Which formula is used to find an object's acceleration? ​

Answer:

in all three cases the total moment is zero

cases A and B the kinetic energy is conserved.  

In case C the velocity decreases so the kinetic energy decreases

Explanation:

This is a momentum conservation exercise

          p = mv

In order for the moment to be preserved, we must define a system formed by the two cars, so that the forces during coke have been internal.

Before crash

car 1      p₀₁ = m v₀

car 2     p₀₂ = - mv₀

pose us several situations, we analyze each one

A) After the crash the cars stop

      [tex]p_{f}[/tex] = 0

p₀₁      m v₀

p₀₂    -m v₀

p_{f}  0

B) After the collision, each vehicle reverses its direction

p₀₁            m v₀

p₀₂           -m v₀

p_{f1}       -m v₀

p_{f2}       m v₀

C) In this case some of the kinetic energy is lost which is converted into internal energy, for example, deformation, heat, friction.

Consequently the speed of the cars is

               v < v₀

p₀₁          m v₀

p₀₂         - m v₀

p_{f1}     -m v

p_{f2}    m v

D) in cases A and B the momentum is maintained, but in case C the total momentum is maintained, even when the speed of the cars decreases, this is pf_total = 0

In all cases the total impulse is zero

           p₀ = p₀₁ + p₀₂ = m v₀ - mv₀

           p₀_total = 0

in all three cases the total moment is zero

E) The total kinetic energy is the sum of the kinetic energy of each car

          K_total = K₀₁ + K₀₂

          K_total = ½ m v₀² + ½ m (-v₀)²

          K_total = m v₀²

we see that because it is squared, the sign of the velocity does not matter, therefore in cases A and B the kinetic energy is conserved.

In case C the velocity decreases so the kinetic energy decreases

         Kf_total < K₀_total

the missing energy is transformed into internal energy during sackcloth.

In the attachment we can see a vector diagram of the momentum in each case

Answer:

The magnitude of the resultant force is 6201 N

The direction of the resultant force is 72°

Explanation:

Please find the attached file for explanation;

Answer:

(a). The distance is 9.80 km.

(b). The magnitude of the couple’s displacement is 2.94 km.

(c). The direction of the couple’s displacement is 45°.

Explanation:

Given that,

Radius of lake = 2.08 km

(a). We need to calculate the total distance

Using formula of distance

[tex]d=\dfrac{3}{4}(2\pi R)[/tex]

Put the value into the formula

[tex]d=\dfrac{3}{4}(2\pi\times2.08)[/tex]

[tex]d=9.80\ km[/tex]

(b). We need to calculate the magnitude of the couple’s displacement

Using formula of displacement

[tex]D=\sqrt{R^2+R^2}[/tex]

[tex]D=\sqrt{2R^2}[/tex]

[tex]D=\sqrt{2\times(2.08)^2}[/tex]

[tex]D=2.94\ km[/tex]

(c), The direction of the displacement is given by

Using formula of direction

[tex]\tan\theta=\dfrac{R}{R}[/tex]

[tex]\theta=\tan^{-1}(1)[/tex]

[tex]\theta=45^{\circ}[/tex]

Hence, (a). The distance is 9.80 km.

(b). The magnitude of the couple’s displacement is 2.94 km.

(c). The direction of the couple’s displacement is 45° relative to the east.

The distance they travel is approximately 6.54644 km. The magnitude of the couple's displacement is 4.16 km. The direction of their displacement is opposite to due east.

(a) The distance they travel is:

Distance = (3/4) × 2 × 3.14159 × 2.08

Distance = 3.14159 × 2.08 km

Distance = 6.54644 km

So, the distance they travel is approximately 6.54644 km.

(b) The magnitude of the couple's displacement is:

Displacement = 2 × 2.08

Displacement = 4.16 km

So, the magnitude of the couple's displacement is 4.16 km.

(c) The direction of their displacement is opposite to due east.

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Answer:yes

Explanation:The constan acceleration means that it wont stop moving but if you kick it a different direction then it will change direction

Answer:

The value is  [tex]h_a  =   1.712 \  m [/tex]

Explanation:

From the question we are told that

   The  height of the top meter stick above the ground is  [tex]h_1  =  1.47 \  m[/tex]

    The  time taken for the acorn to pass the length of the  stick is [tex]t =  0.281 \  s[/tex]

Generally the height of the acorn at the point it is the same height with the metered stick is mathematically represented as  

     [tex]h =  h_m =  u_a  * t  +  \frac{1}{g} t^2[/tex]

Here [tex]h_m[/tex] is height of the meter stick and the value is 1 m (This because we are told in the question that the stick is 1 meter in length ( a meter stick))

So

      [tex]1  =  u_a  *  0.281  +  \frac{1}{9.8} (0.281)^2[/tex]

=>   [tex]u_a  =  -2.2 \  m/s[/tex]

Generally the velocity of the acorn just before passing the top of the meter stick is mathematically represented by a kinematic equation as

         [tex]u^2_a   =  u^2  + 2gs[/tex]

here  u is zero since the acorn started from rest

So  

         [tex] (-2.2)  =  0  + 2 *  9.8 * s[/tex]

         [tex]s  =  0.242 \  m[/tex]

Generally the height of the acorn is

     [tex]h_a   =  h_1 + s[/tex]

      [tex]h_a  =  0.242  +  1.47[/tex]\

      [tex]h_a  =   1.712 \  m [/tex]

Answer:

[tex]VB -  VA  =  - 33.4[/tex]

Explanation:

Generally the workdone in moving the proton is mathematically represented as

     [tex]W  =  KE_f  - KE_i[/tex]

Where [tex]KE_i \ and \  KE_f \  are\  the\  initial  \  and  \  final \  kinetic \  energy  [/tex]

So

    [tex]KE_i  =  \frac{1}{2} m v_a^2[/tex]

Here [tex]v_a[/tex] is the velocity at A with value  50 m/s

So

    [tex]KE_i  =  \frac{1}{2} (1.67*10^{-27}) * 50^2 [/tex]

    [tex]KE_i  = 2.09 *10^{-24} \  J  [/tex]

Also  

     [tex]KE_f  =  \frac{1}{2} m v_b^2[/tex]

Here [tex]v_a[/tex] is the velocity at A with value [tex]80 km/s = 80000 m/s [/tex]

=>   [tex]KE_f  =  \frac{1}{2} (1.67*10^{-27}) * 80000^2 [/tex]

=>   [tex]KE_f  = 5.34 *10^{-18} \  J[/tex]

 So

    [tex]W  =   5.34 *10^{-18}  - 2.09 *10^{-24}[/tex]

     [tex]W  =   5.34 *10^{-18}  m/s[/tex]

Now this workdone is also mathematically represented as

     [tex]W =  q *  V[/tex]

So  

    [tex]   q *  V =   5.34 *10^{-18}   [/tex]

Here  [tex]q =  1.60*10^{-19} C[/tex]

So

        [tex]   V =   \frac{5.34 *10^{-18} }{1.60*10^{-19}}[/tex]

         [tex]   V =   33.4 \  V  [/tex]

Generally proton movement is in the direction of the electric field it means that  [tex] VA>VB [/tex]

So

    [tex]VB -  VA  =  - 33.4[/tex]

Answer:

What is a Control Group? The control group (sometimes called a comparison group) is used in an experiment as a way to ensure that your experiment actually works. It's a way to make sure that the treatment you are giving is causing the experimental results, and not something outside the experiment

Explanation:

Answer:

The final temperature is [tex]\left(T_1^{C_1}+T_2^{C_2}\right)^{\frac {1}{C_1+C_2}}[/tex]

and the maximum amount of workdone is [tex]C_1T_1 + C_2T_2-(C_1+C_2)\left(T_1^{C_1}+T_2^{C_2}\right)^{\frac {1}{C_1+C_2}}[/tex].

Explanation:

Assume that [tex]R_1[/tex] is the reservior having temperature [tex]T_1 K[/tex] and heat capicity [tex]C_1 \frac JK[/tex] and [tex]R_2[/tex] is the reservior having temperature [tex]T_2[/tex] and heat capicity [tex]C_2 \frac JK[/tex].

The work will be extracted till that both the reservior reach the thermal equilibrium. Let the final temperature of both the reservior is [tex]T_f[/tex].

Let total [tex]Q_1[/tex] heat is extracted by the heat engine from the reservior [tex]R_1[/tex] and its temperature decreases from [tex]T_1[/tex] to [tex]T_f[/tex] and [tex]Q_2[/tex] heat is rejected by the heat engine to the reservior [tex]R_2[/tex] and its temperature decreases from [tex]T_2[/tex] to [tex]T_f[/tex].

So, The maximum amount of work done,

[tex]w= Q_1 - Q_2\; \cdots (i)[/tex]

Now, as the heat engine is reversible, so change is entropy for the universe is 0, which means sum of change in entropy for the ststem as well as surrounding is 0.

As shown in figure, the system is the reversible engine, so, change is entropy for the system is 0. Hence, change in entropy for the the surrounding is 0.

As temperature of [tex]R_1[/tex] is changing fron [tex]T_1[/tex] to [tex]T_f[/tex], so, change in entropy of surrounding due to transfer of [tex]Q_1[/tex] is [tex]C_1 \ln \frac {T_f}{T_1}[/tex].

Similarly,  change in entropy of surrounding due to transfer of [tex]Q_2[/tex] is [tex]C_2 \ln \frac {T_f}{T_2}[/tex].

As the net change in entropy of the surrounding is 0.

[tex]\Rightarrow C_1 \ln \frac {T_f}{T_1}+C_2 \ln \frac {T_f}{T_2}=0[/tex]

[tex]\Rightarrow \ln \left( \frac {T_f}{T_1} \right)^{C_1}+ \ln \left( \frac {T_f}{T_2}\right)^{C_2}=0[/tex]

[tex]\Rightarrow \ln \left(\frac {T_f}{T_1}\right)^{C_1}=- \ln \left( \frac {T_f}{T_2}\right)^{C_2}[/tex]

[tex]\Rightarrow \ln \left(\frac {T_f}{T_1}\right)^{C_1}= \ln \left( \frac {T_2}{T_f}\right)^{C_2}[/tex]

[tex]\Rightarrow \left( \frac {T_f}{T_1}\right)^{C_1}=\left( \frac {T_2}{T_f}\right)^{C_2}[/tex][taking anti-log both the sides]

[tex]\Rightarrow T_f^{(C_1 +C_2)}=T_1^{C_1}+T_2^{C_2}[/tex]

[tex]\Rightarrow T_f=\left(T_1^{C_1}+T_2^{C_2}\right)^{\frac {1}{C_1+C_2}}\; \cdots (ii)[/tex]

This is the required final temperature.

Now, from equarion (i), the maximum amount of work done is

[tex]w= Q_1 - Q_2[/tex]

As [tex]Q=C\Delta T[/tex]

[tex]\Rightarrow w=C_1(T_1-T_f)-C_2(T_f-T_2)[/tex]

[tex]\Rightarrow w=C_1T_1 + C_2T_2-(C_1+C_2)T_f[/tex]

From equation [tex](ii)[/tex],

[tex]w=C_1T_1 + C_2T_2-(C_1+C_2)\left(T_1^{C_1}+T_2^{C_2}\right)^{\frac {1}{C_1+C_2}}[/tex]

This is the required maximum workdone.

Answer: length of B =4.00

Explanation:

for  the vectors A and B and the angle between them as  x.

Magnitude of the sum of A and B is  given as = √(A²+B²+2ABcosx

where

Magnitude of A  = 3.00

Magnitude of the sum of A and B is  5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b=  √16

b= 4

Answer:

v = 5.26 10² m / s

Explanation:

We can solve this exercise using the concepts of conservation of mechanical energy, because there is no friction

starting point. Red blood cells too far away

          Em₀ = K = ½ m v²

final point. Red blood cells touching r = 8.20 10⁻⁶ m

          Em_f = U = k q₁ q₂ / r₁₂

          Em₀ = Em_f

          ½ m v² = k q₁ q₂ / r₁₂

          v = √ (2 k q₁ q₂ / m r₁₂)

we calculate

          v =√ (2 9 10⁹ 2 10⁻¹² 2.9 10⁻¹² / (4.60 10⁻¹⁴  8.20 10⁻⁶))

          v = √ (0.276775 10⁶)

          v = 0.526 10³ m / s

          v = 5.26 10² m / s

Answer:

the answer is A, B, and C

Explanation:

D is wrong because your weight does change...it is your mass that doesn't change

Answer:145 km/hr

Explanation: v1+v2 100+45 =145 km/hr

Answer:

egocentric

Explanation:

Answer:

D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.

Hope this helps!

The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies. Thus option D is correct.

Energy is the ability to do work It can be movement of a body to do some physical activity.

If the energy is stored in the form of chemical bonds of a complex molecule then the energy is called as chemical energy.

The energy released in the chemical reaction and produced as as a by-product, that process is known as an exothermic reaction.

For instance,  chemical energy sored in biomass, batteries, natural gas, petroleum, and coal.

Dry wood also the storage of chemical energy, as it burns the chemical energy is released and converted into light energy and thermal energy

The food we eat is also an example of chemical energy storage as it is liberated during digestion process.  

Thus option D is correct.

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Complete Question

Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in ( The diagram is shown on the first uploaded image ) has a mass m= 10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it:

The applied force F (directed θ=30∘ above the horizontal).

The force of gravity Fg=mg (directly down, where g=9.8m/s2).

The normal force N (directly up).

The force of static friction fs (directly left, opposing any potential motion).

If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:

Fcosθ−μsN=0

Fsinθ+N−mg=0

In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g, θ, and μs (no N)

Note the diagram is shown on the first uploaded image

Answer:

The expression for F is [tex]F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}[/tex]

Explanation:

Generally from the diagram we see that

[tex]Fcos\theta -f_s = 0[/tex]

From the question we are told that

[tex]f_s = \mu_s * N[/tex]

So

[tex]Fcos\theta - \mu_s * N = 0[/tex]

=> [tex] N = \frac{Fcos(\theta)}{\mu_s}[/tex]

Also from the diagram

[tex]Fsin(\theta )+N - F_g = 0[/tex]

Here [tex]F_g = m * g[/tex]

So

=> [tex]Fsin(\theta )+ \frac{Fcos(\theta)}{\mu_s} - m* g = 0 [/tex]

=> [tex]F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}[/tex]

Answer:

Yes

Explanation:

I took physics last year that that was a requirement.

Answer:

A. matter was compressed into a single point and then exploded outward to form the universe

Explanation:

The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now (and it could still be stretching).

A. matter was compressed into a single point and then exploded outward to form the universe.

this option describes the big bang theory

The Big Bang hypothesis states that all of the current and past matter in the Universe came into existence at the same time, roughly 13.8 billion years ago. At this time, all matter was compacted into a very small ball with infinite density and intense heat called Singularity.

The Big Bang was the moment 13.8 billion years ago when the universe began as a tiny, dense, fireball that exploded. Most astronomers use the Big Bang theory to explain how the universe began. But what caused this explosion in the first place is still a mystery.

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Answer:

Velocity = 56.67 mi/hr

Explanation:

Distance = 170 miles

Time = 3 hours

Velocity =?

[tex]Velocity = \frac{Distance}{Time} \\\\V = \frac{170}{3} \\\\V =56.67[/tex]

Answer:

the angle is about 67.79 degrees

Explanation:

We know that at its maximum height, the vertical component of the projectile's launching (initial) velocity (Vyi) is zero, so at that point it total velocity equals the horizontal component of the initial velocity (Vxi = 0.5 m/s)

We also know that the maximum height of the projectile is given by the square of its initial vertical component of the velocity (Vyi) divided by 2g, therefore half of such distance is :

[tex]half\,\,max-height = \frac{v_{yi}^2}{4\,g}[/tex]

we can use this information to find the y component of the velocity at that height via the formula:

[tex]v_{yf}^2-v_{yi}^2=-2\,g\,\Delta y\\\\v_{yf}^2-v_{yi}^2=-2\,g\,(\frac{v_{yi}^2}{4\,g} )\\v_{yf}^2=v_{yi}^2-\frac{v_{yi}^2}{2} \\v_{yf}^2=\frac{v_{yi}^2}{2}[/tex]

Now we use the information that tells us the speed of the projectile at this height to be 1 m/s. That should be the result of the vector addition of the vertical and horizontal components:

[tex]1=\sqrt{v_{yf}^2+0.5^2} \\1=\sqrt{\frac{v_{yi}^2}{2} +0.5^2}\\1^2=\frac{v_{yi}^2}{2} +0.5^2}\\1-0.5^2=\frac{v_{yi}^2}{2} \\2(1-0.5^2)=v_{yi}^2\\1.5 = v_{yi}^2\\v_{yi}=\sqrt{1.5} \\[/tex]

Now we can use the arc-tangent to calculate the launching angle, since we know the two initial component of the velocity vector:

[tex]tan(\theta)=\frac{v_{yi}}{v_{xi}} =\frac{\sqrt{1.5} }{0.5} \\\theta= arctan(\frac{\sqrt{1.5} }{0.5})=67.79^o[/tex]

The motion of an object through the air does not affect by its mass. The rate of fall of objects does not depend upon the mass.

Free fall is a motion of a body in which gravity is the only force acting upon it. An object moving upwards might not be considered to be falling. But if the object is under the effect of the force of gravity, it is said to be in free fall.

Free fall is a type of motion in which the force acting upon an object is only gravity. Objects are not encountering a significant force of air resistance as they are only falling under the sole influence of gravity. All objects under such conditions will fall with the same rate of acceleration, regardless of their masses.

As an object falls through the air, have gone through some degree of air resistance. Air resistance is the collisions of the object's leading surface with molecules present in the air. The two most common factors that have a direct effect on the amount of air resistance are the cross-sectional area of the object and the speed of the object.

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Explanation:

It's pressure become three times larger because according to Boyles Law the pressure of fixed mass of gas is inversely proportional to it's volume provided that temp remains constant. That means a reduction in volume, will result in an increase in pressure and vice versa.

Answer:

4

Explanation: the problem with this one is 75 the problem the problem with

Answer:

The distance traveled by the bus was 1080 m

Explanation:

Please find the attached file for explanation

Answer:

The Answer Is 17s

Explanation:

Displacement trianglex = 50m

Time t = ?

Average velocity v = 3.0 m/s

You can rearrange the equation v = trianglex/t to solve for time t.

v = tianglex/t

t = trianglex/v

= 50m/3.0m/s

= 17s

Answer:

Explanation:

The time that the baseball spends in the air is known as time of flight and it is expressed as shown;

T = Using(theta)/g where;

U is the velocity of the baseball

g is the acceleration due to gravity.

Given parameters

U = 4.55m/s

theta = 22.0°

g = 9.81m/s²

Substituting the values in the formula;

T = 4.55sin22°/9.81

T = 4.55(0.3746)/9.81

T = 1.7045/9.81

T = 0.1738second

Hence the time flight of the baseball is 0.1738second

b) The horizontal distance covered by the ball is called the RANGE in projectile.

Range = U√2H/g

U = 4.55m/s

H is the maximum height = 2.90m

g = 9.81m/s²

Substitute the given parameters into the formula

Range = 4.55√2(2.90)/9.81

Range = 4.55√5.8/9.81

Range = 4.55√0.5912

Range = 4.55(0.7689)

Range = 3.4986m

Hence the horizontal distance from the roof edge to the point where the baseball lands on the ground is 3.4986m

Answer:

Explanation:

I can't name the whole characters, I will try to name as much as I can remember, thanks.

Pat Conroy (Conrack) or (C'roy)

C'roy happens to be the male teacher on Yamacraw Island.

Dr. Henry Piedmont

Dr. Henry is the Superintendent for the school district in Beaufort, South Carolina.

Ezra Bennington

Ezra is the Deputy Superintendent of Beaufort County schools, in South Carolina

Mrs. Brown

Mrs Brown is a teacher on the Yamacraw Island. A racist teacher, if I might add.

Barbara Bolling Jones Conroy

Barbara lives with a Yamacraw Island teacher.

Ted Stone

Ted is the man with an awful lot of responsibilities on Yamacraw Island.

Lou Stone

Lou is the Yamacraw Island postmaster, in addition to being the school bus driver.

Zeke Skimberry

Zeke is the Yamacraw Island maintenance man who eventually becomes friends with one of the teachers.

Babies

This is a nickname is for the students of Yamacraw Island.

That's the lot I can mention. I hope that's enough.

Answer:

Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position).

Hope this helps! :)

Explanation:

Answer:

Answer is D

Explain:

Just did it on Abex

The equation best describes a cost-benefit analysis for installing new, more efficient solar panels on the International Space Station which the team might perform is Improved efficiency - manufacturing expenses - fuel to reach orbit = net benefit.

A panel designed to absorb the sun's rays as a source of energy for generating electricity or heating. Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.

The advantages of solar power are:

A cost-benefit analysis is the process of comparing the projected or estimated costs and benefits (or opportunities) associated with a project decision to determine whether it makes sense from a business perspective.

The Elements of Cost-Benefit Analysis is

Hence, Improved efficiency - manufacturing expenses - fuel to reach orbit = net benefit best describes a cost-benefit analysis the team might perform.

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Answer:

D

Explanation:

5 Km=5000m

so Δv=5000 m/sec

a=Δv/Δt

=5000/10

a=500 m/sec²                 as 500÷1000=0.5 Km

a=0.5 km/sec²

so D is the right answer.