Which is the
Simplified form
r-7+s-12

Answer:

yes

Step-by-step explanation:

The total amount of time university students in the United States spend sleeping, eating and drinking, and doing leisure and sports is about: Average weekday time used for full-time college and university students in the US Sleeping 36.2% Leisure and sports 17.1% 3.3% Grooming 4.2% Eating and drinking 13.8% 5.8% Educational activities 9.6% Traveling 10.0% Other Work and related activities A A 1/3 of their total time 3/5 of their total time C) 1/2 of their total time 3/4 of their total time

"Our data was consistent with what researchers have found in academic studies — that students are in bed, on average, seven to eight hours per weeknight," says Brian Wilt, Jawbone's head of data science and analytics.

On average, college students get a whopping six hours of sleep a night according to a study by the University of Georgia. Lack of sleep can take a toll on your mental health, cause a reduction in cognitive performance and affect your memory capacity!

Learn more about the average college student spend sleeping at

https://brainly.com/question/14448167

#SPJ2

Answer:

The number of flowers on the plant

Step-by-step explanation:

Answer:

C: Number of flowers on the plant

Step-by-step explanation:

i got it right on my test

RHS

[tex]\\ \sf\longmapsto \frac{2 \tan( \theta) }{ \sin(2 \theta) } \\ \\ \sf\longmapsto \frac{ \frac{2 \sin( \theta) }{2 \cos( \theta) } }{ \sin(2 \theta) } \\ \\ \sf\longmapsto \frac{1}{ \cos {}^{2} ( \theta) } \\ \\ \sf\longmapsto {sec}^{2} \theta[/tex]

Answer:

−4304

Step-by-step explanation:

1. The given determinant is :

[tex]\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}[/tex]

We need to find its determinant . It can be solved as follows :

[tex]\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}=7(14)-142(31)\\\\=-4304[/tex]

So, the value of determinant is equal to −4304.

Answer:

A= -4269

B= 1768

C= 647.36

Step-by-step explanation:

Answer:

A) Exponential growth

Step-by-step explanation:

Answer:

There are two types of exponential functions: exponential growth and exponential decay. In the function f (x) = bx when b > 1, the function represents exponential growth. In the function f (x) = bx when 0 < b < 1, the function represents exponential decay.

Step-by-step explanation:

Answer:

B. 550

Step-by-step explanation:

550 is the smallest number that becomes 600 when rounded to the nearest hundred

Answer: 7x + 9y >_ (more or equal) 314

X + Y <_ ( less or equal) 35

Step-by-step explanation:

Answer:

h+s≤35 and 7h + 9s >_314

Step-by-step explanation:

Answer:

a) 120

b) 6

c) 1/20

Step-by-step explanation:

a) 5! = 120

b) (5 - 2)! = 6

c) 6/120 = 1/20

Answer:

-14 is the answer for the second term (?)

Answer:

A

Step-by-step explanation:

         1                                          2                                       3  

days hours minutes       days   hours   minutes     days    hours  minutes  

  7        8         20             6       24+8       20              6        31        60+20

  4       10         30

 -

_______________

         4

days     hours    minutes

  6           31           80

  4            10          30

-

____________________

  2             21          50

___________________

Answer:

46%

Step-by-step explanation:

Divde the smaller # by the bigger # to get the precentage

An average San Francisco customer uses what percent of electricity used by an average Houston customer?

In other words, San Francisco is what part of Houston?

---Just like, 7 is what part of 49? These are the same questions and would be solved in the same way

San Francisco / Houston

6753 / 14542

0.4644 = 46.44%

ANSWER: 46%

Hope this helps!

Answer:

[tex]M_{st} = (\frac{-2+4}{2}, \frac{-4+6}{2})[/tex]  

[tex]M_{st}=(\frac{2}{2}, \frac{2}{2} )[/tex]

[tex]M_{st}=(1, 1)[/tex]

[tex]M_{cd}=(\frac{-6+4}{2} , \frac{10-8}{2} )[/tex]

[tex]M_{cd}=(\frac{-2}{2} , \frac{2}{2} )[/tex]

[tex]M_{cd}=(-1, 1)[/tex]

Answer:

The acceleration is 1.8 m/s^2.

Step-by-step explanation:

initial velocity, u = 30 mph = 13.4 m/s

Final velocity, v = 50 mph = 22.4 m/s

time, t = 5 s

Let the acceleration is a.

Use first equation of motion

v = u + at

22.4 = 13.4 + 5 a

a = 1.8 m/s^2

Answer:

B. Yes. By SSS~

Step-by-step explanation:

From the diagram given, we have the corresponding sides of both triangles as follows:

RQ/KL = 24/20 = 6/5

QP/LM = 18/15 = 6/5

RP/KM = 12/10 = 6/5

From the above, we can see that the ratio of the corresponding side lengths of both triangles are equal. This means that all three sides of one triangle are proportional to all corresponding sides of the other triangle.

The SSS similarity theorem states that if all sides of one triangle are proportional to all corresponding sides of another, then both triangles are similar to each other.

Therefore, ∆KLM ~ ∆RQP by SSS similarity.

The domain of a set is the possible input values the set can take.

It is true that the domain of ∀x ∃y(x+y≥0) is the set of real numbers

Given that: ∀x ∃y(x+y≥0)

Considering x+y ≥ 0, it means that the values of x + y are at least 0.

Make y the subject in x+y ≥ 0

So, we have:

[tex]\mathbf{y \le -x}[/tex]

There is no restriction as to the possible values of x.

This means that x can take any real number.

Hence, it is true that the domain of ∀x ∃y(x+y≥0) is the set of real numbers.

Read more about domain at:

https://brainly.com/question/15110684

Answer:

z(max) = 16

z(min) = -24

Step-by-step explanation:

2x - y = 12  multiply by 2

4x - 2y = 24  (1)

4x + 2y = 0  add equations

8x = 24

x = 3

4(3) + 2y = 0

y = -6

so (3, -6) is a common point on these two lines

z = 2(3) + 5(-6) = -24

4x - 2y = 24   (1)

x + 2y = 6   add equations

      5x = 30

        x = 6

6 + 2y = 6

         y = 0

so (6, 0) is a common point on these two lines

z = 2(6) + 5(0) = 12

4x + 2y = 0    multiply by -1

-4x - 2y = 0

  x + 2y = 6  add equations

       -3x = 6

         x = -2

-2 + 2y = 6

         y = 4

so (-2, 4) is a common point on these two lines

z = 2(-2) + 5(4) = 16

Answer:

1

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2

+

5

−

2

=

0

x^{2}+5x-2=0

x2+5x−2=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{5}}

b=5

=

−

2

c={\color{#129eaf}{-2}}

c=−2

=

−

5

±

5

2

−

4

⋅

1

(

−

2

)

√

2

⋅

1

Step-by-step explanation:

this should help

Answer:

the answer is 89

Step-by-step explanation:

this is a hard one to salve but basically if you know and lern hout to do it it is not that hard

Answer:

X-intercept = -3 and y-intercept = 6

Step-by-step explanation:

We can start off by isolating the y term. To do that, we must add 2y to both sides to get

[tex]4x=2y-12[/tex]

Now, we must add 12 to both sides and the y term will be all alone on the right side:

[tex]4x+12=2y[/tex]

Now, to have only y on the right side, we must divide by 2 to get:

[tex]y=2x+6[/tex]

In slope-intercept form, b is the y-intercept, and 'b' in this equation is 6. We have our y-intercept.

To find our x-intercept, y must be equal to zero. We can plug in that value for y and solve for x:

[tex]0=2x+6[/tex]

We can start off by subtracting 6 from both sides to get:

[tex]2x=-6[/tex]

We can then divide both sides to get [tex]x=-3[/tex] when y is equal to 0. Thus, we have our x-intercept.

Answer:

y-intercept= -6

x-intercept= 3

Step-by-step explanation:

First, rearrange the equation to be in y=mx+b.

4x-2y=12

4x-12=2y

(1/2)(4x-12)=y

y=2x-6

From here, we know that the 'b' in an equation in form y=mx+b is the y-intercept, which is -6.

To find the x intercept make y=0 and solve.

You can also solve without rearranging the equation and simply making x=0 and solving to find the y-intercept. and making y=0 and solving to find the x-intercept.

Answer:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:                                                                     [tex]\displaystyle \lim_{x \to c} x = c[/tex]

L'Hopital's Rule

Differentiation

Basic Power Rule:

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

We are given the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]

When we directly plug in x = 0, we see that we would have an indeterminate form:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]

Plugging in x = 0 again, we would get:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]

Substitute in x = 0 once more:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Answer:

Step-by-step explanation:

slopee -1

y-intercept (0,11)

 x   y

0    11

1     10

Answer:

Two tailed test

Test statistic = 3.20

Pvalue = 0.001

H1 : p ≠ 0.91

Step-by-step explanation:

Given :

Test of p=0.91 vs p≠0.91

The use if not equal to ≠ sign in the null means we have a tow tailed test, which means a difference exists in the proportion which could be lesser or greater than the stated population proportion.

The test statistic :

This is the Z value from the table given = 3.20

The Pvalue = 0.001

Since Pvalue < α ;Reject H0

Answer:

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Person has diabetes.

Probability of a positive test:

0.95 out of 0.1(person has diabetes).

0.007 out of 1 - 0.1 = 0.9(person does not has diabetes). So

[tex]P(A) = 0.95*0.1 + 0.007*0.9 = 0.1013[/tex]

Probability of a positive test and having diabetes:

0.95 out of 0.1. So

[tex]P(A \cap B) = 0.95*0.1 = 0.095[/tex]

What is the probability that a randomly selected person has diabetes, given that his test is positive?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.095}{0.1013} = 0.9378[/tex]

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Answer:

Short leg = x

Longer leg = 12

Hypotenuse = y

Short leg = 4√3

longer leg = 12

Hypotenuse = 8√3

Answered by GAUTHMATH

Answer:

Step-by-step explanation:

[tex]\begin{bmatrix}3 & 6 & 1\\ 2 & 4& 0\\ 0 & 6 & 2\end{bmatrix}\times\begin{bmatrix}2\\ 0\\ 1\end{bmatrix}[/tex]

Multiply the terms of the rows of the first matrix with the terms given in the column of the second matrix.

[tex]=\begin{bmatrix}(3\times 2+6\times 0+1\times 1)\\ (2\times 2+4\times 0+0\times1)\\ (0\times 2+6\times 0+2\times 1)\end{bmatrix}[/tex]

[tex]=\begin{bmatrix}7\\ 4\\ 2\end{bmatrix}[/tex]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

As a result, Poisson for each driver seems to be the number of accidents.

Let X be the random vector indicating accident frequency.

Let, [tex]\lambda=[/tex]Expected accident frequency

[tex]P(X=0) = e^{-\lambda}[/tex]

For class 1:

[tex]P(X=0) = \frac{1}{(1-0.2)} \int_{0.2}^{1} e^{-\lambda} d\lambda \\\\P(X=0) = \frac{1}{0.8} \times [-e^{-1}-(-e^{-0.2})] = 0.56356[/tex]

For class 2:

[tex]P(X=0) = \frac{1}{(2-0.4)} \int_{0.4}^{2} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{1.6} \times [-e^{-2}-(-e^{-0.4})] = 0.33437[/tex]

For class 3:

[tex]P(X=0) = \frac{1}{(3-0.6)} \int_{0.6}^{3} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{2.4} \times [-e^{-3}-(-e^{-0.6})] = 0.20793[/tex]

The population is equally divided into three classes of drivers.

Hence, the Probability

[tex]\to P(X=0) = \frac{1}{3} \times 0.56356+\frac{1}{3} \times 0.33437+\frac{1}{3} \times 0.20793=0.36862[/tex]