Which of the following organisms is a decomposer?
a plant
a tiger
a mushroom
a deer

Answer:

B

Explanation:

Answer:

this equation doesn't work

Explanation:

no one listens to radio anymore

Answer:

What numbers?

Explanation:

Answer:

A) A wedge

B) The efficiency of the machine is 50%

Explanation:

The type of simple machine Scott used is the wedge

A) A wedge is a simple machine that consists of a long thick metal or wood stem that tapers to a thin (Relatively sharp) end. It is used for a splitting, tightening,  and lifting.

An example of a wedge is an axe

B) The efficiency of a machine is given approximately as the ratio of the work output to the work input as follows;

The amount of input energy the axe uses = 200 Joules

The amount of output work Scott receives from the axe  = 100 Joules

Therefore, the efficiency of the machine, η, is given as follows;

[tex]\eta = \dfrac{The \ out.put \ work \ Scott \ receives \ from \ the \ axe}{The \ amount \ of \ in.put \ energy \ the \ axe \ uses} \times 100[/tex]

[tex]\therefore \eta = = \dfrac{100 \ J}{200 \ J} \times 100 = 50\%[/tex]

The efficiency of the machine, η = 50%

Answer:

the angle of reflection also increases

Explanation:

this is because the law of reflection states that the angle of incidence equals to the angle of reflection, thus, if the angle of incidence increases, angle of reflection should also increase, basically , think as if the angle of incidence is the same thing as the angle of reflection

hope this helps, if not please report it someone else can try it

Answer:64 m/s

Explanation:❤️

Answer:

behind

Explanation:

because just because that's why lol

By Newton's second law,

• the net vertical force on the box is

∑ F = n - mg = 0

where n = magnitude of the normal force, m = mass of the box, and g = acceleration due to gravity; then

n = mg = (20 kg) (9.8 m/s²) = 196 N

• the net horizontal force on the box is

∑ F = -f = -ma

where f = mag. of kinetic friction and a = acceleration of the box. Since

f = µn

where m is the coefficient of kinetic friction, so that

f = 0.5 (196 N) = 98 N

Then the box's acceleration is

-98 N = - (20 kg) a   →   a = (98 N)/(20 kg) = 4.9 m/s²

Answer:

a

Explanation:

Stars with very big masses will become neutron stars or black holes.

Smaller stars will become white dwarfs

Answer:

1.5 km/s²

Explanation:

Given that:

a car starts from rest; it means the initial velocity (u) = 0 km/hr = 0 m/s

after time (t) = 20 seconds

the final velocity = 108 km/hr = 30 m/s

The acceleration (a) of the car can be determined by using the formula:

[tex]a = \dfrac{v-u}{t}[/tex]

[tex]a = \dfrac{30\ m/s -0 \ m/s}{20 \ s}[/tex]

[tex]a = \dfrac{30 \ m/s}{20 \ s}[/tex]

a = 1.5 km/s²

Answer:

The kinetic energy of bocce ball is more.

Explanation:

Given that,

Mass of a bowling ball, m₁ = 4 kg

Speed of the bowling ball, v₁ = 1 m/s

Mass of bocce ball, m₂ = 1 kg

Speed of bocce ball, v₂ = 4 m/s

We need to say which has more kinetic energy.

The kinetic energy of an object is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

Kinetic energy of the bowling ball,

[tex]E_1=\dfrac{1}{2}m_1v_1^2\\\\E_1=\dfrac{1}{2}\times 4\times (1)^2\\\\E_1=2\ J[/tex]

The kinetic energy of the bocce ball,

[tex]E_2=\dfrac{1}{2}m_2v_2^2\\\\E_2=\dfrac{1}{2}\times 1\times (4)^2\\\\E_2=8\ J[/tex]

So, the kinetic energy of bocce ball is more than that of bowling ball.

Answer:

7 hours.

Explanation:

This is because you are traveling 5 kilometers per hour so 5 multiplied by 7= 35.

Answer: small intestine

Explanation:

I took a test

Answer:

HI!

Here is ur answer

Magnetic PE depends on both distance and orientation in the magnetic field. ... The magnetic fields are aligned. This makes an attractive force between the two magnets. The farther apart they are, the higher their potential energy.

Explanation:

A machine with a velocity ratio of 30 moves a load of 3000N when an effort of 200N is applied.the efficiency of the machine is what?

Explanation:

Parameters

Number of oscillation = 40 oscillations

Time of oscillation = 128s

Formular

Period (T) = No of oscillation

Time taken

T = 128

40

T=3.2s

Answer:

1.Asteroids aren't all round like planets. They have jagged and irregular shapes.

2.Some asteroids are hundreds of miles in diameter, but many more are as small as pebbles.

3.Most asteroids are made of different kinds of rocks, but some have clays or metals, such as nickel and iron.

Explanation:

it is simple really  u just need to remember that astorids do not orbit a sun they crash into  things like planets  and mess them up really bad  if they   hit our sun which might happen  it will just burn up because our sun is so hot that it can burn stuff  if a astorid hits earth it wont be to bad for our earth at all it might cause some damage but we will be fine.      

Answer:

A. 9.8 m/s

Explanation:

The vertical velocity of an object increases by 9.8 m/s each second. After 1 second, the bowling ball would have a vertical velocity of 9.8 m/s.

Answer:

A body is said to have power of 1 watt if it does work at the rate of 1 joule in 1 s. Watt is the SI unit of power. Other units of power include ergs per second, horsepower, metric horsepower or cheval vapeur (CV)), and foot-pounds per minute. The unit Watt is named after the scientist James Watt.

Answer:

Wave A.

Explanation:

The energy of a wave is directly proportional to the square of the amplitude.

If a wave has higher amplitude, it will have more energy. On the other hand, a wave having lower amplitude, it will have less eenergy.

In this case, we need to tell which wave has higher energy. Hence, the correct option is A because it has a higher amplitude.

Answer:

Check attachment for your answer

Good luck

Answer:

The velocity of the second ball is 15.88 m/s East

Explanation:

The given parameters are;

The type of collision = Perfectly elastic collision

The mass of the ball moving East, m₁ = 0.400 kg

The velocity of the ball moving East, v₁ = 3.7 m/s

The mass of the ball at rest, m₂ = 0.200 kg

The initial velocity of the ball at rest, v₂ = 0 m/s

The velocity of the first ball, 'm₁', after the collision, v₃ = 4.24 m/s (The direction is assumed as being towards the West)

The velocity, 'v₄', of the second ball, 'm₂', after the collision is given by the law of conservation of linear momentum as follows;

m₁·v₁ + m₂·v₂ = m₁·v₃ + m₂·v₄

Substituting the known values gives;

0.400 kg × 3.7 m/s + 0.200 kg × 0 m/s = 0.400 kg × (-4.24 m/s) + 0.200 kg × v₄

∴ 0.200 kg × v₄ = 0.400 kg × 3.7 m/s - 0.400 kg × (-4.24 m/s)

Therefore;

0.200 kg × v₄ = 0.400 kg × 3.7 m/s + 0.400 kg × 4.24 m/s = 3.176 kg·m/s

v₄ = 3.176 kg·m/s/(0.200 kg) = 15.88 m/s

The velocity of the second ball = v₄ = 15.88 m/s East.

Answer:

F = 19.62[N]

Explanation:

By means of Newton's second law which tells us that the sum of the forces on a body is equal to the product of mass by acceleration, we can determine the force.

[tex]F=m*a[/tex]

where:

F = force [N]

m = mass = 2 [kg]

a = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]F=2*9.81\\F=19.62[N][/tex]

Complete Question:

A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s.

(a) How much work is done in 25 s?

(b) What power is being used?

(c) What force of friction is acting on the object?

Answer:

a. Workdone = 312.5 Joules.

b. Power = 12.5 Watts.

c. Force of friction = 5 Newton.

Explanation:

Given the following data;

Force = 5N

Speed = 2.5m/s

Mass = 6kg

Time = 25 secs

a. To find the work done.

We would first solve for the distance covered by the object.

Distance = speed * time

Distance = 2.5 * 25

Distance = 62.5 meters.

Workdone = force * distance

Workdone = 5 * 62.5

Workdone = 312.5 Joules.

b. To find the amount of power being used.

Power = workdone/time

Power = 312.5/25

Power = 12.5 Watts.

c. To find the force of friction is acting on the object.

Since we know that there is no net force acting on the body. Therefore, the force of friction is equal to 5 Newton.

a) Power is being used will be 12.5 Watts.

b)  Force of friction is acting on the object will be 5 Newton.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

m is the mass of object =6.0 kg

u is the speed =2.5 m/s

a) Power is being used will be 12.5 Watts.

The distance traveled by the object is;

[tex]\rm d = v \times t \\\\ \rm d = 2.5 \times 25 \\\\ \rm d = 62.5 m[/tex]

The work done is the product of force and displacement;

[tex]\rm W = F \times d \\\\ \rm W = 5 \times 62.5 \\\\ \rm W = 312.5 \ J[/tex]

The power is the ratio of work done to the  time;

[tex]\rm P= \frac{W}{t} \\\\ \rm P= \frac{312.5 }{25 } \\\\\ \rm P=12.5 \ Watt[/tex]

Hence Power is being used will be 12.5 Watts.

b) Force of friction is acting on the object will be 5 Newton.

If the all unbalanced force is zero the net force is equal to the force of friction;

The force of friction= Net force

Force of friction= 5 Newton.

Hence the force of friction is acting on the object will be 5 Newton.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663

Answer:

The original length of the iron rod is approximately 572.189 meters.

Explanation:

This is a case of linear expansion, which is defined by the following differential equation:

[tex]\alpha = \frac{1}{L}\cdot \frac{dL}{dT}[/tex] (1)

Where:

[tex]\alpha[/tex] - Linear expansion coefficient, measured in [tex]\frac{1}{^{\circ}C}[/tex].

[tex]L[/tex] - Length of the element, measured in centimeters.

[tex]\frac{dL}{dT}[/tex] - First derivative of the length of the element with respect to temperature, measured in centimeters per degree Celsius.

If we assume that thermal deformation are small regarding the length of the element, then we simplify (1) in the following form:

[tex]\alpha \approx \frac{\Delta L_{o}}{L\cdot \Delta T}[/tex]

[tex]L_{f} -L_{o} = \alpha \cdot L_{o} \cdot \Delta T[/tex]

[tex]L_{f} = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})][/tex] (2)

Where:

[tex]L_{o}[/tex], [tex]L_{f}[/tex] - Initial and final lengths of the element, measured in centimeters.

[tex]T_{o}, T_{f}[/tex] - Initial and final temperatures of the element, measured in degrees Celsius.

Given that brass has a higher coefficient of linear expansion, it is suppose that initial length is less than the initial length of the iron element. Then, we have the following system of linear equations:

Brass

[tex]L = L_{o}\cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})][/tex] (3)

Iron

[tex]L = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})][/tex] (4)

Where [tex]\alpha_{B}[/tex], [tex]\alpha_{I}[/tex] are coefficients of linear expansion of brass and iron, measured in [tex]\frac{1}{^{\circ}C}[/tex].

By equalizing (3) and (4), we have the following formula:

[tex]L_{o} \cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})] = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})][/tex]

[tex]L_{o} \cdot (\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o}) = 28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})][/tex]

[tex]L_{o} = \frac{28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]}{(\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o} )}[/tex]

If we know that [tex]\alpha_{B} = 1.9\times 10^{-5}\,\frac{1}{^{\circ}C}[/tex], [tex]\alpha_{I} = 1.2\times 10^{-5}\,\frac{1}{^{\circ}C}[/tex], [tex]T_{o} = 20\,^{\circ}C[/tex] and [tex]T_{f} = 90\,^{\circ}C[/tex], then the initial length of the iron rod is:

[tex]L_{o} = \frac{28\cdot [1+\left(1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)]}{\left(1.9\times 10^{-5}\,\frac{1}{^{\circ}C}-1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)}[/tex]

[tex]L_{o} = 57190.857\,cm[/tex]

[tex]L_{o, I} = 57218.857\,cm[/tex]

[tex]L_{o,I} = 572.189\,m[/tex]

The original length of the iron rod is approximately 572.189 meters.

The magnitude of the normal force is to be considered as the mg cos θ when the box of mass m is at rest.

In terms of physics, it refer to the maximum size where it should be extended also it defined the object direction. It is factor for vector and the scalar quantities.

When the box of mass m should be at rest so here the ramp should be an angle so here the weight should be perpendicular to the string.

hence, The magnitude of the normal force is to be considered as the mg cos θ when the box of mass m is at rest.

Learn more about magnitude here: https://brainly.com/question/14576767

Answer:

Sophie

Explanation:

Only Sophie's results supported Newton's second law. The other students' measured accelerations were significantly lower than expected. This could indicate that their experimental designs had not sufficiently eliminated drag forces.

F=ma         Rearranging when solving for acceleration gives:  a=F/m

Answer:

2.False 1.False.

Explanation:

2. I think Because it's formula is kilogram/mole

1 The si unit of mass is KG.