Which of the following statements contain a variable? Check all that apply
A. How much the car weighs.
B. Five feet tall.
C. The highest temperature over three days.
D. The length of the track.

Probability of winning race is 5/12 shows odds against horse winning for every 7 times horse is expected to lose it is expected to win 5 times.

Probability of horse win the race= 5/12

The odds against the horse winning,

First calculate the probability of the horse losing.

Since there are only two possible outcomes winning or losing.

Find the probability of losing by subtracting the probability of winning from 1,

P(losing) = 1 - P(winning)

⇒P(losing) = 1 - 5/12

⇒P(losing) = 7/12

This means that the probability of the horse losing is 7/12.

The odds against the horse winning can be expressed as a ratio of the probability of losing to the probability of winning.

odds against winning = P(losing) / P(winning)

Substituting the probabilities we calculated, we get,

odds against winning = 7/12 / 5/12

⇒odds against winning = 7/5

Therefore, as per the probability of winning the odds against the horse winning are 7 to 5.

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Answer:

f(-6) = 30

Step-by-step explanation:

f(x)=x^2+x

Let x = -6

f f(-6)=(-6)^2+(-6)

        = 36 -6

         = 30

Answer:

30

Step-by-step explanation:

Given that,

f ( x ) = x² + x

To find the value of f(-6)​, replace x with -6 and solve the expression.

Let us solve it now.

f ( - 6 ) = (-6)² + (-6)

f ( - 6 ) = 36 - 6

f ( - 6 ) = 30

The Test statistic: z = 1.77 and the P-value = 0.0381.

To test the hypothesis H0: μ1 â μ2 = 0 versus Ha: μ1 â μ2 > 0 at a significance level of 0.01, we use a two-sample z-test. We first calculate the sample mean and standard deviation for both groups. Then we calculate the pooled standard deviation and the test statistic. The test statistic is z = (x - y - 0) / SE, where SE = √(Ï1²/m + Ï2²/n). We compare the test statistic to the critical value from the standard normal distribution at a significance level of 0.01.

Since the test statistic is greater than the critical value, we reject the null hypothesis. The P-value is calculated as the probability of observing a test statistic as extreme or more extreme than the calculated test statistic under the null hypothesis. Since the P-value is less than the significance level, we reject the null hypothesis. Therefore, we conclude that the tension bond strength of the modified mortar is significantly greater than that of the unmodified mortar.

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Each payment into the sinking fund should be $4,566.71, made at the end of each period.

To find the amount of each payment to be made into a sinking fund, we can use the formula:

P = A * (r / ((1 + r)^n - 1))

Where:
P = payment amount
A = amount to be accumulated ($50,000 in this case)
r = interest rate per period (4% per period in this case)
n = number of periods (since interest is compounded semiannually, there will be 2 periods per year, so if we want to accumulate the $50,000 in, say, 5 years, then n = 5 * 2 = 10)

Substituting the values into the formula, we get:

P = 50000 * (0.04 / ((1 + 0.04)^10 - 1))
P = $4,566.71 (rounded to the nearest cent)

Therefore, each payment into the sinking fund should be $4,566.71, made at the end of each period.

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The perimeter of triangle WXY is 3b + 8a - 5.

The polynomial that represents the perimeter of polygon WXYZ is

4a + 8b - 1

We have,

Part A.

The perimeter of triangle WXY.

= (2b + a) + (3a + b - 2) + (4a - 3)

= 3b + 8a - 5

Part B.

WYZ has a perimeter of (4a + 5b - 2).

Now,

The polynomial that represents the perimeter of polygon WXYZ.

= (3b + 8a - 5) + (4a + 5b - 2) - 2(4a - 3)

= 3b + 8a - 5 + 4a + 5b - 2 - 8a + 6

= 4a + 8b - 1

Thus,

The polynomial that represents the perimeter of polygon WXYZ is

4a + 8b - 1

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Answer:

To eliminate the parameter t, we need to solve for t in terms of x and y.

From the first equation, we have: t = (x - 3) / 6

Substituting this into the second equation, we get:

y = 7√(t + 3) = 7√[(x-3)/6 + 3] = 7√[(x+15)/6]

To ensure that the expression under the square root is non-negative, we need:

x + 15 ≥ 0

x ≥ -15

Therefore, the domain of the function is all real numbers greater than or equal to -15, expressed in interval notation as:

[-15, ∞)

Step-by-step explanation:

Overall, analyzing the four factors can help determine the validity and generalizability of the results of an observational study: Confounding Variables, Sampling Method, Data Collection Methods, Study Design.

Confounding Variables: Confounding variables are extraneous variables that are related to both the dependent variable and the independent variable, which can lead to a false association between the two. When critiquing an observational study, it is important to analyze whether confounding variables were adequately controlled for. This can be done by examining whether the study design accounted for potential confounders, such as through stratification or matching, or whether statistical techniques were used to adjust for confounding.

Sampling Method: The sampling method used in an observational study can have a significant impact on the generalizability of the results. It is important to analyze whether the study used a representative sample of the population of interest, and whether any biases were present in the sampling method.

Data Collection Methods: The methods used to collect data in an observational study can also impact the validity of the results. When critiquing an observational study, it is important to analyze whether the data collection methods were standardized and reliable, and whether any biases were present in the data collection process.

Study Design: The study design used in an observational study can also affect the validity of the results. When critiquing an observational study, it is important to analyze whether the study design was appropriate for answering the research question of interest, and whether there were any limitations or potential sources of bias in the study design.

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A poll was conducted with 331 Americans who had the option to go to college but did not. The results of the poll showed that 48% of the respondents did not go to college because they could not afford it.

This means that 48% of the 331 respondents chose not to go to college because they did not have the financial means to do so. It is important to note that this result is based on the sample of respondents who were surveyed and may not be representative of the entire population of Americans who did not go to college due to financial reasons.

It is also worth noting that the cost of college can vary widely depending on the institution, location, and field of study, among other factors. Therefore, the financial barriers to college may be different for different individuals and may require different solutions.  

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Full Question: Exercise 6.16 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they cannot afford it.

Calculate a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context.

lower bound: (please round to four decimal places)

upper bound: (please round to four decimal places) Interpret the confidence interval in context:

90% of Americans choose not to go to college because they cannot afford it

We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

We can be 90% confident that our confidence interval contains the sample proportion of Americans who choose not to go to college because they cannot afford it

The position of a particle moving along a curve in the xy-plane can be described using parametric equations, where x and y are both functions of a third variable, usually time (t).


1. Parametric equations are equations that express the coordinates of a point (x, y) in the xy-plane in terms of a single variable, often time (t). In this case, x = f(t) and y = g(t), where f(t) and g(t) are functions of time.

2. To find the position of the particle at any given time, plug the value of time (t) into both functions, f(t) and g(t), to find the corresponding x and y coordinates. The position of the particle at time t is given by (x(t), y(t)).

3. To visualize the path of the particle, you can plot the curve described by the parametric equations x = f(t) and y = g(t) on the xy-plane. The particle moves along this curve as time progresses.

4. If you need to find the particle's velocity or acceleration, you can calculate the first and second derivatives of the position functions with respect to time.

In summary, the position of a particle moving along a curve in the xy-plane can be described by parametric equations, which relate the x and y coordinates to a third variable, usually time (t). The position of the particle at any given time can be found by plugging in the value of time into the parametric equations.

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One solution for the given linear equation is the poiont (1, 1)

We want to find a solution for the linear equation:

y = 2x - 1

A solution will be any pair (x, y), such that when we replace these values in the equation, it becomes true.

To find a solution we can evaluate the equation in some value of x, for example, if x = 1

y = 2*1 - 1

y = 2 - 1

y = 1

(1, 1) is a solution for the line.

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To find the probability that LeBron James makes his first free throw on the second or third attempt, we'll consider two scenarios: making the first free throw on the second attempt and making it on the third attempt.

1. Second attempt:
- He misses the first free throw (49% chance) and makes the second one (51% chance).
Probability = 0.49 * 0.51 = 0.2499

2. Third attempt:
- He misses the first two free throws (49% chance for each) and makes the third one (51% chance).
Probability = 0.49 * 0.49 * 0.51 ≈ 0.122517

Now, add the probabilities of these two scenarios to find the total probability:
Total probability = 0.2499 + 0.122517 ≈ 0.3724

So, the probability that LeBron James makes his first free throw on the second or third attempt is approximately 37.24%.

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1)  The value of x is 31°

The correct answer is an option (b)

2) The value of arc a is 68°

The correct answer is an option (c)

3) The value of angle b is 28°

The correct answer is an option (a)

4) The value of angle s is 35°

The correct answer is an option (a)

5) The measure of angle y cannot be determined.

The correct answer is an option (d)

6) The value of arc Z is 126°

The correct answer is an option (c)

We know that  any two inscribed angles in a circle with the same intercepted arcs are congruent.

Also, the Inscribed Angle Theorem states that the measure of an inscribed angle is equal to the half the measure of its intercepted arc.

1) In the first question, the inscribed angles x and angle that measures 31° have the same intercepted arc.

So, the measure of angle x is 31°

The correct answer is an option (b)

2) We need to find the measure of arc 'a'

Using Inscribed Angle Theorem, the measure of arc a would be twice the measure of angle 34°

So, the measure of arc 'a' would be a = 2 × 34

                                                         a = 68°

The correct answer is an option (c)

3) We need to find the measure of angle b.

Using Inscribed Angle Theorem, the measure of angle b would be half the arc that measures 56°

so, the measue os angle b = (1/2) × (56°)

                                          =  28°

The correct answer is an option (a)

4) The arc subtended by angle s would be equal to 180° - 110° = 70°

By Inscribed Angle Theorem, the measure of angle s would be half the measure of aubtended arc

i.e., s = (1/2) ×   70°

     s = 35°

The correct answer is an option (a)

5) We need to find the measure of angle y.

We know that the alternate segment theorem states that the angle formed between the tangent and the chord through the point of contact of the tangent in any circle is equal to the angle formed by the chord in the alternate segment.

So, the measure of angle y cannot be determined.

The correct answer is an option (d)

6) Using Inscribed Angle Theorem, the measure of arc a would be twice the measure of angle 85°

2 × 85 = m + 90

170 = m + 90

m = 80°

The measure of angle subtended by arc (90° + 64°) would be,

1/2 (90° + 64°) = 77°

The angle subtended by arc (z° + 64°) would be, 1/2(z° + 64°)

And the angle subtended by arc (z° + 80°) would be, 1/2(z° + 80°)

We know that the sum of all angles of quadrilateral is 360°

⇒ 85° + 77° + 1/2(z° + 80°) + 1/2(z° + 64°) = 360°

⇒ 1/2(z° + 80° + z° + 64°) = 360° - (85 + 77)

⇒ z° + 80° + z° + 64° = 2 × 198

⇒ 2z° + 80° + 64° = 396°

⇒ 2z° + 144° = 396°

⇒ 2z° = 252°

⇒ z = 126°

The correct answer is an option (c)

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The missing 4th question is shown below.

[tex](5m-3n) (5m-3n)[/tex] is the factor of [tex]25m^{2} - 30mn + 9n^{2}[/tex].

Factoring is the method of breaking down an expression into less difficult terms (components) that when multiplied together deliver the original expression. Variables are numbers, expressions, or algebraic quantities that when multiplied together deliver a given product. 

Factoring is an imperative tool in variable-based math and is utilized in solving equations, simplifying expressions, and finding common denominators in divisions. 

Factorize,

 [tex]25m^{2} - 30mn + 9n^{2}\\= 25m^{2} - 15mn - 15mn + 9m^{2} \\= 5m(5m-3n) - 3n (5m-3n)\\= (5m-3n) (5m-3n)[/tex]

Therefore, (5m-3n) (5m-3n) is the factor of 25m^2 -30mn+ 9n^2.

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There are 3,537,090 different eight-card hands that contain exactly two suits, with four cards from each suit.

The number of eight-card hands that contain exactly two suits with four cards from each suit can be calculated as follows:

First, we choose two suits out of four possible suits in 4C2 ways. Then, we choose four cards from each of the two chosen suits in 13C4 ways. Therefore, the total number of such hands is:

4C2 * 13C4 * 13C4 = 6 * 715 * 715 = 3,537,090

Regarding the second question, the author felt it necessary for Mrs. Candy to have a quantity greater than 30 of each type of candy to ensure that there are enough candies of each type to give to each child. Since each child is supposed to get three pieces of candy, and there are nine children, Mrs. Candy needs at least 27 pieces of candy in total. If each type of candy is available in a quantity greater than 30, then there will be enough candies of each type to give to each child without running out. However, if the quantity of any type of candy is less than 27, then Mrs. Candy may not be able to distribute the candy to all nine children fairly.

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The correlation coefficient of .78 indicates a strong positive correlation between math achievement and math attitude.

This means that as math attitude increases, so does math achievement. It also suggests that math attitude can be a good predictor of math achievement. However, it is important to note that correlation does not imply causation, and other factors may also influence math achievement.

The correlation of .78 between math achievement and math attitude indicates a strong positive relationship between the two variables. This means that as one's math attitude improves, their math achievement is likely to improve as well, and vice versa.

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Answer:

Step-by-step explanation:

Expert-Verified Answer​​ The result is a very large negative number, specifically -2,176,782,192. Therefore: 4a²−b⁶ = -2,176,782,192, when a=6 and b=36.

The group rented 12 two-person tubes and 3 one-person tubes for their float down the Ichetucknee River.

Let's denote the number of one-person tubes as x, and the number of two-person tubes as y.

From the problem statement, we know that:

x + y = 15 (Equation 1)

And the cost of renting the tubes is $277.50, so:

12.5x + 20y = 277.5 (Equation 2)

Now we can use Equation 1 to solve for x in terms of y:

x = 15 - y

Substituting this into Equation 2, we get:

12.5(15-y) + 20y = 277.5

187.5 - 12.5y + 20y = 277.5

7.5y = 90

y = 12

So the group rented 12 two-person tubes.

Using Equation 1, we can solve for x:

x + y = 15

x + 12 = 15

x = 3

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The probability of Shaq making a basketball shot is approximately 0.615 or 61.5%.

The number of likely outcomes divided by the total number of outcomes determines the likelihood that an event will occur.

In this case, the event we are interested in is Shaq making a basketball shot.

The number of favorable outcomes is the number of shots that Shaq made, which is 8.

The total number of possible outcomes is the total number of shots that Shaq took, which is 13 (since he made 8 shots and missed 5).

To find the probability of Shaq making a basketball shot, we need to know the total number of shots he took and the number of shots he made.

The total number of shots Shaq took is [tex]8 + 5 = 13[/tex]

(since he made 8 shots and missed 5).

Therefore, the probability of Shaq making a basketball shot is:

total rounds fired / total shots made

[tex]= 8 / 13[/tex]

[tex]= 0.615 or 61.5%[/tex]

So the probability of Shaq making a basketball shot is approximately 0.615 or 61.5%.

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(L2) In any triangle, the  circumcenter  will always be the same distance from each vertex of the triangle.

In Euclidean geometry, the circumcenter is defined as the point of intersection of the perpendicular bisectors of the sides of a triangle. The perpendicular bisector of a side is the line that is perpendicular to the side and passes through its midpoint. Therefore, the circumcenter is equidistant from the vertices of the triangle since it lies on the perpendicular bisectors of the sides.

This property of the circumcenter can be used to construct the circumcenter of a triangle, as well as to find its location given the vertices. It is also useful in solving problems related to the circumcircle of a triangle, such as finding the radius of the circumcircle or determining if a point lies inside or outside the circumcircle.

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Answer:

50 large boxes

Step-by-step explanation:

First, "boxes of two sizes" means we can assign variables:

  Let x = number of large boxes

       y = number of small boxes

 "There are 115 boxes in all"    means    x + y = 115      [eq1]

Now, the pounds for each kind of box is:

    (pounds per box)*(number of boxes)

So,

  pounds for large boxes     +    pounds for small boxes      =    4125 pounds

                 "the truck is carrying a total of 4125 pounds in boxes"

        (50)*(x)                   +              (25)*(y)                  = 4125    [eq2]

It is important to find two equations so we can solve for two variables.

Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2.  Let's solve for x:

   x = 115 - y          [from eq1]

    50(115-y) + 25y = 4125             [from eq2]

     5750 - 50y  + 25y = 4125           [distribute]

     5750 - 25y = 4125

      -25y = -1625

         y = 65             [divide both sides by (-25)]

 There are 65 small boxes.

Put that value into either equation (now, which is easier?) to solve for x:

  x = 115 - y

  x = 115 - 65

  x = 50

Step-by-step explanation:

The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula:

slope = (y2 - y1)/(x2 - x1)

In this case, the two points on the line k are (-4, 3) and (2, -1). Using the formula above, we can calculate the slope of k as:

slope = (-1 - 3)/(2 - (-4)) = (-4)/6 = -2/3

Therefore, the slope of line k is -2/3.

To write a ratio expressing the slope of k, we can choose any two different values of x and y that are on the line k, and write the ratio of the change in y to the change in x. Let's choose the two points (2, -1) and (-4, 3) again.

The change in y between these two points is:

-1 - 3 = -4

The change in x between these two points is:

2 - (-4) = 6

Therefore, the ratio of the change in y to the change in x is:

-4/6 = -2/3

This is the same as the slope of line k that we calculated earlier. So the ratio expressing the slope of k is -2/3.

The slope of the line that goes through the origin and the point (6, -4) is -2/3.

To find the slope of a line that goes through two given points (x₁, y₁) and (x₂, y₂), you can use the formula:

slope = (y₂ - y₁) / (x₂ - x₁)

In this case, one of the points is the origin, which has coordinates (0, 0), so x₁ = 0 and y₂ = 0. The other point is (6, -4), so x₂ = 6 and y₂ = -4. Substituting these values into the slope formula gives:

slope = (-4 - 0) / (6 - 0) = -4/6 = -2/3

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The value of the given triple integral is 486π/5.

What is volume?

A volume is simply defined as the amount of space occupied by any three-dimensional solid. These solids can be a cube, a cuboid, a cone, a cylinder, or a sphere. Different shapes have different volumes.

To evaluate the triple integral ∫∫∫B(x²+y²+z²)² dv using spherical coordinates,

we need to express the integrand and the volume element in terms of spherical coordinates and determine the limits of integration.

In spherical coordinates, the integrand is given by:

f(ρ, θ, φ) = (ρ²)² = ρ⁴

The volume element in spherical coordinates is:

dV = ρ² sin(φ) dρ dθ dφ

The limits of integration for the triple integral are:

0 ≤ ρ ≤ 3 (since B is the ball with center the origin and radius 3)

0 ≤ θ ≤ 2π (since θ ranges over the full circle)

0 ≤ φ ≤ π (since φ ranges over the upper hemisphere)

Therefore, we have:

∫∫∫B(x²+y²+z²)² dv

= ∫₀³ ∫₀²π ∫₀ᴨρ⁴ sin(φ) dφ dθ dρ (substituting in the expression for f(ρ, θ, φ) and dV)

= ∫₀³ ∫₀²π [-ρ⁴ cos(φ)] from φ=0 to φ=π dθ dρ (evaluating the integral with respect to φ)

= ∫₀³ ∫₀²π 2ρ⁴ dθ dρ (since cos(0) - cos(π) = 2)

= ∫₀³ 2πρ⁴ dρ (integrating with respect to θ)

= (2π/5) [ρ⁵] from ρ=0 to ρ=3 (integrating with respect to ρ)

= (2π/5) [3⁵ - 0⁵]

= (2π/5) (243)

= 486π/5

Therefore, the value of the given triple integral is 486π/5.

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In the RSA algorithm, the total number of coprime numbers is determined by the Euler's totient function (phi function), denoted as phi(n). For any given positive integer n, phi(n) is the number of positive integers that are less than or equal to n and are coprime to n. In other words, phi(n) is the count of all numbers between 1 and n (inclusive) that do not share any factors with n except 1.

In the context of the RSA algorithm, the total number of coprime numbers refers to the Euler's totient function, denoted as φ(n). Euler's totient function counts the number of integers from 1 to n that are coprime to n. Two numbers are considered coprime if their greatest common divisor (GCD) is 1, meaning they have no common factors other than 1.

The RSA algorithm uses this concept in the following steps:

1. Select two distinct prime numbers, p and q.
2. Compute n = p * q.
3. Calculate φ(n) = (p-1) * (q-1).
4. Choose a public key exponent e, such that 1 < e < φ(n) and GCD(e, φ(n)) = 1 (e and φ(n) are coprime).
5. Compute the private key exponent d, such that d * e ≡ 1 (mod φ(n)).
6. Use the public key (n, e) to encrypt messages and the private key (n, d) to decrypt them.

In summary, the total number of coprime numbers in the RSA algorithm is represented by Euler's totient function φ(n), which is used to choose the public and private key exponents and ensure their coprimality for secure encryption and decryption.

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The area bounded region that above the x-axis, below the curve x(t) = t² + 4t + 8, [tex] y = e^{−t}[/tex] with interval 0≤t≤1, is equals to the -6.27453.

The area between two curves is defined as the area that bounded in between two curves and can be calculated using integral calculus. We have two curves with the following equation, x(t) = t² + 4t + 8, [tex] y = e^{−t}[/tex] with interval, 0≤ t ≤1. We will determine the area of the region that lies inbetween x-axis and curves. The formula for area under the curves is written as below, [tex]A = \int_{0}^{1} x(t)y'(t) dt [/tex]

Substitute the known values in above formula, [tex]= \int_{0}^{1} ( t² + 4t + 8) ( - e^{-t}) dt [/tex].

Now, integration by letting [tex]e^{-t}[/tex]

as first function and (t² + 4t + 8) as second function, [tex]= [( t² + 4t + 8) e^{-t}]_{0}^{1} - \int_{0}^{1} (2t + 4) e^{-t} \\ [/tex]

[tex]= [( 1 + 4×1 + 8) e^{-1} - ( 8e^{0})] + [ (2t + 4) e^{-t}]_{0}^{1} - \int_{0}^{1} 2 e^{-t}] \\ [/tex]

[tex]= [13e^{-1} - 8] + [ (2×1 + 4) e^{-1} - 4]- \int_{0}^{1} 2 e^{-t}] \\ [/tex]

[tex]= 13e^{-1} - 8 + 6e^{-1} - 4 + 2 e^{-1} - 2 \\ [/tex]

[tex]= 21e^{-1} - 14 [/tex]

= - 6.27453

Hence, required value is - 6.27453.

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If point C is between points A and B, then AC + CA = AB (option b).

Let's start by defining the distance between two points. The distance between two points, let's say points A and B, is the length of the line segment that connects them. We can find the distance between two points using the distance formula:

distance = √((x₂-x₁)² + (y₂-y₁)²)

where (x₁, y₁) are the coordinates of point A and (x₂, y₂) are the coordinates of point B.

Now, let's go back to the problem. We know that point C is located between points A and B. That means the distance from point A to point C, plus the distance from point C to point B, should equal the distance from point A to point B.

In other words, AC + CB = AB

But the problem asks for the value of AC + something that equals AB. So, let's rearrange the equation:

AB = AC + CB

We can substitute CB with CA since AC and CA represent the same line segment:

AB = AC + CA

And finally, we can simplify the equation:

AB = 2AC

So, the answer to the problem is (C) CA.

The distance from point A to point C is half the distance from point A to point B.

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The statement that is true abut the slopes of perpendicular lines is that: D. One of the slopes is negative and the other is positive.

If two lines are perpendicular, it means that their slope (which is the change in y over x or rise/run along the line) will be negative reciprocal to each other.

For example, if the slope of one line is 2, the slope of any line that is perpendicular to the line must be negative reciprocal to 2, which is -1/2.

If we multiply their slopes together, we must have -1. I.e. 2 * -1/2 = -1. Therefore, if one is negative the other would be positive.

The correct answer is: D. One of the slopes is negative and the other is positive.

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Total possible arrangements are 55,450

Multiply the number of opportunities for each event by its own X times, where X equals the number of occurrences in the sequence.

A child possesses 12 blocks, six of that are black, three of which are red, two of which are white, and one of which is blue. If the child arranges the blocks in a line, we must determine the best possible arrangement.

If the child arranges the blocks in a line, the following arrangements are possible:

As a result, the arrangements could be as follows:

[tex]= > \frac{12!}{6!3!2!1!}[/tex]

=> (12 × 11 × 10 × 9 × 8 × 7 × 6! )/ 3 × 2 × 1 ×2 × 6!

=> 55,440

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Answer:

Theoretical A - 20%

Experimental - 24%

Theoretical B - <

Step-by-step explanation:

The theoretical probability of choosing a card with the number 2 is:

1 out of 5 cards have the number 2, so the probability of choosing a card with the number 2 is 1/5 or 0.2, which is equal to 20%.

The experimental probability of choosing a card with the number 2 is:

Out of the 400 people surveyed, 96 chose the card labeled 2. So the experimental probability is 96/400 or 0.24, which is equal to 24%.

The solution of the given simultaneous equations is x = 3 and y = 5.

The given equations are:

3x + 2y = 19

x + 2y = 13

To solve them using the elimination method, we need to eliminate one variable from the equations. In this case, we can eliminate y by subtracting the second equation from the first equation, as follows:

(3x + 2y) - (x + 2y) = 19 - 13

Simplifying the left-hand side, we get:

2x = 6

Dividing both sides by 2, we obtain:

x = 3

Now that we have found the value of x, we can substitute it back into one of the original equations to find the value of y. Let's substitute it into the second equation:

x + 2y = 13

3 + 2y = 13

Subtracting 3 from both sides, we get:

2y = 10

Dividing both sides by 2, we obtain:

y = 5

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