Answers
Answer:
C.) Csp² - Nsp³
Explanation:
Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).
The hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
What is hybridization?Hybridization is defined as the concept of the mixing of the atomic orbitals for the formation of new hybrid orbitals which are suitable for the pairing of electrons in forming chemical bonds in valence bond theory. And the orbital formed by the hybridization are termed as hybrid orbitals.
Since the carbon atom form one single bond with hydrogen atom and one pi bond with nitrogen bond, so the conformation of carbon atom is Csp2. On the other hand, nitrogen also form one single bond and a pi bond, so it also contribute three hybrid orbital. Since it have one lone pair of nitrogen so they take one orbitals. Therefore, the conformation of nitrogen atom is Nsp3.
Thus, we concluded that the hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
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Related Questions
A 1dm3 solution was made by mixing 0.0040 mol of HCl(aq) and 0.0025 mol of NaOH(aq). What was the pH of the resulting solution?
Answers
The pH of the resulting solution is 2.82.
What is pH ?pH is the measure of acidity and alkalinity of a solution , It has a range of 1 to 14.
HCl + NaOH → NaCl + H₂O
0.0040 .0025 0 0
0.0040 -0.0025 0 0.0025 0.0025
Moles of HCl = 0.0015
As 0.0025 moles of NaOH reacts with 0.0025 moles of HCl leaving behind 0.0015 moles of HCl
Concentration of HCl = 0.0015/ 1 = 0.0015 M
[ H⁺] = 0.0015 M
pH = -log [ H⁺]
pH = -log [ 0.0015]
pH = 2.82
Therefore the pH of the resulting solution is 2.82.
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BaCl2(aq)+Na2SO4(aq)⟶BaSO4(s)+2NaCl(aq)
Using the balanced chemical equation, determine how many moles of NaCl will be produced, if 0.731 mol of BaCl2 is allowed to react with an excess of Na2SO4.
Answers
Answer:
1.46 moles NaCl
Explanation:
To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.
1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)
0.731 mole BaCl₂ 2 moles NaCl
--------------------------- x ------------------------- = 1.46 moles NaCl
1 mole BaCl₂
If 0.731 mol of BaCl₂ is allowed to react with an excess of Na₂SO₄, 1.462 moles of NaCl will be produced.
The balanced chemical equation is:
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)
The mole ratio of BaCl₂ to NaCl is 1:2. This means that 1 mole of BaCl2 will produce 2 moles of NaCl.
Moles of BaCl₂ = 0.731 mol
Mole ratio BaCl₂:NaCl = 1:2
Moles of NaCl = 0.731 mol * 2 = 1.462 mol
If we have 0.731 moles of BaCl₂, then we will produce 2 * 0.731 = 1.462 moles of NaCl.
Therefore, 1.462 moles of NaCl will be produced.
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When did China's earliest civilization originate?
Answers
Answer:
The Chinese civilization really has an exact chronology, and the historical period began in the first year of the Western Zhou Dynasty in 841 BC. Before that, only the lineage records of the kings were recorded. Therefore, the earliest origin of Chinese civilization has not yet been finalized. Although there are many records about the Xia Dynasty in the traditional literature, due to the late completion of the book, there is no recognized evidence of the existence of the Xia Dynasty and its previous history. Therefore, some people in the modern and modern historical circles have always questioned the existence of the Xia Dynasty. sex.
Explanation:
What is the volume occupied by 14.3 g of argon gas at a pressure of 1.35 atm and a temperature of 436 K?
Answers
Answer:
9.487 L
Explanation:
argon mole wt = 39.948 gm/mole
14.3 gm / 39.948 gm/mole = .357965 moles of argon
Use Ideal Gas Law:
PV = n RT where R = .082057 L-atm / K-mol
V = .357965 * .082057 * 436 / 1.35 = 9.487 L
