Which picture correctly shows the path of refracted light rays given an object outside the focal point? Select one: a. A b. B c. C d. D

Answer:

A

Explanation:

5.2mm/s

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Answer:

Following precautions for obtaining the refractive index of a triangular glass prism:-

Explanation:

(1) All the faces of the prism should be neat and clean.

(2) Pins for holding the paper on the drawing board must be pinned perpendicular to the paper for better handling.

(3) While fixing the pins for checking the refractive index of the prism, make sure that the reflective images of the pins should be aligned to your eye to avoid any type of parallax error.

(4) Pins should not be removed or pinned again during the experiment.

(5) Avoid mishandling of the prism.

(6) Same edge of the prism should be taken as vertex for observations.

(7) For drawing the boundary of the prism, a sharp pencil should be used.

(8) Soft board and pointed pins should be used.

(9) The distance between the pins should be 5 cm or more.

(10) Make sure the glass slab or prism taken are polished and not broken.

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Answer:

My explanation and answer are down here↓:

Explanation:

p→q is false only when p is true and q is false.

∴p→(q∨r) is false when p is true and (q∨r) is false, and

q∨r false when both q,r are false.

Hence T,F,F.

The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.

The velocity of the third piece is calculated from the principle of conservation of linear momentum.

mu = m₁u₁ + m₂u₂ + m₃u₃

where;

6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y

0 = 6.84 + 3u₃y

u₃y = -6.84/3

u₃y = -2.28 m/s

ΔP = Pf - Pi = J

where;

2640(0.1) = 2(10)cos32 +  1(8)cos(28) + 3u₃x - 6(22)

264 = -108 + 3u₃x

3u₃x = 372

u₃x = 372/3

u₃x = 124 m/s

u₃ = √(124² + 2.28²)

u₃ = 124.02 m/s

tanθ = u₃y/u₃x

tanθ = 2.28/124

tanθ = 0.018

θ = 1.05⁰ (below the horizontal)

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Wave 3 will have the highest frequency. Option c is correct.

What is the frequency?

Frequency is defined as the number of repititions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

[tex]\rm v = \lambda \times f[/tex]

If the wavelength of the wave is content the velocity of the wave is directly propotional to the frequency.

The velocity of wave 3 is maximum. So that the wave 3 will have the highest frequency.

Hence option c is correct.

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(a) Let [tex]v[/tex] be the maximum linear speed with which the ball can move in a circle without breaking the cord. Its centripetal/radial acceleration has magnitude

[tex]a_{\rm rad} = \dfrac{v^2}R[/tex]

where [tex]R[/tex] is the radius of the circle.

The tension in the cord is what makes the ball move in its plane. By Newton's second law, the maximum net force on it is

[tex]F = (1.500\,\mathrm{kg}) a_{\rm rad}[/tex]

so that

[tex](1.500\,\mathrm{kg}) \dfrac{v^2}{1.50\,\rm m} = 64.0\,\mathrm N[/tex]

Solve for [tex]v[/tex] :

[tex]v^2 = \dfrac{(64.0\,\mathrm N)(1.50\,\mathrm m)}{1.500\,\rm kg} \\\\ \implies \boxed{v = 8.00 \dfrac{\rm m}{\rm s}}[/tex]

(b) The net force equation in part (a) leads us to the relation

[tex]F = \dfrac{mv^2}R \implies v = \sqrt{\dfrac{FR}m}[/tex]

so that [tex]v[/tex] is directly proportional to the square root of [tex]R[/tex]. As the radius [tex]R[/tex] increases, the maximum linear speed [tex]v[/tex] will also increase, so the cord is less likely to break if we keep up the same speed.

Answer:

Kinetic energy is referred to the energy associated with movement and or motion, thus the only object that is moving would be A boat sailing across the ocean.

Explanation:

Magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.

When the Earth's magnetic field reverses, a new stripe starts to form. Such magnetic patterns enable the scientist to recognize the occurrence of sea-floor spreading and provides strongest evidence for the theory of plate tectonics.

So we can conclude that magnetic stripes provide evidence of seafloor spreading due to their occurrence in the region of sea floor.

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Answer:

a magnetic force

Explanation:

(a.1) The component of displacement along the East is  7.36 km.

(a.2) The component of displacement along the North is  4.25 km.

(b)  When the East and North legs are reversed in order, you will still travel 8.5 km.

dx = d cosθ

dx = 8.5 km x cos(30)

dx = 7.36 km

dy = d sinθ

dy = 8.5 km x sin(30)

dy = 4.25 km

dx = 4.25 km

dy = 7.36 km

Resultant displacement;

R = √(dx² + dy²)

R = √(4.25² + 7.36²)

R = 8.5 km

Thus, when the East and North legs are reversed in order, you will still travel 8.5 km.

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Answer:

D

Explanation:

GPE = mgh

GPE / gh = m

m = GPE/gh

m = 915 / 6.5 x 9.8

m = 915 / 63.7

m = 14.4kg

Answer:

108 is the correct answer

The gravity force between Jupiter and Io will be 6.343 × 10²² N.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data;

Mass of Jupiter,[tex]\rm m_j = 1.9 \times 10^{27} \ kg[/tex]

Mass of moon of Jupiter,[tex]\rm m_{i_0}= 8.9 \times 10^{22} \ kg[/tex]]

The gravitational constant is,[tex]\rm G = 6.67 \times 10^{-11 } \ m^3 kg^{-1} s^{-2}[/tex]

Distance between Jupiter and Io, R = 421,700 km = 4,217,00,000 m

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

The gravitational force is found as;

[tex]\rm F = G \frac{ m_J m_{I_0}}{R^2} \\\\\ F = (6.67\times 10^{-11}) \frac{( (1.9\times 10^{27})\times (8.9\times 10^{22} )} { (421700000)^2}\\\\ F_g = 6.343 \times 10^{22} \ N[/tex]

Hence, the gravity force between Jupiter and Io will be 6.343 × 10²² N.

The complete question is

"Jupiter has a mass of 1.9 × 1027 kg, and its moon Io has a mass of 8.9 × 1022 kg. Their centers are separated by a distance of 421,700 km what is the force of gravity acting on Io? "

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Explanation:

an object's gravitational potential energy Eg is m×g×h where:

m=mass

g=9.8m/s²

h=height relative to the closest object below it (because it cannot potentially fall through it

so Eg = 15×9.8×5=735J

[tex] \color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}[/tex]

[tex] \: \: [/tex]

Given :

[tex] \: \: [/tex]

[tex] \: \: [/tex]

We, have to find frequency :

[tex] \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

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Answer:

Let distance between two cities is x km . So total distance travelled bus x+x=2x km and time taken was=(x/40)+(x/60)=(3x+2x)/120=5x/120=x/24 hrs . So avg speed is 2x/(x/24)=48 km per hr.

or

dt1=60km1h

dt2=30km1h

2dt1+t2=r¯

d=60t1

d=30t2

60t1=30t2

2t1=t2

2dt1+(2t1)=r¯

2(60t1)t1+2t1=r¯

2(60t1)=r¯(t1+2t1)

120=r¯+2r¯

r¯=1203

r¯=40km/h

Answer:

672 000 J      or 672 kJ

Explanation:

change in the thermal energy = mass x specific heat capacity x temperature change

     =   2 kg * 4200J/kg-C *80 C =672000 J

The height of the object will be -5.19 cm

A concave mirror's reflecting surface curves inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall

So let,

v =  Image distance from the mirror = -33.5 cm

u = object distance from the mirror (concave) = 24 cm

hi = Image height = 7.25 cm

h = height of the object = ?

Using below formula to find height of the object

-v/u = hi/h

Putting all value in the formula we get

-(-33.5)/(-24) = 7.25/h

h = -5.19 cm

Therefore the height of the object will be -5.19 cm

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Answer:

D

Explanation:

F = G m1 m2 / r^2       now double  r

 F =  G m1m1/ (2r)^2

    F =  1/4  G m1m2/r^2     <===== this is 1/4 of the original

Q in = Q out

mcΔt in = mcΔt out (c = equal)

mΔt in = mΔt out

200 x  (75-25) = M x (25-5)

M = 500 g

∆T for hot water

∆T for cold water

Both are equal according law of conservation of energy

[tex]\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta [/tex]

[tex]\\ \rm\Rrightarrow 200(50)=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow 10000=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow m_2=500g=0.5kg[/tex]

Hello!

Begin by plugging in the values for m and n. We get the equation for the velocity of the particle to be:
[tex]v(t) = 10 + 2t^2[/tex]

A.

To find the change in velocity over the interval (2s ≤ t ≤ 5s), we can simply find the difference in the velocities at these times.

[tex]\Delta v= v_f - v_i[/tex]

For this situation:
[tex]\Delta v = v(5) - v(2)[/tex]

Substitute these times for 't' into the equation and solve.

[tex]v(5) = 10 + 2(5^2) = 60 \frac{cm}{s}\\\\v(2) = 10 + 2(2^2) = 18 \frac{cm}{s}\\\\\Delta v = 60 - 18 = \boxed{42 \frac{cm}{s}}[/tex]

B.

To find the average acceleration, we must take the SLOPE of the velocity function over this interval using the slope formula:

[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]

Plug in the values for the particle's velocity at t = 2 s and 5 s that we solved for above.

[tex]a_{avg} = \frac{60- 18}{5 - 2}\\\\a_{avg} = \frac{42}{3} = \boxed{ 14 \frac{cm}{s^2}}[/tex]

C.

The instantaneous acceleration can be found by taking the derivative of the v(t) function using the power rule. Recall:
[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]

Using this rule:
[tex]a(t) = v'(t) = 2(2t) = 4t[/tex]

Substituting in t = 2 s:
[tex]a(2) = 4(2) = \boxed{8 \frac{cm}{s^2}}[/tex]

At a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.

Temperature is the measure of degree of hotness or coldness of a body. It is also the measure of average kinetic energy of a body.

As temperature increases, the average kinetic energy of a body increases.

K.E = ¹/₂mv²

v² = 2K.E/m

v = √( 2K.E/m)

where;

From the equation above, at a constant temperature, the speed of a gas molecule will decrease with increase in the mass of the molecules and vice versa.

Thus, at a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.

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Answer:

a

Explanation:

Answer:

-0.10472[tex]\frac{rad}{s}[/tex]

Explanation:

Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.

The formula for period is:

[tex]T = \dfrac{2\pi}{\omega}[/tex]

Solve for [tex]\omega\\[/tex] and you get:

[tex]\omega=\dfrac{2\pi}{T}[/tex]

The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).

The specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

The amount of heat required to increase a substance's temperature by one degree Celsius is known as its "specific heat capacity."

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

Given data;

Mass of liquid sample of Alcohol  m₁ = 200-gram

The temperature of alcohol, T₁ =  -6°C.

Mass of liquid sample of water  m₂ = 400-gram

The temperature of the water, T₂=  20°C.

The specific heat capacity of the alcohol, S₁=?

The specific heat capacity of water is, S₂=4.19 kJ/kg.°C

As we know that;

[tex]\rm Q_{gain}= Q{loss} \\\\ Q_{alcohol} =Q_{water} \\\\\ m_1s_1\triangle T_1 = m_2S_2 \triangle S_2 \\\\ 200 \times 10^{-3} \times S_1 [ (12-(-6) ] = 40 \times 10^{-3} \times 4.19 \times 10^{-3} \times (20-12)\\\\S_1 = 2 \times 4.19 \times 10^3 \times \frac {8}{18} \\\\ S_1 = 3.72 \ kJ /kg ^0 C[/tex]

Hence the specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

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They use less wire, A

The speed of sound waves in air at room temperature T=20° is 344.035 m/s.

The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is  17.20 m to  0.0172 m.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = c/f

where c is the speed of sound wave.

Given the room temperature T = 20 +273 = 293K

The velocity of sound wave is given by

v = √(γRT/m)

​where γ =1.4 , m = 28.8×10⁻³ kg/mol  R = 8.31 J/K.mol

Substituting the values, we get

v = 344.035 m/s

Thus, the speed of sound wave is 344.035 m/s

​

The human ear can hear frequencies in the range of 20 – 20,000Hz.

The wavelength corresponding to 20Hz is

λ = c/f

λ =  344.035 /20

λ  = 17.20 m

The wavelength corresponding to 20,000Hz is

λ =  344.035 /20000

λ  = 0.0172 m

Thus, the range of wavelength is 17.20 m to  0.0172 m sensitive to human ear.

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The force the rod exerts on the ball at the given angle is determined as 3.94 N.

The force exerted is calculated as follows;

F = ma

F = mv²/r

F = mω²r

where;

r = 2cosθ

ωf² = ωi² + 2αθ

where;

ωf² = (1)² + 2(2)(15 x π/180)

ωf² = 2.04

ωf = √2.04

ωf = 1.428 rad/s

F = mω²(2cosθ)

F = (1)(1.428)²(2 x cos15)

F = 3.94 N

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Stimulating plant growth is not a use of nuclear chemistry in industry. Thus, the correct option is D.

Nuclear chemistry may be defined as the sub-branch of chemistry that involves the investigation of physical and chemical characteristics of elements that are affected by transformations in the configuration of the atomic nucleus.

Thickness gauges measure the thickness, density, and fill levels and are utilized in manufacturing to make sure that an entire product or a set of products are of identical thickness.

Tracers are utilized in tracing the actual composition of radioactive decay through the chemical compounds. While the leak detectors monitor the actual and constant flow of water through a given system precisely.

Therefore, the correct option for this question is D.

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Answer:

it is d

Explanation: