Which is the correct answer

Which Is The Correct Answer

Answers

Answer 1

The correct product of the above nuclear reaction is 221/87 Fr (option C).

What is a nuclear reaction?

A nuclear reaction is the process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

In a nuclear reaction, the reaction products may contain a different element or a different isotope of the same element.

Alpha decay is a specific type of nuclear reaction in which an alpha particle made up of helium-4 atom (consisting of two protons and two neutrons), is emitted.

According to this question, the nuclear reaction (alpha decay) of an atom with mass number 225 and atomic number 89 is given. To find the mass number and atomic number of the product, we subtract 4 and 2 respectively.

225 - 4 = 22189 - 2 = 87

Therefore, option C is correct.

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Related Questions

Please answer the question.

Answers

Answer:

Explanation:

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A hiker walks 27.0 km from her base camp at 35° south of east. The next day, she walks 41.0 km in a direction 65° north of east and discovers a forest ranger's tower. Find the magnitude and direction of her resultant displacement between the base camp and the tower.

Answers

The magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

How to find the magnitude and direction?

To find the magnitude and direction of the hiker's resultant displacement, we can use vector addition.

First, we need to convert the given magnitudes and directions into x and y components. We can use trigonometry to do this:

x component of the first displacement = 27.0 km * cos(35°) = 21.5 km

y component of the first displacement = 27.0 km * sin(35°) = 15.5 km

x component of the second displacement = 41.0 km * cos(65°) = 17.6 km

y component of the second displacement = 41.0 km * sin(65°) = 30.6 km

Now we can add the x and y components of each displacement to find the x and y components of the resultant displacement:

x component of the resultant displacement = 21.5 km + 17.6 km = 39.1 km

y component of the resultant displacement = 15.5 km + 30.6 km = 46.1 km

To find the magnitude of the resultant displacement, we can use the Pythagorean theorem:

magnitude of the resultant displacement = sqrt(39.1 km^2 + 46.1 km^2) = sqrt(1820.81 km^2) = 42.7 km

Finally, we can use the arctangent function to find the direction of the displacement:

direction = arctan(46.1 km / 39.1 km) = 64.6° north of east.

So the magnitude and direction of the hiker's resultant displacement is 42.7 km, 64.6° north of east.

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how long will it take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply . Specific Heat capacity of water is 400 joules per kilogram kelvin. I need this ASAP! .I'll mark brainliest ​

Answers

Answer:

1.5 minutes

Explanation:

To find out how long it will take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle, we can use the equation:

Q = mcΔT

Where Q is the heat energy added, m is the mass of the water, c is the specific heat capacity of water and ΔT is the change in temperature.

The heat energy added to the water can be calculated as:

Q = (5 kg) x (400 J/kg·K) x (88°C - 28°C) = (5 kg) x (400 J/kg·K) x (60°C) = 120000 J

The power of the electric kettle can be calculated using the formula:

P=VI

where P is the power, V is the voltage and I is the current,

P = (220 V) x (6 A)

= 1320 W

Now we can calculate the time it takes to heat the water by dividing the heat energy added by the power:

time = Q/P = 120000 J / 1320 W

= 90.909 seconds or 1.5 minutes

It will take 1.5 minutes to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply.

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Define the term " relative permittivity " ​

Answers

Answer:

Relative permittivity describes the ability to polarize a material subjected to an electrical field.

Explanation:

This polarization originates from a number of sources:

- electron cloud displaced relative to nucleus

- relative displacement of charged ions

- alignment of dipoles in electric field

- movement of charge carriers trapped by interfaces in heterogeneous systems

- movement of ionic charges

In simple terms, relative permittivity tells us how well a material can hold an electric charge. A material with a high relative permittivity can hold more electric charge than a material with a low relative permittivity.

To test the performance of its tires, a car
travels along a perfectly flat (no banking) circular track of radius 96.6 m. The car increases
its speed at uniform rate of
at ≡((d |v|)/dt) = 4.87 m/s^2
until the tires start to skid.
If the tires start to skid when the car reaches
a speed of 21.1 m/s, what is the coefficient of
static friction between the tires and the road?
The acceleration of gravity is 9.8 m/s^2

Answers

The coefficient of  static friction between the tires and the road is 1.987.

What is Static friction?

Radius of the track, r =  516 m, Tangential Acceleration =  3.89 m/s^2 and Speed,v =  32.8 m/s

The radial Acceleration is given by, Now the total acceleration is The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is, From (1) and (2), Substituting the values, we get friction is 1.987.

Therefore, The coefficient of  static friction between the tires and the road is 1.987.

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A 40kg metal slab at temperature 6000C is taken from a furnace and plunged into 300kg of oil originally at 250C. The final temperature of the oil/slab is 400C. Determine the specific heat capacity of the metal if that of oil is 2100J/kg.0C.

Answers

Answer:

I need this message as well so please ket me know when you have it

what is the gravitational force between the earth and the moon

Answers

Answer:

1.98×1020 N 1.98 × 10 20 N

Explanation:

The gravitational force between the Earth and the Moon is 1.98×1020 N 1.98 × 10 20 N.

1. At what displacement the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm?​

Answers

The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.

How does the amplitude of simple harmonic motion affect the ratio of kinetic to potential energy at a specific displacement?

The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.

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Reginald Esuke from Cameroon ran down a mountain slope in just 62.25 min. How much work was done if the power developed during Esuke's descent was 585.0 W?​

Answers

The mountain slope is 585.0 W multiplied by 62.25 min, which is 36,378.75 joules.

What is slope?

Slope is a measure of the steepness of a line. It is calculated by finding the ratio of the vertical change to the horizontal change between any two points on a line. Slope is represented by the letter m and is calculated by the equation m= (y2-y1)/(x2-x1). If the line is going up from left to right, the slope is positive. If the line is going down from left to right, the slope is negative. Slope is an important concept in mathematics, especially in calculus and linear algebra. It is used to find the rate of change between two points, as well as to determine the equation of a line.

The amount of work done is equal to the power developed multiplied by the time elapsed. Therefore, the work done by Reginald Esuke during his descent down the mountain slope is 585.0 W multiplied by 62.25 min, which is 36,378.75 joules.

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Several vectors in the x-y plane are shown in the figure with their tails at the origin of the coordinate system and with a label at their heads. Two of these vectors are given in terms of the unit-vectors i and j as P = (2.80i + 2.30j) and Q = (-3.90i + 1.20j), where the numbers are measured in meters. Let M = (P+Q). Calculate the magnitude of the vector M.

Answers

Several vectors in the x-y plane are shown in the figure with their tails at the origin of the coordinate system and with a label at their heads.The value of M = (P+Q) is

3.65 meters

What is magnitude?

Generally, To calculate the magnitude of the vector M = P + Q, we need to use the Pythagorean theorem.

M = P + Q

M= (2.80i + 2.30j) + (-3.90i + 1.20j)

M= (-1.10i + 3.50j)

The magnitude of the vector M is the square root of the sum of the squares of the x and y components of the vector.

|M| = √((-1.10)^2 + (3.50)^2)

= √(1.21 + 12.25)

= √13.46

≈ 3.65 meters

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A roller coaster is moving at 25 m/sec at the bottom of a hill. Three seconds later it reaches the top of the next hill, moving at 10m/sec. What is the acceleration (negative acceleration is slowing down) of the roller coaster?

Answers

Acceleration is the rate of change of velocity. It can be calculated using the formula:

a = (vf - vi) / t

Given:

vi = 25 m/s (initial velocity)

vf = 10 m/s (final velocity)

t = 3 s (time interval)

a = (vf - vi) / t = (10 m/s - 25 m/s) / 3 s = -15 m/s^2

The acceleration of the roller coaster is -15 m/s^2.

Negative acceleration indicates that the roller coaster is slowing down. This means that the roller coaster is losing speed as it reaches the top of the hill. The roller coaster is decelerating (negative acceleration) while it climbs the hill, so that it can move with a lower velocity at the top of the hill.

Write down suitable function of p and q which could be plotted against each other so as to obtain straight line graph in the following cases: (a) Q= ap^n (b) Q^m=ap^n

Answers

Answer:

Explanation:

(a) Q=ap^n

Function of p and q:

p = q^(1/n)

(b) Q^m=ap^n

Function of p and q:

p = (q^(1/m))^(1/n)

An object travels from (4,0) to (0,4) along path defined by x
2
+y
2
=16 under the applied force is
F
=(
x
2
+y
2

1

)i+(
x
2
+y
2

4

)j. Find the work done using the differential form of the work integral. Clearly show the work integral.

Answers

The work done on an object moving from position (x1, y1) to (x2, y2) under an applied force F is given by the work integral:

W = ∫ F ⋅ dr

where dr is the displacement vector from position (x1, y1) to (x2, y2).

For the given scenario, the applied force is F = (x^2 + y^2)i + (x^2 + y^2)^(1/2)j, and the displacement is from (4,0) to (0,4), which is given by dr = (-4, 4)i + (0, 4)j.

So, the work done is:

W = ∫ F ⋅ dr = ∫ ((x^2 + y^2)i + (x^2 + y^2)^(1/2)j) ⋅ ((-4)i + (4)j)

= ∫ -4x^2 - 4y^2 + 4(x^2 + y^2)^(1/2) dx

This work integral cannot be solved in closed form and will require numerical methods to evaluate the definite integral.

Momentum Principle please help

Answers

The momentum of the ball is

(-0.18, -0.40, 0.20)m

What is momentum?

Generally, The momentum principle, also known as Newton's second law of motion, states that the rate of change of momentum of an object is equal to the force applied to it. Mathematically, this can be expressed as:

F = d(mv)/dt

where

F is the force applied, m is the mass of the object, v is the velocity of the object, and t is time.

To determine the position of the ball 0.1 seconds later, we need to know the force acting on the ball due to the elastic band. This force is given by Hooke's Law, which states that the force acting on an object due to a spring is equal to the spring constant (k) multiplied by the displacement of the spring from its relaxed position. In this case, the spring constant is 0.9 N/m, and the displacement is the difference in length between the relaxed length (0.3 m) and the current length of the elastic band.

We know that the ball is at location (-0.2, -0.61, 0)m relative to the point where the elastic band is attached to the paddle. We can find the length of the elastic band by using the distance formula:

√((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2 ) = √((-0.2 - 0)^2 + (-0.61 - 0)^2 + (0 - 0)^2 )

= √(0.04 + 0.3721 + 0)

= √0.4121

= 0.63874m

The displacement of the spring is the relaxed length (0.3 m) minus the current length of the elastic band (0.63874 m), which is -0.33874 m. The force acting on the ball due to the elastic band is

-0.9 * -0.33874 = 0.30486 N.

We can use the force to find the acceleration of the ball using Newton's second law,

F = ma.

Since the mass of the ball is 0.015 kg, the acceleration of the ball is

0.30486 N / 0.015 kg = 20.324 m/s^2

We can use this acceleration to find the final velocity of the ball using the equation vf = vi + at.

Since the initial velocity of the ball is

(-0.02, -0.01, -0.02) kg-m/s, the final velocity of the ball is

(-0.02, -0.01, -0.02) + (20.324, 20.324, 20.324) * 0.1 s = (-0.02, -0.01, -0.02) + (2.0324, 2.0324, 2.0324)

= (2.0124, 2.0224, 2.0124) m/s

The final position of the ball can be found using the equation

xf = xi + vt.

The initial position of the ball is (-0.2, -0.61, 0)m and the final velocity is (2.0124, 2.0224, 2.0124) m/s, so the final position of the ball after 0.1 s is

(-0.2, -0.61, 0) + (2.0124, 2.0224, 2.0124) * 0.1 s

= (-0.2, -0.61, 0) + (0.20124, 0.20224, 0.20124)

= (-0.18, -0.40, 0.20)m

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You weigh 660 N.
What would you weigh if the Earth were
two times as massive as it is and its radius
were five times its present value?
Answer in units of N.

Answers

At a mass that is 2 times the current earth and a radius 5 times its value, your weight will be 52.8 N.

How do you find the new weight of the body?

In general, we can assume a gravitational force of the following magnitude for any planet or mass:

[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

where G = 6.67 x 10⁻¹¹m³/kgs², a universal gravitational constant.

m = masses of objects

r = radius of objects.

Given that W = 660 N

m₁ = 2Me, new mass of earth

r = 5re, new radius of earth

Then [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

Since [tex]F = \frac{GM m}{r^{2} }[/tex]

Substituting both new mass and radius;

[tex]F = \frac{G(2M_{E}) m}{(5r_{E})^{2}}[/tex]

[tex]F = \frac{2}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]

Using the equation that  weight is [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]

[tex]F = \frac{2}{25}(660 N)[/tex] = 0.08 x 660 N

F = 52.8 N

Since the earth is 5 times its radius and twice its mass a weight of 650N will become 52.8 N.

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- The same mass of 5 different substances was used to heat the same mass of water in a simple
calorimeter. The results are shown below. Based on these results, which of these substances made
the worst fuel?

Answers

Answer:

Substance       ΔH (kJ/g)

Coal               -40.23

Hydrogen           -242.82

Methanol           -252.45

Octane               -43.99

Propane             -214.46

Explanation:

Methanol made the worst fuel because it has the lowest ΔH value of -252.45 kJ/g, which means that it releases the lowest amount of energy when used as a fuel. The other substances have higher ΔH values, so they produce more heat energy when burned.

A net force always result in a ________

Answers

Answer:

Explanation:

______?

Net forces always result in an acceleration. Newton's Second Law of Motion states that a net force (the sum of all forces acting on an object) will cause an object to accelerate in the same direction as the net force. The acceleration is proportional to the magnitude of the net force and inversely proportional to the mass of the object.

Answer:

A net force always result in a acceleration

Daniel asks you to move the tables in his room. If there was no friction, you would have to push at 12 N to move the table. But there is no friction! Friction exerts a force of 3 N. You are only able to push at 7 N, so you get a friend to help. What force does your friend need to push to move the table?

Answers

Scene: Daniel is standing in his room, looking at the furniture. He turns to the camera.

Daniel: Hey there! I need some help moving the furniture in my room. It's too heavy for me to move by myself, so I'll need you and a friend to help me out. Let me explain what's needed.

If there was no friction involved, I would only need 12 Newtons of force to move the table, but due to friction, that's increased to 15 Newtons. I can manage pushing at 7 Newtons, but I need your friend to help push the rest of the way. So, your friend will need to push at 8 Newtons. Together, we should be able to get the job done!

Can you and your friend help me out? It would be much appreciated!

Camera pans to you and your friend

You: Sure, we can definitely help out.

Your Friend: No problem! We got this.

Camera pans back to Daniel

Daniel: Thanks a lot guys! I really appreciate it. Okay, let's get the furniture moved!

A swimming fish has a momentum of 8 kg-m/s. It eats a stationary 2 kg fish and keeps
swimming. What is their new momentum?
a. Zero
b. 10 kg-m/s
c. 8 kg-m/s
d. 16 kg-m/s

Answers

Answer:

d. 16 kg-m/s

Explanation:

The new momentum of the swimming fish after eating the stationary fish can be calculated by adding the momentum of the initial swimming fish and the momentum of the stationary fish. Since momentum is a vector quantity, the direction of the momentum is the same as the direction of motion of the fish. If the fish continues to swim with the same velocity after eating the stationary fish, then the new momentum is the sum of the initial momentum of the swimming fish and the momentum of the stationary fish.

Initial momentum of swimming fish = 8 kg-m/s

Momentum of stationary fish = 2 kg * 0 m/s = 0 kg-m/s

New momentum = Initial momentum of swimming fish + Momentum of stationary fish = 8 kg-m/s + 0 kg-m/s = 8 kg-m/s + 2 kg-m/s = 10 kg-m/s.

So, the correct answer is (d) 16 kg-m/s.

Answer:

C

Explanation:

Using law of conservation of momentum of the system

Momentum before = momentum after

         8 kg m/s       = 8 kg m/s

The second fish has zero momentum, so after eating it the system still has momentum of 8 kg m/s

The purpose of the chiller is to
A. remove heat from the air.
B. cool conditioned air.
C. distribute the refrigerant.
D. cool warmed water.

Answers

The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

What is a Chiller?

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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A bullet of mass mb=11.9gr is being fired from a stationary gun of mass mg=2.1kg. If the velocity of the bullet is vb=235.1 m/s, what would be the recoil velocity of gun, vg, in m/s?

Answers

Answer:given that-

Bullet mass= 11.9gr

gun mass= 2.1

Velocity of bullets= 235.1m/s

A/q,

satisfied-

law of conservation of momentum

pf=pi

(Mass of gun+ mass of bullets)reserve velocity= mass of bullets ×velo of bullets

=>( 2100+11.9)vr=11.9×235.1

=>(2111.9 )vr=2797.69

=>vr=297.69/2111.9

vr=1.32m/

The most powerful ice breaker in the world was built in the former Soviet Union. The ship is almost 150 m long, and its nuclear engine generates 56 MegaWatts (56 E^6 W) of power. How much work can this engine do in 1.0 hour? (1 hour = 3600 seconds)

Answers

The amount of work the engine can do in 1.0 hour, given that the engine generates 56 MegaWatts is 2016×10⁸ Joules

How do I determine the amount of work the engine can do?

Work is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = force (F) × distance (d)

Power is defined as the rate at which work is done:

Power = Work / time

Using the power-work relationship formula above, we can detertmine the work the engine will do in 1.0 hour as follow:

Power = 56 MegaWatts = 56×10⁶ WattsTime = 1.0 hour = 3600 secondsWork =?

Power = Work / time

Cross multiply

Work = Power × time

Work = 56×10⁶ × 3600

Work = 2016×10⁸ Joules

Therefore, we can conclude from the above calculation that the work the engine will do is 2016×10⁸ Joules

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A highway curves to the left with radius of
curvature of 36 m and is banked at 25 ◦
so
that cars can take this curve at higher speeds.
Consider a car of mass 1091 kg whose tires
have a static friction coefficient 0.87 against
the pavement.
How fast can the car take this curve without
skidding to the outside of the curve? The
acceleration of gravity is 9.8 m/s^2.
Answer in units of m/s.

Answers

The car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve

How do we calculate the speed to which the car can move?

The maximum speed at which a car can take a curved road without skidding outward is given by the formula:

v = √(g * r * (cos(theta) + (mu * sin(theta))/mu_s))

where:

v = velocity of the car

g = acceleration due to gravity (9.8 m/s^2)

r = radius of curvature of the road (36 m)

theta = angle of banking of the road (25 degrees)

mu = coefficient of friction between the tires and the road (0.87)

mu_s = coefficient of static friction between the tires and the road (0.87)

So the maximum speed at which the car can take this curve without skidding is:

v = √(9.8 * 36 * (cos(25) + (0.87 * sin(25))/0.87))

v = √(9.8 * 36 * (0.9063 + 0.4696))

v = √(9.8 * 36 * 1.376)

v = √(352.48)

v = 18.8 m/s

Therefore, the car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve.

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Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between them.
1 ) Find the magnitude of the net gravitational force exerted by the two larger masses on the 74.8 kg mass.
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2 /kg^2.
Answer in units of N.

2 ) Leaving the distance between the 141 kg and the 494 kg masses fixed, at what distance from the 494 kg mass (other than infinitely remote ones) does the 74.8 kg mass experience a net force of zero?
Answer in units of m.

Answers

( 1) The net gravitational force between the 74.8 kg mass is  8.09 x 10⁻⁵ N.

( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.

What is net gravitational force on the middle mass?

The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.

F = ( GmM ) / ( R² )

where;

G is universal gravitation constantm is the mass of the middle massM is the mass of the first massR is the distance of separation between the two masses

The force between the first mass and the middle mass is calculated as;

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )

F' = 1.8 x 10⁻⁵ N

The force between the third mass and the middle mass is calculated as;

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )

F'' = 6.29 x 10⁻⁵ N

The net gravitational force on the middle mass;

F (net)  = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N

F ( net ) = 8.09 x 10⁻⁵ N

Let the distance of zero net force from the 141 kg mass = d.

then the distance from the 494 kg mass = 0.396 m - d

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )

F' = 0.704 x 10⁻⁶ / d²

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²

F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²

for zero net force, the two forces must be equal

0.704 x 10⁻⁶ / d²  = 2.47 x 10⁻⁶ / ( 0.396 - d )²

0.704 (0.396 - d )² = 2.47d²

(0.396 - d )²  = ( 2.47d² ) / ( 0.704 )

(0.396 - d )²  = 3.51d²

0.396 - d = √ ( 3.51d² )

0.396 - d = 1.87d

1.87d + d = 0.396

d (1.87 + 1) = 0.396

d (2.87) = 0.396

d = 0.396 / 2.87

d = 0.138 m

The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m

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26 miles and 385 yards to kilometers

Answers

To convert 26 miles and 385 yards to kilometers, we first need to convert miles and yards to the same unit.

1 mile = 1760 yards

26 miles = 26 x 1760 = 45600 yards

Then add the yards of the distance, so the total distance in yards is 45600+385 = 45985 yards

Now we can convert yards to kilometers.

1 yard = 0.9144 meters

45985 yards = 45985 x 0.9144 = 42.195 kilometers

So 26 miles and 385 yards is approximately 42.195 kilometers.

(PLEASE HELP) Place the following in order according to how fast light travels through them: Gas, Liquid, Solid, Vacuum.

Answers

Answer:

Light waves do not need a medium in which to travel but sound waves do. Explain that unlike sound, light waves travel fastest through a vacuum and air, and slower through other materials such as glass or water.

Explanation:

Light travels in a straight line as a wave. It does not require any medium or material to travel like sound waves which means it can travel in vacuum.The speed of the light  from the special theory of relativity is a constant value of 38x10^8m/second

If the potential across two parallel plates, separated by 4.0 cm, is 15.0 V, what is the electric field strength in volts per meter?

27 V
0.27 V
380 V
3.8 V

Answers

The electric field strength in volts per meter is 380 V. Option D is the correct answer.

What is electric field strength?

This refers to the physical field that encloses electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It can also be called the physical field for a system of charged particles or ( E-field).

The electric field strength (E) can be calculated using the  b the formula:

E = V / d,

where,

V = the potential difference (in volts)

d = the distance (in meters) between the plates.

Calculating the electric:

V = 15.0 V

d = 0.04 m (4.0 cm converted to meters).

Hence,

E = 15.0 V

      0.04 m

= 375 V/m.

E ≈ 380 V

Hence The electric field strength (E) is 380 V.

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How long will it take a pulse moving at 0, 25 m-s¹ to travel a distance of 20 m?​

Answers

Answer:

T=80

Explanation:

soln

v=0.25ms

d=20m

t=?

therefore; velocity=distance/time taken

equating the valuables we have

0.25=20/t

making t the subject formula we have

t=20/0.25 => 80s

How did the Egyptians use chemistry?

Answers

Answer:

as far as I know they use chemistry to build pyramids block with reaction that why pyramids still exists

Answer: I hope this answer your question

Explanation:

The Egyptians were known in the ancient world as experts in many applied chemistry fields such as metallurgy, wine and beer making, glass making, paper manufacture, paint pigments, dyes, cosmetics, perfumes, and pharmaceuticals.Egyptians performed tasks that ranged from metallurgy to the production of dyes and pottery.They developed ways to measure time and distances , and applied their knowledge to monumental architecture.Used to build structures, manage the food supply and compute the flood levels of the Nile, math was vital to everyday life in Ancient Egypt. A remnant of their impressively sophisticated mathematical system, the Rhind Papyrus illustrates how Egyptians approached geometry, arithmetic and algebra.

001 (part 1 of 2) 10.0 points
The arm of a crane at a construction site is
16.0 m long, and it makes an angle of 13.9°
with the horizontal. Assume that the max-
imum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane with-
stand if the maximum load the crane can
handle is 768 N?
Answer in units of N. m.

Answers

If the crane can carry a maximum weight of 768 N, the maximum torque it can generate is 2383.4 N

The axis of rotation is the point at which the item rotates, and torque is the twisting force that causes rotation. Due to the fact that it causes an object to rotate along an axis, torque is a rotating force.

The perpendicular component of the force multiplied by the distance is torque.

T = F _|_ T

Part One

T = (768 N cos 13.9°) (16.0 m)

T = 10,368 Nm

Part Two

10368 Nm = (F cos 27.0°) (16.0 m)

F = 2383.4 N

Hence, maximum torque can the crane with-stand if the maximum load the crane can handle is 768 N is 2383.4 N

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