Which of the following would result if the gases that are responsible for the greenhouse effect were removed from our atmosphere?

Answer: [tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation when when aqueous solutions of chromium(III) sulfate and calcium nitrate are combined is:

[tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Answer:

12.4 * 10^-8 m or 1.24 * 10^--7 m or 124 nm

Explanation:

We have to obtain the energy of the N≡N triple bond in joules as follows;

E = 945 * 1000/6.02 * 10^23 = 9.45 * 10^5/6.02 * 10^23

E = 1.6 * 10^-18 J

But;

E = hc/λ

h = Planks constant

c = speed of light

λ = wavelength of light

λ = hc/E

λ= 6.6 * 10^-34 * 3 * 10^8/1.6 * 10^-18

λ = 12.4 * 10^-8 m or 1.24 * 10^--7 m or  124 nm

Answer:

0.020 mg

Explanation:

Let assume that the amount of the dissolved acetaminophen is (10. to 30/μgml); &

the volume of blood sample is = 2ml

We need to understand that the minimum mass of the acetaminophen that can be detected by the new system is = 10 μgml × 2

= 20 μg

= (20/1000) mg

= 0.020 mg

Answer:

6 moles of Carbon.

Explanation:

One mole of Carbon is equal to 12 grams of Carbon, so you would divide 72 by 12 and the answer would be 6.

Answer:

K

Explanation:

Ionization energy refers to the energy required to remove an electron from an atom. It usually increases across the period due to the increase in the size of the nuclear charge and decreases down the group due to increase in the number of shells.

If we look at the element, K, it has only one electron in its outermost shell. This implies that after this one electron is removed, the second ionization energy involves the removal of an electron from a filled shell.

This usually requires a lot of energy. Hence, the element having the highest difference in energy between first and second ionization energy is K.  

Mass of X₄Z₅= 378.621 g

Given

3.89 x 10²³ molecules/formula units of X₄Z₅

Required

Mass of X₄Z₅

Solution

1 mol = 6.022 x 10²³ particles(molecules, atoms, ions)

N = n x No

No = Avogadro's number

n = mol

Conversion to mol :

n = N : No

n = 3.89 x 10²³ : 6.022 x 10²³

n = 0.646

MW X₄Z₅ :

= 4 x 76.15 + 5 x 56.3

= 304.6 + 281.5

= 586.1 g/mol

Mass :

= mol x MW

= 0.646 x 586.1

= 378.621 g

Answer:

1.54 x 10⁻¹¹kg

Explanation:

The charge to mass ratio is given as:

               1.044 x 10⁻⁸kg/C

 Charge on the proton  = 1.602 x 10⁻¹⁹C

 So;

    [tex]\frac{e}{m}[/tex]   is the charge to mass ration

e is the charge

m is the mass

  1.044 x 10⁻⁸kg/C  = [tex]\frac{1.602 x 10^{-19} }{m}[/tex]    

    m = [tex]\frac{1.602 x 10^{-19} }{1.044 x 10^{-8} }[/tex]   = 1.54 x 10⁻¹¹kg

Answer:

formula of starch is (C6H10O5)n, where n is the number of glucose molecules in the chain.

Explanation:

Answer:

Mountains are formed from the collision of the earths tectonic plates and they are formed at different times because of the geologi activity below them

Explanation:

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

a very strong Abiotic factor in the world is the sun it let's off vitamin d and it can burn humans to were you get skin cancer so the sun

Answer:

[tex]^{127}_{53} I[/tex]

53 protons and electrons and 74 neutrons.

Explanation:

Hello!

In this case, since the nuclide symbol of an isotope is represented by putting the atomic mass as a prefixed superscript and the number of protons as a prefixed subscript, for I-127 we have:

[tex]^{127}_{53} I[/tex]

Now we realize this isotope have 53 electrons and protons and the following number of neutrons:

[tex]neutrons= 127-53=74[/tex]

Notice this isotope has about the same molar mass of the average iodine atom.

Best regards!

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

[tex]Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-[/tex]

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

Answer:

[tex]XeF_2[/tex]

Explanation:

Hello!

In this case, according the law of conservation of mass, we can see that, since the total mass of the Xe-F compound is 0.678 g and that of xenon is 0.526 g, we have 0.152 g as the mass of reactants equal the mass of the products. It means that we can compute the moles of each atom in the compound as shown below:

[tex]n_{Xe}=0.526g/131.3g/mol=0.004mol\\\\n_F=0.152g/19.0g/mol=0.008mol[/tex]

Now we divide the moles of both reactants by the moles of xenon as those are the fewest ones in order to find their subscripts in the empirical formula:

[tex]Xe=0.004/0.004=1\\\\F=0.008/0.004=2[/tex]

Thus, the empirical formula is:

[tex]XeF_2[/tex]

Best regards!

The case kf the compound which consist of the xenon and the fluoride was made by shining the sunlight on a mixture of Xe and F2 gas.

Learn more about the xenon and fluorine was prepared by.

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Answer:

an unbalanced force

Explanation:

Answer:

Density, Mass, Pressure

Answer:

it's answer is A

A nonspotaneous redox reaction

hope it helps you

Answer:

Enthalpy of formation of strontium chloride, SrCl = -558.1 kJ/mol

Explanation:

Sr(s) -------> Sr(g)       ΔHsublimation = +164 kJ/mol

Sr⁺(g) -------> Sr⁺(g)    First Ionization energy, IE₁ = +549 kJ/mol

Sr⁺(g) -------> Sr²⁺(g)    Second ionization energy, IE₂ = +1064 kJ/mol

I₂(s) --------> I₂(g)   ΔHsublimation = +62.4 kJ/mol

I₂(g) -------> 2I(g)   Bond dissociation energy, BE = +152.55 kJ/mol

2I(g) ----> 2I⁻(g)   Electron affinity, EA = 2 (-295.15 kJ/mol) = -590.3 kJ/mol

Sr²⁺(g) + 2I⁻(g) ------> SrI₂(s)    Lattice energy, LE = -1959.75 kJ/mol

Overall equation for the formation of SrCl₂ is given as:

Sr(s) + I₂(s) ----> SrI₂(s)    ΔHformation = ?

Enthalpy of formation, ΔHformation = (ΔHsublimation of Sr(s) + IE₁ + IE₂ + ΔHsublimation of I₂(s) + BE + EA + LE)

ΔHformation = {164 + 549 + 1064 + 62.4 + 152.55 + (-590.3) + (-1959.75)} kJ/mol

Sr(s) + I₂(s) ----> SrI₂(s)    ΔHformation = -558 kJ/mol

Therefore, enthalpy of formation of strontium chloride, SrCl = -558.1 kJ/mol

Answer:

its has to be AAAAAAAAAA

Answer:

The answer is A

Explanation:

Answer:

crystalline and amorphous.

Explanation:

Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order

Answer:

It becomes insoluble again.

Explanation:

The chemical equation showing the reaction between benzoic acid, and sodium hydroxide,NaOH is given below;

C6H5COOH + NaOH ------------------------> C6H5COO^- Na^+ + H2O.

The Benzoic acid, C6H5COOH is insoluble but when it reacted with 1M Sodium hydroxide, NaOH it changes to sodium benzoate, C6H5COO^- Na^+ which is more soluble than the benzoic acid.

C6H5COO^- Na^+ + HCl -------------------> C6H5COOH + NaCl.

When the sodium benzoate, C6H5COO^- Na^+ reacts with 6M HCl, it is converted back to benzoic acid which is insoluble. Hence, precipitation is observed.

Answer:

1.54 x 10⁻¹¹kg

Explanation:

The charge to mass ratio is given as:

               1.044 x 10⁻⁸kg/C

 Charge on the proton  = 1.602 x 10⁻¹⁹C

 So;

    [tex]\frac{e}{m}[/tex]   is the charge to mass ration

e is the charge

m is the mass

  1.044 x 10⁻⁸kg/C  = [tex]\frac{1.602 x 10^{-19} }{m}[/tex]    

    m = [tex]\frac{1.602 x 10^{-19} }{1.044 x 10^{-8} }[/tex]   = 1.54 x 10⁻¹¹kg

Answer:

the partial pressure of methane CH₄ is 239.4 torr.

Explanation:

Given;

molar mass of methane, CH₄ = 90.0 g

molar mass of argon, Ar = 10.0 g

total pressure of the gases, Pt = 250 torr

number of moles of methane CH₄;

[tex]n_{CH_4} = \frac{90}{16} = 5.625 \ moles[/tex]

number of moles of Ar;

[tex]n_{Ar} = \frac{10}{39.95} = 0.25 \ mole[/tex]

The mole fraction of methane XCH₄ is calculated as;

[tex]X_{CH_4} = \frac{n_{CH_4} }{n_{CH_4} \ + \ n_{Ar}} \\\\X_{CH_4} = \frac{5.625}{5.625 \ + \ 0.25} \\\\X_{CH_4} = 0.9575[/tex]

Apply Dalton's law of partial pressure, to determine the partial pressure of methane CH₄;

[tex]P_{CH_4} = X_{CH_4} P_t\\\\P_{CH_4} = 0.9575 \ \times \ 250 \ torr\\\\P_{CH_4} = 239.4 \ torr[/tex]

Therefore, the partial pressure of methane CH₄ is 239.4 torr.

The partial pressure of CH₄ in the mixture containing 90 g of CH₄ and 10 g of Ar having a total pressure of 250 torr is 239.25 torr

We'll begin by calculating the number of mole of CH₄ and Ar. This can be obtained as follow:

Mass of CH₄ = 90 g

Molar mass of CH₄ = 12 + (4×1) = 16 g/mol

Mole = mass / molar mass

Mole of CH₄ = 90 / 16

Mass of Ar = 10 g

Molar mass of Ar = 40 g/mol

Mole = mass / molar mass

Mole of Ar = 10 / 40

Mole of CH₄ = 5.625 mole

Mole of Ar = 0.25 mole

Total mole = 5.625 + 0.25

Total mole = 5.875 mole

Mole fraction = mole of substance / total mole

Mole fraction of CH₄ = 5.625 / 5.875

Mole fraction of CH₄ = 0.957

Total pressure = 250 torr

Partial pressure = mole fraction × total pressure

Partial pressure of CH₄ = 0.957 × 250

Therefore, the partial pressure of CH₄ in the mixture is 239.25 torr

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Answer:

I think this means that they always compatible so th er e basically friends and they stick together. c: hope I helped

Answer:

[PbNO₃] = 3.13 M

Explanation:

Molarity is a specific sort of concentration where we have, the amount of solute's moles contained in 1 L of solution.

In this case, our solution's volume is 500 mL.

We convert to L → 500mL . 1L/1000 mL = 0.5L

Moles → 1.565 mol

Molarity (mol/L) → 1.565 mol / 0.5L = 3.13 M

There also types of concentration, for example molality which indicates the moles of solute in 1kg of solvent.

Answer:

[tex]m_{O_2}=36.3gO_2[/tex]

Explanation:

Hello!

In this case, since the reaction between propane and oxygen is:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Given the 1:5 mole ratio between propane and oxygen, and their molar masses (44.09 g/mol and 32.00 g/mol respectively), we can follow up the shown below stoichiometric setup to compute the required mass of oxygen for the reaction:

[tex]m_{O_2}=10.0gC_3H_8*\frac{1molC_3H_8}{44.09gC_3H_8}*\frac{5molO_2}{1molC_3H_8} *\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=36.3gO_2[/tex]

Best regards!

Answer:

Oxygen is a pure element. Water, however, is a compound molecule containing oxygen. Water also contains hydrogen, In an H2O molecule, the two hydrogen molecules and the oxygen molecules are chemically bonded together.

Answer:

Water is 1% oxygen and it is a compound

While oxygen is a Pure element that means it forms with only oxygen molecules

Explanation:

Answer: 216km

Explanation:

An integer simply refers to a whole number. We should note that fractions and decimals are not integers. Therefore, expressing 2.015×107km as an integer will be:

= 2.015 × 107

= 215.605

= 216

Answer:

The solid particles will be trapped behind on the strainer while the liquid molecules will pass or filter through.

Explanation:

Filtration is a process of separation of mixtures involving an insoluble solid and a fluid such as liquids or gases using a filtering medium such as paper or cloth or any other material. During the process, the liquid molecules pass through the filtering medium whereas the solid particles are not allowed to pass through but are retained by the medium. The reason is that the pores on the filtering medium are only small enough for the liquid molecules to pass through but not the solid particles.

An example of a mixture that can be separated through filtration is a suspension of chalk and water. Also, a mixture of water and solid particles such as water and tea leaves can also be separated using a strainer with cloth.

In the question, if a mixture of insoluble solids in a liquid is passed through a strainer with cloth, the solid particles will be trapped behind on the strainer while the liquid molecules will pass through.

Filtration is a technique in which the solute and the solvent can be separated. This technique is based upon the size of the solute particle.

Therefore, if the mixture of insoluble solid is separated from a solvent then the solid will be retained on the cloth of the strainer while the liquid will flow through.

To learn more about the process of filtration follow the given link:

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