Higher wind speeds would increase the amount of electricity generated by a wind turbine.
What is a power plant?A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.
Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.
Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.
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Newton's second law of motion states that Choose one: A. the force of gravity is proportional to the masses of the two objects and the inverse of the square of the distance. B. the acceleration of an object is proportional to the net force acting on it. C. objects have inertia. D. every action has an equal and opposite reaction.
Answer:
B
Explanation:
I turn a glass upside down, trap the air in it by putting it in water, and then i take the glass down to 10 metres/33 feet. The air space would
The air space would be half the size it was at the surface.
What is airspace?It should be noted that airspace means the portion of the atmosphere controlled by a country that's above its territory.
Based on the information given, the The air space would be half the size it was at the surface.
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Explain how the scenario below illustrates a lack of understanding of the importance of quality control.
Situation: Tomas is the manager of a local restaurant.
Tomas: “The health inspection department is too strict. We have to leave some cold foods out to prepare salads for lunch.”
Answer:
He is being careless.
Explanation:
he is trying to "get rid" of one problem so he can tackle another. This is food though, and you have customers to serve. You also have to be careful about food poisoning.
when you rub neutral objects
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
b gained electrons
A ball dropped onto a trampoline returns to the same height after the rebound.
a) Describe the energy change of the ball from the point of release to the top of the rebound
b) What can you say about the energy of the ball at the point of release compared with at the top of the rebound?
a)The ball's potential energy changes as it moves from the release point to the top of the rebound.
b)The ball's potential energy is at its highest and rests when it is in the top position.
What is potential energy?The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
The potential energy is mainly dependent upon the height of the object.
Potential energy = mgh
The kinetic energy of the body is due to the virtue of motion.
According to the Law of Conservation of Energy, energy can neither be created nor destroyed but can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
A ball dropped onto a trampoline returns to the same height after the rebound.
Hence, the ball's potential energy changes as it moves from the release point to the top of the rebound. When the ball is at the top position the potential energy is maximum and the ball is at rest.
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The kinetic energy of an object is proportional to the square of its _______?
Answer:
kinetic energy of an object is proportional to the square root of its boiling vocelity
The wave equation says that a wave's speed is equal to its wavelength times its _________________.
Answer:
Frequency
Explanation:
speed = wavelength * speed
What is the peak value of a sine wave whose VAV value is 15V?
The peak value of a sine wave whose VAV value is 15V is 21. 21
What is a peak value?A peak value is simply known as the highest or maximum value reached in one cycle by an alternating quantity.
The formula for peak value is given as;
peak value = Voltage * √2
Voltage = 15V
Peak value = 15 * √ 2 = 15 * 1. 4142 = 21. 21
Thus, the peak value is 21. 21
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If you float a piece of wood in a container half-full of water that rests on a weighing scale, the weight reading on the scale will
If you float a piece of wood in a container half-full of water that rests on a weighing scale, the weight reading on the scale will increase.
What is Buoyancy?Buoyancy is the force through your fluids or total or submerged bodies. Also known as Archimedes' theorem. The fluid of the direction on the body produces a resultant force but with the direction of the weight, with the opposite direction, upwards.
All material submerged in a liquid under the action of buoyancy, for this reason we have that the value on the scale will be increased with a system of a wood floating in water.
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Which of the objects around you is following Newton's first law of motion?
The object which follows Newton's first law of motion around me is; my scientific calculator.
What is the Newton's first law of motion?The concept which describes objects as forever stationary except acted upon by external forces can be attributed to.the Newton's first law of motion. The postulation of the law is that; An object remains at rest if at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. Hence, except acted upon by an external force(myself), my calculator will remain at rest.
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The objects around us that obeys newton's first law of motion are
A book placed on the top of a table,A moving car,A standing fan,A building.Newton's first law of motionNewton's first law of motion states that every object will continue to be in its state of rest on remain in uniform motion except it is acted upon by an external force.
Newton's first law of motion is also called the law of inertia
Examples of newton's first law of motion are
A book placed on the top of a tableA moving car,etc.
Hence, The objects around us that obeys newton's first law of motion are
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the pressure in a water pipe in the ground floor of a building is 4×10⁵ Pa and three floors up is 2×10⁵. What is the difference in height between the ground floor and the third floor? Density of water=1×10³ kgm-³
The difference in height between the ground floor and the third floor is
What is gauge pressure?The pressure measured by the pressure gauge is called the gauge pressure.
Given is the the pressure in a water pipe in the ground floor of a building is 4×10⁵ Pa and three floors up is 2×10⁵ Pa. Density of water ρ = 1×10³ kg/m³
From the Bernoulli's theorem,
ΔPg = ρgΔh
( 4×10⁵ - 2×10⁵) = 1000 x 9.81 x Δh
Δh = 20.4 m
Thus, the difference in height is 20.4 m
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A football is kicked with an initial velocity of 10 m/s at an angle of 25°. If it hits the ground 1.5s later, how many meters does it travel?
Answer:
i am pretty sure its 15 m
Explanation:
10 m/s
1.5 seconds
25 angle
10m/1.5s
10x1.5=15
You push a 50.0 kg box across a floor at a constant speed of 2.0m/s. If the coefficient of friction between the two surfaces is 0.20, then how much force are you exerting on the box? If you stop pushing, then how far will the box slide before coming to rest? Start by drawing a FBD.
(a) The force applied on the box is 98 N.
(b) When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
Force exerted on the box
The force exerted on the box is calculated from Newton's second law of motion.
F - Ff = ma
where;
a is acceleration of the boxF is applied forceFf is frictional forceat constant speed, a = 0
F - Ff = 0
F = Ff
Ff = μmg
Ff = 0.2 x 50 x 9.8
Ff = 98 N
When you stop pushing, applied force = 0F - Ff = ma
-Ff = ma
a = -Ff/m
a = -98/50
a = - 1.96 m/s²
Displacement of the boxv² = u² + 2as
when the box stops, v = 0
0 = u² + 2as
0 = (2)² + 2(-1.96)s
0 = 4 - 3.92s
3.92s = 4
s = 4/3.92
s = 1.02 m
When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
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Rana writes a summary about a mass on a spring in simple harmonic motion as it moves upward from the equilibrium position toward the maximum positive displacement. as the mass moves upward, the velocity is positive and decreasing while the acceleration is negative and decreasing. what error did rana make? the velocity should be negative, not positive. the acceleration should be positive, not negative. the velocity should be increasing, not decreasing. the acceleration should be increasing, not decreasing.
Answer:
The magnitude of acceleration should be increasing.
Velocity is positive as the mass is moving towards the maximum positive displacement. Velocity would be decreasing. Acceleration is negative as velocity is decreasing. Additionally, the magnitude of acceleration would be increasing (becomes more negative.)
Explanation:
As the mass in this question moves upwards, the displacement of this mass is becoming more positive. Hence, the velocity of this mass would be positive.
In a simple harmonic motion, velocity is:
maximized at the equilibrium position (where displacement is [tex]0[/tex],) and[tex]0[/tex] when displacement is maximized.The mass in this question is moving from [tex]0[/tex] displacement (where velocity is maximized) towards maximum displacement (where velocity is [tex]0[/tex].) Thus, the velocity of the mass would be decreasing.
Since the velocity of this mass is decreasing, the acceleration of this mass would be negative. In a simple harmonic motion, acceleration is:
[tex]0[/tex] at the equilibrium position, andmaximum when displacement is maximized, but opposite to the direction of displacement.The mass in this question is moving from the equilibrium position (where acceleration is [tex]0[/tex]) towards maximum displacement (where acceleration is most negative.) Thus, the magnitude of the acceleration of this mass would be increasing, and the acceleration of the mass would become more negative.
Answer:
the acceleration should be increasing, not decreasing.
or in other words, D.
Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the appropriate banking angle so that the car stays on its path without the assistance of friction
The angle of baking from the calculation is obtained as 30°.
What is banking?The term banking refers to a means of preventing vehicles from skidding off the road at curves.
We know that the banking angle is obtained from;
θ = tan-1(v^2/rg)
v = 24.5 m/s
r = 110 m
g = 9.8 m/s^2
θ = tan-1(25^2/9.8 * 110)
θ = tan-1(625 /1078)
θ = 30°
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Circle the letters of the places where portions of Earths fresh water are located
A. In streams B. In the atmosphere
C. In the oceans D. In lakes
Choose more than one
The portions of Earth's fresh water are located in lakes and streams. The options A and D are correct.
What is freshwater?The freshwater is the one which does not contains any harmful chemical and saltiness.
The oceans contains salt water and the lakes and the streams have fresh water.
So, the option A and D are correct.
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An uncharged spherical conductor hangs by an insulating thread. You bring a negatively charged rod near
from the left side. The net charge on the hanging conductor’s left side is (choose one):
a. Positive
b. Negative
c. Neutral
Answer:
Positive
This type of charging is called charging by induction In this the uncharged body gets the opposite type of charge.when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges
so In left side all positive charges appears and in right side all negetive
Types of methods of charging
Charging by contact charging by rubbing charging by induction.A ball with a mass of 2000 g is floating on the surface of a pool of water. What is the minimum volume that the ball could have without sinking below the surface of the water? (Note that water has a density of 1.00 g/cm³.)
Answer:
[tex]2000\; {\rm cm^{3}}[/tex].
Explanation:
When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.
The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.
Let [tex]m(\text{ball})[/tex] denote the mass of this ball. Let [tex]m(\text{water})[/tex] denote the mass of water that this ball has displaced.
Let [tex]g[/tex] denote the gravitational field strength. The weight of this ball would be [tex]m(\text{ball}) \, g[/tex]. Likewise, the weight of water displaced would be [tex]m(\text{water})\, g[/tex].
For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:
[tex]\text{buoyancy} \ge m(\text{ball})\, g[/tex].
At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:
[tex]\text{buoyancy} = m(\text{water}) \, g[/tex].
Therefore:
[tex]m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g[/tex].
[tex]m(\text{water}) \ge m(\text{ball})[/tex].
In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let [tex]\rho(\text{water})[/tex] denote the density of water. The volume of water that this ball should displace would be:
[tex]\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \end{aligned}[/tex].
Given that [tex]m(\text{ball}) = 2000\; {\rm g}[/tex] while [tex]\rho = 1.00\; {\rm g\cdot cm^{-3}}[/tex]:
[tex]\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}[/tex].
In other words, for this ball to stay afloat, at least [tex]2000\; {\rm cm^{3}}[/tex] of the volume of this ball should be under water. Therefore, the volume of this ball should be at least [tex]2000\; {\rm cm^{3}}\![/tex].
PLEASE HELP ASAP!!!
Describe the two forces that form mid-ocean ridges and ocean trenches
Ridge push refers to the pressure exerted by the excess height of the mid-ocean ridge, while Slab pull refers to the force exerted by the weight of the subducted slab on the plate it is attached to.
Two forces that form mid-ocean ridgesThe two forces that form mid-ocean ridges are ridge-push and slab pull.
What is Ridge push?Ridge push refers to the pressure exerted by the excess height of the mid-ocean ridge.
What is Slab pull?Slab pull refers to the force exerted by the weight of the subducted slab on the plate it is attached to.
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A boy throws a ball vertically up it returns the ground after 10 seconds find the maximum height reached by the ball
Answer:
Approximately [tex]122.625\; {\rm m}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the ball was launched from ground level, and that the drag on the ball is negligible.)
Explanation:
Let [tex]v_{0}[/tex] denote the velocity at which the ball was thrown upward.
If the drag (air friction) on the ball is negligible, the ball would land with a velocity of exactly [tex](-v_{0})[/tex]. The velocity of the ball would be changed from [tex]v[/tex] to [tex](-v_{0})\![/tex] (such that [tex]\Delta v = (-v_{0}) - v_{0} = (-2\, v_{0})[/tex]) within [tex]t = 10\; {\rm s}[/tex].
Also because the drag on the ball is negligible, the acceleration of the ball would be [tex]a = -g = -9.81\; {\rm m\cdot s^{-2}}[/tex]. Thus:
[tex]\Delta v = a\, t = 10\; {\rm s} \times (-9.81\; {\rm m\cdot s^{-2}}) = -98.1\; {\rm m\cdot s^{-1}}[/tex].
Since [tex]\Delta v = (-2\, v_{0})[/tex]:
[tex]-2\, v_{0} = \Delta v = -98.1\; {\rm m\cdot s^{-1}[/tex].
[tex]\begin{aligned}v_{0} &= \frac{-98.1\; {\rm m\cdot s^{-1}}}{-2}= 49.05\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
The ball reaches maximum height when its velocity is [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex]. Apply the SUVAT equation [tex]x = ({v_{1}}^{2} - {v_{0}}^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] between the original position (ground level, where [tex]v_{0} = 49.05\; {\rm m\cdot s^{-1}}[/tex]) and the max-height position of the ball (where [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex].)
[tex]\begin{aligned}x &= \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (49.05\; {\rm m\cdot s^{-1}})^{2}}{2 \times (-9.81\; {\rm m\cdot s^{-2}})} \\ &\approx 122.625\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 kg, calculate its velocity.
Answer:The velocity of the object will be 5[tex]\sqrt7[/tex]m/s or 13.23m/s
Explanation:
force exerted by the object= 30N
distance displayed by the object by the action of force=6.0m
mass of object=10kg
velocity gained by the object=?
[tex]\frac{1}{2}mv^{2}= forcexdisplacement\\\frac{1}{2}10v^{2} = 30x6\\ 5v^{2}=180\\ v^{2}= 180-5\\ v^{2} =175\\v=\sqrt{175} \\v=5\sqrt{7} or 13.23[/tex]
PLEASE ANSWER THESE FAST
AND CORRECT PLEASE
you plan to use a slingshot to launch a ball that has a mass of 0.025kg
From the calculations, the force required is 0.437 N.
What is force?The term force is defined a the product of mass and acceleration. The force is required to move the sling the required distance.
If mass = 0.019 kg and acceleration = 23 m/s2 then we know that F = ma
It then follows that the required force is;
F = 0.019 kg * 23 m/s2= 0.437 N
Missing parts
You plan to use a slingshot to launch a ball that has a mass of 0.019 kg. You want the ball to accelerate straight toward your target at 23 m/s2. How much force do you need to apply to the ball?
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the mechanical advantage of a simple machine is 3 and its velocity ratio is 4 find its efficiency
Answer:
75%
Explanation:
Efficiency=MA/VR*100
=3/4*100
=0.75*100
=75%
two conducting spheres are touched together
Answer:
I think its either A or B. I’m not really sure, don’t listen to me. Read my explanation and it should help you.
Explanation:
When the two conducting spheres are brought together to touch, it is as though they become one single big conductor and the total charge of the two spheres spreads out across the whole surface of the touching spheres. When the spheres are moved apart again, each one is left with half of the total original charge…
X and Y are two identical conducting spheres separated by a distance d. X has a charge of +6µC and Y has a charge of -2µC. The electric force between them is +F (i.e. attractive). The spheres are touched together and are then returned to their original separation d. What is the new value of the force between them? Any help is greatly appreciated. I assumed that since the net charge should remain the same after, there would be no change in the value of the force, but the answer scheme gives the answer as -F/3…
you began with a 544 g sample
Answer:
34g
(second option listed)
Explanation:
half life is the number of days it takes to decrease by half,
after 8 days you are left with half of the original portion
in a period of 32 days, we experience 4 repeats of 8 days
(it gets cut in half four times):
544 / 2 = 272 {day 8}
272 / 2 = 136 {day 16}
136 / 2 = 68 {day 24}
68 / 2 = 34 {day 32}
so, after 32 days, 34g of ooblek are left un-decayed
hope this helps!! have a lovely day :)
Suppose the resistance of a copper wire is 1.05 ohms at 30°C. Find the temperature at which the resistance becomes 1.50 ohms.
Suppose the resistance of a copper wire is 1.05 ohms at 30°C. the temperature is mathematically given as
T=139.89
What is the temperature at which the resistance becomes 1.50 ohms.?Generally, the equation for the coefficient of change is mathematically given as
[tex]\mu_k= 0.2+(0.043)3\\\\\mu_k=0.2+(0.043)(4.343)[/tex]
[tex]\mu_k=0.387[/tex]
In conclusion, the Temperature of copper
[tex]R=R_0( 1+ \alpha(T-T1))[/tex]
1.5(1+0.005(T-30))
T=139.89
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8. in a hall experiment, a current of 25 a is passed through a long foil of ag, which is 0.1 mm thick and 3mm long. calculate the hall voltage produces across the width by a flux of 1.4 w/m2. if the conduction of ag is 6.8x10mho/m. estimate the mobility and hall coefficient.
The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
What is electric current?Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.
Given data;
Electric current,I= 25 A
Thickness = 0.1 mm
Length = 3 mm
Flux = 1.4 w/m²
The charge density is found as;
[tex]\rm \rho =- \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3[/tex]
The value of the hall voltage is;
[tex]\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v[/tex]
The mobility of electrons is;
[tex]\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}[/tex]
Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
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by considering action-reacton forces,identify why water rises up a thin capillary tube
The forces of attraction between water molecules and the glass walls and within the molecules of water themselves are what enable the water to rise in a thin tube immersed in water.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Surface or interfacial forces lead to capillarity. The forces of attraction between the water molecules and the glass walls and among the water molecules themselves are what causes the water in a thin tube submerged in water to rise.
Hence, the water rises up a thin capillary tube can be explained by Newton's third law.
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Sonam and Wangchuk are taking part in a long jump event during their school's annual sports day. Sonam ran a few distances before taking the jump while Wangchuk jumped without running. Who will jump furthest? Justify your answer.
Answer:
Sonam will jump further than wangchuck
