The statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans. That is option C.
Who is an audiologist?Audiologist is an individual that specializes in the diagnosis, treatment and management of hearing loss and balance disorders in adults and children.
An anthropologist is also an individual that studied the past and present experiences of individuals.
Therefore, the statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans.
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Question 9 of 34
When you graph displacement versus time (a displacement-time graph), what
variable is on the y-axis?
O A. Speed
OB. Displacement
C. Time
O D. Velocity
SUBMIT
Answer:
Option B) Displacement
The ability to provide for our needs without damaging Earth's resources is called _______.
A. Acid Rain
B. Sustainability
C. Degradation
D. Pollution
Answer = B
Explanation:
Sustainability is the most appropriate as it means meeting our own needs without compromising the ability of future generations to meet their own needs.
2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
her displacement after 15.0 seconds?
Answer:
337.5m
Explanation:
Kinematics
Under constant acceleration, the kinematic equation holds:
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex], where "s" is the position at time "t", "a" is the constant acceleration, "[tex]v_o[/tex]" is the initial velocity, and [tex]s_o[/tex] is the initial position.
Defining Displacement
Displacement is the difference in positions: [tex]s-s_o[/tex] or [tex]\Delta s[/tex]
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex]
[tex]s-s_o=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
Using known information
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+(0)*t[/tex]
[tex]\Delta s=\frac{1}{2}at^2+0[/tex]
[tex]\Delta s=\frac{1}{2}at^2[/tex]
So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:
[tex]\Delta s=\frac{1}{2}at^2[/tex]
[tex]\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2[/tex]
[tex]\Delta s=337.5[m][/tex]
The vertical component of 9N is found to be four-thirds of the horizontal component.
a) Find the horizontal component.
b)Find the magnitude of the vector
Answer:
a) Let horizontal component be h
4/3×h= 9
4h = 9x3
h = 27/4
b) Magnitude = √ [9²+ (27/4)²
= 11.25
51. A balloon starts rising from the ground, vertically upwards, uniformly at the rate of 1 m s-1. At the end of 4 seconds, a body is released from the balloon. Calculate the time taken by the released body to reach the ground. 51. A balloon starts rising from the ground , vertically upwards , uniformly at the rate of 1 m s - 1 . At the end of 4 seconds , a body is released from the balloon . Calculate the time taken by the released body to reach the ground
Answer:
4s
Explanation:
when a bOdy rises into the air,the time it takes to reach a particular height is the same as the time it will take the body to fall from that height to the ground.
what evidence did astronomers use to prove jets travel in opposite directions?
The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
Who are the astronomers?Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.
Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
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What is a characteristic of a catamaran hull? tends to pitch in waves only recommended on calm inland waters planes at low speed a stable ride
A Stable Ride is the main characteristic of a catamaran hull.
What is catamaran hull?
Catamaran Hull is a multi-hulled watercraft, which have two parallel hulls of equal size.
The characteristic of a catamaran hull are as follows:
A catamaran hull has less volume than an equal size monohull.Catamaran hulls are distinguished by lighter displacement and shallower draft when compared to monohulls of the same length. Catamarans can be used in shallow waters as well. This feature makes catamarans quite flexible and versatile.Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability.Catamarans derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat.Therefore, Catamarans has a stable ride, according to their characteristic.
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In the homecoming game, the field goal kicker attempts to make a 47 yard (43 m) field goal. He kicks with an initial velocity of 20 m/s at an angle of 60° The field goal posts are 3 m high. Does he make the field goal? Explain your answer.
Given the data from the question, the goal kicker did not make the field goal.
To determine if the goal kicker makes the field goal, we shall determine the distance (i.e range) travelled by the ball after it was kicked by the kicker. This can be obtained as follow:
How to determine the range Initial velocity (u) = 20 m/sAngle of projection (θ) = 60 °Acceleration due to gravity (g) = 9.8 m/s²Range (R) = ?R = u²Sine(2θ) / g
R = 20² × Sine (2×60) / 9.8
R = 400 × Sine 120 / 9.8
R = 35.3 m
Since the distance travelled by the ball is 35.3 m and the goal post is situated 47 yard (43 m) away.
Thus, we can conclude that the goal kicker did not make the goal as the ball did not get to the post which is 47 yard (43 m)
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Use the image to determine the volume of the rock.
Answer:
12 ml
Explanation:
The initial volume in the cylinder is 20 ml
adding the rock adds volume to the cylinder
the new volume is 32 ml .....the increase in volume is the volume of the rock : 32 - 20 = 12 ml volume of rock
A ball is shot from the ground straight up into the air with initial velocity of 40 ft/sec. Assuming that the air resistance can be ignored, how high does it go
The height to which the ball attained, given the data is 7.58 m
Data obtained from the questionInitial velocity (u) = 40 ft/s = 40 × 0.3048 = 12.192 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =? How to determine the maximum heightv² = u² – 2gh (since the ball is going against gravity)
0² = 12.192² – (2 × 9.8 × h)
0 = 12.192² – 19.6h
Collect like terms
0 – 12.192² = –19.6h
–12.192² = –19.6h
Divide both side by –19.6
h = –12.192² / –19.6
h = 7.58 m
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An atom is the most basic particle that represents what type of matter?
OA. Element
OB. Compound
OC. Crystal
OD. Mixture
Answer:
b
Explanation:
What is the change of state when magma crystallises to form igneous rock?
Answer:
liquid
Explanation:
due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock
Find the energy u of the capacitor in terms of c and q by using the definition of capacitance and the formula for the energy in a capacitor
The formula for the energy in a capacitor , u in terms of q and c is q²/2c
What is the energy of a capacitor?The energy of a capacitor u = 1/2qv where
q = charge on capacitor and v = voltage across capacitor.What is the capacitance of a capacitor?Also, the capacitance of a capacitor c = q/v where
q = charge on capacitor and v = voltage across capacitor.So, v = q/c
The formula for energy of the capacitor in terms of q and c
Substituting v into u, we have
u = 1/2qv
= 1/2q(q/c)
= q²/2c
So, the formula for the energy in a capacitor , u in terms of q and c is q²/2c
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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.500 m. What is net force on 93?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m-
-5.00 x 10-6 C
92
-5.00 x 10-6 C
93
0.500 m-
The answer to the question is 1.125 Newton
Formula for electrostatic force is F = ( K q1 q2 )/ r²
where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.
Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.
Electrostatic force between q1 and q3
r will be 0.500 + 0.500 = 1 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²
F₁₃ = 2.25 × 10⁻¹ N
Electrostatic force between q2 and q3
r will be 0.500 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²
F = (225 × 10⁻³) / (25 × 10⁻²)
F₂₃ = 9 × 10⁻¹ N
Total force on q3 will be F₁₃ + F₂₃
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 11.25 × 10⁻¹ ) N
Total force on q3 = 1.125 N
Thus after solving we got the net force on q3 as 1.125 Newton
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What are two models of light? how does each model explain part of the behavior of light?
The two most successful theories of light were the corpuscular (or particle) theory of Sir Isaac Newton and the wave theory of Christian Huygens. Newton's corpuscular theory stated that light consisted of particles that travelled in straight lines.
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the 12-lead ecg shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv. what is this finding indicative of?
The 12-lead ECG test that shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, could be a diagnostic for myocardial infarction.
What is 12 - lead ECG test?
A 12-lead electrocardiogram (ECG) is a medical test that is recorded using leads, or nodes, attached to the body.
Electrocardiograms, sometimes referred to as ECGs, capture the electrical activity of the heart and transfer it to graphed paper.
When a 12-lead ECG shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, it could be a diagnostic for myocardial infarction.
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