Which is a property of all bases?

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 7O2 = 4CO2 + 6H20      A  

3. C3H8 + 502 = 3CO2 + 4H20            C

To find the appropriate end products, use the following rules

Thus for equation;

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 2O2 = 4CO2 + 6H20      A  

3. C2H8 + 502 = 2CO2 + 4H20            C  

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M = n/V

V = n/M

V = (14.5 : 56.1056)/2.8

V = 0.0923 L = 92.3 mL

Answer:

D.) It has a negative charge and is located in orbitals around the nucleus.

Explanation:

Electrons always have a negative charge. Since electrons can be shared or donated/received, they must be located in the orbitals around the nucleus. Protons, which have a positive charge, and neutrons, which are neutral, are  located in the nucleus.

Assuming pressure is held constant,

[tex]\frac{8}{3}=\frac{V_{2}}{4}\\\\V_{2}=4\left(\frac{8}{3} \right) \approx \boxed{10.7 \text{ L}}[/tex]

Answer:

A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.

The outer shell of a non-metal is, therefore, more than half full of electrons.

Answer: 50.806 cm is the correct answer.

Explanation: First divide 6104.5 cm^2 by 22.3 cm.

[tex]\frac{6104.5cm^2}{22.3cm} = 273.74 cm[/tex]

*Note: When dividing units, subtract the exponents, and when multiplying units simply add the exponents.

Then continue by subtracting 324.55 cm - 273.74 cm.

This should give you an answer of 50.806 cm.

Answer:

Explanation:

A

c option is correct answer

Atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

Atomic radius decreases across a period because of nuclear charge increases whereas atomic radius of atoms generally increases from top to bottom within a group because there is again an increase in the positive nuclear charge.

Ionization energy increases when we move from left to right across an period and decreases from top to bottom.

Electronegativity also increases from left to right across a period and decreases from top to bottom.

So we can conclude that atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

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Answer:

The answer is B an open system allows energy and mass to move in and out of it

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Answer:

2 Hg (g) + o2 ---> 2 H2o

equilibrium constant

K = (c) (d) / (a)(b)

K= ( H2o)²/(He) ²(o2)

350 Kcal is equals to 350000 calorie and 1464400 Joule.

The equation for calculating the energy content of a food source via calorimetry is as follows: Energy (joules) = Mass of water (g) × 4.2 (J/gºC) × Temperature increase (ºC)

1 Kcal = 1000 calorie

Therefore,

35 Kcal = 350 x 1000

            = 350000 calorie

Now,

1 calorie = 4.184 joule

Therefore,

35000 calorie = 350000 x 4.184

                        = 1464400 joule

Hence, 350 Kcal is equals to 350000 calorie and 1464400 Joule.

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Answer:

A and B

Explanation:

A is crust

B is mantle

The heat that creates this temperature change coming from change in the internal energy of the system as per as first law of thermodynamics.

A law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

As we know, Boyle's law only works when the gas is kept at a constant temperature

Here,

When volume of gases decreased, it means work done has occurred on the system, so the work done is used for raising internal energy of the gas and the other is released as the thermal energy.

So,

According to 1st law of thermodynamics,

we know  Q =  ΔU + W  i.e, change in internal energy and work done. So this is a reason. Changing temperature occurs.

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Answer:

A

Explanation:

The error caused will lower the number of moles when he did not do the second heating.This question is related to the empirical formula.

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

The empirical formula is the simplest ratio of atoms in a given compound.

we know that heating is used to eliminate most of the water molecules which are attached to the compound in the question, it's given that the second heating was not performed by the students.

This means that there are still some water molecules attached to the compound. This will imply that higher mass will be calculated for the compound because the water molecules are also considered.

So now, if we look at the calculation for the number of moles of water in this, we can say that this will be lower than the actual amount.

This is because there are some unaccounted moles of water which are still attached to the compound and these will be accounted in the compound mass rather than the waters. Therefore, the number of moles will be lower.

Hence, The error caused will lower the number of moles when he did not do the second heating.

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Answer: A. Wearing loose comfortable clothing so you can concentrate on the lab.

Explanation:

Wearing loose clothing can make it cling onto certain things, which could create a spill or a different hazard. B, C, and D are all things you SHOULD be doing to achieve safe lab behavior.

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Answer: The true volume of the gas will be lower than predicted by the ideal gas law because the volume of the actual particles is more significant under high pressure.

180.189 g was the mass of the zinc sample with a specific heat of zinc is 0.390 j/g°C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Using specific heat capacity formula here:

[tex]C_{Zn}[/tex] × [tex]m_{Zn}[/tex]×  Δ[tex]T_{Zn}[/tex] = [tex]C_{H_2O}[/tex]× [tex]m_{H_2O}[/tex] ×  Δ[tex]T_{H_2O}[/tex]

0.390J/g°C × [tex]m_{Zn}[/tex] ×77.4ºC = 4.184J/g°C×  65.0g ×  20.00ºC.

[tex]m_{Zn}[/tex] = 180.189 g

Hence, 180.189 g was the mass of the zinc sample.

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Answer:

The two that are true are, "this represents a pure compound in two different states" and "it represents a mixture a solid and a gas".

Explanation:

This two are concluded only from the picture and the use of uniform colors throughout the picture (Showing the same element).

Answer:

OOO

Explanation:

OOOOOO

Answer:

0.217 ×2. =9.86×10moles

44

Running blades is the controversial prosthetics which may confer an athletic advantage over able-bodied runners.

This is also referred to as running prosthetics which allows someone move faster with less effort.

This happens when top speed has been achieved and offers an advantage over able-bodied runners.

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C= 87.8 : 12 = 7.316

H= 12.2 : 1 = 12.2

C : H = 1 : 1.667 =  3 : 5

C₃H₅

Answer:

A real gas will act as an ideal gas under high temperature and at a low pressure.

Real gases are non-ideal gases whose molecules occupy space and have interactions, consequently, they do not adhere to the ideal gas law.

An ideal gas has molecules that occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Explanation:

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of [tex]SO_2[/tex] molecules in 9.87 moles  [tex]SO_2[/tex] is 59.43 molecules.

The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe is 0.23 x [tex]10^{-1}[/tex]

The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex] is 3.81.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × [tex]10^{23}[/tex] x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of [tex]SO_2[/tex] molecules in 9.87 moles of [tex]SO_2[/tex]:

6.02214076 × [tex]10^{23}[/tex] x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe:

1.40 x [tex]10^{22}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

0.2324754694 x [tex]10^{-1}[/tex] moles.

0.23 x [tex]10^{-1}[/tex] moles.

D. The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex]:

2.30x[tex]10^{24}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

3.819239854 moles=3.81 moles

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Answer:

1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left

Explanation:

Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.

Adding a catalyst has no effect on equilibrium reactions.

When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.

Answer:

4.458 L

Explanation:

Assuming the pressure remains constant  and assuming 24° C and 58° C

V1/T1  = V2/T2       Where T is in Kelvin

V1/T1  *  T2  = V2

4 / ( 273.15 +24)    *    ( 273.15 + 58)    =  4.458 L

The combustion of lauric acid is shown as CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

In a combustion reaction, a substance is burnt in oxygen. If the substance is an organic compound a the case is here, the products are carbon dioxide and hydrogen.

No the equation of the combustion of lauric acid is shown as;

CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

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