Which of the following is named using the unmodified element name and adding the word "ion"? Select the correct answer below:

a. simple cations (monatomic cations of elements of only one possible charge)
b. simple anions (monatomic anions of elements of only one possible charge)
c. simple protons
d. simple neutrons

Explanation:

A Bronsted-Lowry base is a substance that accepts a proton in the form of a hydrogen (H) atom.

On the other hand;

Bronsted-Lowry acid is the substance that donates the proton.

HF (aq) + SO32- ⇌ F- + HSO3-

In the forward reaction;

Bronsted-Lowry acid : HF

Bronsted-Lowry base: SO32-

In the backward reaction;

Bronsted-Lowry acid : HSO3-

Bronsted-Lowry base: F-

The conjugate base of HF is F-

The conjugate acid of SO32- is HSO3-

Answer:

I am not sure, but I think this is the answer 72.987 g/mol

the second statement is the correct one quarks are needed to balance charges in all subatomic particles such as neutrons, protons and electrons

Answer:

Explanation:

Condensation is the word you seek.

Answer:

Condensation

Explanation:

When a gas is subjected to decrease in temperature it is condensed

Answer:

Hydrogen peroxide is ans

Answer:

5

Explanation:

Answer:

5

Explanation:

Answer:

[tex]M=0.213M[/tex]

Explanation:

Hello,

In this case, for each nitrate-based salt, we compute the nitrate moles as shown below:

[tex]n_{NO_3^-}=20.00gCa(NO_3)_2*\frac{1molCa(NO_3)_2}{164.088 gCa(NO_3)_2} *\frac{2molNO_3^-}{1molCa(NO_3)_2} =0.244molNO_3^-[/tex]

[tex]n_{NO_3^-}=10.00gNaNO_3*\frac{1molNaNO_3}{84.9947 gNaNO_3} *\frac{1molNO_3^-}{1molNaNO_3} =0.118molNO_3^-[/tex]

[tex]n_{NO_3^-}=50.00gAl(NO_3)_3*\frac{1molAl(NO_3)_3}{212.996gAl(NO_3)_3} *\frac{3molNO_3^-}{1molAl(NO_3)_3} =0.704molNO_3^-[/tex]

We notice calcium nitrate has two moles of nitrate ion, sodium nitrate has one and aluminium nitrate has three. Hence we add the moles to obtain the total moles nitrate ion:

[tex]n_{NO_3^-}^{Tot}=0.244+0.118+0.704=1.066molNO_3^-[/tex]

Finally, we compute the molarity:

[tex]M=\frac{1.066molNO_3^-}{5.00L} \\\\M=0.213M[/tex]

Regards.

Answer: Transpiration---A

Explanation: Transpiration is the process in the water cycle whereby plant loose(excess) water by evaporation through the stomata of their leaves since not all water absorbed by the root is actually used for growth in plants.In order to allow the intake of carbon-dioxide, water must exit the leaves through transpiration which then  provides the plant with cooling, rigidity and maintaining the overall water balance of the plant.

Answer:

a) -7.395kJ of energy are released.

b) 125g of O₂ must react.

Explanation:

Based on the reaction:

4 Fe (s) + 3 O₂(g) → 2 Fe₂O₃ (s) ΔH = -1652 kJ

4 moles of iron with an excess of oxygen release -1652kJ of energy

a) The heat released is:

1.00g Fe (molar mass: 55.845g/mol)

1.00g × (1mol / 55.845g) = 0.0179 moles de Fe.

As 4 moles release -1652kJ, 0.0179 moles release:

0.0179 mol Fe × (-1652kJ / 4mol Fe) = -7.395kJ of energy are released.

b) As 3 moles of oxygen produce -1652kJ, 2150kJ are released when react:

2150kJ × (3 mol O₂ / 1652kJ) = 3.9 moles of O₂

As molar mass of O₂ is 32g/mol, mass of 3.9 moles of O₂ is:

3.9 mol O₂ × (32g / mol) = 125g of O₂ must react.

Answer: Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass, occupies 22.4 L at STP  contains avogadro's number [tex](6.023\times 10^{23})[/tex] of particles.

Molecular mass of protein = 480,000 g/mol

Thus 1 mole of protein weighs = 480,000 g

So 27 moles of protein weighs = [tex]\frac{480,000}{1}\times 27=12960000g[/tex]

Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams

Answer:

[tex]Q=-361.56kJ[/tex]

Explanation:

Hello,

In this case, the decomposition of hydrogen peroxide is given by:

[tex]2H_2O_2\rightarrow 2H_2O+O_2[/tex]

Which occurs in gaseous phase, therefore the enthalpy of reaction is:

[tex]\Delta _rH=2\Delta _fH_{H_2O}-2\Delta _fH_{H_2O_2}[/tex]

Oxygen is not included as it is a pure element. The enthalpies of formation for both hydrogen peroxide and water are -136.11 and -241.83 kJ/mol respectively, so we compute the enthalpy of reaction:

[tex]\Delta _rH=2(-241.83kJ/mol)-2(-136.11kJ/mol)=-211.44kJ/mol[/tex]

Then, the total heat that is released for 1.71 mol of hydrogen peroxide is:

[tex]Q=n*\Delta _rH=1.71mol*-211.44kJ/mol\\\\Q=-361.56kJ[/tex]

Whose sign means a released heat.

Regards.

Answer:

Chemical reactions, kinetics, organic chemistry

Explanation:

You might study the chemical reaction, learn about the differences between products and reactants, about delta H and exothermic and endothermic reactions. You may also study Kinetics by studying the rates of reactions with certain chemicals in a maple's enzymatic processes.

Another thing that you might learn about is organic chemistry. The glucose molecules, carbohydrates, lipids, nucleic acids, all have a structure based on the Carbon atom. You can learn about the specific structures of some chemicals that are involved in photosynthesis and simple hydrocarbons that are involved in photosynthetic/bio-synthetic pathways.

There's probably a lot more - but these are the most basic things I could think of.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is [tex]K_c = 14.39[/tex]

Explanation:

The chemical equation for this decomposition of ammonia is

                [tex]2 NH_3[/tex]  ↔   [tex]N_2 + 3 H_2[/tex]

The initial concentration of ammonia is mathematically represented a

          [tex][NH_3] = \frac{n_1}{V_1} = \frac{29}{75}[/tex]

          [tex][NH_3] = 0.387 \ M[/tex]

The initial concentration of nitrogen gas  is mathematically represented a

         [tex][N_2] = \frac{n_2}{V_2}[/tex]

         [tex][N_2] = 0.173 \ M[/tex]

So  looking at the equation

   Initially (Before reaction)

      [tex]NH_3 = 0.387 \ M[/tex]

      [tex]N_2 = 0 \ M[/tex]

      [tex]H_2 = 0 \ M[/tex]

During reaction(this is gotten from the reaction equation )

        [tex]NH_3 = -2 x[/tex](this implies that it losses two moles of concentration )

         [tex]N_2 = + x[/tex]  (this implies that it gains 1 moles)

         [tex]H_2 = +3 x[/tex](this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

        [tex]NH_3 = 0.387 -2x[/tex]

       [tex]N_2 = x[/tex]

        [tex]H_2 = 3 x[/tex]

Now since

     [tex][NH_3] = 0.387 \ M[/tex]

     [tex]x= 0.387 \ M[/tex]    

[tex]H_2 = 3 * 0.173[/tex]    

[tex]H_2 = 0.519 \ M[/tex]    

[tex]NH_3 = 0.387 -2(0.173)[/tex]

[tex]NH_3 = 0.041 \ M[/tex]

Now the equilibrium constant is

           [tex]K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}[/tex]

substituting values

           [tex]K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}[/tex]

           [tex]K_c = 14.39[/tex]

Answer:

[tex]n_N=0.041molN[/tex]

Explanation:

Hello,

In this case, for this mole-mass relationship, we are able to compute the moles of nitrogen atoms by firstly obtaining the moles of the given compound, considering its molar mass that is 194 g/mol:

[tex]n_{C_8H_{10}O_2N_4}=2.0gC_8H_{10}O_2N_4*\frac{1molC_8H_{10}O_2N_4}{194gC_8H_{10}O_2N_4} =0.01molC_8H_{10}O_2N_4[/tex]

Then, by knowing that one mole of the given compound has four moles of nitrogen atoms, we apply the following relationship:

[tex]n_N=0.01molC_8H_{10}O_2N_4*\frac{4molN}{1molC_8H_{10}O_2N_4} \\\\n_N=0.041molN[/tex]

Best regards.

Answer:

7.5 atm

Explanation:

Initial pressure P1 = 1.0 ATM

Initial volume V1= 196 L

Final pressure P2= the unknown

Final volume V2= 26000ml or 26 L

From Boyle's law we have;

P1V1= P2V2

P2= P1V1/V2

P2= 1.0 × 196/26

P2 = 7.5 atm

Therefore, as the air is compressed, the pressure increases to 7.5 atm.

Answer:

Chemical Change

Explanation:

Physical change normally mean that the change can revert back to its orginal state, which in this case that is not possible therfore it is a chemical change.

Answer:

The answer is B) A metal replaces a metallic ion below it on the list.

Explanation:

I just did it and got it correct, luckily I didn't use the other answer posted for this question.

A metal replaces a metallic ion below it on the list give reaction which would be predicted by the  activity series list.

So, option B is correct one.

The list in which elements arranged in the increasing order of their electrode potential values is called Electrochemical series.

The Electrochemical series is also called activity series.

To learn more about  Electrochemical series here.

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Explanation:

Benzene is colorless, with a sweet odour.

Color of Bromine is reddish brown .

Hope this helps.

Answer:

2. It helps us to eliminate waste

3. It helps regulate our body temperature

Explanation:

In addition to the function of bringing nutrients to the cells, water provides the elimination of substances out of the body. This occurs, for example, through urine, which is basically formed by water and toxic or excess substances dissolved.

Water also helps in regulating body temperature. This occurs when the heat becomes exaggerated, sweat is released, which has water in its composition. When in contact with the medium, the sweat evaporates on the surface of the skin, causing the body to cool.

Answer:

No, the sample needs to be insoluble or sparingly soluble at room temperature so that the maximum amount of purified crystals form at room temperature and in the ice bath.

Explanation:

For a solvent to be adequate it must completely dissolve the substance to be purified when it is hot, that is, at boiling temperature only. It should be practically insoluble when the solvent is cold or at room temperature. This must occur in this way since impurities must be removed by hot filtering or dissolved in the mother liquor.

Answer: The molecular formula for the carcinogenic form of asbestos [tex]Mg_3Si_2H_4O_9[/tex]

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Mg = 26.31 g

Mass of Si= 20.20 g

Mass of H= 1.45 g

Mass of O= (100-(26.31+ 20.20+ 1.45)) =  52.04 g

Step 1 : convert given masses into moles

Moles of Mg=[tex]\frac{\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac{26.31g}{24g/mole}=1.10moles[/tex]

Moles of Si=[tex]\frac{\text{ given mass of Si}}{\text{ molar mass of Si}}= \frac{20.20g}{28g/mole}=0.72moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.45g}{1g/mole}=1.45moles[/tex]

Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{52.04g}{16g/mole}=3.25moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = [tex]\frac{1.10}{0.72}=1.5[/tex]

For Si =[tex]\frac{0.72}{0.72}=1[/tex]

For H=[tex]\frac{1.45}{0.72}=2[/tex]

For O =[tex]\frac{3.25}{0.72}=4.5[/tex]

The ratio of  Mg : Si: H: O = 1.5 : 1 : 2 : 4.5

Converting them into whole numbers :

The ratio of  Mg : Si: H: O = 3 : 2 : 4 : 9

Hence the empirical formula is [tex]Mg_3Si_2H_4O_9[/tex]

Empirical mass =[tex]3\times 24+2\times 28+4\times 1+9\times 16=276g[/tex]

Molecular mass = 277 g

[tex]n= \frac{\text {Molecular mass}}{\text {Empirical mass}}=\frac{277}{276}=1[/tex]

Thus molecular formula =[tex]1\times Mg_3Si_2H_4O_9=Mg_3Si_2H_4O_9[/tex]

Answer:

H2CO3 = 2H+ + CO3-

Explanation:

It is simply what carbonic acid breaks down into when placed in water. Since carbonic acid is made up of H and CO3, these are the products.

Answer:

Less than 0.033 M:

[tex][Z]_{eq}=2.4x10^{-3}M[/tex]

Explanation:

Hello,

In this case, the described equilibrium is:

[tex]2A+B\rightarrow 2Z[/tex]

Thus, the law of mass action is:

[tex]K=\frac{[Z]^2}{[A]^2[B]}=0.43[/tex]

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

[tex]\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33[/tex]

Know, by introducing the change [tex]x[/tex] due to the reaction extent, we can write:

[tex]2.33=\frac{(2x)^2*x}{(0.033-2x)^2}[/tex]

Which has the following solution:

[tex]x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M[/tex]

But the correct solution is [tex]x_3=0.0152M[/tex] since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

[tex][Z]_{eq}=0.033M-2(0.0153M)[/tex]

[tex][Z]_{eq}=2.4x10^{-3}M[/tex]

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

Answer:

A .    [tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

B.   [tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

C.  The system is at steady state but not at equilibrium

Explanation:

Given that:

The volumetric flow rate of the water = 15 gallons per minute

The diameter of the pipe that leaves the pump is 1 inch.

A. The objective here is  to determine how much work flow is done by the water as it leaves the pump and enters the pipe

The work flow that is said to be done can  be expressed by the relation :

W = P × V

where;

P = pressure

V = volume

Also the given outlet pressure is the gauge pressure

The pressure in the pump P  is can now be expressed by the relation:

[tex]P_{absolute} = P_{guage} + P_{atmospheric}[/tex]

[tex]P_{absolute}[/tex] =  10 psig + 14.7 psig

[tex]P_{absolute}[/tex] =  24.7 psig

W =  P × V

W =  24.7 psig  ×  15 gal/min

[tex]W = (24.7 \ psig * \dfrac{\frac{lb_f}{in^2}}{psig}) * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})[/tex]

[tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

Thus ; the rate of flow of work is said to be done by the water at [tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

B.

Given that :

The water returns to the pool through an opening that is 1.5 inches in diameter.

where the pressure is 1 atm.

Then ; the rate of work done  by the water as it leaves the pipe and enter the pool is as follows:

W =  P × V

W = 1 atm  ×  15 gal/min

[tex]W = 1 \ atm * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})[/tex]

[tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

Thus ; the rate of flow of work done by the water leaving the pipe and enters into the pool is  at [tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

C.

We can consider the system to be at steady state due to the fact that; the data given for the flow rate and pressure doesn't reflect upon the change in time in the space between the pump and the pool.

On the other-hand the integral factor why the system is not at equilibrium is that :

the pressure leaving the pipe is different from that of the water at the surface of the pool as stated in the question.

Answer:

It is the portion of internal energy that can be transferred from one substance to another.

Thermal energy is the portion of internal energy that can be transferred from one substance to another.

Thermal energy is the energy an object posses which is as a result of particles movement within it.

It is also the internal energy system in a state of thermodynamic equilibrium which is as a result of its temperature. Thermal energy cannot be concert to useful work easily.

Therefore, thermal energy is the portion of internal energy that can be transferred from one substance to another.

Learn more about thermal energy from the link below.

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Answer:

Na₂SO₄

Explanation:

Barium nitrate, Ba(NO₃)₂ produce precipitate with SO₄²⁻, CO₃²⁻. That means the precipitate could be obtained from Na₂SO₄ and Na₂CO₃.

Also, magnesium nitrate, Mg(NO₃)₂, produce precipitate just with CO₃²⁻. As the unknown solution produce no precipitate, the unknown compound is:

Na₂SO₄

Answer:

The brain

Explanation:

With all those instructions the body recqures to respond to it must be so

Hope it helps

Answer:

a. Put a piece of fresh sliced yam with a bore into it into the soup.

Explanation:

b. Osmosis may occur

The chef can put a slice of yam in the soup with a hole in it as it will absorb excess of salt by process of diffusion.

Diffusion is defined as the process of movement of molecules which takes place under concentration gradient. It helps in movement of substances in and out from the cell.The molecules move from lower concentration region to a higher concentration region till the concentration becomes equal.

There are 2 main types of diffusion:

1) simple diffusion-process in which substances move through a semi-permeable membrane without the aid of transport proteins.

2) facilitated diffusion- It is a passive movement of molecules across cell membrane from higher concentration region to lower concentration.

There are 2 types of facilitated diffusion one is osmosis and dialysis.

Learn more about diffusion,here:

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Answer:

A- 25.9 kJ

Explanation:

ΔH of formation is defined as the amount of energy that is involved in the formation of 1 mole of substance.

ΔH of rust is -826kJ/mol, that means when 1 mole of rust is formed, there are released -826kJ.

Moles of 5.00g of Fe₂O₃ (Molar mass: 159.69g/mol) are:

5.00g ₓ (1 mole / 159.69g) = 0.0313 moles of Fe₂O₃.

If 1 mole release -826kJ, 0.0313 moles release:

0.0313 moles ₓ (-826kJ / 1 mole) = -25.9kJ

Thus, heat involved is: