Which two elements have similar properties and 8 electrons in their outmost shells?

The average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.

What is average speed?

Average speed is a measure of the rate of change in position of an object over a certain period of time. It is calculated by dividing the total distance traveled by the total time taken. In other words, it is the rate at which an object covers a given distance. Average speed is useful in determining the efficiency of a vehicle, or of a person, in covering a particular distance. For example, if a person drives for 2 hours and travels a total distance of 200 kilometers, the average speed of the body is 100 km/hr (200km / 2 hrs).

The average speed is,

[tex]V_{avg} = \frac{d_{1}+ d_{2} }{\frac{d_{1} }{V_{1} }+ \frac{d_{2} }{V_{2} } }[/tex]

        [tex]= \frac{0.50m + 0.50m}{\frac{0.50m}{1.2m/s}+\frac{0.50m}{0.70m/s} }[/tex]

       = 0.884 m/s

Due to the average speed is 0.884 m/s the average speed of the blood becomes less than 0.95 m/s.

Therefore, the average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.

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Answer:

Answer:

Hugo de Vries

Explanation:

In the history of evolutionary biology, Hugo dr Vries is known as a proponent of the mutation theory of evolution, in which new species are believed to arise by single mutational events.

The energy lost due to friction is 0.49 J. And the speed of the bob passing through its lowest point will be 2.19 m/s.

The mass is 5 kg and the heights are h₁ 0.25 m and h₂ = 0.24. And the difference in the height is given as,

h₁ - h₂ = 0.25 - 0.24

h₁ - h₂ = 0.01

The energy loss due to friction is given as,

Energy loss = mgh₁ - mgh₂

Energy loss = mg (h₁ - h₂)

Energy loss = 5 x 9.8 x 0.01

Energy loss = 0.49 J

The energy lost due to friction is 0.49 J.

The velocity is given as,

KE = mgh₁ - E / 2

(1/2) x 5 x v² = 5 x 9.8 x 0.25 - 0.49 / 2

2.5v² = 12.25 - 0.245

v² = 4.802

v = 2.19 meters per second

The speed of the bob passing through its lowest point will be 2.19 m/s.

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The energy transformation that takes place when using a wind turbine to generate usable energy is mechanical-to-electrical.

This is done by converting the kinetic energy of the wind into mechanical energy, which then turns a generator to produce electrical energy. Then, residences and businesses can be powered by this electrical energy. Wind drives the rotor blades of contemporary wind turbines, which transform kinetic energy into rotational energy. Kinetic energy is a particular kind of power that can be present in a moving object or particle. An object can perform work, which involves the transfer of energy, by applying a net force. The effect is that the object accelerates and acquires kinetic energy. Aerodynamic force is used by the rotor blades of a wind turbine, which function similarly to an aeroplane wing or a helicopter rotor blade, to transform wind energy into electricity. The air pressure drops on one side of the blade as the wind passes across it.

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complete question: What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?

A) friction- electrical

B) kinetic - mechanical - electrical

C) friction - mechanical - electrical

D) mechanical - friction - electrical

The therapeutic effects of heat include increasing the extensibility of collagen tissues; decreasing joint stiffness; reducing pain; relieving muscle spasms; reducing inflammation, edema, and aids in the post acute phase of healing; and increasing blood flow.

In the process of ATP production by cells throughout the body, approximately 60 percent of the energy produced is in the form of heat used to maintain body temperature. Thermoregulation is an example of negative feedback.

Why is heat used as a treatment during health care?

Heat treatments should be used for chronic conditions to help relax and loosen tissues, and to stimulate blood flow to the area. Heat is a great treatment option for chronic conditions caused from old injuries or even arthritis. Heat can be applied before participating in activities to help limber up.

So we can conclude that heat is one of the most important form of energy for our daily life.

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Answer: B

Explanation: The best answer is B. A baseball thrown by a professional pitcher. Momentum is the product of an object's mass and its velocity. Since the baseball has the greatest velocity of all the objects listed, it has the greatest momentum.

The correct answer is : Planet X, because the sun pulls it with a greater force

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Answer: A A A !!!!  

Explanation: just did the test, got it right thx thx!!!

The acceleration is 2.7 m/s^2.

Acceleration is a measure of the rate at which an object changes its velocity. It is defined as the change in velocity per unit time and has units of meters per second squared (m/s^2). Acceleration can be positive (when an object is speeding up), negative (when it is slowing down), or zero (when its velocity is constant).

We can get the acceleration;

v^2 = u^2 - 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

Thus we have that;

v = 0 m/s thus;

u^2 = 2as

a = u^2/2s

a = (71.4)^2/2 * 939

a = 5097.96/1878

a = 2.7 m/s^2

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The magnitude of the velocity of the horse will be 8.89 m/s.

Given, the mass of the horse is 900 kg and the momentum of the horse is 8000 Kgm/s.

To calculate, the velocity of the horse from the given values.

Momentum of any body is defined as the product of the mass of the body and the velocity of that body.                                         Momentum(p) = Mass(m) × Velocity(v)

Keeping the provided values in the formula, momentum = mass × velocity to calculate the velocity of the horse

8000 Kgm/s =  900Kg × velocity

velocity = 8000/900 m/s = 8.89 m/s

So, the velocity of the horse is 8.89 m/s.

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Answer: no answer

Explanation:

The spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.

What is Potential Energy?

It is a form of energy that is stored in an object and has the potential to do work. The amount of potential energy depends on the position, shape, and orientation of the object. The most common types of potential energy are gravitational potential energy, elastic potential energy, and chemical potential energy.

The elastic potential energy stored by a spring is given by the formula:

Elastic potential energy = 1/2 * spring constant * (extension)^2

where the spring constant is measured in Newtons per meter (N/m), and the extension is measured in meters (m).

Given that the spring constant is 2 N/m and the extension is 0.5 m, we can plug these values into the formula:

Elastic potential energy = 1/2 * 2 N/m * (0.5 m)^2

= 0.5 J

Therefore, the spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.

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Answer:

10 g at 10°C

Explanation:

Answer:

10 g at 10°C

Explanation:

Heat energy is directly proportional to the mass and the temperature of a substance. When comparing two samples of the same substance, the one with higher mass contains more heat energy. Similarly, a substance with higher temperature contains more heat energy compared to the same substance with a lower temperature.

In this case, the smallest amount of heat energy would be in the sample of 10g at 10°C. This is because it has the lowest mass and temperature compared to the other three options.



ALLEN

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer

explain about the copper ?

Copper is a chemical element with the symbol Cu and atomic number 29. It is a soft, malleable, and ductile metal with high thermal and electrical conductivity. Copper has been used by humans for thousands of years for various purposes including coinage, electrical wiring, plumbing, and industrial machinery. It is commonly found in nature as copper oxide or copper sulfide, and it can be extracted through mining and refining processes. Copper is also an essential nutrient for all living organisms and plays important roles in biological processes such as the formation of red blood cells and the maintenance of the nervous and immune systems.

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer. This is because in metals like copper, the outermost electrons of atoms are not tightly bound to their respective nuclei, and can therefore move easily through the material, allowing for efficient conduction of electricity. On the other hand, in non-metal substances like carbon fiber, the electrons are more tightly bound to their respective nuclei, making it less efficient in conducting electricity.

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Answer:

(Question) Why is copper wire a better conductor of electricity than carbon fiber?

(Answer) The electrons in copper (Cu) are loosely bound to the nucleus

(Question) Which of the following best describes a direct current?

(Answer) An electrical current that flows in one direction

(Question) Which of the following substances would allow an electric current to flow through it easily?

(Answer) aluminum (Al)

(Question) Which of the following statements about electrical charges is true?

(Answer) Opposite charges attract one another

(Question) Which of the following statements best describes the relationship between atoms and conductivity?

(Answer) Atoms with a nearly empty valence shell make good conductors

Explanation:

i just finished the quick check

The resistance (slope of a curve) is about 490 so when bulb is lit. According to this model, the resistance was inversely proportional to temperature for materials (such this tungsten filament).200 ohms

The datasheet for such LED will include this information as well as the forward dc voltage. LEDs typically demand 10 to 20mA. For instance, a 9V battery powered ultra-bright blue LED has a forwards voltage or 3.2V and a typical current is 20mA. Thus, the resistor must be 290 ohms and as close to that value as is feasible.

Due to their relatively high resistance, alkaline, carbon-zinc, and the majority of primary batteries can only be used in low-current devices like flashlights, remotes, portable entertainment systems, and kitchen clocks. The resistance gets worse when these batteries run out of power.

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Answerbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Explanation:

A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. Therefore, 60m/s is the average velocity of the deer during this time.

Motion may be defined using physical quantity concepts such as speed, velocity, duration, displacement, as well as acceleration. Sir Isaac Newton provided the correct explanation of motion.

All of these quantities are explained in terms of a single quantity, time. In this section, we will look at average velocity, its mathematical representation, and its graphical depiction.

average velocity =  520 m+  380 m / 15=60m/s

Therefore, 60m/s is the average velocity of the deer during this time.

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The drop distance is 23.7402 m

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

S = ut + ½ at²

S = 0 × t × ½ × 9.81 × 2.2²

S= 23.7402 m

The drop distance is23.7402 m

v = u + at

v = 0 + 9.81 × 2.2

v= 21. 582 m/s

When they hit the airbags at the bottom of the tower the speed of the experiments is 21.582 m/s

The final speed of the fall will be the initial velocity of stopping

v² - u² = 2as

a = v² - u²/ 2s

a= 310.521816 m/s²

The average stopping acceleration is 310.521816 m/s²

What is displacement?

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Answer:

F(Net) = F(a) + F(g) + F(f) + FN.

The speed of light in vacuum is 3 × 10⁸ m/s. If the refractive index of a transparent liquid is 4/3, then the speed of light in water will be 2.25 × 10⁸ m/s.

Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to the speed of light in the second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n'.

R.I. of water = Speed of light in vacuum / speed of light in water

n' = 4/3

Speed of light in vacuum = 3 × 10⁸

n' = Speed of light in vacuum / speed of light in water

Speed of light in water = Speed of light in vacuum/ n'

Speed of light in water = 3 × 10⁸/ 4/3

Speed of light in water = 2.25 × 10⁸

Therefore, the speed of light in water medium will be 2.25 × 10⁸ m/s.

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Uniform distribution of charge a) [tex]-1.752 * 10^(-17) C/m[/tex] b) [tex]-4.038 * 10^(-16) C/m^2[/tex] c)  [tex]-6.346 * 10^(-16) C/m^2[/tex] d) [tex]-4.580 * 10^(-13) C/m^3[/tex]

(a) To find the linear charge density along the arc, we divide total charge (-275e) by arc length. Arc length is product of radius (3.85 cm) by the angle (in radians) arc subtends. Convert angle to radians:

[tex]37 degree = (37/360) * 2\pi radians = 0.6435 radians[/tex]

The length of the arc is then:

length = radius x angle = (3.85 cm) x (0.6435) ≈ 2.477 cm

The linear charge density is then:

linear charge density = charge in total / length magnitude = (-275e) / (2.477 cm)

e: elementary charge.

Using charge value:

linear charge density = [tex]-1.752 * 10^(-17) C/m[/tex]

Therefore, linear charge density along the arc is [tex]-1.752 * 10^(-17) C/m.[/tex]

(b) To find the surface charge density over the face of the circular disk, we need to divide the total charge (-275e) by area of disk. Area of face of disk is [tex]\pi[/tex] times radius squared

area =[tex]\pi * (1.85 cm)^2 = 10.78 cm^2[/tex]

The surface charge density is then:

surface charge density = total value of charge / area magnitude = [tex](-275e) / (10.78 cm^2)[/tex]

e: elementary charge.

Using charge value:

surface charge density = [tex]-4.038 * 10^(-16) C/m^2[/tex]

Surface charge density over the face of the circular disk is  [tex]-4.038 * 10^(-16) C/m^2[/tex].

(c) To get surface charge density over sphere surface, we divide total charge (-275e) by sphere surface area:

surface area = [tex]4\pi * (radius)^2[/tex]

The surface charge density:

surface charge density = total charge / surface area =[tex](-275e) / [4\pi * (1.85 cm)^2][/tex]

where e is the elementary charge.

Use charge value:

surface charge density ≈ [tex]-6.346 * 10^(-16) C/m^2[/tex]

Surface charge density over sphere is[tex]-6.346 * 10^(-16) C/m^2.[/tex]

(d) To get volume charge density in the sphere, we divide the total charge (-275e) by the volume of the sphere.

volume = [tex](4/3)\pi * (radius)^3[/tex]

The volume charge density is then:

volume charge density = total charge / volume = [tex](-275e) / [(4/3)\pi * (1.85 cm)^3][/tex]

e: elementary charge

Using value of the elementary charge:

volume charge density = [tex]-4.580 * 10^(-13) C/m^3[/tex]

Therefore, the volume charge density in the sphere is [tex]-4.580 * 10^(-13) C/m^3[/tex]

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Answer:

The correct sequence of events is:

A. Martin Cooper invented the first cell phone.

B. AT&T discussed the concept of a wireless phone.

C. Cell phone became the most common electronic device.

D. The FDA ruled that the health risks of cell phones were small.

Because the charge densities per unit area on every plane are equal. Hence, the strength of the electric field around point P is the same in situations A and B.

Gauss' law can be used to determine the electric field of such an infinite line charge with such a uniform linear charge density.

The electric field is of equal strength at each point of a cylinder and thus is pointed outward when a Gaussian surface with radius r is modeled as a cylinder.

We discovered that electric field is radially oriented away as from line charge and that its strength decreases in inverse proportion to its distance.

Hence, the strength of the electric field around point P is the same in situations A and B.

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Answer:

Explanation:

C. 113.5 Ns

Answer:

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Explanation:

The moment of inertia of a uniform disc of mass M and radius R rotating about its axis is [tex](1/2) MR^2[/tex].

The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter is [tex](8/5) MR^2[/tex].

The moment of inertia of a uniform disc of mass M and radius R rotating about its axis can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the axis of rotation.

Using polar coordinates, we can write dm = (M/πR^2)rdrdθ, where r ranges from 0 to R and θ ranges from 0 to 2π.

The moment of inertia of each element is given by dI = dm r^2. Therefore, we have:

I = ∫dI

= ∫[tex]r^2 dm[/tex]

= ∫₀²π ∫₀ᴿ (M/πR^2)r³drdθ

= (M/πR^2) ∫₀²π [∫₀ᴿ r³dr] dθ

= (M/πR^2) ∫₀²π [(1/4)R^4] dθ

= (M/πR^2) (1/4)R^4 (2π)

= [tex](1/2) MR^2[/tex]

The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the diameter. Using spherical coordinates, we can write dm = (M/4πR^3)r^2sinθdrdθdφ, where r ranges from 0 to R, θ ranges from 0 to π, and φ ranges from 0 to 2π. The moment of inertia of each element is given by dI = dm r^2sin^2θ. Therefore, we have:

I = ∫dI = ∫r^2sin^2θ dm = ∫₀²π ∫₀ᴾ ∫₀ᴿ (M/4πR^3)r^4sin^3θdrdθdφ

= (M/4πR^3) ∫₀²π ∫₀ᴾ [∫₀ᴿ r^4sin^3θdr] dθdφ

= (M/4πR^3) ∫₀²π ∫₀ᴾ [(2/5)R^5sin^3θ] dθdφ

= (2/5) MR^2 ∫₀²π [∫₀ᴾ sin^3θ dθ] dφ

= (2/5) MR^2 ∫₀²π [(-cosθ + (3/2)cos^3θ/3)|₀ᴾ] dφ

= (8/15) MR^2 ∫₀²π dφ

= (8/15) MR^2 (2π)

= (8/5) MR^2

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Answer:

the driver does 29,400 J of work in pushing the car to the gas station.

Explanation:

To find the amount of work done by the driver, we need to know the force applied by the driver and the distance the car is moved.

The force applied by the driver is given as 140 N, and the distance the car is moved is given as 210 m.

Work done can be calculated using the formula:

W = F * d * cos(θ)

where W is the work done, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. Since the force and displacement are in the same direction, θ = 0, and the cosine of 0 is 1.

So,

W = F * d * cos(θ) = 140 N * 210 m * 1 = 29,400 J

Answer:

it is accelerating because it is at constant speed.

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Explanation:

The pressure exerted on the floor by each leg of the chair is [tex]7.080685*10^6M Pa[/tex]

Given :

Mass of person = 65 kg

Mass of chair = 3.6 kg

Diameter of contact point = 1.1 cm = D

Radius of contact point = 1.1/2 = 0.55 cm

The total mass of chair and person = 65 + 3.6 = 68.6 kg = M

Acceleration due to gravity = 9.81 m/s²

Force acting on the floor F

F=mg

F= 68.6 * 9.81

F = 672 .9 N

Area of the contact point

A = [tex]\pi r^2[/tex]

A = [tex]\pi (0.55)^2[/tex]

A = [tex]0.00003025\pi[/tex]

Pressure = force/Area

Pressure = [tex]672.9/0.00003025\pi[/tex]

Pressure =[tex]7.080685*10^6[/tex]

What is pressure in short answer?

Pressure is an expression of force exerted on a surface per unit area. if a force F is applied on area A, then pressure P=F/A.

What is the formula for pressure, force, and area?

Pressure is defined as force per unit area. It is expressed as P = F/A, where P is pressure in pascals, F is the force in newtons, and A is the area in square meters.

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1) Statements best describes the electric field in the region between the spheres  field points radially outward.

2) Statements best describes the electric field in the region outside the red sphere The field is zero.

For positive charge, E field lines are projecting outward of positive charge.

For negative charge, E field lines are projecting inward of negative charge.

Then, between the spheres,

because of q, E field lines are projecting outward of q and inward of- q;

and because of- q, E filed lines are projecting outward of q and inward of- q

So, The field points radially outward

2) C still, net charge inside the gaussian face is zero, If we draw a gaussian face outside the spheres.

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