Which graph shows a function where f(2) = 4

Answers

Answer 1

The that graph shows a function where f(2) = 4 is:

option 1

Which graph shows a function where f(2) = 4?

We have to find a function where f(2)=4. It means the value of function is 4 at x=2.

In graph 1, the value of function is 4 at x=2, therefore option 1 is correct.

In graph 2, the value of function is -4 at x=2, therefore option 2 is incorrect.

In graph 3, the value of function is not shown in the graph at x=2, therefore option 3 is incorrect.

In graph 4, the value of function is not shown in the graph at x=2, therefore option 4 is incorrect.

Therefore, correct option is 1.

Learn more about function on:

brainly.com/question/1415456

#SPJ1

Complete Question

Check attached image

Which Graph Shows A Function Where F(2) = 4

Related Questions

Can someone help on this please? Thank youu:)

Answers

The equations are written as;

Slope - intercept form : y = mx + c

Point- slope form; y − y₁= m(x − x₁).

Standard form; y - mx + c = 0

How to determine the equations

First, we need to know that the general formula representing the equation of a line of graph is expressed as;

y = mx + c

Such that the parameters of the formula are;

y is a point on the y -axism is the slope of the linex is a point on the x -axisc is the intercept of the line on the y-axis

From the information given, we have that the graph is a straight line.

Then, we have;

y = mx + c

Learn more about equation of a line at: https://brainly.com/question/18831322

#SPJ1

Which is 0.54 with bar converted to a simplified fraction?

Answers

Answer:

6/11

Step-by-step explanation:

6/11 = 0.54

x = 0.54

> 100x = 54.54[repetition bar]

> 100x - x = 54.54 - 0.54

> 99x = 54

> x = 54/99 = 6/11

Answer:

6/11

Step-by-step explanation:

(Spaces between steps for better understanding)

To convert the recurring decimal 0.54 with bar to a simplified fraction, we can use the following steps:

Step 1: Let's represent the recurring decimal 0.54 with bar as x.

x = 0.54 (with bar and it can't be represented as it violates terms)

Step 2: Multiply both sides of the equation by 100 to move the decimal point to the right:

100x = 54.54 (with bar)

Step 3: Subtract the equation obtained in Step 1 from the equation obtained in Step 2 to eliminate the recurring part:

100x - x = 54.54 (with bar) - 0.54 (with bar)

99x = 54

Step 4: Divide both sides of the equation by 99 to solve for x:

x = 54/99

Step 5: Simplify the fraction by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 9 in this case:

x = (54/9) / (99/9)

x = 6/11

Therefore, the recurring decimal 0.54 with bar can be simplified to the fraction 6/11.

The population of the world 1 t years after 2010 is predicted to be P=6.77e 0.012t
billion. Round your answers to one decimal place. (a) What population is predicted in 2026? The predicted population of the world in the year 2026 is billion people. (b) What is the predicted average population between 2010 and 2026 ? The average population of the world over this time period is billion people. 1
www.indexmundi.com, accessed February 4, 2021.

Answers

Population predicted in 2026:To find the predicted population in the year 2026, we can substitute t = 16 into the equation

P = 6.77e^(0.012t).

Thus,

P = 6.77e^(0.012*16) billion≈ 9.77 billion.

Therefore, the predicted population of the world in the year 2026 is approximately 9.77 billion people.(b) Predicted average population between 2010 and 2026 To find the predicted average population between 2010 and 2026, we need to find the total population over this time period and divide by the number of years.Using t = 16, we can find the population in the year 2026 as we did in part (a):

P = 6.77e^(0.012*16) billion≈ 9.77 billion.

To find the population in the year 2010, we can substitute

t = 0:P = 6.77e^(0.012*0)

billion= 6.77 billion

Therefore, the population in the year 2010 was approximately 6.77 billion people.The time period between 2010 and 2026 is 16 years.Thus, the total population over this time period is:Total population = 9.77 + 6.77 = 16.54 billionThe predicted average population between 2010 and 2026 is therefore:Average population = Total population/Number of years= 16.54/16≈ 1.03 billionTherefore, the average population of the world over this time period is approximately 1.03 billion people.

To know more about substitute visit :

https://brainly.com/question/29383142

#SPJ11

Dance Company Students The number of students who belong to the dance company at each of several randomly selected small universities is shown below. Round sample statistics and final answers to at least one decimal place. 28 28 26 25 22 21 47 40 35 32 30 29 26 40 Send data to Excel Estimate the true population mean size of a university dance company with 80% confidence. Assume the variable is normally distributed.

Answers

Mean = 31.4

Standard deviation = 7.708

Standard Error = 2.061

Critical value = 1.282

Margin of error = 2.644

Confidence interval = (28.756, 34.044)

To estimate the true population mean size of a university dance company with 80% confidence, we can use the sample data provided and calculate a confidence interval.

Given the sample data: 28, 28, 26, 25, 22, 21, 47, 40, 35, 32, 30, 29, 26, 40

1. Calculate the sample mean (X) and the sample standard deviation (s) of the data.

  X = (28 + 28 + 26 + 25 + 22 + 21 + 47 + 40 + 35 + 32 + 30 + 29 + 26 + 40) / 14 = 31.4

  s = √[(Σ(x - X)^2) / (n - 1)]

    = √[((28 - 31.4)^2 + (28 - 31.4)^2 + ... + (40 - 31.4)^2) / (14 - 1)]

    ≈ 7.708

2. Calculate the standard error (SE) of the sample mean.

  SE = s / √n

     = 7.708 / √14

     ≈ 2.061

3. Determine the critical value (z*) corresponding to an 80% confidence level.

  The confidence level is 80%, which means the significance level (α) is 1 - 0.8 = 0.2.

  Since we assume a normal distribution, we can find the critical value from the standard normal distribution table or use a calculator. For a 80% confidence level, the critical value is approximately 1.282.

4. Calculate the margin of error (ME).

  ME = z* * SE

     = 1.282 * 2.061

     ≈ 2.644

5. Construct the Confidence interval.

  Confidence interval = X ± ME

                     = 31.4 ± 2.644

                     ≈ (28.756, 34.044)

Therefore, with 80% confidence, we estimate that the true population mean size of a university dance company is between approximately 28.8 and 34.0.

To know more about Confidence Interval refer here:

https://brainly.com/question/13067956#

#SPJ11

Suppose a railroad rail is 3 kilometers and it expands on a hot day by 14 centimeters in length. Approximately how many meters would the center of the rail rise above the ground?

Answers

The approximate rise of the center of the rail above the ground would be 0.14 meters / 2 = 0.07 meters.

To calculate the approximate rise of the center of the rail above the ground, we need to consider the expansion of the rail length and the geometry of the rail itself.

Given that the rail expands by 14 centimeters in length, we can convert this measurement to meters by dividing by 100: 14 centimeters / 100 = 0.14 meters.

Since the rail expands uniformly, we can assume that the center of the rail rises halfway between the two ends. In other words, the rise of the center is half of the expansion length.

Therefore, the approximate rise of the center of the rail above the ground would be 0.14 meters / 2 = 0.07 meters.

It's important to note that this calculation assumes the rail expands uniformly along its entire length, without any other external factors influencing the expansion. Additionally, this approximation assumes a straight rail without any curves or bends. In reality, railway tracks often have curves and other structural considerations that can affect the expansion and rise.

This calculation provides a rough estimation based on the given information, but for precise calculations and engineering purposes, it is recommended to consult the specific expansion coefficient and structural data provided by the rail manufacturer or relevant engineering standards.

for more such question on rail  visit

https://brainly.com/question/31827085

#SPJ8

The slope of line /is 2/3 Line m is perpendicular to line 1.
What is the slope of line m?

Answers

when the slope of a line is 2/3

the slope of a line which is prependicular to it is -3/2

For the given cost function C(z) = 72900 + 200x + ² find: a) The cost at the production level 1200 b) The average cost at the production level 1200 c) The marginal cost at the production level 1200 d

Answers

c) the marginal cost at the production level of 1200 is 2600.

To answer the questions, let's break down each part:

a) The cost at the production level 1200:

To find the cost at the production level of 1200, we can substitute x = 1200 into the cost function C(z).

C(z) = 72900 + 200x + x²

Substituting x = 1200:

C(1200) = 72900 + 200(1200) + (1200)²

        = 72900 + 240000 + 1440000

        = 2172900

the cost at the production level of 1200 is 2,172,900.

b) The average cost at the production level 1200:

To find the average cost, we need to divide the total cost at a specific production level by the quantity produced. In this case, it is 1200.

Average cost = Total cost / Quantity

Average cost at x = 1200:

Average cost = C(1200) / 1200

           = 2172900 / 1200

           ≈ 1810.75

the average cost at the production level of 1200 is approximately 1810.75.

c) The marginal cost at the production level 1200:

The marginal cost represents the rate of change of the cost function with respect to the production level. In other words, it is the derivative of the cost function.

To find the marginal cost, we differentiate the cost function C(z) with respect to x:

C'(z) = 200 + 2x

Substituting x = 1200:

C'(1200) = 200 + 2(1200)

         = 200 + 2400

         = 2600

To know more about derivative visit:

brainly.com/question/25324584

#SPJ11

Suppose you compute a derivative of a continuous function \( g \) and simplify it as the following: \[ g^{\prime}(x)=\frac{30 x^{2}(5 x-1)}{5-x} \] (a) Find the critical points of \( g \). (b) Determine the sign of g^4 on each subinterval of the real number line where cp1,cp2, and cp3 refer to the critical points from smallest to largest. (c) Use the signs to classify each critical point as a local maximum, local minimum, or neither.

Answers

For ( a)  the critical points of [tex]\( g \) are \( x = 0 \) and \( x = \frac{1}{5} \).[/tex] For ( b ) Since [tex]\( g'(1) \)[/tex] is

positive, the sign of [tex]\( g'(x) \)[/tex] is positive on the interval [tex]\((\frac{1}{5}, \infty)\).[/tex] For ( c ) the

critical point [tex]\( x = \frac{1}{5} \)[/tex]  and  [tex]\( x = 0 \)[/tex] is also a local minimum.

(a) To find the critical points of [tex]\( g \)[/tex] , we need to solve the equation [tex]\( g'(x) = 0 \)[/tex]. In this case, the derivative of [tex]\( g \)[/tex] is given by:

[tex]\[ g'(x) = \frac{{30x^2(5x-1)}}{{5-x}} \][/tex]

To find the critical points, we set the numerator equal to zero and solve for [tex]\( x \):[/tex]

[tex]\[ 30x^2(5x-1) = 0 \][/tex]

We can see that this equation will be satisfied if either [tex]\( 30x^2 = 0 \) or \( 5x-1 = 0 \).[/tex] Solving these equations individually, we get:

For [tex]\( 30x^2 = 0 \):[/tex]

[tex]\[ x = 0 \][/tex]

For [tex]\( 5x-1 = 0 \):[/tex]

[tex]\[ x = \frac{1}{5} \][/tex]

Therefore, the critical points of [tex]\( g \) are \( x = 0 \) and \( x = \frac{1}{5} \).[/tex]

(b) To determine the sign of [tex]\( g'(x) \)[/tex] on each subinterval of the real number line, we need to test the intervals created by the critical points and the endpoints. Let's consider the intervals: [tex]\((- \infty, 0)\), \((0, \frac{1}{5})\), \((\frac{1}{5}, \infty)\).[/tex]

For the interval [tex]\((- \infty, 0)\):[/tex]

Choosing a test point [tex]\( x = -1 \)[/tex] in this interval, we can evaluate [tex]\( g'(-1) \)[/tex] to determine the sign. Substituting [tex]\( x = -1 \)[/tex] into the derivative, we get:

[tex]\[ g'(-1) = \frac{{30(-1)^2(5(-1)-1)}}{{5-(-1)}} = \frac{{-120}}{{6}} = -20 \][/tex]

Since [tex]\( g'(-1) \)[/tex]  is negative, the sign of [tex]\( g'(x) \)[/tex] is negative on the interval [tex]\((- \infty, 0)\).[/tex]

For the interval [tex]\((0, \frac{1}{5})\):[/tex]

Choosing a test point [tex]\( x = \frac{1}{10} \)[/tex] in this interval, we can evaluate [tex]\( g'(\frac{1}{10}) \)[/tex]  to determine the sign. Substituting [tex]\( x = \frac{1}{10} \)[/tex] into the derivative, we get:

[tex]\[ g'(\frac{1}{10}) = \frac{{30(\frac{1}{10})^2(5(\frac{1}{10})-1)}}{{5-(\frac{1}{10})}} = \frac{{-1}}{{5}} \][/tex]

Since [tex]\( g'(\frac{1}{10}) \)[/tex] is negative, the sign of [tex]\( g'(x) \)[/tex] is negative on the interval [tex]\((0, \frac{1}{5})\).[/tex]

For the interval [tex]\((\frac{1}{5}, \infty)\):[/tex]

Choosing a test point [tex]\( x = 1 \)[/tex] in this interval, we can evaluate [tex]\( g'(1) \)[/tex]  to determine the sign. Substituting [tex]\( x = 1 \)[/tex] into the derivative, we get:

[tex]\[ g'(1) = \frac{{30(1)^2(5(1)-1)}}{{5-(1)}} = 120 \][/tex]

Since [tex]\( g'(1) \)[/tex] is positive, the sign of [tex]\( g'(x) \)[/tex] is positive on the interval [tex]\((\frac{1}{5}, \infty)\).[/tex]

Therefore, the sign of [tex]\( g'(x) \)[/tex] on each subinterval is as follows:

[tex]\[(- \infty, 0) & : \text{Negative} \\(0, \frac{1}{5}) & : \text{Negative} \\(\frac{1}{5}, \infty) & : \text{Positive} \\\][/tex]

(c) To classify each critical point as a local maximum, local minimum, or neither, we can use the signs of the derivative on each side of the critical point.

For the critical point [tex]\( x = 0 \):[/tex]

The sign of [tex]\( g'(x) \)[/tex] changes from negative to positive as we move from left to right of [tex]\( x = 0 \).[/tex] Therefore, the critical point [tex]\( x = 0 \)[/tex] is a local minimum.

For the critical point [tex]\( x = \frac{1}{5} \):[/tex]

The sign of [tex]\( g'(x) \)[/tex] changes from negative to positive as we move from left to right of [tex]\( x = \frac{1}{5} \)[/tex]. Therefore, the critical point [tex]\( x = \frac{1}{5} \)[/tex]  is also a local minimum.

In summary, the classification of each critical point is as follows:

[tex]\[\text{cp1} (x = 0) & : \text{Local Minimum} \\\text{cp2} (x = \frac{1}{5}) & : \text{Local Minimum} \\\][/tex]

Please note that we don't have any additional critical points beyond [tex]\( x = 0 \)[/tex] and [tex]\( x = \frac{1}{5} \)[/tex] in this case.

To know more about derivative visit-

brainly.com/question/29212834

#SPJ11

lve the equation 4(2m +5)-39 = 2(3m-7) A. m = 16.5 B. m = 9 C. m = 2.5 D. m = -4

Answers

Option E) m = 5/8 is the correct answer.The equation 4(2m +5)-39 = 2(3m-7) is given.

The value of m is to be determined. We will first simplify the given equation.

4(2m + 5) - 39 = 2(3m - 7)

8m + 20 - 39 = 6m - 14

8m - 19 = 6m - 14

8m - 6m = -14 + 19

8m = 5m = 5/8

On solving the equation, we get the value of m as 5/8.

Hence, option E) m = 5/8 is the correct answer.

To know more about equation visit:

https://brainly.com/question/29657983

#SPJ11

In a study that compares the means of two groups, one way to state the null hypothesis is: "the population mean of Group 1 will be equal to the population mean of Group 2." A. True B. False

Answers

In a study that compares the means of two groups, one way to state the null hypothesis is: "the population mean of Group 1 will be equal to the population mean of Group 2." This statement is true. Why is the statement "the population mean of Group 1 will be equal to the population mean of Group 2" true The null hypothesis is a statement that suggests that no statistical significance exists among the variables.

It is the hypothesis that the researcher is attempting to test and disprove when conducting a study. In a study that compares the means of two groups, one way to state the null hypothesis is "the population mean of Group 1 will be equal to the population mean of Group

2."The null hypothesis for a comparison of two population means is always expressed in this manner. This is because the null hypothesis is essentially saying that there is no difference between the means of two populations, and as a result, the mean of population 1 is equal to the mean of population 2 in the null hypothesis.

The alternate hypothesis, on the other hand, states that the two population means are different. This can be expressed in a variety of ways, but one of the most frequent is that the mean of population 1 is greater than the mean of population 2 or that the mean of population 2 is greater than the mean of population 1.

To know more about population visit:

https://brainly.com/question/15889243

#SPJ11

Determine where the function is concave upward and where it is concave downwa notation.) f(x) = 3x4 – 30x³ + x − 9 concave upward concave downward

Answers

In summary:

- The function is concave upward for x < 0 and x > 5.

- The function is concave downward for 0 < x < 5.

To determine where the function f(x) = 3x^4 - 30x^3 + x - 9 is concave upward and concave downward, we need to find the second derivative of the function and analyze its sign.

First, let's find the first derivative of f(x):

f'(x) = 12x^3 - 90x^2 + 1

Next, let's find the second derivative by differentiating f'(x):

f''(x) = 36x^2 - 180x

To determine where the function is concave upward, we need to find the values of x for which f''(x) > 0.

Setting f''(x) > 0, we have:

36x^2 - 180x > 0

Factoring out 36x from both terms, we get:

36x(x - 5) > 0

To find the critical points, we set each factor equal to zero:

36x = 0   --> x = 0

x - 5 = 0 --> x = 5

Now we can analyze the intervals and determine the concavity:

For x < 0, we choose a test value such as x = -1:

36(-1)(-1 - 5) > 0, which is true. So, f''(x) > 0 for x < 0.

For 0 < x < 5, we choose a test value such as x = 1:

36(1)(1 - 5) < 0, which is false. So, f''(x) < 0 for 0 < x < 5.

For x > 5, we choose a test value such as x = 6:

36(6)(6 - 5) > 0, which is true. So, f''(x) > 0 for x > 5.

Therefore, the function f(x) = 3x^4 - 30x^3 + x - 9 is concave upward for x < 0 and x > 5.

To determine where the function is concave downward, we need to find the values of x for which f''(x) < 0.

Setting f''(x) < 0, we have:

36x^2 - 180x < 0

Factoring out 36x from both terms, we get:

36x(x - 5) < 0

Using the same critical points, we can determine the intervals of concave downward:

For 0 < x < 5, we choose a test value such as x = 1:

36(1)(1 - 5) < 0, which is true. So, f''(x) < 0 for 0 < x < 5.

Therefore, the function f(x) = 3x^4 - 30x^3 + x - 9 is concave downward for 0 < x < 5.

To know more about derivative visit:

brainly.com/question/25324584

#SPJ11

Todd hired a handyman to replace some tiles in his bathroom. He paid him $24 per hour of work and $15 as a tip.
If the handyman worked for t hours, the amount he got paid is given by the expression
. If he worked for 3 hours, he would receive

Answers

Answer:

87

Step-by-step explanation:

24*3=72

72+15=

87

Set Up A Triple (Or Double) Integral To Find The Volume Of The Region Given By Z=Xy, Z=0, 0 ≤ X ≤3, 0 ≤ Y ≤4. Must Show SKETC

Answers

This integral will give you the volume of the region defined by the surfaces Z = Xy, Z = 0, 0 ≤ X ≤ 3, and 0 ≤ Y ≤ 4.

To find the volume of the region bounded by the surfaces Z = Xy, Z = 0, 0 ≤ X ≤ 3, and 0 ≤ Y ≤ 4, we can set up a double integral over the region in the XY-plane and integrate the height function Z = Xy.

The region is defined by the following bounds:

0 ≤ X ≤ 3 (horizontal bounds)

0 ≤ Y ≤ 4 (vertical bounds)

Let's denote the volume as V. The volume can be expressed as:

V = ∬(R) Xy dA,

where R represents the region in the XY-plane.

To set up the double integral, we need to define the limits of integration. Since the region is rectangular, the limits are straightforward:

0 ≤ X ≤ 3 (horizontal bounds)

0 ≤ Y ≤ 4 (vertical bounds)

The integral becomes:

V = ∫(0 to 4) ∫(0 to 3) Xy dX dY.

To visualize the region, we can sketch it in the XY-plane. Since the region is rectangular, it extends from X = 0 to X = 3 and from Y = 0 to Y = 4. The surface Z = Xy represents a curved surface that intersects the XY-plane at Y = 0 and X = 0, creating a triangle-shaped region.

Unfortunately, as a text-based platform, I'm unable to provide a visual sketch here. However, you can plot the region and the surface Z = Xy on a graphing software or calculator to get a better visual representation.

To find the volume numerically, you would need to evaluate the double integral:

V = ∫(0 to 4) ∫(0 to 3) Xy dX dY.

Evaluating this integral will give you the volume of the region defined by the surfaces Z = Xy, Z = 0, 0 ≤ X ≤ 3, and 0 ≤ Y ≤ 4.

Learn more about integral here

https://brainly.com/question/30094386

#SPJ11

Find ∂x
∂f

and ∂y
∂f

for the following function. f(x,y)=(9x−3y) 9
∂x
∂f

=

Answers

Given function:[tex]f(x, y) = (9x - 3y)⁹[/tex]We have to find ∂x and ∂y for the above-given function.To find ∂x:We have to differentiate the given function partially with respect to x by treating y as a constant.

[tex]∂f/∂x = (9x - 3y)⁹[/tex]Now, we will differentiate the above expression with respect to x. Therefore, the derivative of x will be 1, and the derivative of y will be zero[tex].(∂f/∂x) = 9(9x - 3y)⁸ × 9[/tex]Therefore[tex], ∂x = 81(9x - 3y)⁸[/tex]To find ∂y:We have to differentiate the given function partially with respect to y by treating x as a constant.

[tex]∂f/∂y = (9x - 3y)⁹[/tex]Now, we will differentiate the above expression with respect to y. Therefore, the derivative of y will be 1, and the derivative of x will be zero[tex].(∂f/∂y) = 9(-3)(9x - 3y)⁸ × (-1)[/tex]

[tex]∂y = 27(9y - 3x)⁸Hence, ∂x = 81(9x - 3y)⁸ and ∂y = 27(9y - 3x)⁸[/tex].These are the required results for the given function.

To know more about differentiate visit:

https://brainly.com/question/13958985

#SPJ11

please help!!! i don’t get this

Answers

Answer:

I attached an image below with the answers.

Step-by-step explanation:

To find the correct answers to these questions, you can simply take the shown x and y values and plug them into the possible systems of equations listed in the blue. Sub the x into the x and the y into the y. Numbers like 2x and 3y are multiplication.

If the numbers you inputted equal the same on both sides of the equal sign for both equations per box, then the solutions, (x and y) are true for that system.

I hope the image makes sense and you don't have to download it.

Event A occurs with probability 0.6. Event B occurs with probability 0.33. Events A and B are independent. Find: a) P(A∩B) b) P(A∪B) c) P(A∣B) d) P(A^C
∪B)

Answers

Therefore, the probabilities are:

a) P(A∩B) = 0.198.

b) P(A∪B) = 0.867.

c) P(A∣B) = 0.6.

d) P(A^C∪B) = 0.55.

a) To find P(A∩B), the probability of both events A and B occurring, we multiply the probabilities of the two events since they are independent:

P(A∩B) = P(A) * P(B) = 0.6 * 0.33 = 0.198.

b) To find P(A∪B), the probability of either event A or event B (or both) occurring, we can use the formula:

P(A∪B) = P(A) + P(B) - P(A∩B).

Given that A and B are independent, P(A∩B) = P(A) * P(B), so we have:

P(A∪B) = P(A) + P(B) - P(A) * P(B) = 0.6 + 0.33 - (0.6 * 0.33) = 0.867.

c) To find P(A∣B), the conditional probability of event A given that event B has occurred, we use the formula:

P(A∣B) = P(A∩B) / P(B).

Since A and B are independent, P(A∩B) = P(A) * P(B), so we have:

P(A∣B) = (P(A) * P(B)) / P(B) = P(A) = 0.6.

d) To find P(A^C∪B), the probability of either the complement of event A or event B (or both) occurring, we can use the formula:

P(A^C∪B) = P(A^C) + P(B) - P((A^C)∩B).

Since A and B are independent, P((A^C)∩B) = P(A^C) * P(B), so we have:

P(A^C∪B) = P(A^C) + P(B) - P(A^C) * P(B).

The complement of event A is A^C, and its probability is 1 - P(A):

P(A^C∪B) = (1 - P(A)) + P(B) - (1 - P(A)) * P(B).

Plugging in the given probabilities:

P(A^C∪B) = (1 - 0.6) + 0.33 - (1 - 0.6) * 0.33 = 0.55.

Therefore, the probabilities are:

a) P(A∩B) = 0.198.

b) P(A∪B) = 0.867.

c) P(A∣B) = 0.6.

d) P(A^C∪B) = 0.55.

Learn more about complement here:

https://brainly.com/question/29697356

#SPJ11

ss of the solid E with the given density function rho. inded by the planes x=0,y=0,z=0,x+y+z=4;rho(x,y,z)=3y

Answers

The mass and center of mass of the solid E are M = 43.333 and CM = (1.8056, 1.4722, 1.7222), respectively.

The mass of the solid E can be found by using the formula for the triple integral with respect to the volume of a solid. We can also use the formula for the triple integral to calculate the center of mass of the solid.

The mass of the solid E is given by:

M = ∫ ∫ ∫ 3y dx dy dz

We can evaluate the integral with respect to x, y, and z for the given domain of the tetrahedron bounded by the planes x=0, y=0, z=0, and x+y+z=4. The limits of integration for the x variable are 0 to 4-y-z. The limits of integration for the y variable are 0 to 4-x-z. The limits of integration for the z variable are 0 to 4-x-y.

M = ∫ (4-y-z) ∫ (4-x-z) ∫ (4-x-y) 3y dx dy dz

We can evaluate the integrals as such:

M = ∫ (4-y-z) ∫ (4-x-z) (4y-2xy-2xz) dy dz

 = ∫ (4-y-z) (16-4x²-8xz) dz

 = (64 - 8y² - 16yz) z

We can evaluate the integral with respect to z between the limits 0 to 4-y.

M = 43.333

We can use the same method to calculate the center of mass of the solid E. The center of mass of the solid E is given by the formula:

CM = (1/M) ∫ ∫ ∫ x ρ(x, y, z) dx dy dz

We can evaluate the triple integral with the same limits of integration as we did for the mass.

CM = (1/M) ∫ (4-y-z) ∫ (4-x-z) ∫ (4-x-y) × 3y dx dy dz

We can evaluate the integrals as such:

CM = (1/M) ∫ (4-y-z) ∫ (4-x-z) (x²y-xy²-x²z) dy dz

 = (1/M) ∫ (4-y-z) (2x^3y - x²y²- 2x^3z) dz

 = (1/M) (6x^4y - 3x³y² - 6x⁴z) z

We can evaluate the integral with respect to z between 0 to 4-y.

CM = 43.333/M (1.8056, 1.4722, 1.7222)

Therefore, the mass and center of mass of the solid E are M = 43.333 and CM = (1.8056, 1.4722, 1.7222), respectively.

Learn more about the integration here:

https://brainly.com/question/31744185.

#SPJ4

does random assignment always balance the proportion of each group (laptop vs. notebook) that sit in the front or back? no, but we just got unlucky, and we should expect 2000 new randomizations to give us perfectly balanced groups each time. yes, since the graph is centered near 0, it always produces balanced groups. no, since not all of the randomizations produce a difference of 0, but on average, it produces balanced groups. yes, but this would be less likely if we had larger treatment groups.

Answers

Random assignment does not always balance the proportion of each group (laptop vs. notebook) that sit in the front or back. However, by conducting a large number of randomizations, we can expect balanced groups on average.

Random assignment is a commonly used technique in experimental design to assign participants to different groups. While random assignment helps to minimize bias and ensure groups are comparable, it does not guarantee perfect balance in all cases.

In the given scenario, if random assignment does not produce perfectly balanced groups in terms of the proportion of laptops and notebooks in the front or back, it does not imply that we were simply unlucky. The random assignment process inherently introduces variability, and the resulting group composition may differ across randomizations.

However, by increasing the number of randomizations, we can expect the average balance to improve. This is because random assignment aims to distribute potential confounding factors equally among groups, and with a larger sample size or more randomizations, the likelihood of achieving balanced groups increases.

It is important to note that the degree of balance achieved may also depend on the size of the treatment groups. Larger treatment groups may introduce more variability, making it harder to achieve perfect balance even with random assignment.

Learn more about factors here:

https://brainly.com/question/14549998

#SPJ11

Use guess and check to find when an exponential function with a decay rate of 5% per hour reaches half of its original amount, rounded up to the nearest hour The exponential function reaches half of its original amount after hours (Round up to the nearest hour)

Answers

Given that we have an exponential function with a decay rate of 5% per hour, to find out when this exponential function reaches half of its original amount, we can use guess and check method.

The general formula of an exponential function with decay is given by:

y = abˣ

where a is the initial value of the function

b is the base of the exponential function

x is the time decay rate.

In this case, our exponential function is decaying at a rate of 5% per hour, which means that the base is equal to 1 - 0.05 = 0.95. The formula now becomes:

y = a(0.95)ˣ

To find out when the function reaches half of its original amount, we can substitute y with a/2 and solve for x.

a/2 = a(0.95)ˣ

x = log(0.5)/log(0.95)≈ 13.5 hours

Since the question asks us to round up to the nearest hour, we can round up 13.5 to 14 hours. Therefore, the exponential function reaches half of its original amount after 14 hours.

To know more about exponential, visit:

https://brainly.com/question/29160729

#SPJ11

(b) Consider the function \( f(x)=x+\sin 2 x \). Determine the lowest and highest values in the interval \( [0,3] \).

Answers

The lowest value is [tex]\( \frac{5\pi}{6} - \frac{\sqrt{3}}{2} \)[/tex] and the highest value is [tex]\( 3 + \sin(6) \)[/tex].

To determine the lowest and highest values of the function [tex]\( f(x) = x + \sin(2x) \)[/tex] in the interval [tex]\([0,3]\)[/tex], we need to find the points where the function reaches its minimum and maximum values.

First, we evaluate the function at the critical points, which occur when the derivative is equal to zero. Taking the derivative of \[tex]( f(x) \)[/tex]) with respect to [tex]\( x \)[/tex], we have:

[tex]\( f'(x) = 1 + 2\cos(2x) \)[/tex]

Setting [tex]\( f'(x) = 0 \)[/tex], we find:

[tex]\( 1 + 2\cos(2x) = 0 \)[/tex]

[tex]\( \cos(2x) = -\frac{1}{2} \)[/tex]

Solving for [tex]\( x \)[/tex], we get two solutions: [tex]\( x = \frac{\pi}{6} \)[/tex] and [tex]\( x = \frac{5\pi}{6} \)[/tex].

Next, we evaluate [tex]\( f(x) \)[/tex] at the critical points and the endpoints of the interval:

[tex]\( f(0) = 0 + \sin(0) = 0 \)[/tex]

[tex]\( f\left(\frac{\pi}{6}\right) = \frac{\pi}{6} + \sin\left(\frac{\pi}{3}\right) = \frac{\pi}{6} + \frac{\sqrt{3}}{2} \)[/tex]

[tex]\( f\left(\frac{5\pi}{6}\right) = \frac{5\pi}{6} + \sin\left(\frac{5\pi}{3}\right) = \frac{5\pi}{6} - \frac{\sqrt{3}}{2} \)[/tex]

[tex]\( f(3) = 3 + \sin(6) \)[/tex]

By comparing these values, we can determine the lowest and highest values of [tex]\( f(x) \)[/tex] in the interval [tex]\([0,3]\)[/tex].

Therefore, the lowest value is [tex]\( \frac{5\pi}{6} - \frac{\sqrt{3}}{2} \)[/tex] and the highest value is [tex]\( 3 + \sin(6) \)[/tex].

To more on Maxima:
https://brainly.com/question/29502088
#SPJ8

Find six rational numbers between 5/8 3/5

Answers

Six rational numbers between 5/8 and 3/5 are 49/80, 73/160, 121/320, 97/320, 219/640, 335/960.

In mathematics, rational numbers are numbers that can be expressed as the quotient or fraction of two integers, where the denominator is not zero. A rational number can be represented as p/q, where p and q are integers and q is not equal to zero.

Key properties of rational numbers include:

Fractional Form: Rational numbers can be written in fractional form, where the numerator and denominator are integers. For example, 2/3, -5/7, and 1/2 are rational numbers.

Terminating or Repeating Decimals: Rational numbers have decimal representations that either terminate (end) or repeat in a pattern. For example, 0.75 (which is equivalent to 3/4) terminates, while 0.333... (which is equivalent to 1/3) repeats infinitely.

Closure under Operations: Rational numbers are closed under addition, subtraction, multiplication, and division. When rational numbers are added, subtracted, multiplied, or divided, the result is always another rational number.

Rational versus Irrational Numbers: Rational numbers can be contrasted with irrational numbers, which cannot be expressed as fractions and have non-repeating, non-terminating decimal representations. Examples of irrational numbers include √2 (square root of 2) and π (pi).

The given question is asking for six rational numbers between 5/8 and 3/5. To find these numbers, we can start by converting the fractions to have a common denominator.

The common denominator for 8 and 5 is 40. So, we can rewrite the fractions as follows:
5/8 = 25/40
3/5 = 24/40

Now that both fractions have the same denominator, we can find six rational numbers between them by evenly spacing them out. Let's use the method of taking the average of the two fractions:

First rational number: (25/40 + 24/40) / 2 = 49/80
Second rational number: (24/40 + 49/80) / 2 = 73/160
Third rational number: (49/80 + 73/160) / 2 = 121/320
Fourth rational number: (73/160 + 121/320) / 2 = 97/320
Fifth rational number: (121/320 + 97/320) / 2 = 219/640
Sixth rational number: (97/320 + 219/640) / 2 = 335/960

So, six rational numbers between 5/8 and 3/5 are:
49/80, 73/160, 121/320, 97/320, 219/640, 335/960.

These numbers are rational because they can be expressed as a ratio of two integers.

To know more about rational numbers visit:

https://brainly.com/question/24398433

#SPJ11

Which of the following statements is NOT correct about the hypothesis test of comparing two correlation coefficients? O a. As the sample size increases, the critical value for the z-test will become smaller in absolute value O b. Table D (transformation of r to z) shows that when r is smaller, the corresponding z is very close to r O c. Because r distribution is severely skewed, we can't directly user for the hypothesis test O d. For the computation, the two correlation coefficients should be converted into z-scores first

Answers

The statement that is NOT correct about the hypothesis test of comparing two correlation coefficients is option (b): Table D (transformation of r to z) shows that when r is smaller, the corresponding z is very close to r.

The hypothesis test for comparing two correlation coefficients involves comparing the z-scores of the correlation coefficients. The z-score transformation is used to standardize the correlation coefficients and convert them into a common scale, which allows for easier comparison.

Now let's address each option to understand why the other statements are correct:

a. As the sample size increases, the critical value for the z-test will become smaller in absolute value: This statement is correct. When the sample size increases, the standard error of the correlation coefficient decreases, resulting in a smaller critical value for the z-test. This means that a smaller difference between the correlation coefficients is required to reject the null hypothesis.

c. Because the r distribution is severely skewed, we can't directly use it for the hypothesis test: This statement is also correct. The distribution of correlation coefficients (r) is not normally distributed and tends to be skewed. Therefore, we use the z-score transformation to approximate the distribution of the correlation coefficients to a standard normal distribution, which is symmetrical and suitable for hypothesis testing.

d. For the computation, the two correlation coefficients should be converted into z-scores first: This statement is correct. To compare two correlation coefficients, they need to be transformed into z-scores using the Fisher transformation. This transformation stabilizes the variances and allows for valid hypothesis testing.

In summary, option (b) is the statement that is NOT correct about the hypothesis test of comparing two correlation coefficients.

To know more about hypothesis testing, refer here:

https://brainly.com/question/17099835#

#SPJ11

Which function is nonlinear? A. B. C. D. E.

Answers

The nonlinear function for this problem is given as follows:

C. [tex]y = 2 + 6x^4[/tex]

How to define a linear function?

The slope-intercept equation for a linear function is presented as follows:

y = mx + b.

In which:

m is the slope.b is the intercept.

The exponent of the variable x on a a linear function is given as follows:

1.

For option C, the function has an exponent of 4, hence it is the non-linear function.

More can be learned about linear functions at https://brainly.com/question/15602982

#SPJ1

Find the average value gave of the function
g on the given interval.
g(t) =
t
3 + t2
, [1, 3]
gave =

Answers

To find the average value gave of the function g on the given interval, we need to follow the following steps:First, let's find the definite integral of g(t) over the interval [1, 3].

We know that the indefinite integral of g(t) is given as below:

g(t) = t/3 + (1/2)t² + C

To find the definite integral of g(t) over the interval [1, 3], we will evaluate the integral from the lower limit to the upper limit.∫[1,3]g(t)dt=∫[1,3](t/3+t²/2)dt=[(t²/6)+(t³/6)]| [1,3]

Next, we will substitute the upper and lower limits in the definite integral above and find the difference.

gave = [(3²/6)+(3³/6)]-[(1²/6)+(1³/6)] = [9/2 + 27/2] - [1/6 + 1/6] = 18.

To know more about value visit :

https://brainly.com/question/30145972

#SPJ11

What is the answer to this. ?

Answers

Answer:

-3

Step-by-step explanation:

Parallel lines have equal slopes.

Answer: -3

. Let A be an arbitrary 2 × 2 matrix over a field F. а b - [2 d C - First, prove that A can be row-reduced to the identity matrix if and only if ad bc0. Now, suppose instead ad bc = 0. There are three remaining options for the number and positions of pivots in the RREF of A. What are those options? A -

Answers

If the matrix A is an arbitrary 2 × 2 matrix over a field F, it can be row-reduced to the identity matrix if and only if ad bc ≠ 0. There are three remaining options for the number and positions of pivots in the RREF of A.

Those options are:If A can be row-reduced to the identity matrix, then we can express A in terms of elementary matrices:E1E2...EkA = Iwhere E1, E2, ..., Ek are elementary matrices. We know that elementary matrices are invertible, so the inverse of the product E1E2...Ek is also an elementary matrix, and we haveA = (E1E2...Ek)-1

This shows that A is invertible, since its inverse is a product of elementary matrices. Conversely, if A is invertible, then it can be row-reduced to the identity matrix using elementary row operations. Thus, A can be row-reduced to the identity matrix if and only if ad bc ≠ 0.If ad bc = 0, then we cannot row-reduce A to the identity matrix. However, we can still row-reduce A to a matrix in row echelon form.

There are three possible cases for the number and positions of pivots in the RREF of A, depending on whether a or c is zero.1. If a ≠ 0 and c ≠ 0, then the RREF of A isI* where * can be any nonzero element of F. In this case, A has rank 2.2. If a ≠ 0 and c = 0, then the RREF of A is [1 0 * 0]T, where * can be any element of F. In this case, A has rank 1.3. If a = 0 and c ≠ 0, then the RREF of A is [0 * 1 0]T, where * can be any element of F. In this case, A has rank 1.

To know about row echelon form visit:

https://brainly.com/question/30403280

#SPJ11

The time of concentration of a 5.8ha catchment has been estimated as 33 minutes. Estimate the peak rate of runoff for a storm with an intensity of 49mm/hr and a duration of 22 minutes. Assume the coefficient of runoff as 0.61 and the time-area relationship to be linear. Present the result in the unit of m³/s and keep two decimal points (i.e to the accuracy of 0.01).

Answers

The peak rate of runoff for the given storm can be estimated using the Rational Method. The Rational Method is commonly used to estimate peak runoff rates from a catchment area. The formula for the Rational Method is Q = CiA, where Q is the peak runoff rate, C is the coefficient of runoff, i is the rainfall intensity, and A is the catchment area.

In this case, the catchment area is given as 5.8 hectares, which is equivalent to 58000 square meters. The rainfall intensity is given as 49 mm/hr, which is equivalent to 0.049 m/min. The duration of the storm is given as 22 minutes. The coefficient of runoff is given as 0.61.

To calculate the peak rate of runoff, we can substitute the given values into the Rational Method formula:

Q = 0.61 * 0.049 * 58000
Q ≈ 1698.38 m³/min

To convert the peak rate of runoff to m³/s, we can divide by 60 (since there are 60 seconds in a minute):

Q ≈ 1698.38 / 60
Q ≈ 28.31 m³/s

Therefore, the estimated peak rate of runoff for the given storm is approximately 28.31 m³/s.

Know more about Rational Method here:

https://brainly.com/question/10161292

#SPJ11

An hemispherical tank with a 8m radius is positioned so it's base is circular and raised on 20 m stilts. How much work is required to fill the tank with water through a hole in the base if the water source is at ground level? Your work units will be kNm. (The density of water is given by p= 9.8 kN per m³) water

Answers

The hemispherical tank is positioned so it's base is circular and raised on 20 m stilts. So, to fill the tank with water through a hole in the base, the work required is 210.048 kNm.

Let's discuss the solution. Formula used: Work done = Force × DistanceWork done to fill the tank with water = Force × Distance The force required to lift the water to a height of 20 m is given by:

p = density × gWhere density of water, p = 9.8 kN per m³g = acceleration due to gravity = 9.8 m/s² = 0.0098 kN/s²Hence, p = 9.8 × 0.0098 = 0.09604 kN/m³Force required to lift water to 20 m = p × Volume of water to be lifted to a height of 20 mVolume of water to be lifted to a height of 20 m = Volume of water in the tank

Since the tank is a hemisphere, Volume of the tank = 2/3πr³Volume of water in the tank = 1/2 × 2/3πr³ = 1/3πr³Volume of water to be lifted to a height of 20 m = 1/3πr³Force required to lift water to 20 m = 0.09604 × 1/3πr³ The distance traveled by the water to reach a height of 20 m is the height of the stilts + the height of the tankDistance traveled by the water = 20 + 8 = 28 m

Therefore, work done to fill the tank with water through a hole in the base = Force required to lift water × Distance traveled by the water= 0.09604 × 1/3π(8)³ × 28= 210.048 kNm

Hence, the work required to fill the tank with water through a hole in the base is 210.048 kNm.

To know more about hemispherical visit:

brainly.com/question/32714554

#SPJ11

Let f(x)=x^2and g(x)=x+3

Answers

The function fog(x) is written as x³+ 3x²

How to determine the function

First, we need to know that functions are defined as expressions, rules or laws showing the relationship between two variables.

These variables are listed as;

The dependent variableThe independent variables

From the information given, we have that;

f(x)=x²

g(x)=x+3

To determine the composite function fog(x), we need to multiply the functions in terms of x, we get;

fog(x) = x²( x + 3)

expand the bracket, we have;

fog(x) =  x³+ 3x²

Note that we can no longer add the terms, because they have different powers.

Learn more about functions at:  https://brainly.com/question/11624077

#SPJ1

The complete question :

Let f(x)=x^2and g(x)=x+3. Find fog(x)

Express the vector as a product of its length and direction. √√2 √√2 √√2 Choose the correct answer below. O A. B. C. D. 3 1 √√3 k 1 √₂ 3√3 √√3 √√3 j+ -(i-j+ k) √√3

Answers

The vector `V` can be expressed as a product of its length and direction as:V = |V| * D = √6 * [(1/√3) i + (1/√3) j + (1/√3) k]The correct answer is option C) `3 1 √√3 k`.

Given a vector `V

= √2 √2 √2`, express the vector as a product of its length and direction.The magnitude of the vector `V` can be found using the formula:|V|

= √(x² + y² + z²)where `x`, `y`, and `z` are the respective components of the vector `V`.Thus,|V|

= √(√2² + √2² + √2²)

= √(2 + 2 + 2)

= √6The direction of the vector is obtained by dividing each component of the vector by its magnitude. Thus, the direction vector can be obtained as follows:Let `D` be the direction vector of `V`.Then, the direction vector is given by:D = V / |V|

= (√2/√6) i + (√2/√6) j + (√2/√6) k

Simplifying this we get:D

= (1/√3) i + (1/√3) j + (1/√3) k.

The vector `V` can be expressed as a product of its length and direction as:V

= |V| * D

= √6 * [(1/√3) i + (1/√3) j + (1/√3) k]

The correct answer is option C) `3 1 √√3 k`.

To know more about direction visit:

https://brainly.com/question/30173481

#SPJ11

Other Questions
a client with a 4-day-old lumbar vertebral fracture is experiencing muscle spasms. the nurse avoids using which intervention in an effort to relieve the spasm? notice that real gdp trends upward over time but experiences ups and downs in the short run. these short-run fluctuations in real gdp are often referred to as . true or false: small ups and downs in real gdp follow a consistent, predictable pattern. true false which of the following probably occurred as the u.s. economy experienced increasing real gdp in 1958? check all that apply. consumer spending increased. home sales declined. retail sales increased. industrial production declined. Finding area. (AREA!) and dont forget the label please. THANKS SO MUCH! HD Stations-----------Select the DisplayName and SortOrder from the CHANNEL table for all TV channels where the SortOrder isbetween 700 and 799 inclusive. Use the BETWEEN ... AND ... operator. Exclude all rows where the ExternalIDis NULL. Use "Channel Name" as the header for the name column and "Sort Order" for the sort order column.Display results in ascending order by SortOrder.Hint: The correct answer will have 93 rows and will look like this:Channel Name Sort Order------------ -----------KATUDT 702KRCWDT 703KPXGDT 705KOINDT 706DSCHDP 707KGWDT 708WGNAPHD 709KOPBDT 710VEL 711KPTVDT 712KPDXDT 713FUSEHD 714...UPHD 797AXSTV 798NFLNRZD 799 Rent for a 3 bedroom apartment is regularly $936 per month. Apartment management is offering one month free. If you sign a one year lease and apply the free month equally across months, how much is your new, monthly lease amount Infunctional group identification we can meet challenges? talk aboutone test in particular with a limitation of it. Which equation describes the sum of the vectors plotted below? Cross-Selling Scandal In 2013, rumors circulated that Wells Fargo employees in Southern California were engaging in aggressive tactics to meet their daily cross-selling targets. According to the Los Angeles Times, approximately 30 employees were fired for opening new accounts and issuing debit or credit cards without customer knowledge, in some cases by forging signatures. "We found a breakdown in a small number of our team members," a Wells Fargo spokesman stated. "Our team members do have goals. And sometimes they can be blinded by a goal." According to another representative, "This is something we take very seriously. When we find lapses, we do something about it, including firing people." Some outside observers alleged that the bank's practice of setting daily sales targets put excessive pressure on employees. Branch managers were assigned quotas for the number and types of products sold. If the branch did not hit its targets, the shortfall was added to the next day's goals. Branch employees were provided financial incentive to meet cross-sell and customer-service targets, with personal bankers receiving bonuses up to 15 to 20 percent of their salary and tellers receiving up to 3 percent. Tim Sloan, at the time chief financial officer of Wells Fargo, refuted criticism of the company's sales system: "I'm not aware of any overbearing sales culture." Wells Fargo had multiple controls in place to prevent abuse. Employee handbooks explicitly stated that "splitting a customer deposit and opening multiple accounts for the purpose of increasing potential incentive compensation is considered a sales integrity violation." The company maintained an ethics program to instruct bank employees on spotting and addressing conflicts of interest. It also maintained a whistleblower hotline to notify senior management of violations. Furthermore, the senior management incentive system had protections consistent with best practices for minimizing risk, including bonuses tied to instilling the company's vision and values in its culture, bonuses tied to risk management, prohibitions against hedging or pledging equity awards, hold- past retirement provisions for equity awards, and numerous triggers for clawbacks and recoupment of bonuses in the cases where they were inappropriately earned. Of note, cross-sales and products-per- household were not included as specific performance metrics in senior executive bonus calculations even though they were for branch-level employees. QUESTION: a) Identify the stakeholders in the above case and how does it affect each of the stakeholders. Write an equation relating the volume of a cube, V , and an edge of the cube, a. Differentiate both sides of the equation with respect to t. dtdV=( dtda(Type an exprossion using a as the variable.) The rate of change of the volume is (Simplify your answer.) Which of the following is not included in the cost of merchandise inventory? O Purchase discounts. O Purchase returns and allowances. O Purchase price of the inventory. O Freight costs paid by the seller. O Freight costs paid by the buyer. 4 pts 0 Question 2 Sunshine Cleaning purchased $3,500 worth of merchandise. The seller offered a 2% cash discount. Transportation costs for the buyer were an additional $310. The company returned $240 worth of merchandise and then paid the invoice within the discount period. The total cost of this merchandise is: O $3.570.00. O $3,500.00 O $3,332.00 O $3,430.00. $3,504.80 Question 5 A company has not sales of $759.300 and cost of goods sold of $548.300. Its not income is $10.280. The company's gross margin and operating expenses, respectively, are: O $211.000 and $230,750 $739.550 and $191,720 O $529,020 and $230.750 O $211.000 and $191,720 $230,750 and $529,020 4 pts D D Question 5 A company has not sales of $750,300 and cost of goods sold of $548,300. Its not income is $10.280 The company's groas margin and operating expenses, respectively, arm O $211,000 and $230,750 O $739,550 and $191,720 $529,020 and $230,750 O $211.000 and $191,720 O $230.750 and $529,020 Question 6 Sales less sales discounts, less sales returns and allowances equals: Cost of Goods Sold Net Income O Net Sales O Gross Profit 4 pts 4 pts Goods in transit are included in a purchaser's inventory: O At any time during transit. O After the half-way point between the buyer and seller, When the supplier is responsible for freight charges. When the goods are shipped FOB shipping point. OIf the goods are shipped FOB destination. Question 11 The inventory costing method that smooths out erratic changes in costs is: O LCM. O FIFO. OLIFO. O Specific Identification. O Weighted average. 4 t ne 0 Question 12 Krusty Krab has the following products in its ending inventory Compute lower of cost or market for inventory. applied separately to each product Inventory by Product Product Quantity Cost per Unit 500 $ 500 $ 30 600 Scuba Masks Scuba Sults O $265,000 O $290,000. O $250,000 $268,000 O $275,000. Question 13 Market per Unit $ 550 $ 25 If equity is $368,000 and liabilities are $186,000, then assets equal: O $554,000. $922,000. $368,000. $186,000. O $182,000. 2 pts Assuming Base and Derived classes are designed appropriately, and basePtr and derivedPur are pointing to objects of their respective classes, which of the following lines of code will result in slicing? a. derivedPtr = basePtr b. basePtr = derivedPtr c. *derivedPtr = *basePtr d. *basePtr = *derivedPtr (3 pts) Given two classes, Car and Person, we should understand that a Person might have multiple cars and cars can transfer between People. How would you model this relationship? a. Inheritance b. Polymorphism c. A Car object inside the Person class d. A Person pointer inside the Car class Suppose a broker offers you an investment that will provide the following future cash flows: $1000 in exactly 1 year $2000 in exactly 2 years $4000 in exactly 3 years $8000 in exactly 4 years Your broker tells you that you will receive an average return of 13.46% if you pay $10,000 for this investment today. Suppose that y A. You consider the current price of $10,000 to be too expensive. B. You would be willing to pay more than $10,000 today for these exact future cash flows. C. You would pay $10,000, but only if the future cash flows are higher. D. It is impossible to calculate the value of these cash flows. Reset Selection Mark for Review What's This? RNAi is a very powerful potential therapeutic because: Select one: O a. Is readily available commercially O b. The people who discovered it won a Nobel Prize O c. It functions in the mitochondria O d. O e. It is easy to deliver to cells It can be used to turn off the expression of a specific gene Non-viral gene delivery systems are better than viral delivery systems because: Select one: O a. They are bigger than cells Ob. They can enhance the immune response directed towards the therapeutic gene Oc. They can be tailored to be non immunogenic Od. They are copying a system that is seen in nature . They can be altered genetically Find an equation of the tangent line to the graph of the function at the given point. g(x) = ex5 - 6x (-1, e5) I y = The population of a small city is 68,000. 1. Find the population in 23 years if the city declines at an annual rate of 1.9% per year. people. If necessary, round to the nearest whole number. 2. If the population declines at an annual rate of 1.9% per year, in how many years will the population reach 30,000 people? In years. If necessary, round to two decimal places. 3. Find the population in 23 years if the city's population declines continuously at a rate of 1.9% per year. people. If necessary, round to the nearest whole number. 4. If the population declines continuously by 1.9% per year, in how many years will the population reach 30,000 people? In years. If necessary, round to two decimal places. 5. Find the population in 23 years if the city's population declines by 1720 people per year. people. If necessary, round to the nearest whole number. 6. If the population declines by 1720 people per year, in how many years will the population reach 30,000 people? In years. If necessary, round to two decimal places. Consider the following system of gas-phase reactions: 1/2 A X rx = kC\/2k = 0.004(mol/dm) 1. min B=KCA K=0.3 min- A B A Y ry=k3C_k=0.25 dm/mol - min B is the desired product, and X and Y are foul pollutants that are expensive to get rid of. The specific reaction rates are at 27C. The reaction system is to be operated at 27C and 4 atm. Pure A enters the system at a volumetric flow rate of 10 dm/min. 10 11 (g) If you could vary the pressure between 1 and 100 atm, what pressure would you choose? A flare is used to convert unburned gases to innocuous products such as CO and HO. If a gas with the following composition is burned in the flare 70%CH, 5%CH, 15 % CO, 5%0, 5%N 2 and the flue gas contains 7.73%CO, 12.35%HO and the balance is O and N. What is the percent excess air used? Find the value of an investment of $10,000 for 14 years at an annual interest rate of 3.85% compounded continuously. The value of the investment is____. An unpipelined processor takes 6 ns to work on one instruction. It then takes 0.1 ns to latch its results into latches. When we convert the circuits into 4 sequential pipeline stages, the stages have the following lengths: 0.7ns; 1.3ns; 1.4ns; 0.9ns. Assuming that there are no stalls in the pipeline, what is the cycle time in the unpipelined and pipelined processors? O Unpipelined = 6 ns, Pipelined = 1.4 ns Unpipelined =6.1 ns, Pipelined = 1.5 ns O Unpipelined =6 ns, Pipelined = 1.5 ns Unpipelined =6.1 ns, Pipelined = 1.1 ns Unpipelined =6 ns, Pipelined = 1 ns None of the above -AA1992 In your own words, explain why using the "future-self" with a client is helpful. What are the benefits? What does it help your client be able to do?Please describe the following coaching technique hats a coach could wear to help a client: a) Motivational Interviewing (MI), b) Appreciative Inquiry (AI), and, c) Nonviolent Communication (NVC). Briefly describe each.Tell me how each of these coaching methods can be useful to anyone if they incorporate them into coaching. (Please give one concrete example, idea or strategy for each).