Answer:
SO42 - Trigonal planar ion
Explanation:
The SO4^2- ion is tetrahedral and not trigonal planar because the sulphur atom has four regions of electron density which includes the lone pair of electrons on sulphur atom.
This accounts for the observed tetrahedral arrangement of electron pairs around the central sulphur atom in SO4^2- ion, hence the answer.
Identify the molecules or ions below as Lewis acids, Lewis bases, or neither. If there is more than one possible site in the molecule/ion, focus on the central or the charged atom. a) _________ b) _________ c) _________ Submit AnswerRetry Entire Group2 more group attempts remaining Show HintPreviousNext
Answer:
This question is incomplete because of the absence of the molecules been referred to in the question. However, the molecules been referred to in the question is in the attachment below
Explanation:
First of all, we have to define lewis acid and lewis base.
A lewis acid is a substance that has the capacity to accept a pair of electrons. For example, H⁺. While a lewis base is a substance that is capable of donating a pair of electrons (to a lewis acid). For example, OH⁻.
Going by the definitions above, we can deduce the type of substance the molecules in the question (attachment) are
a. BF₃ (boron trifluoride) is a lewis acid because the central atom (as suggested to be focused on in the question) which is boron, has the capacity to accept a pair of electrons.
b. The central atom (carbon) in the compound (2-methyl propane) also has the capacity to accept a pair of electrons since it is positively charged (is electron deficient). Hence, it is a lewis acid.
c. The functional group in this compound (trimethyl borate) is the ether. Ethers are generally lewis bases because the oxygen atom in an ether can donate a pair of electrons from it's lone pair. However, the presence of boron which is central to the compound shows it is also a lewis acid, although weak (majorly due to the presence of the ethers).
If the mass of a helicopter is 4500 kg and the net force on it is 18000 n, what is the helicopters acceleration
Answer:
The answer is
4 m/s²Explanation:
The force of an object can be found by using the formula
F = m × awhere
m is the mass
a is the acceleration
F is the force
Since we are finding the acceleration
[tex]a = \frac{F}{m} [/tex]
From the question
F = 18000 N
m = 4500 kg
Substitute the values into the above formula and solve
That's
[tex]a = \frac{18000}{4500} \\ = \frac{180}{45} [/tex]
We have the final answer as
4 m/s²Hope this helps you
Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3
Answer:
guys can u solve my ques plz
Which type of rock is a foliated metamorphic rock?
A. granite
B. marble
C. quartzite
D. slate
Answer:
D. Slate
Explanation:
Because when it come to think of it then you see that slate is arranged with many parallel layers just like a foliated metamorphic rock.
P.S I took the test and got a 100
Slate is a type of foliated metamorphic rock formed when rocks are subjected to heat,high pressure,etc.
What are metamorphic rocks?Metamorphic rocks are defined as a type of rock which is substantially changed from igneous or sedimentary rocks.They are formed when rocks are subjected to high heat, pressure,hot minerals and even combination of these factors.
Metamorphic rocks are formed by the process of metamorphism which does not melt the rocks rather they are transformed into denser and compact rocks.
New minerals are created by the rearrangement of of minerals or by the reaction of fluids withe the rocks.Metamorphic rocks are often smeared and folded.
Common metamorphic rocks are marble,gneiss,quartzite ,etc.There are two types of metamorphic rocks :foliated and non-foliated metamorphic rocks.
Learn more about metamorphic rocks,here:
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What is the IUPAC name of the following compound?
CH3-CH-C---C-CH2-CH-CH3
CH3-CH2 CH2-CH3
(a) 2,6-diethyl-3-nonyne
(b) 2,5-diethyl-3-nonyne
(c) 3,7-dimethyl-5-nonyne
(d) 3,7-dimethyl-4-nonyne
(e) 2,6-diethyl-3-heptyne
Answer:
(d) 3,7-dimethyl-4-nonyne.
Explanation:
Hello,
In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.
Best regards.
What made the discovery of cells possible? (1 point)
O the observation of cells by Hooke and Pasteur
o the invention of the microscope
o the use of magnifying glasses
o the study of viruses and bacteria
Answer:
the invention of the microscope
Explanation:
because cells are very tiny and cant be seen to the humans naked eye
i need help simplifying 4+7(x+3)
Answer:
7x+25
Explanation:
The table below shows some information about four different elements.
Element
Classification
Density (g/cm³)
barium (Ba)
metal
3.6
beryllium (Be)
metal
1.8
chromium Cr)
metal
7.2
phosphorus P)
nonmetal
1.8
A cube of an unknown element has a shiny, silvery color. The side of the cube measures 2.0 cm and the cube has a mass of 14.56 g.
Based on the information in the table, which element makes up the cube?
Answer:beryllium
Explanation:
Which of the following additions to alkenes occur(s) specifically in an syn fashion?
A) dihydroxylation using Os04, H202
B) addition of H2
C) hydroboration
D) addition of HCI
E) A, B, and C
Answer:
E) A, B, and C
Explanation:
Syn addition refers to the addition of two substituents on the same face or side of a double bond. This differed from anti addition which a occurs across opposite face of the double bond.
Hydrogenation, hydroboration and dihydroxylation all involve syn addition to the double bond, hence the answer chosen above.
Dihydroxylation using Os04, H202, Addition of H2 and Hydroboration to
alkenes occur in a syn fashion.
Syn addition refers to the addition of two substituents( compounds) on the
same side thereby increasing the number of substituents and a decrease in
the bond order.
Hydrogenation, hydroboration and dihydroxylation all undergo syn addition which is the addition of the substituent to the same side which is why it is the right choice.
Read more on https://brainly.com/question/17462452
True or False. For solidification, a substance must absorb heat
Answer:
true
Explanation:
I think it is true but im uncertain
Some enzymes have one or more sulfhydryl (thiol) groups that are important to enzymatic activity but that can react upon standing in solution to form inactive disulfide bonds.
Thiol reagents, such as 1,4-dithiothreitol (DTT), are often added to the solutions of such proteins to protect them from this reaction and to reverse it when it occurs. (The reverse reaction works best at slightly alkaline pH.) Draw the product formed when DTT reacts with a protein disulfide bond to liberate the free thiol groups. Which of the following occurs in this reaction? A. The protein disulfide is oxidized.
B. The protein disulfide is reduced.
C. DTT is reduced.
D. DTT is oxidized.
Answer:
A. Protein disulfide is oxidized.
Explanation:
When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.
Diamonds are measured in carats, where 1 carat = 0.200 g. The density of diamond is 3.51 g/cm^3. What is the volume of a 5.50 carat diamond?
Answer:
5.0 carat x (0.200g / 1 carat) x (1 cm³ / 3.51g) = 0.28 cm³... with 2 sig figs..
Explanation:
USE DIMENSIONAL ANALYSIS. That is the point of this problem. That is why Dr. Zumdahl wrote this problem and put it in his textbook (chpt 1 Problem #57 if you're using the 7th edition, chpt1 problem #63 if you're using his 8th edition).
Draw the products formed when 2−propanol [(CH3)2CHOH], the main ingredient of rubbing alcohol, is treated with H2SO4.
Answer:
Explanation:
Elimination reaction occurs when 2−propanol [(CH3)2CHOH] is treated with H2SO4, this is because the H2SO4 is a dehydrating agent. With concentrated tetraoxosulphate (VI) acid at 180°C, 2 - propanol reacts to form a conjugate acid and a conjugate base.
The reaction formation and the products can be seen in the attached image below.
typically, over 60% of the mass of a piece of bubble gum is made up of sugar. sugar is dissolved in the mouth and swallowed during chewing. if gum is chewed precisely until it loses its flavor, most if not all of the sugar content of the gum should be gone. how would this affect the mass of the gum? how will the mass of gum be affected by chewing time? how does the chewing time necessary to lose significant mass compare between different brands/types of gum? how large a role does saliva play in the processing of gum in the mouth?
Answer:
Hello your question is incomplete attached below is the complete question
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
Explanation:
we will make two assumptions in order to resolve the given problem
next we have to calculate the mean(average) mass of the Chewing gums for each time interval
Regular gum :
initial mean mass = 5.96
mean mass after 1 minute = 5.03
mean mass after 2 minutes = 4.09
next we calculate the mean mass of sugar in the regular gum using this relationship :summation of( initial masses * 60/100 )/ 4 = 3.58 comparing it the the mass of the chewing gum at different time intervals i.e 1 minute and 2 minutes
sugar free gum :
initial mean mass = 2.98
mean mass after 1 minute = 2.59
mean mass after 2 minutes = 2.32
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
How do an independent variable and a dependent variable differ in a scientific investigation?
Answer:
stop cheating and be smart
Explanation:
ugh sjdjdkxkdkdkdkdkdkdahahahajajaja
What are some examples of matter?
Answer:
An apple.
A person.
A table.
Air.
Water.
A computer.
Paper.
Iron.
Hope this helps you
Answer:
your boddy is made of mater and a clock too it is still a mater of time.
Explanation:
Which of the following isn't an example of numerical data?
A.Height
B.Weight
C.Gender
D.Temperature
Answer:
Gender
Explanation:
Use the density formula to solve the following problems. A sample of a substance has a volume of 60.5 mL and a density of 1.20 g/mL. What is the mass of the sample?Use the density formula to solve the following problems.
Answer:
72.6 g
Explanation:
Step 1: Given data
Volume of the substance (V): 60.5 mLDensity of the substance (ρ): 1.20 g/mLMass of the substance (m): ?Step 2: Calculate the mass of the substance
The density of a substance is equañ to its mass divided by its volume. The density formula is:
ρ = m/V
m = ρ × V
m = 1.20 g/mL × 60.5 mL
m = 72.6 g
11. A 100% silver ring would be an example of a
a) Pure substance
b) Mixture
c) Really nice gift
d) Compound
Answer:
a pure substance or a compound
Answer:
a pure substance
Explanation:
Any substance made from a single material is pure. Silver is an element just like all the others listed on the periodic table, so a block of silver is pure.
Calculate the mass of a piece of metal if its volume is 2.3cm^3 and density is .486g/cm^3
Answer:
1.1178 g
Explanation:
The product of volume and density is mass:
(2.3 cm^3)(0.486 g/cm^3) = 1.1178 g
_____
It would be a very unusual piece of metal that would float higher in water than most kinds of wood. The given "metal" at (0.486) has less than 3/4 the density of birch (at 0.67), which is a pretty light wood.
Bromine gas in a container is heated over a flame. What happens to the average kinetic energy of the bromine
particles?
Olt decreases rapidly.
It increases quickly.
O It remains the same.
O It decreases slowly.
Answer:
The answer is b
Explanation:
I got my answer off of quizlet
Answer:
B) It increases quickly.
Explanation:
Edg 2020
14) Describe the Cloud Model.
Determine the number of water molecules in 115g of chromium(III) oxalate trihydrate.
Answer:
[tex]4.92x10^{23}molecules H_2O[/tex]
Explanation:
Hello,
In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:
[tex]=115gCr_2(C_2O_4)_3\ 3H_2O*\frac{1molCr_2(C_2O_4)_3\ 3H_2O}{422gCr_2(C_2O_4)_3\ 3H_2O}*\frac{3molH_2O}{1molCr_2(C_2O_4)_3\ 3H_2O} *\frac{6.022x10^{23}molecules H_2O}{1molH_2O} \\\\=4.92x10^{23}molecules H_2O[/tex]
Best regards.
In a galvanic cell:______.a. reduction occurs at the (name of electrode) _____________b. the anode is the (sign) electrode anions flow in solution toward the (name of electrode)__________ ___________ electrons flow from the (name of electrode) to (name of electrode) ________ _______
Answer:
In a galvanic cell:
a. reduction occurs at the cathode.
b. the anode is the (-) electrode. Anions flow in solution toward the anode. Electrons flow from the anode to the cathode.
Explanation:
The experimental apparatus for generating electricity through the use of a spontaneous reaction is called a galvanic cell or voltaic cell.
By definition, the anode in a galvanic cell is the electrode at which oxidation occurs and the cathode is the electrode at which reduction occurs.
To complete the electrical circuit, the solutions must be connected by a conducting medium through which the cations and anions can move from one electrode compartment to the other. This requirement is satisfied by a salt bridge, which, in its simplest form, is an inverted U tube containing an inert electrolyte solution, such as KCl or NH₄NO₃, whose ions will not react with other ions in solution or with the electrodes.
During the course of the overall redox reaction, electrons flow externally from the anode through the wire to the cathode. In the solution, the cations move toward the cathode, while the anions move toward the anode.
An electric current flows from the anode to the cathode because there is a difference in electrical potential energy between the electrodes.
A common example of a galvanic cell is the Daniell cell, with Zn and Cu electrodes and ZnSO₄ and CuSO₄ solutions.
Which of the following is true concerning ψ²? A) ψ² describes the probability of finding an electron in space. B) ψ² describes the exact path of electron motion in an orbital. C) ψ² describes the electronic structure of the atom according to the Bohr model. D) ψ² describes the exact volume of an atom. E) ψ² describes the size of an atom.
Answer:
A) ψ² describes the probability of finding an electron in space.
Explanation:
The Austrian physicist Erwin Schrödinger formulated an equation that describes the behavior and energies of submicroscopic particles in general.
The Schrödinger equation incorporates both particle behavior, in terms of mass m, and wave behavior, in terms of a wave function ψ, which depends on the location in space of the system (such as an electron in an atom).
The probability of finding the electron in a certain region in space is proportional to the square of the wave function, ψ². According to wave theory, the intensity of light is proportional to the square of the amplitude of the wave, or ψ². The most likely place to find a photon is where the intensity is greatest, that is, where the value of ψ² is greatest. A similar argument associates ψ² with the likelihood of finding an electron in regions surrounding the nucleus.
A few years ago, a newspaper article reported that the Utah Industrial Depot west of Salt Lake
City had made the short list as a possible storage site for 4,408 metric tons of mercury metal.
This material is owned by the Defense National Stockpile Center. Mercury is mined primarily in Algeria, China, Kyrgyzstan, and Ukraine. At least part of this stockpiled material is from
payments to the US made by Spain as part of a WWII war debt. How many atoms of mercury
does this amount represent? (1 metric ton is 1000 kg, and 1 kg is 1000 g)
Answer:
There are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
Explanation:
Mass of mercury metal = 4,408 metric ton
1 metric ton = 1000 kg
4,408 metric ton = 4,408 × 1000 kg = 4,408,000 kg
1 kg = 1000 g
4,408,000 kg = 4,408,000 × 1000 g = 4,408,000,000 g
[tex] 4,408,000,000 g=4.408\times 10^9 g[/tex]
Mass of mercury = [tex]4.408\times 10^9 g[/tex]
Atomic mass of mercury = 200.59 g/mol
Moles of mercury = n
[tex]n=\frac{4.408\times 10^9 g}{200.59 g/mol}[/tex]
[tex]1 mole=N_A=6.022\times 10^{23}[/tex] atoms/molecules/ ions
Number of atoms of mercury in n moles = N
[tex]N=n\times N_A[/tex]
[tex]N=\frac{4.408\times 10^9 g}{200.59 g/mol}\times 6.022\times 10^{23}\\=1.323\times 10^{31} atoms[/tex]
Hence, there are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
How many nanometers are in 6.50 times 10^2 terameters?
Answer:
6.50×10² terameters is equal to 6.5 × 10²³ nm.
Explanation:
We need to find how many nanometers are in 6.50×10² terameters.
6.50×10² terameters = 650 terameters
It means we have to find how many nanometers in 650 terameters. We must know that conversion from one unit to another.
We know that,
1 terameter = 10¹² metres
and 1 metre = 10⁹ nm
So,
650 terameters = 650 × 10¹² metres
or
650 × 10¹² metres = 650 × 10¹² × 10⁹ terameters
Hence, 6.50×10² terameters is equal to 6.5 × 10²³ nm.
You should only change one variable at a time in an experiment.
True or False
Answer:True
Explanation:
Answer:
True
Explanation:
John used an empty beaker with the mass of 53.126 g. In a separate jar, he had a mixture of salt and sand. He transferred two scoops of salt and sand mixture to the beaker. The overall mass was 65.449 g. As you know salt is soluble in water, he added enough water in the beaker with salt and sand mixture to completely dissolve the salt. He filtered the mixture and dried what was left in the filter. The mass of that residue was 8.200 g. Based on the experiment calculate the mass of salt, sand and the mixture (salt sand).
Answer:
[tex]m_{mixture}=12.323g[/tex]
[tex]m_{sand}=8.200 g[/tex]
[tex]m_{salt}=4.123g[/tex]
Explanation:
Hello,
In this case, since the mass of the empty beaker is 53.126 g and with the mixture is 65.449 g, we can compute the mass of the whole mixture (water, sand and salt) via subtraction:
[tex]m_{mixture}=65.449g-53.126g=12.323g[/tex]
In such a way, since the residue obtained via filtration was sand only as it is not soluble in water, we infer that the mass of sand is 8.200 g:
[tex]m_{sand}=8.200 g[/tex]
Finally, since the mixture is composed by salt and sand, the mass of salt is:
[tex]m_{salt}=m_{mixture}-m_{sand}=12.323g-8.200g\\\\m_{salt}=4.123g[/tex]
Best regards.
Q1. Briefly explain why the Zeff experienced by a valence electron in Cl is larger than in Mg. Q2. Briefly explain why the Zeff difference described in Q1 explains why the radius of Cl is smaller than the radius of Mg. Q3. Briefly explain, in terms of the principal quantum number (n), why the radius of Ba is larger than the radius of Mg.
Answer:
See explanation
Explanation:
Q1:
Chlorine has 17 protons while magnesium has only 12 protons. Recall that the Zeff depends on the size of the nuclear charge. The greater the size of the nuclear charge, the larger the Zeff experienced by a valence electron.
Q2:
The larger the Zeff, the smaller the atomic radius. Since the valence electrons of Cl experience a greater Zeff than those of Mg due to greater size of the nuclear charge, the atomic radius of chlorine will be smaller than that of Mg.
Q3:
The radius of an atom increases as the value of the principal quantum number (n) increases down the group due to addition of more shells. The greater the number of shells added, the greater the principal quantum number (n) and the greater the atomic radius, hence the answer.
