which statement is correct?

Which Statement Is Correct?

Answers

Answer 1

Answer:

the first one

Step-by-step explanation:

0.0206×0.188<0.0769/0.000023


Related Questions

Which equation is equivalent to the given equation?
-4(X - 5) + 8x = 9x - 3

Answers

Answer:

-5x=-23

Or

X=23/5

Step-by-step explanation:

Find the indicated side of the
right triangle.
30°
X
X
60
= [?]√]
7
Enter

Answers

Answer:

[tex]7\sqrt{3}[/tex]

Step-by-step explanation:

This is a special triangle with the angles being 30-60-90. The adjacent side to the angle of 30 degrees has a length of x * sqrt(3). The opposite side has a length of x. Since the opposite side has a length of 7 here you simply plug that into x * sqrt(3) to find the length of the adjacent side of the angle 30 degrees which gives you 7 * sqrt(3)

In a casual italian restaurant, sales for the week of september 15 are as follows: food sales: $10.000 beverage sales: $ 2.500 total $12.500 a. if the food cost is 30 percent, how much did the food actually cost? b. if the beverage cost is 25 percent of beverage sales, how much did the beverages cost?

Answers

Answer: $625

Step-by-step explanation:

Total beverage sales = $2,500

Beverage cost = 25%

So, $2,500 x 25% = $2,500 x 0.25 = $625

Pls help asap ily

one hour after junior space cadet had left his house, his sister gwen discovered that he had forgotten his head. if junior was driving at a speed of 50 mph, and gwen drove at a speed of 75 mph, how many hours did it take gwen to restore junior's head to his shoulders?

Answers

Answer:

2 hours

Step-by-step explanation:

you can write two linear equations and then set them equal to each other to see when they intersect. so for the first equation which will be representing the junior space cadets distance from his house. this can be written as

d = 50t + 50

where t represents time and d represents distance. there is 50 being added to the equation since he had already been traveling for an hour

the second equation which will represent his sister Gwen can be represented as

d = 75t

Now we set them equal to each other

50t + 50 = 75t

50 = 25t

2 = t

please help me find the HCF of this​

Answers

Answer: a

Step-by-step explanation:

[tex]a^{2}=a \cdot a\\a^{2}+ab=a(a+b)[/tex]

Therefore, the HCF is a.

Answer:

a

Step-by-step explanation:

Factorizing both terms :

a² = a × aa² + ab = a × (a + b)

The HCF of the terms is a.

Casey picked 6 pounds of strawberries. Karen picked 48 ounces of blueberries. Jude picked 2 pounds of raspberries. They are going to make berry pies. The table shows the amount of berries needed for 1 pie.Select all of the true statements below.
A.

Together, Karen and Jude picked the same weight of fruit as Casey picked.


B.

Casey picked 2 times the weight of fruit that Karen picked.


C.

There are enough berries to make 6 berry pies.


D.

If they make as many pies as they can with the berries they picked, there will be 4 pounds of strawberries left over.


E.

To make 8 berry pies, they will need 1 more pound of blueberries and 2 more pounds of raspberries.

Answers

Answer:

Option B is correct

Answer:

B there is enough raspberries to make 4 pie they can 6 pies if they 2 more of raspberries

Progress
Solve for x. Round to the nearest tenth, if necessary

Answers

Answer:

x ≈ 1.1

Step-by-step explanation:

using the cosine ratio in the right triangle

cos41° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{0.8}{x}[/tex] ( multiply both sides by x )

x × cos41° = 0.8 ( divide both sides by cos41° )

x = [tex]\frac{0.8}{cos41}[/tex] ≈ 1.1 ( to the nearest tenth )

solve the inequality 5x+3> 48

Answers

Answer:

x > 9

Step-by-step explanation:

for this inequality, we want to isolate x, so that we know the inequality of x

5x + 3 > 48

     - 3      -3        {subtract 3 from both sides to get x alone}

5x > 45

/5      /5                {divide both sides by 5 to find 1x}

x > 9

So , x > 9 is the inequality in terms of x {is the solution}

hope this helps! :)

Answer:

[tex]\huge\boxed{\sf x > 9}[/tex]

Step-by-step explanation:

Given inequality:

5x + 3 > 48

Subtract 3 to both sides

5x > 48 - 3

5x > 45

Divide 5 to both sides

x > 9

[tex]\rule[225]{225}{2}[/tex]

Find the Value of log10 (0.0001). Rescue me!

Answers

Let's see

[tex]\boxed{\sf log_aa=1}[/tex]

Now

[tex]\\ \rm\Rrightarrow log_{10}0.0001)[/tex]

[tex]\\ \rm\Rrightarrow log_{10}10^{-4}[/tex]

[tex]\\ \rm\Rrightarrow -4log_{10}10[/tex]

[tex]\\ \rm\Rrightarrow -4[/tex]

Answer:

This has already been answered correctly, but I'll add an additional perspective.  The log of (0.0001 to the base 10 is -4.

Step-by-step explanation:

log(base 10) says give us an exponent, x, that would be required to make [tex]10^{x}[/tex] equal to a specified number, in this case 0.0001.

[tex]10^{0}[/tex] = 1

[tex]10^{1}[/tex] = 10

[tex]10^{-1}[/tex] = 0.1

[tex]10^{-2}[/tex] = 0.01

[tex]10^{-4}[/tex] = 0.0001

The log of (0.0001) to the base 10 is -4.

Consider the transformation shown. 2 triangles are shown. The first is labeled pre-image and the second is labeled image. Both triangles have congruent angle measures. The pre-image has side lengths of 6, 10, and 8. The image has side lengths of 3, 5, and 4. Use the drop-down menus to complete the sentence. The transformation is because the preserved.

Answers

The transformation is non-rigid because the side lengths are not preserved.

How to complete the drop-down menus?

The drop-down menus and the image of the triangles are not given.

However, the question can still be solved using the available parameters.

The given parameters are:

Pre-image: 6, 10, 8

Image: 3, 5, 8

See that the side lengths of the image and the pre-image are not the same

This means that the transformation is a non-rigid transformation

Hence, the complete statement is the transformation is non-rigid because the side lengths are not preserved.

Read more about transformation at:

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What is (-2)-(-2 1/6) and how do i get that answer?

Answers

Answer:

1/6

Step-by-step explanation:

-2 - (-2 1/6)

multiply the number in the parentheses by -1

-2 + 2 1/6

-2 + 2  cancels out

Leaving 1/6 as your answer.

Given lJK , which is an isosceles right triangle, IJ=4 and m

Answers

As IJK is isosceles

IJ=JK

Hypotenuse must not counted counted among equal sides so

IK²=2(LJ)²

Apply roots

IK=LJ√2

Option C

a) Write 2 expressions for the area of the shaded region.
b) Find the length of the shaded region if the perimeter is 48cm.
c) Find the area of the shaded region if perimeter is 48cm.

Answers

Answer:

(a)9×3=37' 97 and 8 are factors of 37

what 1 - 2/9 - 1/3 - 1/6 =

Answers

Answer:

5/18

Step-by-step explanation:

The LCD of 9, 3, and 6 is 18.

1 - 2/9 - 1/3 - 1/6 =

= 18/18 - 4/18 - 6/18 - 3/18

= 5/18

Answer: 5/18

Step-by-step explanation:

1/1 - 2/9 - 1/3 - 1/6

18 - 4 - 6 - 3/18

5/18

PLEASE HELP I WILL MARK BRAINLEST

Answers

#1

Error at sign shift due to -

Correct version

[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]

[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]

[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]

#2

Not multiplied 3x with x

[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]

[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]

y=-6x-8
y=-6x+8

Solve the system of linear equations

Answers

Answer: No solution

Step-by-step explanation:

Both of these equations have the same number as to coefficient of x (-6) but have a different constant (-8 and 8). This means that there are no solutions to this system of equations.

Find the coordinates of the midpoint of the segment whose endpoints are given W (-3,-7) and X (-8,4)

1. (-11/2) -(11/2)
2.(-5/2)-(3/2)
3.(-5/2-(11/2)

Answers

The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.

The complete options are given below.

1. (-11/2) -(11/2)

2.(-5/2)-(3/2)

3.(-5/2-(11/2)

4. (-11/2) -(-3/2)

What is the midpoint of line segment AB?

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The end points are given below.

(-3, -7) and (-8, 4)

We have

(x₁, y₁) = (-3, -7)

(x₂, y₂) = (-8, 4)

Then the mid-point will be

x = (- 3 - 8) / 2

x = -11 / 2

y = (-7 + 4) / 2

y = -3/2

Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).

Then the correct option is D.

More about the midpoint of line segment AB link is given below.

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Which of the following is equivalent to 8-3x > 2(3x - 5) ?
A. 18>9x
B. 9x<13
C. 11>9x
D. -8x>2

Answers

Answer:

A

Step-by-step explanation:

Given:

[tex]8-3x > 2(3x-5)[/tex]

Simplify by distributing:

[tex]8-3x > 6x-10[/tex]

Add 10 to left side and add 3x to the right side:

[tex]18 > 9x[/tex]

x(y − 3) + n(3 − y)


Answers

This is the answer and the following 4 steps to get your answer.

please help!! The dot plots below show the ages of students belonging to two groups of salsa classes:
Based on visual inspection, which group most likely has a lower mean age of salsa students? Explain your answer using two or three sentences. Make sure to use facts to support your answer.

Im thinking group A but at this point im just plain out confused

Answers

Group A I’m pretty confident with that answer

What is the solution to this equation?
8x-5(x-3) = 18
OA. x=5
OB. x = 1
OC. x = 11
OD. x=7

Answers

Answer:

x=1

Step-by-step explanation:

8x-5(x-3) = 18

The first step is to distribute

8x -5x+15 = 18

Combine like terms

3x+15 = 18

Subtract 15 from each side

3x+15-15=18-15

3x=3

Divide by 3

3x/3 =3/3

x=1

(Giving 80 points, Please do not answer if you don't know. The second and third answer are not 4 btw)
Point A is on the point −6 and Point B is on the point 0. Let's use the Ruler Postulate to find the length of AB¯¯¯.

AB=|a−b|

AB=|−6−0|

AB=|−6|

AB=6

The length of AB¯¯¯¯ is 6. We can also write this as AB=6 or mAB¯¯¯¯=6.

Find the Length of CD¯¯¯¯
Now, let's find the length of CD¯¯¯¯. Point C is on the point 4 and Point D is on the point 8.

CD=|c−d|

CD=|4−8|

CD=|−4|

CD=4

The length of CD¯¯¯ is 4. We can also write this as CD=4 or mCD¯¯¯=4

Your Turn
1. What is the length of BC¯¯¯? 4
2. What is the length of AC¯¯¯¯?
3. What is the length of AD¯¯¯¯?

Answers

Answer:

1. 4

2. 10

3. 14

Step-by-step explanation:

A = -6

B = 0

C = 4

D = 8

1. BC = |0 - 4| = 4

2. AC = |-6 - 4| = |-10| = 10

3. AD = |-6 - 8| = |-14| = 14

Answer:

1.  BC = 4

2.  AC = 10

3.  AD = 14

Step-by-step explanation:

Ruler Postulate

The distance between any two points on a number line is their difference.

Question 1

Given:

Point B = 0Point C = 4

Therefore, using the Ruler Postulate:

⇒ BC = |b - c|

⇒ BC = |0 - 4|

⇒ BC = |-4|

BC = 4

Question 2

Given:

Point A = -6Point C = 4

Therefore, using the Ruler Postulate:

⇒ AC = |a - c|

⇒ AC = |-6 - 4|

⇒ AC = |-10|

AC = 10

Question 3

Given:

Point A = -6Point D = 8

Therefore, using the Ruler Postulate:

⇒ AD = |a - d|

⇒ AD = |-6 - 8|

⇒ AD = |-14|

AD = 14

Calculate the AREA of the shape below. Give your answer in cm²

Answers

Answer:

[tex] \boxed{\bf 26\: cm^2} [/tex]

Step-by-step explanation:

We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.

Area of rectangle:-

[tex]\bf 5 \times 2[/tex][tex]\bf 10 \:cm^{2} [/tex]

Area of square :-

[tex]\bf 4 \times 4[/tex][tex]\bf 16 \: {cm}^{2} [/tex]

Total area :-

[tex]\bf 10 + 16[/tex][tex]\boxed{\bf 26 \: {cm}^{2} }[/tex]_________________________

Answer:

26 cm^2

Step-by-step explanation:

you have two rectangles, the bigest has the base of 6cm and the height of 4cm, the area is 6 * 4 = 24cm ^ 2, the other rectangle has the base of 6 - 4 = 2 and the height of 5 - 4 = 1, 2*1=2.

we add the dimensions and we have the area of ​​the complete figure 24 + 2 =

26 cm ^ 2

Write the rate in lowest terms a printer can print 22 pages in 55 seconds

Answers

Answer:

2/5

Step-by-step explanation:

22/11=2

55/11=5

Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x2 + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.

1. At what time will Lindsey be 30 feet in the air?

2. How high is the diving board? Explain your thinking.

Answers

Answer:

1. [tex]x = 2.45s[/tex]

2. The diving board is 45 ft high.

Step-by-step explanation:

• When Lindsey is 30 feet in the air, y = 30.

[tex]30 = -16x^2 + 33x +45\\\\-16x^2 + 33x +15 = 0\\\\16x^2 - 33x -15 = 0\\[/tex]

Using quadratic formula, solve for x:

[tex]x = \frac{33 + \sqrt[]{(-33)^2 - 4(16)(-15)} }{2(16)}[/tex]

[tex]x = 2.45s[/tex]

• If we calculate the height of Lindsey in the air when she is standing on the diving board, we can find the height of the diving board above the ground.

When she is standing on the board, x = 0 as no time has passed after jumping.

[tex]y = -16(0)^2 + 33(0) +45\\\\y = 45 ft[/tex]

albert worked for 8 hours and earned $24. how much does albert earn for 24 hours

Answers

Answer:

$72

Step-by-step explanation:

The probability of a drawing a blue marble from a box of 18 marbles is 2/3. How many green marbles should be added to the box in order to reduce the probability to 1/2?

Answers

Answer:

6 green marbles should be added.

Step-by-step explanation:

If the probability of drawing a blue marble from 18 marbles is 2/3 then there are 12 blue marbles because 18 times 2/3 is 12. This means that to reduce this probability to 1/2 you need to add 6 more marbles to the total amount to get it to 24. Now the probability of getting a blue marble is 12/24 which is 1/2.

Maria is on a hike. if she hikes to the scenic lookout on the following map first, she will have to hike farther than if she went straight to the end of the hike. 3 connected points on a coordinate plane. the point labeled, "maria," is at 4, -4. the point labeled, "end," is at -5, 5. a solid line connect the points "maria" and "end." the point labeled, "scenic lookout," is at 2, 3. dashed lines connect "maria" to "scenic lookout" and connect "scenic lookout" to "end." coordinate values on the map are in kilometers. how much shorter is the path straight to the end of the hike than past the scenic lookout? round your final answer only to the nearest kilometer. \text{km}kmstart text, k, m, end text

Answers

The path straight to the end of the hike is 6 km farther than past the scenic lookout.

How to determine the difference in the parts?

The map is not given, but the question can still be answered

From the question, the positions are given as::

Maria = (4, -4)

Scenic = (2, 3)

End = (-5, 5)

The distance between Maria and the end point is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]

[tex]Route\ 1 = 13[/tex]

The distance between Maria and the scenic lookout is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]

[tex]Route\ 2 = 7[/tex]

The distance between both routes is:

Distance = 13 - 7

Evaluate

Distance = 6

Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.

Read more about distance at:

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This is all the questions I need answers to:


A two-digit locker combination has two non-zero digits and no two digits are the same. Event A is defined as choosing an even digit for the first number, and event B is defined as choosing an odd digit for the second number.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

A. 4/9
B. 1/2
C. 5/9
D. 5/8


A locker combination consists of two non-zero digits, and each combination consists of different digits. Event A is defined as choosing an even number as the first digit, and event B is defined as choosing an even number as the second digit.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?

A. 1/6
B. 5/18
C. 1/2
D. 5/9



A jar contains 5 red marbles and 8 white marbles.
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
If two marbles are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?

A. 3/13
B. 10/39
C. 5/12
D. 8/13



A bag contains 5 blue marbles, 8 green marbles, 4 red marbles, and 3 yellow marbles.
Event A = drawing a green marble on the first draw
Event B = drawing a blue marble on the second draw
If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?

A. 2/19
B. 1/6
C. 4/19
D. 5/19




A jar contains 3 pink balls, 6 blue balls, and 3 red balls.
Event A = drawing a red ball on the first draw
Event B = drawing a pink ball on the second draw
If two balls are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?

A. 3/44
B. 4/9
C. 3/11
D. 1/4




House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?

A. 1/9
B. 5/72
C. 5/8
D. 2/3




House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?

A. 2/7
B. 5/14
C. 5/13
D. 6/13




A two-digit locker combination is made up of two non-zero digits. Digits in a combination are not repeated and range from 3 through 8.
Event A = choosing an odd number for the first digit
Event B = choosing an odd number for the second digit
If a combination is chosen at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?

A. 1/5
B. 3/14
C. 5/18
D. 2/5




A locker combination consists of two non-zero digits. The digits in a combination are not repeated and range from 2 through 9.
Event A = the first digit is an odd number
Event B = the second digit is an odd number
If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

A. 3/8
B. 3/7
C. 1/2
D. 4/7




There are 15 tiles in a bag. Of these, 7 are purple, 5 are black and the rest are white.
Event A = drawing a white tile on the first draw
Event B = drawing a purple tile on the second draw
If two tiles are drawn from the bag one after the other and not replaced, what is P(B|A) expressed in simplest form?

A. 1/5
B. 1/3
C. 7/15
D. 1/2

I know theres a lot here but please hurry :) thx 100 points to the first person to answer all correctly! thx :)

Answers

The  is probability P(B|A) expressed in simplest form is 1/2 (Option B) See computation below.

How do we derive the above?

P (A) = [[tex][\mathrm{C}_{5}^{1} \mathrm{C}_{8}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 8)/(9 x 8)

P (A) = '5/9

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

= '5/18

P(B|A) = P (AB)/P(A)

= ('5/18)/('5/9)

P(B|A)  = 1/2

How do we derive P(A and B) in the simplest form?

From the above we already have P (AB)

this is given as

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

P(AB) = '5/18

How do we derive P(A and B) in the simplest form where a jar contains 5 red marbles and 8 white marbles?

Note that:


Event A = drawing a white marble on the first draw

Event B = drawing a red marble on the second draw

P(A) = 8/13; while

P (B) = (5/12) because the first marble was not replaced, thus reducing th sample to 12.

Thus

P(A and B) = P(A)*P(B) = 8/13 * 5/12

P(A and B) =  10/39 (Option B)

If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?

Event A - Probability of Drawing a Green Marble is 8/20

Event B - Probability of Drawing a Blue Marble is 5/19

Thus P(B|A) = (8/20) * (5/19)

= [tex]\frac{8 * 5 }{20 * 19}[/tex]

= 40/380; divide numerator and denominator by 20

P(B|A) = 2/19 (Option A)



If two balls are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?

Event A = Probability of Drawing a red ball = 3/12

Event A = Probability of Drawing a pink ball without replacing the read in Event A = 3/11

Thus P (B and A) =

3/12 x 3/11

P (B and A) = 3/44 (Option A)

If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?

The conditions given are as follows:

The house number comprises of nonzero digits and are of two digits ranging from 1 to 9.

As per the condition, the First digit 8 can be selected in 9 ways; and Second digits is less than 6 can be selected in  ways

The sum total of ways thus is

9 x 8

= 72 ways........X

Recall that

Event A is defined as selecting 8 as the first numeral

The only way to select this is one way

Event B is defined as choosing a number less than 6 as the second digit, that is 1, 2, 3, 4, 5

Thus, the possible number of ways to fill second digit = 5/8

Thus, the possible number of ways to form two digits 'AnB' =
('AnB') = 1 x 5 = 5 .................y

Hence Probability (AnB) = 5/72 (Option B)

If a combination is chosen at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?

Given that the non-zero digits are in a combination are not repeated and range from 3 through 8, thus the odd numbers between 3 and 8 are:

3, 5, 7

total numbers is 3, 4, 5, 6, 7, 8

Hence; Event A = choosing an odd number for the first digit = 3/6

Event B = choosing an odd number for the second digit (recall that the numbers are not repeated) = 2/5

= [tex]\frac{2*3}{3*6}[/tex]

= 6/30

= 1/5 (Option A)



If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

Event A = the first digit is an odd number

Event B = the second digit is an odd number

The numbers from 2 to 9 are:
2,3,4,5,6,7,8,9

The odd numbers between 2 and 9 are:

3,5,7,9

P (A) = 4/8

P (B) = 3/7

P(B|A) = (3/7)/(4/8)

P(B|A) = 3/7



If two tiles are drawn from the bag one after the other and not replaced, what is P(B|A) expressed in simplest form?

Event A = drawing a white tile on the first draw

Event B = drawing a purple tile on the second draw

P(B|A) = (P(AnB)/P(A)

|n| = 15 * 14 = 210

| A| = 3*14 = 42

| AnB| = 3*7 = 21

P (A) = 42/210 = 6/30

P (AnB) = 21/210 = 1/10

P(B|A) = (1/10)/6/30)

P(B|A) = 1/10 * 30/6

P(B|A) = 30/60
P(B|A) = 1/2 (Option D)

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i need help finding this for clever

Answers

Answer:

The dog is 16 years old.

Step-by-step explanation:

X/4 + 6 = X/8 + 8

X/4-X/8 = 8-6

0.125X = 2

X = 2/0.125

X = 16

Answer:

16 years old

Step-by-step explanation

Dividing the dog’s age by 4 and adding 6

D÷4  + 6

dividing the dog’s age by 8 and adding 8

D÷8  + 8

equating both

D÷4  + 6 = D÷8 + 8

=> D÷4 - D÷8  = 2

multiplying by 8 both sides

=> 2D - D = 16

=> D = 16

hence, the dog is 16 years old

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