Which point is on the graph of f(x) = 3.4x

Triangles FGH and ABC are congruent because of the: AAS congruence theorem.

The AAS congruence theorem states that when two angles and one non-included side in one triangle are congruent to corresponding two angles and one non-included side in another triangle, then both triangles are congruent.

In the proof given, it is established that both triangles have two corresponding congruent angles, and also, BC ≅ GH which are non-included sides.

Therefore, both triangles are congruent because of the AAS congruence theorem.

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Answer:

330.6

Step-by-step explanation:

You have to enter 290 for x.

T(290) = 290 + 0.14(290)

T(290) = 290 + 40.6

T(290) = 330.6

Answer:

Graph C

Step-by-step explanation:

Rearrange the terms so the equation is in slope-intercept form:
4x + y = 7
y = -4x + 7
The slope is -4, and the only graph that has a slope of -4 is graph C.

This is a geometric progression

So

The general formUla is

[tex]\\ \rm\Rrightarrow a(n)=ar^{n-1}[/tex]

[tex]\\ \rm\Rrightarrow a(n)=\dfrac{1}{4}\left(\dfrac{1}{4}\right)^{n-1}[/tex]

Answer:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Step-by-step explanation:

Series: the sum of the elements of a sequence.

Therefore, as the numbers have been defined as a series and we need to find [tex]S_n[/tex]:

[tex]\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{64}+\dfrac{1}{256}+...[/tex]

First determine if the sequence is arithmetic or geometric.

If it is an arithmetic sequence, there will be a common difference between consecutive terms.

if it is a geometric sequence, there will be a common ratio between consecutive terms.

From inspection of the terms, we can see that there is a common ratio of 1/4, as each term is the previous term multiplied by 1/4, so it is a geometric series.

Sum of the first n terms of a geometric series:

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Given:

[tex]a=\dfrac{1}{4}[/tex]

[tex]r=\dfrac{1}{4}[/tex]

Substitute the values of a and r into the formula:

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{1-\frac{1}{4}}[/tex]

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{\frac{3}{4}}[/tex]

[tex]\implies S_n=\dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Therefore:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Answer:

c

Step-by-step explanation:

Answer:

3.2

The value of C when B is 5 is 3.2

Step-by-step explanation:

The activity series is an arrangement of species in order of reactivity.

The activity series is an arrangement of species in order of reactivity. The position of a specie in the series determines the possibility of certain reactions.

The following are the fates of these reactions;

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Step-by-step explanation:

4.500 mm³ → cm³

1 cm³ = 1.000 mm³

= 4.500 ÷ 1.000

= 4,5 cm³ IS THE ANSWER

Answer:

[tex]\boxed{\bf B. \: c = 4 \sqrt{3} }[/tex]

Step-by-step explanation:

Since a = 6, then, b = 3.47 ( opposite of 30°).

By applying the pythagoras theorem..

Answer:

4√3 or B

Step-by-step explanation:

Answer:

the LCM of 18 25 40 80 81 and 72 is 226800

i hope this helps you

Step-by-step explanation:

by which method

prime factorization , division or defination method

Answer:

A = 50x^2+3

B = 75

C = 55

Step-by-step explanation:

[tex]f(x)=2x^2+3\\g(x)=5x[/tex]

A. f(g(x))

[tex]2(5x)^2+3\\2(25x^2)+3\\=50x^2+3[/tex]

B. g(g(3))

[tex]5(5(3))\\5(15)\\=75[/tex]

C. g(f(-2))

[tex]g(2(-2)^2+3)\\g(8+3)\\g(11)\\5(11)\\=55[/tex]

Answer:

9

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The answer is figure A, B, C, D.

Step-by-step explanation:

Because, polygon means a shape with more then 1 side, and in your pic all of the figures have more than one side, so that's the answer.

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

[tex]\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)[/tex]

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

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Answer:

a) The mass of a box of bolts is greater.

b) 3/20 kg

Step-by-step explanation:

a) Firstly, you have to make the denominators of the two fractions the same (by finding the LCM of the denominators).

The LCM of 4 and 5 is 20.

Converting 3/4 into denominator 20:

[tex]\frac{3 * 5}{4 * 5}[/tex]

= 15/20

Converting 3/5 into denominator 20:

[tex]\frac{3 * 4}{5 * 4}[/tex]

= 12/20

Now comparing the numerators:

15 > 12

Hence,

3/4 > 3/5

b) Difference of the boxes can be done by subtracting the numbers with the same denominator:

15/20 - 12/20

= 3/20 kg

Hope this helps and feel free to give me brainliest! :)

Answer:

34.3 square unit.

Step-by-step explanation:

[tex]calculate \: df \: using \: pythagoras \\ theorem \\ df {}^{2} = 8 {}^{2} + 6 {}^{2} \\ df {}^{2} = 64 + 36 \\ df {}^{2} = 100 \\ df = \sqrt{100} \\ df = 10 \\ calculating \: for \: the \: area \: of \: \\ angle \: \: dfg \\ using \: heros \: formular \\ \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2} \\ s = \frac{10 + 11 + 7}{2} = \frac{28}{2} = 14 \\ area = \sqrt{14(14 - 10)(14 - 11)14(14 - 7)} \\ area = \sqrt{14(4)(3)(7)} = \sqrt{14 \times 84} \\ area = \sqrt{1176} = 34.2928564 \\ to \: the \: nearest \: tenth \: = 34.3[/tex]

Here it is stated that, side DE = 8 units, side EF = 6 units, side FG = 7 units and side GD = 11 units. We have to find area of ∆DFG, here we will use heron's formula which is given by:

Area of ∆ = √[s(s – a) (s – b) (s – c)]

Here a, b, and c are sides of ∆. We have;

So firstly lets calculate a i.e DF by using Pythagoras theorem on ∆DEF:

➸ DF² = 8² + 6²

➸ DF² = (8 × 8) + (6 × 6)

➸ DF² = 64 + 36

➸ DF² = 100

➸ DF = √(100)

➸ DF = √(10 × 10)

➸ DF = 10 units

Now, lets calculate s i.e semi - perimeter:

Now, using heron's formula on ∆DFG to calculate its area:

➸ Area(∆DFG) = √[14(14 – 10) (14 – 7) (14 – 11)]

➸ Area(∆DFG) = √[14(4) (7) (3)

➸ Area(∆DFG) = √(14 × 4 × 7 × 3)

We can write it as;

➸ Area(∆DFG) = √(2 × 2 × 2 × 7 × 7 × 3)

➸ Area(∆DFG) = 2 × 7√(2 × 3)

➸ Area(∆DFG) = 14√(6)

➸ Area(∆DFG) = 14 × 2.449

➸ Area(∆DFG) = 34.28

➸ Area(∆DFG) = 34.3 square units (approx)

Answer:

A. (6x + 7)(6x - 7)

Step-by-step explanation:

use difference of squares, which says a^2 - b^2 =(a+b)(a-b)

take the square roots of the two numbers, 6x and 7, and use them as a and b

By looking at the graph of the piecewise function, we can see that:

On the graph, we have a piecewise function, which we want to evaluate in some different values.

First we have x  = -0.0001

This value belongs to the interval (-5, 0), and by looking at the graph, you can see that the function on that interval is equal to -9, then:

G(-0.0001) = -9

x = 0

x = 0 belongs to the interval [0, 9). On that interval the function values -1. (x = 0 belongs to that interval because we have a closed dot). Then we conclude

G(0) = -1

x = 0.0001

This value also belongs to the interval  [0, 9)

Then G(0.0001) = -1

Finally, x = 9.

If you look at the domain of the function, you can see that there is an open dot at x = 9.

This means that x = 9 does not belong to that domain, so:

G(9) is not defined.

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Answer:

15 ($20 dollar bills) and 19 ($10 dollar bills) ! Pretty sure this is correct, if wrong let me know and i'll make a question for you to give your points back, i dont know if i can do that but i can try!! Have a good day.

Answer:

-69

Step-by-step explanation:

inches:-69

-5 9/12 (-5 3/4 clearer) feet

Explanation in detail:

Write the equation down and distribute it.

3x - 1 = 2(x + 34)

3x - 1 = 2x + 68

Remove the variable on one side first (it makes solving the equation less complicated.)

3x - 1 = 2x + 68

-3x -3x

-1 = -x + 68

On all sides, subtract 68.

-1 = -x + 68

-68 -68

-69 = x

I'm guessing the answer in feet and inches is...

inches:-69

-5 9/12 (-5 3/4 simplified) feet

Answer:

1 (2/3) or 1.66666667

Step-by-step explanation:

The slope of a line is found by using the equation :

y2 - y 1 / x2 - x1

So all we have to do is plug in our values given.

To find which belongs with which variable (such as x2 or y1), we do the following:

We know that the coordinates of a point are represented by (x, y). So we must assign a number to each points number.

(2, 8) will be x1 and y1.

(5, 13) will be x2 and y2

Plug in the values :

13 - 8 = 5

5 - 2 = 3

5 / 3 = 1 (2/3)

So, the slope of the line is 1.66666667 or 1 and (2/3)s

Answer:

[tex]\boxed {a, b, c, d}[/tex]

Step-by-step explanation:

Rhombuses, parallelograms, rectangles, and squares cannot be classified as trapezoids as they have 2 pairs of parallel sides each. But quadrilaterals can be classified as trapezoids if they have a pair of parallel sides and a pair of non-parallel sides.

a) rhombuses

b) parallelograms

c) rectangles

d) squares

The numerical length of GH is 20.

Given, FH=4x+8, FG=x and GH=5x.

We need to determine the numerical length of GH.

In geometry, a line segment is a part of a line that is bounded by two distinct end points and contains every point on the line that is between its endpoints.

Given Point G is on the line segment FH, then FG + GH = FH.

Now, substitute the given values into the formula as shown:

x + 5x = 4x + 8

6x = 4x + 8

6x - 4x = 8

2x = 8

x=4

To get the length of GH substitute x=4 for 5x

That is, GH = 5(4)= 20

Hence, the numerical length of GH is 20.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = -3 [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex]\qquad \tt \rightarrow \: f(4) = 1 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

F(x) represents the value of y on curve for given value of x

[tex] \textsf{\large First -} [/tex]

[tex]\qquad \tt \rightarrow \: f(0) =( 0) {}^{2} - 3[/tex]

[ since 0 < 2 ]

[tex]\qquad \tt \rightarrow \: f(0) = 0 {}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = - 3[/tex]

[tex] \textsf{\large Second} [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = (2) {}^{2} - 3[/tex]

[ since 2 = 2 ]

[tex]\qquad \tt \rightarrow \: f(2) = 4{}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex] \textsf{\large Third -} [/tex]

[tex]\qquad \tt \rightarrow \: f(4) = - 4 + 5[/tex]

[ since 4 > 2 ]

[tex]\qquad \tt \rightarrow \: f(4) = 1[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The complete question is

"What is the component form of the vector represented by 2a when a =⟨−2,3⟩?"

The Component form of the vector represented by 2a is (-4,6)

The component form of a vector is represented by (x, y) that has gone x units left to the origin and y units up from the origin.

Given, a=(-2,3)

By using scalar multiplication,

2a = (2(-2), 2(3))

2a = (-4,6).

Therefore the component form of 2a=(-4,6)

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Answer:

7,853.982

Step-by-step explanation:

Edg 2022

Answer:

(x+y)

Step-by-step explanation:

[tex] {x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]

Thus, the HCF is (x+y).

Answer:

(x + y)

Step-by-step explanation:

Factorizing both terms :

The HCF of the terms is (x + y).