Which numbers are arranged in order least to greatest

The "example" which best shows the "labor-issue" related to the wages is (a) Employer is accused of failing to pay "covered-employees" at a rate that meets the requirements of national and state laws.

The "Labor-Issue" involves the payment of wages and compliance with wage laws, which includes minimum wage requirements, overtime pay, and other wage-related regulations.

The Failing to pay the employees at the promised rate that meets the legal requirements can lead to legal and financial consequences for the employer, and may result in a dispute or conflict between the employer and employees.

Therefore, the correct option is (a).

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The given question is incomplete, the complete question is

Which example best shows a labor issue related to wages?

(a) An employer is accused of failing to pay covered employees at a rate that meets the requirements of national and state laws.

(b) An employee is accused of making repeated, unwanted comments based on an employee's age and religion.

(c) A manager refused to allow a woman who had just given birth the time off required by law.

(d) A company is accused of refusing to hire a highly qualified applicant based on his disability and age.

Interval estimation refers to the use of sample data to calculate a range of values that is believed to include the value of the population parameter.

Interval estimation in statistics is the calculation of the interval or set of values in which the parameter is. For example, the mean (mean) of the population is most likely to be located. The confidence coefficient is calculated by choosing intervals in which the parameter falls with a probability of 95 or 99 percent. Consequently, the intervals are referred to as confidence interval estimates. The formula for estimating an interval is, [tex] \mu = \bar x ± Z_{ \frac{\alpha}{2}}(\frac{\sigma}{\sqrt{n}})[/tex]

Where, the confidence coefficient

The purpose of the interval estimate is to quantify the precision of the point estimate. So the desired answer is an interval estimate.

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Answer:

[tex]-6\leq x < 5[/tex]

Step-by-step explanation:

Given compound inequality:

[tex]31 \geq-4x+7\;\;\;\textsf{and}\;\;\;-4x+7 > -13[/tex]

Solve the first inequality:

[tex]\begin{aligned}31 & \geq -4x+7\\\\31 +4x& \geq -4x+7+4x\\\\4x+31& \geq 7\\\\4x+31-31 & \geq 7-31\\\\4x & \geq -24\\\\\dfrac{4x}{4} & \geq \dfrac{-24}{4}\\\\x & \geq -6\end{aligned}[/tex]

Solve the second inequality:

[tex]\begin{aligned}-4x+7& > -13\\\\-4x+7-7& > -13-7\\\\-4x& > -20\\\\\dfrac{-4x}{-4}& > \dfrac{-20}{-4}\\\\x& < 5\end{aligned}[/tex]

Therefore, combining the solutions, the solution to the compound inequality is:

[tex]\large\boxed{-6\leq x < 5}[/tex]

When graphing inequalities:

To graph the solution:

The derivative of F(x) is F'(x) = -x² + 5.

What is derivative?

In calculus, the derivative of a function is a measure of how the function changes as its input changes. More specifically, the derivative of a function at a certain point is the instantaneous rate of change of the function at that point.

To find the derivative of F(x), we need to use the Fundamental Theorem of Calculus and apply the chain rule.

The Fundamental Theorem of Calculus states that:

∫a to x f(t)dt = F(x) - F(a)

where F(x) is the antiderivative of f(x) and a is a constant.

Using this theorem, we can find the derivative of F(x) by first finding its antiderivative:

F(x) = ∫Sx to 3 [(t² - 5)dt]

To find the antiderivative of (t² - 5), we can use the power rule:

∫(t² - 5)dt = (t³/3) - 5t + C

where C is the constant of integration.

Substituting this antiderivative back into F(x), we get:

F(x) = [(3³/3) - 5(3)] - [(Sx³/3) - 5(Sx)]

Next, we can find the derivative of F(x) using the chain rule:

F'(x) = -x² + 5

Therefore, the derivative of F(x) is F'(x) = -x² + 5.

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The coin tosses are a random event, and as the sample size (12 tosses) is relatively small, there is a possibility for some variability in the proportions reported by the students.

a) The histogram to be approximately bell-shaped, with the majority of the data clustered around the center and gradually tapering off towards the edges. This is because the coin tosses are a random event, and as the sample size (12 tosses) is relatively small, there is a possibility for some variability in the proportions reported by the students. However, as the sample size is relatively large (there are many students in the class), the Law of Large Numbers suggests that the sample means should converge towards a normal distribution.

b) The histogram to be centered around 0.5, as the coin is fair and therefore there is an equal chance of getting heads or tails on each toss. This means that the expected proportion of heads is 0.5.

c)  There to be some variability among the proportions reported by the students, as each person's results are based on a random event. However, as the sample size is relatively large, I would expect the variability to be relatively small and for the sample means to converge towards a normal distribution.

d) A Normal model should not be used here because the distribution of the proportions reported by the students is likely to be skewed, as it is bounded by 0 and 1. Additionally, as the sample size is relatively small (12 tosses), the Central Limit Theorem does not necessarily apply, and the sample means may not converge towards a normal distribution. Instead, a binomial distribution may be more appropriate to model the distribution of the proportions reported by the students.

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The best classification of the data in the list is quantitative and discrete.

Quantitative data refers to information that can be measured and expressed numerically. This type of data can be further classified as either continuous or discrete. Continuous data can take on any value within a certain range, while discrete data can only take on specific values.

Discrete data is a type of quantitative data that can only take on certain values. These values are typically integers or whole numbers, and there are no values in between. For example, the number of children in a family is discrete data, as it can only take on whole number values (1, 2, 3, etc.).

In summary, discrete data is a type of quantitative data that is characterized by its ability to only take on specific values, with no values in between.

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Answer:

Step-by-step explanation:

28

Monica should buy the 30 pound bag of dog food

The 20-pound bag contains 20 x 16 = 320 ounces of dog food.

The 30-pound bag contains 30 x 16 = 480 ounces of dog food.

Next, we can determine the cost per ounce of each bag:

The 20-pound bag costs $18, so the cost per ounce is 18 / 320 = $0.05625 per ounce.

The 30-pound bag costs $24, so the cost per ounce is 24 / 480 = $0.05 per ounce.

Finally, we can set up a proportion to compare the cost of each bag of dog food:

Cost of 20-pound bag / 320 ounces = Cost of 30-pound bag / 480 ounces

Simplifying this proportion, we get:

18 / 320 = x / 480

where x is the cost of the 30-pound bag. Solving for x, we get:

x = 24

Therefore, the cost of the 30-pound bag is lower than the cost of the 20-pound bag per ounce of dog food. Since the quality of the dog food is assumed to be the same for both bags, Monica should buy the 30-pound bag of dog food.

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Answer:

  (b)  No, the triangles do not have congruent angles.

Step-by-step explanation:

You want to know if triangle ABC with angles A=32° and B=60° is similar to triangle DEF with angles D=32° and F=38°.

The third angle in ∆ABC is ...

  C = 180° -A -B

  C = 180° -32° -60° = 88°

If the triangles were similar, angle C would have the same measure as angle F.

We notice angle C = 88° and angle F = 38°. They are not congruent.

Are the triangles congruent?

  (b) No, the triangles do not have congruent angles.

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If the rate of change of f at x=c is twice the rate of change at x=1, then c=4.

What is derivatives?

In calculus, the derivative is a mathematical concept that measures how a function changes as its input changes.

We can start by finding the derivative of f(x) using the power rule:

f'(x) = [tex](1/2)x^{(1/2)}[/tex]

Then, we can find the rate of change of f at x=c by evaluating f'(c). Similarly, we can find the rate of change of f at x=1 by evaluating f'(1). We know from the problem that the rate of change at x=c is twice the rate of change at x=1, so we can write:

f'(c) = 2*f'(1)

Substituting the expressions for f'(c) and f'(1), we get:

[tex](1/2)c^{(-1/2)}[/tex] = 2*(1/2)*[tex](1)^{(-1/2)}[/tex]

Simplifying the right-hand side, we get:

[tex](1/2)c^{(-1/2)}[/tex] = 1

Multiplying both sides by 2 and taking the reciprocal, we get:

[tex]c^{(1/2)}[/tex] = 2

Squaring both sides, we get:

c = 4

Therefore, c = 4.

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The p-value will be smaller if the sample proportions are far apart because a larger difference results in a larger absolute value of the numerator of the test statistic. A

The p-value measures the strength of the evidence against the null hypothesis.

A smaller p-value indicates stronger evidence against the null hypothesis, and a larger p-value indicates weaker evidence against the null hypothesis.

Comparing two sample proportions with a two-sided alternative hypothesis, all other factors being equal, the p-value will be smaller if the sample proportions are far apart.

This is because a larger difference between the sample proportions results in a larger absolute value of the numerator of the test statistic, which is used to calculate the p-value.

The numerator of the test statistic is the difference between the sample proportions, so a larger difference between the sample proportions will result in a larger absolute value of the numerator, which will result in a smaller p-value.

Option A correctly explains this by stating that a larger difference between the sample proportions results in a larger absolute value of the numerator of the test statistic, which results in a smaller p-value.

Option B is not correct, as a pooled proportion close to 0.5 actually results in a larger standard error, which would result in a larger p-value, not a smaller one.

Option C is not correct, as a smaller difference between the sample proportions would result in a larger p-value, not a smaller one.

Option D is also not correct, as a smaller standard error would result in a larger test statistic and a smaller p-value, but the standard error is not affected by the closeness of the sample proportions.

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If boat is heading towards a lighthouse, whose beacon-light is 142 feet above the water, the distance from point A to point B is approximately 226.6 feet.

To find the distance from point A to point B, we can use the tangent function. Let x be the distance between point A and the lighthouse, and let y be the distance between point B and the lighthouse. We can then set up two equations based on the angles of elevation:

tan(13°) = 142/x

tan(20°) = 142/y

Solving for x and y, we get:

x = 142/tan(13°) ≈ 627.8 feet

y = 142/tan(20°) ≈ 401.2 feet

The distance between point A and point B is the difference between x and y:

x - y ≈ 226.6 feet

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Complete question is:

A boat is heading towards a lighthouse, whose beacon-light is 142 feet above the water. From point A, the boat’s crew measures the angle of elevation to the beacon, 13 degree, before they draw closer. They measure the angle of elevation a second time from point B at some later time to be 20 degrees . Find the distance from point A to point B. Round your answer to the nearest foot if necessary.

To dynamically allocate memory for an array named stock prices with 500 elements, each of type float, we can use the malloc() function in C.

The syntax for malloc() is as follows: float *stock_prices = (float*)malloc(500 * sizeof(float));.
This allocates memory for 500 float elements and assigns the pointer to the first element to the variable stock_ prices.

To assign values to the first five elements of the array using pointer arithmetic, we can use the following code:

*(stock_prices + 0) = 10.0;
*(stock_prices + 1) = 12.0;
*(stock_prices + 2) = 15.5;
*(stock_prices + 3) = 13.25;
*(stock_prices + 4) = 17.8;

This code uses pointer arithmetic to access the first five elements of the array and assign values to them. The *(stock_prices + i) notation means "the value at the memory location stock_prices + i", where i is the index of the element we want to access.

In this way, we have dynamically allocated memory for an array of float elements, assigned some values to the first five elements using pointer arithmetic, and utilized the concepts of value, array, and arithmetic in the process. you can use the following C++ code:

```cpp
#include
#include

int main() {
   float *stock_prices = new float[500]; // Dynamically allocate memory for an array of 500 floats

   // Assign values to the first five elements using pointer arithmetic
   *(stock_prices + 0) = 10.0;
   *(stock_prices + 1) = 15.0;
   *(stock_prices + 2) = 20.0;
   *(stock_prices + 3) = 25.0;
   *(stock_prices + 4) = 30.0;

   // Display the first five values
   for (int i = 0; i < 5; i++) {
       std::cout << "stock_prices[" << i << "] = " << *(stock_prices + i) << std::endl;
   }

   delete[] stock_prices; // Release the dynamically allocated memory
   return 0;
}
```

This code creates a float pointer 'stock_prices', allocates memory for 500 elements, assigns values to the first five elements using pointer arithmetic, and displays them. Finally, it releases the dynamically allocated memory.

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The F statistic, we divide the mean square for treatments by the mean square for error, which gives us 9.86

What is the mean and standard deviation?

The standard deviation is a summary measure of the differences of each observation from the mean. If the differences themselves were added up, the positive would exactly balance the negative and so their sum would be zero. Consequently, the squares of the differences are added.

Using the information given,

To calculate the F statistic, we divide the mean square for treatments by the mean square for error, which gives us:

F = MS(T)/MS(E) = 2280/231.11 = 9.86

The degrees of freedom for treatments is 2 (since there are three methods and we lose one degree of freedom due to the constraint that the sum of the means of each method is equal to the overall mean), and the degrees of freedom for error is 27 (which is the total number of observations minus the total number of treatments).

Therefore, the ANOVA table for this problem is in the attached figure.

Hence, the F statistic, we divide the mean square for treatments by the mean square for error, which gives us 9.86

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The circular arcs of radius 5 units bound the region so the area, in square units, of the region is 50.

The simplest way to think about it is as follows. Assume we wish to define R as the entire region in the first quadrant above the graph y = x 2. S is now defined as the entire region below the graph of y = x. It is obvious that the region R S equals the area in the first quadrant below y = x minus the area under the curve y = x 2. Try to figure out why this is the case, and then click Continue.

Now that we know what kind of problem we're dealing with, we can start turning it to arithmetic, namely integrals. Take note that the region of interest goes between the two curve junctions.

The area of the semicircle is = [tex]\frac{1}{2} \pi 15^2[/tex]

= 25/2π

The area of the two quarter - circles is

= 2 x 1/4 x π x 25

= 25π/2

So, the area of the region is

= 25π/2 + 5x(5+5) - 25π/2

= 50

Therefore, area of square unit is 50.

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there are 1500 different super subs that can be made.

What is combination?

In mathematics, a combination is a way of selecting objects from a set, where the order in which the objects are selected does not matter. Combinations are used in various areas of mathematics and statistics, as well as in real-world applications such as probability theory, genetics, and computer science.

For the toppings, we have to choose 4 out of the 6 available, so the number of ways to do that is:

6C4

=15

This is the number of combinations of 4 toppings that can be chosen from 6.

For the condiments, we have to choose 3 out of the 6 available, so the number of ways to do that is:

6C3

=20

This is the number of combinations of 3 condiments that can be chosen from 6.

Finally, we have 5 choices of bread.

Therefore, the total number of different super subs that can be made is:

15*20*5 = 1500

So there are 1500 different super subs that can be made.

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The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

To solve this differential equation, we can use separation of variables.

First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:

dy/dx = 1/3(sin x − xy^2)

dy/(sin x - xy^2) = dx/3

Now we can integrate both sides:

∫dy/(sin x - xy^2) = ∫dx/3

To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:

∫dy/(sin x - xy^2) = ∫du/(sin x - u)

= -1/2∫d(cos x - u/sin x)

= -1/2 ln|sin x - xy^2| + C1

For the right side, we simply integrate with respect to x:

∫dx/3 = x/3 + C2

Putting these together, we get:

-1/2 ln|sin x - xy^2| = x/3 + C

To solve for y, we can exponentiate both sides:

|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)

|sin x - xy^2| = 1/e^(2C/3 - x/3)

Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.

Case 1: sin x - xy^2 > 0

In this case, we have:

sin x - xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]

Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:

y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5

Squaring both sides and solving for C, we get:

C = 3/2 ln(1/25)

Putting this value of C back into the expression for y, we get:

y = √[(sin x - e^(x/2)/25)/x]

Case 2: sin x - xy^2 < 0

In this case, we have:

- sin x + xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(e^(2C/3 - x/3) - sin x)/x]

Again, using the initial condition y(0) = 5 and solving for C, we get:

C = 3/2 ln(1/25) + 2/3 ln(5)

Putting this value of C back into the expression for y, we get:

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]

So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:

y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5

Note that there is no solution for y when sin x - xy^2 = 0.

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The matrix a is given such that a² - 3a - 2I = 0. It is shown that ai is invertible, and its inverse is  (1/2)(a_i - 3i).

Given: a² - 3a = 2i

Multiplying both sides by a⁻¹, we get

a - 3i = 2a⁻¹

Rearranging, we get

a⁻¹ = (1/2)(a - 3i)

Now, we need to show that a_i is invertible, i.e., we need to find (a_i)⁻¹.

We know that

(a_i)² - 3(a_i) = a

Multiplying both sides by a_i⁻¹, we get

a_i - 3i = a_i⁻¹ * a

Rearranging, we get

a_i⁻¹ = (1/2)(a_i - 3i)

Therefore, (a_i)⁻¹ exists and is given by (1/2)(a_i - 3i).

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Rounding up to the nearest whole number, the sample size used to conduct this confidence interval is roughly 385. So, the sample size used to conduct this 95% confidence interval is roughly 340 students.

To find the sample size that was used to conduct this confidence interval, we need to use the formula:

n = (Z^2 * p * q) / E^2

where:

n = sample size
Z = the z-score associated with the confidence level (in this case, 1.96 for a 95% confidence interval)
p = the proportion of first-year students who played in intramural sports (0.35 in this case)
q = 1 - p (the proportion who did not play in intramural sports)
E = the margin of error (0.05 in this case)

Plugging in the values we have:

n = (1.96^2 * 0.35 * 0.65) / 0.05^2
n = 384.16

Rounding up to the nearest whole number, the sample size used to conduct this confidence interval is roughly 385.

Based on the given 95% confidence interval for the proportion of first-year students who played intramural sports, we can estimate the sample size used. The conservative interval is 35% ± 5%, which means the proportion ranges from 30% to 40%.

To calculate the sample size, we can use the following formula:

n = (Z^2 * p * (1-p)) / E^2

Where:
n = sample size
Z = Z-score for a 95% confidence level (1.96)
p = proportion (0.35)
E = margin of error (0.05)

n = (1.96^2 * 0.35 * (1-0.35)) / 0.05^2
n ≈ 340

So, the sample size used to conduct this 95% confidence interval is roughly 340 students.

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Answer:

The area of the circular floor in square feet is 6,939.78 ft².

The area of the circular floor in square yards is 771.09 yd².

The legislature must spend $60,145 for the carpeting project.

Step-by-step explanation:

The area of a circle is given by the formula A = πr², where r is the radius of the circle.  The radius of a circle is half its diameter.

Given the diameter of the state capital building's circular floor is 94 feet, its radius is:

[tex]\implies r=\dfrac{94}{2}=47\sf \;ft[/tex]

To find the area of the circular floor in square feet, substitute r = 47 into the formula for area of a circle:

[tex]\begin{aligned}\implies \sf Area &= \pi(47)^2\\&=2209\pi\\&=6939.78\;\sf ft^2\;(2\;d.p.)\end{aligned}[/tex]

Therefore, the area of the circular floor in square feet is 6,939.78 ft² (rounded to two decimal places).

To convert square feet to square yards, divide the area in square feet by 9. Therefore, the area of the circular floor in square yards is:

[tex]\begin{aligned}\implies \sf Area &= \dfrac{2209\pi}{9}\\&=771.09\; \sf yd^2\;(2\;d.p.)\end{aligned}[/tex]

Therefore, the area of the circular floor in square yards is 771.09 yd² (rounded to two decimal places).

To find the total cost of the project, given the lowest bid for the project is $78 per square yard, multiply the area of the circular floor in square yards by the cost per square yard:

[tex]\begin{aligned}\implies \sf Total\;cost &=771.09 \cdot \$78\\&=\$60145.02\end{aligned}[/tex]

Therefore, the legislature must spend $60,145 for the carpeting project, (rounded to the nearest dollar).

Answer:

Y=13

Step-by-step explanation:

Based on the information given in your question, where the expectation of the square of the maximum eigenvalue is at most Nσ², we can deduce that the expression should have the form:

E[(λ_max(A))²] ≤ Nσ²

A matrix is a rectangular array made up of numbers, equations, or symbols. With an order of number of rows x number of columns, this arrangement is made up of horizontal rows and vertical columns.

Let's consider the random matrix A with iid entries and variance σ². We denote its maximum eigenvalue as λ_max(A).

To establish an upper bound on the expectation of the square of the maximum eigenvalue, we'll use the result from random matrix theory known as Marchenko-Pastur law.

According to the Marchenko-Pastur law, for a random matrix A with iid entries, as the size of the matrix becomes large (N → ∞), the distribution of eigenvalues follows a Marchenko-Pastur distribution. This distribution depends on the aspect ratio, q = p/N, where p represents the number of columns in the matrix A.

The Marchenko-Pastur distribution has a probability density function given by:

f(λ) = (1/(2πσ²qλ)) * √((λ_max - λ)(λ - λ_min))

where λ_min and λ_max are the minimum and maximum eigenvalues supported by the distribution, which can be calculated as:

λ_min = (1 - √(q))²σ²

λ_max = (1 + √(q))²σ²

Now, let's calculate the expectation of the square of the maximum eigenvalue:

E[(λ_max(A))²] = ∫[λ_min, λ_max] λ² * f(λ) dλ

Substituting the expression for f(λ), we get:

E[(λ_max(A))²] = ∫[λ_min, λ_max] λ² * (1/(2πσ²qλ)) * √((λ_max - λ)(λ - λ_min)) dλ

After simplification, we find:

E[(λ_max(A))²] = (1/(2πσ²q)) ∫[λ_min, λ_max] √((λ_max - λ)(λ - λ_min)) dλ

The integral on the right-hand side can be computed analytically using standard techniques. However, the exact form of the expectation will depend on the specific values of q and σ².

Based on the information given in your question, where the expectation of the square of the maximum eigenvalue is at most Nσ², we can deduce that the expression should have the form:

E[(λ_max(A))²] ≤ Nσ²

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8(a). To find the sample proportion, divide the number of adults with pinworm infestation (68) by the total number of adults in the sample (820).

Sample proportion (p) = 68 / 820 = 0.083

To find the critical value, we use a 98% confidence interval, which leaves 2% in the tails. Divide this by 2 to get 1% in each tail. Using a z-table, we find that the z-score corresponding to a 99% cumulative probability is 2.576.

Critical value (z) = 2.576

Next, we calculate the margin of error. The formula for margin of error is:

Margin of error = z * √(p * (1-p) / n)

Margin of error = 2.576 * √(0.083 * (1-0.083) / 820) ≈ 0.028

8(b). To construct the 98% confidence interval, add and subtract the margin of error from the sample proportion:

Lower limit = 0.083 - 0.028 = 0.055
Upper limit = 0.083 + 0.028 = 0.111

The 98% confidence interval is (0.055, 0.111).

8(c). We want to determine if we are 98% confident that more than 5% of all U.S. adults have pinworm. Since 0.05 is below the lower limit of the confidence interval (0.055), the correct answer is:

Yes, because 0.05 is below the lower limit of the confidence interval.

8(d). In Sludge County, the proportion of adults with pinworm is 0.12. We need to compare this to our confidence interval (0.055, 0.111). Since 0.12 is above the upper limit of the confidence interval, the correct answer is:

Yes, because 0.12 is above the upper limit of the confidence interval.

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Answer:

28.27

Step-by-step explanation:

A=πr2=π·32≈28.27433mi²

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If we remove an arbitrary edge from a tree, the resulting graph will still be connected and acyclic (meaning it does not contain any cycles). This is because a tree is defined as a connected and acyclic graph. Removing an edge will not disconnect the graph since there is always at least one path between any two vertices in a tree. However, the resulting graph will no longer be a tree, as a tree must have exactly one fewer edge than vertices.

If we remove an arbitrary edge from a tree, then the resulting graph will be:

1. A disconnected graph: Since a tree is a connected graph with no cycles, removing an edge will separate it into two components.
2. The components will be trees: Each component will still have no cycles and will remain connected.

So, when you remove an arbitrary edge from a tree, the resulting graph will be a disconnected graph with two tree components.

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The degree of the expression 12x+5x²-99x⁵ is

The degree of an algebraic expression is the highest power of the variable in the expression. An expression can have a variable or more.

For example, the degree of the expression 5y⁷+ 6y⁴+ 3y² is 7 because 7 is the highest exponent of the variable y in the expression.

Similarly the expression 12x+5x²-99x⁵ has 3 terms with x has the variable. The highest power of x in the expression is 5. Therefore the degree of the expression is 5.

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The experimental probability of drawing a heart is given as follows:

0.30.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

The total number of outcomes is given as follows:

6 + 4 + 7 + 3 = 20.

Out of these 20 trials, 6 resulted in a heart, hence the experimental probability of drawing a heart is given as follows:

p = 6/20

p = 0.3

p = 30%.

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Since the proposed side length of the square is between 6 and 7, we can assume that it is 6.5 hence, the lengths will be d = 6.5 and c = 9.19.

Here is what we were given:

Side length of square = 6 > x <7

A convenient assumption for this is 6.5

We also know that d and c and the base of two right triangles. where their hypotheses' are equal to the side lenght of the square = 6.5

we also know that the in between the line formed by D and C is a 90 degree angle.

Hence the sum of the other angle will be 45 degrees each.

This is  based on sum of angles in a triangle.

Hence,

c = b /sin(β)

= 6.5/sin (45)

= 6.5/0.70710678118

 c = 9.19

d = √c² - b²

 = √(9.19238815542512² - 6.52²)

= √42.25

d = 6.5

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The resolution of the human eye is ultimately limited by the pupil diameter.

When the pupil diameter is 2.18mm, the smallest diameter spot the eye can produce on the retina is determined by the diffraction limit, which can be calculated using the formula:

θ = 1.22 * (λ / D)

where θ is the angular resolution, λ is the wavelength of light (typically around 550 nm for the visible spectrum), and D is the pupil diameter (2.18mm in this case). To find the smallest diameter spot on the retina, you would need to multiply the angular resolution by the distance from the lens to the retina (approximately 17mm for an average human eye).

However, the information provided is insufficient to calculate the exact smallest diameter spot. Additionally, factors like the density of photoreceptor cells in the retina also play a role in determining the resolution of the eye.

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The height at the 45th percentile is approximately 63.75 inches.

The height at the 45th percentile, we can use the z-score formula:

z = (x - μ) / σ

where:

x is the height we want to find

μ is the population mean, which is 64 inches

σ is the population standard deviation, which is 2.0 inches

z is the z-score corresponding to the 45th percentile, which we can find using a standard normal distribution table or calculator.

The z-score corresponding to the 45th percentile, we can use the inverse normal cumulative distribution function (also called the inverse Gaussian function) with a probability of 0.45:

z = invNorm(0.45) = -0.1257 (rounded to four decimal places)

Now we can solve for x:

z = (x - μ) / σ

-0.1257 = (x - 64) / 2.0

-0.1257 × 2.0 = x - 64

-0.2514 + 64 = x

x = 63.7486

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