Which expression shows the sum of the polynomials with like terms grouped together?

(a) [tex]\{x: x > -4 \}[/tex]

(b) [tex](-4, \infty)[/tex]

Answer:

[tex]7 469.8.56[/tex]

nossa nem sei como é bom saber se fala com a mãe e o pai do mundo e vc não tem mais nada pra comer e não tem como fazer a gente vai ficar muito tempo sem fazer a mãe dela não e vc como tá o trabalho rede de nada em casa e é só pra mim né não é fácil de fazer a mãe dela e a mãe dele tá bem né não é fácil de fazer o que vc quer que Deus quiser vai dar pra mim né e não tem como fazer d id da x não vou poder é o que eu te abençoe e ilumine e ilumine todos os dias entre?01029)

Answer:

-7 is -7 units away from zero. Its opposite is 7 from zero.

Step-by-step explanation: Count from 0 how many digits away it is

Answer:

1491 girls (99.4 percent)

Step-by-step explanation:

explanation is in the attached picture

The proportion of sides of the triangle which is not true are 13.5/21 = 9/14, 9/13.5 = 6/21 and 14/6 = 21/9

The three sides of each of the rectangles should be proportional to each other

Triangle A : Triangle B

9 cm : 13.5 cm

= 9/13.5

14 cm : 21 cm

= 14 cm / 21 cm

6 cm : 9 cm

= 6 cm / 9 cm

Therefore, the proportion of sides of the triangle which is not true are 13.5/21 = 9/14, 9/13.5 = 6/21 and 14/6 = 21/9

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The triangle is not a right triangle. This is because the sum of the square of the two shorter lengths is not equal to the square of the longest length.

In order to determine if the triangle is a right triangle, Pythagoras theorem would be used.

The Pythagoras theorem: a² + b² = c²

where a = length

b = base

c = hypotenuse

12 ² + 24²

= 144 + 576 = 720

29² = 841

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Based on the upper and lower quartiles of the box plots:

Range for Maths is 60 to 85

Range for Language arts is 60 to 80.

In a box plot, the about half of the data set lies between the upper quartile and the lower quartile which are represented at the beginning and the end of the edges of the box respectively. This makes up 50% of a data distribution.

Thus, for Maths, the Upper and lower quartiles are between 60 to 85, hike that for Language arts are between 60 to 80.

Therefore, 50% of Theos scores for Maths ranges from: 60 to 85, while for Language arts is: 60 to 80.

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The quotient [tex]\frac{x^2 - 49}{x + 2} \div \frac{x^2 - 14 +49}{3x + 6}[/tex] is [tex]\frac{3(x +7)}{(x -7)}[/tex]

The expression is given as:

[tex]\frac{x^2 - 49}{x + 2} \div \frac{x^2 - 14 +49}{3x + 6}[/tex]

Express x^2 - 49 as difference of two squares

[tex]\frac{(x + 7)(x- 7)}{x + 2} \div \frac{x^2 - 14 +49}{3x + 6}[/tex]

Factorize other expressions

[tex]\frac{(x + 7)(x- 7)}{x + 2} \div \frac{(x -7)(x-7)}{3(x + 2)}[/tex]

Express as product

[tex]\frac{(x + 7)(x- 7)}{x + 2} \times\frac{3(x + 2)}{(x -7)(x-7)}[/tex]

Cancel the common factors

[tex]\frac{(x + 7)}{1} \times\frac{3}{(x -7)}[/tex]

Evaluate the product

[tex]\frac{3(x +7)}{(x -7)}[/tex]

Hence, the quotient [tex]\frac{x^2 - 49}{x + 2} \div \frac{x^2 - 14 +49}{3x + 6}[/tex] is [tex]\frac{3(x +7)}{(x -7)}[/tex]

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Answer:

First Inverse function= f^-1(x)=x/3-5/3

Second Inverse function=f^-1(x)=x/3-5/3

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

492/99x100=21.43

nearest tenth percentage is 20

Step-by-step explanation:

I'm going to assume you meant to write [tex]\sqrt{r+1}[/tex] in the equation as +1 - 1 wouldn't make much sense since they would just cancel out.

a. [tex]f(-1) = \sqrt{-1 + 1} - 1\\ f(-1) = \sqrt{0} - 1\\f(-1) = 0-1\\f(-1) = -1[/tex]

b. [tex]f(24) = \sqrt{24 + 1} - 1\\ f(24) = \sqrt{25} - 1\\f(24) = 5 - 1\\f(24) = 4[/tex]

c. [tex]f(x-1) = \sqrt{(x-1)+1} -1\\f(x-1) = \sqrt{x} - 1[/tex]

Answer: 180 degrees

Step-by-step explanation:

The measure of the arc of a semicircle is 180 degrees.

She did 21 question correctly.

Let number of correct answers : x

Let number of wrong answer : y

Given, Total question wrote : 30

So,  

      x + y = 30          (i) - equation

Got 8 point on each correct answer, total point : 8*x

Got -2 point on each wrong answer, total point : (-2)*y

Total point she score was : 150          (given)

so, our next equation is

                                      8*x - 2*y = 150       (ii) - equation

                                      y = 30 - x            [from (i) - equation]

put in (ii) - equation, we get

                                    8*x - 2*(30 - x) = 150

                                    8*x - 60 + 2*x = 150

                                    10*x = 210

                                       x = 21

Therefor, only 21 answers are correct.

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The formula to find the volume of the composite solid is: C. V = πr²h + ⅔πr³.

The volume of the composite solid in the image given = Volume of cylinder + volume of hemisphere.

Volume of cylinder = πr²h

Volume of hemisphere = ⅔πr³

Therefore, formula to find the volume is: C. V = πr²h + ⅔πr³.

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Answer:

C

Step-by-step explanation:

I Just Took the Test.

Answer:

[tex]x = \frac{25}{13} [/tex]

Step-by-step explanation:

Given:

[tex] \frac{2}{5} x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6} x[/tex]

Combine like terms:

[tex] \frac{2}{5} x - \frac{5}{6} x = \frac{1}{3} + \frac{1}{2} [/tex]

Find GCF :

[tex] \frac{12}{30} x - \frac{25}{30} = \frac{2}{6} + \frac{3}{6} [/tex]

Subtraction and Addition :

[tex] \frac{13}{30} x = \frac{5}{6} [/tex]

Divide both sides by 13/30 :

[tex] \frac{ \frac{13}{30} }{ \frac{13}{30} } x = \frac{ \frac{5}{6} }{ \frac{13}{30} } [/tex]

Simplify :

Multiplication (Reciprocal) :

[tex]x = \frac{5}{6} \times \frac{30}{13} [/tex]

[tex]x = \frac{150}{78} [/tex]

[tex]x = \frac{25}{13} [/tex]

Answer :

[tex]x = \frac{25}{13} [/tex]

Hope it helps

The average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.

Since the arrival rate and service rate follow a Poisson distribution, we can use the Poisson arrival rate formula to calculate the average queue length.

Average queue length = (arrival rate * service time) / (1 - arrival rate * service time)

For the given problem, the average queue length is:

Average queue length = (50 * 35) / (1 - 50 * 35)

= 175

Since the average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.

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Answer:

true

Step-by-step explanation:

this is absolutely true

An equation is formed when two equal expressions are equated together. The value of x in the equation [√(x+7)]-11=2 is 162.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution for x in the equation [√(x+7)]-11=2 can be solved as,

[tex]\sqrt{x+7}-11=2\\[/tex]

Using the addition property of equality,

[tex]\sqrt{x+7} -11+11= 2+11\\\\\\\sqrt{x+7} = 13[/tex]

Squaring both the sides of the equation,

x + 7 = 169

Using the subtraction property of equality,

x + 7 - 7 = 169 - 7

x = 162

Hence, the value of x in the equation [√(x+7)]-11=2 is 162.

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Answer:

1188

Step-by-step explanation:

√121 (3^2)(2(6)) = 1188

Answer:

264

Step-by-step explanation:

√(121m^2 n^6)   =   11 m n^3

  sub in the values given for m and n

                       11 (3)(2^3) = 11 * 3 * 8 = 264

Answer:

x = -14

Step-by-step explanation:

- x + 8 + 3x = x - 6

- x + 8 + 3x - x + 6 = 0

x + 14 = 0

x = -14

Answer:

3qr - 6q²

Step-by-step explanation:

3q(r - 2q) ← multiply each term inside the parenthesis by 3q

= 3qr - 6q²

Answer:

3qr – 6q²

Step-by-step explanation:

3q(r – 2q)

E X P A N D I N G :-

3qr – 6q²

Answer:

2 erasers cost $1.20

Step-by-step explanation:

Nigel bought 10 pencils and 5 erasers for $8.

We can write this algebraically:

10p + 5e = 8

We know that the price of 2 pencils is $1. That is $0.50/Pencil.

So, p = $0.50. Now we can plug that into out equation and find the price of one eraser:

10(0.50) + 5e = 8

5 + 5e = 8

5e = 3

e = $0.60

Now, we have the price of one eraser, $0.60, and we can multiply this by 2 to find the price of 2 erasers, which equates to $1.20.

Answer:

600/100*20=6*20=120

600-120=480$

Answer:

[tex] \frac{?}{?} [/tex]

Using the normal distribution, it is found that 0.2119 = 21.19% of rainy days have rainfall with pH below 5.0.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 5.43, \sigma = 0.54[/tex]

The proportion of rainy days have rainfall with pH below 5.0 is the p-value of Z when X = 5, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 5.43}{0.54}[/tex]

Z = -0.8

Z = -0.8 has a p-value of 0.2119.

0.2119 = 21.19% of rainy days have rainfall with pH below 5.0.

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Answer:

C   34  cm

Step-by-step explanation:

Area = L x W

  72  = 8 x W     then W = 9

Perimeter = 2 ( L+W) = 2 ( 8+ 9) = 34  cm

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{Area of rectangle: A = wl; whereas \boxed{\textsf a} is \underline{area}, \boxed{\textsf w} is \underline{width}, \& \boxed{\textsf{l}} is}\\\large\text{\underline{length}.}[/tex]

[tex]\large\text{a = wl}\\\\\large\text{wl = a}\\\\\large\text{w(8) = 72}\\\\\large\text{8w = 72}\\\\\large\textsf{DIVIDE 8 to BOTH SIDES}\\\\\rm{\dfrac{8w}{8} = \dfrac{72}{8}}\\\\\large\text{SIMPLIFY IT!}\\\\\rm{w = \dfrac{72}{8}}\\\\\rm{w = 9}\\\\\\\huge\text{Therefore, your answer should be: \boxed{\mathsf{width = \bf 9}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

The Mean and Standard deviation for the given data would be as follows:

μ =79.7

б =7.81

Step-by-step explanation:

Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers.

Standard deviation is the square root of the arithmetic mean of the squares of deviations of the items from their mean values.

Frequency Distribution

Given that,

Temperature       Lower Limit           Upper Limit             Days([tex]f_{i}[/tex])

50-59                       50                           59                          2

60-69                       60                           69                         313

70-79                         70                           79                          1419

80-89                        80                          89                          1503

90-99                        90                          99                           319

100-109                    100                         109                            9  

Average([tex]x_{i\\}[/tex])    

[tex]\frac{50+59}{2} = 54.5\\ \\\frac{60+69}{2} = 64.5\\ \\\frac{70+79}{2} = 74.5\\\\\frac{80+89}{2} = 84.5\\ \\\frac{90+99}{2} = 94.5\\ \\\frac{100+109}{2} = 104.5[/tex]

As we know,

Mean (μ) =∑ [tex](x_{i}f_{i})[/tex]/∑[tex]f_{i}[/tex]

= { (54.5 * 2) + (64.5 * 313) +(74.5 * 1419)+(84.5*1503)+(94.5*319) + (104.5*9)/ (2+313+1419+1503+319)

∵ μ = 79.7

As we know,

Standard Deviation:-

[tex]\sigma={\sqrt {\frac {\sum(x_{i}-{\mu})^{2}}{N}}}[/tex]

by putting the values, we get

∵ б = 7.81

Hence, μ = 79.7 and б=7.81  are the correct answers.

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The missing pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula [tex]n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}[/tex], equivalent to the recurrence formula [tex]a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}[/tex].

A sequence is a set of elements which observes at least a defined rule. In this question we see a sequence which follows this rule:

[tex]n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}[/tex]      (1)

Now we prove that given expression contains the pattern:

n = 0

7

n = 1

7 + (- 1)² · 2² = 7 + 4 = 11

n = 2

7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2

n = 3

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18

n = 4

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7

The missing pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula [tex]n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}[/tex], equivalent to the recurrence formula [tex]a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}[/tex].

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