Streak is the color of the mineral when it is powdered. This property is useful for identifying minerals, as the streak of a mineral is often different from its visible color.
For example, hematite, which appears as a dull red or brown in its natural form, has a streak that is a bright red color. This property is determined by rubbing the mineral on a piece of unglazed porcelain, which leaves behind a streak of the powdered mineral. Streak can be affected by the presence of impurities in the mineral, but in general, it is a reliable way to identify a mineral.Streak is a physical property of minerals that refers to the color of the powdered form of a mineral. It is determined by rubbing the mineral on an unglazed porcelain plate, which leaves behind a streak of the mineral's powder. Streak is a useful tool for mineral identification, as it can often be more consistent and distinct than the visible color of a mineral. For example, some minerals may have variable visible colors due to impurities, but their streak will be consistent. Streak can also be used to distinguish between minerals that may look similar but have different properties.
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Are enzymes reused or consumed?
Enzymes can be reused. Because they are not reactants, enzymes are not depleted during a reaction. An enzyme can be employed for other reactions after it has catalysed a reaction and been freed from its binding to a substrate.
Our bodies include enzymes that function as catalysts to quicken processes by reducing the activation energy required to initiate a reaction. The substrate is a molecule that fits into a specific location on each enzyme molecule known as the active site. Like when you insert a key into a lock and the lock unlocks, the substrate undergoes a chemical reaction and transforms into a new molecule called the product.
Each cell in your body includes thousands of distinct enzymes since they are required for the majority of chemical processes. Chemical processes in the body can occur millions of times more quickly with the aid of enzymes than they would otherwise. Enzymes may be utilised over and over again because they are not a component of the final product. How productive!
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Which of the following questions would most likely be investigated by a chemist?
Answer:
Chemists typically investigate questions related to the composition, structure, and properties of matter, as well as its interactions with energy and other substances. Some examples of questions that a chemist might investigate include:
What is the chemical composition of a given substance?
How does the structure of a molecule affect its properties?
How do different chemical reactions occur, and what are the conditions necessary for them to occur?
How do substances interact with one another in solution?
What is the rate at which a chemical reaction occurs, and how can it be influenced by various factors such as temperature, pressure, and concentration?
Explanation:
These are just a few examples of the types of questions that a chemist might investigate. In general, a chemist's research is focused on understanding the underlying principles and processes of matter and energy at the molecular and atomic level.
Which would be an invalid listing within an electron configuration?
As in: a) 2s2 b) 5d9 c) 3p4 d) 1s3
The correct option is d.)1s3 Explanation s- orbital can hold a maximum of 2 electrons.
1s3- There is only one s orbital per energy level, and each orbital can hold a maximum of two electrons, so there can not be 3s electrons at any energy level. The Aufbau principle dictates the manner in which electrons are filled in the atomic orbitals of an atom in its ground state.
It states that electrons are filled into atomic orbitals in the increasing order of orbital energy level. According to the Aufbau principle, the available atomic orbitals with the lowest energy levels are occupied before those with higher energy levels.
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. you have a solution at ph 12 containing 0.1 moles of histidine. write the main chemical reaction that would take place as you are adding the final drop of: (just indicate the functional group involved) a). 0.05 moles hcl
When you add hydrochloric acid (HCl) to a solution of histidine (pH 12), the following chemical reaction takes place:
Histidine + H+ + Cl- --> Histidine-H+Cl-
The functional groups involved in this reaction are the carboxyl group (-COOH) and the amino group (-NH2) of histidine, which can react with H+ and Cl-, respectively, to form the histidine-H+Cl- salt.
A chemical reaction is a process that leads to the transformation of one set of chemical substances into another. During a chemical reaction, chemical bonds between atoms are broken and new bonds are formed, resulting in a rearrangement of atoms and the creation of new molecules or compounds.
Chemical reactions can be represented by chemical equations, which typically show the reactants on the left side of the equation and the products on the right side. The chemical equation also includes the stoichiometry of the reaction, which indicates the number of molecules or moles of each reactant and product involved.
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draw the structure of cis−jasmone, a natural product isolated from jasmine flowers, formed by treatment of alkyne a with h2 in the presence of the lindlar catalyst. click the draw structure button to launch the drawing utility.
Cis-jasmone is a natural product with a molecular formula of C11H16O. It has a cyclopentenone ring and an unsaturated side chain with a cis double bond. The structure of cis-jasmone can be drawn as follows:
H
|
H--C--O
| |
H--C--C--C--CH3
| | |
H H--C=C
|
H
The synthesis of cis-jasmone from alkyne A using H2 in the presence of the Lindlar catalyst involves the hydrogenation of the alkyne to form a cis-alkene, followed by cyclization to form the cyclopentenone ring.
Cis-jasmone is a natural organic compound with the molecular formula C11H16O. It has a cyclopentenone ring and an unsaturated side chain with a cis double bond. Cis-jasmone is a fragrant compound that is responsible for the characteristic aroma of jasmine flowers. It is used in perfumes and as a flavoring agent in the food industry.
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write a brief conclusion to the experiment summarizing the experimental conditions that gave rise to the greatest observed electrical conductivity.
A brief conclusion to the experiment summarizing the experimental conditions that gave rise to the greatest observed electrical conductivity:
To observe electrical conductivity of substances in colorful waterless resultsTo determine of the result is a strong or weak electrolyteTo interpret a chemical response by observing waterless result conductivity.Electrical conductivity is grounded on the inflow of electrons. Essence are good operators of electricity because they allow electrons to flow through the entire piece of material. therefore, electrons flow like a “ ocean of electrons ” through essence. In comparison, distilled water is a veritably poor captain of electricity since veritably little electricity flows through water. largely ionized substances are strong electrolytes. Strong acids and mariners are strong electrolytes because they fully ionize( disconnect or separate) in result. The ions carry the electric charge through the result therefore creating an electric current.
Slightly ionized substances are weak electrolytes. Weak acids and bases would be distributed as weak electrolytes because they don't fully disconnect in result.
Substances that don't conduct an electric current are called non-electrolytes. Non-electrolytes don't ionize; they don't contain portable ions. The LEDs of a conductivity cadence won't light because there are no ions to carry the electric current. The table below lists exemplifications of strong, weak and non-electrolytes.
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sort these nucleotide building blocks by their name or classification.
Depending on the molecule's chemical composition, they can be purines or pyrimidines.
Nucleotide building blocks are the monomers (single molecules) that make up nucleic acids, such as deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). They are classified as either purines or pyrimidines, depending on the chemical structure of the molecule.
Purines: Adenine (A), Guanine (G)
Pyrimidines: Cytosine (C), Thymine (T), Uracil (U)
Sorted by name: Adenine (A), Cytosine (C), Guanine (G), Thymine (T), Uracil (U)
Sorted by classification: Purines: Adenine (A), Guanine (G) Pyrimidines: Cytosine (C), Thymine (T), Uracil (U).A nucleotide is the basic structural unit of nucleic acids such as DNA and RNA.
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complete question:sort these nucleotide building blocks by their name or classification. from below image
concentrated hcl is a 12.0 m solution in water and has a density of 1.22 g/ml. a. what is the molality of hcl in the solution?
The molality of HCl in the solution is[tex]0.00122 mol/kg[/tex]
Molality is defined as the number of moles of a solute in one kilogram of a solvent. In this case, the solvent is water.
To calculate the molality, we first need to calculate the molarity of the solution. Molarity is defined as the number of moles of a solute in one liter of solution.
To calculate the molarity, we need to know the mass of the solute (HCl) and the volume of the solution. The mass of the solute can be calculated using the density of the solution (1.22 g/ml):
Mass of HCl =[tex]Density * Volume[/tex]
Volume = [tex]\frac{Mass}{Density }[/tex]
Volume =[tex]\frac{(12.0 mol/L) }{ (1.22 g/ml) }= 9.839 L[/tex]
Molarity = [tex]\frac{ (12.0 mol/L) }{(9.839 L) }= 1.22 mol/L[/tex]
Now, we can calculate the molality:
Molality = [tex]\frac{ (1.22 mol/L) }{(1000 g/kg) }= 0.00122 mol/kg[/tex]
Therefore, the molality of HCl in the solution is [tex]0.00122 mol/kg[/tex].
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What is the concentration of N2(g), in
parts per billion, in a solution that
contains 1.5 * 10 ^ - 6 g of N2(g) dissolved
in 7.5 g of H2O(l)?
Can someone tell me why 200 is the right answer?
Answer:
The concentration of N2(g) in parts per billion (ppb) in a solution can be calculated as follows:
(mass of N2(g) in solution / total mass of solution) * 10^9 ppb
Plugging in the given values, we have:
(1.5 * 10^-6 g / (7.5 g + 1.5 * 10^-6 g)) * 10^9 ppb = (1.5 * 10^-6 g / 7.5 g) * 10^9 ppb = 200 ppb
So, the concentration of N2(g) in the solution is 200 ppb.
if the initial concentration of ni(co)4(g) is 1.0 m and x is the equilibrium concentration of co(g), what is the correct equilibrium relation?
For this reaction, the appropriate equilibrium relation is x = (Kc)1/4.
How is the equilibrium concentration determined?Write the reaction's equilibrium constant expression. To find x, substitute the final concentrations and the known K value. Determine each substance's final concentration in the reaction mixture. By adding these values to the expression for the equilibrium constant to get K, you may verify your answers.
Nickel tetracarbonyl, Ni(CO)4, decomposes in an equilibrium reaction that is:
Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)
which is given by the expression:
Kc = [Ni(s)] [CO]4 / [Ni(CO)4(g)]
The initial concentration of nickel tetracarbonyl gas is also given as 1.0 M.
Let x be the equilibrium concentration of CO gas, then the equilibrium expression can be written as:
Kc = (1) (x)4 / (1.0)
Simplifying the expression gives:
Kc = x4
Taking the fourth root of both sides gives the equilibrium relation:
x = (Kc)1/4
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would the flame temperature be higher or lower if pure oxygen were used instead of air? why? (use the 1st law to explain your answer)
Using pure oxygen instead of air for combustion would result in a higher flame temperature.
This is because air contains a significant amount of nitrogen (about 78% by volume), which is not involved in the combustion reaction and therefore acts as a diluent, reducing the concentration of oxygen available for the reaction. By using pure oxygen, the concentration of oxygen is increased, allowing for more complete combustion and producing a higher flame temperature. The first law of thermodynamics, also known as the law of conservation of energy, states that energy cannot be created or destroyed, but it can be transformed from one form to another. In the case of combustion, the chemical energy stored in the fuel is transformed into thermal energy (heat) and other forms of energy, such as light and sound. The amount of heat released during combustion is determined by the enthalpy change of the reaction, which depends on the chemical composition of the reactants and products.
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In the SI system of units, the mole is one of seven base units. It is frequently used in
chemical calculations. However, a mole of something is just a particular quantity of it. It
is not a unit of measure in the way that meters, seconds, and kilograms are.
Calculations performed with the number of moles of a substance could also be
performed with the number of particles of a substance. Based on this information, do
you think that the mole should be considered a base unit in the SI system? Explain why
or why not.
Answer:
Whyyy
Explanation:
The mole should be considered a base unit in the SI system because it is widely used in chemical calculations as a standard unit for counting the number of particles in a substance. The mole allows for easy and accurate calculation of the amount of substance, which is a crucial aspect in many chemical processes. In addition, the mole is defined as the number of entities in a substance, such as atoms, molecules, or ions, and its definition is based on Avogadro's constant. The mole also has practical applications in fields such as pharmacology and environmental science, where the measurement of a specific quantity of a substance is essential.
In conclusion, the mole is a necessary unit for the SI system of units due to its widespread use in chemical calculations and its important role in accurately measuring the amount of substance in a variety of scientific disciplines.
a.Calculate the freezing point of a solution containing 10.6 g FeCl3 in 159 g waterCalculate the boiling point of a solution above.b. Calculate the freezing point of a solution containing 3.9 % KCl by mass (in water).Calculate the boiling point of a solution above.c. Calculate the freezing point of a solution containing 0.168 m MgF2.Calculate the boiling point of a solution above.
Molar mass of MgF2 = 62.30 g/mol and freezing point = 0 °C - 0.764 °C = -0.764 °C
a) To calculate the freezing point depression of a solution, we can use the formula:
ΔTf = Kf x molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent (water) and molality is the concentration of the solute (FeCl3) in moles per kilogram of solvent (water).
The molality of the solution can be calculated as follows:
mass of FeCl3 = 10.6 g
molar mass of FeCl3 = 162.2 g/mol
moles of FeCl3 = mass / molar mass = 10.6 g / 162.2 g/mol = 0.0654 mol
mass of water = 159 g
molality = moles of solute / mass of solvent (in kg) = 0.0654 mol / 0.159 kg = 0.411 mol/kg
The freezing point depression constant for water is 1.86 °C/m. Thus, the change in freezing point can be calculated as follows:
ΔTf = Kf x molality = 1.86 °C/m x 0.411 mol/kg = 0.764 °C
The freezing point of pure water is 0 °C, so the freezing point of the solution is:
freezing point = 0 °C - 0.764 °C = -0.764 °C
b) To calculate the boiling point elevation of a solution, we can use the formula:
ΔTb = Kb x molality
where ΔTb is the change in boiling point, Kb is the boiling point elevation constant for the solvent (water) and molality is the concentration of the solute (KCl) in moles per kilogram of solvent (water).
The molality of the solution can be calculated as follows:
mass of KCl = 3.9 g
molar mass of KCl = 74.55 g/mol
moles of KCl = mass / molar mass = 3.9 g / 74.55 g/mol = 0.0523 mol
mass of water = 100 g (assuming the total mass of the solution is 103.9 g, with 3.9 g KCl and 100 g water)
molality = moles of solute / mass of solvent (in kg) = 0.0523 mol / 0.1 kg = 0.523 mol/kg
The boiling point elevation constant for water is 0.52 °C/m. Thus, the change in boiling point can be calculated as follows:
ΔTb = Kb x molality = 0.52 °C/m x 0.523 mol/kg = 0.272 °C
The boiling point of pure water is 100 °C, so the boiling point of the solution is:
boiling point = 100 °C + 0.272 °C = 100.272 °C
c) To calculate the freezing point depression of a solution, we can use the formula:
ΔTf = Kf x molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent (water) and molality is the concentration of the solute (MgF2) in moles per kilogram of solvent (water).
The molality of the solution can be calculated as follows:
molarity of MgF2 = 0.168 mol/L
molar mass of MgF2 = 62.30 g/mol
mass of MgF2 in 1 L of solution = molarity x volume x m
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If you collect 350.0 mL H2 gas over water at 90.oC and under 115.4 kPa of pressure, what will the dry gas volume be at
STP? (water vapor pressure at 90.0oC is 70.1 kPa)
The concept Boyle's law is used here to determine the volume of the gas at STP. The volume of dry gas at STP is 576.17 mL.
What is Boyle's law?The Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure. Mathematically the law can be expressed as:
PV = k (Constant)
For two different gases, the equation is:
P₁V₁ = P₂V₂
Then the new volume is:
V₂ = P₁V₁ / P₂
= 115.4 × 350.0 / 70.1
= 576.17 mL
Thus the volume of the dry gas is 576.17 mL.
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2. Some gold used for jewelry is called '18-karat white gold. This alloy is 75% gold (Au), 12.5%
silver (Ag), and 12.5% copper (Cu). If you wanted to make 25 grams of 18-karat white gold for a
ring, how many grams of each metal would you need to start with?
If you wanted to make 25 grams of 18-karat white gold for a ring then grams of each metal will remain same.
What is gold?Gold has the chemical symbol Au (from Latin: aurum) as well as the atomic number 79. As a result, it is one among the highest atomic number elements found in nature.
Some gold used for jewelry is called '18-karat white gold. This alloy is 75% gold (Au), 12.5% silver (Ag), and 12.5% copper (Cu). If you wanted to make 25 grams of 18-karat white gold for a ring then grams of each metal will remain same.
Therefore, if you wanted to make 25 grams of 18-karat white gold for a ring then grams of each metal will remain same.
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a sample has a mass of 23.5g. when the sample is lowered into the water in a graduated cylinder, the water level rises from 23.8 ml to 28.5 ml. what is the density of this metal?
In the given sample, when the water level is rises from 23.8ml to 28.5 ml, the density of the metal is 5.00 g/cm³
To find the density of the metal, we need to use the formula:
density = mass / volume
We are given the mass of the metal as 23.5 g. To find the volume of the metal, we need to subtract the initial volume of water in the cylinder from the final volume of water after the metal is added. The difference in volume is equal to the volume of the metal.
The initial volume of water is 23.8 ml, and the final volume of water is 28.5 ml, so the volume of the metal is:
volume = final volume - initial volume
volume = 28.5 ml - 23.8 ml
volume = 4.7 ml
Now we can substitute the values for mass and volume into the density formula:
density = mass / volume
density = 23.5 g / 4.7 ml
We need to convert the volume to cubic centimeters (cm³) because the units of density are expressed in g/cm³.
1 ml is equal to 1 cm³, so:
density = 23.5 g / 4.7 cm³
density = 5.00 g/cm³ (rounded to two decimal places).
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What are allotropes ?
Which would be an invalid listing within an electron configuration?
a) 2s2
b) 5d9 c) 3p4 d) 1s3
Ans) d- 1s3
How can you find electronic configuration for this?The s- orbital can accommodate up to two electrons. The aforementioned configuration is faulty because there are three "s" electrons, which is not conceivable.
Since there are two electrons, 2s2 is conceivable.
The greatest number of electrons in the d orbital is 10. Thus, 5d9 is also conceivable.
The p orbital can accommodate up to 6 electrons. So 3p4 is also a possibility.
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Please help now ASAP I don’t get it
The total mass of the products is 125 g
What is the law of the conservation of mass?The law of conservation of mass, also known as the principle of mass conservation, states that the total mass of a closed system remains constant over time, regardless of the changes that may occur within the system. This means that the mass of the system can change form, but the total mass remains the same.
The law of conservation of mass is a fundamental principle in physics and is widely accepted as a basic law of nature. It is based on the idea that matter can be neither created nor destroyed, only transformed from one form to another.
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who is credited with the discovery of atomic number?
Henry Moseley used the analysis of X-ray spectra to determine the atomic number in the year 1913. He discovered that when the atomic number of an element is increased by one, certain lines in its x-ray spectra travel by the same amount each time.
In 1913–1914, English physicist Henry Moseley discovered and published the law. The "atomic number" of an element was previously only known as its position in the periodic table and had no known connection to any quantifiable physical property before Moseley's work. Chemical elements are identified exclusively by their atomic number. We owe Henry Moseley, a British physicist, credit for this discovery since he used physical rules to support this empirical and chemical understanding of the atomic number.
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when 1-bromopropane is exposed to magnesium, followed by ethylene oxide, and then aqueous acid, what is the resulting product?
When 1-bromopropane is subjected to magnesium, 1-pentanol results, which is then followed by ethylene oxide and aqueous acid.
A Grignard reagent is created when 1-bromopropane reacts with magnesium to begin the process. Then, the ethylene oxide and the Grignard reagent combine to create an intermediary molecule. Aqueous acid is then used to transform this intermediate chemical into 1-pentanol.
To turn alkenes into alcohols, a technique known as the "Wacker oxidation" or "Wacker process" is utilized. It is significant to remember that Wacker oxidation is a multi-step procedure that calls for particular reagents and circumstances in order to be properly carried out. To produce the desired product, the reaction must be carried out in an inert environment at high temperatures.
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compete question: when 1-bromopropane is exposed to magnesium, followed by ethylene oxide, and then aqueous acid, what is the resulting product? a.) 2-pentanol b.) 2-methyl-2-pentanol c.) 2-methyl-2-hexanol d.) 1-pentanol
a prescription for chad calls for triamcinolone injectable suspension 10mg/ml to be diluted down to 0.125 mg/ml by adding distilled water. how much triamcinolone suspension and how much water must be added to make 480ml of the final product?
To dilute the triamcinolone injectable suspension from 10mg/ml to 0.125 mg/ml, we need to dilute it 80 times (since 10 ÷ 0.125 = 80). This means that we need to add 1 part of the 10mg/ml suspension to 79 parts of distilled water.
To calculate how much of each we need, we can use the following formula:
C1V1 = C2V2
where C1 is the initial concentration (10mg/ml), V1 is the initial volume (unknown), C2 is the final concentration (0.125mg/ml), and V2 is the final volume (480ml).
First, we can solve for V1:
C1V1 = C2V2
10mg/ml x V1 = 0.125mg/ml x 480ml
V1 = (0.125mg/ml x 480ml) / 10mg/ml
V1 = 6ml
So we need 6ml of the 10mg/ml triamcinolone injectable suspension.
Next, we can calculate how much distilled water we need to add:
Total volume - volume of triamcinolone suspension = volume of distilled water
480ml - 6ml = 474ml
Therefore, we need to add 6ml of the 10mg/ml triamcinolone injectable suspension and 474ml of distilled water to make 480ml of the final product with a concentration of 0.125mg/ml.
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how do you separate and recover the basic compound from a mixture containing an acidic compound and a neutral compound?
Separation of materials according to their acidic- basic properties is known as acid-base extraction method. This is commonly used in separating organic compounds.
Here we have to separate a basic compound from a mixture containing acidic, basic and neutral compounds. Usually these are dissolved in organic solvents. Basic compounds usually accepts protons from a strong acid. So a strong acid like HCl is used to provide protons. The bases reacts with the acids and ionic compounds are formed. But the acidic and neutral compounds do not react.
The ionic compounds are ionized and readily dissolved in water. We are adding aqueous solutions of acid. So while shaking vigorously, the basic compound, which is ionized dissolves in water layer. Unionized acidic and neutral compounds remains in organic solvent layer. The water layer and organic solvent layer separates according to density. We extract the basic compound along with water.
So acid-base extraction method is used here.
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by titration, it is found that 11.9 ml of 0.101 m naoh(aq) is needed to neutralize 25.0 ml of hcl(aq). calculate the concentration of the hcl solution.
By titration, it is found that the 11.9 ml of the 0.101 M NaOH(aq) is needed to neutralize the 25.0 ml of HCl(aq).The concentration of the HCl solution is 0.048 M.
The reaction is as follows :
NaOH + HCl ----> NaCl + H₂O
The concentration of the NaOH = 0.101 M
The volume of the NaOH = 11.9 mL = 0.0119 L
The moles of the NaOH = molarity ×volume
= 0.101 × 0.0119
= 0.0012 mol
The Volume of the HCl = 25 mL = 0.025 L
The moles of the HCl = 0.0012 mol
The concentration of the HCl = moles / volumes in L
= 0.0012 / 0.025
= 0.048 M
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Draw all stereoisomers formed when the following alkene is treated with mCPBA. How many stereoisomers of the product are possible? Draw the product of the reaction, including stereochemistry.
There is just one stereoisomer that can exist. The product's structure is shown in the figure below, attached.
Below is a diagram illustrating the reaction's transition state. Because of this transition state, the trans alkene never produces trans product while the cis alkene always produces cis product.
According to a general definition, stereoisomers are isomers with the same composition (i.e., the same components), but different orientations in space. Enantiomers and diastereomers are the two different types of stereoisomers. Diastereomers are everything else, while enantiomers are mirror images, like one's hands. However, as was already said, timing and energy are crucial. It is useful to first think about a particular sort of stereoisomer, the conformational isomer, in order to comprehend these concerns.
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you are experimenting with blood samples and you place a drop of rbcs into a solution of 300 millimoles of cacl2. what effect does this have on the rbcs?
You are experimenting with blood samples and you place a drop of rbcs into a solution of 300 millimoles of CaCl2, there is no efect on RBCs.
The reason why the cell would shrink further in CaCl2 result is because it has a advanced van't Hoff factor i.e. total number of separated ionic species per solute patch( it is 2 for NaCl whereas it's 3 for CaCl2).
Nonionic solutes don't disconnect and will thus have a van't Hoff factor of 1)
Bibulous pressure( and other colligative parcels) are commensurable to van't Hoff factor. thus bibulous pressure in CaCl2 result will be3/2 times of that in an equimolar NaCl result.
Note that the ionic chemical eventuality isn't what drives osmosis; it's the discriminational attention of water( or any other detergent) that drives it.
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How many moles of 02 are produced by the decomposition of 6.2 moles of KCLO3 Balance reaction first _KCLO3 _KCL +_ O2
Number of moles of O2 produced by the decomposition of 6.2 moles of KCLO3 is 9.3 moles.
The mole idea is a useful way to indicate how much of a substance there is. Any measurement can be divided into two components: the magnitude in numbers and the units in which the magnitude is expressed.
Initial reaction,
KCLO3 ⇒ KCL + O2
The ratio is 1: 1 for KClO3 and O2
After balancing the equation we get,
2KClO3 ⇒ 2KCl + 3O2
So ratio of KClO3 and O2 is now 2:3
For every 2 moles of KClO3 we have 3 moles of O2 so
For 6.2 moles of KCLO3,
Number of moles of O2 = 6.2x3/2
= 9.3 moles
Therefore, number of moles of O2 produced by the decomposition of 6.2 moles of KCLO3 is 9.3 moles.
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the volume of a gas at 5.0 atm is 3.5 l. what is the volume of the gas at 7.0 atm at the same temperature?
At the same temperature, the gas has a 2.5 L volume at 7.0 atm. Volume in the context of gases is the quantity of space a gas takes up.
The ideal gas law, which connects a gas's pressure, volume, and temperature, can be used to solve this issue. PV = nRT. Assuming that the temperature stays constant, we may apply the ideal gas law in the following manner: P1V1 = P2V2. With the supplied values plugged in, we obtain (5.0 atm)(3.5 L) = (7.0 atm) (V2). We can calculate V2 as follows: V2 = (5.0 atm)(3.5 L) / (7.0 atm) = 2.5 L. As a result, the gas has a 2.5 L volume at the same temperature at 7.0 atm. In many industrial, scientific, and medical applications, accurate gas volume measurement and management are crucial.
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Determine the mean absolute deviation for when any ice was present. How can the men’s deviation be improved?
Inspire science notebook (energy in atmosphere) page 36
Answer: Clarify your question please.
Explanation:
I'm sorry, but I need more context to determine the mean absolute deviation for "when any ice was present" and how to improve the men's deviation. Can you provide more details or clarify your question?
the pioneers found that placing a large tub of water in a storage cellar would prevent their-food from freezing on really cold nights. explain why.
The pioneers found that placing a large tub of water in a storage cellar would prevent their-food from freezing on really cold nights, it can absorb or lose quite a bit of energy.
Because water has a high specific heat, it can absorb or lose quite a bit of energy and not witness important change in temperature. The water would act as a means of precluding the temperature in the basement from varying important so that stored goods would neither indurate nor come too warm.
The high mass and specific heat of the barrel of water and its high heat of emulsion mean that a large quantum of energy would have to blunder out of the basement before the water and the yield set solid. Evaporation of the water keeps the relative moisture high to cover foodstuffs from drying out.
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