Which of these will have the same units if acceleration is multiplied by time? Force Time velocity Pressure

Answer:

Convection

Explanation:

because it tis the transfer of energy through a fluid or gas

When you roast a marshmallow by holding it campfire, the heat transfer in the process of radiation.

Thermal radiation is a process in which energy, in the form of electromagnetic radiation, is emitted from a heated surface in all directions and moves at the speed of light directly to its site of absorption. Thermal radiation does not move through an intermediary medium.

From the longest infrared rays through the visible light spectrum to the shortest ultraviolet rays, thermal radiation spans the entire electromagnetic spectrum. The temperature of the emitting surface controls the distribution and intensity of radiant radiation within this range.

When you roast a marshmallow by holding it campfire, the heat transfer by the process of radiation through air.

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Explanation:

Hey there!

By dividing "total distance" by "time taken".

Reason: From formula.

[tex]average \: speed = \frac{total \: distance}{time \: taken} [/tex]

Hope it helps...

Answer:

[tex]F_{10} = - \frac{k_{q1}* qo }{d_{1} ^{2} } j[/tex]

Explanation:

The net force ( F ) on particle 0 due to particle 1  can be expressed as

[tex]F_{10} = \frac{K_{q1}*qo }{r_{10} ^{3} } r_{10}[/tex]

k = coulomb constant

[tex]r_{10}[/tex] = distance between charge o and charge 1

to get the vector form ( attached below ) we substitute [tex]d_{1}[/tex] for [tex]r_{10}[/tex] and [tex]- d_{1} j[/tex] for [tex]r_{10}[/tex]

The net force on [tex]q_{0}[/tex]  by [tex]q_{1}[/tex] is , [tex]F=-K\frac{q_{0}*q_{1}}{r^{2} }j[/tex]

The force between two charges is given by Coulomb force law.

                 [tex]F=K\frac{q_{0}*q_{1}}{r^{2} }[/tex]

Where K is Coulomb constant, [tex]K=9*10^{9}Nm^{2}/C^{2}[/tex]

and r is the distance between both charges.

Here given that, [tex]q_{0}[/tex] is located as (0, 0, 0) and [tex]q_{1}[/tex] is located at [tex](0,d_{1}, 0)[/tex]

The force on [tex]q_{0}[/tex]  by [tex]q_{1}[/tex] in the negative y - axis.

So that , Direction of force is,  [tex]-j[/tex]

Hence, the net force on [tex]q_{0}[/tex]  by [tex]q_{1}[/tex] is , [tex]F=-K\frac{q_{0}*q_{1}}{r^{2} }j[/tex]

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Answer:

The cheetahs velocity component due north is 6.99 m/s

The cheetahs velocity component due west is 18.21 m/s

Explanation:

Given;

speed of the cheetah, v = 19.5 m/s

direction of the cheetah's speed, θ = 69°

Find the attached document for explanation

Answer:

substances is ur answer dear mate

comment in the comment section

Answer: A rock is a substance.

Explanation: Rock is a substance because a rock does no have genes like  you and I. And most rocks are made of sediment. That have been compressed together overtime.

Answer:

Hey :)

Explanation:

Work is a net force applied through a distance in order to displace an object, commonly abbreviated as W.  A net force is the sum of all forces acting on an object. Work is mass times acceleration and distance so to find out the work you simply calculate the acceleration of the box being brought in. Next find the distance it was carried to get in the house. Then find out the mas of the box and finally multiply those sums together to get the amount of work put in to bring the package inside.

hope this helps :) xo

Answer:

0 km

Explanation:

Since she is running in a circle, her final position is where she started which is at 0 km.

0km is her total displacement. So, the correct option is (D).

Displacement is described as a change in the position of an object which is a vector quantity and has a direction and a magnitude. It is represented as an arrow pointing from the starting position to the final position. For example- If an object moves from position A to position B, then the position of the object changes.

Displacement is defined as the shortest distance from the initial position to the final position of the object. For above given information, Angie is running in a circle, so her final position is where she started which is at 0 km.

Thus, 0km is her total displacement. So, the correct option is (D).

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Answer:

Δx=(v+v0/2)t

Explanation:

We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.

In this problem, the target unknown is the initial velocity v_0v  

0

​  

v, start subscript, 0, end subscript of the roller coaster.

Answer:

the velocity of the fish relative to the water when it hits the water is 9.537m/s and 66.52⁰ below horizontal

Explanation:

initial veetical speed V₀y=0

Horizontal speed Vx = Vx₀= 3.80m/s

Vertical drop height= 3.90m

Let Vy = vertical speed when it got to the water downward.

g= 9.81m/s² = acceleration due to gravity

From kinematics equation of motion for vertical drop

Vy²= V₀y² +2 gh

Vy²= 0 + ( 2× 9.8 × 3.90)

Vy= √76.518

Vy=8.747457

Then we can calculate the velocity of the fish relative to the water when it hits the water using Resultant speed formula below

V= √Vy² + Vx²

V=√3.80² + 8.747457²

V=9.537m/s

The angle can also be calculated as

θ=tan⁻¹(Vy/Vx)

tan⁻¹( 8.747457/3.80)

=66.52⁰

the velocity of the fish relative to the water when it hits the water is 9.537m/s and 66.52⁰ below horizontal

Answer: Refraction

Explanation:

The observation of a wet spot on a hot highway in the summer season is caused by refraction. Therefore, option (C) is correct.

Refraction can be defined as the redirection of light as it passes from one medium to another medium. The redirection of light is caused by a change in the medium or by the wave's change in speed.

Refraction of light can be described as an observed phenomenon, but other waves such as sound waves and water waves also experience refraction.

Refraction of light obeys Snell's law that the ratio of the sines of the angle of incidence and refraction must be equal to the ratio of phase velocities in the two media to the refractive index of the two media.

When the sunlight makes a blacktop hot highway. The appearance of the wet spot is bright because of the refraction of light from the sky.

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Answer:

29.5*10^3 k N/C

Explanation:

Using

E = λ/2πEor x k

So = 18*10^9 x 3.6 ✕ 10−6 / 2.2 x k

= 29.5*10^3 k N/C

Answer:

  t = √ 2y₀ / g

if they are at the same height, all the bullets must carry the target, since when advancing the height decreases

Explanation:

In this exercise we see that the bullets are fired horizontally so the time it takes to reach the ground is

          y = y₀ + [tex]v_{oy}[/tex]  t - ½ g t²

as they are fired horizontally their vertical velocity is zero and the height upon reaching the ground is zero y = 0

         0 = y₀ - ½ g t²

         t = √ 2y₀ / g

from here we can see that the time it takes for the bullets to hit the floor depends only on the initial height

Therefore, all the bullets that come out of the same height reach the ground at the same time, but at a different distance, so if one misses the target, everything must fail since reaching the target is below the initial height.

The horizontal distance traveled by the bullets is

        x = v₀ₓ t

        v₀ₓ =v₀

        x = v₀ √2y₀/g

For a more precise calculation we should know the height of the target and the bullets, but if they are at the same height, all the bullets must carry the target, since when advancing the height decreases

Answer:

[tex]2.48*10^{10}[/tex]

Explanation:

Given the expression  (3.96 x 10^2)/(1.6 x 10^-8), we are to express in scientific notation. Applying one of the laws of indices which says;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

The expression becomes;

[tex]= \dfrac{3.96}{1.6}*\dfrac{10^2}{10^{-8}}\\ \\= \dfrac{3.96}{1.6}*10^{2-(-8)}\\\\= \dfrac{3.96}{1.6}*10^{2+8}\\\\= \dfrac{3.96}{1.6}*10^{10}\\\\= 2.475*10^{10}\\\\= 2.48*10^{10} (to \ 2dp)[/tex]

Answer:

the correct answer is f    EXPERIMENT

Explanation:

In this exercise on these young people we want to know to which part of the scientific method their statement corresponds.

In order to answer, we must describe the main parts of the scientific method.

* Question. It is a question that we unleash to answer

* Hypothesis. It is an assumption that we want to check

* Independent variable. It's the thing that researcher controls

* dependent variable . It is the magnitude is measured

* Experiment. It is the design of a methodology to test the hypothesis.

In this case, the young people describe a procedure to test a hypothesis, so this part corresponds to an EXPERIMENT

the correct answer is f

Answer:

6logs

Explanation:f

First finding the volume of the logs

V= π/4d²l

= 0.098m³

So number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

So

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5 which is approx 6logs

The minimum number of logs that must be used is 6 logs.

Here first determine the volume of the logs i.e.

V= π/4d²l

= 0.098m³

Now

number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5

= 6logs

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Answer:

Only the speed is constant.

The acceleration and velocity are changing.

Explanation:

The velocity of an object refers to its speed in a specific direction. Due to the fact that the car is driving in a circle, the direction of the car is changing.  This makes the car not to have a constant velocity as this value changes each time the car makes a bend on the circular path. (which is pretty much all the time).

The acceleration is a direct derivative of the velocity of the car. As a result, if the velocity is changing, the acceleration is also changing.

Speed is a scalar quantity. This means it does not deal with the direction of the car. It only deals with how fast the car is moving. The car is on cruise control. this means that the speed of the car does not change.

Answer:

A) a_av = 5.695 m/s²

B) a_av = 7.88 m/s

C) x_f = 182.24 m

D) x_f = 13029.12 m

Explanation:

A) Initial velocity at 0 seconds; v_i = 0 m/s

Final velocity at 8 seconds;v_f = 164 km/h = 45.56 m/s

So, formula for average acceleration is;

a_av = change in velocity/change in time.

Thus, for the first 8 seconds;

a_av = (45.56 - 0)/(8 - 0)

a_av = 45.56/8

a_av = 5.695 m/s²

B) From part A, we now want to find the average acceleration from 8 seconds to 1 minute (60 seconds)

After the 60 seconds, the speed is 1640 km/h = 455.56 m/s

Thus;

Average acceleration is;

a_av = (455.56 - 45.56)/(60 - 8)

a_av = 7.88 m/s

C) Now we are told the acceleration is constant and we want to find the distance the rocket travels during the first 8 seconds.

So, distance formula we will use is;

x_f = x_i + ½(v_i + v_f)t

So at this stage, v_i = 0 m/s and v_f = 45.56 m/s and x_i = 0 m

Thus;

x_f = 0 + ½(0 + 45.56)8

x_f = 182.24 m

D) Now we want to find the distance the rocket travels during the 8 seconds to 1 minute (60 seconds) interval.

From part B, v_i = 45.56 m/s and v_f = 455.56 m/s

Also, x_i = 0 while time interval(t) = 60 - 8 = 52 s

Thus;

x_f = 0 + ½(45.56 + 455.56)52

x_f = 13029.12 m

Answer:

2.9*10^-9 J

Explanation:

Given that sound level is B= 120dB

And B=10log(Io/I)

And I = (10^12)Io

So I = 1W/m²

So to find Energy

∆E= I∆V/v

Where ∆V= 1*10-6m³

v = 343

So ∆E=2.9*10^-9 J after substituting the values

Answer:

The value is [tex]D =  15 \  km [/tex]

Explanation:

From the question we are told that

   The  speed of the marathon runner is  [tex]v = 15 \ km /hr[/tex]

   The distance from the distance from the finish is  [tex]d =  7.5 \  km[/tex]

   The  speed of the bird is  [tex]v_b  =  30 \ km / hr[/tex]

  Generally the time taken for the runner to reach the finish is mathematically represented as

       [tex]t =  \frac{d}{v}[/tex]

       [tex]t =  \frac{7.5}{15}[/tex]

        [tex]t =  \frac{1}{2}[/tex]

So the distance covered by the bird is  

      [tex]D =  v_b  *  t[/tex]

      [tex]D =  30  *  \frac{1}{2}[/tex]

         [tex]D =  15 \  km [/tex]

Answer:

-1.82m/s²

Explanation:

Given that the reaction time (t) is negligible and car brakes with constant acceleration.

Initial Velocity (u) = 20m/s

Distance(d) from Intersection when light turns red = 110m

Hence, the magnitude of braking acceleration that will bring the car to rest at exactly the intersection :

Using the motion equation:

v² = u² + 2as

Where v = final velocity at the intersection

u = initial velocity ; s = distance to intersection ; a = acceleration of the car

Exactly at the intersection ; v = 0

0 = 20² + 2×a×110

0 = 400 + 220a

-400= 220a

a = - 400 / 220

a = - 1.818

a = - 1.82 m/s²

- stands for negative acceleration (deceleration)

Answer:

 E_{z} = E_{z} (RCP) + E_{z} (LCP)

  E_{z} = 2 E₀ cos (kz-wt) i^

Explanation:

An electromagnetic wave is said to be polarized if the electric field for a fixed point in space has a definite direction in time.

Based on this definition we can define some types of polarization; Linear; right-hand, left-hand circular, and elliptical

Circular polarization is that for a fixed point in space, the electric field describes a circle in time, if this circle rotates clockwise it is called right circular polarization (RCP) and if it rotates counterclockwise it is called polarization left circular (LCP)

For wave moving in the z direction the electric fields must oscillate in the x or y direction

for right-hand circular polarization (RCP)

         [tex]E_{z}[/tex] = E₀ cos (kz -wt) i^ + E₀ sin (kz -wt) j^

for left circular polarization (LCP)

         E_{z} = E₀ cos (kz -wt) i ^ - E₀ sint (kz -wt) j ^

linear polarization can be obtained if we add these two polarizations

        E_{z} = Ez (RCP) + Ez (LCP)

        E_{z} = E₀(cos (kz -wt) i^ + sint (kz -wt) j^ +  cos (kz -wt) i^ - snt (kz -wt)j^ )

        E_{z} = 2 E₀ cos (kz-wt) i^

the latter is a linear polarization on the x axis

Answer:

The acceleration is 0.133 m/s²

The time taken to build the final speed is 219.32 s

Explanation:

Given;

final speed of the cyclist, v = 105 km/h = 29.17 m/s²

distance traveled by the cyclist, d = 3.2 km = 3,200 m

initial speed, u = 0

Apply the following kinematic equation to determine the acceleration of the cyclist;

v² = u² + 2as

(29.17 )² = 0 + (2 x 3200)a

850.89 = 6400a

a = (850.89 ) / (6400)

a = 0.133 m/s²

The time taken to build up the final speed is given by;

v = u + at

29.17 = 0 + (0.133)t

t = 29.17 / 0.133

t = 219.32 s

Answer:

generator

Explanation:

it can run an electric current to an outlet and let it charge

Answer:

Option A - 2ω²A/π

Explanation:

The displacement of simple harmonic motion is usually given as;

x = Asinωt

Where;

A is amplitude

ω is angular frequency

Now, average acceleration in half time period is given as;

a_av = d²x/dt² = -ω²A sinωt

Thus;

a_av = ∫a(t)dt/(∫dt) with both numerator and denominator between the boundaries of T/2 and 0.

Full expression gives;

(2/T)(ω²A∫sin(ωt) dt between the boundaries of T/2 and 0.

Now, integrating gives;

(2/T)(ω²A × 1/ω)[-cos(ωt)] between the boundaries of T/2 and 0.

Plugging in the boundary conditions gives us;

(2/T)(ω²A × 1/ω)[-cos(ωT/2) + cos0]

Simplifying gives;

(2ωA/T)[-cos(ωT/2) + 1]

In simple harmonic motion, we know that ω = 2π/T

​Thus we have;

(2ωA/T)[-cos(2π/2) + 1]

(2ωA/T)[-cos(π) + 1]

This gives;

(2ωA/T)[1 + 1]

= (4ωA/T)

Now, from earlier ω = 2π/T

Thus, T = 2π/ω

So, we have;

a_av = (4ωA/(2π/ω))

a_av = 2ω²A/π

Answer:B. Form a hypothesis

Answer:

C

Explanation:

Because its a region of high biological productivity with a lot of water organism allowing for high reflectivity of sonar pulse mimicking ocean bottom