostatic force between two charged masses, the force of attraction is proportional to the product of the charges on the masses. This means that the more the charge on the masses, the more the electric force on them. And adding more charge to either balloon will only cause the balloons to repel each other with a greater amount of force.
The electric force between two charged masses is of the same magnitude both ways, regardless of the individual charges on the masses. This justifies the fact that If one balloon has more electric charge, it will cause a greater electric force to be exerted between both balloons, causing them to deflect equally.
Determine the velocity vector of the given path. c(t)=6ti+((3t)^2)j+((t)^3)k
Explanation:
Given,
Position vector, [tex]c(t)=6ti+((3t)^2)j+((t)^3)k[/tex]
We need to find the velocity vector of the given path
[tex]v=\dfrac{d(c(t))}{dt}\\\\v=\dfrac{d(6ti+((3t)^2)j+((t)^3)k)}{dt}\\\\v=\dfrac{d(6ti)}{dt}+\dfrac{d((3t)^2j}{dt}+\dfrac{d(t^3)k}{dt}\\\\v=6i+18tj+3t^2k[/tex]
Hence, this is the velocity vector of the given path.
While on vacation in the tropical Bahamas, Suzy decides to try out a water jet pack. She places the jet pack on her back (like you would wear a backpack), pushes the buttons in her hands, and water comes shooting out of the bottom of the jetpack, exerting a force on the ocean below. Why does Suzy fly up into the air? In your answer, be sure to state which of Newton's laws of motion this pertains to, describe this law, and explain how it causes Suzy to fly up into the sky.
Answer:
-Suzy flies up into the sky because of the upward force on the jetpack.
-Newton's third law of motion can be ascribed to this.
Explanation:
We know that in momentum, Force is described as the rate of change of momentum. Thus, for us to understand the forces, we will need to establish how the momentum of the water changes.
Suppose the mass flow rate of the water is denoted as M kg/sec and the upward velocity is denoted as v_u.
Now, since water is lying stationary at the sea, the initial momentum of the water will be zero. If every second the boat pumps upwards with mass flow rate M at velocity vu, the momentum per second would be;
Δp = F_water = Mv_u
Now, from Newton's third law the boat/pump would experience a downwards force with the formula:
F_boat = −Mv_u
Furthermore at the jetpack, the water does a reverse turn in direction and is now again directed back down at a different velocity v_d. Therefore the final momentum per second is Mv_d and therefore change in momentum is now;
Δp = M(v_d - v_u)
The velocity v_d will be negative since the boat/pump would experience a downwards force. Thus, the force on the water will be downwards and F_water ≤ 0 .
We will finally use Newton's third law to conclude that the upward force on the jetpack will be;
F_jetpack = M(v_u - v_d)
Thus upward force is what makes Suzy to fly up in the sky.
The flow rate of water through a tapered straight horizontal pipe fitting is 5 m/s. The diameter at the entrance is 0.7 m and is reduced by a factor of 0.6 at the exit. If the gauge pressure at the entrance is 350 kPa and drops by 50 Pa, the horizontal thrust on the fitting is,
Answer:
The value is [tex]F_t = 76024 \ N[/tex]
Explanation:
From the question we are told that
The flow rate is [tex]v_1 = 5 \ m/s[/tex]
The entrance diameter is [tex]d = 0.7 \ m[/tex]
The exit diameter is evaluated as [tex]d_e = 0.6 * 0.7 = 0.42 \ m[/tex]
The entrance gauge pressure is [tex]P_g = 350 \ kPa = 350*10^{3} \ Pa[/tex]
The droped gauge pressure is [tex]P_d = 50 \ kPa = 50*10^{3} \ Pa[/tex]
The presure at the exist is evaluated as [tex]P_e =(350 - 50 ) \ kPa = 300*10^{3} \ Pa[/tex]
Generally the entrance cross-sectional area is mathematically represented as
[tex]A = \pi \frac{d^2}{4}[/tex]
[tex]A = 3.142 \frac{0.7^2}{4}[/tex]
[tex]A =0.385 \ m^2[/tex]
Generally the exit cross-sectional area is mathematically represented as
[tex]A_e = \pi \frac{d_e^2}{4}[/tex]
[tex]A_e = 3.142 \frac{0.42^2}{4}[/tex]
[tex]A_e =0.139\ m^2[/tex]
Generally from the continuity equation
[tex]v_1 * A = v_2 * A_e[/tex]
=> [tex]v_2 = \frac{v_1 * A}{A_e}[/tex]
=> [tex]v_2 = \frac{5 * 0.385}{0.139}[/tex]
=> [tex]v_2 = 13.8 m/s [/tex]
Generally the net force in horizontal axis is equivalent to the net momentum change in the horizontal direction
So
[tex]P_g * A + F_t - P_e * A_e = P_d [ A_e * v_2^2 - A* v_1^2][/tex]
Here [tex]F_t[/tex] is the horizontal thrust on the fitting
So
[tex]350*10^{3} * 0.385 + F_t -0.385 * 0.139 = 50*10^{3} [ 0.385* 13.8^2 - 0.385* 5^2][/tex]
An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 9.40 m/s in 3.50 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.20 s has elapsed?
Answer:
a) Magnitude = 1.03 m/s², Direction: south
b) [tex]V_{f} = 8.16 m/s [/tex]
Explanation:
a) The magnitude and direction of the acceleration can be calculated using the following equation:
[tex] V_{f} = V_{0} + at [/tex] (1)
Where:
[tex]V_{f}[/tex]: is the final speed = 9.40 m/s
[tex]V_{0}[/tex]: is the initial speed = 13.0 m/s
t: is the time = 3.50 s
Solving equation (1) for a, we have:
[tex] a = \frac{V_{f} - V_{0}}{t} = \frac{9.40 m/s - 13.0 m/s}{3.50 s} = -1.03 m/s^{2} [/tex]
Hence, the magnitude of the acceleration is 1.03 m/s² and the direction of the bird's acceleration is the opposite of the initial velocity direction, which means that the bird is decelerating.
b) The final velocity of the bird can be found using the same equation 1:
[tex] V_{f} = V_{0} + at [/tex]
[tex] V_{f} = 13.0 m/s + (-1.03 m/s^{2})*(3.50 s + 1.20 s) = 8.16 m/s [/tex]
Therefore, the bird’s velocity after an additional 1.20 s has elapsed is 8.16 m/s.
I hope it helps you!
10.A car is travelling at a constant speed of 27m/s. The driver looks away from the road for a 2.0s to tune in a station on the radio. How far does the car go during this time?
Explanation:
Distance = speed × time
d = (27 m/s) (2.0 s)
d = 54 m
Light is incident along the normal on face AB of a glass prismwith refractive index 1.52.
A. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in air.
B. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in water.
air refactive index = 1.00029
water refractive index = 1.33
Answer:
48.9°, 29°
Explanation:
We kno that snell's law States that
( sin i / sin r ) = ( n 2 / n 1 )
And here
i = 90 - α
r = 90
n 2 = n a = 1.00029
n 1 = n = 1.52
So
( sin ( 90 - α ) / sin 90 ) = (1.00029 / 1.52 )
= 0.658
sin ( 90 - α ) = 0.658
90 - α = sin -1 ( 0.658 )
= 41.15
α = 90 - 41.15
= 48.9°
( b ) to find angle when prism immerssed in water
Using snell's law again
( sin i / sin r ) = ( n 2 / n 1 )
here i = 90 - α
r = 90
n 2 = n w = 1.33
n 1 = n = 1.52
So
( sin ( 90 - α ) / sin 90 ) = (1.33 / 1.52 )
= 0.875
sin ( 90 - α ) = 0.875
90 - α = sin -1 ( 0.875 )
= 61
α = 90 - 61
= 29°
Counseling psychologists typically handle severe psychological disorders.
Please select the best answer from the choices provided
T
F
Answer:
FALSE
Explanation:
Answer:
False
Explanation:
What is the definition of Unbalanced Forces in Science ?
A person is driving down a country lane at 25 m/s, when a deer suddenly jumps in front of the car. The deer is 75 m ahead and when the driver hits the brakes, the car slows at a rate of 4.20 m/s each second. Does the car hit the deer?
Answer:
The car does not hit the deer.
Explanation:
In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.
2as = Vf² - Vi²
where,
s = distance covered by car before stopping = ?
a = deceleration of car = - 4.2 m/s²
Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)
Vi = Initial Velocity of the Car = 25 m/s
Therefore,
2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²
s = (- 625 m²/s²)/(-8.4 m/s²)
s = 74.4 m
So, the car stops in 74.4 m, while the deer is at a distance of 75 m.
Hence, the car does not hit the deer.
Using third equation of kinematics
[tex]\boxed{\sf v^2-u^2=2as}[/tex]
[tex]\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s[/tex]
[tex]\\ \sf\longmapsto -625=-8.4s[/tex]
[tex]\\ \sf\longmapsto 8.4s=625[/tex]
[tex]\\ \sf\longmapsto s=\dfrac{625}{8.4}[/tex]
[tex]\\ \sf\longmapsto s=74.4m[/tex]
AS IT IS LESS THAN 75M HENCE CAR DOESNOT HIT THE DEAR.8. An object that is traveling 50m/s slows down with an
acceleration rate of -3.5m/s/s. This took place over a period of 4s.
What was the objects final velocity? *
Answer:
36 m/s
Explanation:
Given:
v₀ = 50 m/s
a = -3.5 m/s²
t = 4 s
Find: v
v = at + v₀
v = (-3.5 m/s²) (4 s) + 50 m/s
v = 36 m/s
Find an expression for the square of the orbital period.
Answer:
T²= 4π²R³/GM
Explanation:
First we know that
Fg= Fc
Because centripetal force must equal gravitational force
So
GMm/R² = Mv²/R
But velocity is 2πR/T
So by substitution we have
GMm/R²= M (2πR/T)/T
We have
T²= 4π²R³/GM as period
a delivery van has a mass of 7000 kg and a kinetic energy of 31,500 J. what is it’s speed
Answer:
The answer is
3 m/sExplanation:
The speed of an object given it's kinetic energy and mass can be found by using the formula
[tex]v = \sqrt{ \frac{2KE}{m} } [/tex]
where
KE is the kinetic energy
m is the mass
v is the speed
From the question
KE = 31,500 J
m = 7000 kg
The speed is
[tex]v = \sqrt{ \frac{2(31500)}{7000} } \\ = \sqrt{ \frac{63000}{7000} } \\ = \sqrt{ \frac{63}{7} } \\ = \sqrt{9} \: \: \: \\ = 3 \: \: \: \: \: \: \: [/tex]
We have the final answer as
3 m/sHope this helps you
b. How tar from the li u
b. Obtain the value of g from the motion of the moon assuming that its period
of rotation round the earth is 27 days 8 hours and the radius of its orbit is
60.1 times the radius of the earth.
0.
7.2 m. Compute
Answer:
Approximately [tex]9.79\; \rm m \cdot s^{-2}[/tex] at the surface of the earth, given that the radius of the earth is known to be approximately [tex]6.371\times 10^{6}\; \rm m[/tex]. Assumptions: the earth is a sphere, the orbit of the moon is circular, and that the gravitational pull of the earth is the only force on the moon.
Explanation:
Convert the orbital period of the moon around the earth to seconds:
[tex]\begin{aligned}t &= (27\; \text{day} \times 24\; \text{hours} \cdot \text{day}^{-1} + 8\; \text{hour})\times 3600\; \rm \text{s}\cdot \text{hour}^{-1}\\ &= 2361600\; \text{s} \end{aligned}[/tex].
Calculate the angular velocity of the moon around the earth using the formula[tex]\displaystyle \text{angular velocity} = \frac{2\pi}{\text{orbital period}}[/tex]:
[tex]\begin{aligned}\omega = \frac{2\pi }{t} = \frac{2\pi}{2361600\; \rm s} \approx 2.66056\times 10^{-6}\; \rm s^{-1}\end{aligned}[/tex].
Let [tex]m(\text{moon})[/tex] denote the mass of the moon. Let [tex]g[/tex] denote the gravitational field strength at the surface of the earth (not at the position of the moon.) Let [tex]r[/tex] denote the radius of the earth.
The orbital radius of the moon would thus be [tex]60.1\, r[/tex]. Note that in the gravitational field due to a single spherical mass, the field strength is inversely proportional to the square of distance from the center of that mass.
The surface of the earth is at a distance of [tex]r[/tex] away from the center of the earth. The distance between the moon and the center of the earth would then be [tex]60.1[/tex] times that number (that is: [tex]60.1\, r[/tex].)The gravitational field at the surface of the earth is [tex]g[/tex]. Therefore, at the position of the moon ([tex]60.1[/tex] times further away from the center of the earth compared to the earth surface,) the gravitational field strength would be:
[tex]\displaystyle \left( \frac{r^2}{(60.1\, r)^2} \right)\, g = \frac{g}{60.1^2}[/tex],
Hence, the gravitational pull of the earth on the moon would be [tex]\displaystyle \frac{m(\text{moon})\, g}{60.1^2}[/tex].
Assume that the gravitational pull of the earth is the only force on the moon. That gravitational pull would then be the equal (in size) to the net force on the moon. That is:
[tex]\displaystyle \text{Net force on the moon} = \frac{m(\text{moon})\, g}{60.1^2}[/tex].
On the other hand, the rotation (assumed to be perfectly circular) of the moon would give the net force on the moon in terms of:
the mass of the moon, the angular speed of the rotation, andthe radius of the orbit.[tex]\displaystyle \text{Net force on the moon} = m(\text{moon})\, \omega^2\, (60.1\, r)[/tex].
Combine the two expressions for the net force on the moon to obtain an equation for [tex]g[/tex]:
[tex]\displaystyle \frac{m(\text{moon})\, g}{60.1^2} = m(\text{moon})\, \omega^2\, (60.1\, r)[/tex].
Simplify and solve for [tex]g[/tex]:
[tex]\displaystyle g = 60.1^3 \, \omega^2\, r[/tex].
The angular velocity of this rotation, [tex]\omega[/tex], has already been found to be approximately [tex]2.66056\times 10^{-6}\; \rm s^{-1}[/tex]. Look up the radius of the earth: [tex]r = 6.371\times 10^{6}\; \rm m[/tex]. Evaluate this expression for [tex]g[/tex]:
[tex]\begin{aligned}g &= 60.1^3 \, \omega^2\, r \\ &\approx 60.1^3 \times \left( 2.66056\times 10^{-6}\; \rm s^{-1}\right) \times 6.371\times 10^{6}\;\rm m \\ &\approx 9.79\; \rm m \cdot s^{-1}\end{aligned}[/tex].
URGENT HELP!! PLEASE ANSWER QUICK
Answer:
im pretty sure it is B or D
A tennis racquet hits a tennis ball. Why doesnt the racquet swing backwards when the ball hits it? (Shouldn't it swing back because of the action-reaction forces?)
Answer:
You are putting more force on the ball no the racket so the racket wouldnt swing back but if you hit a racket on the ground it will swing backits just the way the force reaction works
Explanation:
^^^^^^^^^^^^^^^
The racket wouldn't swing back because you were applying more power to the ball than to the racket, so the racquet swings backward when the ball hits it.
What is force?Any action that aims to maintain, modify, or deform a body's motion is considered a force in mechanics. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687).
According to Newton's third law, whenever one body applies force to another, the second body also applies an equal amount of force to the first body. The action-reaction concept explains why a force tends to cause a body to deform, or change shape, whether it moves the body.
The racket wouldn't swing back because you were applying more power to the ball than to the racket, but it would if you struck the racket on the ground; that's how the force reaction operates.
Therefore, the racquet swings backward when the ball hits it.
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An elephant pushes with 200 N on a load of trees. it then pushes these trees for 10 N. How much work did the elephant do?
Answer:
the answer is 2000Nm
Explanation:
wprk done = force × distance moved
w.d = 200N × 10m
w.d = 2000Nm
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You get out of school and walk north for 20 minutes to travel 1.6 km what is your average velocity?
Answer: 12.5 km/h
Explanation: 20/1.6 = 12.5 km/h
The average velocity of an individual will be "0.08 km/min". To understand the calculation, check below.
Distance and VelocityAccording to the question,
Time, t = 20 minutes
Distance, d = 1.6 km
We know the formula,
→ Distance = Speed × Time,
Or,
Speed, v = [tex]\frac{Distance}{Time}[/tex]
By substituting the values,
= [tex]\frac{1.6}{20}[/tex]
= 0.08 km/min
Thus the avg. velocity will be "0.08 km.min" is correct.
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The most common type of mirage is an illusion that light from faraway objects seem to be reflected by a pool of water that is not really there. Mirages are generally observed in deserts, when there is a hot layer of air near the ground. The index of refraction of air is lower at higher temperature. What physical phenomena explains how mirages are formed? Give a brief explanation of the phenomena as your LPE.
Answer:
Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.
Explanation:
On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.
Newtons third lawWhat action-reaction forces are involved when a rocket engine fires? Why doesnt a rocket need air to push on? Atction force:_______ Reaction Force:________
Answer: action forc roketorce
reaction force is engine fires
A neutral atom of sodium has 12 neutrons and 11 protons. How many electrons does this sodium have? a.1 b.11 c.12 d.23
Answer:
We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass)
When an individual registers sensory input without being aware of the process consciously, __________ occurs. subliminal stimulation sensory adaptation signal detection processing absolute threshold
Answer:
Subliminal simulation
Explanation:
When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.
What is Subliminal simulation?Subliminal stimulation defined as sensory stimulation which is below a person's threshold for perception.
It can't be seen by the bare eye or consciously heard. An example is visual stimuli which is flashed so quickly on a screen that a person can't process it. So, they are unaware they have seen anything.
Subliminal stimuli helps facilitate conscious processing of related information, changes the current mood, boost our motivation. It can even change a person's political attitudes and voting intentions.
When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.
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Convert 360 s to ms? Pls need help
Answer:
360000
Explanation:
Answer:
360000 milliseconds
Explanation:
I have this remembered dont worry homie i got chu
An average human has a heart rate of 70 beats per minute. If someone's heart
beats at that average rate over a 70-yr lifetime, how many times would it beat?
a.) 7 x 10 to the 5th power
b.) 2 x 10 to the 6th power
c.) 2x 10 to the 7th power
d.) 3 x 10 to the 9th power
Give an example of each type of electromagnetic radiation.
Answer:
Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.
Explanation:
A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
Answer:
57.0 m
Explanation:
Assume the time it takes for the sound to reach the top of the well is negligible.
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3.41 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²
Δy = 57.0 m
Answer:
57 m
Explanation:
