Which statement describes the particles in a liquid?
A. They do not move.
B. They are far apart.
C. They are close together.
D. They are locked in position.

Answer:

The rock with more mass will also have more force pulling it down, so the accelerations can be the same.

Explanation:

Answer:

The distance of man from the mirror is 3 m

Refer to the attachment

[tex]\Large\textsf{Hope \: It \: Helped}[/tex]

The distance of the man from the mirror is 3m

From the characteristics of image formed in a plane mirror,

⇒ From the last point,

⇒ From the question,

Hence, The distance of the man from the mirror is 3m

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Answer:

  2.5 m/s east

Explanation:

Let east be the positive direction for velocity.

The change in momentum of the 0.75 kg model car is ...

  m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)

  = (0.75 kg)(20 m/s) = 15 kg·m/s

The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.

  m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s

The required relation is ...

  15 kg·m/s = -2(v2 -10) kg·m/s

  -7.5 = v2 -10 . . . . divide by -2

  2.5 = v2 . . . . . . . add 10

The velocity of the model truck after the collision is 2.5 m/s east.

Answer:

Explanation:

An impulse results in a change of momentum

If the wagon and dog both stop, they must have had equal and opposite momentums

FΔt = mΔv

F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)

v₁ = t₀ = 0

F = m(v₀)/t₁

F = 55(2.1)/0.1 = 1155 N

We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.

The acceleration due to gravity on Mars is 11.81 m/s².

The given parameters:

The equation of motion to determine the acceleration due to gravity on the moon is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2[/tex]

where;

Since the time measured is two way time, the new equation for the total distance traveled is calculated as;

[tex]v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m[/tex]

The acceleration due to gravity is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2[/tex]

Thus, the acceleration due to gravity on Mars is 11.81 m/s².

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Answer:

Light takes less time than sound.

Explanation:

Let's say, the teacher and the student are at a distance "d" from each other.

The medium around them would be air.

And,

The speed of light in air is approx. 3× 10⁸ m/s

while, the speed of sound in air is approx. 330 m/s

We have a formula that establishes the relation between speed, distance and time.

[tex] \boxed{ \mathsf{speed = \frac{distance}{time} }}[/tex]

Our hunt for time — Speed in both the scenarios is known to us whereas the distance is same.

Sound

[tex] \mathsf{330 = \frac{d}{time_{s}} }[/tex]

[tex] \underline{\mathsf{time _{s} = \frac{d}{330} }}[/tex]

Light

[tex] \mathsf{3 \times {10}^{8} = \frac{d}{time _{l} } }[/tex]

[tex] \underline{ \mathsf{ time _{l} = \frac{d}{3 \times {10}^{8}} }}[/tex]

The best way of comparison is finding their ratio.

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ \frac{d}{330} }{ \frac{d}{3 \times {10}^{8} } } }[/tex]

simplifying the fraction

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{d \times (3 \times {10}^{8} )}{330 \times d}}[/tex]

d gets canceled and we're left with the following expression

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ (3 \times10 \times {10}^{7} )}{330}}[/tex]

30, being a common factor in the numerator as well as denominator, gets canceled out. and in its place remains 1/ 11

(why?

=> 30÷330 = 1÷11)

[tex] \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ 1\times {10}^{7} }{11}}[/tex]

taking timeₛ to the numerator on the other side.

[tex] \implies \mathsf{time_{s} = \frac{ 1\times {10}^{7} }{11}\times time_{l}}[/tex]

Therefore, we get timeₛ is approx. 10⁶ times the timeₗ.

That's a big difference, no wonder light's way much faster than sound.

As lesser the time taken to cover a distance, faster is the wave.

The sound takes about 874,000 times MORE time than the light takes.

Answer:

Explanation:

momentum is conserved. Initial momentum was zero, so final total momentum must also be zero

0.042(650) + 70v = 0

v = -0.39 m/s

|v| = 0.39 m/s

Answer:

2.quickly change the direction of your movement

Explanation:

Answer:

analyze, assess or interpret an historical event, era, or phenomenon,.

Explanation:

Secondary sources are works that analyze, assess or interpret an historical event, era, or phenomenon, generally utilizing primary sources to do so. Secondary sources often offer a review or a critique. Secondary sources can include books, journal articles, speeches, reviews, research reports, and more.

Answer:

The nervous system handles the stress response, which, if overworked, can eventually lead to diseases ranging from high blood pressure to diabetes.

Explanation:

hope I helped

Answer:

Give me what kind of example you need please so I can help you. Put it in the comments.

Explanation:

Answer:

geothermal energy

Explanation:

the energy is obtained from the heat within the surface of earth

Answer:

heat energy

Explanation:

Answer:

ıf u find the answer can u comment me to notification thank u

Explanation:

(a) The period of the sound wave is 0.005 s.

(b) The wavelength of the wave when the speed of the wave is 1480 m/s is 6.73 m.

(c) The wavelength of the sound wave as it travels through air is 1.55 m.

The given parameters;

The period of the sound wave is calculated as follows;

[tex]T = \frac{1}{f} \\\\T = \frac{1}{220} \\\\T = 0.005 \ s[/tex]

The wavelength of the wave when the speed of the wave is 1480 m/s is calculated as follows;

[tex]v = f\lambda \\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{1480}{220} \\\\\lambda = 6.73 \ m[/tex]

The wavelength of the sound wave as it travels through air with a speed of about 341 m/s;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{341}{220} \\\\\lambda = 1.55 \ m[/tex]

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Answer:

18.36 m/s

Explanation:

We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:

1/2mv^2=mgh

m=mass

g=gravity

h=height

v=velocity

We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.

19m-1.8m=17.2m

Now we can plug in our variables to solve for velocity.

First we negate mass since its on both sides and cancels out leaving us with.

1/2v^2=gh

Plug in.

1/2v^2=(9.8)(17.2)

1/2v^2=168.56

v^2=337.12

v=18.36m/s

The name and strength of the force holding the block up is 50 N upward - Normal force.

The given parameters:

The weight of the block acting downwards due to gravity is calculated as follows;

W = mg

where;

W = 5 x 10

W = 50 N (downwards)

Since the block is at rest, an a force equal to the weight of the block must be acting upwards. This force is known as normal reaction.

Fₙ = 50 N (upwards)

Thus, the name and strength of the force holding the block up is 50 N upward - Normal force.

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The block will remain on the table because the normal force balances with the weight of the block. The correct answer is  50 N upward normal force

From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be

Weight W = mg

let g = 10 m/[tex]s^{2}[/tex]

W = 5 x 10

W = 50 N

The block will also produce an equal but in opposite direction of a normal force which is equal to the weight of the block. That is,

Normal force N = 50 N

The block will remain on the table because the normal force balances with the weight of the block.    

Therefore, the correct name and strength of the force holding the block up is 50 N upward normal force.

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Answer:

Light behaves differently in space than on Earth.

Explanation:

Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.

Explanation:

12N by first law of newton is net force after colloision

Answer:

Looks good to me

Explanation:

#2 should probably be turning potential energy to kinetic.

Answer:

h = change in vertical position (height)

has units of distance.

Explanation:

The equation below can be used to calculate a change in gravitational potential energy then the units used for the height would be meters.

The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.

As given in the problem, the equation below can be used to calculate a change in gravitational potential energy, the units used for the height of the object would be in meters, which is the SI unit of the length

The gravitational potential energy = mass×acceleration ×height

Thus, the unit of height used in the gravitational potential energy formula would be meter.

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Answer:

7.5m/s

Explanation:

Force= mass × velocity

Energy is conserved, the car and van should have the same overall force.

1500kg × 30m/s= 6000kg × final velocity

Final velocity = 7.5m/s

The strength of the thrust is 122 newtons.

The motion of the rocket is described by the second Newton's law, whose model is shown below:

[tex]\Sigma F = F - D = m\cdot a[/tex] (1)

Where:

If we know that [tex]D = 90\,N[/tex], [tex]m = 8\,kg[/tex] and [tex]a = 4\,\frac{m}{s^{2}}[/tex], then the strength of the thrust is:

[tex]F = D + m\cdot a[/tex]

[tex]F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 122\,N[/tex]

The strength of the thrust is 122 newtons.

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Hi there!

The period is given by:

[tex]T = \frac{2\pi}{w}[/tex]

T = Period (sec)

w = angular frequency (rad/sec)

According to the equation for SHM in terms of position:

y(t) = Asin(ωt + φ)

A = Amplitude (m)

ω = angular frequency (rad/sec)

t = time (sec)

φ = phase angle

In this instance, the angular frequency is given as 18π.

Plug this value into the equation for T:

[tex]T= \frac{2\pi}{18\pi} = \frac{1}{9} = \boxed{0.111 s}[/tex]

Answer:

6621.75J

Explanation:

In this case, the bell is not in motion. So we are going to calculate its potential energy rather than its kinetic energy since kinetic energy is the energy a body possesses in motion.

The formula for the potential energy is m*g*h, meaning the mass * acceleration due to gravity * height. Here the mass, m = 15kg, the acceleration due to gravity = 9.81m/s^2, and the height, h = 45m

Substituting our values, the answer becomes 15 * 9.81 * 45 = 6621.75J. Hope you understood my explanation?

Answer:

-9.0 × 10-6 m3 kg

Explanation:

I'm not sure if that's what you're looking for nor do I know how to explain it.

All metals are solid at (our) living temperatures except for mercury which is a liquid. Metals are shiny for a while at least when properly finished. Metals are good conductors of both heat and electricity. This is due to the excess electrons in their valence clouds that facilitate energy transfer.What are 5 characteristics of metal?

Metals are lustrous, malleable, ductile, good conductors of heat and electricity

Silver conducts electricity better than any other metal.

Brass is an alloy made from zinc and copper.

Pure gold is too soft for many things so most gold is combined with other metals to make it stronger. ...

World time periods are often listed by the metal used.

Explanation:

a) Here is the free-body diagram. Note that I included the components of the weight mg (shown in dotted arrows) for use in the other parts of the problem.

b) The component of the weight parallel to the plane (shown in the diagram as a dotted arrow along the x-axis) is [tex]mg\sin15[/tex] and it is equal to

[tex]mg\sin15 = (25\:\text{kg})(9.8\:\text{m/s}^2)\sin15 = 63.4\:\text{N}[/tex]

c) Applying Newton's 2nd law to the y-axis, we can write

[tex]y:\;\;\;N - mg\cos15 = 0 \Rightarrow N = mg\cos15[/tex]

[tex]N = (25\:\text{kg})(9.8\:\text{m/s}^2)\cos15 = 236.7\:\text{N}[/tex]

d) The component of the weight mg into the plane is the same as the normal force, hence it's also 236.7 N.

e) To solve for the coefficient of friction, we apply Newton's 2nd law to the x-axis:

[tex]x:\;\;\;mg\sin15 - F_f = 0[/tex]

[tex]\Rightarrow F_f = mg\sin15\;\;(2)[/tex]

where [tex]F_f[/tex] is the frictional force defined as [tex]F_f = \mu N[/tex] so we can use Eqn(1) on Eqn (2) to write

[tex]\mu (mg\cos15) = mg\sin15[/tex]

Solving for [tex]\mu,[/tex] we get

[tex]\mu = \dfrac{\sin15}{\cos15} = \tan15 = 0.27[/tex]

Explanation:

decomposition reaction.....

Answer:

caco₃--cao+co₂

calcium oxide + carbon die oxide gives us calcium carbonate

this is the reaction of Acidic oxide(cao) and Basic oxide (co₂) to form salt.

An object following a straight-line path at constant speed is option C.) has zero acceleration.

There are no forces operating on a body if it is travelling straight ahead at a steady speed. There are no forces operating on a body if it is travelling straight ahead at a steady speed.

Note that the physics concept of acceleration measures how quickly an object's motion is changing. An object's speed or velocity is what largely defines its motion.

Therefore, An object is considered to be accelerating when its velocity changes over time and as such  since acceleration of the object is  said to be  zero, one can say that the net force acting on it is also zero.

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