which mass movement does this describe?

Answers

Answer 1

Answer:

landslide mudflows slump and creep

Explanation:

no explanation


Related Questions

Calculate the Ka of your acetic acid solution. Discuss this calculation. Based on the value of Ka, is acetic acid a strong acid or a weak acid

Answers

Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.

Acids can be strong or weak. This is determined by its tendency to break apart into ions or stay together to form molecules. Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a high number of ions within their solutions.

Weak acids, on the other hand, are those that tend to stay together in the form of molecules and therefore possess very low ion counts in their solutions. The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.

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Which statement best describes a mechanical wave?

Answers

Answer:

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium.

Explanation:

While waves can move over long distances, the movement of the medium of transmission—the material—is limited. Therefore, the oscillating material does not move far from its initial equilibrium position.

--------------

hope this helped!

✼-answers by brookeangelx

The wave transmits energy from one point to another in the form of signals. Some waves require a medium for propagation while some others does not require a medium for the propagation.

What is a mechanical wave?

The mechanical wave is defined as the wave which involves the oscillation of matter and it is responsible for the transfer of energy through a medium. These types of waves does not need a medium for propagation.

The mechanical waves cannot travel through vacuum. Some of the examples of mechanical waves are sound waves, water waves, seismic waves, etc. These waves are not capable of transmitting its energy through a vacuum.

The sound wave is a mechanical wave and the medium which it propagates can be solid, liquid or gas. It can travel fastest in solids and slower in gases.

Thus mechanical wave is an oscillation of matter.

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In an acid/base titration where NaOH(aq) is the titrant and HCl(aq) is the analyte, what is true about the moles of each reactant present in the reaction flask at the equivalence point?
A. The moles of NaOH are equal to moles of HCl.
B. There are more moles of NaOH than HCl.
C. There are more moles of HCl than NaOH.
D. The concentrations are needed to determine moles.

Answers

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A) The moles of NaOH are equal to moles of HCl.

Explanation:

NaOH + HCl ↦NaCl + H20

Which option correctly describes the relative charges and masses of the subatomic particles?

Answers

Answer:

D

Explanation:

D Is The Answer Fella, My Head Hurt Really Bad

The structure of Disodium edta

Answers

Answer:

EDTA disodium salt | C10H14N2Na2O8

Explanation:

outline the properties of alkanes​

Answers

Answer:

Physical Properties of Alkanes : -

1. Structures of Alkanes

All the carbon atoms present in an alkane are  s p 3.  Hybridized that is, every carbon atom forms four sigma bonds with carbon or hydrogen atoms. General configuration of alkane is  C n H 2 n + 2. They exhibit tetrahedral geometry with a bond angle of 109.47° between them. The methane molecule has a symmetrical tetrahedral structure.

2. Solubility of Alkanes

Due to very little difference of electronegativity between carbon and hydrogen and covalent nature of C-C bond or C-H bond, alkanes are generally non-polar molecules. As we generally observe, polar molecules are soluble in polar solvents whereas non-polar molecules are soluble in non-polar solvents. Hence, alkanes are hydrophobic in nature that is, alkanes are insoluble in water. However, they are soluble in organic solvents as the energy required to overcome the existing Van Der Waals forces and generate new Van Der Waals forces is quite comparable.

3. Boiling Point of Alkanes

As the intermolecular Van Der Waals forces increase with the increase of the molecular size or the surface area of the molecule we observe. The boiling point of alkanes increases with increasing molecular weight. The straight-chain alkanes are observed to have a higher boiling point in comparison to their structural isomers.

4. Melting Point of Alkanes

The melting point of alkanes follows the same trend as their boiling point that is, it increases with an increase in molecular weight. This is attributed to the fact that higher alkanes are solids and it’s difficult to overcome intermolecular forces of attraction between them.It is generally observed that even-numbered alkanes have higher trend in melting point in comparison to odd-numbered alkanes as the even-numbered alkanes pack well in the solid phase, forming a well-organized structure which is difficult to break.

Chemical Properties of Alkanes

Alkanes are the least reactive type of organic compound. Alkanes are not absolutely unreactive. Two important reactions that they undergo are combustion, which is the reaction with oxygen and halogenation, which is the reaction with halogens.

1. Combustion

A combustion reaction is a chemical reaction between a substance and oxygen that proceeds with the evolution of heat and light. Alkanes readily undergo combustion reactions when ignited. \When sufficient oxygen is present to support total combustion then carbon dioxide and water are the products.

CH2 + 2O2 → CO2 + 2H2O + energy

2C6H14 + 19O2 → 12CO2 + 14H2O + energy

The exothermic nature of alkane combustion reactions explains the extensive use of alkanes as fuels. Natural gas, used in home heating is predominantly methane.

2. Halogenation

Halogenation of an alkane produces a hydrocarbon derivative in which one or more halogen atoms have been substituted for hydrogen atoms. An example of an alkane halogenation reaction is

CH3 - CH3 + Br2 → CH3 - CH2 - Br + HBr

Alkane halogenation is an example of a substitution reaction a type of reaction that often occurs in organic chemistry. A general equation for the substitution of a single halogen atom for one of the hydrogen atoms of an alkane is

R - H + X2 → R - X + H - X

Explanation:

Three test tubes contain aqueous hydrogen sulfide, aqueous sulfur-dioxide and Lugol reagent. By mixing any two of the three test tubes, identify their contents. Explain, stating reasons, how you arrive at your conclusions. Write equations whenever applicable.

Answers

Answer:

Initial rate experiments

The simplest initial rate experiments involve measuring the time taken for some recognizable event to happen early in a reaction. This could be the time required for 5 cm3 of gas to be produced, for a small, measurable amount of precipitate to form, or for a dramatic color change to occur. Examples of these three indicators are discussed below.

The concentration of one of the components of the reaction could be changed, holding everything else constant: the concentrations of other reactants, the total volume of the solution and the temperature. The time required for the event to occur is then measured. This process is repeated for a range of concentrations of the substance of interest. A reasonably wide range of concentrations must be measured.This process could be repeated by altering a different property.

Explanation:

I don't think so if this is the answer. if not ok sorry

How many carbon dioxide molecules and water molecules are needed to make one molecule of glucose?

Answers

Answer:

It takes six molecules of carbon dioxide and six molecules of water to make one molecule of glucose.

Name the following Type 3 compound
1. PCIE
2. P406
3. SF6
4. SO3
5. SO2
6. N203
7. SiO2
8. O2F2
9. XeF6

Answers

Answer:

32

Explanation:

Consider the case where a closed vessel initially is filled with 1 mol of EE at 88 kPa. Then, pure EtOH is gradually added to the system at constant temperature and pressure until the system is comprised of 1 mol EE and 9 mol EtOH. Describe how the phase behavior and phase composition change throughout this process. Does the system phase separate at any point

Answers

Answer:

chu papi

Explanation:

The strongest intermolecular interactions between propanol (CH3CH2CH2OH) molecules arise from hydrogen bonding

a. True
b. False

Answers

The claim that the strongest intermolecular interactions between propanol molecules arises from hydrogen bonding is True.

Intermolecular forces are weaker attraction forces that are utilized to define physical characteristics of molecules such as:

boiling point temperature densitymelting points

Hydrogen bonding is an type of intermolecular forces.

It is a type of dipole-dipole interaction that only happens when a hydrogen atom is connected to the atomic element of oxygen, nitrogen, or fluorine.

From the question given, in the propanol (CH3CH2CH2OH) molecule, the hydrogen usually has a partially positive charge which attracts the partially negative charge of the oxygen.

Therefore, we can conclude that the claim is True.

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2 nitrogen atoms and five chlorine atoms what compound does that make

Answers

Answer:

dinitrogen pentachloride

Please help asap chemistry worksheet doesn’t make sense

Answers

Answer:

dog dog im not gon hold u we kinda screwed

helpp
What mass of carbon dioxide will be produced if
144 g of carbon react with 384 g of oxygen gas
according to the equation C+02 → CO2?

Answers

The mass of the carbon dioxide that will be produced when 144 g of carbon react with 384 g of oxygen gas is 528 g

We'll begin by calculating the masses of C and O₂ that reacted and the mass of CO₂ produced from the balanced equation.

C + O > CO

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 12 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 1 × 32 = 32 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mass of CO₂ from the balanced equation = 1 ×44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted with 32 g of O₂ to produce 44 g of CO₂

Next, we shall determine the limiting reactant

From the balanced equation above,

, 12 g of C reacted with 32 g of O₂.

Therefore,

144 g of C will react with = (144 × 32)/12 = 384 g of O₂.

From the calculations made above, we can see that both C and O₂ are sufficient for the reaction. Thus, C and O₂ are both limiting reactants.

Finally, we shall determine the mass of CO₂ obtained from the reaction.

From the balanced equation above,

balanced equation above, 12 g of C reacted to produce 44 g of CO₂.

Therefore,

144 g of C will react to produce = (144 × 44)/12 = 528 g of CO₂.

Thus, the mass of CO₂ obtained from the reaction is 528 g

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Which of the following is true about a compound where there is a difference in
electronegativity of the two elements if the formula of the compound is greater than
1.7?
The compound is a binary covalent compound.
The compound is a covalent compound.
The compound is an ionic compound.
The compound is a polyatomic compound.

Answers

Answer:

D  BLESSS Y

Explanation:

Which stage of a fire can be described as follows: The flames are not visible and the combustible item no longer generates heat or combustion products

Answers

Fire extinguishment is referred to the stage in which flames are not visible

and the combustible item no longer generates heat.

This stage refers to when the fire has been put out through a fire

extinguisher or other compounds.   When fire is put out, there is no longer

flames present.

The absence of flames also means that there is no heat generation or

combustion products due to the absence of a heat source.

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WILL GIVE BRAINLEST

Water waves in a small tank are 6.0 cm long. They pass at a given point at a rate of 4.8 waves per second. What is the speed of the wave?

Answers

Answer:,   Correct option is    0.288m/s

Explanation:    

The relationship between the velocity of the wave, its wavelength and frequency is given by the formula

Wavelengthλ=

Frequency(ν)

Speed(v)

,

where, v - velocity of the wave

           λ - wavelength of the wave

          f - frequency of the wave.

In the question it is given that the frequency is 4.8 Hz and the wavelength is 6.0 cm, that is, 0.06 meters.

The velocity of the sound is calculated as follows.

v=f×λ=4.8 Hz×0.06 m=0.288 m/s

Hence, the speed of the water wave is 0.288 m/s.

Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)

Answers

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻   (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).  

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

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I hope it helps you!

Can anybody complete this for me?

Answers

Answer:

I wish i could

Explanation:

5. If 10.0 gram of aluminum chloride are decomposed, how many molecules of Cl, are
produced?

Answers

Answer:   6.77*1022 Molecules

Explanation: :)

For the given reactions determine if the entropy increases or decreases.

A) 2 KClO3 (s)⇌2 KCl (s)+3 O2 (g)

B) CoCl2 (s)+6 H2O (g)⇌CoCl2⋅6H2O

Answers

Entropy increases in reaction 1 due to increase in the number of particles while entropy decreases in reaction 2 due to decrease in the number of particles.

Entropy refers to the degree of disorderliness in a system. The higher the entropy, the more disorderly the system is and the lower the entropy, the less disorderly the system is. We must note that entropy increases with increase in the number of particles.

In the reaction,  2 KClO3 (s)⇌2 KCl (s)+3 O2 (g), entropy increases because one of the products is a gas and the number of particles increases from left to right. In the second reaction, CoCl2 (s)+6 H2O (g)⇌CoCl2⋅6H2O, entropy decreases because the number of particles decreases.

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In a reaction, 0.209 moles of gas is evolved. Given that the pressure is 0.669 atm and the volume of the gas is 7.30 L, calculate the
temperature of the gas in Kelvin, giving your answer to three significant figures.
The value of R is 0.0821 L'atm-K-1.mol-1
Temperature =
Kelvin

Answers

16161819292xxdddscccdd

Find the volume of 0.170 M sulfuric acid necessary to react completely with 72.2 g sodium hydroxide.

Answers

The volume of sulphuric acid, H₂SO₄ needed for the complete reaction with 72.2 g of sodium hydroxide, NaOH is 5.31 L

We'll begin by calculating the number of mole in 72.2 g of NaOH. This can be obtained as follow:

Mass of NaOH = 72.2 g

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 72.2 / 40

Mole of NaOH = 1.805 mole

Next, we shall determine the number of mole of H₂SO₄ needed to react with 1.805 mole of NaOH.

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

From the balanced equation above,

2 moles of NaOH reacted with 1 mole of H₂SO₄.

Therefore,

1.805 mole of NaOH will react with = 1.805 / 2 = 0.9025 mole of H₂SO₄.

Finally, we shall determine the volume of H₂SO₄.

Mole of H₂SO₄ = 0.9025 mole

Molarity of H₂SO₄ = 0.170 M

Volume of H₂SO₄ =?

Volume = mole / Molarity

Volume of H₂SO₄ = 0.9025 / 0.170

Volume of H₂SO₄ = 5.31 L

Thus, the volume of H₂SO₄ needed for the reaction is 5.31 L

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plate tectonics-1.gif
What is the above image a representation of?

Answers

Answer:

Subduction Process where the oceanic plate subducted under the continental plates because it denser than the Continental plate.

The boiling point of a substance is tested. After 10 tests, the result is given as 37+/−3°C. Which conclusion can be drawn from this result?

A- The scientists do not need to collect more data because they have narrowed down the range of the results.

B- The scientists should not report these results until they have the exact number.

C- The actual boiling point is either 34°C or 40°C.

D- The actual boiling point is probably between 34°C and 40°C.

Answers

From the data obtained from the tests, the actual boiling point lies between 34°C and 40°C.

The boiling point of a substance is the temperature at which the pressure of the substance becomes equal to atmospheric pressure. Pure substances have a sharp boiling point while impure substances boil over a temperature range.

In this case, the boiling point of the substance after 10 tests is obtained as 37+/−3°C. This implies that the actual boiling point lies between 34°C and 40°C.

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hydrogen bond is a strong dipole interaction for example water and other molecules true or false

Answers

Answer:

hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond it is a mere electrostatic attraction. These attractions can occur between molecules or within different parts of a single molecule. Intramolecular hydrogen bonds are those which occur within one single molecule.

Explanation:

CAN I GET BRAINLIEST

Explain how the following properties change across the periodic Table from group 1 to group 2, and give reasons for the increase or decrease thereof:
a) Ionic radius
b) Ionization enthalpy
c) Density
d) Melting point
e) Electropositive character​

Answers

The following properties change across the periodic Table from group 1 to group 2

a) Ionic radius - decreaseb) Ionization enthalpy - increasec) Density - increased) Melting point - increasee) Electropositive character​ - decrease

Group 1 are alkali metals that have one valence electron in the outermost orbit whereas alkaline earth metals are in group 2 have two valence electrons in the outermost orbit.

a) Ionic radius:

The atomic and ionic radii of alkaline earth metals are fairly large though smaller than those of the corresponding alkali metals.  

b) Ionisation enthalpy:

Alkali metals have low Ionisation energy.in the case of alkaline earth metals Ionisation energy is higher compared to alkali metals  

c) Density:

The alkaline earth metals are denser than the alkali metals due to the smaller size and better packing of the atoms in the crystal lattice  

d) Melting point:

Melting points of alkaline earth metals are low but higher than those of alkali metals.  

e) Electropositive character:

all alkali metals are strongly Electropositive due to their low Ionisation enthalpies.alkaline earth metals are less Electropositive than alkali metals.

Thus, changes in properties are:

a) Ionic radius - decreaseb) Ionization enthalpy - increasec) Density - increased) Melting point - increasee) Electropositive character​ - decrease

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You measure the absorbance of your extracted curcumin solution and realize that the solution is too concentrated. What made you realize this

Answers

If the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high.

Spectrometry measures the interaction of light with molecules. The absorbance refers to how much light that interacts with molecules of the substance. The more the concentration of the substance the higher the absorbance of the solution.

Hence, if  the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high. An unusually high absorbance tells us that the solution is too concentrated.

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HELP HELP HELP ASAPPPP!

So the question is:

Relate the electron configuration pattern to the general trends in atomic properties in the periodic table including definitions
a. Atomic radii (size)
b. Electronegativity
c. Ionization energy

Answers

Answer:

b. Electronegativity

Explanation:

electronic configuration

Calcium has an electronegativity value of 1.0.

Oxygen has an electronegativity value of 3.5.

What type of bond will form between the two atoms?

Answers

Answer:

ionic bond

Explanation:

Calcium gives its two valence electrons to oxygen and forms an ionic bond with oxygen. An ionic bond formed when one atom transfers one or more electrons from itself to its neighboring atom, and an ionic bond formed between the two atoms of the compound.

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