The equation of the line is y = 2x - 8.
The equation of a line in slope-intercept form (y = mx + b) is determined by the slope (m) and the y-intercept (b).
Given that the point (3, -2) lies on the line and the slope is 2, we can substitute these values into the slope-intercept form to find the y-intercept.
Using the point-slope formula:
y - y1 = m(x - x1)
Substituting (3, -2) and m = 2:
y - (-2) = 2(x - 3)
Simplifying:
y + 2 = 2x - 6
Rearranging to slope-intercept form:
y = 2x - 8
The equation of the line containing the point (3, -2) with a slope of 2 in slope-intercept form is y = 2x - 8.
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A pet store has 10 puppies, including 3 poodles, 4 terriers, and 3 retrievers. If Rebecka selects one puppy at random, the pet store replaces the puppy with
a puppy of the same breed, then Aaron chooses a puppy at random. Find the probability that they both select a poodle.
The probability is
(Type an integer or decimal rounded to three decimal places as needed.)
The probability that Rebecka and Aaron both select a poodle is 0.09 or 9/100.
We have,
There are 3 poodles out of 10 puppies, so the probability that Rebecka selects a poodle is 3/10.
After Rebecka selects a poodle and it is replaced with another poodle, there are still 3 poodles out of 10 puppies.
This means,
The probability that Aaron selects a poodle, given that Rebecka selected a poodle, is also 3/10.
Now,
P(both select a poodle) = P(Rebecka selects a poodle) × P(Aaron selects a poodle | Rebecka selected a poodle)
= (3/10) × (3/10)
= 9/100
= 0.09
Therefore,
The probability that Rebecka and Aaron both select a poodle is 0.09 or 9/100.
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Evaluate the integral
guys pls help thank you sm
ln|sec(x)tan(x)| + C is the integral value of ∫sec²x/tanx dx
We can start by using the identity sec²(x) = 1 + tan²(x) to rewrite the integrand as:
sec²(x)/tan(x) = (1 + tan²(x))/tan(x)
= tan(x)/tan(x) + tan³(x)/tan(x)
= 1 + tan²(x)
Now we can make the substitution u = tan(x) to get:
∫sec²x/tanx dx = ∫(1 + tan²(x)) dx
= ∫(1 + u²) du
= u + (1/3)u³ + C
= tan(x) + (1/3)tan³(x) + C
= ln|sec(x)tan(x)| + C,
Therefore, ln|sec(x)tan(x)| + C is the integral value of ∫sec²x/tanx dx
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Select the rule the describes the transformation shown below
Note that the rule that describes the transformation shown is: (x,y) → (x+7,-y)(Number 2)
We have,
A transformation is a broad phrase covering four distinct methods of changing the shape and/or location of a point, line, or geometric figure. The Pre-Image is the original shape of the item, and the Image is the final shape and location of the object after the transformation.
Thus, with regard to the transformation above,
At Point A: The original coordinate of point A was (-6,-6).
The coordinate after the transformation is A'(1,6), which eliminates option 3.
At Point B:
The original coordinate of point B was (-2,4).
After the transformation, we have B'(5,-4), which eliminates option 1 and option 4. It is therefore right to state that (x,y) → (x+7,-y) is the correct representation of the transformation.
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Full Question:
The missing options are:
Which rule describes the transformation shown?
1. (x,y) → (-y, x+7)
2. (x,y) → (x+7,-y)
3. (x,y) → (-x, y+7)
4. (x,y) → (y+7, -x)
4. When the expression x²-3x-18 is factored completely, which expression is one of
the factors?
A.
x-2
B. x-3
C. x-6
D. x-9
The factored form of the expression is (x+3) (x-6), which is equivalent to choice C. x-6 , is one of the factors.
To factor a quadratic expression like this, we want to find two numbers that multiply to the constant term (-18) and add up to the coefficient of the x term (-3).
In this case, those numbers are -3 and 6, because (-3) * 6 = -18 and (-3) + 6 = 3.
Then, we can use those numbers to split the middle term into two terms:
x²-3x-18
=x²+3x - 6x-18
=x(x+3) -6(x+3)
=(x+3) (x-6)
So the factored form of the expression is (x+3) (x-6),
which is equivalent to choice C. x-6 , is one of the factors.
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The sizes (in square meters) of each house on prince street are shown in the histogram below. How many more houses have an area between 150 and 200 m^2 than between 250 and 300 m^2?
The number of more houses between the area 150m² and 200 m² than between 250m² and 300 m² is 8.
What is an histogram?Histogram is a graphical representation of discrete or continuous data. In other words, it is a graphical representation of distribution of data.
Therefore, the histogram has number of houses on the y-axis and area on the x -axis,
The histogram relates the number of houses to the area of the houses in square metres.
Therefore, let's find how many more houses have an area between 150m² and 200 m² than between 250m² and 300 m²?
Hence,
Houses between 150m² and 200 m² = 9
Houses between 250m² and 300 m² = 1
Finally,
difference between them = 9 - 1 = 8 houses
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Write an expression without using the absolute value symbols
The absolute value function can be written as:
if x > 5, then |7 - (12 - x)| = x - 5if x = 0, then |7 - (12 - x)| = 0if x < 5, then |7 - (12 - x)| = 5 - xHow to write the absolute value function?Here we have the function:
|7 - (12 - x)|
We can simplify this to get.
|7 - 12 + x| = |x - 5|
Now, if the argument is positive, then the function is equal to the argument.
If the argument is negative, the function is equal to minus the argument.
Then we can write:
if x > 5, then |7 - (12 - x)| = x - 5
if x = 0, then |7 - (12 - x)| = 0
if x < 5, then |7 - (12 - x)| = 5 - x
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PLEASE ANSWER URGENTLY
What is the domain of y = cot x?
A. (0,pi)
B. all x ≠ kpi/2, where k is an integer
C. all x ≠ pi/2 + kpi, where k is an integer
D. all x ≠ kpi, where k is an integer
E. (-00,00)
The domain of y = cot x is (d) all x ≠ kπ, where k is an integer
Calculating the domain of y = cot x?From the question, we have the following parameters that can be used in our computation:
y = cot x
The domain of the function y = cot x is the set of input values the function can take
As a general rule
The function y = cot x is undefined at the points x = πk where x is an integer
This means that the domain of the function is the set of all real numbers except x = πk
Hence, the domain of y = cot x is (d)
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One eight-ounce glass of apple juice and one eight-ounce glass of orange juice contain a total of 187.7 milligrams of vitamin C. Three eight-ounce glasses of apple juice and four eight-ounce glasses of
orange juice contain a total of 651.4 milligrams of vitamin C. How much vitamin C is in an eight-ounce glass of each type of juice?
apple juice mg
orange juice mg
Answer: Let's use the following variables to represent the amount of vitamin C in an eight-ounce glass of each type of juice:
A: amount of vitamin C in an eight-ounce glass of apple juice (in milligrams)
O: amount of vitamin C in an eight-ounce glass of orange juice (in milligrams)
Using this, we can set up a system of two equations based on the given information:
Equation 1: A + O = 187.7 (total vitamin C in two glasses)
Equation 2: 3A + 4O = 651.4 (total vitamin C in three glasses of apple juice and four glasses of orange juice)
We can solve for one of the variables in terms of the other by rearranging Equation 1:
A = 187.7 - O
Substituting this expression for A into Equation 2, we get:
3(187.7 - O) + 4O = 651.4
Simplifying and solving for O, we get:
563.1 - 3O + 4O = 651.4
O = 88.3
Therefore, an eight-ounce glass of orange juice contains 88.3 milligrams of vitamin C. To find the amount of vitamin C in an eight-ounce glass of apple juice, we can substitute this value into Equation 1:
A + 88.3 = 187.7
A = 99.4
So, an eight-ounce glass of apple juice contains 99.4 milligrams of vitamin C.
Therefore, the amount of vitamin C in an eight-ounce glass of apple juice is 99.4 mg, and the amount of vitamin C in an eight-ounce glass of orange juice is 88.3 mg.
Step-by-step explanation:
Find the volume of the figure. Use 3.14 for . 12 cm 14 cm
The volume of the figure is V = 5,730.265 cm³
Given data ,
Let the figure be represented as V
Now , the figure consists of a cone and hemisphere
So , V = Volume of cone + volume of hemisphere
where height = 14 cm
And , radius r = 12 cm
On simplifying , we get
V = ( 1/3 ) πr²h + ( 2/3 )πr³
V = ( 1/3 ) ( 3.14 ) ( 12 )² ( 14 ) + ( 2/3 ) ( 3.14 ) ( 12 )³
V = 2,111.15026 + 3,619.1147369
On further simplification , we get
V = 5,730.265 cm³
Hence , the volume is V = 5,730.265 cm³
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The complete question is attached below :
Find the volume of the figure. Use 3.14 for . 12 cm 14 cm
Which ratios have a unit rate greater than 1? Choose ALL that apply.
3 1/5 pounds : 4 pounds
7 1/10 pounds : 9/10 pound
7/8 pound : 2 pounds
9/4 pounds : 3/4 pound
3 pounds : 1 1/2 pounds
2 pounds : 1/3 pound
The ratios with unit rates greater than 1 are:
3 1/5 pounds : 4 pounds
7 1/10 pounds : 9/10 pound
9/4 pounds : 3/4 pound
2 pounds : 1/3 pound.
A unit rate is the comparison of two quantities with a denominator of 1.
To determine if the unit rate is greater than 1, we need to compare the numerator to the denominator.
If the numerator is greater than the denominator, the unit rate is greater than 1.
Let's analyze each ratio:
3 1/5 pounds : 4 pounds:
The numerator (3 1/5) is greater than the denominator (4), so the unit rate is greater than 1.
7 1/10 pounds : 9/10 pound:
The numerator (7 1/10) is greater than the denominator (9/10), so the unit rate is greater than 1.
7/8 pound : 2 pounds:
The numerator (7/8) is less than the denominator (2), so the unit rate is not greater than 1.
9/4 pounds : 3/4 pound:
The numerator (9/4) is greater than the denominator (3/4), so the unit rate is greater than 1.
3 pounds : 1 1/2 pounds:
The numerator (3) is equal to the denominator (1 1/2), so the unit rate is not greater than 1.
2 pounds : 1/3 pound:
The numerator (2) is greater than the denominator (1/3), so the unit rate is greater than 1.
Therefore, the ratios with unit rates greater than 1 are:
7 1/10 pounds : 9/10 pound
9/4 pounds : 3/4 pound
2 pounds : 1/3 pound
3 1/5 pounds : 4 pounds
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A scuba diver is 356 feet below the surface of the water. The angle of depression the div-
er makes with her boat is 39⁰.
show your work
The distance between the boat and the diver is D = 276.5 feet
Given data ,
A scuba diver is 356 feet under the water's surface.
And the diver establishes a 39° angle of depression with her boat.
Therefore, using the trigonometric relationships, we can
tan θ = opposite / adjacent
On simplifying , we get
tan 39° = D / 356
Multiply by 356 on both sides , we get
D = 276.5 feet
Hence , the distance is therefore 276.5 ft.
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Triangles A and B are similar. Triangle A is shown below.
The shortest side of triangle B is 6cm. What is the length of the other two sides?
The length of the other two sides of triangle B are determined as:
9 cm and 12 cm.
How to Find the Length of the Sides of Similar Triangles?When solving for the length of the side of triangles that are are similar, note that their sides have lengths that are proportional to each other.
Thus, since triangles A and B are similar, it means they will have side corresponding side lengths that are proportional, therefore:
Let x represent the length of the longest side of triangle B and y represent the medium side.
Therefore, we have:
4/6 = 6/y
4y = 36
4y/4 = 36/4
y = 9 cm
4/6 = 8/x
4x = 48
x = 12 cm
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All of the apportionment methods we have looked at have the potential to violate at least one of the desired properties of apportionment.
Consider the desired property that each state get at least one seat.
1. Explain how/why the others have the potential to violate this property.
2. Explain how/why the two methods guarantee that each party get at least one seat.
Answer:
26
Step-by-step explanation:
I did this a year ago but I forgot my work sorry!
At this rate, how many marshmallows and graham crackers will Janna use to make 13 s'mores?
Janna would be use 30 marshmallows and 45 graham crackers to make 15 s'mores.
Since, We know that;
Multiplication is a mathematical arithmetic operation. It is also a process of adding the same types of expression for some number of times.
Example - 2 × 3 means 2 is added three times, or 3 is added 2 times.
We have to given that;
Janna wants to make s'mores at the backyard campfire.
The table below shows the parts of marshmallows to graham crackers to make s'mores.
S'mores Marshmallows Graham Crackers
4 8 12
15
That means, the rate is,
8/4 = 2 Marshmallows for each S'mores,
And 12/4 = 3 Graham Crackers for each S'mores.
Therefore, 30 marshmallows and 45 graham crackers to make 15 s'mores.
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Complete question is,Janna wants to make s'mores at the backyard campfire. The table below shows the parts of marshmallows to graham crackers to make s'mores.
S'mores Marshmallows Graham Crackers
4 8 12
15
At this rate, how many marshmallows and graham crackers will Janna use to make 15 s'mores?
Janna will use 17 marshmallows and 21 graham crackers to make 15 s'mores.
Janna will use 16 marshmallows and 24 graham crackers to make 15 s'mores.
Janna will use 25 marshmallows and 48 graham crackers to make 15 s'mores.
Janna will use 30 marshmallows and 45 graham crackers to make 15 s'mores.
A bag contains 20 pieces of candy. There are 8 grape pieces, 7 cherry pieces, and 5 lemon pieces. One piece is drawn from the bag. Suppose 2 grape pieces, 1 cherry piece, and 1 lemon piece are removed from the bag.
What is the theoretical probability of drawing each flavor now? Enter answer as a decimal number with a leading zero. Example: 0.5
Step-by-step explanation:
20+8+7+2=37
Graph � ( � ) = 2 cos ( � 5 � − 2 � 5 ) − 4 f(x)=2cos( 5 π x− 5 2π )−4f, left parenthesis, x, right parenthesis, equals, 2, cosine, left parenthesis, start fraction, pi, divided by, 5, end fraction, x, minus, start fraction, 2, pi, divided by, 5, end fraction, right parenthesis, minus, 4 in the interactive widget. Note that one moveable point always defines an extremum point in the graph and the other point always defines a neighbouring intersection with the midline.
The equation represents a cosine function that is horizontally shifted, vertically shifted, and scaled with specific values for amplitude, period, phase shift, and midline adjustment.
The equation and description of the interactive widget graph. It appears that the equation you've shared represents a periodic function, specifically a cosine function, with some transformations applied to it.
The general form of a cosine function is given by:
f(x) = A * cos(Bx - C) + D
In your equation, the parameters have specific values:
A = 2
B = 5π/5 = π
C = 5/(2π) = 5/2π
D = -4
The parameter A determines the amplitude of the cosine function, which controls the vertical range of the graph. In this case, it is 2, so the graph will oscillate between 2 units above and 2 units below the midline.
The parameter B affects the period of the function. Since B = π, the period of the cosine function will be 2π/B = 2π/π = 2. This means that the graph completes one full cycle (i.e., goes through one peak and one trough) over an interval of length 2.
The parameter C introduces a phase shift or horizontal translation to the graph. The value of C, 5/2π, determines how much the graph is shifted horizontally. Specifically, it is shifted 5/(2π) units to the right.
The parameter D is the vertical shift or midline adjustment. With D = -4, the entire graph is shifted downward by 4 units.
The movable point mentioned in the widget likely allows you to change the value of x and observe how it affects the position of the extremum point and the intersection points with the midline.
Overall, the equation represents a cosine function that is horizontally shifted, vertically shifted, and scaled with specific values for amplitude, period, phase shift, and midline adjustment.
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14in Find the area. 19in 13in A = [?] in² Enter
The value of the area of a triangle is equal to 133 in^2.
We are given that;
Dimensions= 19in 13in
Now,
To determine the area of a triangle, we can use the formula A = (1/2) bh, where b is the base and h is the height.
The base and the height are the sides that are perpendicular to each other. For example, the area of a right triangle with base 12 in and height 9 in is;
A = (1/2) * 12 * 9
A = 54 in^2.
To find the area of the given triangle, we need to identify the base and the height. The base could be any side of the triangle, but the height must be perpendicular to it. In this case, we can choose the side with length 19 in as the base, and the side with length 14 in as the height. Using the formula, we get:
A = (1/2) * b * h
A = (1/2) * 19 * 14
A = 133 in^2
Therefore, by the area, the answer will be 133 in^2.
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A carpenter has $91 to buy wood. If each piece of wood costs $3, how many pieces can the carpenter buy?
Answer:
30 pieces----------------------------
Divide the total amount by the cost per piece:
$91 ÷ $3 = 30.3333Since the carpenter can only buy whole pieces of wood, they can buy 30 pieces.
fine the nth term of 11,13,15,17
The nth term of 11,13,15,17 is,
⇒ T (n) = 9 + 2n
Given that;
The sequence is,
11, 13, 15, 17, ....
Here, Common difference is,
13 - 11 = 2
15 - 13 = 2
Hence, Sequence is in Arithmetic sequence.
So, the nth term of 11,13,15,17 is,
⇒ T (n) = a + (n - 1)d
⇒ T (n) = 11 + (n - 1) 2
⇒ T (n) = 11 + 2n - 2
⇒ T (n) = 9 + 2n
Thus, The nth term of 11,13,15,17 is,
⇒ T (n) = 9 + 2n
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Use the table that shows the recent population, in millions, of the ten largest U.S. cities.
Find the mean absolute deviation. Round to the nearest hundredth.
The mean absolute deviation =________million.
The mean absolute deviation of the population is:
1.50 million
How to calculate the mean absolute deviation of a data set?Mean absolute deviation (MAD) is a measure of the average absolute distance between each data value and the mean of a data set. The formula for MAD is:
MAD =∑|x-m|/n
∑ is known as Sigma and means to sum up
| | are vertical bars that mean absolute value
x is each value
m is the mean
n is the total number of data points in your data set
n = 10
m = (1.5 + 3.8 + 1.3 + 1.6 + 2.9 + 1.4 + 0.9 + 2.3 + 8.4 + 1.3)/10
= 25.4/10
= 2.54
∑|x-m| = |1.5-2.54| + |3.8-2.54| + |1.3-2.54| + |1.6-2.54| + |2.9-2.54| + |1.4-2.54| +|0.9-2.54| + |2.3-2.54| + |8.4-2.54| + |1.3-2.54|
= 1.04 + 1.26 + 1.24 + 0.94 + 0.36 + 1.14 + 1.64 + 0.24 + 5.86 + 1.24
= 14.96
MAD =∑|x-m|/n = 14.96/10 = 1.496
Rounding to the nearest hundredth:
MAD = 1.50
Therefore, the mean absolute deviation of the population is 1.50 million
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(a) If tan² A = 1 + 2tan² B, prove that cos² B = 2cos² A
Step-by-step explanation:
Note:
tanA=sinA/CosA i.e tan^2A=sin^2A/cos^2A
tanB=sinB/cosB
cos^2A+sin^2A=1
cos^2B+sin^2B=1
I hope this helps.
What is the product when the sum of (-2) and (-4) is multiplied with their difference?
Answer:
- 12--------------------
The sum of (-2) and (-4) is:
(- 2) + (- 4) = - 6The difference of (-2) and (-4) is:
(- 2) - (- 4) = - 2 + 4 = 2The product of the sum and difference is:
(-6) × 2 = - 12Lingenburger Cheese Corporation has 6.4 million shares of common stock outstanding, 200,000 shares of 3.8 percent preferred stock outstanding, par value of $100, and 120,000 bonds with a semiannual coupon of 4.8 percent outstanding, par value $1,000 each. The common stock currently sells for $54 per share and has a beta of 1.08, the preferred stock currently sells for $103 per share, and the bonds have 15 years to maturity and sell for 107 percent of par. The market risk premium is 7.5 percent, T-bills are yielding 2.4 percent, and the company's tax rate is 22 percent. eBook Hint Print a. What is the firm's weight of equity, debt, and preferred stock.
The weights of equity, debt, and preferred stock, based on the market value of each component, of Linge burger Cheese Corporation, are as follows:
Weight of equity = 69.87%Weight of preferred stock = 4.17%Weight of debt = 25.96%.What is the firm’s weight of equity, debt, and preferred stock?Firstly, we calculate the market value of each capital component and divide the result by the total market value of the firm. This process determines the weights of equity, debt, and preferred stock.
The market value of equity is the number of shares outstanding multiplied by the current share price.
Common stock:Number of shares outstanding = 6.4 million
Market value per share = $54
Common stock beta = 1.08
Market value = $345.6 million (6.4 million × $54)
3.8% preferred stock:Number of shares outstanding at $100 par value = 200,000
Market value per share = $103
Market value = $20.6 million (200,000 × $103)
4.8% Bonds:Number of bonds outstanding, par value $1,000 each = 120,000
Maturity period of bonds = 15 years
Market value per bond = 107 percent of par
Market value of debt = $128.4 million (120,000 × 1.07 × $1,000)
T-bill yields = 2.4%
Corporate tax rate = 22%
Total market value = $494.6 million ($345.6 million + $20.6 million + $128.4 million)
Weight of equity = 0.6987 or 69.87% ($345.6 million ÷ $494.6 million)
Weight of preferred stock = 0.0417 or 4.17% ($20.6 million ÷ $494.6 million)
Weight of debt = 0.2596 or 25.96% ($128.4 million ÷ $494.6 million)
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what is the single power of 10 for 10^5*10^0
Answer: If we resolve, 10 to the power of 5 means 100,000.
Step-by-step explanation:
Which retirement plan(s) potentially involve contributions from an individual's employer?
I Traditional IRA
II Social Security
III Pension Plan
IV 401(k)
I, II
II, III
I, II, III
II, III, IV
The retirement plans that potentially involve contributions from an individual's employer are I, III, and IV.
I - Traditional IRA: A Traditional IRA is an individual retirement account (IRA) that allows individuals to set aside money on a pre-tax basis. Contributions to a Traditional IRA may be made by an individual, or they may be made by an employer as part of an employee's retirement plan.
III - Pension Plan: A pension plan is a retirement plan organized by an employer that provides a guaranteed income to an employee after retirement. Employers typically make contributions to their employee's pension plan on their behalf.
IV - 401(k): A 401(k) is an employer-sponsored retirement savings plan. Contributions to a 401(k) plan can be made by an employee and their employer. Employers may match employee contributions, up to a certain percentage.
Therefore, the retirement plans that potentially involve contributions from an individual's employer are I, III, and IV.
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use the convolution theorem to solve
Answer:
[tex]y(t)=\frac{1}{2}t^2+y_1t }[/tex]
Step-by-step explanation:
Refer to the attached image(s).
[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Table of basic Laplace Transforms:}}\\1\rightarrow \frac{1}{s} \\t^n\rightarrow \frac{n!}{s^{n+1}}\\e^{at} \rightarrow\frac{1}{s-a}\\ \sin(at)\rightarrow\frac{a}{s^2+a^2}\\\cos(at)\rightarrow\frac{s}{s^2+a^2}\\e^{at}\sin(bt)\rightarrow\frac{b}{(s-a)^2+b^2}\\e^{at}\cos(bt)\rightarrow\frac{s-a}{(s-a)^2+b^2}\\t^ne^{at}\rightarrow\frac{n!}{(s-a)^{n+1}} \end{array}\right}[/tex]
6c –2c =4 into a real life word problem
Answer:
1
Step-by-step explanation:
6c - 2c = 4
4c = 4
c = 4/4
c = 1
Approximate the direction angle of the vector 4i+ 4j-2k.
The approximate direction of the angle of the vector is determined as 45 degrees.
What is the direction of the angle of the vector?The approximate direction of the angle of the vector is calculated by applying the following formula for direction of a vector as follows;
The formula for the direction of a vector is given as;
tan θ = Vy / Vx
where;
Vy is the y component of the vectorVx is the x component of the vectorThe vector is given as;
V = 4i + 4j - 2k
The y component = 4, and the x component = 4
The direction of the vector is calculated as;
tan θ = 4 / 4
tan θ = 1
θ = arc tan (1 )
θ = 45⁰
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Converting a Repeating Decimal into a Fraction
Through the work that was shown, you have
999x = 393
If you divide both sides of the equation by 999, you'd have
[tex]x=\dfrac{393}{999} = \dfrac{131}{333}[/tex]
So, [tex]0.\overline{393} =\dfrac{131}{333}[/tex]
A rectangle has vertices A(6, 4), B(2, 4), C(6, -2), D(2, -2).
What are the coordinates of the vertices of the image after a dilation with the origin as its center and a scale factor of 2?
The vertices of the image after a dilation with the origin as its center and a scale factor of 2 are having coordinates A' = (12, 8), B' = (4, 8), C' = (12, -4) and D' = (4, -4)
To dilate a figure with the origin as the center, we only need to multiply each coordinate by the scale factor. In this case, the scale factor is 2.
So, for vertex A(6, 4), we have:
x-coordinate after dilation: 2 × 6 = 12
y-coordinate after dilation: 2 × 4 = 8
Similarly, for vertex B(2, 4), we have:
x-coordinate after dilation: 2 × 2 = 4
y-coordinate after dilation: 2 × 4 = 8
For vertex C(6, -2), we have:
x-coordinate after dilation: 2 × 6 = 12
y-coordinate after dilation: 2 × (-2) = -4
Finally, for vertex D(2, -2), we have:
x-coordinate after dilation: 2 × 2 = 4
y-coordinate after dilation: 2 × (-2) = -4
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