Which statement is true?
A. The number 31 is prime, but 37 is composite.
B. The number 29 is prime, but 37 is composite.
C. The number 31 is prime, but 33 is composite.
D. The number 33 is prime, but 35 is composite.

[tex]DE=\sqrt{13^{2}+12^{2}-2(13)(12)(\cos 59^{\circ})} \approx \boxed{12.3}[/tex]

Answer: 72.0472

Step-by-step explanation:

[tex]A=\left(\frac{129}{360} \right)(\pi)(8^{2}) \approx \boxed{72.0472}[/tex]

Answer:

1.6

Step-by-step explanation:

4,4-2.8 = 1.6

6-4.4 = 1.6

7.6-6 = 1.6

Then common difference is 1.6

Answer:

C = 105°

Step-by-step explanation:

added in the picture

Answer:

4 kg

Step-by-step explanation:

so 1.6 * 4 is 6.4 so you just double check if you want

4 + 1.6 which is 1/4 of 6.4 will be 5.6 (matches with the question)

4 + (1.6*4) (indicates it's full) = 10.4( also Matches with the question)

there is another way by setting up an equation. let me know in comments if you want to see it that way

If  tank weighs 5.6kg when it 1/4 filled with water. If it weighs 10.4kg when it is full , then weight when it is empty is 0.93kg

Two or more expressions with an Equal sign is called as Equation.

Given,

A tank weighs 5.6kg when it 1/4 filled with water

Tank weighs 10.4kg when it is full

We need to find the weight when it is empty.​

Let weight of the tank “x” and the weight of the water in the full tank “y”.

From the problem statements, we deduce the following equations:

x + y/4 = 5.6kg => x = 5.6kg - y/4

x + y = 10.4kg => y = 10.5kg - x

y = 10.5kg - (5.6kg - y/4)

3y/4 = 4.9

Thus y = 6.53kg; x = 0.93kg

Hence, weight of the tank when it is empty is 0.93kg.

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Answer:

8 [units].

Step-by-step explanation:

if to see the given coordinates, then it is clear the x-coordinates are equal. It means, the required distance can be calculated:

d=5+3=8 [units].

Answer:

Area of Floor = 21.6.m²

Area of tile = 288 cm² = 0.0288 m²

No. of tiles = Area of floor/ area of tile

= 21.6/0.0288

= 750

The weight of each pile yesterday will be 6 and 8 pounds.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

It is Given that Yesterday the ratio of seeds in these piles was 3:4.

Let 3x and 4x represent the seeds.

If the 2 pounds of seeds are added in the bigger pile, then

4x + 2

He also ate 1/4 pound from the smaller pile,

3x - 1/4

The quantities of seeds in those piles is in the ratio of 5:16.

So, 4x + 2 = 5x

3x - 1/4 = 16x

Solve;

So, 4x + 2 = 5x

2 = 5x - 4x

x = 2

The weight of each pie will be

3x = 6 pound

4x = 8 pound

Hence, The weight of each pile yesterday would be 6 and 8 pounds.

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Answer:

x=100/7

Step-by-step explanation:

The interior angles will sum to 360 so 72+89+99+7x=360

260+7x=360

7x=100

x=100/7

Answer:

1

Step-by-step explanation:

49 is divisible by 7, 1, 49. 25 is divisible by 5, 1, 25. they are exclusively prime so the highest factor is 1 and the only

Answer:

Step-by-step explanation:

[tex]25x^4-49y^2=(5x^2)^2-(7y)^2\\=(5x^2+7y)(5x^2-7y)\\=(5x^2+7y)[(\sqrt{5} x)^2-(\sqrt{7y} )^2]\\=(5x^2+7y)(\sqrt{5} x+\sqrt{7y} )(\sqrt{5} x-\sqrt{7y} )[/tex]

Answer: Read attachment.

Step-by-step explanation: Attached is my work. Hope it helps!

If my answer was helpful, please mark as brainliest. Or not, it's fine.

Answer:

[tex]\fbox {f(16) = -10}[/tex]

Step-by-step explanation:

Given :

f(x) = -3/4x + 2

Substitute x = 16 :

f(16) = -3/4(16) + 2

f(16) = -12 + 2

f(16) = -10

The solution to the inequality d / 7 + 4 ≤ 0 will be (–∞, –28]. Then the correct option is B.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The inequality equation is given below.

d / 7 + 4 ≤ 0

By simplifying the equation, we have

d / 7 ≤ – 4

    d ≤ – 28

Then the value of d must be less than or equal to the negative 28.

Then the correct option is B.

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Question 1

B. Set of whole numbers

Question 2

A. Set of real numbers

If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.

Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)

We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.

First option is set of rational numbers which is right for the function.

Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.

Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.

Hence the domain is set of rational numbers.

Now we will solve the second part of the question

f(x)=3x+8(3-x)

we have not told about the range of the function so we can put any value  in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.

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Answer:

Second choice GD and GF with the LINE symbol over each

Step-by-step explanation:

Angle named DGF means that G ( in the middle) is the vertex so GD would be a line starting at G going out toward D and G F would be a line starting at G going out to F

[tex]\mathsf {2(10 + 2) = 3(y + 3)}[/tex]

[tex]\mathsf {24 = 3y + 9}[/tex]

[tex]\mathsf {3y = 15}[/tex]

[tex]\textsf {y = 5}[/tex]

[tex]\textsf {The value of y will be 5. }[/tex]

Answer: -8

Step-by-step explanation:

[tex]y=8-2(8)=\boxed{-8}[/tex]

Hello!

We are trying to describe the behavior of the graph given in the question.

To help us understand how to solve this question, we would need to understand concavity.

There are two types of concavity:

When a graph is concave up, the slope of the line would look like a "U".

When a graph is concave down, the slope of the line would look like a "U" that is flipped upside down.

In this case, we can see that the graph is concave down.

We can tell that the slope is negative due to the fact that the slope is going down, which results in the graph having a negative slope.

We can also tell that the graph is decreasing due to the fact that the line is doing downward.

Answer:

C). negative and decreasing

The situations described can be classified as experiment, and observational study.

An experiment is a tool to test a hypothesis about the occurrence of a particular phenomenon. According to the above, it can be stated that student-centered instruction can be classified as an experiment because this method of education is used and it is verified whether it is effective or not.

An observational study is a methodology to identify the occurrence of an event in a particular situation. From the foregoing, it can be inferred that the participation of women in the 2016 election is the product of an observational study because only the number of voters should be counted and the number of women who participated should be identified.

Note: This question is incomplete because there is some information missing. Here is the information missing.

OPTIONS:

Does learner-centered instruction increase students' success rates in maths?

What proportion of registered women voters voted in the 2016 U.S. presidential election?

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Answer:

In standard form thats 4.4024

In standard form, 4+0.4+0.0024 can be written as 4.4024

Concept: Any number we can write as a decimal number, between 1.0 and 10.0, multiplied by 10, is said to be in the normal range. 1.23 × 108;

If you look closely, 1.23 is a decimal number between 1.0 and 10.0 so we have a standard form 123,000,000 as 1.23 × 108.

Given: 4+0.4+0.0024

In this case,4 is the integral value and 0.4 is at the first decimal place followed by 0.0024 at the third and 4th decimal place so combining them all together and writing them in standard form we get,4.4024

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Answer:

D represents a difference of squares.

Answer: Choice [D] - [tex]\boldsymbol{81-49y^2}[/tex]

Step-by-step explanation:

Hii, do you need to know which expression represents a difference of squares? No problem! (:

   Let's consider it for a moment. The "difference of squares" means we subtract two numbers squared, like [tex]\boldsymbol{a^2-b^2}[/tex].

Now let's check our choices and see where we subtract two numbers squared.

The only choice like that is Choice [D] - [tex]\boldsymbol{81-49y^2}[/tex].

In choice A, we add 2 numbers; in choices B and C we don't subtract two numbers squared.

Voila! There's our solution, cheers! (:

--

Hope that this helped! Best wishes.

[tex]\it Reach\;far.\;Aim\;high.\;Dream\;big.[/tex]

--

∠ A = 132°

Step-by-step explanation:

∠ A + ∠C = 180° (Angle sum of cyclic quadrilateral)

∠ A = 180° - ∠ C = 180° - 48°

∠ A = 132°

The question is incomplete. Below you will find the missing content in the figure.

Prove: m/EIF = m/GIH

Step                                                                    Reason

m∠EIF+m∠FIG = 180°

m∠FIG+m∠GIH= 180°

m∠EIF+m∠FIG= m∠FIG+m∠GIH

m∠EIF = m∠GIH

The figure is shown below.

The correct answer is m∠EIF = m∠GIH

Here lines FH and GE intersect each other at the point I.

we have to prove the angle

m∠EIF = m∠GIH

so,

m∠EIF+m∠FIG = 180° as angels ∠EIF and ∠FIG forming a linear pair summing up to 180°. angels ∠EIF and ∠FIG form straight angels on a line EG.

m∠FIG+m∠GIH= 180° as angels ∠FIG and ∠GIH forming a linear pair summing up to 180°. angels ∠FIG and ∠GIH form straight angels on a line FH.

m∠EIF+m∠FIG= m∠FIG+m∠GIH because of the substitution property of equality. we replace 180° by m∠FIG+m∠GIH.

m∠EIF = m∠GIH because of the subtraction property of equality. We can subtract the same elements from both sides by the subtraction property of equality.

Therefore m∠EIF = m∠GIH.

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Bikash borrowed Rs150,000 from Anish at the rare 21% per year at the end of 9 month. How compound interest should he pay compound half yearly.

Answer:

[tex]\textsf {p(-4) = -134}[/tex]

Step-by-step explanation:

[tex]\textsf {Given :}\\[/tex]

[tex]\mathsf {p(x) = x^{3} - 3x^{2} + 7x + 6}[/tex]

[tex]\textsf {Substitute x = -4 to find p(-4) :}[/tex]

[tex]\mathsf {p(-4) = (-4)^{3} - 3(-4)^{2} + 7(-4) + 6}[/tex]

[tex]\mathsf {p(-4) = -64 - 48 - 28 + 6}[/tex]

[tex]\textsf {p(-4) = 6 - 140}[/tex]

[tex]\textsf {p(-4) = -134}[/tex]