Theta Company has the following variances at the end of February:
Material Price Variance $40 Unfavorable
Material Usage Variance $225 Unfavorable
Labor Rate Variance $110 Unfavorable
Labor Efficiency Variance $335 Unfavorable
What is the journal entry to be passed by Theta Company at the end of the month of February to close the variances?
Answer:
Debit Cost of Goods Sold $710
Credit Material Price Variance $40
Credit Material Usage Variance $225
Credit Labor Rate Variance $110
Credit Labor Efficiency Variance $335
Step-by-step explanation:
Preparation of the journal entry to be passed by Theta Company at the end of the month of February to close the variances
Debit Cost of Goods Sold $710
($40+$225+$110+$335)
Credit Material Price Variance $40
Credit Material Usage Variance $225
Credit Labor Rate Variance $110
Credit Labor Efficiency Variance $335
(To close the variances)
At what age do babies learn to crawl? Does it take longer to learn in the winter when babies are often bundled in clothes that restrict their movement? Data were collected from parents who brought their babies into the University of Denver Infant Study Center to participate in one of a number of experiments between 1988 and 1991. Parents reported the birth month and the age at which their child was first able to creep or crawl a distance of 4 feet within 1 minute. The resulting data were grouped by month of birth: January, May, and September:
Answer:
Babies learn to crawl between age of 6 to 10 months.
Step-by-step explanation:
It may take longer for babies to crawl in winter season since the climate restricts the babies movement due to extra clothes. The babies who are born in summer will learn crawling earlier than those who are born in winter season.
The graph shown below expresses a radical function that can be written in
17
the form f(x) = a(x + k)!
C. What does the graph tell you about the
value of k in this function
Answer:
C. [tex]k[/tex] is greater than zero.
Step-by-step explanation:
We know that graph is obtained from the function of the form [tex]f(x) = a\cdot (x+k)^{1/n} + c[/tex]. According to the graph and if [tex]x + k = 0[/tex], we find that:
[tex]x = -k[/tex] (1)
[tex]x < 0[/tex] (2)
By (1) and (2):
[tex]-k < 0[/tex]
[tex]k > 0[/tex]
Hence, correct answer is C.
Find the measure of the missing angles.
Answer:
e = 41 , f = 139 and d = 90
Step-by-step explanation:
?
We know that vertically opposite angles are equal.
So, e = 41° [Vertically opposite angles]
We know that linear pair of angles are supplementary (180°).
So, f + 41° = 180° [Linear pair of angles]
=> f = 180° - 41°
=> f = 139°
and d + 90° = 180° [Linear pair of angles]
=> d = 180° - 90°
=> d = 90°
HELP! PLEASE!!
Simplify the expression.
9514 1404 393
Answer:
D
Step-by-step explanation:
Regrouping the factors, we have ...
I really need the help please and thank you
BBBBB BBBBBBBBBBBBBBBBBBBBBBBBBBBB
Which is the sum of the sequence {5*1, 5*8, 5*27, 5*64, 5*125, 5*216}?
Answer:
2160
Step-by-step explanation:
I find that it is easier to split the sequence into smaller, more manageable sections. For numbers beyond 13, the simplest way is to split it up into place values.
Note: * is a multiplication symbol
5*1 = 5
5*8 = 40
5*27 = (5*20) + (5*7) = 100+35 = 135
5*64 = (5*60) + (5*4) = 300+20 = 320
5*125 = (5*100) + (5*20) + (5*5) = 500+100+25 = 625
5*216 = (5*200) + (5*10) + (5*6) = 1000+50+30=1080
Now you can add all of the totals up!
135+320+625+1080 = 2160
Which side is the “adjacent” side to θ?
Answer:
third answer "a"
Step-by-step explanation:
Let T:R²->R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)
compute T(3,3) pls help me
Answer:
(-4,-1)
Step-by-step explanation:
We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.
This implies for scalars a and b that
T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)
T((a,2a)+(-b,b))=a(-1,1)+b(2,3)
T((a-b,2a+b))=(-a,a)+(2b,3b)
T((a-b,2a+b))=(-a+2b,a+3b)
This means we should be able to solve the system below to find a and b for T(3,3):
a-b=3 and 2a+b=3
Add equations to eliminate b and solve for a:
3a=6
Divide 3 on both sides:
a=2
If a-b=3 and a=2, then b=-1.
Plug in a=2, b=-1:
T((a-b,2a+b))=(-a+2b,a+3b)
T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)
T(3,3)=(-4,-1).
