Answers
Option C is the use of the equations to arrive at an expression for the electric field produced by a shifting magnetic field.
A current will be induced in a coil of wire if the coil is put in a magnetic field that is changing. Since there is an electric field causing the charges to be forced around the wire, current is flowing as a result. The charges are not initially moving, hence it cannot be the magnetic force.
The moving + and - charges radiate a changing electric field, and it is also visible that this field generates a changing magnetic field as well. With increasing distance from the antenna, the source of the radiation, the electric and magnetic fields lose strength.
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Related Questions
mention any two points to in established the importance of Physics.
Answers
Here are two points that establish the importance of Physics:
1. Understanding the natural world: Physics is the branch of science that helps us understand the natural world. By studying the laws of physics, we can understand the behavior of the universe, from the smallest subatomic particles to the largest structures in the cosmos. Physics provides us with a framework for understanding how the world around us works, from the motion of objects to the behavior of light and other forms of energy.
2. Advancing technology and innovation: Physics has been instrumental in advancing technology and driving innovation in many fields. From the development of electricity and electronics to the creation of the internet and advanced materials, physics has provided the fundamental knowledge and tools needed to create many of the technologies that we rely on today. Many of the most important technological advancements of the past century have been based on our understanding of physics, and continued research in this field will likely lead to many more exciting discoveries and innovations in the future.
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the temperature of an ideal gas in a sealed 0.60m^3 container is reduced from 440 k to 270 k. the final pressure did the gas is 40kpa. the molar heat capacity at constant volume of the gas is 28.0j/mol•k. what is the work done by the gas?
Answers
Great Company manufactures and sells a product whose peak sales occur in the third quarter. Management is now preparing detailed budgets for 20x4- the coming year and has assembled the following information to assist in the budget preparation: The company’s product selling price is Br. 20 per unit. The marketing department has estimated sales in units as follows for the next six quarters.
Answers
Answer:
Explanation:
Quarter 1 - 10,000 units
Quarter 2 - 12,000 units
Quarter 3 - 16,000 units
Quarter 4 - 14,000 units
Quarter 5 - 10,000 units
Quarter 6 - 8,000 units
Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.
DOES FORCE ALWAYS HAVE SOME EFFECT ON ALL OBJECT
Answers
Answer:
Answer is down below…
Explanation:
A force does not always bring a change in motion of an object. For instance, if you push the walls of the room with your hands, the walls do not move. Sometimes force changes the shape and size of an object without any change in the state of motion of an object. Q.
Particles q1 =+9.33 uC, q2 =+4.22 uC, and q3=-8.42 uC are in a line. Particles q1 and q2 are separated by 0.180 m and particles q2 and q3 are separated by 0.230 m. What is the net force on particle q2?
Answers
The net force on q₂ will be 1.07 x 10⁻² N, pointing to the left.
To find the net force on particle q₂, we need to calculate the force due to q₁ and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:
F = k × (q₁ × q₂) / r²
where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force due to q₁ on q₂ can be calculated as:
F₁ = k × (q₁ × q₂) / r₁²
where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).
Similarly, the force due to q₃ on q₂ can be calculated as:
F₂ = k × (q₃ × q₂) / r₃²
where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).
The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.
To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:
Fnet = F₁ - F₃
Substituting the values we get:
Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²
Plugging in the values we get:
Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]
Fnet = 1.07 x 10⁻² N
Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.
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in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
Answers
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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A student is asked to move a box from ground level to the top of a loading dock platform, as shown in the
figures above. In Figure 1, the student pushes the box up an incline with negligible friction. In Figure 2, the
student lifts the box straight up from ground level to the loading dock platform. In which case does the student
do more work on the box, and why?
Answers
The student does the same amount of work in both cases, as the displacement and force applied are the same.
The understudy does likewise measure of work in the two cases, ignoring any energy misfortunes because of contact or different elements. This is on the grounds that work is characterized as the result of the power applied and the removal of the item toward the power. In the two cases, the removal of the crate is something similar (the upward separation from ground level to the shipping bay stage) and the power applied by the understudy is the heaviness of the container, which is likewise something similar. Thusly, the work done by the understudy in the two cases is something similar.
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Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval listed below.
HELP PLEASE!!!
Answers
Answer:
Day 0 to day 2: 5km/day
Day 2 to day 3: 2km/day
Explanation:
Day 0 to day 2: 10/2 = 5
Day 2 to day 3: 12 - 10 = 2
To Calculate:
The x-axis, or the days from 0 to 6, line up with the y-axis, or the distance from 0 to 24. The point in the graph means that on that day, the turtle traveled that much distance. For example, on the third point (2, 10), the day is 2 and the distance is 10. To find the distance over multiple days, catalog the days in your mind and look for the points. Then, find the difference. For example, from day 2 (2, 10) to day 5 (5, 18), this would look like: 5 - 2 = 3, and 18 - 10 = 8, so this means that over 3 days, the turtle traveled 8 km.
